Answer:
d. 2-
when it forms an ion.
Explanation:
Which notation of a radioisotope is correctly paired with the notation of its emission particle?
1)³⁷Ca and ⁴₂He
2)²³⁵U and ⁰+₁e
3)¹⁶N and ¹₁P
4)³H and ⁰₋₁e
³⁷Ca and ⁴₂He is the notation of a radioisotope that is correctly paired with the notation of its emission particle.
Generally, radioisotope is defined as an unstable form of a chemical element that releases radiation as it breaks down and becomes more stable. Basically, radioisotopes may occur in nature or be made in a laboratory. Generally, in medicine, they are used in imaging tests and in treatment and it is also called radionuclide.
Generally, uranium is the best known example of a naturally-occurring radioisotope. All but 0.7 per cent of naturally-occurring uranium occurs as uranium-238 while the rest is the less stable, or more radioactive, uranium-235, which has three fewer neutrons in its nucleus.
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How did plastics become the material of choice for so many varied applications?
Answer:
people as: it Is less expensive. easy to carry
How many grams of BeF2 are present in 655 ml of a 0.442 m solution of Bef2
Answer:
13.6 g
Explanation:
The mass of BeF₂ present in 655 ml of a solution that is 0.442 M is equal to 13.82 g.
What is the molarity?We can calculate the concentration of a solute in a solution in terms of molarity, molality, and normality.
The molarity of a particular solution can be determined from the number of moles of a solute per unit volume of the solution.
The Molarity of the particular solution can be determined from the mathematical formula mentioned below:
Molarity = Moles/Volume of the Solution
Given, the molarity of BeF₂ solution = 0.442 M
The volume of the BeF₂ solution, V = 655 ml = 0.655 L
The molar mass of the BeF₂, M = 47.01 g/mol
Molarity of BeF₂ solution = m/(M × V)
0.442 = m/ (47.01 × 0.655)
m = 13.82 g
Therefore, 13.82 g of BeF₂ is required for the given solution.
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Trace amounts of rare elements are found within groundwater and are of interest to geochemists. Europium and terbium are lanthanide-series elements that can be measured from the intensity of their fluorescence emitted when a solution is illuminated with ultraviolet radiation. Certain organic compounds that bind Eu(III) and Tb(III) enhance the emission, and substances found in natural waters can decrease the emission. For that reason it is necessary to use standard additions to the sample to correct for such interference. The graph at the right shows the result of such an experiment in which the concentration of Eu(III) and Tb(III) was measured in a sample of groundwater.
In each case 10.00 mL of sample solution and 15.00 mL of of organic additive were placed in 50-mL volumetric flasks. Eu(III) standards (0, 5.00, 10.00, 15.00, and 20.00 mL) were added and the flasks were diluted to 50.0 mL with water.
The purpose of using standard additions in this experiment is to correct for interference and accurately measure the concentration of Eu(III) and Tb(III) in the groundwater sample. The interference can arise from organic compounds that enhance or substances that decrease the fluorescence emitted by these elements.
The procedure involves preparing a series of standard solutions with known concentrations of Eu(III). In this case, the Eu(III) standards are prepared by adding known volumes (0, 5.00, 10.00, 15.00, and 20.00 mL) of a standard Eu(III) solution to the 10.00 mL sample solution and 15.00 mL of the organic additive in the 50-mL volumetric flasks. The flasks are then diluted to the final volume of 50.0 mL with water.
By comparing the fluorescence intensity measurements obtained from the sample solution and the different standard additions, the interference effects can be determined. The change in fluorescence intensity with increasing standard addition volumes allows for the calculation of the concentration of Eu(III) in the groundwater sample.
The graph you mentioned likely shows the relationship between the fluorescence intensity and the volume of the Eu(III) standard added, providing information on the interference effects and enabling the determination of the concentration of Eu(III) in the groundwater.
In conclusion, the use of standard additions in this experiment helps correct for interference and accurately measure the concentration of Eu(III) and Tb(III) in the groundwater sample. By comparing the fluorescence intensity measurements between the sample and different standard additions, the interference effects can be accounted for, leading to an accurate determination of the concentration of these lanthanide-series elements.
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An atom contains 5 protons, 6 neutrons, and 6 electrons. What is the mass
number of this atom? *
Answer:
here you go
Explanation:
Atomic Number (Z) = Mass Number (A) - Number of Neutrons An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11
a solution of hydrochloric acid contains 1.5 moles of the solute in 2.0 liters of solution. calculate the molarity of this solution
Answer:
0.75 M
Explanation:
Molarity = moles of solute / liters of solution
so;
Molarity = \(\frac{1.5 Moles}{2.0 Liters}\)
According to molar concentration, the molarity of this solution is 0.75 molar.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substitution in formula gives, molarity= 1.5/2=0.75 M
Thus, the molarity of this solution is 0.75 molar.
