What is the aim of the in vitro screen performed at the institute?
a) To analyze the usefulness of robots in compound screening
b) To study the chemical composition of compounds
c) To identify potential anticancer compounds
d) To characterize the morphology of cancer cells

The Galactic Zone Grounds is a location in the video game Fallout 4, where the players can collect a total of nine Star Cores.

To locate the star cores in the galactic zone grounds, you need to follow the given instructions:Players need to head to the Galactic Zone Grounds and the entrance to the zone from the park. Upon entering, head to the right towards the Star Control section and continue through the exhibits.Keep an eye out for the display marked "RobCo Battlezone" that you must enter and kill the robots inside it to collect the star core.

The next star core is located in the "Starlight Interstellar Theater" section of the Galactic Zone. Players need to search for a display that will have two planets orbiting around a sun in the middle of the room. Press the button on the display, which will activate a hidden elevator that will take you to the second level. You will find the Star Core in this room.The third star core is in the "Vault-Tec: Among the Stars" exhibit. Search for the display that has a rocket and a video in the back of the room.

You will discover a security gate with a terminal. Unlock the gate with the terminal and take the Star Core.In the "RobCo Battlezone" section of the Galactic Zone, players will find the fourth star core. Search for a display of the RobCo robot and the battle zone computer. Hack the terminal to turn on the robot and collect the Star Core.Fifth, sixth, seventh, eighth and ninth star cores can be found in the "Starport Nuka" area of the Galactic Zone. These five stars cores are located within the space walk area that will lead to the "Nuka-Galaxy Rollercoaster." The five Star Cores in this area are hidden behind walls, so you will need to look for them meticulously.

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The number of mutations that will occur in the S.aureus population in foot wounds is 0.0336.

The natural habitat of S. aureus in humans is in the area of ​​the skin, nose, mouth, and large intestine, where under normal immune system conditions, S. aureus is not pathogenic (normal human microflora).

Bacterial genes can mutate quickly. These mutations can make bacteria reproduce faster, become stronger, and kill. The mutation can also be accelerated by the excessive use of antibiotics. As a result, bacteria also become more resistant to antibiotics.

Generations are produced in 12 hours:

12*60/30 = 24 generations.

Mutations in 1 generation are 0.0028.

Then the mutation after 12 hours is 12* 0.0028 = 0.0336

Your question is incomplete but most probably your full question was:

Staphylococcus aureus is a bacterium that can cause infections in broken skin. A single S. aureus cell gets into a wound on someone's foot. An S. aureus cell divides by binary fission approximately every 30 minutes. S. aureus has 2.8 x 106 base pairs in its genome. Mutations occur at a rate of 1 per 1010 base pairs per generation. Therefore, approximately 0.0028 mutations will occur per cell in the population. At the end of 12 hours, how many mutations will be present in the population of S. aureus in the wound on the foot?

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Answer:

Actually, the substance is the one that changes from liquid to gas.

The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.

The force exerted by the wrestler on the weights of mass 90 kg that accelerates downward at a rate of 2.69 m/s^2 is - 242.1 N

F = m a

F = Force

m = Mass

a = Acceleration

m = 90 kg

a = - 2.69 m / s²

F = 90 * - 2.69

F = - 242.1 N

The formula used to solve the given problem is the Newton's second law of motion according to which force is the rate of change of momentum. The force is negative because the force acts on the opposite direction to motion of the weights.

Therefore, the force exerted by the wrestler on the weights is - 242.1 N

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Answer:

4

Explanation:

Impact Force = mv/2t

Impact force is inversely proportional to t

If m and v are constant and the only thing that changes is t, then:

0.005 s increases by a factor of 4 to 0.020 s

Therefore, impact force reduces by a factor of 4 (1/4 less than when the time of impact was 0.005 s)

Answer:

1) Use multiple instruments to measure

2) Take several measurements

3) Control the other variables delicately  

4) Be meticulous when measuring

Answer:

Meditation and Positive Thinking

Explanation:

The charge stored in the capacitor doubles when the potential difference across it does, according to the equation above.

Accordingly, a capacitor with a large capacitance can store a significant quantity of charge Q at a negligibly large potential difference.

The capacitor has two plates, one of which is charged positively, Q, and the other negatively, -Q. The charge Q on the plates and the potential difference V between the two plates are proportionate. Q = CV, and C = Q/V, where C is the proportional constant.

