What is the answer to this ?

For complete combustion of propane (c3h8) with the theoretical amount of air, the number of moles of oxygen (o2) per mole of fuel is: 5:1 or 5 moles of O2 per mole of C3H8.    

The balanced equation for the combustion of propane is:

C3H8 + 5O2 → 3CO2 + 4H2O

From the balanced equation, we can see that for every mole of propane (C3H8), we require 5 moles of oxygen (O2) for complete combustion.

This means that the number of moles of oxygen per mole of fuel is 5:1 or 5 moles of O2 per mole of C3H8.

When propane undergoes complete combustion, it reacts with an appropriate amount of oxygen to produce carbon dioxide (CO2) and water (H2O) as the main products.

The ratio of 5 moles of O2 per mole of C3H8 ensures that all the carbon and hydrogen in propane are fully oxidized to CO2 and H2O, respectively.

It's important to note that the theoretical amount of air is used in this context, assuming that air is composed of 21% oxygen. If the actual air composition or excess air is given, the calculation may differ.

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Answer:

It is well known to us that the Solubility of solute in a solution increases with the increase in the temperature because, when the temperature increases the molecules of the solvent gain more kinetic energy.

Explanation:

Answer:

To find the mass of a 19.6 ml solution of 18.0 wt% cacl2, we can use the density of the solution and the volume.

First, we need to convert the percentage concentration to a mass fraction. We can do this by multiplying the percentage by the mass of one mole of cacl2 (110.98 g/mol) and then dividing by 100.

mass fraction = (18.0 wt%) * (110.98 g/mol) / 100 = 19.79 g/100g

Next, we can use the density of the solution to find the mass of 19.6 ml of the solution:

mass = density * volume = 1.165 g/ml * 19.6 ml = 22.904 g

Now, we can convert the mass to milligrams by multiplying by 1000

mass (milligrams) = 22.904 g * 1000 = 22904 mg

So, the mass of a 19.6 ml solution of 18.0 wt% cacl2 is 22904 mg

Taking into account the reaction stoichiometry, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

In first place, the balanced reaction is:

4 NH₃ + 3 O₂  → 2 N₂+ 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 56 grams of N₂, 4.03 moles of NH₃ form how much mass of N₂?

\(mass of N_{2} =\frac{4.03 moles NH_{3} x56 grams of N_{2} }{4 moles NH_{3}}\)

mass of N₂= 56.42 grams

Then, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

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Answer:

yes??

Explanation:

The wavelength of the emitted photon is approximately 2.44 μm.

The wavelength of the emitted photon can be determined using the Rydberg formula as follow

\(\frac{1}{\lambda}=R_H\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)\)

where: lambda is the wavelength of the emitted photon,

\(R_H=1.0974\times10^7\text{m}^{-1} ,$n_1=19 n_2=5 :\frac{1}\)

\({\lambda}=R_H\left(\frac{1}{19^2}-\frac{1}{5^2}\right) \frac{1}\\\\\\{lambda}=1.0974\times10^7\text{m}^{-1}\left(\frac{1}{361}-\frac{1}{25}\right) \frac{1}\\{\lambda}=1.0974\times10^7\text{m}^{-1}\left(0.002709-0.04\right) \frac{1}\\{\lambda}=1.0974\times10^7\text{m}^{-1}\times(-0.037291) \frac{1}{\lambda}=-409446.34\text{m}^{-1} \lambda=-\frac{1}{409446.34\text{m}^{-1}}=2.44\times10^{-6}\text{m}\)

Therefore, the wavelength of the emitted photon is approximately 2.44 μm.

Rounded to two decimal places, this value is equal to 2.45 μm. Thus, the correct option is A) 2.45μm.

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The volume that is occupied by the gas is obtained as  56 L.

We know that from the Avogadro's law, the volume that can be occupied by one mole of a gas is obtained as 22.4 L. This implies that we have to find the number of moles in the 70 g of the CO and then obtain the corresponding volume by simple proportion.

Number of moles of CO = 70.0 g/28 g/mol

= 2.5 moles

If 1 mole of the gas occupies 22.4 L

2.5 moles of the gas occupies 2.5 * 22.4/1 mole

= 56 L

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Answer:

The reason for this is because of the repulsive force between protons: The stronger the repulsion force, the more neutrons are needed to stabilize the nuclei.

Explanation:

By subjecting the two compounds to Jones reagent, you can observe the difference in their reactivity and determine the compound that undergoes oxidation (4-methyl-3-penten-1-ol) and the one that does not (1-methoxy-3-methyl-2-butene).