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Helppppppppppppppppppppppppppppp
Answer:
বোকাচোদা মাণ্ডু খানকির ছেলে চোদাচুদি করে
What is S for silicon tetrachloride, SiCl4
S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon shares its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency
What is Covalency ?
The number of covalent bonds that a particular atom can make with other atoms in forming a molecule.
Covalent bond id formed by the sharing of electron between two atoms.
Hence, Silicon shares its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ . It is also known as covalency
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Indicate which compounds present i) in the reactants and ii) in the products from this lab experiment could be expected to give positive tests with a) permanganate and b) ceric ammonium nitrate. Reactants: "fresh aqueous aspartame" hydrolyzed aspartame "beverage A," which is a diet soft drink 24% aqueous methanol distilled water products: -the result of: 30 mL of aspartame stock solution, 10 drops of 6M NaOH in a flask and heated gently for 60 minutes on a steam bath -the result of: 10mL of diet soft drink with 10 drops of 95% ethanol
The hydrolyzed aspartame in the reactants and the result of the first product from the lab experiment are expected to give positive tests with both permanganate and ceric ammonium nitrate.
permanganate and ceric ammonium nitrate are both oxidizing agents that react with compounds containing functional groups such as aldehydes, ketones, and alcohols. Hydrolyzed aspartame contains an amide functional group that can be hydrolyzed to form an aldehyde and a carboxylic acid, both of which can react with permanganate and ceric ammonium nitrate. The result of the first product from the lab experiment also contains these functional groups due to the hydrolysis of aspartame. However, the other compounds in the reactants and products, such as methanol and ethanol, do not contain these functional groups and are not expected to give positive tests with permanganate and ceric ammonium nitrate.
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Draw dot and cross diagram to show formation of carbon dioxide
The dot and cross diagram is a way of representing a molecule along with its valence electrons and respective bonds. Valence electrons are drawn as a dot or a cross, each element will have a different connotation. Around the atoms, circles are drawn that indicate the bonds and how the electrons are shared.
Carbon has 4 valence electrons and oxygen has 6, the dot-and-cross diagram of CO2 will be:
Which is the best interpretation of the chart?
Lead has the highest specific heat of the four materials shown.
The energy transferred and type of material are inversely proportional to each other.
Different materials have different abilities to transfer energy.
Mass and type of material are proportional.
Answer:
i beg to say that i have an urgent piece of work at home
Explanation:
tano ni pta olo da kn
A sprinter set a high school record in track and field, running 200.0 m in 21.3 s. What is the average speed of the sprinter in kilometers per hour?
Answer:
33.8km/h
Explanation:
average speed=dostance traveled/time
200/21.3=9.39 m/s
1m/s=3.6km/h
33.8km/h
please give brainliest
what is a correct name of the following molecule? question 11 options: 4-chloro-1,2-dimethylcyclopentane cis-1-chloro-3,4-dimethylcyclopentane trans-1-chloro-3,4-dimethylcyclopentane cis-1-chloro-trans-3,4-dimethylcyclopentane two of the above are acceptable
The correct name of the molecule depends on the arrangement of the substituents on the cyclopentane ring.
If the chlorine atom and the two methyl groups are on the same side of the ring, the molecule is called cis-1-chloro-3,4-dimethylcyclopentane.
If the chlorine atom and the two methyl groups are on opposite sides of the ring, the molecule is called trans-1-chloro-3,4-dimethylcyclopentane.
Therefore, both "cis-1-chloro-3,4-dimethylcyclopentane" and "trans-1-chloro-3,4-dimethylcyclopentane" are correct names for the molecule, and two of the options provided in the question are acceptable.
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The half-life of C-14 is 5,730 years. How much of a 50.0-gram sample of C-14 will remain after 28,650 years?
Answer:
1.5625
Explanation:
the half life of an isotope is the amount of time it takes for one half of the isotope to decay
28650 is 5 half lives (28650÷5730=5)
after one half life the mass will be 25 grams
after two half lives the mass will be 12.5 grams
after 3 half lives the mass will be 6.25 grams
after 4 half lives the mass will be 3.125 grams
after 5 half lives the mass will be 1.5625 grams
as the temperature of a gas decreases is volume
Answer:
it's volume also decrease
Thinking and questioning is the start of the scientific inquiry process
Explanation:The scientific inquiry process is the process in which scientists or researchers find an explanation for any natural world phenomena with logic and evidence collected by the systemic method or work. The scientific inquiry process begins with a question or thinking (observation) for any natural phenomena like why freshwater has low albedo where ice has a high albedo percentage.
