Answer:
1 / 3 or 0.33
that is if you meant that the object accelerates at 3 m / s² not 3 m / s
for the unit of acceleration is m / s²
Explanation:
m = ?
a = 3
f = 1N
where;
m = mass ( kg )
a = acceleration ( m / s² )
f = force ( N )
from all the parameters we are given, we can use Newton's second law of motion to solve it
that is;
a = f / m
to make m the subject of the formula, we have to cross multiply to give us;
m( a ) = f
divide through by a to give us;
m ( a ) / a = f / a
therefore,
m = f / a
so, we substitute our values to give us;
m = 1 / 3
therefore. m = 1 / 3 or 0. 33
hope this helps
thank you!!!!
experiment 1: where did the extra mass come from? (hint: the final product is magnesium oxide.)
The extra mass of the magnesium oxide comes from then magnesium nitride that is also formed.
What causes the extra mass?If we look at the law of the conservation of mass, we know from that very law that the masses of the substances at the beginning of the reaction must be the same as the masses of the substances at the end of the reaction and this is because the mass of the reaction is conserved.
Given the fact that magnesium does combine with nitrogen to give magnesium nitride in the reaction then the mass of the product would be higher.
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a 0.60 kg book slides on a horizontal table. the kinetic friction force on the book has magnitude 1.9 n .the book now slides 3.6 m to the right, returning to its starting point. during this second 3.6 m displacement, how much work is done on the book by friction?
The amount of work done on the book by friction during its second 3.6 m displacement is 13.68 J.
To calculate the work done on the book by friction during its second 3.6 m displacement, we need to use the equation W = Fd, where W is the work done, F is the force applied, and d is the displacement.
We know that the kinetic friction force on the book has a magnitude of 1.9 N and that the book slides 3.6 m to the right and then returns to its starting point, so the total displacement is 7.2 m (3.6 m + 3.6 m).
To find the work done on the book by friction during this displacement, we can use the formula W = Fd. Plugging in the values, we get:
W = (1.9 N)(7.2 m)
W = 13.68 J
Therefore, the work done on the book by friction during its second 3.6 m displacement is 13.68 J.
In simpler terms, the friction force is constantly opposing the book's motion, causing it to slow down and eventually stop. As the book slides to the right and then returns to its starting point, the friction force is constantly acting in the opposite direction, resulting in negative work being done on the book. This negative work results in a decrease in the book's kinetic energy, causing it to eventually come to a stop. The amount of work done on the book by friction during this process is calculated using the formula W = Fd.
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a toy cork gun contains a spring whose spring constant is 18n/m. the spring is compressed 7.47 cm and then used to propel a 9 cork. the cork, leaves the spring from the spring's relaxed length. with what speed, in m/s, does the cork leave the spring?
The cork leaves the spring at a speed of 3.02 m/s.
We can use the conservation of energy to determine the speed at which the cork leaves the spring.
The initial potential energy stored in the spring is converted to the kinetic energy of the cork as it leaves the spring. Neglecting air resistance, the conservation of energy equation is:
(1/2) k x^2 = (1/2) m v^2
where k is the spring constant, x is the distance the spring is compressed, m is the mass of the cork, and v is the speed of the cork as it leaves the spring.
Substituting the given values:
(1/2) * 18 N/m * (7.47 cm / 100 cm/m)^2 = (1/2) * 0.009 kg * v^2
Solving for v:
v^2 = (18 N/m * (7.47 cm / 100 cm/m)^2) / 0.009 kg
v^2 = 9.119 m^2/s^2
Taking the square root of both sides:
v = 3.02 m/s
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Q1 b name the three tiny particles which make up atoms ? a write the charge alongside each one ?
Answer:
Protons
Neutrons
Electrons.
Protons + charge(positively charged)
Neurons no charge.
Electrons - ( negatively charged).
Explanation:
Atom is the smallest unit of a matter that constitutes chemical elements.
It is composed of three particles which are protons,neutrons and electrons.
Protons is positively charged,neuron has no charge and electrons is negatively charged.
Proton and neuron are found in the nucleus while electron is found outside the neuron.
What is the impulse experienced by a 24kg dog as he speeds up from 2m/s to 6m/s
Given
m = 24kg
vi = 2 m/s
vf = 6 m/s
Procedure
Impulse = Change in momentum
\(\begin{gathered} I=m\Delta v \\ I=m(v_f-v_i) \\ I=24\cdot(6-2) \\ I=96\operatorname{kg}m/s \end{gathered}\)The answer would be I = 96 kg*m/s
help needed for assignment
Answer: acceleration is when speed increase
Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the two naturally occurring electrons is removed. The radius of the orbit is 2.65 10-11 m. Determine the magnitude of the electron's centripetal acceleration.
