what is the magnitude of the force exerted on the bottom of the bottle?

Answer:

In physics, motion is the phenomenon in which an object changes its position with respect to time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed

Explanation:

I got this off internet. Hope it helps!

Explanation:

i think this is the answer

The velocity of ball with respect to ground is 55km/h whereas with respect to car is 35km/h travelling opposite to its motion.

speed of ball relative to the truck = 15km/h

speed of truck relative to ground = 70km/h

(a) velocity of the ball relative to ground = speed of ball + speed of truck

Vb = (-15 )+75 [here - indicates that speed of ball is relative to the truck in the direction opposite its motion]

Vbg = 55km/h

(b) speed of car = 90km/h

velocity of the ball relative to car = 55 + (-90) as car is travelling opposite to ball.

Vbc = 35km/h

A person riding in the back of a pickup truck traveling at 70 km/h on a straight, level road throws a ball with a speed of 15 km/h relative to the truck in the direction opposite to the truck's motion. What is the velocity of the ball (a) relative to a stationary observer by the side of the road, and (b) relative to the driver of a car moving in the same direction as the truck at a speed of 90 km/h?

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Answer: The ball travels at a velocity of 55 km/h relative to the ground and 35 km/h relative to the moving car.

Explanation: The ball travels at a speed of 55 km/h relative to the ground and 35 km/h relative to the moving car.

Truck speed in relation to ball speed is 15 km/h

truck's speed with relation to the ground is 70 km/h

(A) The ball's velocity in relation to the ground equals its combined ball and truck speeds

Vb = (-15)+75 [here - denotes that the ball's speed is related to the truck's velocity in the opposite direction]

55 km/h, Vbg

(b) automobile speed equals 90 km/h

Car is moving in the opposite direction as the ball, hence the ball's velocity in relation to it is 55 + (-90).

Vbc = 35 kph.

When a person riding in the back of a pickup truck traveling at 70 km/h on a straight, level road throws a ball with a speed of 15 km/h relative to the truck in the direction opposite its motion. The ball travels at a velocity of 55 km/h relative to the ground and 35 km/h relative to the moving car.

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Respuesta: T2 = 131.04K

Explicación: Dado lo siguiente:

Presión, P1 = 1.5 atm = 1.5 × 760 = 1140 mmHg

Presión, P2 = 1.2 atm = 1.2 × 760 = 912 mmHg

Volumen, V1 = 500cm3 Volumen, V2 = 300cm3

Temperatura, T1 = 273K Temperatura, T2 =?

Usando la fórmula de gas combinada:

P1V1 / T1 = P2V2 / T2

Ingresando nuestros valores:

(1140 × 500) / 273 = (912 × 300) / T2

T2 × (1140 × 500) = 912 × 300 × 273

T2 = 74692800/570000 T2 = 131.04K

Answer:

7) there is a theory that these animals can see the magnetic field of the Earth due to a compass like mechanism inside their eyes in order to navigate.

8) Earth's magnetic field is a result of the currents found inside the outer core that consist of electricity.

Answer:

The radius of the slave piston​ = 14.10 cm

Explanation:

The formula to apply here is that for pressure where ;

Pressure = Force / Area

F₁ /A₁ =F₂/A₂    where ; F₁=200 N  , A₁= 25 cm² , F₂ =5000 N ,A₂ =?

Apply values in the equation as ;

200/ 25 = 5000/ A₂

A₂ = 625 cm²

Formula for area is ;

A = πr²  

625 = π * r²

625/π = r²

√625/π =r

14.10 cm = r

The barge will Motion 252 m³ of water while maintaining a 2.00 m top height above the water.

An object in motion maintains a straight course and a steady speed until it is affected by an unbalanced force. An object at rest maintains its state of rest. The mass of an item and the force acting on it define the acceleration of that thing.

The barge's displacement of water is proportional to its volume below the waterline.

The following formula may be used to determine the barge's volume:

Volume of barge = length × width × depth

Volume of barge = 14.0 m × 9.0 m × 4.0 m

Volume of barge = 504 m³

The top section of the barge is 2.00 m deep, so its volume can be calculated as follows:

Volume of top section = length × width × depth

Volume of top section = 14.0 m × 9.0 m × 2.0 m

Volume of top section = 252 m³

Now, the barge's displacement of water may be computed as follows:

Volume of water displaced = Volume of barge - Volume of top section

Volume of water displaced = 504 m³ - 252 m³

Volume of water displaced = 252 m³.

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Answer:What is the acceleration of a car that moves from rest to 15.0 m/s in 10.0 s? Vi=0, vf= 15.0 m/s,t=10.0s, a=? a= vf =vi/tA=15.0m/s-0m/s/10.0s = 15.0s/10.0s m/s*1/s =1.50 m/s^2 11.