Potassium atoms contribute one eletron to metallic bonding,but calcium atoms contribute two eletrons .Explain which metal is likely to be harder
Answer:
potassium is likely to be harder
Explanation:
because whenan atom loss electron they can form particle ion acquare stable a arrangement that loos electron can transfer to another which that also to acquaire stable
which of the following are true for the cell below? select all that apply. zn(s)|zn2 (aq)||cu2 (aq)| cu(s) the electrons flow from copper to zinc. the electrons flow from zinc to copper. copper is the cathode and zinc is the anode. copper is the anode and zinc is the cathode. copper is reduced and zinc is oxidized. copper is oxidized and zinc is reduced.
The following statements are true for the cell below, which is Zn(s)|Zn2+ (aq)||Cu2+ (aq)|Cu(s):
1. The electrons flow from zinc to copper.
2. Copper is the cathode and zinc is the anode.
3. Copper is reduced and zinc is oxidized.
The anode is where oxidation occurs, while the cathode is where reduction occurs. When a metal is oxidized, it loses electrons and goes into the solution as an ion; when a metal ion gains electrons, it is reduced to the solid metal.
In the given cell, Zinc is oxidized, which means it gives away electrons and goes into the solution as Zn2+ ion. Cu2+ ion in the solution takes electrons from Zn and gets reduced to solid Cu.
Therefore, the electrons are flowing from zinc to copper. Zinc is anode and copper is cathode.Cu2+ + 2e- → Cu Zn → Zn2+ + 2e-
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1 an element x with electronic configuration 1s² 2s² 2p⁶ 3s² combines with another element Y with electronic configuration 1s² 2s² 2p⁶ 3s² 3o⁵
A in tabular form,show the formation of the compound formed between X and Y
B write the formation of the compound
2 draw the formation of the compound
A carbon (iv) oxide Co2
B methane
Answer:
Explanation:
A. Tabular form of the formation of the compound formed between X and Y (carbon and oxygen):
| Element | Electronic Configuration |
|---------|-------------------------|
| X | 1s² 2s² 2p⁶ 3s² |
| Y | 1s² 2s² 2p⁶ 3s² 3p⁵ |
B. Formation of the compound:
The compound formed between X and Y is carbon dioxide (CO2). Carbon (X) has an electronic configuration of 1s² 2s² 2p⁶ 3s², and oxygen (Y) has an electronic configuration of 1s² 2s² 2p⁶ 3s² 3p⁵.
Carbon has 4 valence electrons in its outermost energy level, while oxygen has 6 valence electrons in its outermost energy level. In order to achieve stability, carbon needs to gain 4 electrons, while oxygen needs to gain 2 electrons.
To form the compound CO2, carbon will share electrons with two oxygen atoms. Carbon will share 2 electrons with each oxygen atom, resulting in a double bond between carbon and each oxygen atom.
The formation of the compound can be represented as follows:
O = C = O
2. Drawing the formation of the compound:
In text format, the formation of the compound CO2 can be represented as:
O
//
C
\\
O
Here, the central carbon atom (C) is bonded to two oxygen atoms (O) through double bonds. The structure of carbon dioxide is linear, with the carbon atom in the center and the oxygen atoms on either side.
Has 3 valence electrons and 4 energy levels ?
You are looking for an element in the fourth period and a transition metal. As most have about 3 valence electrons. Gallium and Scandium work perfectly.
Answer:
Gallium is the Answer.
Explanation:
Balance the below equation:
____NH_3+ 〖____O〗_2 → ____NO+ ____H_2 O
How many grams of NO can be produced from 12 g of NH3 and 12 g of O2?
What is the limiting reactant? What is the excess reactant?
How much excess reactant remains when the reaction is over?
Answer:
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)
This is an oxidation-reduction (redox) reaction:
4 N-III - 20 e- → 4 NII
(oxidation)
10 O0 + 20 e- → 10 O-II
(reduction)
NH3 is a reducing agent, O2 is an oxidizing agent.
Explanation:
good luck
The regiochemistry of hydroboration/oxidation of alkenes is: (a) Markovnikov (b) non-Markovnikov (c) subject to solvent effects (d) unrelated to alkene structure (e) it is a not a regiospecific reaction.
The regiochemistry of hydroboration/oxidation of alkenes is (a) Markovnikov.
The hydroboration/oxidation reaction follows Markovnikov's rule, which states that the electrophile (in this case, the boron atom) adds to the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it. The regioselectivity of the reaction is determined by the relative stability of the carbocation intermediates formed during the reaction.