? m/s2
The answer are magnitude of the electron's centripetal acceleration is 1.96 x 10^22 m/s^2
Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the two naturally occurring electrons is removed. The radius of the orbit is 2.65 10-11 m. To determine the magnitude of the electron's centripetal acceleration,
We can use the formula for centripetal acceleration:
a = v^2 / r
Where a is the centripetal acceleration, v is the velocity of the electron, and r is the radius of the orbit.
We can also use the formula for the force on an electron in an electric field:
F = kq1q2 / r^2
Where F is the force, k is the Coulomb constant, q1 and q2 are the charges of the electron and the nucleus, and r is the radius of the orbit.
Since the force on the electron is equal to the product of its mass and its centripetal acceleration, we can set the two formulas equal to each other:
mav^2 / r = kq1q2 / r^2
Solving for the centripetal acceleration, we get:
a = kq1q2 / (mr)
Plugging in the values for the charges of the electron and the nucleus, the Coulomb constant, the mass of the electron, and the radius of the orbit, we get:
a = (8.99 x 10^9 Nm^2/C^2)(1.6 x 10^-19 C)(3.2 x 10^-19 C) / ((9.11 x 10^-31 kg)(2.65 x 10^-11 m))
a = 1.96 x 10^22 m/s^2
Therefore, the magnitude of the electron's centripetal acceleration is 1.96 x 10^22 m/s^2.
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fill in the blank ,if a charge body touches the disc of an uncharged electroscope the leaves ------------------
Answer:
leaves will deverge
Explanation:
because of the nagwtive charge will become positive
According to Ohm’s law, which combination of units is the same as the unit for voltage?
ohm ÷ ampere
ampere × ohm
ohm + ampere
ampere ÷ ohm
Answer:
ampere × ohm
Explanation:
Ohm's law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance of the resistor. Mathematically, this can be expressed as:
V = IR
where:
V is the voltage across the resistor in voltsI is the current through the resistor in amperesR is the resistance of the resistor in ohmsSince voltage is equal to current multiplied by resistance.
and their unit will be ampere*ohm
So,
The combination of units which is the same as the unit for voltage is ampere*ohm.
Answer and Explanation:
According to Ohm's law, the unit for voltage is the same as the combination of units "ampere × ohm".
Ohm's law states that voltage (V) is equal to the current (I) multiplied by the resistance (R), which can be represented as V = I × R.
The unit for current is ampere (A), and the unit for resistance is ohm (Ω).
When we multiply ampere by ohm, we get the unit for voltage. This can be seen in the equation V = I × R, where the unit for voltage is equal to the unit for current multiplied by the unit for resistance.
Therefore, the correct combination of units that is the same as the unit for voltage is "ampere × ohm".
Which fundamental force is very strong across a short distance?
A. Electromagnetic
B. Strong nuclear
C. Gravitational
D. Weak nuclear
Increased temperature causes the length of a material to increase because: a Atoms are getting larger b Bonds get weaker so atom vibration amplitude increases c Atom vibration amplitude increases asymmetrically d Bond strength of valence electrons decrease e Atom's electron clouds become fuzzier Warm forming is a process that increases the temperature of a material so that it may be more easily shaped. Assume that in this process the heating device, such as a furnace, is able to pass an equal amount of energy in a fixed time to each of the following materials. Which material would be expected to have the highest temperature? a Copper (cp = 386 J/kg*K) b Aluminum (cp = 900 J/kg*K) c Brass (cp = 375 J/kg*K) d Invar (63Fe-36Ni, cp = 500 J/kg*K)
Brass (cp = 375 J/kg*K) would be expected to have the highest temperature . (C)
Increased temperature causes the length of a material to increase because the bonds get weaker so atom vibration amplitude increases.
This is due to the fact that as temperature increases, the atoms in a material begin to move around more and the bonds between them become weaker. This allows for the atoms to vibrate more, causing an increase in the length of the material.
In the warm forming process, the material with the lowest specific heat capacity (cp) would be expected to have the highest temperature.
This is because the specific heat capacity is a measure of the amount of energy required to raise the temperature of a material by one degree. The lower the specific heat capacity, the less energy is required to raise the temperature, and therefore the higher the temperature will be.
