What is the equation of the parabola with focus (0,7) and directrix y = 1?

Answer: -27

Step-by-step explanation: Use inductive reasoning to predict the most probable next number in the list.

3, 9, -3, 3, -9, -3, -15, -9, -21, ?

We can start by looking at the differences between consecutive terms in the list:

9 - 3 = 6 -3 - 9 = -12 3 - (-3) = 6 -9 - 3 = -12 -3 - (-9) = 6 -15 - (-3) = -12 -9 - (-15) = 6 -21 - (-9) = -12

Notice that the differences alternate between positive 6 and negative 12. This suggests that the pattern involves adding 6, then subtracting 12, and then adding 6 again. Applying this pattern to the last term in the list (-21), we get:

-21 + 6 = -15 -15 - 12 = -27 -27 + 6 = -21

Therefore, we predict that the most probable next number in the list is -27.

The function m(x) = 2tan(3x+4) is obtained by applying a sequence of transformations to the parent tangent function.

To determine the sequence of transformations, let's break down the given function:

1. Inside the tangent function, we have the expression (3x+4). This represents a horizontal compression and translation.

2. The coefficient 3 in front of x causes the function to compress horizontally by a factor of 1/3. This means that the period of the function is shortened to one-third of the parent tangent function's period.

3. The constant term 4 inside the parentheses shifts the function horizontally to the left by 4 units. So, the graph of the function is shifted to the left by 4 units.

4. Outside the tangent function, we have the coefficient 2. This represents a vertical stretch.

5. The coefficient 2 multiplies the output of the tangent function by 2, resulting in a vertical stretch. This means that the graph of the function is stretched vertically by a factor of 2.

In summary, the sequence of transformations applied to the parent tangent function to create the function m(x) = 2tan(3x+4) is a horizontal compression by a factor of 1/3, a horizontal shift to the left by 4 units, and a vertical stretch by a factor of 2.

Example:
Let's consider a point on the parent tangent function, such as (0,0), which lies on the x-axis.

After applying the transformations, the corresponding point on the function m(x) = 2tan(3x+4) would be:
(0,0) -> (0,0) (since there is no vertical shift in this case)

This example helps illustrate the effect of the transformations on the graph of the function.

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Answer:

(a)16 (b)-64 (c)-100

Explanation

Part A

Part B

Part C

In a case whereby baseball game receives 3 raffle tickets and a $2 certificate for the team store. A group of people receives 39 raffle tickets the amount of money in certificates the group receive is  $26.

If one baseball game receives 3 raffle tickets and a $2 certificate for the team store, then we can say that each raffle ticket is worth 2/3 dollars ($2 divided by 3 tickets).

So, for 39 raffle tickets, the group would receive (39 x 2/3) = $26

Therefore, the amount of money in certificates the group receive is  $26

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The drop down menu is used to match each situation as below.

1. The rocket reached its maximum  the x-value of the vertex

height in 5 s.

2. ground level                                    the y-intercept

3. The rocket launcher was                the y-value of the point containing

on the ground.                                     the x-intercept on the right

4. The rocket was in the air 10           the x-intercept on the right                                                                                    

5. The maximum height of the           the y-value of the vertex

rocket is 50 ft.

6. the time the rocket was                the x-value of the point containing the

launched                                          y-intercept

The key features of the curve such as the x intercept is the point the launcher and the rocket were on ground.

The vertex is the point the rocket had the maximum and height.

Generally, the curve traces a parabolic path

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============================================================

Explanation:

Ignoring the slashes, there are 8 digits here. If we could tell those '1's and '2's apart, then we'd have 8! = 40,320 different codes. The exclamation mark indicates a factorial.

However, the '1's and '2's are indistinguishable. We have to divide by a!*b! = 3!*3! = 6*6 = 36 to account for this.

The a! = 3! = 6 is from the fact we have 3 copies of '1'.

The b! = 3! = 6 is from the fact we have 3 copies of '2'

Dividing by 36 gets us (40,320)/36 = 1120

Answer:

All of the them excluding f(x)=-27x+2

The required function is \(f(x)=-2x^2+2\). Hence, option a is correct.

