what is the angular speed ω , in rad/s,rad/s, of an object that completes 8.00 rev8.00 rev every 18.0 s?

Converting 0.745 atm to mmHg, the result is approximately 563 mmHg, considering the appropriate significant figures.

To convert atmospheres (atm) to millimeters of mercury (mmHg), we can use the conversion factor of 1 atm = 760 mmHg.

Given that the original value is 0.745 atm, we can multiply it by the conversion factor:

0.745 atm * (760 mmHg / 1 atm) = 565.200 mmHg.

Considering significant figures, the original value has three significant figures. Since the conversion factor has an exact value, the result should also have three significant figures.

Rounding the result to three significant figures, we get approximately 563 mmHg.

Therefore, when converting 0.745 atm to mmHg with the appropriate number of significant figures, the result is approximately 563 mmHg.

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The two reasons why a home computer scanner requires electromagnetic waves to operate are

C. The charge-coupled device contains a silicon chip that releases electrons by the photoelectric effect, producing an image.

D. Visible light needs to reflect off an object and be captured by a charge-coupled device.

The waves that may go through vacuum space are electromagnetic waves. Magnetic and electrical components are present in electromagnetic waves.

All of them move at the speed of light. The atoms of the material absorb and reemit wave energy as part of the energy transport process through a medium. To transfer their energy from one place to another, mechanical waves need a medium to move through.

Therefore, the correct options are c and d.

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The final velocity of the car, given the data is 32.88 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question:

The final velocity of the car can be obtained as follow:

a = (v – u) / t

1.6 = (v – 22) / 6.8

Cross multiply

v – 22 = 1.6 × 6.8

v – 22 = 10.88

Collect like terms

v = 10.88 + 22

v = 32.88 m/s

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Answer:

1.26

Explanation:

f=1/(2pi) square root k/m

f=1/(2pi) square root 42.4/.675

f=1.26 I just did this question and found this right

Answer:

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

x is the final velocity of the 0.25kg ball

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at 0.55 m/s towards the right

Changing the length of a string may alter the force in a physical system, like a pulley mechanism, if it impacts its tension and length.

Nonetheless, regarding a digital system such as a software application, replacing the string with another one that does not affect any crucial factors is improbable to cause an alteration in said force amount.

Determining whether changing a component of a method leads to any modifications in strength requires recognizing essential aspects influencing that force while keeping in mind how this modification might hinder these key elements.

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Answer:

A :>

Explanation:

It opens the circuit so that electric charges do not flow to the timer.

When electricity flows over the entire path of an electric circuit, it is said to be closed or complete.

Here,

In a closed circuit, there is no interruption to the flow of electric current through it, because each point in the path of a closed circuit are connected.

When the wire is cut from the bomb, it stopped the countdown timer. This means that, while cutting the wire, the circuit of the bomb, which was a closed electric circuit, became an open circuit.

As a result, the current flow through the circuit is blocked by the open circuit system.

Therefore, the countdown timer of the bomb stopped by cutting the wire.

Hence,

It opens the circuit so that electric charges do not flow to the timer.

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Explanation:

the pressure is given by P=hpg

where h is height,p is density, g is 10m/s²

thus P= 0.05m•13.6x10³•10

P=6.8x10³ Hgmm

Answer:

A. 3.4 m

Explanation:

Given the following data;

Force = 56.7N

Workdone = 195J

To find the distance

Workdone is given by the formula;

\( Workdone = force * distance\)

Making "distance" the subject of formula, we have;

\( Distance = \frac {workdone}{force} \)

Substituting into the equation, we have;

\( Distance = \frac {195}{56.7} \)

Distance = 3.4 meters.

Answer:

c. prone; supine

Explanation:

The magnitude of the current in the long wire is approximately 2 × 10^6 Amperes or 2,000,000 Amperes. ω is the angular speed, ω = 36.54 m/s.

To find the magnitude of the current in the long wire, we can use Ampere's Law, which relates the magnetic field produced by a current-carrying wire to the current flowing through it.

Ampere's Law states that the magnetic field at a distance r from an infinitely long straight wire is given by:

B = (μ₀ * I) / (2π * r)

where B is the magnetic field, μ₀ is the permeability of free space (μ₀ = 4π × 10^-7 T m/A), I is the current in the wire, and r is the distance from the wire.

We are given the magnetic field B as 0.004 × 10^-4 T and the distance r as 1.0 mm (which is equal to 0.001 m).

We can rearrange the equation to solve for the current I:

I = (B * 2π * r) / μ₀

Substituting the given values:

I = (0.004 × 10^-4 T * 2π * 0.001 m) / (4π × 10^-7 T m/A)

Simplifying the expression:

I = (0.008π) / (4π × 10^-7) A

I ≈ 2 × 10^6 A

Therefore, the magnitude of the current in the long wire is approximately 2 × 10^6 Amperes or 2,000,000 Amperes.

As for the second part of your question, to find the angular speed (ω) of the charged particle moving in a circle due to the magnetic field, we can use the formula:

ω = v / R

where ω is the angular speed, v is the linear velocity of the particle, and R is the radius of the circular path.

