What is the lowest common multiple of 24, 8 and 16.

Answer:

x=16

Step-by-step explanation:

x+15=6x-65

x+80=6x

80=5x

16=x

hope this helps :P

The quadratic sorting algorithms are the ones that have a time complexity of O(n^2) or worse.

These algorithms are known for their inefficiency when sorting large datasets, as their time complexity grows exponentially with the size of the input.
Now, coming back to the question at hand, we are asked to identify which of the following algorithms is not a quadratic sorting algorithm.

The options given are Bubble sort, Selection sort, Quick sort, and Insertion sort.

Bubble sort and Selection sort are both examples of quadratic sorting algorithms, as they have a time complexity of O(n^2).

Bubble sort is a simple algorithm that repeatedly compares adjacent elements and swaps them if they are in the wrong order.

Selection sort is another simple algorithm that sorts an array by repeatedly finding the minimum element from the unsorted part of the array and putting it at the beginning.

Insertion sort, on the other hand, has a time complexity of O(n^2) in the worst case, but it can perform better than quadratic sorting algorithms on average, especially for small datasets.

This algorithm works by iterating over an array and inserting each element in its correct position in a sorted subarray.

Finally, Quick Sort is a well-known sorting algorithm with an average time complexity of O(nlogn) and a worst-case time complexity of O(n²).

This algorithm works by dividing the array into two smaller subarrays, one with elements smaller than a pivot element, and one with elements greater than the pivot, and then recursively sorting these subarrays.

Therefore, the answer to the question is Quick sort, as it is not a quadratic sorting algorithm. It has a much better time complexity than Bubble sort and Selection sort, and it can perform well on large datasets.

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The semimajor axis of Halley's Comet's orbit is approximately 17.91 AU. To find the semimajor axis of Halley's Comet's orbit, we can use Kepler's third law, which relates the orbital period (T) and the semimajor axis (a) of an object in an elliptical orbit:

T^2 = 4π^2a^3/GM,

where T is the orbital period, G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2), and M is the mass of the central body (in this case, the Sun).

First, we need to convert the orbital period from years to seconds:

T = 76 years = 76 × 365.25 days × 24 hours × 60 minutes × 60 seconds = 2.399 × 10^9 seconds.

Next, we can rearrange the equation to solve for the semimajor axis (a):

a = (T^2 * GM / (4π^2))^(1/3).

The mass of the Sun, M, is approximately 1.989 × 10^30 kg.

Plugging in the values, we have:

a = (2.399 × 10^9 seconds)^2 * (6.67430 × 10^-11 m^3 kg^-1 s^-2) * (1.989 × 10^30 kg) / (4π^2)^(1/3).

Calculating this expression, we find:

a ≈ 17.91 astronomical units (AU).

Therefore, the semimajor axis of Halley's Comet's orbit is approximately 17.91 AU.

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The calculations, we can see that the values of r, x, and y do not satisfy the equation r = x - y , it is not possible to determine the unknown value of x using the given data.

To find the value of x using the formula r = x - y, we need to determine the corresponding values of r, x, and y from the given data.

Based on the provided data, we have:

r | x | y

10 | 11 | 12

12 | 13 | 16

13 | 14 | 17

14 | 15 | 18

To calculate the r-value, we can use the formula r = x - y. Let's apply this formula to each row of the data:

r = 10, x = 11, y = 12

10 = 11 - 12

r = 12, x = 13, y = 16

12 = 13 - 16

r = 13, x = 14, y = 17

13 = 14 - 17

r = 14, x = 15, y = 18

14 = 15 - 18

From the calculations, we can see that the values of r, x, and y do not satisfy the equation r = x - y. Therefore, it is not possible to determine the unknown value of x using the given data.

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The diameter of the sphere is approximately 39.12 inches.

Given that a sphere has a volume of approximately 24,416.64 cubic inches.

Using the formula for the volume of a sphere, we have

V = 4/3πr³

where

V = Volume of the sphere

π = 3.14r

  = Radius of the sphere.

Substituting the given values

24,416.64 = 4/3(3.14)(r³)

Multiply both sides by 3/4 to isolate r³ and simplify the right side

24,416.64 x 3/4 = 2.3553648 x 10⁴

                          = 3.14r³

Divide both sides by 3.14:2.3553648 x 10⁴/3.14 = r³r³

                                                                               ≈ 7490.99

Taking the cube root of both sides, we have

r ≈ 19.56 inches

Therefore, the diameter of the sphere ≈ 2r

                                                                ≈ 2 x 19.56 inches

                                                                ≈ 39.12 inches

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From the equation we see that the center of the circle is at (-2,3) and the radius is 9.

