what is the area of frustum?

The distance from the point (2, 1) is double it's distance from (1, 2)​ is 2.8

The distance between two points in a 2D Cartesian coordinate system is the length of the path connecting them. The shortest path distance is a straight line. The Pythagorean theorem states that the distance between points (X1, Y1) and (X2, Y2) is given by the formula [(x2 x1)2 + (y2 y1)2], where (x1, y1) and (x2, y2) are two points on the coordinate plane.

Distance = √(y₁-y₂)² + (x₁-x₂)²

distance = √(2-1)² + (1-2)²

the distance = √1+1

The distance = √2 = 1.4 = 2*1.4 = 2.8

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Answer:

7

Step-by-step explanation:

Rounding rules. Anything below 5 will round down

Answer:

Step-by-step explanation:

(a) Let x represent the length of the first side. Then the second side is (x+4) and the third side is (x+3). The perimeter is ...

  x + (x+4) +(x+3) = 15

  3x = 8 . . . . collect terms, subtract 7

  x = 2 2/3 . . . . divide by 3

The third side is x+3 = 5 2/3 inches.

__

(b) For this, we are told the second side is S, so we have ...

  S = (x+4)

  x = S -4 . . . . . subtract 4 to solve for x

Using this in our expression (in part (a)) for the third side, we have ...

  third side = (x +3) = (S -4) +3

  third side = S -1

To determine the sample size needed to estimate the proportion of crimes in which firearms are used within a certain margin of error and confidence level, we can use the following formula:

n = (\(Z^2\) * p * (1 - p)) / \(E^2\)

where:

n is the sample size

Z is the Z-score associated with the desired level of confidence (1.645 for 90% confidence)

p is the estimated proportion of successes in the population (we don't have an estimate, so we'll use 0.5, which gives the maximum sample size)

E is the desired margin of error

Substituting these values into the formula, we get:

n = (\(1.645^2\) * 0.5 * (1 - 0.5)) / 0.0\(2^2\)

n = 601.41

Rounding up to the nearest integer, we get a sample size of 602. Therefore, the U.S. Crime Commission should sample at least 602 crimes to estimate the proportion of crimes in which firearms are used within 0.02 with 90% confidence.

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Answer:

answer=-7*-7-8*-7-20

=49+56-20=85

out of -7+2=-5

=85out of -5

=-7

Answer:

Order of Operations

Step-by-step explanation:

Answer: lagairthims

Step-by-step explanation: odessey

we have to add 7775000 to make 7800000 from 25000 which is calculated by using Substraction method.

Subtraction in mathematics is the process of subtracting one integer from another. In other terms, the result of subtracting two from five is three. After addition, subtraction is usually the second process you learn in math class.Subtraction is the action or procedure of determining the difference between two quantities or figures. The phrase "taking away one number from another" is also used to describe the process of subtracting one number from another.

Distance to be covered altogether= 7800000 m
THE distance has covered= 25000 m.

We can calculate the thousands needs to be added in 25000 to make it 7800000 by using Substraction method:-

7800000-25000= 7775000m

hence, to make 7800000 from 25000 we have to add 7775000.

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Answer:

6x - 18

Step-by-step explanation:

3 x 6 = 18, so thats how you get the 18 in the answer

3 x 2x = 6x, which is how you get the 6x

and theres  a subraction sign so we know to put a - there.

Answer:

6x - 18

Step-by-step explanation:

3(2x - 6) =

("... - 6" means that whatever we do with the 6, we have to remember that it's negative)

3(2x - 6) =

3 * 2x + 3 * (-6) =

6x + (-18) =

(if we add a negative number then it's the same as subtracting that number)

6x + (-18) = 6x - 18

-------------------------------------------------

Hope i didn't make it to complicated to understand, glad to help :D

P.S. Dont be afraid to ask me a question if you didn't uderstand.

Answer:

Well 51 per hour and there is 24 hours so you just multiply the two together. Which you would get get 1,224 Miles

There are a total of $15^5 = 759,375$ distinct possibilities for the values in the diagonal going from top left to the bottom right of a BINGO card, in order.