We are given the charge of the particle as 8.5 mC (milli-Coulomb), the mass as 1.3 g (which is equal to 0.0013 kg), and the magnetic field as 5.5 T.

First, we need to find the linear velocity of the particle. Since the particle moves in a circle, the magnetic force acting on it provides the centripetal force required for circular motion:

qvB = mω²R

where q is the charge, v is the linear velocity, B is the magnetic field, m is the mass, ω is the angular speed, and R is the radius.

Rearranging the equation, we have:

v = ωR = (qB) / m

Substituting the given values:

v = (8.5 × 10^-3 C * 5.5 T) / 0.0013 kg

v ≈ 36.54 m/s

Now, we can calculate the angular speed using the formula:

ω = v / R

Substituting the values of v and R:

ω = 36.54 m/s

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Answer:

a = \(-\frac{25}{27}\) m/s²

Explanation:

Acceleration (a) = (final velocity - initial velocity) ÷ (final time - initial time) =  \(\frac{v_{f} - v_{i} }{t_{f} - t_{i} }\)

Converting the speed from km/h to m/s;

100 km = 100000m

1hr = 3600s

∴ 100km/hr ⇄ \(\frac{100000 m}{3600 s}\) = \(\frac{250}{9} m/s\)

Acceleration = \(\frac{0 - 250/9}{30}\) = \(-\frac{250}{9 * 30} = -\frac{25}{27}\) m/s²

i.e deceleration = \(\frac{25}{27}\) m/s²

The coefficient of kinetic friction between the puck and surface id 0.20.

What is coefficient of kinetic friction?

Coefficient of kinetic friction is the ratio between frictional force present in the motion of two surfaces that are in contact to the normal force that presses the two surface together.

It is calculated mathematically as: μ = F/N, where

F= frictional force and N= normal force.

v2 = u2 +2as

0= 62 + 2a9

18a + 36= 0

18a = -36

a= -2

friction =  μ × normal force

or friction =ma

ma=  μN

ma=  μ(mg)

μ = a/g where g = 9.8 N

μ= -2/9.8

⇒0.20.

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The force of air resistance acts on any object while moving through the air.

We live in a medium where the air is present everywhere. It is not a vacuum where no force will be experienced by us but we live on earth where the air is present everywhere. Whenever we cut through, the air we encounter a force called air resistance.

Air resistance is like friction, it is everywhere. Air resistance always acts opposite to our direction of motion and like friction, it is a necessary evil.

Whenever an object moves through the air, air resistance always acts to oppose its motion.

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When a box weighs 18 newtons, a force of 6 newtons is required to drag it, the coefficient of kinetic friction is 0.333. Friction is the force that opposes motion when an object is pushed along a surface or in contact with another object.

It always acts in the opposite direction to the direction of movement. There are two types of friction, kinetic friction and static friction. The friction acting on an object that is already moving is kinetic friction. Friction acting on an object that is at rest is called static friction. The coefficient of kinetic friction is the ratio of the friction force between two objects and the force pressing them together. It's a dimensionless scalar quantity. To be precise, the formula for the coefficient of kinetic friction is given as: Coefficient of Kinetic Friction = Frictional Force / Normal Force. Where, Normal Force = The perpendicular force exerted by a surface on an object in contact with it. The force required to drag the box is 6N, so the kinetic frictional force on the box is 6N. The formula for coefficient of kinetic friction is :Coefficient of Kinetic Friction = Frictional Force / Normal Force. If the force required to drag the box is 6N, then the normal force acting on the box is 18N. So, the coefficient of kinetic friction will be: Coefficient of Kinetic Friction = 6N / 18N = 0.333

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Answer:

1. 310 N

2. 310 N

Explanation:

1. Determination of the net force.

Force applied (Fₐ) = 430 N

Force experience (Fₑ) = 120 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fₑ

Fₙ = 430 – 120

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N

2. Determination of the net force.

Force applied (Fₐ) = 375 N

Force of friction (Fբ) = 65 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 375 – 65

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N.

Answer:

The size of an object is directly proportional to the gravity

Explanation:

The size of an object has significant impact on the gravity exerted by such a body.

The more massive a body is, the larger the gravity it exerts.

The reason for this is because of the newton's law of universal gravitation.

The data set that is most likely from the car equipped with ABS is :

Although the plots related to your question is missing attached below is the missing data.  

The First plot ( acceleration vs time ) plot is the data that represents the application of brakes in a car fitted with ABS ( antilock braking system ) because of the absence of skidding effect between 6.5 and 9 seconds in the graph.

The skidding effect is present in the second plot around the same time because the car is not fitted with ABS  

Hence we can conclude that the graph that shows the car fitted with ABS is the first plot .

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Given:

The area of the plate is: A = 0.188 m²

The field produced between the plates is: E = 37000 N/C

To find:

The charge to be placed on the plates.