Out of the materials listed, brass has the lowest specific heat capacity at 375 J/kg*K, meaning that it would require the least amount of energy to raise its temperature and would therefore have the highest temperature.
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How do interaction forces act on different masses and on different objects?
Dosen't make sense
Explanation:
TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.
the nebular hypothesis of star formation predicts that planet formation is a natural consequence of star formation. as a cloud contracts it heats up and spins faster; the faster rotation causes the cloud to fling material out into a protoplanetary disk. if the nebular hypothesis is correct, all star systems should have planets, yet none are currently known to exist in the boodle system. the most likely explanation is that no one has bothered to look for planets orbiting boodle. why might an astrobiologist ignore stars like boodle in the search for habitable worlds?
Astrobiologists tend to focus their search on stars that are similar to our own sun, as these are more likely to have conditions that support life. Boodle, being a relatively unknown star, may not be a priority for astrobiologists in the search for habitable worlds.
The nebular hypothesis of star formation predicts that planets should form around all stars. However, this hypothesis is yet to be proven, and there may be other factors at play that affect planet formation. Additionally, the current technology for detecting planets is limited, and it is possible that planets around stars like Boodle may have been overlooked.
Furthermore, astrobiologists tend to focus their search on stars that are similar to our own sun, as these are more likely to have conditions that support life. Boodle, being a relatively unknown star, may not be a priority for astrobiologists in the search for habitable worlds. Therefore, while the nebular hypothesis predicts that planets should form around all stars, the search for habitable worlds is more focused on stars that are similar to our own sun and have a higher likelihood of supporting life.
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If I release a golf ball at a height of 31 cm and a length of 31 cm the mass is equal to 45.93 g what is theKinetic energy
When a ball is at a particular height it possess potential energy which is given as,
\(U=\text{mgh}\)The potential energy is converted into kinetic energy of the ball. According to conservation of energy,
\(K=U\)which can be further given as,
\(K=\text{mgh}\)Substitute the known values,
\(\begin{gathered} K=(45.93\text{ g)(}\frac{1\text{ kg}}{1000\text{ g}})(9.8m/s^2)(31\text{ cm)(}\frac{1\text{ m}}{100\text{ cm}})(\frac{1\text{ J}}{1kgm^2s^{-2}^{}}) \\ =0.140\text{ J} \end{gathered}\)Thus, the kinetic energy of the ball is 0.140 J.
how do the sun and moon work together to create a neap tide?
Answer:
Neap tide, which also occour twice a month. It happens when sun and moon are right angle to each other.
Explanation:
In both cases, the gravitational pull of the sun is “added”to the gravational pull of the moon on the Earth.
1) What are the x- and y-components of vector d (magnitude 100 m and at 45 degrees south of east)?
The x- and y-components of vector d (magnitude 100 m and at 45 degrees south of east) is x- component \(50 \sqrt{2}$\) and y- component is \(50 \sqrt{2}$\).
A. x component\($=100 \sin 45^{\circ}\)
\(100 \sin \left(45^{\circ}\right)$$\)
Use the following trivial identity: \($\quad \sin \left(45^{\circ}\right)=\frac{\sqrt{2}}{2}$\)
\(=100 \cdot \frac{\sqrt{2}}{2}$$\)
\(100 \cdot \frac{\sqrt{2}}{2}=50 \sqrt{2}$$\)
\($$=50 \sqrt{2}$$\)
y component \($=100 \cos 45^{\circ}\)
\($$100 \cos \left(45^{\circ}\right)$$\)
Use the following trivial identity: \($\quad \cos \left(45^{\circ}\right)=\frac{\sqrt{2}}{2}$\)
\($$=100 \cdot \frac{\sqrt{2}}{2}$$\)
\($$\begin{aligned}&100 \cdot \frac{\sqrt{2}}{2}=50 \sqrt{2} \\&=50 \sqrt{2}\end{aligned}$$\)
A quantity with both magnitude and direction is called a vector. In contrast to a scalar number, a vector quantity also includes a direction component that aids in locating one location in relation to another.
A vector in mathematics is a number that not only defines magnitude but also indicates how an item moves or is positioned in relation to other points or objects. It is sometimes referred to as a spatial vector, geometric vector, or Euclidean vector.
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A plank 3.8 m long and weighing 124 N has its left end resting on a block and the other end supported by a rope. The plank is in the horizontal position. If the greatest tension the rope can withstand is 414 N, how far from the block can a 63.2 kg girl walk out on the plank before the rope breaks
Using the concept of torque, the girl can walk out 1.52 m on the plank before the rope breaks.
