What is the molar concentration of a solution formed when. 55 mol of Ca(OH)2 are dissolved in 2. 20 liters of HOH?

Answer:

Yeah u valid

Explanation:

Answer

Explanation

The reaction between Ca(OH)₂ and HCl is a neutralization reaction. Ca(OH)₂ is a base and HCl is an acid, their reaction will produce salt and water.

The balanced chemical equation of the reaction is shown below:

Answer:

It is in the same phase as the reactants.

Explanation:

i took the test

The energy released when adding an electron is the energy released in the atomization reaction. This energy is called electron affinity. The electron affinity of Si is 133.6 KJ/mol.

Electron affinity of an atom is its tendency to capture an electron from other atoms towards its nucleus. The more the electron affinity the more will be its reactivity.

The minimum energy required to remove a loosely bound electron from the valence orbital is called its ionization energy. In the given reaction, silicon is accepting an electron to form its atomic state. Thus, it is releasing the energy.

This energy released during gaining one electron is equal to the electron affinity of silicon that is 133.6 kJ/mol.

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Answer:

2Mg+O=2MgO

Explanation:

32gram of reacting

Answer:

Mass = 17.8 g

Explanation:

Given data:

Number of atoms of Ca = 2.68 × 10²³

Mass in gram = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.68 × 10²³ atoms × 1 mole  /6.022 × 10²³ atoms

0.445 mol

Mass in gram;

Mass = number of moles ×  molar mass

Mass = 0.445 mol  ×  40 g/mol

Mass = 17.8 g

Answer:

no it is not a complete model

Answer:

Explanation:simple 1s22s22p63s23p1

short form [Ne] 3s23p1

orbital energy diagram

The ground state electronic configuration, 1s22s22p63s23p645' is of potassium in the periodic table. Option C is correct.

A periodic table is an arrangement done by Mosley for better learning and understanding of the physical and chemical properties of an element and to know about the electronic configurations of the elements.

In potassium the arrangement of electrons in the shells of s, p, d, and f are 1s22s22p63s23p645' and these shells contain different energies and this is the stable electronic configuration that means at the ground state for the element.

Therefore, Option C is correct. The  ground state electronic configuration, 1s22s22p63s23p645' is of potassium in the periodic table.

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Answer:

it keeps the heat in and the bugs and flys out

Explanation:

Bones can be classified based on their shape. There are five classifications of bone based on shape. These categories are as follows: long bones, short bones, flat bones, irregular bones, and sesamoid bones.

In order to determine the classification of a bone, we need to identify its shape. Therefore, we cannot determine the classification of a bone unless we know its shape. The shape of a bone is important because it can tell us a lot about its function. For example, long bones are found in the limbs and are responsible for providing support and leverage. Short bones are found in the hands and feet and are responsible for providing stability and support. Flat bones are found in the skull and are responsible for protecting the brain. Irregular bones are found in the spine and are responsible for providing support and flexibility. Sesamoid bones are found in the knees and are responsible for protecting the tendons.

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1) To determine the solubility of potassium chloride at different temperatures, we can refer to a solubility curve for potassium chloride. Unfortunately, since the solubility curve is not provided, I cannot give you the exact solubility values at 80°C and 40°C. Solubility is typically given in grams of solute per 100 grams of solvent (usually water) at a specific temperature.

2) To calculate the mass of potassium chloride that would crystallize out of solution, we need to determine the difference in solubility between 80°C and 40°C. Let's assume that at 80°C, the solubility of potassium chloride is 50 g/100 g of water, and at 40°C, the solubility is 30 g/100 g of water.

The initial amount of potassium chloride in the solution is 50 g (saturated solution in 100 g of water at 80°C). At 40°C, the solubility decreases to 30 g/100 g of water.

The amount of potassium chloride that crystallizes out can be calculated by subtracting the final solubility from the initial amount:

50 g - 30 g = 20 g

Therefore, 20 grams of potassium chloride would crystallize out of the solution when cooled from 80°C to 40°C.

Moderates weather so that highs and lows are less extreme because of sea breeze motion.

Sea breeze are that as the warm air from the land is rising and the cooler air from the ocean is flowing over land and will replace the warmer air that is rising. in simple words , land gets warmer during the day than the water and the hot air rising up and cooler air move towards the land  called as sea breeze. moderate weather is refers to that weather which is neither very cold nor very hot.

Thus, Moderate weather so that highs and lows are less extreme because of sea breeze motion.

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To calculate the Ksp value in the presence of ion activity, it is necessary to measure the ion product at the point of saturation for multiple compounds. The ion product nears the Ksp value at lower temperatures due to lower ionic strength, and a table is finally used to determine the Ksp Value.