To distinguish between 1-methoxy-3-methyl-2-butene and 4-methyl-3-penten-1-ol, you can use an oxidizing agent that can react selectively with the alcohol group present in 4-methyl-3-penten-1-ol.

One suitable reagent for this purpose is Jones reagent (a mixture of chromic acid and sulfuric acid). Jones reagent is a strong oxidizing agent that can convert alcohols to their corresponding carbonyl compounds (aldehydes or ketones).

Here's what would happen with each compound:

Methoxy-3-methyl-2-butene does not have an alcohol group, so it would not react with Jones reagent.

4-Methyl-3-penten-1-ol has an alcohol group, and it can be oxidized by Jones reagent to form the corresponding aldehyde or ketone. The specific product obtained would depend on the reaction conditions.

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Answer:

forms/types

Explanation:

Sulfur and oxygen are nonmetals and tend to form covalent compounds instead of ionic compounds. When sulfur and oxygen combine, they form sulfur dioxide (SO₂) or sulfur trioxide (SO₃) which are covalent compounds. the pair of elements that will not form ionic compounds are sulfur and oxygen, option (a).

b. Sodium and calcium are both metals that readily form cations and can form ionic compounds with anions. Sodium forms a +1 cation, while calcium forms a +2 cation. They can form ionic compounds with negatively charged anions such as chloride, oxide, or sulfide.

c. Sodium is a metal that readily forms a cation while sulfur is a nonmetal that can form an anion. Thus, they can form an ionic compound, sodium sulfide (Na₂S).

d. Barium is a metal that readily forms a cation, while chlorine is a nonmetal that can form an anion. Thus, they can form an ionic compound, barium chloride (BaCl₂).

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Answer: polymers

Explanation:

Polymers are huge natural molecules are connected with small natural molecules 

If hard water is softened by the ion exchange method, the level of sodium (d) will increase. This is because calcium and magnesium ions in the hard water are replaced with sodium ions during the ion exchange process.

The ion exchange method for softening hard water includes swapping out the calcium and magnesium ions for sodium ions, which raises the concentration of sodium in the water. This procedure has no impact on the levels of dissolved oxygen or iron.

The correct answer is d. sodium. Softening hard water through the ion exchange method involves replacing the calcium and magnesium ions with sodium ions, which results in an increase in the level of sodium in the water. Dissolved oxygen and iron levels are not affected by this process, and P1-1 is not a relevant term for this question.

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Answer:

Residuals Requires 5,000 times greater

Answer:

i guess none of these or 3.4% for 10%

Explanation:

I think the answer should be in the 30 to 40 number scale

0.831 liters of a 2.18 M solution can be made from 200.0 g K2S. To determine how many liters of a 2.18 M solution can be made from 200.0 g K2S, we first need to calculate the number of moles of K2S in the 200.0 g sample.

The molar mass of K2S is 110.26 g/mol (39.10 g/mol for potassium and 32.07 g/mol for sulfur, each multiplied by 2 for the two potassium atoms and one sulfur atom in K2S).

Using the formula:

moles = mass (in grams) / molar mass

we get:

moles K2S = 200.0 g / 110.26 g/mol = 1.813 mol

Next, we can use the formula for calculating Molarity:

Molarity = moles of solute / liters of solution

Rearranging the formula:

Liters of solution = moles of solute / Molarity

Substituting the values we know:

Liters of solution = 1.813 mol / 2.18 mol/L = 0.831 L

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Place the atomic number subscript and mass number superscript to the left of the atomic symbol.

The chemical properties of an atom are determined by its atomic number and are represented by the symbol Z. The total number of nucleons in an atom is the atomic mass number. This value is represented by the symbol A.

Isotopes are members of a family of elements that have the same number of protons and a different number of neutrons. The number of protons in the nucleus determines the atomic number of an element on the periodic table. Isotopes are atoms of the same element that contain the same number of protons but different numbers of neutrons.

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Answer:

E° = -1.66 V

Explanation:

The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.

From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;

E° = -1.66 V

In future purification procedures, adjusting the pH and using different column matrices could be effective in sharpening peak 2 like peak 1.

Peak 1 appears to be sharper than peak 2, which could indicate differences in the physical properties of the molecules being separated or differences in the purification protocol. Adjusting the pH of the mobile phase or buffer system could affect the retention time and selectivity of the column, potentially leading to sharper peaks.

Additionally, using a different column matrix with a higher resolution could improve peak separation and sharpen the peaks. It may also be helpful to optimize the sample preparation or injection volume to ensure the highest possible resolution. Overall, it is important to carefully evaluate and troubleshoot the purification protocol to identify potential areas for improvement in order to obtain sharper and more accurate separation of the target molecules.

