what is the distance between fringes (in cm) produced by a diffraction grating having 141 lines per centimeter for 653-nm light, if the screen is 1.50 m away? your answer should be a number with two decimal places, do not include unit.

Answer:

0.0136

Explanation:

For the series connection

Effective resistance= 6 + 12= 18 ohm

Current= 6/18=0.33 A

Heat= I^2R= 0.33^2 × 18= 1.96 J

For parrallel

Effective resistance= 6^- 1+12^-1 = 0.167 + 0.083= 0.25 ohm

Current= 6/0.25= 24 A

Heat= 24^2 × 0.25=144J

Ratio of series to parallel= 1.96/144=0.0136

A shuffleboard disk is accelerated at a constant rate from rest to a speed of 6.0 m/s over a 1.8 m distance by a player using a cue. at this point the disk loses contact with the cue and slows at a constant rate of 2.5 m/s2until it stops. Therefore, it takes about 3 seconds to elapse from, when the disk begins to accelerate until it stops. It is because,

Given, u = 0 m/s, v = 6 m/s and s = 1.8 m

It is given that acceleration is constant so we can use,

⇒ v² = u² + 2as

Hence, putting the values, u = 0 m/s, v = 6 m/s and s = 1.8 m,

⇒ (6)² = 0² + 2 a × 1.8

⇒ a = 10 m/s²,

Using v = u + at,

Putting values again, u = 0 m/s, v = 6 m/s and a = 10 m/s²,

⇒ 6 = 0 + 10t

⇒ t = 0.6 s

Time taken during distance 1.8 m in 0.6 seconds,

Now, acceleration changes as, a = -2.5 m/s² and board stops, that is v =0,

⇒ v = u + at,

Putting values, u = 6 m/s, v = 0 m/s and a = -2.5 m/s²

⇒ 0 = 6 - 2.5t,

⇒ t = 2.4 s,

Time taken during to stop after 1.8 m is 2.4 seconds.

Total time taken = 2.4 + 0.6 = 3 seconds.

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A obtained experimental is indeed a long, narrow chunk of stone that is extracted by drilling a hole through a rock with such a unique tool and lifting out an undamaged piece of the rock.

Work is being done on the thing as you lift it. The equation W = Fd describes the work W performed on an item by a constant force. It is determined by multiplying the force's intensity by how far the object is moved by the force.

Surface and body are no longer in contact when the body is lifted, eliminating any frictional forces. For the simple reason that friction opposes any relative motion between a surface and a substance (both are in contact).

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1. The non-destructive testing (NDT) method is a test that is carried out to detect and evaluate flaws in materials. It is a testing technique that does not damage the object being tested. The non-destructive testing method that uses a magnet yoke for the identification of defects in metal components is known as Magnetic particle testing (MPT).

2. Cold rolling of metals increases the hardness of the metal by causing dislocations and deformations in the crystal lattice of the metal. During cold rolling, the metal is deformed below its recrystallization temperature, which hardens the metal and makes it stronger.

3. To produce the hardest surface on metal, hardening heat treatment methods such as flame hardening, induction hardening, and carburizing can be used.

4. Yes, Brass can be a meal at 500°F because it is a metal alloy that is composed of copper and zinc, and it has a melting point of around 900 to 940°F.

5. The casting process that can make the largest castings is known as sand casting. Sand casting is a process of making metal castings by pouring molten metal into a sand mold. Sand casting is the most widely used casting process because it is capable of producing castings of virtually any size and shape.

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Answer:   this was the answer you were looking for -

Explanation

Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

When one physics professor talking produces a sound intensity level of 51 dB, then 100 physics professors talking simultaneously would produce a sound intensity level of 71 dB.

The sound intensity level (SIL) is measured in decibels (dB) and is logarithmic in scale. When two sound sources are combined, the resulting SIL is calculated by adding the SILs of each source. The equation for calculating the combined SIL in dB is:

\(SIL_{combined} = 10 log10(I_{combined} / I_0)\)

where:

\(I_{combined} = the\  combined \ sound \ intensity (W/m^2)\)

\(I_0 = the \ reference \ sound \ intensity (1 \times 10^{-12}\  W/m^2)\)

Assuming that the sound intensity level of each physics professor talking is the same (51 dB), the combined sound intensity level of 100 physics professors talking simultaneously can be calculated as follows:

\(SIL_{combined} = 10 log10(I_{combined} / I_0)\)