To find the number of distinct possibilities for the values in the diagonal going from top left to the bottom right of a BINGO card, we need to consider the range of numbers that can be placed in the diagonal.

In the given BINGO card, the diagonal starts with the number 5 in the top left corner and ends with the number 71 in the bottom right corner. We can see that the numbers in the diagonal follow a pattern:

5, 17, 32, 49, 71

We can analyze this pattern to find the number of distinct possibilities.

- The first number, 5, can be any number from the set $1-15$.
- The second number, 17, can be any number from the set $16-30$.
- The third number, 32, can be any number from the set $31-45$.
- The fourth number, 49, can be any number from the set $46-60$.
- The fifth number, 71, can be any number from the set $61-75$.

To find the number of distinct possibilities, we multiply the number of choices for each position:

15 choices for the first number × 15 choices for the second number × 15 choices for the third number × 15 choices for the fourth number × 15 choices for the fifth number

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Answer:

1. Transitive

2. Reflexive

3. Symmetric

4. Reflexive

5. Symmetric

6. Transitive

Answer:the photo is for part A.

B) the weight would be Invnorm(.25,77,6)=72.95

C)the weight would be 81.04 but this is the work invnorm(.75,77,6)=81.04

D)IQR=Q3-Q1

81.04-72.95=8.09

E)9.12 is the answer the work normalcdf(85,1000,77,6)=.0912

F).6892 or 68.92% are the answers the work normalcdf(60,80,77,6)=.6892

G).0227 or 2.27% is the answer and the work normalcdf(0,65,77,6)=.0227

Step-by-step explanation:

Using the normal distribution, we have that:

----------------------

Problems of normal distribution can be solved using the z-score formula.

In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

----------------------

----------------------

Item b:

\(Z = \frac{X - \mu}{\sigma}\)

\(-0.675 = \frac{X - 77}{6}\)

\(X - 77 = -0.675(6)\)

\(X = 72.95\)

A weight of 72.95 pounds would represent the 25th percentile.

----------------------

Item c:

\(Z = \frac{X - \mu}{\sigma}\)

\(0.675 = \frac{X - 77}{6}\)

\(X - 77 = 0.675(6)\)

\(X = 81.05\)

A weight of 81.05 pounds would represent the 75th percentile.

----------------------

Item d:

The interquartile range is the difference between the 75th and the 25 percentile, thus:

\(81.05 - 72.95 = 8.1\)

The interquartile range is of 8.1 pounds.

----------------------

Item e:

The proportion is 1 subtracted by the p-value of Z when X = 85, thus:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{85 - 77}{6}\)

\(Z = 1.33\)

\(Z = 1.33\) has a p-value of 0.9082.

1 - 0.9082 = 0.0918.

0.0918 = 9.18% of male adult Labrador retrievers weigh above 85 pounds.

----------------------

Item f:

The proportion is the p-value of Z when X = 80 subtracted by the p-value of Z when X = 60, thus:

X = 80:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{80 - 77}{6}\)

\(Z = 0.5\)

\(Z = 0.5\) has a p-value of 0.6915.

X = 60:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{60 - 77}{6}\)

\(Z = -2.83\)

\(Z = -2.83\) has a p-value of 0.0023.

0.6915 - 0.0023 = 0.6892.

0.6892 = 68.92% of male adult Labrador retrievers weigh between 60 and 80 pounds.

----------------------

Item g:

This proportion is the p-value of Z when X = 65, thus:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{65 - 77}{6}\)

\(Z = -2\)

\(Z = -2\) has a p-value of 0.0228.

0.0228 = 2.28% of male adult Labrador retrievers weigh less than 65 pounds.

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The story of the raccoon and the piggy bank is a fascinating one. A raccoon was trained to place one coin in a piggy bank, but when the trainer attempted to teach the raccoon to place two coins in the bank, the raccoon rubbed the coins together for several minutes and refused to let them go. This event is an example of an animal's ability to understand the concept of quantity.

The raccoon's reaction can be attributed to the fact that it was unable to comprehend the notion of more than one item. It is a popular misconception that animals lack the ability to grasp concepts like quantity, but recent research has revealed that they are capable of comprehending these ideas to a certain extent.