The solubility product is calculated by multiplying the molar concentration of ions in chemical reactants by the number of ions produced by each chemical component in a saturated solution.The solubility product is the result of multiplying the amount of ions produced by each chemical component in a saturated solution by the molar concentration of ions present in two or more chemical reactants.The ion activity refers to the concentration of ions in a solution, and it is an important factor to consider when calculating the ksp value.

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Answer:

A piece of gold foil was hit with alpha particles, which have a positive charge. Most alpha particles went right through. This showed that the gold atoms were mostly empty space. Some particles had their paths bent at large angles. A few even bounced backward. The only way this would happen was if the atom had a small, heavy region of positive charge inside it.

c) positively charged and relatively small.

It will take approximately 196 years for a 70-mg sample of strontium-90 to decay to a mass of 56 mg.

Radioactive decay is a process in which unstable atomic nuclei lose energy by emitting radiation. The rate at which radioactive decay occurs can be described using a parameter called the half-life. The half-life is the time it takes for half of the radioactive material to decay.

In this case, the half-life of strontium-90 is given as 28 years. This means that after 28 years, half of the initial amount of strontium-90 will decay.

To calculate the time it takes for the sample to decay to a mass of 56 mg, we can use the concept of half-lives.

Initially, we have a 70-mg sample of strontium-90. After the first half-life of 28 years, the mass will be reduced to 35 mg (half of 70 mg). After the second half-life, it will be reduced to 17.5 mg (half of 35 mg). This process continues until we reach a mass of 56 mg.

By calculating the number of half-lives required to reach a mass of 56 mg, we can determine the time it takes.

Starting with 70 mg, we need to divide it by 2 repeatedly until we reach 56 mg:

70 mg ÷ 2 = 35 mg

35 mg ÷ 2 = 17.5 mg

17.5 mg ÷ 2 = 8.75 mg

8.75 mg ÷ 2 = 4.375 mg

4.375 mg ÷ 2 = 2.1875 mg

2.1875 mg ÷ 2 = 1.09375 mg

1.09375 mg ÷ 2 = 0.546875 mg

0.546875 mg ÷ 2 = 0.2734375 mg

It takes a total of 7 half-lives to reach a mass of approximately 56 mg. Since each half-life is 28 years, we multiply the number of half-lives by the length of each half-life:

7 half-lives × 28 years/half-life = 196 years

Therefore, it will take approximately 196 years for a 70-mg sample of strontium-90 to decay to a mass of 56 mg.

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"To insure proper operation of an oxygen cylinder regulator, make sure no oil residue is present" is true because oil residue can compromise the functioning of an oxygen cylinder regulator.

Explanation: It is true that to ensure proper operation of an oxygen cylinder regulator, it is important to make sure that no oil residue is present. Oxygen cylinders contain highly concentrated oxygen that can react violently with oil or grease, leading to combustion or explosions. Oil residue can contaminate the regulator and pose a significant safety risk.

Therefore, it is crucial to keep oxygen cylinders and their regulators free from any oil or grease to maintain safe and proper functioning.

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Answer:

The reason is carbon's ability to form stable bonds with many elements, including itself. 

Explanation:

This property allows carbon to form a huge variety of very large and complex molecules. In fact, there are nearly 10 million carbon-based compounds in living things!

Answer:

Explanation:

The reason is that carbon is able to form stable bonds with many elements, including itself, which allows carbon to form a huge variety of very large and complex molecules.

Answer:

Covalent bonds usually occur between nonmetals.

Explanation:

Answer:

hope you like it

Explanation:

No, your refreshing glass of water won't spontaneously combust. Water is made up of two elements, hydrogen and oxygen. Hydrogen is flammable, but oxygen is not. ... You can, however, break it down into hydrogen and oxygen by putting energy into it, in the form of an electric current.

The chemical formula of the ionic compound is XY₂.

During the formation of the ionic compound between an ion X that has a charge of 2+ and ion Y has a charge of 1-, two negatively charged ions of Y are required to form a neutral ionic ionic compound when they react with X.

The chemical the formula of the ionic compound they form is as follows;

X²⁺  + 2Y⁻ ---> XY₂

Therefore, the chemical formula of the ionic compound is XY₂.

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Different rock and mineral ,soil profile

Answer:

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

We usually balance O and H atoms last.

AsCl₃ + H₂S → As₂S₃ +HCl

reactants

As --- 1

Cl --- 3

H --- 2

S --- 1

products

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

reactants

As --- 2

Cl --- 6

H --- 2

S --- 1

products

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

reactants

As --- 2

Cl --- 6

H --- 6

S --- 3

products

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

reactants

As --- 2

Cl --- 6

H --- 6

S --- 3

products

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

Answer:

33.085476 meV ≈ 33 meV

Explanation:

Hope this helped!

