What is the difference between distilled water and purified water.

The next general chemistry subject is CHEM 107: General College Chemistry II, which comes after CHE 105. Due to the heavy math and extensive equation memorization required, some individuals find CHEM 107 to be more difficult than CHE 105.

Fundamentals of Chemistry, or CHEM 107, is a required subject for students majoring in allied health, engineering, or science. It examines general chemistry topics. States of matter, atomic structure, the periodic chart, bonds, nomenclature, chemical reactions, chemical equations, and quantitative connections are some of the subjects covered. The target audience for this course is primarily students planning to enroll in more advanced chemistry classes. CHEM 108 functions as the supplementary lab for students who require one. 1 hour of recitation and 3 lesson hours each week. Every autumn and spring, as well as possibly during additional sessions, the course is offered.

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a. There are 0.1596 moles of NaCl in 0.3 L of NaCl stock solution.

b. There are 0.1596 moles of NaCl in 2.1 L of NaCl dilute solution.

c. The concentration of NaCl in the final solution is 0.076 M.

Molarity is said to be the number of moles of solute per liter of solution. For example, when salt is dissolved in water, the salt becomes the solute and the water becomes the solution. Since, one mole of sodium chloride weighs 58.44 grams and dissolving 58.44 grams of NaCl in 1 liter of water makes a 1 molar solution, abbreviated as 1M.

c. Let's calculate the concentration of NaCl in the final solution:

M₁V₁ = M₂V₂

M₁ = Initial concentration of NaCl (0.532 M)

V₁ = Initial volume of NaCl (0.3 L)

M₂ = Final concentration of NaCl

V₂ = Initial volume of NaCl (2.0 L)

0.532 × 0.3 = M₂ × 2.1

M₂ = (0.532 × 0.3)/2.1

M₂ = 0.076 M

a. To calculate number of moles in 0.3 L of NaCl stock solution.

Molarity = Mole of solute/Volume of solution

0.532 = Mole of NaCl/0.3

Mole of NaCl = 0.532×0.3

Mole of NaCl = 0.1596 mol

b. To calculate number of moles in 2.1 L of NaCl solution.

0.076 = Mole of NaCl/2.1

Mole of NaCl = 0.076×2.1

Mole of NaCl = 0.1596 mol

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Answer:

the 3rd one

Explanation:

In an ionization counter, radioactive emissions collide with gas particles, producing ion pairs, which can be detected as an electric current.

The radiation ionizes the gas atoms or molecules, creating charged particles that are then collected as a current, allowing for the detection and measurement of radioactivity.

On the other hand, a scintillation counter detects radioactive emissions by its ability to excite atoms and cause them to emit photons (light). The radiation interacts with certain materials, such as scintillators, which absorb the energy and re-emit it as visible light. The emitted light is then converted into an electric current through the photoelectric effect or the use of photomultiplier tubes, enabling the detection and measurement of radioactivity based on the emitted light intensity.

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Answer:

394.68 J

Explanation:

The amount of heat gained or lost by an object when its temperature changes can be calculated by using the formula:

\(\boxed{\sf c = \dfrac{Q}{m \cdot \Delta T}}\)

where:

The initial temperature of the marble was 22°C and its final temperature is 45°C. Therefore, the change in temperature, ΔT, is:

\(\implies \sf \Delta T=45^{\circ}C-22^{\circ}C=23^{\circ}C\)

Therefore, the values to substitute into the formula are:

Substitute these values into the formula:

\(\implies \sf \dfrac{0.858\;J}{g \cdot \!\!\!\!\phantom{2}^{\circ}C}}=\dfrac{Q}{20.0\;g \cdot 23 ^{\circ}C}\)

\(\implies \sf Q=\dfrac{0.858\;J \cdot 20.0\;g \cdot 23^{\circ}C}{g \cdot \!\!\!\!\phantom{2}^{\circ}C}}\)

\(\implies \sf Q=0.858\;J \cdot 20.0 \cdot 23\)

\(\implies \sf Q=394.68\;J\)

Therefore, 394.68 J of heat is required to raise the temperature of 20.0 g of marble from 22°C to 45°C.