So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...

d^2=(8--2)^2+(4-3)^2  and d^2=r^2=81 so

81=10^2+1^2

81=101  which is not true...

So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.  

Thus the point lies outside or on the exterior of the circle...

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Answer:

D

Step-by-step explanation:

Answer: I think it (7,4.1)

Step-by-step explanation:

Answer:

7.3.0

Step-by-step explanation:

Answer:

I believe its B, sorry if im wrong

Step-by-step explanation:

Answer:  There are 8   3/4 in 6.

Step-by-step explanation:

To find out how many 3/4 are in 6,  then divide  6 by 3/4.

6 ÷ 3/4 = 8  

If two lines form wide and narrow angles, it implies that they intersect at a point. If two lines form wide and narrow angles, then the lines must intersect.

When two lines intersect, they form four angles around the point of intersection. These angles can be classified based on their measurements. If two lines form a wide angle and a narrow angle, it means that they intersect and create angles of different sizes.

A wide angle is greater than 90 degrees, while a narrow angle is less than 90 degrees. This indicates that the lines are not parallel or perpendicular to each other, but instead, they intersect at an angle that is neither right (90 degrees) nor straight (180 degrees).

In conclusion, it is assumed that two lines cross at a place when they form wide and narrow angles.

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Answer: b

Step-by-step explanation:b

The value of x to the nearest hundredth is 9.04.

The correct option is C.

One of the six fundamental functions in trigonometry is the tangent function. As stated, Tan A = Opposite Side/Adjacent Side is the Tangent Formula. Tangent may be modeled using sine and cosine as follows: Tan A = Sin A / Cos A.

Given:

A triangle JHP is given in the diagram.

To find the value of x:

Applying tangent identity,

tan(37°) = 12/x

Apply cross multiplication,

we get,

x = 12tan(37°)

x = 9.042

x = 9.04 to the nearest hundredth.

Therefore, the value of x is 9.04.

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+ 12 - 4 + 3 - 15

= 12 + 3 - 4 - 15

=     15   -   19

= - 4

Answer:

He has -4 points. if I'm not mistaken

Step-by-step explanation:

12 - 4 + 3 - 15 = -4

I apologize if I am incorrect

Answer:

Last one could be either "Prove" or "CPCTC"

Answer:

a: 3°

b: -4°

c: -3°

d: 3°

e: -4°,-3°,0°,3°,3°

f: 7

The obtained values are where (f – g)(x) is above the x-axis, i.e., (f – g)(x) is positive.The interval where this occurs is (–2, [infinity]). The correct option is (–2, [infinity]).

Given the linear functions f (x) and g(x) in the tables, the solution to the expression (f – g)(x) is positive where x is in the interval (–2, [infinity]).

The table has the following values:

x -8 -5 -2 1 4

f(x) -4 -6 -8 -10 -12

g(x) -14 -11 -8 -5 -2

To find (f – g)(x), we have to subtract each element of g(x) from its corresponding element in f(x) and substitute the values of x.

Therefore, we have:(f – g)(x) = f(x) - g(x)

Now, we can complete the table for (f – g)(x):

x -8 -5 -2 1 4

f(x) -4 -6 -8 -10 -12

g(x) -14 -11 -8 -5 -2

(f – g)(x) 10 5 0 -5 -10

To find where (f – g)(x) is positive, we only need to look at the values of x such that (f – g)(x) > 0.

These values are where (f – g)(x) is above the x-axis, i.e., (f – g)(x) is positive.

The interval where this occurs is (–2, [infinity]).

Therefore, the correct option is (–2, [infinity]).

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The sentence which describes a situation which can be represented by the equation 4 ÷ 1 1/3 is,  "4 divided by the fraction number 11 by 3"

An equation is a mathematical term, which indicates that the value of two algebraic expressions are equal. There are various parts of an equation which are, coefficients, variables, constants, terms, operators, expressions, and equal to sign.

For example, 3x+2y=0.

Types of equation

1. Linear Equation

2. Quadratic Equation

3. Cubic Equation

Given that,

An equation,

⇒ 4 ÷ 1 1/3

Mathematically, it represents that,

4 is divided by fraction number 11 by 3

or

Product of 4 and reciprocal of 11 divided by 3

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Answer: 3.74 inches.