Explanation:

Answer:

d

\(f(x) = {x}^{2} - 5x + 3 \\ f( - 1) = {( - 1)}^{2} - 5( - 1) + 3 \\ = 9\)

Answer:

the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.

Explanation:

Given;

wavelength, λ = 0.802 mm = 0.802 x 10⁻³ m

speed of sound in human tissue, v = 1540 m/s

The minimum frequency of ultrasound that will allow you to see the details is calculated as;

\(f = \frac{v}{\lambda} \\\\f = \frac{1540}{0.802 \times 10^{-3}} \\\\f = 1.92 \ \times \ 10^6 \ Hz\)

Therefore, the minimum frequency of ultrasound that will allow you to see the details is 1.92 x 10⁶ Hz.

If an object has an acceleration of 12.0 m/s². If the net force was tripled and the mass was doubled, then the new acceleration would be 18  m/s².

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = m × a

As given in the problem  net force was tripled and the mass was doubled,

3F = 2m × a

a₁ = 3/2 a

   = 3/2 × 12

   = 18 m /s²

Thus,  the new acceleration would be 18  m/s².

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normal force=mass*gravitational force

normal force=40*0

normal force=40

The velocity of the object when it is 27.0m above the ground is -17.64 m/s. The total distance the object travels during the fall is 42.75 m.

Final distance = 27m

Time taken to reach this distance = 1.8 seconds

We have to find the velocity of the object when it is 27.0m above the ground.

Also, we need to find the total distance the object travels during the fall.

(a) Velocity of the object when it is 27.0m above the ground:From the first equation of motion,

v = u + gt

Here,Initial velocity (u) = 0 (since the object is released from rest)

Final velocity (v) = ?

Time taken (t) = 1.8 seconds

Acceleration (g) = 9.8 m/s² (downwards)

v = 0 + 9.8 × 1.8v = 17.64 m/s

So, the velocity of the object when it is 27.0 m above the ground is 17.64 m/s downwards.

Hence, the answer is -17.64 m/s.

(b) Total distance the object travels during the fall: From the second equation of motion,

s = ut + 1/2 gt²

Here,Initial velocity (u) = 0 (since the object is released from rest)

Time taken (t) = 1.8 seconds

Acceleration (g) = 9.8 m/s² (downwards)

The distance travelled (s) = ?

So, putting the values in the above equation, we get:s = 0 + 1/2 × 9.8 × (1.8)²s = 15.75 m

So, the total distance the object travels during the fall is 27 m + 15.75 m = 42.75 m. Hence, the answer is 42.75 m.

The velocity of the object when it is 27.0m above the ground is -17.64 m/s. The total distance the object travels during the fall is 42.75 m.

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The work done by the force on the block is:

\(W=135.41*3=406.23 \: J\)

The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.

Using trigonometric functions:

\(F_{y}=Fsin(37)\)

This component is in the positive y-direction.

Now, there is a friction force between the block and the wall, so we need to find the friction force.

\(F_{f}=\mu N\)

Where:

Let's use the first Newton's Law to get F.

F(y) is upward (+) and F(f) and the weight is downward (-).

\(F_{y}-F_{f}-W=0\)

\(F_{y}-F_{f}=mg\)

Factoring F in the left side:

\(F(sin(37)-\mu cos(37))=mg\)    

\(F=\frac{mg}{sin(37)-\mu cos(37)}\)  

\(F=\frac{5*9.81g}{sin(37)-(0.3*cos(37))}\)  

\(F=135.41\: N\)    

Therefore, the work done will be:

\(W=Fd\)  

\(W=135.41*3=406.23 \: J\)  

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A total differential is an equation in which all the differentials can be integrated independently of each other. To verify that the given expressions are total differentials, we must check if they meet the conditions of being an exact differential function.The given expression is not an exact differential function.

According to the exact differential function, an expression dQ should be equal to the sum of two partial derivatives of the same function. i.e, dQ= dP+ dRA primitive function of an expression is obtained by integrating the given expression partially. Let's solve the given expressions, one by one:

1. Expression : (x² + 2xy-y²)dx + (x²-2xy - y²)dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = x² + 2xy - y²  ∂Q/∂y = x² - 2xy - y².

On verifying, we get:∂P/∂x = ∂Q/∂y.

Hence, the given expression is an exact differential function.

To find the primitive function, we need to integrate any one of the partial derivatives with respect to x and other with respect to y.

∴ P(x,y) = ∫(x² + 2xy - y²)dx = x³/3 + x²y - xy² + C1 and ∴ Q(x,y) = ∫(x² - 2xy - y²)dy = x²y - y³/3 + C2.

Therefore, the primitive function of the expression is: P(x,y) = Q(x,y) = x³/3 + x²y - xy² - y³/3 + C2.