\(\blue{\huge {\mathrm{SPECIFIC \; HEAT \; CAPACITY}}}\)

\(\\\)

\({===========================================}\)

\({\underline{\huge \mathbb{Q} {\large \mathrm {UESTION : }}}}\)

\({===========================================}\)

\( {\underline{\huge \mathbb{A} {\large \mathrm {NSWER : }}}} \)

\({===========================================}\)

\({\underline{\huge \mathbb{S} {\large \mathrm {OLUTION : }}}}\)

The formula for calculating the amount of heat required to raise the temperature of an object is:

where

Using the given values, we can plug them into the formula:

\(\begin{aligned}\sf Q& =\sf 20.0\: g \cdot 0.858\: J/g^{\circ}C \cdot (45^{\circ}C - 22^{\circ}C)\\& =\sf 20.0\: g \cdot 0.858\: J/g^{\circ}C \cdot 23^{\circ}C \\& = \boxed{\bold{394.68\: J}}\end{aligned}\)

Therefore, the amount of heat required to raise the temperature of 20.0 g of marble from 22°C to 45°C is 394.68 Joules.

\({===========================================}\)

\(- \large\sf\copyright \: \large\tt{AriesLaveau}\large\qquad\qquad\qquad\qquad\qquad\qquad\qquad\tt 04/02/2023\)

Answer: distance by time

20/2=10

Explanation:

Answer: True

Explanation:

because

Answer:

True

Explanation:

I took the test

Answer:

Anything below 7.0 is acidic, and anything above 7.0 is alkaline, or basic. pH scale, ranging from 0 (very acidic) to 14 (very basic/alkaline) and listing the pH values of common substances.

Explanation:

PRESS THE CROWN

The pH scale ranges from 0 to 14. A pH of 7 is neutral. A pH less than 7 is acidic. A pH greater than 7 is basic.

Explanation:

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

When the temperature is increased, there is the increase in thermal energy of the system. The final temperature of the iron in kelvins is 570 K.

The energy is the ability to do work.

Given is the energy Q = 3.5 kJ = 3500 J, mass of sample m = 28.2 g, specific heat of iron Cp = 0.449 J(g•K).

The initial temperature in kelvins is T1 = 20°C = 20 + 273 = 293K

The heat is related to the temperature difference as

Q = m c ∆T

Substitute the values into the expression,

3500 = 28.2 × 0.449 × ∆T

3500 = 12.6618 × (T2 -T1)

T2 - T1 = 276.4220

T2 = 276.4220 K +293 K

T2 = 569.4220K

The temperature of the iron is approximately 570 K.

Thus, the final temperature of the iron in kelvins is 570K.

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The daughter nucleus that is produced is ₂₉⁶³cu.

What is Electron capture?

The process of drawing an electron to the nucleus, where it combines with a proton to create a neutron and a neutrino particle, is known as electron capture.

The daughter nucleus is the nucleus that is made by the parent nucleus. The nucleus that remains after the decay is called the daughter nucleus.

Here is the chemical formula for the reaction that results in the electron capture of the zinc-63 nucleus:

\(_A^ZX + e^- = _A^Z_-_1 Y + ye\)

\(_3_0^6^3Zn\; + e^- = _2_9^6^3Cu + ye\)

Thus, the daughter nucleus produced when zn63 undergoes electron capture is \(_2_9^6^3Cu\).

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Answer:

36

Explanation:

H - 1

O - 16

H2O = 2(1) + 16 = 18

2(H2O) = 36

The earth contains a lot of oxygen. According to estimates of the proportions of various atom types present in the cosmos, oxygen ranks fourth in terms of abundance, behind hydrogen, helium, and neon. Here among the given elements, oxygen is 16th element. The correct option is A.

Five elements make up group 16 of the contemporary periodic table: oxygen, sulphur, selenium, tellurium, and polonium. Because several of the elements in this group may be recovered from oxide or sulphide ores, they are frequently referred to as chalcogens or ore-forming elements.

O is used as the chemical symbol for oxygen. It is a tasteless, colourless gas that humans breathe in order to create carbon dioxide during the respiration process. As a diatomic molecule (O₂), oxygen exists.

