What is the base unit of mass when using the metric system?

Answer:

26.5m/s²

Explanation:

Given parameters:

Tangential velocity of the object  = 23m/s

Radius of track = 20m

Unknown:

Acceleration = ?

Solution:

The acceleration of the body is its centripetal acceleration. It is given by;

  a  = \(\frac{v^{2} }{r}\)  

v is the tangential velocity

r is the

          a  = \(\frac{23^{2} }{20}\)   = 26.5m/s²

Veda would likely score very high on a personality test that measures extraversion. The answer is C)

The five-factor model of personality, also known as the Big Five personality traits, includes openness, conscientiousness, extraversion, agreeableness, and neuroticism.

Extraversion is one of the five dimensions that describes a person's level of social interaction and stimulation-seeking. Individuals who score high on extraversion tend to be outgoing, sociable, fun-loving, and affectionate, while those who score low tend to be reserved, introverted, and reflective.

Given Veda's personality traits of being sociable, fun-loving, and affectionate, it is likely that she would score high on a personality test that measures extraversion.

This would indicate that she enjoys being around others, seeks out new experiences and stimulation, and is energized by social interactions. In contrast, if Veda were more reserved and reflective, she would likely score lower on extraversion and may instead score higher on other dimensions such as openness or conscientiousness, depending on her other traits.

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Answer:

The answer is B.

Explanation:

A Block has a density of 0.97 g/cm 3. That is why 97 percent of the ice will sink in below the water.

To find the output voltage v0(t) across the load, we need to determine the current flowing through the load. First, let's find the total impedance of the parallel combination of RL and CL.

The impedance of a resistor is equal to its resistance, so the impedance of RL is also 2Ω. The impedance of a capacitor is given by ZC = 1/(jωC), where j is the imaginary unit and ω is the angular frequency. In this case, since the voltage source has a time-domain expression, we can consider ω = 1 rad/s.

Thus, the impedance of

\(CL is ZC = 1/(j * 1 * 0.25) = -4jΩ.\)

To find the total impedance, we can use the formula for parallel impedance:

\(1/Ztotal = 1/ZL + 1/ZC\)

Substituting the values, we get:

\(1/Ztotal = 1/2 + 1/(-4j) = 1/2 - j/4\)

Taking the reciprocal, we get:

\(Ztotal = 2/(1 - j/2)\)

To find the current flowing through the load, we can use Ohm's Law: I = V/Z, where V is the source voltage and Z is the total impedance.

Since the source voltage is

vS(t) = 4e^(-t)u(t),

we can find the current:

\(I(t) = vS(t)/Ztotal = (4e^(-t)u(t))/(2/(1 - j/2))\)

Now that we have the current, we can find the output voltage v0(t) across the load. The output voltage is given by Ohm's Law:

\(v0(t) = I(t) * RL.\)

Substituting the values:

\(v0(t) = [(4e^(-t)u(t))(1 - j/2)/2] * 2\)

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The output voltage across the load is given by v_0(t) = 10e^(-t)u(t). Given the voltage source v_s(t) = 4e^(-t)u(t) with a series source impedance R_s = 1Ω connected to a load of R_L = 2Ω in parallel with C_L = 0.25F, we can find the output voltage v_0(t) across the load.

To solve this problem, we can use the voltage division rule. First, let's calculate the total impedance of the load, which consists of R_L and C_L in parallel.

The impedance of a capacitor is given by

    Z_C = 1/(jωC)

    where

    j is the imaginary unit and

    ω is the angular frequency.

In this case, ω = 1 rad/s.

    Z_C = 1/(j * 1 * 0.25) = -4jΩ

Next, we can calculate the total impedance Z_total by summing the source impedance and the load impedance in parallel.

    Z_total = R_s || Z_L = (R_s * Z_L) / (R_s + Z_L)

=> Z_total = (1 * -4jΩ) / (1 + -4jΩ) = -4j/5Ω

Finally, we can use the voltage division rule to find the output voltage v_0(t) across the load.

    v_0(t) = v_s(t) * (Z_L / Z_total)

=> v_0(t) = 4e^(-t)u(t) * (Z_L / Z_total)

=> v_0(t) = 4e^(-t)u(t) * (2Ω / -4j/5Ω)

Simplifying the expression, we get:

    v_0(t) = 10e^(-t)u(t)

Therefore, the output voltage across the load is v_0(t) = 10e^(-t)u(t).