Important information:

The graph has two x-intercepts (1,0) and (-1,0). It means it is a quadratic function and \((x-1)\) and \((x+1)\) are two factors.

\(f(x)=a(x-1)(x+1)\)

\(f(x)=a(x^2-1)\)         ...(i)

The graph passes through the point (0,2). Substitute \(x=0,f(x)=2\) in the above function.

\(2=a(0^2-1)\)

\(2=-a\)

\(-2=a\)

Substitute \(a=-2\) in (i).

\(f(x)=-2(x^2-1)\)

\(f(x)=-2x^2+2\)

Therefore, the correct option is a.

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The expressions that will correctly calculate what percent 19 is of 20 are:

A.19/20 .100

D.19.100/20

The concept that will be used here is percentage. A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. The proportion therefore refers to a component per hundred. Per 100 is what the word percent means.

From the options we can see that to find the percentage of 19  of 20, iot can be expressed mathematically as :

(19/20) *100 and this can as well be expressed as (19*100)/20 becausethey will still give use the same value which is 95%

Therefore, option A and D are correct.

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Answer:

Step-by-step explanation:

a) If we assume the annual withdrawals are at the beginning of the year, we can use the formula for an annuity due to compute the necessary savings.

The principal P that must be invested at rate r for n annual withdrawals of amount A is ...

  P = A(1+r)(1 -(1 +r)^-n)/r

  P = $60,000(1.08)(1 -1.08^-20)/0.08 = $636,215.95

__

b) 20 withdrawals of $60,000 each total ...

  20×$60,000 = $1,200,000

__

c) The excess over the amount deposited is interest:

  $1,200,000 -636,215.95 = $563,784.05

Answer:

B) \(x=9\)

Step-by-step explanation:

\(\sqrt{x}+9=12\\\\\sqrt{x}=3\\\\x=9\)

Answer:

B. \(x = 9\)

Step-by-step explanation:

\(\sqrt{x} +9 = 12\)

\(\sqrt{x} = 12 -9\)

\(\sqrt{x} = 3\)

                        [ changing sides, changed square root to square ]

\(x = 3^2\)

\(x = 9\)

The payback period for Project A is 3 years, and the payback period for Project B is also 3 years.

To calculate the payback period for Project A and Project B, we need to determine the time it takes for the cumulative cash flows to equal or exceed the initial investment of $40,000.

For Project A:

Year 1 cash flow: $42,000

Year 2 cash flow: $22,000

Year 3 cash flow: $10,000

To find the payback period, we start by subtracting the cash flows from the initial investment until we reach a cumulative cash flow equal to or greater than $40,000:

Year 1: $40,000 - $42,000 = -$2,000

Year 2: -$2,000 + $22,000 = $20,000

Year 3: $20,000 + $10,000 = $30,000

The cumulative cash flow reaches $30,000 in Year 3. However, it does not exceed the initial investment of $40,000. Therefore, we can estimate the payback period as follows:

Payback period for Project A = 2 years + ($40,000 - $30,000) / $10,000

= 2 years + 1 year

= 3 years

For Project B:

Year 1 cash flow: $40,000

Year 2 cash flow: $21,000

Year 3 cash flow: $15,000

Using the same process as above, we calculate the cumulative cash flows:

Year 1: $40,000 - $40,000 = $0

Year 2: $0 + $21,000 = $21,000

Year 3: $21,000 + $15,000 = $36,000

The cumulative cash flow reaches $36,000 in Year 3, which is greater than the initial investment. Therefore, the payback period for Project B is:

Payback period for Project B = 3 years

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54 is one of the heights, so there would be a solid dot on 54. Because you need to be taller, the arrow would point to the right from the solid dot at 54 inches.

The correct graph is C ( the third one down)

The graph that represents the set of heights that satisfy this requirement is the third graph.

