What is the density of this liquid that has a mass of 300g and volume 600ml.

Answer:

c. natural resources

Explanation:

mercantilism is an economic practice by which governments use their economies

if am ryt

Answer:

C. natural resources

Explanation:

Mercantilism is based on the concept of a nation's power being directly related to its wealth. A nation's goal under mercantilism was to obtain as much gold and silver as possible and to export more goods than it imported from other nations. Gold and Silver are natural resources.

Answer:

A scientific model is a physical and/or mathematical and/or conceptual representation of a system of ideas, events or processes. Scientists seek to identify and understand patterns in our world by drawing on their scientific knowledge to offer explanations that enable the patterns to be predicted.

Answer:

D

Explanation:

Given,

The work done by the engine, W=23 kJ

The time it takes for the engine to do the given amount of the work, t=1800 s

The power is the time rate of change of transfer of energy or the energy transferred in unit time. Thus the power supplied by the engine can be calculated as the ratio of the work done to the time.

Thus the power supplied by the engine is given by,

On substituting the known values,

Thus the power supplied by the engine is 12.78 W.

Answer:

Plasma is by far the most common form of matter. Plasma in the stars and in the tenuous space between them makes up over 99% of the visible universe and perhaps most of that which is not visible. On earth we live upon an island of "ordinary" matter.

The geothermal gradient in the tectonically stable region is approximately 21°C/km, indicating that the temperature increases by an average of 21 degrees Celsius per kilometer of depth.

To calculate the geothermal gradient, we need to find the rate at which the temperature increases with depth.

Temperature at the surface (T₁) = 14°C

Temperature at a depth of 5.0 km (T₂) = 119°C

Temperature difference = T₂ - T₁ = 119°C - 14°C = 105°C

Depth difference = 5.0 km - 0 km = 5.0 km

Geothermal gradient = Temperature difference / Depth difference

Geothermal gradient = 105°C / 5.0 km

Calculating this expression, we find:

Geothermal gradient ≈ 21°C/km

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The wavelength of the absorbed photon when the oscillator undergoes a transition from the n = 2 to the n = 3 energy level is 4.93 μm.

The energy of a photon with a particular wavelength is given by the equation:

E = hc/λ

where E is the energy of the photon, h is Planck's constant (6.626 x 10⁻³⁴ J s), c is the speed of light (2.998 x 10⁸ m/s), and λ is the wavelength of the photon.

When a harmonic oscillator undergoes a transition from the n = 1 to the n = 2 energy level, the energy absorbed is equal to the difference in energy between the two levels:

ΔE = E₂ - E₁ = hν

where ΔE is the energy absorbed, E₁ is the energy of the n = 1 level, E₂ is the energy of the n = 2 level, and ν is the frequency of the absorbed photon. Since the oscillator is a harmonic oscillator, the energy levels are given by the equation:

En = (n + 1/2)hν0

where En is the energy of the nth level, ν0 is the frequency of the oscillator, and n is an integer.

We can rearrange this equation to solve for the frequency of the oscillator:

ν₀ = En / ((n + 1/2)h)

For the n = 1 to n = 2 transition, we can set n = 1 and n = 2 to find the frequencies of the two levels:

ν₁ = E1 / (3/2 h)

ν₂ = E2 / (5/2 h)

Substituting the energy difference ΔE = hν and the wavelength λ = c/ν into these equations, we get:

ν₂ = (E₁ + ΔE) / (5/2 h) = (hc/λ + ΔE) / (5/2 h)

λ = hc / (ν₂ (5/2 h) - ΔE)

λ = (6.626 x 10⁻³⁴ J s x 2.998 x 10⁸ m/s) / ((1.5 x 6.90 x 10⁻⁶ m⁻¹) x (5/2 x 6.626 x 10⁻³⁴J s) - (4.64 x 10⁻¹⁹J))

λ = 4.93 μm

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The number of ring particles in Saturn's rings if total mass of material in Saturn's rings is about 10¹⁸ kg is 6.67 * 10¹⁷

ρ = m / V

ρ = Density

m = Mass

V = Volume

ρ = 1000 kg / m³

r = 6 cm = 0.06 m

V = 4 / 3 π r³

V = 4 / 3 * 3.14 * ( 0.06 )³

V = 0.015 m³

m = ρ V

m = 1000 * 0.015

m = 15 kg

The total mass of Saturn's ring is 10¹⁸ kg

Mass of one particle of a Saturn ring = 15 kg

Total number of particles = 10¹⁸ / 15

Total number of particles = 6.67 * 10¹⁷

Therefore, the number of particles is 6.67 * 10¹⁷

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An automobile accelerates at the rate of 57 m/s² with a final velocity of 15 m/s. Then, the distance covered by the automobile will be equal to 1.97 meters.

A moving object's speed and orientation vary over time at a certain rate, which is known as acceleration.

An object or location is considered to be accelerated when it moves more quickly or more slowly in a straight path. A circle's motion increases despite its constant speed because its direction is always changing. For all other motions, by and to velocity is used.