Step-by-step explanation: We can use the following to help us solve this proportion:

1.4 / 1.54 = 3.4 / x (where x is the unknown value that we are trying to solve)

1.54 / 1.4 = 1.1

x / 3.4 = 1.1

The only number that can make the following above true is 3.74, so that is your answer.

Let me know if this is right! :)

I think its B

not 100% sure tho

Answer:

52in^2

Step-by-step explanation:

The area of a triangle is A= 1/2bh

The area of a rectangle is A=lw

The base of the top triangle would be the length of the base of the two right triangles plus the length of the width of the the rectangle.

A=1/2bh

A=1/2(2+2+4)(4)

A=1/2(8)(4)

A=1/2(32)

A=16in^2

        2. The two right triangles

A=1/2bh

A=1/2(2)(6)

A=1/2(12)

A=6in^2

(Because the two triangle are the same we just multiply the area by 2 to get the value of both)

A=12in^2

       3. The rectangle

A=lw

A=6(4)

A=24in^2

-

Now just add the value of the areas for the different shapes.

16in^2 + 12in^2 + 24in^2 = 52in^2

Answer:

S.A for Edmentum and Plato

Like and Rate

No. For each set of parallel lines, pairs of alternate interior angles are congruent, pairs of alternate exterior angles are congruent, and pairs of same-side interior angles are supplementary. This is the same result as in questions 2 through 4.

No. For each set of parallel lines, pairs of alternate interior angles are congruent, pairs of alternate exterior angles are congruent, and pairs of same-side interior angles are supplementary. This is the same result as in questions 2 through 4.

If we modify the set of parallel lines by moving point A to different locations while ensuring that points A and B do not cross line EF, the relationships among the angles will not change. The statements regarding pairs of alternate interior angles being congruent, pairs of alternate exterior angles being congruent, and pairs of same-side interior angles being supplementary will still hold true.

The reason for this is that the properties of alternate interior angles, alternate exterior angles, and same-side interior angles are dependent on the fact that lines AB and CD are parallel. As long as AB and CD remain parallel, regardless of the position of point A, these angle relationships will remain consistent.

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Answer:

He can fill 3 crates, there would be 1 orange left over

Step-by-step explanation:

four equal rows of three oranges = 12 total. 12x3= 36, so 1 left over

i think D hope it helps

Step-by-step explanation:

1 7/8 the least because it farther from the line than 0

Answer:

D. -1 7/8, -1 1/4, -1 1/2, 1

Answer:

Domain: x>= -3

Range: y <= -2

Step-by-step explanation:

Domain is all the x's on the graph or allowed in the equation.

Range is all the y's on the graph or able to come from the equation.

Answer:

The answer is 20 hours

Step-by-step explanation:

This is becuase 1280 divided by 64 equals 20.  There are no unit coversions.

In time t = 0.02 hour the car travels a distance of 1280 meters with a speed of 64 kilometers per hour.

Given that,
A car travels a distance of 1280 meters at an average speed of 64 kilometers per hour.

Speed is defined as when an object is in motion, the distance covered by that object per unit of time is called speed.

Here,
Time  = distance/speed
Time. t = 1.280 / 64

t = 0.02 hours

Thus, In time t = 0.02 hour the car travels a distance of 1280 meters with a speed of 64 kilometers per hour.

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Answer:

THE ONLY STATEMENT THAT IS FALSE IS THE NUMBER 5.

Step-by-step explanation:

Table of ordered data

number of       value

data

1                      62

2                      88

3                      89

4                      90

5                      92

6                      95

7                      96

8                      98

9                    100

10                  100

Range of scores: 100 - 62 = 38

Oulier: 62 => Range without the outlier = 100 - 88 = 12

Interquartile range, IQR, = difference between third quartile and first quartile: IQR = Q3 - Q1

Quartlies of all the data:

1                      62

2                      88

3                      89 ---------------   first quartile, Q1 = 89

4                      90

5                      92

------------------------------------------ median, Q2 = (95 + 92) / 2 = 93.5

6                      95

7                      96

8                      98 ---------------- third quartile, Q3 = 98

9                    100

10                  100

=> IQR = 98 - 89 = 9 : the interquartle range is 9

Quartlies without the outlier:

2                      88

3                      89

------------------------------------- first quartile, Q1 = (89 + 90) / 2 = 89.5

4                      90

5                      92

6                      95 --------------- median, Q2 = 95

7                      96

8                      98

------------------------------------ third quartile, Q3 = (98 + 100) / 2 = 99

9                    100

10                  100

=> IQR = Q3 - Q1 = 99 - 89.5 =  : the interquartle range without the outlier is 9.5

Therefore, the outlier impacts more the range than it impacts the IQR.