The requirment is that the heights of the people who ride the roller coaster should be at least 54 inches. This means that the height of the riders can be 54, 55, 100 0r 120.

Thus the graph that represents this is the graph that has a coloured circle on 54 and extends to number greater than 54.

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The answer choice which belongs in the green box and is the longest side of the triangle as required is; 11.06.

It follows from the task content that since the sum of angles in a triangle is; 180°, the missing angle measure is; 180 - 51 - 109° = 20°.

Consequently, it follows from the sine law that;

4 / sin 20° = x / sin 109°

x = 4 sin 109° / sin 20°

x = 11.06.

Ultimately, the number that belongs in the green box is; 11.06.

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The graph of the composition of functions is on the image at the end.

Here we want to graph the composition of the functions g(x) and f(x), where:

f(x) = -2x - 5

g(x) = x - 1

The composition:

g(f(x)) will give:

g(f(x)) = f(x) - 1 = -2x - 5 - 1 = -2x - 6

So it is just a linear function, basically it is a translation of 1 unit down of f(X), the graph of this composition is on the image at the end.

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Answer:

m = -1; b = 2

Step-by-step explanation:

the first step in solving this equation is to find the slope

so we use the equation (y2-y1)/(x2-x1)

so with this the equation is

(4 - 3)/(-2 + 1)

then it would be 1/-1

that is -1

so the function so far is f(x) = -x + b

to find the b you would plug in the coordinates

we can plug in the first set

3 = 1 + b

b = 2

so the m is -1 and the b is 2

Answer: 0.4419

Step-by-step explanation:

Given: The birth weights of full-term newborn infants in the U.S. have an approximately normal distribution with a mean weight of 6.8 lbs and a standard deviation of 1.7.

i.e. \(\mu=6.8\ \ \ \text{ and }\sigma= 1.7\)

Let X denotes the birth weight.

Then, the proportion of newborn babies will have a birth weight between 6 lbs and 8 lbs is given by :-

\(P(6<X<8)=P(\dfrac{6-6.8}{1.7}<\dfrac{X-\mu}{\sigma}<\dfrac{8-6.8}{1.7})\\\\=P(-0.47<Z<0.71)\ \ \ [Z=\dfrac{X-\mu}{\sigma}] \\\\=P(Z<0.71)-(1-P(Z-0.47))\\\\=0.7611-(1-0.6808)\ \ \ [\text{By z-table}]\\\\= 0.4419\)

Hence, the proportion of newborn babies will have a birth weight between 6 lbs and 8 lbs is 0.4419 .

Three or more line segments that only intersect at their ends form closed, two-dimensional shapes known as polygons.

A polygon is a closed, two-dimensional shape with straight sides that is flat or plane. It has straight sides. Polygons are a different category that belongs to the category of two-dimensional figures because two-dimensional (2D) figures are flat because they lack volume.

Polygons are flat 2D shapes that have straight lines and all lines are closed, meaning that they don't have any disconnected lines. Polygons are a subcategory of 2D figures because they carry all traits of 2D figures but also have special ones of their own. Examples of polygons are squares, rectangles, and triangles. Examples of nonpolygons but still are 2D figures are circles, ovals, and any other flat shape.

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Complete question

How can polygons be considered a subcategory of two-dimensional figures?

Step-by-step explanation:

(A U B) = {1,2, 4, 6, 7}

(A U B)'= U- (A U B) = { 3,5}<------- Answer

The solution is Option A.

The coordinate of the triangle after the translation is given by A' ( 0 , -3 ) with 4 units right and 4 units down

A translation moves a shape up, down, or from side to side, but it has no effect on its appearance. A transformation is an example of translation. A transformation is a method of changing a shape's size or position. Every point in the shape is translated in the same direction by the same amount.