Explanation:

The electric field produced between two parallel plates is given as:

Here, Q is the charge on the parallel plates and ε₀ is the permittivity of free space having a value of 8.85 × 10⁻¹² C²/N.m²

Rearranging the above equation, we get:

Substituting the values in the above equation, we get:

Final answer:

The amount of charge to be placed on parallel plates is 6.156 × 10⁻⁸ C.

Answer:

F = 32.2 m

Explanation:

F = ma

F = m * 32.2

Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

Answer:

The correct option is;

The index of refraction of the second medium is lower

Explanation:

The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.

The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum

Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium

Answer: Newton was a realist

Explanation: Newton held a realist reading of scientific theory as based upon inference from facts and observation, and his gravitational theory (or NGT) as deduced from observed phenomena and Kepler's laws.

The speed of the other object formed is 4.8 m/s.

The change in kinetic energy is 9.84 J.

Mass of the first object, m₁ = 3 u

Velocity of the first object, v₁ = 0.8 c

Mass of the second object, m₂ = 4 u

Velocity of the second object, v₂ = 0.6 c

Mass of the object at rest, m' = 6 u

a) According to the conservation of momentum,

m₁ + m₂ = m'+ m

So, m = (3 + 4) - 6

m = 7 - 6 = 1 u

m₁v₁ + m₂v₂ = (m x v) + (m' x v')

(3 x 0.8) + (4 x 0.6) + (1 x v) + (6 x 0)

Therefore, the speed of the other object formed is,

v = 2.4 + 2.4

v = 4.8 m/s

b) The change in kinetic energy is given by,

E = KE - (KE₁ + KE₂)

E = 1/2mv² - (1/2m₁v₁² + 1/2m₂v₂²)

E = 1/2(mv² - m₁v₁² - m₂v₂²)

E = 1/2[(1 x (4.8)² - 3 x (0.8)² - 4 x (0.6)²]

E = 1/2(23.04 - 1.92 - 1.44)

E = 1/2 x 19.68

E = 9.84 J

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The quantity of internal and mechanical energy that things contain fluctuates as a result of work.

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Answer: C. Discrimination by employers

Explanation:

Economist Y is most likely to be correct when labor and product markets are highly competitive and the lower wages of the disfavored group result from discrimination by employers.

option C is the correct answer.

Discrimination in the workplace happens when an employer treats his or her employee unfairly or unequally because of specific characteristics.

Labor market discrimination against certain workers unfairly leads to lower wages for the disfavored group.

Example of labor market discrimination include the following;

According economist Y, government intervention cannot eliminate this unfair treatment since it is caused by the market (employers) and the best solution to the unfair treatment is to let the market (employers) work to eliminate it on its own.

Thus, economist Y is correct because this discrimination is caused by the market (employers).

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Answer:

B. 2.77 x \(10^{-4}\) N

Explanation:

The required force can be calculated by:

F = \(\frac{Kq_{1}q_{2} }{d^{2} }\)

Where F is the force between the particles, K is the coulomb's constant (9 x \(10^{9}\) \(Nm^{2}/C^{2}\)), \(q_{1}\) is the charge on the first particle, \(q_{2}\) is the charge on the second particle and \(d^{2}\) is the distance between the particles.

So that:

F = \(\frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9} }{(0.015)^{2} }\)

  = \(\frac{6.2307*10^{-8} }{(2.25*10^{-4} }\)

  = 2.7692 x \(10^{-4}\)

 The force between the particles is 2.77 x \(10^{-4}\) N.

Answer:

b

Explanation:

a pex

Answer:

The atomic number is typically located above the element symbol. ... The atomic mass number is equal to the number of protons plus neutrons, which provides the average weight of all isotopes of any given element. This number is typically found beneath the element symbol.

Explanation:

The periodic table is the systematic arrangement of the elements in the increasing order of their atomic number.

The periodic table is the organized arrangement of all the elements, arranged in the increasing order of their atomic numbers.

The elements are grouped into the s-block, p-block, d-block and the f-block elements in the periodic table.

The atomic number is typically located above the element symbol. The atomic mass number is equal to the number of protons plus neutrons,

which provides the average weight of all isotopes of any given element. This number is typically found beneath the element symbol.

Thus the periodic table is the systematic arrangement of the elements in the increasing order of their atomic number.

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Around 3 p.m., when the sun is sufficiently low in the sky, more heat is lost than is received.

Even though the sun's beams are most direct around noon, the afternoon is the warmest part of the day because air temperatures close to the earth's surface will continue to rise as long as incoming solar radiation outweighs outgoing longwave earth radiation.

Around 3 p.m., it gets the warmest. When the sun is at its zenith in the sky, or after midday, heat continues to accumulate as long as more heat is entering the earth than is leaving. When the sun is low enough in the sky, around 3 p.m., more heat is lost than is gained.

Many people believe that noon is when it gets the warmest. We receive the maximum energy from the sun at noon, which may make it feel hotter. But during the day, Earth is accumulating heat or energy from incoming sources. The air becomes warmer as the day goes on.

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