In conclusion, the output voltage across the load is given by v_0(t) = 10e^(-t)u(t).

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Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

Answer:

Longitudinal (sound waves, heat transmission, etc.) require a medium for transmission,    air, insulation, etc.

Transverse waves - light, radio, etc can travel thru a vacuum

Question:

What is a disadvantage of using nuclear power to produce electricity?

Answer:

Disadvantages of Nuclear Power

The further implementations of nuclear power are limited because although nuclear energy does not produce CO2 the way fossil fuels do, there is still a toxic byproduct produced from uranium-fueled nuclear cycles: radioactive fission waste.

Answer:

Disadvantages of nuclear energy include the high cost of building a power plant and safety concerns about the operation of the plant and disposal of spent fuel rods.

Explanation:

Hope this helps.

the answer is c i think

Answer:

C. Planets in motion will have a constant speed unless acted on by an outside force.

Explanation:

Took the test

We would apply the relativistic kinetic energy formula which is expressed as

KE = (y - 1)mc^2 = [1/√(1 - v^2/c^2 - 1]mc^2

where

m is the mass of proton

c is the speed of light

v is the speed of the proton

From the information given,

m = 1.67 x 10^-27 kg

c = 3 x 10^8 m/s

v = 0.54c

Thus,

KE = 1.67 x 10^-27 x (3 x 10^8)^2[1/√(1 - (0.54c/c)^2 - 1]

KE = 28.27 x 10^-12 J

We would convert from joules to mev

1 J = 6,241,509,343,260 MeV

28.27 x 10^-12 = 28.27 x 10^-12 x 6,241,509,343,260

KE = 176.48 Mev

the translational kinetic energy is 176.48 Mev

a. This results in an imaginary number, indicating that the car never reaches its maximum speed during the journey. Instead, it slows down uniformly and comes to rest again at x = 900 m.

b. The acceleration is positive for the first 16.78 s and then becomes negative. It is zero at two points: at t = 0 s and t = 33.56 s.

a. Calculation of the time it takes for the car to move through 900 meters:

We know the acceleration of the car is +2.25 m/s², and the distance it covers is 4/9 of the total distance. Here, initial velocity, u = 0, acceleration, a = 2.25 m/s², and distance, s = 4/9 × 900 = 400 m.

Using the equation s = ut + 1/2 at², we can calculate the time (t):

400 = 0 + 1/2 (2.25) t²

This simplifies to:

800/2.25 = t²

t = √(800/2.25) = 16.78 s

Now, for the remaining distance of 5/9 × 900 = 500 m, the acceleration is -0.75 m/s². Since the car is now at rest, the initial velocity (u) is unknown.

Using the equation v² - u² = 2as and v = u + at, we can calculate the final velocity (v) at x = 900 m:

v = √(u² + 2as)

Plugging in the values, we get:

v = √(0 + 2(-0.75)(500)) = √(-750)

b. Graph of position x, velocity v, and acceleration a versus time t:

In the graph below, the blue line represents the position x, the red line represents the velocity v, and the green line represents the acceleration a.

The graph shows that the velocity starts from 0 and reaches a maximum value after 16.78 s. After that, it starts to decrease uniformly to 0 again when the car comes to rest at x = 900 m.

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Answer:

1080 meters

Explanation:

60sec in 1 minute

So, 3x60=180

So, 6x180=1080 meters

Answer:

A) 250 J

B) 150 J

C) The efficiency = 0.6 and the percentage efficiency = 60%

Explanation:

The question relates to definition of terms in energy transfer and the calculation of efficiency

The parameters of the given are;

The energy the object transfers = 150 J

The amount of electrical energy supplied to the motor = 250 J

Therefore, we have;

A) The total energy supplied to the motor = The amount of electrical energy supplied to the motor = 250 J

B) The useful energy transferred = The energy used to do work = 150 J

C) The efficiency = (Useful energy transferred (out))/(Total energy supplied (in)

