What is the mass of a bowling ball if a 48 Newton force is accelerating the bowling ball
3m/s22
16 kg
0 45 kg
51 kg
144 kg
Next​

Answer:

0.2

Explanation:

3/15

Answer:

Recycled answer from jaskhanna07343

Explanation:

Water does not wet waxed surfaces because the cohesive forces within the drops are stronger than the adhesive forces between the drops and the wax. Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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The initial mass of 235U required to operate a 950-MW reactor for 1 year with 24% efficiency is about 146.72 kg.

To calculate the initial mass of 235U required to operate a 950-MW reactor for 1 year, we need to use the following formula:

mass of 235U = (energy output x time x efficiency) / (energy per fission x number of fissions per atom x mass per atom)

First, we need to calculate the energy output of the reactor for 1 year. To do this, we can use the following formula:

energy output = power x time

where power is the power output of the reactor (950 MW) and time is the operating time of the reactor in seconds. Since there are 365 days in a year and 24 hours in a day, the operating time of the reactor in seconds is:

operating time = 365 days x 24 hours/day x 3600 seconds/hour = 31,536,000 seconds

Therefore, the energy output of the reactor for 1 year is:

energy output = 950 MW x 31,536,000 s = 2.9988 x 10^16 J

Next, we need to calculate the energy per fission of 235U. The average energy released per fission of 235U is about 200 MeV or 3.204 x 10^-11 J.

The number of fissions per atom of 235U is around 2.5, which means that each fission of 235U releases 2.5 x 3.204 x 10^-11 J of energy.

The mass per atom of 235U is about 235 g/mol, which is equivalent to 3.90 x 10^-22 kg/atom.

Plugging these values into the formula, we get:

mass of 235U = (energy output x time x efficiency) / (energy per fission x number of fissions per atom x mass per atom)

mass of 235U = (2.9988 x 10^16 J x 1 year x 0.24) / (2.5 x 3.204 x 10^-11 J x 3.90 x 10^-22 kg/atom)

mass of 235U = 146.72 kg

Therefore, the initial mass of 235U required to operate a 950-MW reactor for 1 year with 24% efficiency is about 146.72 kg.

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To find the height h of the center of the rail when the temperature is 25.0°C, we need to solve a transcendental equation. When the temperature increases, the rail buckles, forming an arc of a vertical circle.

To solve the equation, we can use the formula:

h = R - R * cos(θ)

where h is the height of the center of the rail, R is the radius of the arc, and θ is the angle of the arc.

Given that the rail is 1.00 km long, we can calculate the radius R using the formula:

R = 0.5 * length

R = 0.5 * 1.00 km

R = 0.5 km

Now, let's find the angle θ. As the rail buckles, it forms an arc. The length of this arc can be calculated using the formula:

length of arc = R * θ

Since the rail is 1.00 km long, we have:

1.00 km = (0.5 km) * θ

θ = 2 * (1.00 km / 0.5 km)

θ = 4 radians

Now, substituting the values of R and θ into the equation for h, we get:

h = (0.5 km) - (0.5 km * cos(4 radians))

h ≈ 0.087 km

Therefore, when the temperature is 25.0°C, the height h of the center of the rail is approximately 0.087 km.

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Graph A does.

The work you do to carry the ball up to the top of the cliff is the total energy it has.

Before you drop it, all that energy is potential energy.  

Once you drop it, the potential energy starts to turn into kinetic energy as it falls.  

When it hits the ground, its kinetic energy is exactly the amount of potential energy it had at the top, and it has no more potential energy.

The total (potential + kinetic) energy is the same amount all the way down. Energy isn't created or destroyed.

The graph that shows the ball's total energy and the elapsed time as the ball falls to the ground is graph A.

For a body that is falling from a height, the potential energy of the body is being converted to kinetic energy. We must note that the total mechanical energy of the body is constant.

As such, the graph that shows the ball's total energy and the elapsed time as the ball falls to the ground is graph A.

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Answer: 1.Magnification and resolution are important because the magnification in larges the image and the resolution makes it move shape and detailed creating the perfect image.  2. i dont know the second one, sorry

Explanation:

Answer:

(a) the height of the diving board is 22.896 m

(b) the horizontal distance traveled by the girl is 7.02 m

(c) if she had just drop off the board, her time to drop to the water would have been longer.