\(51\  dB = 10 log10(I_1 / I_0)\)

where \(I_1\)is the sound intensity of one physics professor talking. Solving for\(I_1\), we get:

\(I_1 = I_0 \times 10^(SIL_{combined} / 10)\)

To calculate the combined sound intensity, we need to use the SIL formula to find SIL_combined:

\(SIL_{combined} = 51 \ dB + 10 log10(100)\)

\(SIL_{combined} = 51 \ dB + 10 log10(10^2)\)

\(SIL_{combined} = 51 \ dB + 20 \ dB\)

\(SIL_{combined} = 71 \ dB\)

Therefore, the sound intensity level of 100 physics professors talking simultaneously is approximately 71 dB (with two significant figures).

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The voltage across the capacitor is VC = 0 - j0.003654V.

The circuit given on the right is a series circuit comprising a resistor R, an inductor L, and a capacitor C. The applied voltage is given as δV = δVmax sin(ωt) where δVmax = 51V and ω = 15rad/s. The values of L, R and C are 0.6H, 25Ω and 0.011F respectively.

The complex impedance of the circuit is given as follows;

Z = R + jωL - j/ωC = 25 + j(15)(0.6) - j(1/15)(0.011)

= 25 + j9 - j0.000733=

25 + j8.99927Ω

The amplitude of the current in the circuit is given as;

I = V/Z where V is the amplitude of the applied voltage.

Substituting the values of V and Z;

I = δVmax/Z= 51/(25 + j8.99927)

The current in the circuit is thus;

I = 1.661 - j1.8355A.

The voltage drop across each component can be obtained by multiplying the amplitude of the current by the impedance of each component. The voltage across the resistor is given as;

VR = IR = (1.661)(25) = 41.525V

The voltage across the inductor is given as;

VL = jωLI = j(15)(0.6)(1.661) = j14.98V

The voltage across the capacitor is given as;

VC = -j(1/ωC)I = -j(1/15)(0.011)(1.661)

= -j0.003654V

The voltage across the capacitor is thus;

VC = 0 - j0.003654V.

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Answer:

A

Explanation:

Explanation:

Speed = distance / time

= 20 km / 1 hr

= 20 km/hr

≈ 5.56 m/s

Three identical capacitors are connected in parallel to a potential source (battery). If a charge of Q flows into this combination, Each capacitor will carry a charge of Q/3.  

A capacitor is a two-terminal electrical device that can store energy in the form of an electric charge. It consists of two electrical conductors that are separated by a distance. The space between the conductors may be filled by vacuum or with an insulating material known as a dielectric.capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.

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Time taken to slow down the speed will be 5 seconds.

Average acceleration of the bus, a = 1.8 m/s²

Initial velocity of the bus, u = 9.0 m/s

Final velocity of the bus, v = 0 m/s

According to the First Equation of the motion which relates the acceleration, velocity and time we can say that

v = u + at

v - u = at

0 - 9 = (-1.8) * t

9 = 1.8 * t

t = \(\frac{9}{1.8}\)

t = 5 s

Therefore 5 seconds will be required by the bus to slow down its speed from 9.0 m/s to 0.0 m/s

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Answer:

Original fundamental frequency = 311.111 Hz (Approx)

Explanation:

Given:

Frequency (f) = 560 Hz

3rd harmonic

Used length = 60%

Find:

Original fundamental frequency.

Computation:

Fundamental frequency = Frequency (f) / 3rd harmonic

Fundamental frequency = 560 / 3

Original fundamental frequency = 560 / 3(60%)

Original fundamental frequency = 560 / 1.8

Original fundamental frequency = 311.111 Hz (Approx)

Answer:

Friction of the mountain on the skier in the opposite direction

Explanation:

answered it on khan academy

Friction of the mountain on the skier in the opposite direction.

A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.

Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).

There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Therefore, Friction of the mountain on the skier in the opposite direction.

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The necessary to determine the amount of thermal energy applied to the water by the stove is option C. The initial temperature of the room, the initial mass of water, the specific heat of water, the latent heat of fusion of water, and the boiling point of water.

The latent heat of fusion, also known as enthalpy of fusion, is the quantity of strength that should be furnished to a solid substance (generally in the form of heat) so as to cause a trade in its bodily kingdom and convert it right into a liquid.

