What is the perimeter of ABC to the nearest whole number?
B
25
39°
С
(440
A А
A 53
B. 92
C 108
D 180

Answer: \(\lim_{x \to \infty} (\frac{sinh(x)}{e^x})\)\(= 0\)

Step-by-step explanation:

\(\lim_{x \to \infty} (\frac{sinh(x)}{e^x})\)

\(\lim_{n \to \infty} \frac{sinh(\infty)}{e^(\infty)}\)

As x approaches infinity, the exponential term e^x becomes much larger than the hyperbolic sine function sinh(x), so the entire expression sinh(x)/e^x becomes very close to zero.

Therefore, the limit of the expression as x approaches infinity is 0:

Answer:

A.)

 1.) b = h(2)

 2.) p = b - 3

B.) 10

C.) 5

Step-by-step explanation:

A.)

 1.) The birch tree is twice the size of the orange tree so, birch = orange * 2

 2.)  The peach tree is 3m shorter than the birch so, peach = birch - 3meters

B.) b = 5(2)

C.) 8 = 4(2)

     p = 8 - 3

Answer:

2 cm

10 cm

Step-by-step explanation:

14/7 = 2

This helps to find because area of rectangle = bh or base times height.

A = 1/2 bh

30 = 1/2 b 6

30 = 3b

b = 10

Answer:

b = 2 cm

b = 10 cm

Step-by-step explanation:

Area of a Rectangle: A = lw

Area of a Triangle: A = 1/2bh

We are given area and length, so simply plug it in:

14 = 7w

w = 2 cm

We are given area and height, so simply plug it in:

30 = 1/2(6)(b)

30 = 3b

b = 10 cm

Reject H0 if the test statistic is less than  -1.321  or greater than  1.321  .

What is a hypothesis simple definition?

A tested assertion regarding the relationship between two or more variables .

                  a theory put out to explain an observed occurrence is referred to as a hypothesis (plural: hypotheses) in a scientific context.      

Reject H0 if the test statistic is less than  -1.321  or greater than  1.321  .

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The two equations that represent lines parallel to 3x - 4y = 7 and passing through the point (-4, -2) are 3x - 4y = -4.

To find the equation of a line parallel to the line 3x - 4y = 7 and passing through the point (-4, -2),

we need to determine the slope of the given line and then use that slope along with the given point to write the equation. The two equations that represent lines parallel to 3x - 4y = 7 are 3x - 4y = k1 and 3x - 4y = k2, where k1 and k2 are constants.

The given equation, 3x - 4y = 7, can be rewritten in slope-intercept form (y = mx + b) by isolating y:4y = 3x - 7

y = (3/4)x - 7/4

From this form, we can see that the slope of the given line is 3/4.

Since we want to find a line parallel to this one, the parallel line will also have a slope of 3/4. Now, using the point (-4, -2) and the slope of 3/4, we can write the equation of the line in point-slope form:

y - y1 = m(x - x1)

y - (-2) = (3/4)(x - (-4))

y + 2 = (3/4)(x + 4)

To write the equation in standard form, we can multiply both sides of the equation by 4 to eliminate the fraction:4(y + 2) = 3(x + 4)

4y + 8 = 3x + 12

Rearranging the equation, we get:

3x - 4y = -4

Thus, the two equations that represent lines parallel to 3x - 4y = 7 and passing through the point (-4, -2) are 3x - 4y = -4.

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Answer:

1 9/40

Step by step explanation:

\frac{49}{40}=1\frac{9}{40}

Answer:

2.75+11.50S\(\leq\)55

4

Step-by-step explanation:

The Total amount of money Alonso went to the market with is: = $55

Items to be bought includes:

Alonso knows that:

Requirement for his taste for sugar:

From this information, the objective would be to determine the number of sugar he can purchase with the money left after he has already bought the eggs.

To start with, the amount of money left after buying the eggs is:

= $55 - $2.75

= $52.25

Now, if a box of sugar he likes cost = $11.50

Then he will be able to purchase (x( bost of sugar with = $52.50

Now, to determine the number of boxes of sugar he can purchase, we have:

1 box of sugar = $11.50

x(box) of sugar = $52.25

∴

\(\mathbf{x (box) of sugar = \dfrac{\$52.25 \times 1 box of sugar }{\$11.50}}\)

x = 4.5 box of sugar

Therefore, after buying a pack of 12 eggs for = $2.75, Alonso will be able to buy \(\mathbf{ 4\dfrac{1}{2}}\)  or 4.5 boxes of sugar.