THE ONLY STATEMENT THAT IS FALSE IS THE NUMBER 5.

Type number of the system is 2.

The type number of the given system can be determined by calculating the number of poles at the origin and the number of poles in the right-hand side of the s-plane.

If there are “m” poles at the origin and “n” poles in the right-hand side of the s-plane, then the type number of the system is given as:

                       n-mIn this case, the transfer function of the given system is G(s) = (s+2) / s^2(s+ 8)

We can see that the order of the denominator polynomial of the given transfer function is 3.

Hence, the order of the system is 3.Since there are two poles at the origin, the value of “m” is 2.

Since there are no poles in the right-hand side of the s-plane, the value of “n” is 0.

Therefore, the type number of the system is:

                     Type number = n - m= 0 - 2= -2

However, the type number of a system can never be negative.

Hence, we take the absolute value of the result:

          Type number = | -2 | = 2

Hence, the type number of the given system is 2.

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Answer:

(1,-1)

Step-by-step explanation:

-2x-1 = x+2

-3x = 3

x = -1

substitute

y = (-1) + 2

y = 1

point: (1,-1)

The total electric potential at point a is the sum of the electric potentials due to q1 and q2 is 0, the total electric potential at point b is the sum of the electric potentials due to q1 and q2 is 84.5 and the work done on q3 by the electric forces exerted by q1 and q2 is -0.42 J.

The electric potential at point a due to q1 and q2 can be calculated using the formula for electric potential due to a point charge,

V=kq/r, where k=9×10^9 N.

m²/C² is the Coulomb constant,

q is the point charge,

and r is the distance from the point charge to the point where the potential is being measured.

Using this formula, the electric potential due to q1 at point a is:

V1=kq1/r1

where q1=+2.00μC is the charge on q1 and r1 is the distance from q1 to point a.

Since q1 is at one of the corners of the square and a is at the center, the distance r1 is half the length of the diagonal of the square:

r1=√(12+12)=0.75 cm

Substituting the values in the formula, we get:

V1 = 9×10^9×2.00×10^-6/0.75×10^-2V1

     = 240 V

The electric potential due to q2 at point a can be calculated similarly.

Since q2 is at the opposite corner of the square, the distance r2 is the length of a side of the square:

r2=1.50 cm

Substituting the values in the formula, we get:

V2 = 9×10^9×(-2.00)×10^-6/1.50×10^-2V2

     = -240 V

The total electric potential at point a is the sum of the electric potentials due to q1 and q2:

V = V1+V2V=240 - 240V

   = 0

Since point b is at the empty corner closest to q2, the electric potential at point b due to q2 is zero.

The electric potential at point b due to q1 can be calculated using the same formula we used for point a:

V1=kq1/r1

where q1=+2.00μC is the charge on q1 and r1 is the distance from q1 to point b.

Since q1 is at one of the corners of the square and b is at the opposite corner, the distance r1 is the length of a diagonal of the square:

r1=√(1.5²+1.5²)=2.12 cm

Substituting the values in the formula, we get:

V1 = 9×10^9×2.00×10^-6/2.12×10^-2V1

     = 84.5 V

The total electric potential at point b is the sum of the electric potentials due to q1 and q2:

V = V1+V2V

   = 84.5 + 0V

    = 84.5 V

The electric force exerted on a point charge by another point charge is given by Coulomb's law:

F=kq1q2/r²

where F is the force,

           q1 and q2 are the point charges,

           r is the distance between the charges,

           and k is the Coulomb constant.

Since q3 is negatively charged, it will experience a force in the direction opposite to the force experienced by a positive charge at the same location.

Thus, the total work done by the electric forces exerted by q1 and q2 on q3 can be calculated as the negative of the change in electric potential energy of q3 from point a to point b:

W=-ΔPE

where ΔPE is the change in potential energy of q3 from point a to point b.

Substituting the values, we get:

W=-q3(Vb - Va)

where q3=-5.00μC is the charge on q3,

           Va=0 is the electric potential at point a,

            and Vb=84.5 V is

the electric potential at point b:

W = -5.00×10^-6(84.5 - 0)W

   = -0.42 J

Therefore, the work done on q3 by the electric forces exerted by q1 and q2 is -0.42 J.

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