\(The \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} = \dfrac{150 \, J}{250 \, J} = 0.6\)

The percentage efficiency is given as follows;

\(The \ percentage \ efficiency = \dfrac{Useful \ energy \ transferred \ (out)}{Total \ energy supplied \ (in)} \times 100\)

\(\therefore The \ percentage \ efficiency = \dfrac{150 \, J}{250 \, J} \times 100 = 0.6 \times 100 = 60\%\)

Answer:

A) 250 J

B) 150 J

C) efficiency = 0.6, percentage efficiency = 60%

Explanation:

The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.

To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.

First, let's calculate the resonant frequency (ω) of the circuit:

ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.

The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.

Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.

Now, let's find the impedance (Z) of the circuit:

Z = √(R^2 + (Xl - Xc)^2),

where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.

R = 20 Ω

Xl = ωL = 1 * 10 = 10 Ω

Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω

Plugging in these values, we get:

Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.

The amplitude of the current (I) can be calculated using Ohm's Law:

I = E / Z = 200 / 22.36 ≈ 8.94 A.

The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:

tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.

Therefore, Φ ≈ -0.464 rad.

The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.

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The final velocity of the block and the bullet after the collision is 12.43 m/s.

First, we need to determine the initial velocity of the bullet. We can use the conservation of momentum principle, which states that the total momentum of a system remains constant if no external forces act on it. Thus, we have:

m_bullet x v_bullet = (m_bullet + m_block) x v_final

where m_bullet is the mass of the bullet, v_bullet is its initial velocity, m_block is the mass of the wooden block, and v_final is the final velocity of the block and the bullet after the collision. Since the bullet remains embedded in the block, we can assume that their final velocities are the same.

Substituting the given values, we get:

7.00 g x v_bullet = (7.00 g + 1.20 kg) x v_final

Simplifying, we get:

v_bullet = v_final x (1.20 kg / 7.00 g + 1.20 kg)

v_bullet = v_final x 0.994

Next, we need to find the frictional force acting on the block. We can use the formula:

f_friction = friction coefficient x normal force

where f_friction is the frictional force, friction coefficient is the coefficient of kinetic friction between the block and the surface, and normal force is the force exerted by the surface perpendicular to the block's surface. Since the block is resting on a horizontal surface, the normal force is equal to its weight, which is:

m_block x g = 1.20 kg x 9.81 m/s² = 11.772 N

Substituting the given friction coefficient, we get:

f_friction = 0.20 x 11.772 N = 2.354 N

The frictional force acts in the opposite direction to the block's motion, so we can use it to find the work done by friction, which is:

W_friction = f_friction x d

where W_friction is the work done by friction, and d is the distance the block slides along the surface. Substituting the given values, we get:

W_friction = 2.354 N x 0.390 m = 0.917 J

Finally, we can use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy. In this case, the initial kinetic energy of the bullet is equal to zero, and the final kinetic energy of the block and the bullet is also zero, since they come to a stop. Thus, the net work done on the system is:

W_net = W_friction

Substituting the previously calculated value of W_friction, we get:

W_net = 0.917 J

This work is equal to the initial kinetic energy of the bullet, which is:

K_initial = (1/2) x m_bullet x v_bullet²

K_initial = (1/2) x 7.00 g x (v_final x 0.994)²

K_initial = 2.435 x 10⁻³ J x v_final²

Equating this to the net work done, we get:

2.435 x 10⁻³  J x v_final² = 0.917 J

v_final = 12.43 m/s

Therefore, the final velocity of the block and the bullet after the collision is 12.43 m/s.

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Answer:

The magnitude of the net electric field is:

\(E_{net}=90.37\: N/c\)

Explanation:

The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).

On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).

Knowing this, the magnitude of the net electric field will be the E1 + E2.

Let's find first E1 and E2.