Because of its magnitude and direction, it is a vector quantity.

As per the given information in the question,

Acceleration, a = 57 m/s²

Final velocity, v = 15 m/s

Use the equation of motion,

v² - u² = 2as

Put the values in the equation,

15² - 0 = 2(57)(s)

s = 225/114

s = 1.97 meters.

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Answer:

Limestone classifacation: sedimentary rock

Sandstone: sedimentary rock

Answer:

1. True - gravity affects the y motion

2. False - x-coordinates affect the horizontal motion

3. y because gravity affects motion in  the y-direction

4. x generally no external forces act in the x direction and hence no acceleration in the x direction

The net force is F   = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N

Coulomb's law states that the electrostatic force of attraction between two charges separated by a distance r, q 1 and q 2, is given by:

F = k (q1q2/r2)

Coulomb's constant k = 9×\(10^{9}\) Nm2/Kg2

Location of charge q3: P (0,d2,d2)

By Coulomb's law, the force on charge q0 due to q3 is:

F = k × q0 × q3 / \(d_{2} ^{2}\) × \(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^ k)

F   = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N

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If Cora draws a model of an atom with two protons, four neutrons and two electrons, it will look like this; a green cloud with 1 concentric white line that surrounds the center, with2 small green balls marked with minus signs. At the center of her model, she will draw 4 unmarked red balls interspersed with 2 blue balls marked with plus signs.

The options to your question seems clustered, but if separated, I'm sure this is what it would look like;

A.) at the center, 2 unmarked red balls are interspersed with 4 blue balls marked  with plus signs.

B.)a green cloud with 1 concentric white line surrounds the center, with 2 small green balls marked with minus signs on the white line. at the center, 4 unmarked red balls are interspersed with 2 blue balls marked with plus signs

C.)a green cloud with 1 white line surrounds the center, with 2 small green balls marked with minus signs on the white line. at the center, 2 unmarked red balls are interspersed with 2 blue balls marked with plus signs.

D.) a green cloud with 1 white line surrounds the center, with 4 small green balls marked with minus signs on the white line. at the center, 4 unmarked red balls are interspersed with 2 blue balls marked with plus signs.

E.)a green cloud with 1 white line surrounds the center, with 4 small green balls marked with minus signs on the white line.

When arranged like this, the answer to the question will be option B. The green cloud represents the nucleus of the model atom. The white line that surrounds the green cloud ( nucleus ) represents the orbit or shell. Therefore, the small green balls marked with minus signs are the electrons, as they are negatively charged and are found on the orbit/shell of an atom.

The unmarked red ball at the center of the model represents the neutron. Neutrons have no charge which is shown by the red balls not being marked by any sign.  The blue balls marked with a plus sign are the protons since they are positively charged.

The atom Cora wants to draw contains two protons, four neutrons and two electrons, therefore her model will contain 2 small green balls marked with minus sign as the electrons, 4 unmarked red balls as the neutrons and 2 blue balls with a plus sign as the protons. Hence the answer is option B.

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The ruler placement hypothesis can be summed up as follows:

The set of points on the line and the set of real numbers are equivalent in every way, and the absolute value of the difference between the matching numbers is equal to the distance between two points.

According to this, a set of points on a line can be matched with a set of real numbers, and vice versa. In order to help you better understand the ruler placement postulate, a general overview is provided based on the fact that your question is incomplete.

A ruler is a tool or measuring device that is used to measure length and draw straight lines. A measure is used to determine the length in both measured and conventional units.

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Answer:

C. 2 and 4

Explanation:

my teacher went over it and the answer was that

The sections of the track in which the sled would experience an unbalanced force are: C. Sections 2 and 4.

In Science, there are two (2) main types of force that acts on an object and these include:

An unbalanced force refers to a type of force that occurs when two (2) or more forces acting on an object are unequal in magnitude, and as such, it typically results in a change of motion.

In this scenario, the sections of the track in which the sled would experience an unbalanced force are sections 2 and 4 respectively.

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Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.

Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).

Part B :

We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :

The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)

The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore

\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)

The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).

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Answer:

neutron.

Explanation:

subatomic particles include,

neutron.

proton.

electron.

hope it helps. :)

The value of c is 0, indicating that the force function \(F = cx - (3.00 N/m^2)x^2\) is zero.

The given force function is\(F = cx - (3.00 N/m^2)x^2\). We need to find the value of c.  

To solve for c, we can use the work-energy principle. The work done by the force F is equal to the change in kinetic energy of the particle.

The work done by F is given by the integral of F dx over the limits of \(x = 0\)to \(x = 3\).

