What is the definition of an Isomer?

The units for atomic mass are atomic mass units (amu).  the atomic mass of copper for this location is 63.55 amu.

The chemical symbol Cu stands for copper. Copper is a soft, malleable, ductile metal that is a good conductor of heat and electricity. Copper is one of the most widely used metals in electrical and electronic equipment due to its superior conductivity and non-corrosive properties. This metal is widely used in wiring, roofing, plumbing, and electronic applications. Its atomic mass is 63.55 amu.The atomic mass of copper for this location can be determined using the following formula:

Atomic mass = (mass of isotope 1 x relative abundance of isotope 1) + (mass of isotope 2 x relative abundance of isotope 2)The atomic mass of copper for this location

= (62.93 x 0.6915) + (64.93 x 0.3085) = 63.55 amu

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Answer:

B. Trigonal planar

Explanation:

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From the forgoing, we can conclude that the the correct statements are;

The redox reaction is one in which one specie is oxidized and the other is reduced. We can obtain the equilibrium constant from the relation;

E°cell = 0.0592/n log K

E°cell = cell potential

n = number of electrons

K = equilibrium constant

E°cell = -0.403 - 0.535 = -0.938 V

n = 2 electrons

Thus;

-0.938 =  0.0592/2 logK

-0.938 * 2/ 0.0592 = log K

K = 2 * 10^-31

Also;

ΔG = - nFE°cell

ΔG = - (2 * 96500 *  -0.938)

ΔG = 181kJ/mol

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Answer:

A cuz a heterogeneous mixture is no uniform

Answer:

A heterogeneous mixture

Answer:

thermal energy.

Explanation:

Thermal energy is produced when the atoms and molecules in a substance vibrate faster due to a rise in temperature.

The amount of energy needed to heat 500 g of ice at  0⁰C to 60⁰C is 292,400 J. Option C.

In order to calculate the energy required to heat the ice, we need to consider two stages: first, we need to calculate the energy required to melt the ice, and second, we need to calculate the energy required to heat the resulting liquid water to 60°C.

To melt the ice, we need to supply energy equal to the heat of fusion of ice. The heat of fusion of ice is 334 J/g. Therefore, the energy required to melt 500 g of ice is:

Q1 = (334 J/g) x (500 g) = 167,000 J

Once the ice is melted, we need to heat the resulting liquid water to 60°C. The specific heat capacity of water is 4.184 J/(g°C). Therefore, the energy required to heat 500 g of water from 0°C to 60°C is:

Q2 = (4.184 J/(g°C)) x (500 g) x (60°C - 0°C) = 125,520 J

The total energy required to melt the ice and heat the resulting liquid water to 60°C is the sum of Q1 and Q2:

Q = Q1 + Q2 = 167,000 J + 125,520 J = 292,520 J

Thus, the amount of energy needed to heat 500 g of ice at  0⁰C to 60⁰C is 292,400 J.

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The mass of sodium chloride produced by the chemical reaction between sodium bicarbonate and hydrochloric acid is 8.37g.

The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl):

NaHCO₃ + HCl → NaCl + H₂O + CO₂

1 mole of sodium bicarbonate (NaHCO3) reacts with 1 mole of hydrochloric acid (HCl) to produce 1 mole of sodium chloride (NaCl), 1 mole of water (H₂O), and 1 mole of carbon dioxide (CO₂).

NaCl: Molar mass = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

The number of moles of sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) using their respective masses:

Number of moles of NaHCO₃ = Mass of NaHCO₃ / Molar mass of NaHCO₃

Number of moles of NaHCO₃ = 12 g / (22.99 g/mol + 1.01 g/mol + 48.00 g/mol + 16.00 g/mol)

Number of moles of NaHCO₃ = 12 g / 84.00 g/mol ≈ 0.143 moles

Number of moles of HCl = Mass of HCl / Molar mass of HCl

Number of moles of HCl = 5.58 g / (1.01 g/mol + 35.45 g/mol)

Number of moles of HCl = 5.58 g / 36.46 g/mol ≈ 0.153 moles

Since the reaction stoichiometry is 1:1 between NaHCO₃ and NaCl, the number of moles of NaCl produced will be the same as the number of moles of NaHCO₃ reacted. Therefore, the mass of NaCl produced can be calculated as follows:

Mass of NaCl produced = Number of moles of NaCl × Molar mass of NaCl

Mass of NaCl produced = 0.143 moles × 58.44 g/mol

The Mass of NaCl produced ≈ 8.37 g

Hence, the mass of sodium chloride produced is approximately 8.37 grams.