The electric field equation is given by:

\(|E_{1}|=k\frac{|q_{1}|}{d_{1}^{2}}\)

Where:

\(|E_{1}|=(9*10^{9})\frac{|-2.60*10^{-9}|}{0.538^{2}}\)

\(|E_{1}|=80.84\: N/C\)

And E2 will be:

\(|E_{2}|=k\frac{|q_{2}|}{d_{2}{2}}\)

\(|E_{2}|=(9*10^{9})\frac{|-8.30*10^{-9}|}{1.36^{2}}\)

\(|E_{2}|=40.39\: N/C\)

Finally, we need to use the  Pythagoras theorem to find the magnitude of the net electric field.

\(E_{net}=\sqrt{E_{1}^{2}+E_{2}^{2}}\)

\(E_{net}=\sqrt{80.84^{2}+40.39^{2}}\)

\(E_{net}=90.37\: N/c\)

I hope it helps you!

Answer:

+90.3 N/C

Explanation:

acellus

Answer:

I think it's D

Explanation:

I don't know I just think

The free-body-diagram of the rod showing all the forces acting.

To find the expression for the angular acceleration of the rod, use the moment of inertia of the rod about point G is given byI = mk² + md²where k is the radius of gyration, d is the distance from G to P, m is the mass of the rod.The rod is acted on by a force F at point P which is displaced from the center of mass of the rod by a distance d.

The net torque acting on the rod is given byτ = F × dWhere F is the force acting on the rod, d is the distance between the center of mass of the rod and the point of application of the force.

The moment of inertia of the rod about point G and the net torque acting on the rod gives the angular acceleration of the rod asα = τ / Iα = (F × d) / (mk² + md²)The angular acceleration of the rod is given in terms of the a3 unit vector asα = (F × d a3) / (mk² + md²)(c) Let the acceleration of point P be a.

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A 1987 205 cubic inch V6 Mercruiser 4.3 engine with 575 hours on it does not necessarily have too many hours with potential breakdowns in the near future, as long as it has been well-maintained and shows no major signs of wear and tear.

The number of hours on an engine is just one factor to consider when determining the potential for breakdowns. Other factors such as maintenance history, usage conditions, and overall condition of the engine can also play a role.

With that being said, 575 hours on a 1987 4.3 Mercruiser engine is not necessarily an alarming number, as these engines are known for their durability and longevity. However, it is important to have the engine inspected and properly maintained to ensure it continues to run smoothly. Regular maintenance and inspections can help prevent potential breakdowns and extend the life of the engine.

1. Assess the average lifespan of a Mercruiser 4.3 engine. Generally, these engines can last anywhere from 1,500 to 2,000 hours with proper maintenance.

2. Evaluate the maintenance history of the engine. Regular maintenance, such as oil changes, spark plug replacements, and cooling system checks, can significantly prolong the engine's lifespan.

3. Inspect the engine for signs of wear and tear. Check for corrosion, oil leaks, or any other visible issues that may indicate potential breakdowns.

Considering these factors, a 1987 205 cubic inch V6 Mercruiser 4.3 engine with 575 hours on it does not necessarily have too many hours with potential breakdowns in the near future, as long as it has been well-maintained and shows no major signs of wear and tear.

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Answer:

Correct Answer: Option B

Explanation:

Explanation

P1/T1 = P2/T2

80/(273+47) = P1/(273+27) = 75Nm-2

Answer: 75.0 Nm^-2

Explanation:

P1/T1 = P2/T2 80/(273+47) = P1/(273+27) = 75Nm-2

a) If S is a subspace of vector space V, then the span of S, (S), is equal to S itself.

To show that if S⊆V, then (S) = S, we need to prove two inclusions:(i) (S) ⊆ S:
By definition, (S) is the smallest subspace of V that contains S. Since S⊆(S), it follows that every element in S is also in (S). Therefore, S is a subset of (S).(ii) S ⊆ (S):
Let's consider S as a subspace of V. Since S is already a subspace, it satisfies all the properties of a vector space, including closure under scalar multiplication and addition. Therefore, S is a subset of itself.
Combining both inclusions, we conclude that (S) = S.

b)The span of the union of subspaces W₁ and W₂, (W₁ ∪ W₂), is equal to the sum of W₁ and W₂, denoted by W₁ + W₂.