Explanation:

Given;

initial speed of the girl, u = 3.9 m/s

time to hit the water, t = 1.8 s

(a) the height of the diving board is calculated as;

h = ut + ¹/₂gt²

h = (3.9 x 1.8)  +  ¹/₂ x 9.8 x 1.8²

h = 7.02 + 15.876

h =  22.896 m

(b) the horizontal distance traveled by the girl is calculated as;

X = ut

X = 3.9 x 1.8

X = 7.02 m

(c) if she just drop off the board, then the initial speed will be zero;

h = ut + ¹/₂gt²

h = 0 + ¹/₂gt²

2h = gt²

\(t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \ \times\ 22.896 }{9.8} }\\\\t = 2.16 \ s\)

Thus, if she had just dropped off the board, her time to drop to the water would have been longer.

Answer:

A lens

Explanation:

A lens forms images when light passes Through it bending the rays of in the process.A phenomena called refraction and the speed of light changes in the process because it enters a medium since it's wavelength is reduced.

During episodes of non-compliance, it may be necessary to use a more intrusive type of prompt. This could include physical prompts, such as gently guiding the individual towards the desired behavior, or verbal prompts, such as reminding them of the expectations or consequences of their behavior.

Physical prompts may be used when an individual is struggling with a task or not responding to verbal prompts. However, it is important to use these types of prompts in a respectful and non-threatening manner.

Verbal prompts may be more appropriate for individuals who are able to understand language and respond to instructions. These prompts should be clear and direct, using simple language and positive reinforcement when appropriate.

It is important to remember that the use of prompts should be individualized and based on the specific needs and abilities of the person. The goal is to provide support and guidance to help the individual successfully complete the task or behavior, while also respecting their autonomy and dignity.

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Answer:

23 student photos

Explanation:

All you have to do is divide 1,127 by 49. So take the photos and fill each poster board. There will be no photos left! Hope this helps!

Answer:    Answer: The object moves forward at 5 m/s, stops, and then changes velocity.

Explanation:

With the information given in the question we can graph the points (image attached).

As we can observe, in the first segment of the graph the velocity is increasing linearly (at a constant rate) and is 5 m/s, then in the second segment we can see the position of the object remains the same from second 2 to second 4, which means the object is stopped.

Finally, in the third and last segment, we can observe a change in velocity (at a negative constant rate, because is decreasing), which is decreasing until the object stops.

Explanation:

We are given that a skater starts at a height of 2 meters. If we do a balance of energy and assume that there is no friction or any other nonconservative forces we get:

Where:

We can cancel out the mass and the acceleration of gravity:

Substituting the initial height we get:

Therefore, on the other side, he will get to 2 meters in height.

Answer: electrostatic force

Explanation:

electrostatic forces pull or push on objects without touching them, which is how when you rub some materials together they can result in something called a 'charge', being moved from point A to point B.

The radius of the wire is 0.0156 mm.

To calculate the radius of the wire, we need to use the following formula:

Total length of wire = (2 x π x r) x number of turns

where r is the radius of the wire.

Substituting the given values, we have:

Therefore, the radius of the wire is 0.0156 mm.

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Answer:

t = 5.05 s

Explanation:

This is a kinetic problem.

a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m

b) in this system the equations of motion are

              y = v₀ t + ½ g t²

where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth

e)    y = 0 + ½ g t²

     t = √ (2y / g)

     t = √(2 125 / 9.8)

     t = 5.05 s

Answer:

d

Explanation:

At absolute zero temperature, the pressure that a fluid exerts on its container is determined by its quantum mechanical nature, rather than by thermal motion.

What happens at absolute zero temperature?

At absolute zero, the fluid would have no thermal motion, and all the particles would be in their lowest energy state. This means that the fluid would still exert pressure on its container, but it would be a residual pressure, determined by the quantum mechanical properties of the fluid.

In some cases, the residual pressure at absolute zero can be significant and can be calculated using the ideal gas law and quantum statistical mechanics. In general, residual pressure is a fundamental property of a fluid, and is related to its intermolecular forces and density.

However, it is important to note that it is not possible to reach absolute zero temperature in practice, due to the laws of thermodynamics and the limitations of current technology. Nevertheless, the residual pressure at absolute zero can still be studied theoretically and provides important insights into the behavior of fluids at very low temperatures.

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.

The acceleration of the system still depends only on the difference in mass between the two masses, but the direction of the net force has changed, so the direction of acceleration has also changed.

When the masses are different, the system accelerates in the direction of the heavier mass. According to Newton's second law, the net force acting on each mass is equal to its mass times its acceleration:

F1 = m1a

F2 = m2a

where F1 and F2 are the tensions in the rope on either side of the pulley. Since the rope is inextensible and the pulley is ideal, the tension in the rope is the same on both sides, so F1 = F2 = T, where T is the tension in the rope.