This is important because it suggests that animals may have more intelligence than previously believed and may be able to perform more sophisticated tasks than previously assumed.

This research has significant implications for the treatment of animals, particularly in cases where they are used for experimentation or entertainment. By acknowledging that animals have a greater capacity for learning than previously believed, it becomes clear that they are deserving of more respect and consideration.

Additionally, the recognition of their cognitive abilities may lead to the development of more humane methods of training and treating animals, which would be a significant advancement in the field of animal welfare.

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We are given a function y = -4x^3 - 9x^11, and we need to find its first and second derivatives.

To find the first derivative, we apply the power rule and the constant multiple rule. The power rule states that the derivative of x^n is nx^(n-1), and the constant multiple rule states that the derivative of kf(x) is k*f'(x), where k is a constant. Applying these rules, we can find the first derivative of y = -4x^3 - 9x^11.

Taking the derivative term by term, the first derivative of -4x^3 is -43x^(3-1) = -12x^2, and the first derivative of -9x^11 is -911x^(11-1) = -99x^10. So, the first derivative of y is dy/dx = -12x^2 - 99x^10.

To find the second derivative, we apply the same rules to the first derivative. Taking the derivative of -12x^2, we get -122x^(2-1) = -24x, and the derivative of -99x^10 is -9910x^(10-1) = -990x^9. Therefore, the second derivative of y is d^2y/dx^2 = -24x - 990x^9.

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The level of measurement is required of the independent variable (iv) and dependent variable (dv) to conduct a chi-square analysis is "the chi-squared test for independence."

A chi-square (X²) statistic is a test which compares a model to real observed data. A chi-square statistic requires data that is random, raw, mutually exclusive, obtained from independent variables, & drawn from a large enough sample. Tossing a fair coin, for example, meets these criteria.

Some key features regarding chi-square test are-

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In  sequence ,

(1) (B) y = x and

(2) (D) Rotation 90° counter-clockwise, then translation 4 units left.

What do "sequence" and "example" mean?

An ordered list of numbers is referred to as a sequence. To go forward in the defined pattern, three dots are shown. A phrase is used to refer to each number in the series.

                               One is the first word, three is the second, five is the third, and so on, in the series 1, 3, 5, 7, 9,...

Since we are given that ΔA'B'C' is formed after a sequence of transformations applied to ΔABC.

The first is a reflection across a line and second is a translation.

The co-ordinates of point C are (-4, -2). After reflection from the line y = x, the co-ordinates becomes  (2, -4).

Also, the coordinates of point C' are (12, 0).

So, to reach point C' from point C, we should add 10 units to the x-coordinate and 4 units to the y-coordinate.

That is, the translation of 10 units right and 4 units up.

Thus, the complete transformation is

The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the line y = x followed by a translation 10 units right and 4 units up.

Thus, the correct answer is (1) y = x and (2) 10 units to the right and 4 units up.

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Since the calculated t-value of 2.128 is greater than the critical t-value of ±2.101, we can reject the null hypothesis. This suggests that there is evidence to conclude that the mean lifetimes of the items produced by company A and company B are significantly different.

To draw a conclusion from the given data, we can perform a hypothesis test to compare the mean lifetimes of the items produced by company A and company B.

Let's set up the null and alternative hypotheses:

Null hypothesis (H0): The mean lifetimes of the items produced by company A and company B are equal.

Alternative hypothesis (Ha): The mean lifetimes of the items produced by company A and company B are not equal.

We can perform a two-sample t-test to compare the means of two independent samples. Since the population standard deviations are not known, we will use the t-test instead of the z-test.

Given:

Sample size for both company A and company B (n) = 10

Sample mean for company A (x(bar)A) = 80 hours

Sample standard deviation for company A (sA) = 6 hours

Sample mean for company B (x(bar)B) = 75 hours

Sample standard deviation for company B (sB) = 5 hours

Using the t-test formula:

t = (x(bar)A - x(bar)B) / sqrt((\(sA^2 / n) + (sB^2 / n))\)

Substituting the values:

t = (80 - 75) / sqrt(\((6^2 / 10) + (5^2 / 10))\)

t = 5 / sqrt(3.6 + 2.5)

t = 5 / sqrt(6.1)

t ≈ 2.128

To determine the conclusion, we need to compare the calculated t-value with the critical t-value at a specified significance level (α). The critical t-value will depend on the degrees of freedom, which is calculated as (nA + nB - 2) = (10 + 10 - 2)

= 18.