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Answer:

hope it helps..

Explanation:

'Motile' (or moving) cilia are found in the lungs, respiratory tract and middle ear. ... These cilia have a rhythmic waving or beating motion. They work, for instance, to keep the airways clear of mucus and dirt, allowing us to breathe easily and without irritation.

Answer: to keep airway clear of mucus and dirt allowing us to breathe easy

Explanation:

The density of a metal block that has a mass of 250.00 grams and the length is 16.25 cm, the width is 2.30 cm, and the height is 6.00 cm is 1.11.

Density can be defined as the measurement of how tightly a material is pecked together. It is defined as mass per unit volume.

Its SI unit is g/cm3 .

Density can be expressed as

Density = mass/ volume  

Volume of metal block = length x width x height

                                      = 16.25 x 2.30 x 6.00

                                      = 224.3  ml

Density = 250.0 / 224.3 g/ml

             = 1.11 g/ml

Thus, the density of a metal block that has a mass of 250.00 grams and the length is 16.25 cm, the width is 2.30 cm, and the height is 6.00 cm is 1.11.

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Answer:

\(m_{KAl(SO_4)_2\dot \ 12H_2O}^{actual}=32.23gKAl(SO_4)_2\dot \ 12H_2O\)

Explanation:

Hello,

In this case, we balance the given equations as shown below:

\(Al(s)+KOH(aq)+3H_2O(l)\rightarrow KAl(OH)_4(aq)+\frac{3}{2} H_2(g)\\\\KAl(OH)_4(aq)+2H_2SO_4(aq)\rightarrow KAl(SO_4)_2(aq)+4H_2O(l)\\\\KAl(SO_4)_2(aq)+12H_2O\rightarrow KAl(SO_4)_2\dot\ 12H_2O(aq)\)

Now, with 3.00 grams of aluminium, 50.00 mL of water and 10.00 mL of 8.00M potassium hydroxide, the first step is to identify the limiting reactant by firstly computing the moles of all of them:

\(n_{Al}=3.00 gAl*\frac{1molAl}{27gAl}=0.111molAl\\ \\n_{KOH}=0.010L*8.00mol/L=0.08molKOH\\\\n_{H_2O}=50.00mL*\frac{1g}{1mL} *\frac{1mol}{18g}=2.78molH_2O\)

Thus, we can notice that 0.111 mol of aluminium will consume 0.11. moles of potassium hydroxide and 2.78 moles of water will consume 0.927 moles of potassium hydroxide, for that reason, we can infer that since there are only 0.08 moles of potassium hydroxide, it is the limiting reactant, therefore, we compute the yielded moles of potassium aluminium hydroxide in the first reaction:

\(n_{KAl(OH)_4}=0.08molKOH*\frac{1molKAl(OH)_4}{1molKOH} =0.08molKAl(OH)_4\)

Next, we compute the yielded moles of potassium aluminium sulfate in the second reaction assuming sulfuric acid is in excess:

\(n_{KAl(SO_4)_2}=0.08molKAl(OH)_4*\frac{1molKAl(SO_4)_2}{1molKAl(OH)_4}=0.08molKAl(SO_4)_2\)

Finally, in the third reaction, we compute the yielded grams of potassium aluminum sulphate dodecahydrate by using its molar mass and its mole ratio with potassium aluminium sulfate:

\(m_{KAl(SO_4)_2\dot \ 12H_2O}=0.08molKAl(SO_4)_2*\frac{1molKAl(SO_4)_2\dot \ 12H_2O}{1molKAl(SO_4)_2} *\frac{474.00gKAl(SO_4)_2\dot \ 12H_2O}{1molKAl(SO_4)_2\dot \ 12H_2O} \\\\m_{KAl(SO_4)_2\dot \ 12H_2O}=37.92gKAl(SO_4)_2\dot \ 12H_2O\)

Which is the theoretical yield, thus, by using the percent yield the actual yielded mass turns out:

\(m_{KAl(SO_4)_2\dot \ 12H_2O}^{actual}=0.85*37.92gKAl(SO_4)_2\dot \ 12H_2O\\\\m_{KAl(SO_4)_2\dot \ 12H_2O}^{actual}=32.23gKAl(SO_4)_2\dot \ 12H_2O\)

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Answer:

1.811 g

Explanation:

The computation of the mass need to use to make the solution is shown below:

We know that molarity is

\(Molarity = \frac{Number\ of\ moles}{Volume\ in\ L}\)

So,

\(Number\ of\ moles = Molarity\ \times Volume\ in\ L\)

\(= 0.223\times 0.141\)

= 0.031 moles

Now

\(Mass = moles \times Molecualr\ weight\)

where,

The Molecular weight of NaCl is 58.44 g/mole

And, the moles are  0.031 moles

So, the mass of NaCL is

\(= 0.031 \times 58.44\)

= 1.811 g

We simply applied the above formulas

Considering the ideal gas law, the volume occupied by 3.25 moles of an ideal gas at a temperature of 18.00°C is 686.71 L.