Expression : (2xcosy - y² sinx) dx + (2ycosx - x² siny) dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = 2cosy  ∂Q/∂y = 2ycosx.

On verifying, we get:∂P/∂x ≠ ∂Q/∂y .

Hence, the given expression is not an exact differential function.

Therefore, there does not exist a primitive function for the given expression.

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Answer:b

Explanation:

Answer:

b

Explanation:

a force is a push or pull. hope i helped!

The total vapor pressure of the solution is (c) 99.3 mmHg.

A substance's or an object's temperature is a measurement of how hot or cold it is. It is a characteristic of matter that has to do with the typical kinetic energy of the atoms or molecules that make up the thing or material. Normally, temperatures are expressed in either degrees Celsius (°C) or degrees Fahrenheit (°F).

Raoult's law, because substance A's mole fraction is 0.35, it follows that substance B's mole fraction must be 0.65. (since the two mole fractions must add up to 1). The partial pressures of A and B in the solution can be determined using Raoult's law:

A's partial pressure is calculated as 0.35 x 87 mmHg, or 30.45 mmHg.

B's partial pressure is equal to 79.3 mmHg (0.65 x 122 mmHg).

The partial pressures of A and B are added to determine the solution's overall vapor pressure:

Total vapor pressure equals partial pressures of A and B, or 30.45 mmHg, 79.3 mmHg, and 109.75 mmHg respectively.

Rounding to the nearest tenth, we obtain 109.8 mmHg, which is the value that is most similar to option (c) 99.3 mmHg. Hence, the correct response is (c) 99.3 mmHg.

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Answer:

-100 kg · m/s

Explanation:

We can find the momentum of an object using the formula:

Let's start by converting the mass of the object to kilograms.

Since the left direction is the negative direction, we know that the velocity of the object is -25 m/s.

Using these variables, we can solve for p in the formula.

The momentum of the object is -100 kg · m/s.

The angular momentum immediately before and after the collision is equal. The rotational kinetic energy before the collision is greater than the rotational kinetic energy after the collision.

When a body is rotating in a plane about a center, the energy possessed by the body is known as rotational kinetic energy.

Angular momentum is the momentum of a body having circular motion.

According to the law of conservation of angular momentum, the momentum remains conserved before and after the collision.

In the given sphere rod system, after the sphere (m0) sticks to the rod(2m0), the mass increases to 3m0 due to which the moment of inertia is increased but the speed is decreased.

Rotational Kinetic Energy =\(\frac{1}{2}\)Iω²

Thus, the angular momentum immediately before and after the collision is equal. The rotational kinetic energy before the collision is greater than the rotational kinetic energy after the collision.

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Answer:

Troposphere

High-pressure areas form due to downward motion through the troposphere, the atmospheric layer where weather occurs.

Answer:

In Newton’s first law, an object at rest remains at rest until an external force isapplied. When I play soccer, the soccer ball will be at rest on the field (the initial condition) andremain in that spot on the field until I kick it (my muscles applying an external force to the ball).According to Newton’s second law, force = mass x acceleration (F=ma). When I kick the resting soccer ball, which has a given mass, it will accelerate in the direction that I kick it. From the equation, acceleration = force divided by mass. Therefore, since the mass of the soccer ball is fixed, the stronger my leg is and the more force I can apply to the ball, the faster it willaccelerate.According to Newton’s first law, an object in motion remains in motion until an external force isapplied. After I kick the soccer ball, it will continue in motion in the direction that I kicked it,but its acceleration will gradually slow down due to the external forces of friction from the airand the surface of the field. According to Newton’s third law, for every action there is an equal and opposite reaction.When I kick the soccer ball forward, if I also kick it in an upward direction, such as a thirty-degree angle from the field, it will come down at an angle when it strikes the field. When theball lands and strikes the field, there will be an equal and opposite reaction whereby instead oftraveling downward it will bounce of the surface of the field and will then be travelling upward.

Answer:

♧ Write the correct abbreviation for each metric unit.

♧ Try these conversions, using the ladder method.

♧ Compare using <, >, or =.

16. <

17. >

18. =

19. =

20. <

21. >

Answer:

Explanation:

the directions may change

Or they will repel and become opposite sides

Answer:

i think it's A

Explanation:

Answer:

The answer is A

Explanation:

When the same block is placed in water, still completely submerged, the tension in the string will (b) decrease. This is because the water exerts an upward buoyant force on the block, which is equal to the weight of the water displaced by the block.

The buoyant force is proportional to the density of the fluid, and since water is denser than oil, the buoyant force on the block will be greater in water than in oil.

This means that the effective weight of the block is reduced, and thus the tension in the string that is required to balance the weight of the block will also be reduced. This phenomenon is known as Archimedes' principle, and it explains why objects float or sink in fluids and why the apparent weight of an object changes when it is submerged in a fluid.

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