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To get the decimal expansion of

We need to divide both numbers:

This is a periodic number. As we can see, the period is 12 after the decimal point, and it will repeat to the infinity:

We can represent it as:

or

The decimal expression for 4/33 is 0.121

The method for converting a fraction into a decimal expression can be done by dividing 4 by 33

First step would be dividing the 4 into 33 parts

As we know that 4 cannot be divided into 33 parts , hence we have to take an extra zero while dividing them, and while putting an extra zero in front of 4 we have to put a decimal sign.

4/33 = 4÷33

4÷33 = 0.121

now we have to put an extra zero in front of 4 in order to make it divisible by 33

Hence after calculation, we will get the answer nearest to 3 decimal places as 0.121

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Answer:

y = -6x - 4

Step-by-step explanation:

Using two points on the line, (0, -4) and (-1, 2),

\( Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - (-4)}{-1 - 0} = \frac{6}{-1} = -6 \)

m = -6

y-intercept (b) = -4 (the value of y when x = 0)

To write the equation, substitute m = -6, and b = -4 into y = mx + b

y = -6x - 4

Answer:24-25a

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

4x=0

divide both sides of the equation by 4

x=0

so,

x=0

the overall answer to your question is 0

Rounded to one decimal place, 0.09 is approximately equal to

0.1.

0.09 rounded to the nearest 3 decimal places = 0.090

For given question,

We need to round the number 0.09 to the nearest 3 decimal places.

We know, 0.09 = 0.09000

For the number 0.09,

the number at the thousandth place is 0 (0.09000)

the number next to the thousandth place is 0 (0.09000) which is less than 5.

So, round down the number.

Therefore, 0.09 rounded to the nearest 3 decimal places = 0.090

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Answer:

14

Step-by-step explanation:

-4 |-5| = -20

-2(-17) = 34

34-20 = 14

Random variable

a. E (X+ Y) = 14.10

   E|(X – Y)| = 5.1

b. E[max(X ,Y )] = 9.60

   E[min(x, y)] = 4.5

Conversely, once Y=y is observed, we would more likely be interested in the quantity E(X∣Y=y)=ρy which is a scalar.

Maybe this seems like needless complication, but regarding E(X∣Y) as a random variable in its own right is what makes things like the tower-law E(X)=E[E(X∣Y)] make sense - the thing on the inside of the braces is random, so we can ask what its expectation is, whereas there is nothing random about E(X∣Y=y).

a. E (X+ Y)

=∑∑( x +y)p(x ,y)

= (0+0)(0+2) + (0 + 5)(.06) + … + (10 + 15)(.01)

= 14.10

E|(X – Y)| = ∑∑ |x – y| p(x,y)

= |(0-0)|(0.02) + |(0-5)|(0.06) + ……+ |(10-15)|(0.01)

= 5.1

b.

E[max(X ,Y )] = ∑∑max(x+y).p (x ,y)

= (0)(.02) + (5)(.06) +…+(15)(.01)

= 9.60

E[min(x, y)] = ∑∑ min (x,y) p(x,y)

= 0(0.02) + 0(0.06) + ……+ 10(0.14) + 10(0.01)

= 4.5

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a) The unit prices to determine the best buy are as follows:

b) The best buy is the 14-ounce bottle of salad dressing with a unit cost of $0.24 since they are all Grade A products.

The unit price or cost is the cost for an item or a unit.

The unit price can be compared to the unit rate, which is the quotient of the total cost and the number of units.

                              6 ounces   14 ounces   20 ounces

Total costs               $1.56           $3.36          $5.60

Unit cost                  $0.26          $0.24          $0.28

                            ($1.56/6)      ($3.36/14)     ($5.60/20)

Thus, buying a 14-ounce bottle of salad dressing is more economical than others.

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Answer:

4,482,186 becomes 4,482,190

Step-by-step explanation:

The statement is false. The existence of a scalar α such that αv is an eigenvector of a does not imply that v itself is an eigenvector of a.

A group of numbers built up in a rectangular array with rows and columns. The elements, or entries, of the matrix are the integers. In addition to numerous mathematical disciplines, matrices find extensive use in the fields of engineering, physics, economics, and statistics.

The statement is false. An eigenvector is a non-zero vector that, when multiplied by a matrix, produces a scalar multiple of itself. In other words, if v is an eigenvector of a matrix A, then Av = λv, where λ is the corresponding eigenvalue.

The statement suggests that if a is an nn matrix (presumably an n x n matrix), and a scalar α exists such that αv is an eigenvector of a, then v must also be an eigenvector of a. However, this is not necessarily true.