The rotating force or moment of a force around a particular axis or pivot point is measured by torque. The tendency of a force to cause an object to spin along an axis is described as a vector quantity, torque.
We need to consider the torque exerted by the girl's weight and the tension in the rope.
The torque equation is given by:
τ = F × d where:τ is the torque, F is the force, and d is the distance from the pivot point.
In this case, the torque due to the girl's weight is balanced by the torque due to the tension in the rope.
The weight of the girl is
Weight = 63.2 kg * 9.8 = 619.36 N
Assuming the girl walks out on the plank at a distance of x m from the block.
The torque due to her weight is τ₁ = Weight × x
The maximum tension the rope can withstand is 414 N, so the torque due to the tension in the rope is: τ₂ = Tension * (3.8 - x)
To find the maximum distance the girl can walk out on the plank before the rope breaks, we need to set the torques equal to each other:
τ₂ = τ₁
Weight × x = Tension × (3.8 - x)
putting all the values in the above equation
619.36 × x = 414 × (3.8 - x)
x = 1.52 m
Therefore, The girl can walk out 1.52 m on the plank before the rope breaks.
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A 20 MHz uniform plane wave travels in a lossless material with the following features:
student submitted image, transcription available below
Calculate (remember to include units):
a) The phase constant of the wave.
b) The wavelength.
c) The speed of propagation of the wave.
d) The intrinsic impedance of the medium.
e) The average power of the Poynting vectorr or Irradiance, if the amplitude of the electric field Emax = 100V/m.
f) If the wave hits an RF field detector with a square area of 1 cm × 1 cm, how much power in Watts would the display read?
To calculate the various quantities for a 20 MHz plane wave in a lossless material, let's go through each part step by step:
a) The phase constant (β) of the wave can be calculated using the formula:
β = 2πf/v,
where f is the frequency (20 MHz) and v is the velocity of propagation.
b) The wavelength (λ) can be determined using the formula:
λ = v/f,
where f is the frequency (20 MHz) and v is the velocity of propagation.
c) The speed of propagation (v) can be calculated using the formula:
v = λf,
where λ is the wavelength and f is the frequency (20 MHz).
d) The intrinsic impedance (Z) of the medium is given by the formula:
Z = sqrt(μ/ε),
where μ is the permeability of the medium and ε is the permittivity of the medium. Since the medium is lossless, both μ and ε are constant values.
e) The average power of the Poynting vector or irradiance can be calculated using the formula:
Pavg = 0.5 * ε * Emax^2,
where ε is the permittivity of the medium and Emax is the maximum electric field amplitude (100 V/m).
f) To calculate the power detected by an RF field detector with a square area of 1 cm × 1 cm, we need to calculate the intensity (power per unit area). The power detected will depend on the orientation and alignment of the detector with respect to the wave. If we assume the detector is perfectly aligned and perpendicular to the wave, the power detected can be calculated by multiplying the intensity (Pavg/A), where Pavg is the average power calculated in part (e), and A is the area of the detector (1 cm × 1 cm).
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paper craft wall hanging how is it ?
Answer:
Nice
Explanation:
Valu Food Market is an incorporated cooperative. Like other incorporated cooperatives, Valu Food distributes profits to its owners on the basis of Group of answer choices their transactions with the cooperative. the requirements of the state in which it was incorporated. the degree to which they participate in management. the amount of capital they contribute.
Valu Food Market, as an incorporated cooperative, distributes profits to its owners on the basis of the degree to which they participate in management.
In incorporated cooperatives, the distribution of profits to owners is typically based on their level of participation in the management of the cooperative. This means that the more involved an owner is in the cooperative's management and decision-making processes, the greater their share of the profits.
Cooperatives are unique business entities that prioritize the democratic participation of their members. The degree of involvement in management can vary among owners, with some actively participating in decision-making, attending meetings, and taking on leadership roles, while others may have a more passive involvement.
The principle of democratic control is a fundamental aspect of cooperative governance. It ensures that owners have a say in the cooperative's operations and that profits are distributed based on their level of active participation. This approach reflects the cooperative's commitment to fairness and equal representation.
Incorporated cooperatives, including Valu Food Market, distribute profits to their owners based on the degree to which they participate in the management of the cooperative. This system encourages active involvement and ensures that owners who actively contribute their time, knowledge, and effort in managing the cooperative are rewarded accordingly. It reinforces the democratic principles upon which cooperatives are built and fosters a sense of ownership and collective responsibility among the cooperative's members.