Using a significance level of α = 0.05 (commonly used), we can look up the critical t-value from a t-distribution table or use statistical software. For a two-tailed test with 18 degrees of freedom and α = 0.05, the critical t-value is approximately ±2.101.

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.

Answer:

Step-by-step explanation:

Sorry I can't explain how it is done. It is very difficult to explain on paper.

Answer:

people got rock to sell the house and I'm going to fly to the land of the block trained me like a dojo now I'm better than yb and I will be there in about it dirk can you ask mom to get

Answer:

64 miles

Step-by-step explanation:

if you divide 28 by 3.5, this gives you the number of miles per hour, I got 8. Multiply that by 8 because that is the number of hours we are looking for and you get 64. That is the answer.

Answer:

31 years

Step-by-step explanation:

65000*(1.07) ^31 is around $529000

however, 65000*(1.07) ^30 is around $491000

so you would need 31 years to gain more than $500,000.

It will take approximately 30 years to reach $500,000 in savings with an investment that earns an average of 7% per year.

To determine the number of years it will take to reach $500,000 in savings with an investment that earns an average of 7% per year, we can use the given investment model equation: y = 65000(1.07)ˣ.

We need to find the value of x, which represents the number of years.

Setting y = $500,000, we can solve for x:

500,000 = 65,000(1.07)ˣ

500,000/65,000 = (1.07)ˣ

100/13 = (1.07)ˣ

To solve for x, we take the logarithm of both sides:

ln 100/13 = ln (1.07)ˣ

ln 100/13 = x ln (1.07)

x = (ln 100/13)/(ln (1.07))

x = 30

Therefore, it will take approximately 30 years to reach $500,000 in savings with an investment that earns an average of 7% per year.

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Answer:

28+12x

Step-by-step explanation:

Multiply 7 with 4

Multiply 3x with 4

Answer:

28+12x

im pretty sure that is right

Answer:

La diferencia en los tamaños entre los siguientes tamaños de teclas es de 1/32 pulgadas

Step-by-step explanation:

El número de llaves que tiene el mecánico = 20 llaves

El tamaño de la llave más grande = 3/4 pulgadas

El tamaño de la llave más pequeña = 1/8 pulgadas

La diferencia de medida entre la tecla más grande y la más pequeña = 3/4 - 1/8 = 5/8 pulgadas

El aumento de la medición entre las teclas posteriores se puede dar de la siguiente manera;

D = 5 / (20 × 8) = 1/32 pulgadas

Los tamaños de las teclas son;

(Usando Excel y Word)

3/4 pulgadas, 5/7 pulgadas, 2/3 pulgadas, 2/3 pulgadas, 5/8 pulgadas, 3/5 pulgadas, 4/7 pulgadas, 1/2 pulgadas, 1/2 pulgadas, 1/2 pulgadas, 4/9 pulgadas, 2/5 pulgadas, 3/8 pulgadas, 1/3 pulgadas, 1/3 pulgadas, 2/7 pulgadas, 1/4 pulgadas, 2/9 pulgadas, 1/5 pulgadas, 1/6 pulgadas, 1/8 pulgadas

La diferencia en los tamaños entre los tamaños de clave posteriores = 1/32 pulgadas.

Answer:

2700

Step-by-step explanation:

1200/4 = 300

300×5 =1500

1200+1500 = 2700

Answer:

25

Step-by-step explanation:

<ABD=<BDC

Check it out

Answer:

∠ BDC = 25°

Step-by-step explanation:

Since ABCD is a parallelogram , then

AB and DC are parallel , so

∠ BDC = ∠ ABD = 25° ( alternate angles )

Answer:

6/11*5/10 = 3/11

Step-by-step explanation:

first we can get 6/11 which is the probability.

then we minus both sides by 1 to get 5/10

then we times them

The statement "correlation is measured on a scale from 0 to 1, where 0 indicates no linear relationship between two variables, and 1 indicates a perfect linear relationship" is true.