Substituting T for F1 and F2 in the above equations and subtracting the second equation from the first, we get:

m1a - m2a = T - T

(m1 - m2)a = 0

Since the tension cancels out, the acceleration of the system depends only on the difference in mass between the two masses.

If the masses are switched, then the direction of the net force changes, and the system accelerates in the direction of the new heavier mass. The net force acting on each mass is still given by the above equations, but the masses are switched, so m1 is now the smaller mass, and m2 is the larger mass.

Substituting T for F1 and F2 in the above equations and subtracting the first equation from the second, we get:

m2a - m1a = T - T

(m2 - m1)a = 0

Since the tension cancels out, the acceleration of the system still depends only on the difference in mass between the two masses.

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When a 30 micro of capacitor is attached to the a 9 v battery at its intermediate level, the equation states that 2.7μC is the charges on the capacitor.

A capacitor operates on the basis that capacitance of the a conductor exhibits rise when a grounding conductor is introduced near it. As a result, the capacitance has parallel plates that are spaced apart from one another and facing in opposing directions.

Two conductors that are separated from one another and positioned close to one another make up a capacitor, a electrical energy storage device. A parallel-plate capacitor is a simple example with one such storage device.

If we rearrange the previous formula to account for C=30F and V=9v in our issue, we can calculate the charge held in the capacitor:

             Q=CV

                =(30μF) (9v)

                =2.7μC

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The reaction force to the action force during a rocket launch would be C. the force exerted by the ground or launch pad on the rocket.

The force that the ground or launch pad applies to the rocket during a rocket launch will act as a reaction force to the action force. The rocket is propelled upward by the force of explosion caused by the burning fuel and expanding gases. The force that keeps the rocket grounded and keeps it from moving is known as the reaction force, and it is the force that the launch pad or ground exerts in response to this action force.

Equal in magnitude but directed in the opposite direction, the action and reaction forces act on various objects. The reaction force affects the ground or launch pad, whereas the action force affects the rocket.

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Complete question

During a rocket launch, the action force is considered the force of explosion from the burning fuel and expanding gases. Which of the following would be considered the reaction force?

A. The starting force

B. The force of the explosion

C. The force exerted by the ground or launch pad on the rocket.

Answer:

disturbance,energy

Explanation:

Waves are a disturbance that transfer energy from one place to another.

;)

Answer:

See below

Explanation:

A ) distance = 1/2 a t^2    <==== when starting from rest

          20    = 1/2 (a) (3.5^2)      shows a = 3.27 m/s^2

B)   Velocity(at 3.5 s)   =   a t   = 3.27 * 3.5 = 11.42 m/s

C)    3.5 seconds      +    80 m / 11.42 m/s = 10.5 s

A buyer is purchasing a property for $120,000, which has an assessed value of $130,000. If the tax rate is $1.75 per $100, then the buyer will pay approximately $2,091.23 annually in taxes for the property.

To calculate the annual taxes the buyer will pay, we need to determine the property tax based on the assessed value and the tax rate.

Calculate the tax amount per $100 of assessed value:

Tax rate = $1.75 per $100

Tax per 100 = (assessed value / 100) * tax rate

In this case:

Tax per 100 = ($130,000 / 100) * $1.75 = $2,275

Calculate the annual tax amount:

Annual tax = (property price / assessed value) * tax per 100

In this case:

Annual tax = ($120,000 / $130,000) * $2,275 = $2,091.23

Therefore, the buyer will pay approximately $2,091.23 annually in taxes for the property.

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The cork leaves the spring at a speed of 3.02 m/s.

We can use the conservation of energy to determine the speed at which the cork leaves the spring.

The initial potential energy stored in the spring is converted to the kinetic energy of the cork as it leaves the spring. Neglecting air resistance, the conservation of energy equation is:

(1/2) k x^2 = (1/2) m v^2

where k is the spring constant, x is the distance the spring is compressed, m is the mass of the cork, and v is the speed of the cork as it leaves the spring.

Substituting the given values:

(1/2) * 18 N/m * (7.47 cm / 100 cm/m)^2 = (1/2) * 0.009 kg * v^2

Solving for v:

v^2 = (18 N/m * (7.47 cm / 100 cm/m)^2) / 0.009 kg

v^2 = 9.119 m^2/s^2

Taking the square root of both sides:

v = 3.02 m/s

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Answer:19.1m

Explanation: