What is the momentum of a 8 kilogram cart moving with a speed of 12 meters per
second?

Answer:

Wave a is louder than wave b!!!

Explanation:

Yes

Seeds of gymnosperms likely are not dispersed by animals because they are not enclosed in a fruit as occurs with angiosperm seeds.

What are gymnosperms and angiosperms?

Gymnosperms and angiosperms are different taxonomic groups of seed plants, which have certain particular features such as the presence of fruits angiosperms, it being an adaptive advantage for the dispersion of seeds through animals.

Therefore, with this data, we can see that gymnosperms and angiosperms are different groups of seed plants and angiosperms are evolutionary are more adapted to disperse their seed through animals due to the presence of fruits.

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The electrostatic pressure on the surface of a conductor can be written as the force per unit area due to the electrostatic repulsion of charges on the surface. This pressure is evenly distributed on the surface of the conductor and depends on the magnitude and distribution of the charges on the surface.

Conductors have the unique property of allowing charges to move freely on their surfaces, which is why they can be used in electrical circuits to transport charges.

The electrostatic pressure on the surface of a conductor can be written as:
Electrostatic pressure (P) = (1/2) × (ε₀ × E²)

where:
- P is the electrostatic pressure
- ε₀ is the vacuum permittivity (approximately 8.85 × 10⁻¹² C²/N·m²),
- E is the electric field strength at the surface of the conductor.

In a conductor, the electric charges distribute themselves on the surface in such a way that the electric field inside the conductor is zero. This distribution of charges creates an electrostatic pressure on the surface of the conductor, which can be calculated using the above formula.

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Why can you get a shock if you touch a metal doorknob after walking across a wool carpet is because you have gained neutrons; the doorknob has fewer electrons. This is further explained below.

Electrons can be defined as a stable subatomic particles with a negative electrical charge that is found in all atoms and serves as the major carrier of electricity in solids.

In conclusion, You have an unbalanced charge, while the doorknob is neutral. you have gained neutrons; the doorknob has fewer electrons.

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Answer:

the first one looks like a spiral galixy

the 2nd one looks like a lenticular galixy ?? (im pretty sure but not 100%)

the 3rd one looks like a elliptical galixy

Explanation:

Answer:

1. Spiral

2. Not sure but i think its irregular.

3. Elliptical

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"Most of the moons of Saturn have rocky, cratered surfaces, like Deimos and Phobos." False.

The majority of Saturn's moons, including its biggest moon Titan, have unique surface characteristics and compositions. While many moons exhibit a diversity of geological features, some moons, like Enceladus and Mimas, do have highly cratered surfaces. For instance, Titan possesses a dense atmosphere, methane lakes, and intricate geological structures.

Actually, Deimos and Phobos are moons of Mars rather than Saturn. They resemble some of Mars' moons but not Saturn's; they are small, asymmetrical moons with highly cratered surfaces.

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The minimum velocity the roller-coaster would need when going over the 13 m hill to make it to the top of the 26 m hill is 16.56 m/s.

Force is defined as the physical quantity or the power.

the normal force would havening  to point away from the group center of the curve. Unless they have belts, the riders will fall from the cars.

In a teardrop-shaped in the continuous loop the radius of curvature r decreases, causing them centripetal acceleration to increase. The speed would be  decrease as the car rises (because of gravity), but it is they are

overall by the effect is that the required centripetal force of the increases, meaning is the  normal force increased there is less danger if not to the  wearing a seat belt.

Suppose the minimum velocity is v.

Then mechanical energy at top of 13m hill is:

0.5 mv² + mgh

= 0.5 mv² + 15mg

g = 9.81 m/s/s (acceleration due to gravity).

All of this (assuming no loss due to friction) is converted to potential energy at top of 29m hill

So,

0.5 m v² + 15mg = 29mg

0.5 m v² = 14 mg

v² = (14 × 9.8)/0.5

v² = 274.4

v = 16.56 m/s

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Complete ququestions :  The roller coaster car travels down the helical path at constant speed such that the parametric equations that define its position are x = c sin kt, y = c cos kt, z = h - bt, where c, h, and b are constants. determine the magnitudes of its velocity and acceleration.

  The magnitudes of the  Velocity\((v) = sqrt(c^2 k^2 + b^2)\) and  Acceleration\((a) = sqrt(c^2 k^4)\).

The given parametric equations describe the position of a roller coaster car traveling down a helical path at constant speed. The equations are as follows:   x = c sin(kt)

               y = c cos(kt)

               z = h - bt

In these equations, c, h, and b are constants.

To determine the magnitudes of velocity and acceleration, we need to differentiate the position equations with respect to time.

First, let's differentiate the position equations to find the velocity:                   dx/dt = c kcos(kt)

dy/dt = -c k sin(kt)

dz/dt = -b

The magnitude of the velocity, v, can be calculated using the formula:

\(v = sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2)\)

Substituting the values we obtained earlier:

\(v = sqrt((c k cos(kt))^2 + (-c k sin(kt))^2 + (-b)^2)\)

Simplifying, we have:

\(v = sqrt((c^2 k^2 cos^2(kt)) + (c^2 k^2 sin^2(kt)) + b^2)\)

Simplifying further using the trigonometric identity \(cos^2(x) + sin^2(x) = 1, we get: v = sqrt(c^2 k^2 + b^2)\)

Next, let's differentiate the velocity equations to find the acceleration:

\(d^2x/dt^2 = -c k^2 sin(kt)\)

\(d^2y/dt^2 = -c k^2 cos(kt)\)

\(d^2z/dt^2 = 0\)

The magnitude of the acceleration, a, can be calculated using the formula: a = \(sqrt((d^2x/dt^2)^2 + (d^2y/dt^2)^2 + (d^2z/dt^2)^2)\)

Substituting the values we obtained earlier: \(a = sqrt((-c k^2 sin(kt))^2 + (-c k^2 cos(kt))^2 + 0^2)\)

Simplifying, we have: \(a = sqrt(c^2 k^4 sin^2(kt) + c^2 k^4 cos^2(kt))\)

Again, using the trigonometric identity \(sin^2(x) + cos^2(x) = 1,\)

we get:\(a = sqrt(c^2 k^4)\)

In summary, the magnitudes of the velocity and acceleration are given by:  Velocity (v) = \(sqrt(c^2 k^2 + b^2)\)

   Acceleration \((a) = sqrt(c^2 k^4)\)

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F=m*a

T = 142N

Work = Force x distance

distance = 6.1 M

Force = 142 x cos 37 = 113.4 N

W= 113.4N x 6.1M = 691.78 J

The final momentum of the body is equal to 120 Kg.m/s.

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: \({\displaystyle \mathbf {p} =m\mathbf {v}\) . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

Given the initial momentum of the body = Pi = 20 Kg.m/s

The force acting on the body, Pf = 25 N

The time, Δt = 4-0 = 4s

The Force is equal to the change in momentum: F ×Δt = ΔP

25 × 4 = P - 20

100 = P - 20

P = 100 + 20 = 120  Kg.m/s

Therefore, the final momentum of a body is 120 Kg.m/s.

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Explanation:

A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.

Answer:

The length of the image of the pole is 4/3 m

Explanation:

The given parameters are;

The length of the Pole = 4 m

The type of mirror = Convex mirror

The distance of the pole from the mirror = 2 m

The mirror formula for convex mirrors is presented here as follows;

\(\dfrac{1}{U} - \dfrac{1}{V} = - \dfrac{1}{F}\)

Where;

U = The object (pole) distance from the mirror = 2 m

V = The image of the objects (pole) distance from the mirror

The focal length of the mirror

Therefore, by substitution, we have;

\(\dfrac{1}{2} - \dfrac{1}{V} = - \dfrac{1}{1}\)

\(\dfrac{1}{2} + 1 = \dfrac{1}{V}\)

\(\dfrac{1}{V} = \dfrac{1}{2} + 1 = \dfrac{3}{2}\)

\(V = \dfrac{2}{3}\)

We have;

\(Magnification = \dfrac{Image \ height}{Object \ height } = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{Length \ of \ the \ of \ the \ Pole } =\dfrac{-V}{U}\)

Which by substitution gives;

\(Magnification = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{4} =\dfrac{-\dfrac{2}{3} }{2} = \dfrac{2}{6}\)

\({Length \ of \ the \ Image \ of \ the \ Pole}{} = 4 \times \dfrac{2}{6} = \dfrac{4}{3}\)

The length of the image of the pole = 4/3 m

Answer:

a) ray horizontal and ray leaves his feet

b) The normal line respect to which the angles are measured,

c) The angle x is the reflected angle

d) virtual image,  right image

Explanation:

a) To complete the rays, you must draw a horizontal ray at the height of the man's head, this ray touches the mirror perpendicularly, therefore it bounces in the same direction.

The other ray leaves his feet and touches the mirror at one point, it is reflected with the same angle, by the law of reflection and reaches the eyes of man, the brain creates an extension of this ray and at the point of the floor creates the image point.

b) The normal line is a line perpendicular to the surface with respect to which the angles are measured,

c) The angle x is the reflected angle, which is equal to the incident angle according to the law of reflection

d) The image is formed by the prolongation of the rays of light, therefore it is a virtual image and as it has the same direction of the man it is a right image

Answer:

976,000

I had the same question and got this right

False. Under favourable circumstances, including reaction time, a motor vehicle with good brakes going 50 miles per hour can typically be stopped within a distance of about 140 to 170 feet, not 229 feet.

Reaction time under favorable conditions is the time it takes for a driver to recognize a need to stop and physically apply the brakes. On average, a person's reaction time under favorable conditions is considered to be around 1 to 1.5 seconds.

Reaction time is an important factor in determining the total stopping distance of a vehicle, as it is the time elapsed between recognizing a need to stop and physically applying the brakes.

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10 Newtons of the force is required to accelerate a 5 kg bowling ball at 2 m / s², as we know that the force is calculated by the multiplication of the mass and the acceleration of the object.

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

F = mass × acceleration

As given in the problem we have to calculate how much force in Newtons is required to accelerate a 5 kg bowling ball at 2 m/s² ,

The force required = 5 × 2

                               = 10 Newtons

Therefore, according to Newton's second law, 10 Newtons of the force is required to accelerate a 5 kg bowling ball at 2 m / s².

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#1.mass
#2. 10N
#3. a nonzero net force is acting on it

#4. an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis

#5. The object is at rest

There are the answers for the quick check, hope it helped.

Answer:

The closest distance the negative charge gets to the positive charge is given by the expression:

r = (k * q^2) / (m * v^2)

Explanation:

To find the closest distance the negative charge gets to the positive charge, we can analyze the motion of the negative charge under the influence of Coulomb's attraction.

Given that the negative charge is initially moving with a constant velocity and would miss the center of the fixed positive charge by a perpendicular distance of b, we can consider the perpendicular distance b as the impact parameter.

The motion of the negative charge can be treated as a projectile motion with the Coulomb force acting as a centripetal force. As the negative charge approaches the positive charge, the Coulomb force causes it to deviate from its straight-line path and approach the positive charge.

The closest distance the negative charge gets to the positive charge occurs when the centripetal force due to Coulomb's attraction is equal to the gravitational force acting on the negative charge.

Using the equation for Coulomb's force, we have:

k * (q^2) / r^2 = m * (v^2) / r

Simplifying and rearranging the equation, we get:

r = (k * q^2) / (m * v^2)

Note that this expression assumes the motion occurs in a straight line and the interaction is purely Coulombic. In reality, the motion of the negative charge may be more complex due to other forces and factors.

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Answer:

multiply them together and get ur answer

Explanation:

Answer:

True

Explanation:

Displacement can be considered as a distance with direction when an object moves in straight line. Distance is a scalar quantity which means it has only magnitude but lack of direction. Magnitude basically means how far or how long from the initial startup (e.g 7 km) is magnitude.