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Answer:

Explanation:

Average Speed = Total Distance / Total Time

5.3 m/s

Equation

Total distance = d1 + d2

Total Time = t1 + t2

Givens

Total Distance = 16 + 16

Total Distance = 32

Total Time = t2 + t1

Total Time = 2 sec + 4sec

Total Time = 6 sec

Solution

Average Speed = Total Distance / Total Time

Average Speed = 32 / 6

Average Speed = 5.33 m/s

Answer:

first

Explanation:

Newton's Newton's first law of motion states that for every action and there's an equal and opposite reaction

Answer:

D. Third

Explanation:

Answer:

Option 4 'stabilization, strength, and power' is correct.

Explanation:

During the stabilization phase, the focus is on developing proper movement patterns and improving muscular endurance to stabilize joints and improve overall posture.

During the strength phase, the focus shifts towards building muscular strength and increasing muscle size, typically through the use of heavier weights and lower reps.

Finally, during the power phase, the focus is on developing explosive power and speed through the use of plyometrics and other high-intensity exercises.

Explanation:

The reason is simple. Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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The acceleration of all objects increases when there is no air resistance because air resistance slow down the speed of an object.

The rate of change in velocity over time is known as acceleration. Velocity is the speed of an object in a specific direction. Acceleration occurs when change occurs in velocity.

So we can conclude that the acceleration of all objects increases when there is no air resistance because air resistance slow down the speed of an object.

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The cylinder's final angular speed will be 12.0 rad/s.

To find the cylinder's final angular speed when it is initially rotating at 12.0 rad/s, we can use the given information:

Initial angular speed (ω_initial) = 12.0 rad/s

Since there are no other factors or forces mentioned in the question that would affect the cylinder's rotation, we can assume that its angular speed remains constant. Therefore, the final angular speed (ω_final) will be the same as the initial angular speed.

ω_final = ω_initial = 12.0 rad/s

So, the cylinder's final angular speed will be 12.0 rad/s.

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The cylinder's final angular velocity will be approximately 0.34 rad/s.  

If the cylinder is initially rotating at 12.0 rad/s, its angular velocity will be 12.0 rad/s.

The final angular velocity of the cylinder can be found using the equation:

angular velocity = (angular acceleration) / (radius of rotation / 2)

Assuming that the cylinder is rotating without slipping, the torque acting on the cylinder can be found using the equation:

torque = (angular acceleration) / (radius of rotation)

We know that the torque required to rotate the cylinder is 50 Nm, so we can solve for the angular acceleration:

angular acceleration = torque / (radius of rotation)

angular acceleration = (50 Nm) / (12 cm)

angular acceleration = 0.42 rad/s

Substituting this value of angular acceleration in the equation for angular velocity, we get:

angular velocity = (0.42 rad/s) / (12 cm / 2)

angular velocity = 0.34 rad/s

Therefore, the cylinder's final angular velocity will be approximately 0.34 rad/s.  

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Answer:

Jesus

Explanation:

he is the way

The magnitude of the electric field is 1.77 x 10⁶ N/C, under the condition that the  distance is  25.00 cm

The electric field at a distance of 25 cm from the axis of the cylinder can be calculated using Gauss's law. The electric field at a point outside a uniformly charged cylinder is given by

E = (ρ × r) / (2 × ε0),

here

ρ = charge density,

r = distance from the axis of the cylinder

ε0 = permittivity of free space.

Now, we have a non-uniform volume charge density of

ρ = 4 × r²C/m³

r = 25 cm

= 0.25 m

Staging these values in the above equation

E = (ρ × r) / (2 × ε0) = (4 × r³) / (2 × ε0)

= (2 × r³) / ε0

E = (2 × (0.25 m)³) / ε0

= 1.77 x 10⁶ NN/C

Therefore, the magnitude of the electric field at a distance of 25 cm from the axis of the cylinder is 1.77 x 10⁶ N/C.

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The maximum displacement angle of the bob is 13⁰.

The given parameters;

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

\(P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m\)

The maximum displacement angle is calculated as follows;

\(cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0\)

Thus, the maximum displacement angle of the bob is 13⁰.

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Answer:

I guess it's force hope this answer helps

Astronauts measure their mass by measuring the period of oscillation when sitting in a chair connected to a spring. The Body Mass Measurement Device on Skylab, a 1970s space station, had a spring constant of 1.06 N/m. The empty chair oscillated with a period of 0.872 s.

