What is sustainability? How can we make sustainable development a reality? How sustainability can be measured?​

Answers

Answer 1

Answer:

1)The ability to be maintained at a certain rate or amount is called sustainability.

3)Sustainability is measured by assessing performance of Social, Environmental, and Economic principles.

sorry but I don't know number 2.

I hope it will help you)):


Related Questions

Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.

Can someone explain how to do the algebra for this question? I know everything else, I just dont know

Answers

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

An elevator suspended by a vertical cable is moving downward at a constant speed. The tension in the cable must be A) greater than the weight of the elevator. B) less than the weight of the elevator. C) equal to the weight of the elevator.

Answers

Answer:

(C) because the elevator is not accelerating

Note  F = M a = M g (the resultant force on the elevator is due to gravity)

or  Fup = Fc   the force exerted on the elevator by the cable

and Fdown = Fe    the force exerted on the elevator by gravity

F = M a = Fup - Fdown = zero    resultant force on elevator

If a body of mass 2 kg is moving with a velocity of 30 m/s, then
on doubling its velocity the momentum becomes
a 30 kgm/s
b 90 kgm/s
C 120 kgm/s
d 60 kgm/s
HALPLPLPPLL

Answers

Answer:

d. 60

Explanation:

If a body of mass 2 kg is moving with a velocity of 30 m/s, then

on doubling its velocity the momentum becomes

a 30 kgm/s

b 90 kgm/s

C 120 kgm/s

d 60 kgm/s

HALPLPLPPLL

Answer:

120

Explanation:

Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is suddenly applied to the initially uncharged plates through a 1000 ohm resistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 60 volts

Answers

Answer:

\(1.62\times 10^{-8}\ \text{s}\)

Explanation:

\(\epsilon_0\) = Vacuum permittivity = \(8.854\times 10^{-12}\ \text{F/m}\)

\(A\) = Area = \(10\times 2\times 10^{-4}\ \text{m}^2\)

\(d\) = Distance between plates = 1 mm

\(V_c\) = Changed voltage = 60 V

\(V\) = Initial voltage = 100 V

\(R\) = Resistance = \(1000\ \Omega\)

Capacitance is given by

\(C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.854\times 10^{-12}\times 10\times 2\times 10^{-4}}{1\times 10^{-3}}\\\Rightarrow C=1.7708\times 10^{-11}\ \text{F}\)

We have the relation

\(V_c=V(1-e^{-\dfrac{t}{CR}})\\\Rightarrow e^{-\dfrac{t}{CR}}=1-\dfrac{V_c}{V}\\\Rightarrow -\dfrac{t}{CR}=\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-CR\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-1.7708\times 10^{-11}\times 1000\ln(1-\dfrac{60}{100})\\\Rightarrow t=1.62\times 10^{-8}\ \text{s}\)

The time taken for the potential difference to reach the required level is \(1.62\times 10^{-8}\ \text{s}\).

Based on this sequence, what is the most likely observation? A. Balloon 1 and balloon 2 have a negative charge, so they will pull towards each other. B. Balloon 1 and balloon 2 have a negative charge, so they will move away from each other. C. Balloon 1 and balloon 2 have a positive charge, so they will pull towards each other. D. Balloon 1 and balloon 2 have an opposite charge, so they will move away from each other.

Answers

Answer:

B

Explanation:

If both have the same charge they would move away from eachother.

At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in km/hr) is the distance between the ships changing at 4:00 p.m.

Answers

Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

r² = a²   +  b²

r² = 20²  +  100²

r = √10,400

r = 101.98 km

The rate of change of this distance is calculated as;

r² = a²   +  b²

r = 101.98 km, a = 20 km, b = 100 km

\(2r(\frac{dr}{dt} ) = 2a(\frac{da}{dt} ) + 2b(\frac{db}{dt} )\\\\r(\frac{dr}{dt} ) = a(\frac{da}{dt} ) + b(\frac{db}{dt} )\\\\101.98(\frac{dr}{dt} ) = 20(-30 ) + 100(25 )\\\\101.98(\frac{dr}{dt} ) = -600 + 2,500\\\\101.98(\frac{dr}{dt} ) = 1900\\\\\frac{dr}{dt} = \frac{1900}{101.98} = 18.63 \ km/h\)

why no tempature can be lower than 0 kelvin

Answers

Answer:

At zero kelvin (minus 273 degrees Celsius) the particles stop moving and all disorder disappears. Thus, nothing can be colder than absolute zero on the Kelvin scale. Physicists have now created an atomic gas in the laboratory that nonetheless has negative Kelvin values.