In hydroboration, the boron atom adds to the less substituted carbon atom of the double bond, leading to the formation of a boron-alkyl bond and a boron-hydrogen bond. Subsequently, in the oxidation step, the boron-alkyl bond is replaced with an alcohol group (-OH) while maintaining the regiochemistry established during hydroboration.
Therefore, the regiochemistry of hydroboration/oxidation of alkenes is Markovnikov, where the electrophilic addition occurs preferentially at the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it.
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Which of these are components of DNA?
Answer:
nucleotides
Explanation:
Hope this helps :D
Answer:
dna is made up of nucleotides!
Explanation:
hope this helped
combustion analysis of a hydrocarbon produced 33.01 g co2 and 5.42 g h2o.
In combustion analysis, the amounts of carbon dioxide (CO2) and water (H2O) produced from the combustion of a hydrocarbon can be used to determine the empirical formula of the hydrocarbon.
From the given information, we have produced 33.01 g of CO2 and 5.42 g of H2O.
To determine the empirical formula, we need to find the moles of carbon and hydrogen in the products. We can then use these moles to calculate the mole ratio of carbon to hydrogen and simplify it to the smallest whole number ratio.
First, let's find the moles of CO2 and H2O produced:
Moles of CO2 = mass / molar mass = 33.01 g / 44.01 g/mol (molar mass of CO2) = 0.750 mol
Moles of H2O = mass / molar mass = 5.42 g / 18.02 g/mol (molar mass of H2O) = 0.301 mol
Next, we need to determine the mole ratio of carbon to hydrogen. From the balanced combustion equation of a hydrocarbon, we know that one mole of carbon dioxide is produced for each mole of carbon in the hydrocarbon, and one mole of water is produced for each mole of hydrogen in the hydrocarbon.
Mole ratio of carbon to hydrogen = Moles of CO2 / Moles of H2O = 0.750 mol / 0.301 mol ≈ 2.49
Since we need to simplify the ratio to the smallest whole number ratio, we can round it to the nearest whole number. Thus, the empirical formula of the hydrocarbon is approximately C2H5.
It's important to note that this simplified empirical formula assumes the simplest ratio of carbon to hydrogen atoms in the hydrocarbon. However, without additional information, we cannot determine the exact molecular formula of the hydrocarbon. Additional analysis, such as the determination of the molar mass of the hydrocarbon, would be needed to determine its molecular formula.
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Homeostasis is the balance between your internal and external environments. We
learned three major factors that your body helps to regulate. Match each description
of body responses on the right to the types of regulation on the left.
Regulation of Body
Temperature
Regulation of Blood pH
Regulation of Blood glucose
———————————————
1. Sweat or shivering helps control
this
2. Breathing faster or slower help
adjust this
3. Eating or drinking help adjust this
Answer:
They are already matched for you. It goes
1.
2.
3.
in the order of the questions.
Write down your observations of what the pieces of cabbage in the images look like
what organ from a a jelly fish is like a human brain
Answer:
Below:
Explanation:
Instead of a single, centralized brain, jellyfish possess a net of nerves. This “ring” nervous system is where their neurons are concentrated—a processing station for sensory and motor activity. These neurons send chemical signals to their muscles to contract, allowing them to swim.
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It's Muska
Which of the following is a way that groundwater depletion affects streams? a. Lower water level b. Loss of vegetation c. Wildlife disruption d. All of the above.
The affect of ground water depletion is Lower water level, Loss of vegetation and Wildlife disruption.
What is ground water?The amount of water that is present below the upper surface area of the land, which are not easily accessible is known as ground water.
And this ground water keeps the soil hydrated and responsible for good vegetation by providing many minerals through water, wildlife is also depends on the ground water as they provide survival for many species. If the ground water is deplected then it also affects the flow of streams and lower water level.
Hence option (d) is correct i.e. All of the above.
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Answer
D. All of the above
Explanation
Which element is most similar to fluorine in the way it reacts with other elements?
Answer:
The answer is chlorine
Explanation:
Complete the following chart:
The atomic no., mass no., no. of protons, no of neutrons, and no of electrons respectively is as follows:
Uranium-235 = 92, 235, 92, 143, 92Calcium - 20, 48, 20, 28, 18Oxygen - 8, 17, 8, 9, 10What is atomic and mass number?Atomic number is the number of protons in an atom while the mass number is the total number of protons and neutrons in an atomic nucleus.
An atom is made up of three subatomic particles as follows; proton, electron and neutron.
The no of protons and electrons in an atom is usually the same for a neutral atom. However, for an ion, they differ depending on the charge.
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