what is the first transition element with their electronic configuration using KLMN​

Answer:

By increasing the concentration of One of the reactants.

Answer:

Chromium(III) phosphate trihydrate

Explanation:

The correct IUPAC name for CrPO4 · 3H2O is Chromium(III) phosphate trihydrate.

Answer:

Recessive and Dominant

Explanation:

Answer:

4 doughnut

Explanation:

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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Tthe initial temperature of the polystyrene sample is 39.4°C.

Given: Mass of polystyrene sample = 54.2 gSpecific heat of polystyrene = 1.880 J-g°CWater mass = 100.0 g Initial water temperature = 21.0°CWater final temperature = 34.3°CPressure remains constant at 1 atmFormula used:Heat gained by water = heat lost by polystyreneHence,Heat lost by polystyrene = Heat gained by water=> mcΔT = mcΔTwhere,m = mass of polystyrene or waterc = specific heat capacityΔT = change in temperatureThe temperature change is ΔT = 34.3°C - 21.0°C = 13.3°CNow we can use this temperature change to calculate the initial temperature of the polystyrene.Taking the water's specific heat capacity, c = 4.184 J/g°CHeat gained by water = (100.0 g)(4.184 J/g°C)(13.3°C) = 5574 JHeat lost by polystyrene = 5574 JTaking the polystyrene's specific heat capacity, c = 1.880 J/g° ) = 13.3°C Now let's calculate the mass of polystyrene using the specific heat capacity formula.5574 J = (54.2 g)(1.880 J/g°C)(13.3°C - Ti)Ti = 39.4°C

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1. 2SO2 + 2H2 ➡️ 2H2S + 2H20

2. CaCl2 + Na2CO3 ➡️ CaCO3 + 2NaCl

3. 2HNO3 ➡️ NO2 + H2O + 02

4. 12Al + H2SO4 ➡️ A12(SO4)3 + H2

Answer:

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer: OB. 1.806 x 1024

Explanation:

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

volume = 97.68 cm³

density = 1.740 g/cm³

mass = 97.68 × 1.740 = 169.9632 g

We have the final answer as

Hope this helps you

The correct answer is 329.4 Cal.

Remember that specific heat is the ratio of the amount of heat needed to raise a body's temperature by one degree compared to the amount of heat needed to raise the temperature of an equivalent mass of water by one degree, or that specific heat capacity is the amount of heat energy needed to raise a material's temperature by one kelvin (K) per kilogramme.

Mass of sample=50.00-g

Specific heat of metal=0.108 cal/g °C

Change in temperature=78.0 °C-17.0°C=61.0°C

Heat Released by metal can be calculated as follows:

Heat Released = Mass of sample  x Specific heat x  Change in temperature

Heat Released = 50.00 g x  0.108 cal/g °C x 61.0°C

Heat Released = 329.4 Cal

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Answer:

11.2g of the 45% pure silver and 2.8g of the 50% pure silver.

Explanation:

14g of 46% pure silver contains:

14g*46% = 6.44g of silver are required. Thus, we can write:

6.44 = X*50% + Y*45% (1)

Where X is the mass of 50% pure silver and Y the mass of 45% pure silver.

As the mass of the sample must be 14g:

14g = X + Y (2)

Replacing (2) in (1):

6.44 = (14-Y)*50% + Y*45%

6.44 = 7 - 0.5Y + 0.45Y

-0.56 = -0.05Y

Y = 11.2g of the 45% pure silver

And:

14g-11.2g = X

X =

2.8g of the 50% pure silver

The required amount to obtain 14g of 46% pure silver is 2.8g of 50% silver and 11.2g of 45% silver.

To solve this question, we can assume it's a mathematical problem more than a chemistry problem.

let x represent the amount of 45% of pure Ag

let y represent the amount of 50% of pure Ag

But from the question, we only need 14g from both x and y

We can write an equation to represent this

\(x+y=14...equation(i)\)

likewise, we can say that

\(0.45x+0.50y=14*0.46\\0.45x+0.50y=6.44...equation(ii)\)

Solving both equations simultaneously,

\(x+y=14...equation(i)\\0.45x+0.5y=6.44...equation(ii)\)

from equation (i)

\(x+y=14\\x=14-y...equation(iii)\)

substitute equation (iii) into equation (ii)

\(0.45x+0.5y=6.44\\x=14-y\\0.45(14-y)+0.5y=6.44\\6.3-0.45y+0.5y=6.44\\\)

collect like terms

\(-0.45y+0.50y=6.44-6.3\\0.05y=0.14\\y=\frac{0.14}{0.05}\\y=2.8\)

Now we know the value of the 50% Ag which is 2.8g. Let's substitute it's value into equation (i) and solve for x

\(x+y=14\\x+2.8=14\\x=14-2.8\\x=11.2g\)

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Answer:

because of the downward force called gravity

Answer:organic compound is :​ C₄H₈

Explanation: The equation of the reaction of the organic compound burning with excess oxygen gives us the general equation as

C xHy  + 1/2(x+ y/2 )O₂ → xCO₂ + y/2H₂O

We first find the number of moles of CO₂ and H₂O

Number of moles of CO₂= Mass/ molar mass

= 17.6g/ 44g/mol ( 12+ 16 x2)

=0.4 moles

Number of moles of H₂O= Mass/ molar mass

= 7.2g/ 18g/mol ( 1 X 2+ 16)

=0.4 moles

From the reaction , we can see that  

x = 0.4

and  \(\frac{y}{2}\)= 0.4  such that y= 0.4 x 2= 0.8

Their ratios become

\(\frac{x}{y}\) =\(\frac{0.4}{0.8}\)= \(\frac{4}{8}\)

Therefor the organic compound CxHy  = C₄H₈

​  

Answer:

1) Element is a pure substance consisting only of atoms that all have the same numbers of protons in their nuclei.