Thermal electricity refers to the energy contained inside a device that is chargeable for its temperature. heat is the go with the flow of thermal power. a whole branch of physics, thermodynamics, offers how heat is transferred between distinct systems and the way paintings is carried out inside the method (see the 1ˢᵗ regulation of thermodynamics.

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Answer:

GPE = 1.47 Joules.

Explanation:

Given the following data;

Mass = 1kg

Height = 0.15m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

\( G.P.E = mgh\)

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

GPE = 1*9.8*0.15

GPE = 1.47 Joules.

1) The initial velocity of the hoop is 0.  2) T = (0.75 kg)(a) + (0.75 kg)(9.8 m/s² 3)  t = \(\sqrt{\frac{2}{a} }\)  4) ω = (1 m / t) / 0.25 m

1. The acceleration of the centre of the hoop

Weight of the hoop (W): This force acts vertically downwards and is equal to the mass of the hoop (M) multiplied by the acceleration due to gravity (g). The initial velocity of the hoop is 0.

2. The tension force in the string

Tension force in the string (T): This force is directed upwards and is responsible for providing the necessary centripetal force to keep the hoop in circular motion.

The force acting on the hoop, which is given by the difference between the tension force and the weight:

Net force = T - W

Using Newton's second law (F = ma),  the net force to the acceleration (a) of the hoop:

T - W = Ma

Rearranging the equation:

T = Ma + W

Substituting the values: R = 0.25 m, M = 0.75 kg, and g = 9.8 m/s²2:

T = (0.75 kg)(a) + (0.75 kg)(9.8 m/s²2)

Tension force in the string:

The tension force in the string is the same in both cases. Using the same equation as above:

T = (0.75 kg)(a) + (0.75 kg)(9.8 m/s²2)

3. The time it takes the hoop

Time taken for the hoop to descend 1 m

To calculate the time, To determine the initial velocity of the hoop. Since it starts from rest, the initial velocity is 0. We can use the kinematic equation

s = u t + (1/2)at²2

Here, s is the distance travelled (1 m), u is the initial velocity (0 m/s), a is the acceleration, and t is the time .

Substituting the values: s = 1 m, u = 0 m/s, and solving for t:

1 = (1/2)(a)t²2

t²2 = 2/a

t = sqrt(2/a)

4. Angular speed the angular speed of the hoop

The linear speed (v) of the hoop can be related to its angular speed (ω) using the formula

v = Rω

The linear speed by multiplying the angular speed by the radius of the hoop. Since we know the linear distance travelled (1 m) and the time (t), we can calculate the linear speed:

v = s/t

Finally,  the linear speed to the angular speed:

v = Rω

Now,  the angular speed (ω) by rearranging the equation:

ω = v/R

Substituting the values: v = s/t and R = 0.25 m:

ω = (1 m / t) / 0.25 m

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The energy of the laser pulse as it exits the medium is 3.09 * 3 = 9.27 J. The net burst of light energy is 4.0 x 10^16 * 63 * 1.6022 x 10^-19 = 3.856 x 10^14 W. The half-life of the atom is 2.0 * 60 = 120 seconds. The Boltzmann constant is k = 1.38 x 10^-23 J/K.

The time it will take for 1/8 of the original number of atoms to be in the excited state is 62 * 2 = 124 seconds.

The wavelength of the pulse is 2.0 kW * 3.0 µs / 5.2 x 10^22 = 1.18 nm.

The temperature at which you expect to find 10% of the atoms in the E₁ state and 90% in the E, state is 5300 K.

Here is the calculation:

The energy difference between the E₁ and E₂ states is hc/λ = 6.626 x 10^-34 J s * 3 x 10^8 m/s / 979 nm = 2.09 x 10^-19 J.

The Boltzmann constant is k = 1.38 x 10^-23 J/K.

The temperature at which the population of the two states is equal is given by the following equation:

E_1 / k T = E_2 / k T

T = E_1 / E_2

T = 2.09 x 10^-19 J / 6.626 x 10^-19 J = 0.315 K

Rounding to the nearest Kelvin, we get T = 5300 K.