Given data ,

Let the coordinate of the triangle be represented as A

Now , the coordinate A = A ( -4 , 1 )

Now , the coordinate of the triangle after translation is A' ( 0 , -3 )

when there is a translation of the coordinate A by 4 units to the right , we get

A to 4 units right = A ( -4 + 4 , 1 )

The new coordinate of A = A ( 0 ,  1 )

Now , A to 4 units down , we get

The coordinate of A' = A' ( 0 , 1 - 4 )

The coordinate of A' = A' ( 0 , -3 )

Hence , the translated coordinate is A' ( 0 , -3 )

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\(zeros \begin{cases} x=0\implies &x=0\\ x=9\implies &x-9=0\\ x=9\implies &x-9=0 \end{cases}\qquad \implies a(x)(x-9)(x-9)=\stackrel{y}{0} \\\\\\ \stackrel{\textit{with a coefficient of 1}}{1(x)(x-9)(x-9)=y}\implies x(x-9)^2=y\implies x(x^2-18x+81)=y \\\\\\ ~\hfill {\Large \begin{array}{llll} x^3-18x^2+81x=y \end{array}}~\hfill\)

The experimental probability that the next spin falls in a black region is given as follows:

0.205 = 20.5%.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

205 out of the previous 1000 trials fell in the black region, hence the experimental probability is given as follows:

p = 205/1000

p = 0.205.

p = 20.5%.

The problem asks for the experimental probability that the next spin falls in a black region.

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The function can be defined as  price = 6x

It will cost $150 to buy 25 reams of paper.

The domain of the function is all non-negative real numbers, since the number of reams bought cannot be negative.

The range of the function is all non-negative real numbers, since the price cannot be negative.

Fir 25 items, price = 6(25) = $150

It will cost $150 to buy 25 reams of paper.

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Answer:

cioè x ≥ 1; si avrà pertanto x > 0

Step-by-step explanation:

EXERCISE 2. Risolvere le seguenti disuguaglianze:

(1) | x−1 |< 3

(2) | x+1 |> 2

(3) | 2x+1 |< 1

(4) | x−1 |<| x+1 |

Caso: (a): | x−1 |< 3, risolvo

x−1 < 3

x ≥ 1

∪

−x+1 < 3

x < 1

, si avrà quindi

x < 4

x ≥ 1

cioè 1 ≤ x < 4 e

x > −2

x < 1

cioè −2 < x < 1. L’unione tra le due dà la soluzione −2 < x < 4

Caso: (b):

x+1 > 2

x ≥ −1

∪

−x−1 > 2

x < −1

, si avrà quindi

x > 1

x ≥ −1

cioè x > 1 e

x < −3

x < −1

cioè x < −3,

pertanto x < −3 ∪ x > 1

Caso: (c):

2x+1 < 1

x ≥ −1

2

∪

−2x−1 < 1

x < −

1

2

, si avrà quindi

x < 0

x ≥ −1

2

cioè −

1

2 ≤ x < 0 e

x > −1

x < −

1

2

cioè

−1 < x < −

1

2

. pertanto −1 < x < 0

Caso: (d): in questo caso,

−x+1 < −x−1

x < −1

∪

−x+1 < x+1

−1 ≤ x < 1

∪

x−1 < x+1

x ≥ 1

, si avrà quindi

0 < −2

x < 1

cioè non si hanno soluzioni e

x > 0

−1 ≤ x < 1

cioè 0 < x < 1 e

0 < 2

x ≥ 1

cioè x ≥ 1; si avrà pertanto x > 0

The new size of the triangle will increase by a factor 2

The new size of the square will decrease by a factor 4

Dilation refers to a transformation that changes the size of a geometric figure without altering its shape.

When we dilate an image by scale factor, we either enlarge the figure and reduce the figure.

Based on the given diagram, the new length and size of the object is calculated as follows;

For the triangle,

new lengths = 2 times the original length

the new size of the triangle will increase by a factor 2

For the square;

new lengths = 0.25 times the original length

the new size of the square will decrease by a factor 4

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1. Number of athletes did not own any of the three items = 259 - 228

= 31.

2. Number of athletes own a convertible and a TV but not a store = 44 - 9

= 35.

3. Number of athletes own a convertible or a TV = 110 + 91 - 44

= 157.