2) a) Element is a pure substance

  b) It is homogeneous

3) Bromine

4) Elements and compounds are pure chemical substances found in nature. The difference between an element and a compound is that an element is a substance made of same type of atoms, whereas a compound is made of different elements in definite proportions. Examples of elements include iron, copper, hydrogen and oxygen.

5) The law of definite proportions

Explanation:

This is all i know, bro

Answer:

nope

Explanation:

they are not based on size because dimes are the smallest coin but is worth 10 cents and a penny is bigger then a dime but is worth only 1 cent

Answer: high pressure, high temperature water extraction

Explanation:

Answer:

C). high pressure, high temperature water extraction

Explanation:

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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It is an amine, and it has less polar nitrogen-hydrogen and oxygen-hydrogen bonds.

A compound's boiling point is a physical characteristic. These intramolecular linkages between the molecules that make up a chemical affect these physical characteristics.

Alcohols and amino acids have the same kind of intermolecular linkages. The hydrogen bond is the name of this kind of bond.

The electrical attraction between a hydrogen atom from one molecule and an electronegative atom from a nearby molecule is known as a hydrogen bond.

The strength of the bond is in the following order: H.....F > H.....O > H......N

The H....N hydrogen bonds exist in amines, whereas the H....O hydrogen bonds exist in alcohols.

Consequently, the alcohol's hydrogen bonds are stronger and it will impart a higher boiling point on the compound.

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Answer:uses world like

Explanation:

Answer:

1.25 moles

Explanation:

You have 2.5 moles of Cl on product side and you need to make that equal on the reactant side. You can see it is Cl2  so you need to half 2.5 by 2 so both sides are equal. 2.5/2=1.25

Answer:

1. MELTING POINT

2. SUBLIMATION

3. FREEZING POINT

4. DEPOSITION

5. HEAT

Explanation:

The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.

Given the following data:

To determine the specific heat capacity of this chunk of metal:

Mathematically, quantity of heat is given by the formula;

\(Q = mc\theta\)

Where:

Making c the subject of formula, we have:

\(c = \frac{Q}{m\theta}\)

Substituting the given parameters into the formula, we have;

\(c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }\)

Specific heat, c = 0.32 J/g°C.

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Answer:

yes

Explanation:

\(\Large \text{1)}\)

\(\textbf{Use the formula and substitute the values}\)

\(\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}\)

\(\textbf{Solve for the number of moles}\)

\(n = 0.003\ mol\)

\(\textbf{Calculate final volume }\)

\(40+10=50\ mL\)

\(\textbf{Number of moles remains same. Solve for concentration}\)

\(\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L\)

\(\Large \text{2)}\)

\(\displaystyle DF=\frac{V_f}{V_i}\)

\(\displaystyle DF=\frac{50}{10}=5\)

The following data were obtained when a sample of barium chloride hydrate was analyzed as described in the Procedure section. Mass of empty test tube Mass of test tube and hydrate (before heating) Mass of test tube and anhydrous salt (after heating) 18.42 g 20.75 g 20.41 g Calculate :

Note: The percent water in the hydrate should not be negative, so this calculation must be incorrect.

Important terms in studying hydrated water are as follows: 1. Anhydrous salt is a salt that has lost water molecules, this salt is formed from the decomposition of heated hydrate salts 2. Hydrate salts are salts that have a fixed number of water molecules in each molecule.

Compounds that contain water of crystals are called hydrates, while compounds that do not contain water of crystals are called anhydrous compounds

The word element in Greek is stoicheion, while stoichiometry or stoichiometry has the meaning of measuring elements which include several things, namely atomic mass, molecular mass, empirical formula, molecular formula, concentration, number of moles, reaction equations and everything related to chemical reactions. The number of particles present in a substance in stoichiometry is called moles.

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Answer:

Did you figure out what it was?

Explanation:

Answer:

D) atom

Explanation:

The type of compound represented by the graph at right is a strong acid (option B).

An acid is generally any compound capable of dissociating into its respective constituent ions when in an aqueous solution.

An acid is categorised as strong or weak depending on whether it can dissociate completely or partially. A strong acid dissociates completely in water.

According to this question, HA, when added to water, dissociates into H+ and A- ions, hence, is a strong acid.

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Answer:

B. Conjugated diene

Explanation:

Answer:

Convection

Explanation:

Convection is the transfer of thermal energy by particles moving through a fluid.

Answer:

convection

Explanation:

trust