Thus the correct option is A.

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Your question is incomplete, most probably your full question was:

Electron dot diagrams for four elements are shown. Which element would be found in group 16?

A. Oxygen

B. Carbon

C. Boron

D. Helium

Answer:

Explanation:

N =  14.007 g/mol

H = 1.008 g/mol

S = 32.065 g/mol

O = 16 g/mol

2(14.007) + 8(1.008) + 32.065 + 4(16) = 132.143 g/mol

Now you know how much an entire mol weight you multiply it by how much you actually have

0.00456 * 132.143 = 0.603 g

Answer:

When a large, fissile atomic nucleus such as uranium-235 or plutonium-239 absorbs a neutron, it may undergo nuclear fission. The nucleus splits into two or more lighter nuclei, releasing kinetic energy, gamma radiation, and free neutrons.

Explanation:

Answer:

a, b

Explanation:

look at rock cycle charts, I knew this since 2nd grade

Answer:

its c and d

Explanation:

I took the test got 100%

The molarity of the sodium bicarbonate solution is 11.2 M.

We need to know the amount of sodium bicarbonate (NaHCO₃) dissolved in a given volume of solution to calculate its molarity. Let's assume that we have dissolved 1 tsp (teaspoon) of NaHCO₃ in a solution.

According to the problem, 1 tsp = 4.9 mL. We need to convert the volume into liters:

4.9 mL = 4.9/1000 L = 0.0049 L

Now we need to know the amount of NaHCO₃ in moles that is dissolved in this volume of solution. The molar mass of NaHCO₃ will be 84.01 g/mol. Let's assume that the NaHCO₃ is pure and completely dissolved in the solution.

We can use the following formula to calculate the molarity of the solution:

Molarity (M) = moles of solute/liters of solution

moles of NaHCO₃ = mass of NaHCO₃ / molar mass of NaHCO₃

Assuming 1 tsp of NaHCO₃ is equivalent to 4.6 g (which is the approximate weight of 1 tsp of NaHCO₃), we can calculate the moles of NaHCO₃:

moles of NaHCO₃ = 4.6 g / 84.01 g/mol = 0.0548 moles

Now we substitute the values into formula for molarity:

Molarity (M) = 0.0548 moles / 0.0049 L

= 11.2 M

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The answer is (e) 70 milliliters.

Let's assume that x milliliters of the 35% saline solution were used.

The total amount of saline in the solution can be calculated as follows:

Saline in 35% solution = 0.35 * x

Saline in 75% solution = 0.75 * 10 (since 10 milliliters of the 75% solution were used)

The total amount of saline in the resulting 40% solution can be calculated as:

Saline in 40% solution = 0.40 * (x + 10)

Since the saline is being mixed, the total saline in the resulting solution is equal to the sum of the saline in the individual solutions:

0.35 * x + 0.75 * 10 = 0.40 * (x + 10)

Simplifying the equation:

0.35x + 7.5 = 0.40x + 4

Subtracting 0.35x and 4 from both sides:

7.5 - 4 = 0.40x - 0.35x

3.5 = 0.05x

Dividing both sides by 0.05:

x = 3.5 / 0.05

x = 70

Therefore, 70 milliliters of the 35% saline solution were used. The answer is (e) 70 milliliters.

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The process of breathing involves exchanging oxygen for carbon dioxide gas.

The process of breathing involves inhalation and exhalation.

Inhalation is the process of taking in oxygen and Exhalation is the process of taking out carbon dioxide. Air contains 21 % oxygen and 71 % nitrogen and 8 % other gases.

When we breathe in(inhalation) our diaphragm contracts downward while during breath out(exhalation) our diaphragm contracts upward. As food and water are important for us in similar way breathing is also essential for life.

So during the process of breathing, we take in oxygen and take out carbon dioxide.

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Answer:

Any two reasons will be :

1:- It is based on atomic number.

2:-Problem regarding Position of isotopes is resolved.

Hope this helped

Hope this helped ALL THE BEST !!