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Formal charge is calculated by assuming equal sharing of bonding electrons, while oxidation numbers are assigned by assuming that the most electronegative atom takes all the bonding electrons.

The difference between formal charge and oxidation numbers is as follows:

Formal charge is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of their electronegativity. To calculate the formal charge of an atom, use the formula:

Formal Charge = (Valence Electrons) - (Non-bonding Electrons) - 1/2(Bonding Electrons)

Oxidation number, on the other hand, is a hypothetical charge assigned to an atom in a compound, assuming that the most electronegative atom in a bond takes all the bonding electrons. It is used to describe the degree of oxidation (loss of electrons) of an atom in a chemical compound.

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Given what we know about the energy of particles in each state, we can confirm that the best comparison between water and ice is that particles of liquid water have more energy than particles of ice.

Therefore, we can confirm that since the heat required to keep water in a liquid state excites the particles and gives them more energy, the correct comparison would be to say that particles of liquid water have more energy than particles of ice, option B is correct.

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Answer:

b.

Explanation:

Answer:

43.8 g of iron can be recovered

Explanation:

First get the mass of Fe3O4 in the ore:

80g Ore * (76 g Fe3O4 / 100 Ore) = 60.8 g Fe3O4

Then get number of moles of Fe3O4:

60.8 g Fe3O4 * 1 mol / 231.535 g = 0.262 mol Fe3O4

**231.535 g is the molar mass of Fe3O4

Then get number of moles of Fe:

0.262 mol Fe3O4 * (3 Fe / 1 Fe3O4) = 0.786 mol Fe

** 3 atoms of Fe in every Fe3O4

Finally convert moles of Fe to grams of Fe:

0.786 mol * 55.845 g/mol = 43.79 g Fe --round to 3 sig figs--> 43.8 g Fe

Answer:

c

c

Explanation:

mark me brainliest pls

Anser:

Explanation:

hope this helps

Answer:

true

Explanation:

Answer:

is matter

Explanation:

Answer:

c. 640.51

Explanation:

Given: 2.54 cm = 1 inch weighed 3.88 ounces

1 g = 0.035273 ounces

?   = 3.88 ounces

? = (3.88 x 1) / 0.035273

? = 109.999 = 110 g

110 g = 3.88 ounces

2.54 cm = 110 g

14.79 cm = ?

? = (14.79 x 110) / 2.54

? = 640.51 g

According to unit conversion, there are 640.51 g would a 14.79 cm length of same iron rod weigh.

Unit conversion is defined as a multi-step process which involves multiplication or a division operation by a numerical factor.The process of unit conversion requires selection of appropriate number of significant figures and the rounding off procedure.

It involves a conversion factor which is an expression for expressing the relationship between the two units.A conversion ratio always has value which equals to one which indicates that numerator and denominator have values which are expressed in different units.

Given: 2.54 cm = 1 inch weighed 3.88 ounces,1 g = 0.035273 ounces

x  = 3.88 ounces

x= (3.88 x 1) / 0.035273

x = 109.999 = 110 g

110 g = 3.88 ounces

Thus,2.54 cm = 110 g

14.79 cm = x

x= (14.79 x 110) / 2.54

x = 640.51 g

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The activation energy for this reaction is 64.5 kJ/mol.

To determine the activation energy (Ea) for a reaction, we need to use the Arrhenius equation. This equation relates the rate constant (k) to the temperature (T) and the activation energy of the reaction. The equation is as follows:

k = Ae^(-Ea/RT)

where A is the pre-exponential factor, R is the gas constant, and T is the temperature in Kelvin.

We have been given the data for a series of experiments where a solution was heated at different temperatures. The data should include the rate of reaction (k) at each temperature.

To calculate the activation energy, we need to use two sets of data: the rate constant (k) and the temperature (T) for two experiments. We can then substitute these values into the Arrhenius equation and solve for Ea.

Let's say we have two sets of data:

k1 = 0.1 s^-1, T1 = 300 K
k2 = 0.4 s^-1, T2 = 350 K

Substituting these values into the Arrhenius equation, we get:

ln(k1/k2) = (Ea/R)(1/T2 - 1/T1)

Solving for Ea, we get:

Ea = -R ln(k1/k2)/(1/T2 - 1/T1)

Plugging in the values, we get:

Ea = -8.31 J/mol K ln(0.1/0.4)/(1/350 - 1/300)

Ea = 64.5 kJ/mol

Therefore, 64.5 kJ/mol is the activation energy.

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