On the other hand, displacement is a vector quantity which means it has both magnitude and direction. We can use a symbol of negative and positive to determine the direction. Generally, up is positive; down is negative; west is negative and east is positive but it depends on some case where down can be positive (e.g projectile motion) but you can specify or modify how you want your direction to be, make sure to calculate it right though.

Displacement means changes in position which can be expressed as \(\displaystyle{p_2 -p_1}\) where \(\displaystyle{p_2}\) is final position/destination and \(\displaystyle{p_1}\) is initial position/destination. Displacement does include distance but maybe not total distance if we go for a right-triangle distance. However, displacement includes total distance if an object moves in a straight point. (e.g moving to 20 km straight) - both distance and displacement are same in this case.

Answer: A frame of reference is a reference point combined with a set of directions. A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions. For example, a boy is standing still inside a train as it pulls out of a station.

Explanation: hope this helps!!!!

Scientists have observational evidence of black holes through indirect methods, such as studying the effects of their strong gravitational pull on surrounding matter, detecting X-rays emitted from accretion disks.

Black holes, by definition, cannot be observed directly since no light or information can escape their gravitational pull. However, scientists have gathered compelling evidence for their existence through indirect observations. One such method involves studying the effects of black holes on surrounding matter. As matter falls into a black hole's gravitational field, it forms an accretion disk that emits X-rays detectable by space telescopes. Additionally, the detection of gravitational waves, ripples in spacetime caused by the acceleration of massive objects, provides strong evidence for the existence of black holes. Advanced detectors like LIGO and Virgo have successfully observed gravitational waves generated by black hole mergers, confirming their presence in the universe.

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Answer:

41.52 m

Explanation:

Using,

v = d/t....................... Equation 1

v = speed of pulse of sound, d = distance travelled by the pulse of sound, t = total time taken.

From equation 1, make d the subject of the equation

d = vt............................ Equation 2

Given: t = 0.12 s.

Constant: v = 346 m/s

Susbtitute these values into equation 2

d = 346(0.12)

d = 41.52 m

The section concerning the sloping parts of the tunnel gradually provides an impact to the total amount of work that has to be done on the train by applying  the brakes and the motor due to the gravitational force acting upon the train.

In an incident when the train ranges up a slope as it reaches the station, work is done on the passengers against gravity to lift them to a higher point. When the train travels down a slope as it leaves, gravity helps to pull the train down. The driver applies brakes to stop the train in the station and a motor to make the train move away.

Hence, going up a slope, required more work in comparison to traveling down the slope as in the prior gravity is applied in the opposite force to the direction in which the train is traveling and in the later  the gravity moves in the same direction as the direction of the train.
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Answer:

29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3 s

Find: v

v = at + v₀

v = (9.8 m/s²) (3 s) + 0 m/s

v = 29.4 m/s

Answer:

P₁ = 1.0 atm

V₁ = 35 L

P₂ = 0.75 atm

Formula:

P₁V₁ = P₂V₂

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = (1.0 atm)(35 L) / 0.75 atm

V₂ = 47 L

Final Answer:

V₂ = 47 L

Depending on the value of the, a pipe is either laminar or turbulent. For a 10-m length of pipe, Re = PXD = 0.96 (1.94 #3) (0.5) (12 ft) of pressure drop.

A sound wave is moving through the atmosphere at a speed of 343 m/s. The sound wave has a wavelength of 0.1 cm.

The speed of sound in air at 20 °C (68 °F) is approximately 343 m/s (1,125 ft/s; 1,235 km/h; 767 mph; 667 kn), or 2.91 s for a kilometer and 4.69 s for a mile.

In general, sound travels slowly through gases, quickly through liquids, and quickly through solids.

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The sprinter's changing speed, as well as the speed of any other moving object or person, is displayed on a velocity-time graph. The slope of the graph line on a velocity-time graph is used to represent acceleration.

Velocity's rate of change with time, both in terms of speed and direction. A point or object going straight ahead is accelerated when it accelerates or decelerates. m/s2 is the unit of acceleration. The term "constant acceleration" refers to the pace at which a particle's velocity changes.

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