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If you launch a cannon at 15 degrees above horizontal, and another cannon at 75 degrees above horizontal, both will have same horizontal range

In a projectile motion , horizontal range can be calculated using formula

Range = \(u^{2}\) sin ( 2 theta) / g

where

u = initial velocity

theta = angle along the horizontal

g = acceleration due to gravity

if we substitute the value of 15 and 75 in formula , we get

sin ( 2 * theta_1 ) = sin ( 2*15 ) = sin 30 = 1/2

sin ( 2* theta_2 ) = sin ( 2 * 75 ) = sin (150) = 1/2

both the values are coming out to be equal

hence , will have equal value of horizontal range

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Answer:

I'M SO SORRY I SAW THIS TOO LATE :<

Explanation:

im pretty sure it's falseeee, information would probably be accurate

Answer:

There are actually three, Kepler's laws that is, of planetary motion: 1) every planet's orbit is an ellipse with the Sun at a focus; 2) a line joining the Sun and a planet sweeps out equal areas in equal times; and 3) the square of a planet's orbital period is proportional to the cube of the semi-major axis of its

In this scenario, the experimenter would observe that the intensity of the reflected ray is reduced to zero when the transmission axis of the polarizer is perpendicular to the surface of the water.

This happens because the reflected ray is polarized in a direction perpendicular to the plane of incidence, and when the transmission axis of the polarizer is also perpendicular to this direction, it blocks the reflected ray completely. The refracted ray, on the other hand, is polarized in a direction parallel to the plane of incidence, so it would not be affected by the polarizer in this orientation.

This phenomenon is known as Brewster's law and can be used to determine the refractive index of the liquid.

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Answer and Explanation:

For computing the displacement at point B and D we need to determine the following calculations

\(P_Net = P_C + P_E + P_B\)

= 250 + 350 - 50

= 550 N

Now the deflection for bar AB is

\(\delta_{AB} = \frac{PL_{AB}}{AE} \\\\ = \frac{550 \times 500}{6,000 \times 200 \times 10^{3}}\)

Now for bar BC it is

\(\delta_{BC} = \frac{PL_{BC}}{AE} \\\\ = \frac{(550 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 1.5 \times 10^{-04} mm\)

And for bar CD it is

\(\delta_{CD} = \frac{PL_{CD}}{AE} \\\\ = \frac{(550 -250 + 50) \times 250}{5,000 \times 200 \times 10^{3}} \\\\ = 0.875 \times 10^{-4} mm\)

Now the displacement is as follows

For B

2.292 × 10^{-4} mm

For D, it is

\(= 2.292 \times 10^{-4} + 1.5 \times 10^{-4} + 0.875 \times 10^{-4} mm \\\\ = 4.667 \times 10^{-4} mm\)

We simply applied the above formulas for determining the  displacements at points B, D and the same is to be considered  

Answer:

initial velocity (u)=0

final velocity (v)=80m/s

time(t)=5s

acceleration (a)=?

Explanation:

we have

v=u+at

80=0+a×5

5a=80

a=80/5=16m/s²

Answer:

33 Newton upwards to get a net force of zero.

Answer:

The answer is 33 newtons with a net force of 0

Explanation:

Answer:

6.25 m/s

Explanation:

The average speed of an object is the ratio of the total distance traveled by the object and the total time taken to cover the distance. Mathematically,

Average speed = total distance traveled/total time taken.

In this case;

Total distance traveled = 650 + 850 = 1500 m

Total time = 240 s

Average speed = 1500/240 = 6.25 m/s

The average speed of the man is, therefore, 6.25 m/s.

Answer:

false gravity is not considered matter

All of the determinants listed are factors that can affect the price elasticity of demand.

The determinant of the price elasticity of demand that is NOT one of the determinants is:

D) Availability of substitutes

The determinants of price elasticity of demand include:

A) Availability of close substitutes: If there are many close substitutes available for a product, consumers have more options to switch to alternative products when the price changes, resulting in higher price elasticity of demand.

B) Necessity or luxury goods: Necessity goods tend to have lower price elasticity of demand because consumers are less likely to change their purchasing behavior even if the price changes. Luxury goods, on the other hand, tend to have a higher price elasticity of demand as consumers may be more responsive to price changes.

C) Proportion of income spent: If a product represents a significant proportion of a consumer's income, the price elasticity of demand is likely to be higher. Consumers are more sensitive to price changes for products that consume a larger portion of their income.

D) Availability of substitutes: This option is incorrect as it is indeed one of the determinants of price elasticity of demand. The availability of substitutes affects the price elasticity of demand. When there are more substitutes available, consumers have more options to switch to alternative products, making the demand more elastic.

Therefore, the correct answer is not provided in the options given, as all of the determinants listed are factors that can affect the price elasticity of demand.

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