4. Number of athletes owned exactly one type of item = 60 + 13 + 71 = 144.

5. Number of athletes owned at least one type of item = 259 - 31

= 228

6. Number of athletes own a TV or a store, but not a convertible = 13 + 34 +71

= 118.

The number of athletes did not own any of the three items need to subtract the number of athletes who own at least one item from the total number of athletes surveyed.

Total number of athletes surveyed = 259

Number of athletes own at least one item = 110 + 91 + 120 - 15 - 43 - 44 + 9 = 228

Number of athletes who did not own any of the three items = 259 - 228 = 31.

The number of athletes who owned a convertible and a TV but not a store need to subtract the number of athletes who own all three items from the number of athletes who own a convertible and a TV.

Number of athletes who own a convertible and a TV = 44

Number of athletes who own all three items = 9

Number of athletes who own a convertible and a TV but not a store = 44 - 9 = 35

The number of athletes who owned a convertible, or a TV need to add the number of athletes who own a convertible to the number of athletes who own a TV and then subtract the number of athletes own both a convertible and a TV.

Number of athletes who own a convertible or a TV = 110 + 91 - 44

= 157.

The number of athletes owned exactly one type of item need to add up the number of athletes who own a convertible only the number of athletes own a TV only and the number of athletes who own a store only.

Number of athletes own a convertible only = 110 - 15 - 9 = 86

Number of athletes own a TV only = 91 - 44 - 9 = 38

Number of athletes own a store only = 120 - 15 - 43 - 9 = 53

Number of athletes owned exactly one type of item = 60 + 13 + 71 = 144.

The number of athletes who owned at least one type of item can use the result from part (1).

Number of athletes who owned at least one type of item = 259 - 31

= 228

The number of athletes who owned a TV or a store but not a convertible need to subtract the number of athletes who own all three items, and the number of athletes own a convertible and a TV from the number of athletes own a TV or a store.

Number of athletes own a TV or a store = 91 + 120 - 43 - 9 = 159

Number of athletes own a TV or a store not a convertible = 13 + 34 +71

= 118.

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Answer:

No. ADDED: It is not proportional>

Tyler does not charge a constant rates. The rates are not equal because his rate varies. $12, $12, $15, $13

Step-by-step explanation:

Answer:

----------------------------

Divide the total amount by the cost per piece:

Since the carpenter can only buy whole pieces of wood, they can buy 30 pieces.

13 friends make up 48.1%

14 friends make 51.8%

51.8-48.1 = 3.7

3.7% decrease

We have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

To prove that the Newton-Raphson method for solving the equation \(x^k e^x = 0\), where k is a constant, is given by the formula

\(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n,\)

we can start by considering the iterative process of the Newton-Raphson method.

Given an initial guess \(x_n\), we want to find a better approximation \(x_{n+1}\)that is closer to the root of the equation \(x^k e^x = 0.\)

The Newton-Raphson method involves the following steps:

Calculate the function value \(f(x_n) = x_n^k e^x_n\) and its derivative \(f'(x_n) = k x_n^(k-1) e^x_n.\)

Find the next approximation x_{n+1} by using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Let's apply these steps to our equation \(x^k e^x = 0\):

Calculate the function value and its derivative:

\(f(x_n) = x_n^k e^x_n\\f'(x_n) = k x_n^(k-1) e^x_n\)

Find the next approximation x_{n+1} using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Substituting the function value and its derivative:

\(x_{n+1} = x_n - (x_n^k e^x_n) / (k x_n^(k-1) e^x_n)\\= x_n - (x_n^k / k)\)

Simplifying the expression by combining like terms:

\(x_{n+1} = x_n - (x_n^k / k)\\= x_n - x_n^k / k\\= (k - 1) x_n + x_n^2 / k + x_n\)

Therefore, we have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

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Answer:

(x+2.25) ×24

This is how it is written

Answer:

Step-by-step explanation:

y = 24*(x + 2.25)

There, that's an algebraic expression for 24 times the sum of a number and 2.25.