Answer:

After the reaction, the total mass of the products must be D. Less than 10.0 grams

The order of increasing atomic size is: F, Cl, K, Cs.

The atomic size or atomic radius is the distance between the nucleus and the outermost shell of an atom. The atomic size generally increases down a group and decreases across a period on the periodic table.

The given elements are F (fluorine), Cl (chlorine), K (potassium), and Cs (cesium).

Fluorine (F) has the smallest atomic radius because it is the top element of group 17 (halogens) and has the highest effective nuclear charge (the attractive force experienced by the valence electrons towards the nucleus). Chlorine (Cl) has a larger atomic radius than F because it is located below F in the same group.

Potassium (K) has a larger atomic radius than Cl because it is located in group 1 (alkali metals) below Cl. Finally, cesium (Cs) has the largest atomic radius among the given elements because it is located at the bottom of group 1 and has the least effective nuclear charge. Therefore, the order of increasing atomic size is F < Cl < K < Cs.

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No, but Group 1 elements can. Group 1 elements (alkali metals such as Li, Na, K...) all have one valence electron that they donate when forming ionic bonds. This will cause them to have a charge of +1.

Answer:

Explanation:

I HOPE IT HELPS :) VERY MUCH

If we have 10 moles of NaN3, we would produce more N2 than Na.



When NaN3 is heated, it decomposes into Na and N2 gas according to the following balanced equation:

2 NaN3(s) → 2 Na(s) + 3 N2(g)

From the equation, we can see that for every 2 moles of NaN3, we would produce 2 moles of Na and 3 moles of N2. Therefore, if we have 10 moles of NaN3, we would produce:

- 10 moles of NaN3 × (2 moles of Na / 2 moles of NaN3) = 10 moles of Na
- 10 moles of NaN3 × (3 moles of N2 / 2 moles of NaN3) = 15 moles of N2

This means that we would produce more N2 (15 moles) than Na (10 moles).

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The absorbance of the buffered indicator solution can be calculated using the equation above.

To calculate the absorbance of an unbuffered indicator solution and a buffered indicator solution, we need to use the Beer-Lambert Law, which relates the absorbance (A) of a solution to the molar absorptivity (ε), the path length (b), and the concentration (c) of the absorbing species.

The Beer-Lambert Law can be written as:

A = ε * b * c

Given:

ε(HIn) = 7120 M^(-1)cm^(-1)

ε(In) = 961 M^(-1)cm^(-1)

b = 1.00 cm

Total indicator concentration = 8.0 * 10^(-5) M

(a) For an unbuffered indicator solution:

We need to calculate the absorbance using the molar absorptivity of the weak acid form (HIn).

c(HIn) = Total indicator concentration = 8.0 * 10^(-5) M

A(HIn) = ε(HIn) * b * c(HIn)

= 7120 M^(-1)cm^(-1) * 1.00 cm * 8.0 * 10^(-5) M

= 0.5696

Therefore, the absorbance of the unbuffered indicator solution is 0.5696.

(b) For a buffered indicator solution:

To calculate the absorbance, we need to consider the equilibrium between the weak acid form (HIn) and its conjugate base (In) using the Henderson-Hasselbalch equation:

pH = pKa + log([In]/[HIn])

Given:

pH = 6.5 (buffered solution)

K_a = 1.42 * 10^(-5)

From the Henderson-Hasselbalch equation, we can solve for the ratio [In]/[HIn]:

[In]/[HIn] = 10^(pH - pKa)

= 10^(6.5 - (-log10(K_a)))

= 10^(6.5 + 5.85)

= 10^(12.35)

Since [HIn] + [In] = Total indicator concentration, we can express [HIn] in terms of [In]:

[HIn] = Total indicator concentration / (1 + [In]/[HIn])

= Total indicator concentration / (1 + 10^(12.35))

Substituting the values into the Beer-Lambert Law equation for the buffered solution:

A = ε(HIn) * b * [HIn]

= 7120 M^(-1)cm^(-1) * 1.00 cm * (Total indicator concentration / (1 + 10^(12.35)))

A = 7120 M^(-1)cm^(-1) * 1.00 cm * (8.0 * 10^(-5) M / (1 + 10^(12.35)))

Therefore, the absorbance of the buffered indicator solution can be calculated using the equation above.

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The little compartments are mostly likely cells, so C and D can be eliminated. Since one must zoom in to see cells, the image is most likely not large enough to be able to identify the organism. Therefore, my best guess would be B.) Cells of a multicellular organism.

I hope this helped you come to a conclusion!