Let's consider a counterexample to demonstrate this. Suppose we have the 2x2 identity matrix I:

I = [[1, 0],

    [0, 1]]

In this case, any non-zero vector v will satisfy the condition αv = v for α = 1. However, not all non-zero vectors v are eigenvectors of I. In fact, the only eigenvectors of I are [1, 0] and [0, 1] with corresponding eigenvalues of 1.

Therefore, the statement is false. The existence of a scalar α such that αv is an eigenvector of a does not imply that v itself is an eigenvector of a.

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Answer:

graph is shown

Step-by-step explanation:

slope: -1/3

y intercept: (0,-17/3)

The correct answer is:

\(b. \sum f^n(2)/n! (x-2)^n = -3 +16(x-2) + 20(x-2)^2 + \sum 8(x-2)^3^/^n! + \sum (x-2)^4^/^n!\)

The Maclaurin series is:

\(f(x) = \sum (-1)^n (2x)^(^4^n^+^1^)/(3^(^2^n^)^(^2^n^)!) = \sum (-1)^n (2^(^4^n^+^1^)/3^(^2^n^)^(^2^n^)!) x^(^4^n^+^1^)\)

The indefinite integral of (cos(x) - 1/x) can be expressed as an infinite series.

The correct answer for the Taylor series of f(x) = x^4 - 4x^2 + 3 centered at a = 2 is:

\(b. \sum f^n(2)/n! (x-2)^n = -3 +16(x-2) + 20(x-2)^2 + \sum 8(x-2)^3^/^n! + \sum (x-2)^4^/^n!\)

The associated radius of convergence for this series is infinity, since the power series expansion of f(x) exists for all real numbers x.

To obtain the Maclaurin series for \(f(x) = 2x cos(1/3x^2)\), we can first find the Maclaurin series for \(cos(x^2^/^3^)\) and then multiply by 2x:

\(cos(x^2/3) = \sum (-1)^n (x^2/3)^(2n)/(2n)! = \sum (-1)^n x^(^4^n^)/(3^(^2^n^)^(^2^n^)!)\)

Therefore, the Maclaurin series for \(f(x) = 2x cos(1/3x^2)\) is:

\(f(x) = \sum (-1)^n (2x)^(^4^n^+^1^)/(3^(^2^n^)^(^2^n^)!) = \sum (-1)^n (2^(^4^n^+^1^)/3^(^2^n^)^(^2^n^)!) x^(^4^n^+^1^)\)

To evaluate the indefinite integral ∫(cos(x) - 1/x) dx as an infinite series, we can use the Maclaurin series for cos(x) and the power series expansion of \(ln(x) = \sum(-1)^(^n^+^1^) (x-1)^n/n\), which converges for 0 < x ≤ 2. Thus, we have:

\(\int(cos(x) - 1/x) dx = \intcos(x) dx - \int(1/x) dx = \sum(-1)^n x^(^2^n^+^1^)/(2n+1)! - ln|x| + C\)

where C is the constant of integration. We can simplify this expression as follows:

\(\int (cos(x) - 1/x) dx = \sum (-1)^n x^(^2^n^+^1^)/(2n+1)! - ln|x| + C\)

\(= -ln|x| + \sum(-1)^n x^(^2^n^+^1^)/(2n+1)!\)

\(= -ln|x| + \sum(-1)^n (x-1)^(^2^n^+^1^)/(2n+1)x^(^2^n^+^1^)\)

Thus, the indefinite integral of (cos(x) - 1/x) can be expressed as an infinite series.

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Given functions are f(x) = { ! and g(x) = { i.(a) Is the given function continuous at x = 0? The function f(x) + g(x) is discontinuous at x = 0.Answer:No (f) is the given function continuous at x = 0.

To check the continuity of a function at a particular point, we need to verify the three conditions:

Existence of the function at that point. The left-hand limit of the function at the point should exist.The right-hand limit of the function at the point should exist.

Left-hand limit of f(x) as x approaches 0 is f(0-) = !Right-hand limit of f(x) as x approaches 0 is f(0+) = 0

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function f(x) is discontinuous at x = 0.(b) Is the given function continuous at x = 0?

Left-hand limit of g(x) as x approaches 0 is g(0-) = iRight-hand limit of g(x) as x approaches 0 is g(0+) = 0

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function g(x) is discontinuous at x = 0.

(c) Is the given function continuous at x = 0?Left-hand limit of f(-x) as x approaches 0 is f(-0+) = 0Right-hand limit of f(-x) as x approaches 0 is f(-0-) = !

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function f(-x) is discontinuous at x = 0.

(d) Is the given function continuous at x = 0?The function |g(x)| is always non-negative, so its limit at x = 0 must also be non-negative.