The correlation coefficient, typically denoted as r, is a statistical measure that quantifies the strength and direction of the linear relationship between two variables. It ranges from -1 to 1, where -1 represents a perfect negative linear relationship, 1 represents a perfect positive linear relationship, and 0 indicates no linear relationship or correlation between the variables.

A correlation coefficient of 0 means that there is no linear association between the variables being analyzed. As the correlation coefficient moves closer to 1 or -1, it indicates a stronger linear relationship between the variables. Therefore, the scale from 0 to 1 is commonly used to represent the extent of correlation, where 0 signifies no linear relationship and 1 signifies a perfect linear relationship.

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By Using the Cumulative distributed Function(CDF)m we get:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Given:

The cdf is as follows:

F(x) = 0                    x < 0

F(x) = (x^2 / 25)     0 < x < 5

F(x) = 1                   x > 5

Now,

a) Evaluate the CDF given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

P (x <= 3 ) = (3^2 / 25)  - 0

P (x <= 3 ) = 0.36

b) Evaluate the CDF given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the CDF given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

    P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

   So, P( x < a ) = 0.5

         ⇒ (x² / 25) = 0.5

          ⇒ x² = 12.5

          ⇒ x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

      pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

      E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

       E(X) = integral ( x² / 12.5)    

        E(X) = x³ / 37.5                    limits: 0 to 5

        E(X) = 5³ / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

 Var(X) = integral ( x² . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

 Var(X) = integral ( x³ / 12.5).dx - (E(X))^2    

 Var(X) = x⁴/ 50 | - (3.3333)^2                         limits: 0 to 5

 Var(X) = 5⁴/ 50 - (3.3333)^2 = 13.8891

Standard Deviation (s.d) (X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

      h(x) = (f(x))^2 = x^2 / 156.25

The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

E(h(X))) = integral ( x^3 / 156.25)    

E(h(X))) = x^4 / 156.25                      limits: 0 to 25

E(h(X))) = 25^4 / 156.25 = 2500

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The answer to the given binary operation is 10012. The binary operation of adding 1112 and 102 will be solved by converting the binary numbers to base 10, performing the addition in base 10, and then converting the result back to base 2.

Converting the binary numbers to base 10, we have 1112 = 7 and 102 = 2. Adding 7 and 2 in base 10 gives us 9. To convert the result back to base 2, we divide 9 by 2 repeatedly until the quotient becomes 0. The remainder in each division gives us the binary digits of the answer. In this case, 9 divided by 2 is 4 with a remainder of 1, and 4 divided by 2 is 2 with a remainder of 0. Therefore, the binary representation of 9 is 1001. Hence, the answer to the given binary operation is 10012.

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If the absolute value of the computed t-score is greater than the critical value, then the correlation is statistically significant at α = 0.05, two tails.

To determine which correlations are statistically significant with α = 0.05, two tails, we need to compare the computed Pearson correlation coefficient (r) to the critical value from the t-distribution.

In a sample of n = 18 pairs of x and y values, the significance of the correlation is assessed using hypothesis testing. The null hypothesis states that there is no correlation between the variables (ρ = 0), while the alternative hypothesis suggests a significant correlation (ρ ≠ 0).

To test the hypothesis, we calculate the sample correlation coefficient (r) and then convert it to a t-score using the formula

t = (r × \(\sqrt(n-2)\)) / \(\sqrt(1 - r^2)\)

The degrees of freedom for the t-distribution are df = n - 2.

Next, we compare the absolute value of the computed t-score to the critical value of the t-distribution with α/2 = 0.025 significance level.

If the absolute value of the t-score exceeds the critical value, we reject the null hypothesis and conclude that the correlation is statistically significant.

The critical value for α = 0.05, two tails, depends on the degrees of freedom (df = 16 in this case) and can be obtained from a t-table or statistical software. If the absolute value of the computed t-score is greater than the critical value, we can say that the correlation is statistically significant at α = 0.05, two tails.

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