Explanation:

To measure the vast distance in space ,scientists use a unit called a ______, which is how far travels in one year.
The closest star to Earth is ______.
(Look at the picture)

Answers

Answer:

"light year" - about 6 million million miles

The nearest star is alpha Centauri - about 24 million million miles away

Find the moment of 300N force about B​

Find the moment of 300N force about B

Answers

Answer:

300

Explanation Hope I'm not wrong.

6th grade measuring wavelengths!
PLEASE HELP!

6th grade measuring wavelengths!PLEASE HELP!

Answers

Wavelength of the given wave is 8 cm and frequency is  37.5 *\(10^{8}\) Hz.

What is frequency?

The number of vibrations counted per second is called frequency. A wave is a group of vibrations that are referred to as energy. The bottom node is known as the crest, and the top node is known as the trough.

The frequency of an alternating current is the number of full cycles per second. The hertz, also known as Hz, is the accepted unit of frequency. The frequency of a current is 1 Hz if one cycle is completed per second; 60 cycles per second equals 60 Hz.

There are 8 waves so assume one wave is 1 cm so wavelength is 8 cm and frequency of wave = speed of light/ wavelength

frequency = \(3*10 ^{8} / .08\)

Frequency = 37.5 *\(10^{8}\) Hz

Wavelength of the given wave is 8 cm and frequency is  37.5 *\(10^{8}\) Hz.

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what is the amount of matter in an object is called?​

Answers

Answer:

mass

Explanation:

Answer: Mass is the amount of mass an object contains. Mass is measured using a scale. Volume is the amount of space matter takes up.

hope this help!! :) :)

Which of these does sound travel the fastest Through?A. steel SolidB. water LiquidC. Air gasD. Sound travels the same through all mediums

Answers

Speed of sound is maximum on solid.

Correct option.

A) steel Solid

Mass in motion is another way to say

Answers

Answer:

Momentum - Momentum is a measurement of mass in motion. Momentum is equal to the mass times the velocity of an object.

Momentum ........//:////

You have a friend who reports that he falls asleep easily around 11 PM but then awakens for about an hour most nights around two or 3 AM he seems near exhausted what would be the traditional exclamation for his problem how much the information contribute by anthropologists change this view? Give the anthropological view what recommendations would you make your friend?

Answers

It is highly recommended that this friend who is suffering from insomnia visits the doctor and eat foods rich in serotonin.

What is insomnia?

Insomnia is a medical condition in which an individual is unable to sleep or has short periods of interrupted sleep.

A friend who falls asleep easily and then has difficulty going to sleep is probably suffering from insomnia.

It is recommended that this friend who is suffering from insomnia visits the doctor and eat foods rich in serotonin.

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A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes the signs set for the initial position, initial velocity and the acceleration ?​

Answers

The sign set after the slowdown of the bicycle will be positive for the position,  negative for velocity, and negative for acceleration.

What is velocity?

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

According to Que, when a bicyclist moves in a straight line and slows down, then the velocity decrease as displacement is decreasing, and the acceleration also decreases only displacement increases.

Therefore, the sign set for the position is +ve, for velocity it is -ve, and for acceleration also -ve

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A biker slows down after traveling in a long, straight line at initial velocity v0. Which of the following the best \sdescribes the signs set for the initial position, initial velocity and the acceleration? Initial position Initial velocity Acceleration

A. Positive Negative Negative

B. Positive Positive Negative

C. Negative Positive Negative

D. Negative Negative Positive

E. Negative Negative Negative

A car of mass M
= 1200 kg
traveling at 65.0 km/hour
enters a banked turn covered with ice. The road is banked at an angle θ
, and there is no friction between the road and the car's tires as shown in image. Use g
= 9.80 m/s2
throughout this problem.