\(\int\ {cx - (3.00 N/m^2)x^2} \, dx = 11.0 J - 20.0 J\)

By integrating the force function, we get:

\((1/2)cx^2 - (1.00 N/m^2)(x^3/3)\)| from\(x = 0\) to\(x = 3\) = \(-9.0 J\)

Evaluating the integral, we have:

\((1/2)c(3)^2 - (1.00 N/m^2)((3)^3/3) - 0 = -9.0 J\)

\((9/2)c - 9 = -9.0 J\)

\((9/2)c = 0\)

\(c = 0\)

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Complete question is:

A force  F =(cx−(3.00 N/m 2)x ) i acts on a particle as the particle moves along an x axis, with F in newtons, x in meters, and c a constant. At x=0 m, the particle's kinetic energy is 20.0 J; at x=3.00 m, it is 11.0 J. Find c: Number Units

The signal that is needed to indicate that a radiation exposure has been made is dosimetry. Dosimetry is the measurement and calculation of the amount of radiation to which a person or an object has been exposed, hence the correct answer is  option C).

The signal that is needed to indicate that a radiation exposure has been made is dosimetry. Dosimetry is the measurement and calculation of the amount of radiation to which a person or an object has been exposed. Dosimeters are devices that are used to measure the radiation dose and provide a signal indicating the exposure level. Audible sound and visible light are not typically used to indicate radiation exposure because they do not provide accurate and quantitative information about the level of exposure. Density standard is also not a suitable signal because it is not related to radiation exposure. The atomic number of the material is not a signal that directly indicates radiation exposure. However, it is an important factor that affects the amount and type of radiation that a material can absorb or shield. The higher the atomic number of a material, the better it is at absorbing radiation. This is why lead, which has a high atomic number, is often used to shield against radiation. Therefore option C) is correct.

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A blackbody spectrum of temperature 900 Kelvin has been simulated. The peak wavelength in nanometers of an object of that temperature is determined to be nanometers. The intensity of the blackbody radiation at a given temperature and wavelength can be determined using Planck's law.

Planck's law, which describes the intensity of blackbody radiation, is given byI(λ) = 2hc²λ⁻⁵[exp(hc/λkT) - 1]⁻¹Where c = speed of light, h = Planck's constant, k = Boltzmann constant, T = temperatureλ = wavelength of lightI (λ) = spectral radiant intensity expressed in watts per square metre per unit wavelength.

Simulating the blackbody spectrum for a temperature of 900 K:

Using the equation for peak wavelength λ_max = 2897/T nm, where T = 900 KTherefore,λ_max = 2897/900λ_max = 3.22 µm or 3220 nm.

The emissive intensity of the object (the amount of power emitted per unit area) is given asI = σT⁴, where σ is the Stefan-Boltzmann constant.

Therefore,I = σT⁴ = 5.67 × 10⁻⁸ × (900)⁴W/m²= ×10 W/m².

Hence, the emissive intensity of the object is ×10 W/m².

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Answer:

we Are real, I don’t believe hell or heaven, we should take it seriously,

Explanation:

The answer is: Reflected

Explanation:

An image is a copy of an object that is formed by reflected (or refracted) light. Regular reflection occurs when light reflects off a very smooth surface and forms a clear image. Diffuse reflection occurs when light reflects off a rough surface and forms a blurry image or no image at all.

No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.

Gravitational force equation:

F = G * (m1 * m2) / r^2

Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.

So, F = G * (232 kg * 538 kg) / (0.342 m)^2

Plugging in the values, we get:

F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2

The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.

To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.

F = G * (232 kg * 60.6 kg) / (r)^2 = 0

r = √((232 kg * 60.6 kg) / (G))

r = √((232 * 60.6) / (6.672 * 10^-11))

r = 2.36*10^-5 m

At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.

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Testable hypotheses are the theoretical problems that operational definitions have converted into.

Scientific observation is an empirical research designed to systematically address issues about the world. Through the use of operational definitions, theoretical questions are converted into. a provable theory. The measurement process for measuring external, observable behaviour is specified in Operational Definitions. The measurements that are obtained are utilised to define and quantify the construct. A measurement process (a collection of operations) is specified in an operational definition for the purpose of measuring an external, observable behaviour, and the definition and measurement of the hypothetical construct are then based on the results of the measurement procedure. No matter how solid your conceptual definition may be, you cannot measure anything without an operational definition.

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Given,

The length is r=5.70 m

The tangential speed is r=9.10 m/s

The centripetal acceleration is:

The acceleration is:

With a mechanical advantage of 6.7 and an input force of 120 pounds, the inclined plane can move a weight of approximately 804 pounds.

The mechanical advantage of an inclined plane is calculated by dividing the length of the plane by its height. In this case, since the mechanical advantage is given as 6.7, it means that for every 6.7 units of length along the inclined plane, there is a unit of height.

To determine the weight that can be moved, we need to consider the relationship between the input force and the weight. The weight that can be moved is equal to the product of the input force and the mechanical advantage.

In this scenario, the input force is 120 pounds, and the mechanical advantage is 6.7. Multiplying these values together gives us approximately 804 pounds. Therefore, with an input force of 120 pounds, the inclined plane can move a weight of around 804 pounds.

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Answer:

it means the altitude of the object is 5m high or wide

Answer:

4 is correct

Explanation:

The more carbons in a hydrocarbon there are the higher the melting point will become.