An ideal gas is the behavior of those gases whose molecules do not interact with each other and move randomly. Under normal conditions and under standard conditions, most gases exhibit ideal gas behavior.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T), related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

In this case, you know:

Replacing in the ideal gas law:

1.13 atm×V = 3.25 mol× 0.8205 L.atm/K.mol× 291 K

Solving:

V = (3.25 mol× 0.8205 L.atm/K.mol× 291 K)÷ 1.13 atm

V= 686.71 L

Finally, the volume is 686.71 L.

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If heat is going into the system, then energy must have come out from the surroundings.

If heat is entering a system, it means that the system is gaining thermal energy, which can lead to an increase in temperature, changes in state, or other effects depending on the nature of the system and the heat transfer mechanism.

The first law of thermodynamics, also known as the law of conservation of energy, states that the total amount of energy in a closed system remains constant, and energy can neither be created nor destroyed, only transferred or converted from one form to another.

When heat enters a system, it is either used to increase the internal energy of the system or to perform work, such as moving a piston or driving an electrical generator.

The amount of heat transferred to a system can be quantified using the equation Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.

Therefore, if the system is gaining energy in the form of heat, then the surroundings (the rest of the universe) must be losing that same amount of energy. This is because energy is conserved.

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Answer:

\(m_{O_2}=120gO_2\)

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

\(2KClO_3\rightarrow 2KCl+3O_2\)

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

\(m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2\)

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Answer:

dont cheat guys

Answer:

A. 5.5 × 10⁻¹⁰ M, acidic

Explanation:

Step 1: Given data

Concentration of H₃O⁺: 1.8 10⁻⁵ M

Step 2: Calculate the concentration of OH⁻

We will use the ionic product of water.

Kw = 1.0 × 10⁻¹⁴ = [H₃O⁺] × [OH⁻]

[OH⁻] = 1.0 × 10⁻¹⁴/[H₃O⁺] = 1.0 × 10⁻¹⁴/1.8 10⁻⁵ = 5.5 × 10⁻¹⁰ M

Step 3: Determine if the solution is acidic, basic or neutral

Then, the solution is acidic.

Answer:

Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.

Explanation:

:)

Answer:

i think 2 figure ..............

Answer: 3

Explanation:

Answer:

Wavelength

Explanation:

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Matter can change state when thermal energy is absorbed into or out of the body.

Changing states of matter occur when matter loses or absorbs thermal energy. When a substance absorbs energy, the atoms and molecules move more fast which increases kinetic energy of the atoms that pushes particles far enough from each other which resulted in the change of form. This energy which changes the state of matter is the heat or thermal energy. We know that thermal energy increases kinetic energy so that's why the heat energy changes state of matter.

So we can conclude that Matter can change state when thermal energy is absorbed into or out of the body.

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Answer:

Filter it

Explanation:

Answer:

No of molcules(N)= 1.98×10^22

Explanation:

m=5.5, Mm= 167, NA= 6.02×10^23

Moles(n)= m/M= N/NA

5.5/167 = N/6.02×10^23

SIMPLIFY

N=1.98×10^22molecules

Explanation:

H

|

H-C=C-C-OH

| | |

H H H

in this organic compound the functional groups are OH and alkene

prop-2-enol

since it has a double bond, alkene is the functional group. and also it has OH group so hydroxyl group also the other functional group

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

Mitochondria is responsible for converting sugar(glucose)into ATP energy through cellular respiration in both plants and animal cells.

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this is true, wind energy is a renewable natural resource c:

Answer:

ball B

Explanation:

Ball B with a density of 0.9 g/cm³ will float in water.

Option B is the correct answer.

Density is mass per unit volume.

Its unit is given as g/cm³.

We have,

The density of Ball A.

= 22 g / 20 cm³

= 1.1 g/cm³

The density of Ball B.

= 18 g / 20 cm³

= 0.9 g/cm³

Now,

Since the density of water is 1.0 g/cm³,

The ball that will float is the one with a density of less than 1.0 g/cm³.

Therefore,

Ball B with a density of 0.9 g/cm³ will float in water.

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Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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