Left-hand limit of |g(x)| as x approaches 0 is |g(0-)| = |i| = iRight-hand limit of |g(x)| as x approaches 0 is |g(0+)| = |0| = 0

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function |g(x)| is discontinuous at x = 0.

(e) Is the given function continuous at x = 0?Left-hand limit of f(x)g(x) as x approaches 0 is f(0-)g(0-) = ! i = -iRight-hand limit of f(x)g(x) as x approaches 0 is f(0+)g(0+) = 0 x 0 = 0

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function f(x)g(x) is discontinuous at x = 0.

(f) Is the given function continuous at x = 0?Left-hand limit of g(f(x)) as x approaches 0 is g(f(0-)) = g(!)Right-hand limit of g(f(x)) as x approaches 0 is g(f(0+)) = g(0)

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function g(f(x)) is discontinuous at x = 0.

(g) Is the given function continuous at x = 0?Left-hand limit of f(x) + g(x) as x approaches 0 is f(0-) + g(0-) = ! + i = -iRight-hand limit of f(x) + g(x) as x approaches 0 is f(0+) + g(0+) = 0 + 0 = 0

Since left-hand limit and right-hand limit at x = 0 are not equal, therefore, the function f(x) + g(x) is discontinuous at x = 0.

Answer:No (f) is the given function continuous at x = 0.

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Answer:

1: 28,620

2: 28,595

3:277,830

4. 177,120

5: 1111,505

6: 882,000

7: 841,750

8: 6.890,000

9: 695,625

10: 895,275

11: 1016,000

12: 55,464,500

Answer:

b

Step-by-step explanation:

it matches all the numbers on the table

Answer:

The correct option is right-bracket squared 3 squared =x+5

Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Option c: x+5=3^{2}

This is possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option c is equivalent to \log _{3}(x+5)=2

Option b: x+5=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Thus, the correct option is c: x+5=3^{2}

Hence, the equation x+5=3^{2} is equivalent to \log _{3}(x+5)=2

Answer:

B

Step-by-step explanation: Let me know if I am right

Answer:

x = 45 degrees

Step-by-step explanation:

Using the alternate exterior angle theorem, the angles are equal. You can set the expressions equal to each other:

3x = x + 90
2x = 90
x = 45

Hey there!

12(w - 3)

= 12(10 - 3)

= 12(10) + 12(-3)

= 120 - 36

= 84

OR

12(w - 3)

= 12(10 - 3)

= 12(7)

= 84

Therefore, your answer should be:

84

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

The point on the graph of g if g(5)= 0 is (5,0). The point is on the graph of g is (5,0) and the corresponding x-intercept of the graph of g is 5.  

It is given that, g(5) = 0

It is need to find the point on the graph of g and corresponding x-intercept of the graph of g.

The point (x,y) on the graph of g can be obtained by substituting the given value in the function g(x).

Therefore, if g(5) = 0, g(x) = 0 at x = 5.

Then the point on the graph of g is (5,0).

Now, we need to find the corresponding x-intercept of the graph of g.

It can be found by substituting y=0 in the function g(x).

Therefore, we have to find the value of x for which g(x)=0.

g(x) = 0⇒ x - 5 = 0⇒ x = 5

The corresponding x-intercept of the graph of g is 5.

Type of ordered pair = (x,y) = (5,0).

Therefore, the point is on the graph of g is (5,0) and the corresponding x-intercept of the graph of g is 5.

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a. The GRP (Gross Rating Points) for the four-week media buy with a 62 reach and 3.2 frequency can be calculated by multiplying the reach by the frequency. Therefore, the GRP for this buy is 62 * 3.2 = 198.4 GRPs.

b. In the case of the similar buy with 230 GRPs and a 50% reach, we can calculate the frequency by dividing the GRPs by the reach. So the frequency is 230 / 50 = 4.6.

When you reach fewer people, you gain a higher frequency. The difference in frequency between the two buys can be calculated by subtracting the initial frequency (3.2) from the frequency in the second buy (4.6). Therefore, the gain in frequency is 4.6 - 3.2 = 1.4.

c. To determine which buy is better, we need to consider the marketing objectives and strategies. If the objective is to maximize reach and exposure to a wider audience, the first buy with a higher reach of 62 would be better. However, if the objective is to focus on repetition and frequency of message delivery to a more targeted audience, the second buy with a higher frequency of 4.6 might be more suitable. The choice depends on the specific goals and priorities of the advertising campaign.

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Answer:

X=180-(65+65) =50

Z is 180-65 = 115

y =30

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

rational

Step-by-step explanation:

Answer:

The fraction 3/10 is a rational number. All fractions are rational numbers.