Answer:

The modern periodic table has more info and more elements

Explanation:

Answer:

laws:)

Explanation:

Z=35

Electronic configuration:-

\(\\ \sf\longmapsto 1s^22s^22p^63s^23p^64s^23d^104p^5\)

Lab participants should always look at the safety data sheet (SDS) of a substance before using the substance.

The correct option is B.

The safety data sheet (SDS) contains details about the physical, physiological, and environmental dangers of each chemical, as well as information about how to handle, store, and transport each chemical safely.

The information in a safety data sheet is for:

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Answer:

the second one

Explanation:

because there are 3 of Na and one N

Answer:

The answer should be krypton Im doing the test rn.

Explanation:

The most reactive element in period 4 which is shiny and forms a +1 cation is potassium.

The periodic table is defined as an arrangement of elements in groups and periods. The elements in the same group have similar properties while the elements in the same period has the same number of shells.

The element in period 4 that is shiny, forms a cation of +1 charge and is the most reactive in period 4 is the element potassium.

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After the calculating we have Test statistic: -3.874.

Critical values: -2.086 and 2.086.

To test if the population mean pH of rainwater is equal to 5.4, we can perform a one-sample t-test.

We have the data:

Population mean (μ) = 5.4

Sample mean (x) = 4.7

Sample standard deviation (s) = 0.8

Sample size (n) = 21

Significance level (α) = 0.05

To calculate the test statistic, we can use the formula:

t = (sample mean - population mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values:

t = (4.7 - 5.4) / (0.8 / √(21))

Calculating:

t ≈ (-0.7) / (0.8 / 4.582)

t ≈ -3.874

The test statistic is approximately -3.874.

To find the critical values, we need to refer to the t-distribution table or use statistical software. At a significance level of α = 0.05 with (n-1) degrees of freedom (n = sample size), the critical values for a two-tailed test are approximately -2.086 and 2.086.

Therefore, the correct answer is:

Test statistic: -3.874.

Critical values: -2.086 and 2.086.

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The balanced chemical equation you provided is:

C8H16 + 120 O2 -> 8 CO2 + 8 H2O

From this balanced equation, we can determine the mole ratios between the reactants and products. The coefficients in the balanced equation represent the number of moles of each substance involved in the reaction.

Mole ratio between C8H16 and CO2:

For every 1 mole of C8H16, 8 moles of CO2 are produced.

Mole ratio between C8H16 and H2O:

For every 1 mole of C8H16, 8 moles of H2O are produced.

Mole ratio between C8H16 and O2:

For every 1 mole of C8H16, 120 moles of O2 are consumed.

Mole ratio between CO2 and C8H16:

For every 8 moles of CO2 produced, 1 mole of C8H16 is consumed.

Mole ratio between H2O and C8H16:

For every 8 moles of H2O produced, 1 mole of C8H16 is consumed.

Mole ratio between O2 and C8H16:

For every 120 moles of O2 consumed, 1 mole of C8H16 is consumed.

These mole ratios describe the stoichiometric relationship between the reactants and products in the given chemical equation.

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Answer:To calculate the concentration of the Fe(NO3)3 solution after dilution, we can use the formula:

Explanation:

C1V1 = C2V2

C1 = Initial concentration of the solution

V1 = Initial volume of the solution

C2 = Final concentration of the solution

V2 = Final volume of the solution

Initial concentration (C1) = 3.0 M

Initial volume (V1) = 80 mL

Final volume (V2) = 1500 mL

Using the formula, we can solve for C2:

C1V1 = C2V2

(3.0 M)(80 mL) = C2(1500 mL)

Rearranging the equation to solve for C2:

C2 = (C1V1) / V2

C2 = (3.0 M)(80 mL) / 1500 mL

C2 ≈ 0.16 M

Therefore, the concentration of the Fe(NO3)3 solution after dilution is approximately 0.16 M.

we have an initial solution of Fe(NO3)3 with a concentration of 3.0 M and a volume of 80 mL. The goal is to dilute this solution to a final volume of 1500 mL and determine the concentration of the diluted solution.

To do this, we can use the dilution formula: C1V1 = C2V2, where C1 and V1 represent the initial concentration and volume, and C2 and V2 represent the final concentration and volume.

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