The equation for the period of oscillation of a spring-mass system is given as,

T = 2π sqrt(m/k)Here, T = 1.5 s; k = 1.06 N/m;

Substitute the given values in the above equation and solve for m.

m = (T²k)/(4π²) = (1.5² × 1.06)/(4π²) ≈ 0.051 kg

Therefore, the mass of an astronaut who makes the Body Mass Measurement Device oscillate with a period of 1.500 s is approximately 0.051 kg.

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660.62 × 10⁻²⁵ Joule energy of radio wave at which radio station is broadcast.

We use the relationship between the energy of photons and the plank constant. The constant shows how the energy and frequency of a photon are related.    (E = hν)  

E = Energy of photon, h = plank constant, ν = frequency of wave

now, ν = 99.7 mhz                      h = 6.62607015×10−34 joule-hz−1

Then,  E = 99.7 × 10⁹ hz × 6.62607015 × 10⁻³⁴ joule-hz−1

              = 660.62 × 10⁻²⁵ joule

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Answer:

6/5  * R

Explanation:

The 3 in series sum to 3R for one branch of the parallel circuit

 the 2 in series sum to 2R  for the other side of the parallel circuit

now find the equivalent R of the parallel circuit with 3R and 2R

 here is one way

   Requiv = 1 / ( 1/(3R) + 1/(2R) ) =

                  1/ ( 5/(6R) ) =

                    6R/5  

the equiv resistance = 6/5  * R

If the distance between two objects decreased, the force of gravity will increase

This states that the force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

Mathemaically, it is expressed as:

F = GM₁M₂ / r²

Where

F = GM₁M₂ / r²

From the above equation, we can see that force (F) is inversely proportional to the distance (r).

Thus, if the distance between the objects decrease, the force will increase.

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The water dumped on the city by the heavy train is 350000 metric tons.

The heavy rainstorm dumps 1cm of rain on a city of dimensions 5km x 7km.

This happened in a period of 2 hours.

Now, the mass of the water can be calculated as,

Density = Mass/volume

Mass of the water on the city,

Density of water x volumr

Volume of the water collected,

Volume = 5000 x 7000 x 0.01

Volume = 350000m³.

We know the density of water is 1000 kg/m³.

Now, putting values,

Mass of water collected = 1000 x 350000

Mass of water in metric ton = 350000 metric tone.

So, the mass of the water is 350000 metric tons.

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Kim's policy remained in force for a certain number of days even though she forgot to pay the premium. the provision that allows this is called grace period provision

If the policyowner fails to make the premium payments due to some issue or reason, the insurance company will not immediately cancel the policy , whereas the company will wait for few days if no action seen than only they will take action on that account .

The grace period provision allots a specifically designated amount of time in which the policyowner has to make the required premium payments after the stipulated due date.

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The Formula Bar is where data or formulas you enter into a worksheet appear for the active cell. The Formula Bar can also be used to edit data or formula in the active cell. The active cell displays the results of its formula while we see the formula itself in the Formula Bar.

mark me brainliestt :))

Answer:

Explanation:

We know that,

Distance(S)= 100 m

Initial velocity (u)= 15 m/s

Final velocity (v) = 0m/s [As the car stops at last]

We know that,

\(2aS=v^2-u^2\)

\(a= \frac{v^2-u^2}{2S} \\\)

Substitututing values for v,u,S we get,

\(a=\frac{0^2-15^2}{2*100} \\a=\frac{-225}{200} \\a=-1.125\\Approxiametly, -1 (to the nearest whole number)\)

Answer:

Work done = 80 gm/s

Explanation:

Given:

Final velocity (v) = 4 m/s

Initial velocity (u) = 0 m/s

Mass of ball (m) = 40 g

Find:

Work done.

Computation:

Using work energy rule

Work done = Change in kinetic energy

Work done = 1/2[mv-mu]

Work done = 1/2[(40)(4) - (40)(0)]

Work done = 1/2[(40)(4)]

Work done = 80 gm/s

Answer:

spring force = -K × x , where X is elongation or compression in the spring. ( -) sigh shows that the spring force is opposite to the applied force to cause extension.

Potential energy = work done by spring force = integration of Force.

integrate the force (-K × x) over distance 0 to x .

U = 1/2 K × X^2 ( for elongation)

U = -1/2 × K × X^2 ( for compression)