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one afternoon, huyen and phong go outside after it stops raining. the sun comes out, and when they look up, they can see a rainbow. huyen knows that the different colors of light in the rainbow come from waves that have different wavelengths. if each color has a different wavelength, why are huyen and phong able to see all of the different colors at the same time?
Answer: The light waves result in colors that blend together
Question 27
What would be easier for someone with a negative Weber slope for weight detection?
A. Telling the difference between 1 pound and 2 pounds
B. Telling the difference between 10 pound and 11 pounds
C. Telling the difference between 20 pound and 21 pounds
D. No weight discriminations could be made
For someone with a negative Weber slope for weight detection, it would be easier to tell the difference between 20 pounds and 21 pounds.
The Weber's Law states that the just noticeable difference (JND) between two stimuli is proportional to the magnitude of the stimuli. A negative Weber slope indicates that the JND decreases as the magnitude of the stimuli increases. In this case, as the weight increases, the person's ability to discriminate between the weights becomes easier.
Therefore, option C, telling the difference between 20 pounds and 21 pounds, would be easier for someone with a negative Weber slope for weight detection.
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29.92 inches of mercury and 101,325 pascals are both equivalent to 1 atmosphere of pressure. Calculate the number of pascals equivalent to 1 inch of mercury.
The number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
From the question given above, we were told that:
29.92 inches of mercury = 1 atm
101325 pascal = 1 atm
Thus,
29.92 inches of mercury = 101325 pascal
With the above information, we can obtain the number of pascal equivalent to 1 inch of mercury. This can be obtained as follow:29.92 inches of mercury = 101325 pascal
Therefore,
1 inches of mercury = 101325 / 29.92
1 inches of mercury = 3386.53 pascalThus, the number of pascal equivalent to 1 inch of mercury is 3386.53 pascal
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Use the drop-down menu to answer the question. "Take a Closer Look" shows the Hubble telescope. Where is the Hubble telescope located?
Answer:
space
Explanation:
I got it right on E d i n u i t y
A space telescope called the Hubble was put into low-Earth orbit. Therefore, Hubble telescope is located in space.
What is Hubble telescope?A space telescope called the Hubble was put into low-Earth orbit around 1990 and continues to be in use today. Although it wasn't the initial space telescope, it is one of the biggest and most useful ones. It is famous for being both an essential scientific instrument and a public relations success for astronomy.
One of NASA's Big Observatories, the Hubble telescope being dedicated after astronomer Edwin Hubble. Hubble's targets are chosen by the Space Telescope Scientific Institute, which also handles the data processing, while the spacecraft is managed by the Goddard Space Flight Center at NASA. Hubble telescope is located in space.
Therefore, Hubble telescope is located in space.
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An argon gas processor has a first cost of $20,000 with a $5,000 salvage value after 5 years. What is the Book Value at year 3;BV3=? Select one: a. BV3= $13,000 b. BV3= $10,000 c. BV3= $12,000 d. BV3= $11,000 An argon gas processor has a first cost of $20,000 with a $5,000 salvage value after 5 years. What is the Depreciation at year 3, D3=? Select one: a. D3= $4,000 b. D3= $3,000 c. D3= $2,000 d. D3= $5,000
To calculate the book value at year 3 (BV3), we need to determine the accumulated depreciation at year 3. The depreciation is calculated by subtracting the salvage value from the initial cost and dividing it by the number of years.
Initial cost: $20,000
Salvage value: $5,000
Number of years: 5
Depreciation per year = (Initial cost - Salvage value) / Number of years
Depreciation per year = ($20,000 - $5,000) / 5 = $3,000
Accumulated depreciation at year 3 = Depreciation per year * Number of years
Accumulated depreciation at year 3 = $3,000 * 3 = $9,000
Book value at year 3 = Initial cost - Accumulated depreciation at year 3
Book value at year 3 = $20,000 - $9,000 = $11,000
Therefore, the Book Value at year 3 (BV3) is $11,000 (option d).
To calculate the depreciation at year 3 (D3), we can simply use the depreciation per year, which is $3,000. Therefore, the Depreciation at year 3 (D3) is $3,000 (option b).
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Star A and star B appear equally bright, but star A is twice as far from us as star B. Which of the following is true?
a. Star A is twice as luminous as star B
b. Star A is four times as luminous as star B
c. Star B is twice as luminous as star A
d. Star B is four times as luminous as star A
e. Star A and star B have the same luminosity because they have the same apparent brightness
The correct answer is e. Star A and star B have the same luminosity because they have the same apparent brightness.