To show that (W₁ ∪ W₂) = W₁ + W₂, we need to prove two inclusions:
(i) (W₁ ∪ W₂) ⊆ W₁ + W₂:
Let's take an element x from (W₁ ∪ W₂). This means that x is an element of either W₁ or W₂ (or both). If x∈W₁, then x is in the subspace W₁, and therefore, it is also in the sum W₁ + W₂. Similarly, if x∈W₂, then x is in the subspace W₂, and hence it is also in the sum W₁ + W₂. Therefore, any element x from (W₁ ∪ W₂) is also in W₁ + W₂, which implies (W₁ ∪ W₂) ⊆ W₁ + W₂.
(ii) W₁ + W₂ ⊆ (W₁ ∪ W₂):
Let's take an element y from W₁ + W₂. By definition, this means that y can be expressed as the sum of an element in W₁ and an element in W₂. Therefore, y is either an element of W₁ or an element of W₂ (or both), and hence y is in the union (W₁ ∪ W₂). Therefore, any element y from W₁ + W₂ is also in (W₁ ∪ W₂), which implies W₁ + W₂ ⊆ (W₁ ∪ W₂).Combining both inclusions, we conclude that (W₁ ∪ W₂) = W₁ + W₂.

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The initial velocity of the car as it slow to rest with an acceleration of -5 m/s² is 11.5 m/s.

This can be defined as the ratio of displacement to the time of a body

To calculate the initial velocity of the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the initial velocity of the car is 11.5 m/s

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Answer:

it's C

Explanation:

have a nice day............

Answer:

= 1440 kg·m/s

Explanation:

Step by Step Solution to find Momentum of Mass = 288 kg & Velocity = 5 m/s:

Given that,

mass (m) = 288 kg

velocity (v) = 5 m/s

Substitute the value into the formula

p = 288 x 5

p = 1440 kg·m/s

∴ Momentum (p) =1440 kg·m/s

The system will undergo simple harmonic motion in the case where the restoring force is directly proportional to the displacement (option b).

In simple harmonic motion, the restoring force acting on the system is directly proportional to the displacement from the equilibrium position. This relationship is given by Hooke's Law: F = -kx, where F is the restoring force, x is the displacement, and k is the spring constant.

Option a (F directly proportional to x²) does not correspond to simple harmonic motion because the force is proportional to the square of the displacement, which does not follow Hooke's Law.

Option c (F directly proportional to \(\frac{1}{x}\)) does not correspond to simple harmonic motion either because the force is inversely proportional to the displacement, which is not consistent with Hooke's Law.

Option d (F directly proportional to sin x) does not represent a linear relationship between the force and displacement. Simple harmonic motion requires a linear relationship, not a trigonometric one.

Therefore, only option b (F directly proportional to x) satisfies the conditions for the system to undergo simple harmonic motion.

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Answer:

5.2 s

Explanation:

From the question given above, the following data were obtained:

Velocity = 7.5 m/s

Displacement = 39 m up

Time =?

The time taken for the cable cab to get to 39 m can be obtained as follow:

Velocity = Displacement / Time

7.5 = 39 / time

Cross multiply

7.5 × time = 39

Divide both side by 7.5

Time = 39 / 7.5

Time = 5.2 s

Thus, the time taken for the cable cab to get to 39 m up is 5.2 s

If the surface temperature of the sun were to drop by a factor of 2.0, the power impinging on the earth would decrease by a factor of 8 times.

The quantity of energy transferred or transformed per unit of time is known as power. It is a mechanically accepted quantity. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power. Power is related to other factors; for instance, the power required to move a ground vehicle is equal to the product of the vehicle's velocity, traction force on its wheels, and aerodynamic drag. A motor's output power is calculated by multiplying its torque output by the angular velocity of its output shaft. Energy divided by time represents the dimension of power. The watt (W), which equates to one joule per second, is the unit of power in the International System of Units (SI). Another popular unit of measurement is horsepower (hp), which is equivalent to a horse's power; one mechanical horsepower is equal to around 745.7 watts. Ergs per second (erg/s), foot-pounds per minute (fpm), dBm (a logarithmic measurement in relation to 1 milliwatt), calories per hour (cal/h), BTU per hour (BTU/h), and tons of refrigeration are other units of power.

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