Apparent brightness refers to how bright a star appears to an observer on Earth. It is determined by the amount of light received per unit area on Earth's surface. Apparent brightness decreases with increasing distance from the observer, following the inverse square law.
Luminosity, on the other hand, refers to the total amount of light energy emitted by a star per unit time. It is an intrinsic property of the star and represents its true brightness.
In this scenario, since both star A and star B appear equally bright to us, it means they have the same apparent brightness. However, the fact that star A is twice as far from us as star B implies that star A must be emitting four times the amount of light energy to appear equally bright at that distance. This is because the apparent brightness decreases with distance squared.
Mathematically, the relationship between luminosity (L), distance (d), and apparent brightness (B) can be expressed as:
B = L / (4πd^2)
Given that star A and star B have the same apparent brightness, it means their luminosities must be equal. If star A were twice as luminous as star B, it would appear brighter than star B. Similarly, if star B were twice or four times as luminous as star A, it would appear brighter than star A.
Therefore, the correct answer is e. Star A and star B have the same luminosity because they have the same apparent brightness.
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A bowling ball is thrown at a distance of 0.5 m toward the pins. If it takes the
bowling ball 2.3 seconds to reach the pins, what is the speed of the bowling
ball?
Answer:
Speed = 0.217 m/s
Explanation:
Given the following data;
Distance = 0.5m
Time = 2.3 seconds
To find the speed;
Speed = distance/time
Speed = 0.5/2.3
Speed = 0.217 m/s
Therefore, the speed of the bowling
ball is 0.217 meter per seconds.
the third kepler law: relationship between the distance from the sun and the orbital period for a planet. we discussed the third kepler law in class. scientists are still using telescopes to observe the space beyond neptune in our solar system. in principle, it is possible that scientists will find astronomical bodies larger than eris/pluto in the future. let us assume that a new planet with an orbital period ~ 6548 years is discovered in our solar system. please take earth as a reference and calculate the average distance from the sun for the newly-discovered planet in our solar system.A. ∼200AUB. ∼220AUC. ∼240AUD. ∼260AU
According to the Third Kepler Law, the average distance from the Sun (A) is directly proportional to the cube root of the orbital period (T). So, for a new planet with an orbital period of 6548 years, we can calculate the average distance (A) using the equation: A = (T^(1/3)) x (A_earth^(2/3)), where A_earth is the average distance of the Earth from the Sun, which is approximately 150 million km.
Plugging in the given values, we get: A = (6548^(1/3)) x (150x10^6 km)^(2/3) = ∼260AU.
Therefore, the average distance from the Sun for the newly-discovered planet in our solar system is ∼260AU.
The average distance from the sun for the newly-discovered planet in our solar system is approximately 240AU.Kepler's third law states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. It states that "the square of the period of revolution of a planet is proportional to the cube of the semi-major axis of its orbit." Kepler's third law mathematically connects the distance of a planet from the sun and its orbital period, that is, a planet's "year" or "revolution."The equation used to relate the third Kepler law is: T2 = (4π2 a3) / GMWhere T is the orbital period, a is the semi-major axis of the orbit, G is the gravitational constant, and M is the mass of the Sun. The value of T is provided as 6548 years, which is substituted in the equation above:6548^2 = (4π2 × a3) / (6.674 × 10-11 × 1.989 × 1030)Solving for a, we get:a = 239.8 ≈ 240 AU.Hence, the answer is option C. ~240AU.
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Two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415 N.
Answer:
Two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415 N
Answer:
A. 35 N to the right.
EXPLANATION: 450 is going to the right so you subtract what is going against it. Which gives you 35. And because 450 is bigger than 415, it'll be going to the right.
How much work is done on a pumpkin with a force of 24 newtons when you lift it 15 meters? *
Answer:
I'm not that busy solving but I'll tell you the formula that Force x distance is equal to work done
The work is done on a pumpkin when we lift it by 15 m with 24 N is 360 J
What is Work ?Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J).
i.e. Work(W) is force(F) times displacement(s).
W=F× s
When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule.
Writing for it's dimension,
W=F× s
Force has dimension [L¹ M¹ T²]
Displacement has dimension [L¹]
multiplying both the dimensions Force and Displacement
we get,
dimension of Work [L² M¹ T²]
According to newton's second law of motion,
Force(F) is mass(M) times acceleration(a).
i.e. F=ma
Given,
Force = 24 N
Displacement = 15 m
W=F.s= 24*15 = 360 J
Hence work done on pumpkin is 360 J
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