What is the radius r
of the turn if θ
= 20.0 ∘
(assuming the car continues in uniform circular motion around the turn)?

A car of mass M = 1200 kg traveling at 65.0 km/hour enters a banked turn covered with ice. The road is

Answers

A car with a mass of 1200 kg enters a banked turn covered with ice at a velocity of 65.0 km/h. The road is banked at an angle of 20°. The radius of the turn is found to be 91.9 m using the equation r = v²/gtanθ.

The banked turn covered with ice A banked turn is a turn or curve in which the vehicle follows a circular path. The car of mass M=1200kg traveling at 65.0 km/h enters a banked turn covered with ice. There is no friction between the road and the car's tires. Use g=9.80m/s² throughout this problem. The road is banked at an angle of θ=20°. We have to find the radius r of the turn. Assuming the car continues in uniform circular motion around the turn, the centripetal force required to keep the car moving in a circle is given by the equation:Centripetal force, Fc = mv²/r, where, m is the mass of the car, v is the velocity of the carand,r is the radius of the turn. Since the car is moving in uniform circular motion, we can equate the centripetal force to the gravitational force. This is because the gravitational force is acting downwards, towards the centre of the circle, which is also the direction in which the centripetal force is acting. Hence we can say that Fc = mg, where,m is the mass of the car and, g is the acceleration due to gravity.Substituting the above equations for Fc and mg, we getmv²/r = mgtanθMultiplying both sides by rm, we getv² = grtanθTherefore,r = v²/gtanθwhere,v is the velocity of the car and, g is the acceleration due to gravity.Substituting the given values, we getv = 65.0 km/hour = 18.1 m/sθ = 20.0°g = 9.80 m/s²Therefore,r = (18.1 m/s)² / (9.80 m/s² × tan 20.0°) = 91.9 mSummary: The banked turn is a turn or curve in which the vehicle follows a circular path. A car of mass M = 1200 kg traveling at 65.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ = 20.0 ∘. We have to find the radius r of the turn. Assuming the car continues in uniform circular motion around the turn, the radius r can be found by using the equation r = v²/gtanθ. Substituting the given values, the radius r is 91.9m.

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2. Samuel leaves the end of a 4.0-m-high diving board and strikes the
water 1.3 s later, 3.0 m beyond the end of the board. Considering the
diver as a particle, determine:
(a) His initial velocity,
(b) The maximum height reached;
(c) The velocity Vf
with which he enters the water.

Answers

Answer:

a) v = 4.9 m/s at 62° above the horizontal

b) h = 0.94 m above the board or 4.94 m above the water

c) v = 10 m/s at 77° below the horizontal

Explanation:

Assume UP and FOREWARD are positive and the diving board is the origin.

Ignore air resistance.

s = s₀ + v₀t + ½at²

In the vertical

-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)

vy₀ = 4.281 m/s

in the horizontal

3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)

vx₀ = 2.307... m/s

v = √(4.281² + 2.307²) = 4.863...

tanθ = 4.281 / 2.307

θ = 61.680...

v² = u² + 2as

s = (v² - u²) / 2a

h = (0² - 4.281²) / 2(-9.8) = 0.9350...

v² = 4.863² + 2(9.8)(4)

v = 10.1019...

cosθ = 2.307/10.1019

θ = 76.798

(a) The initial velocity of Samuel is 4.02 m/s

(b) The maximum height reached by Samuel is 0.55 m

(c)  The final velocity when he enters the water is 5.20 m/s

The given parameter:

the height of the board, h = 4 mtime to strike the water, t = 1.3 sthe horizontal distance traveled, x = 3.0 m

(a) The initial velocity of Samuel is calculated as;

\(h = v_o_y t + \frac{1}{2} gt^2\\\\\)

Assume downward motion to be in negative direction

The vertical component of the velocity is calculated as;

\(4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)\)

The horizontal component of the velocity is calculated as;

Assume forward motion to be in positive direction

\(x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s\)

The resultant of initial velocity is calculated as;

\(v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s\)

(b) The maximum height reached by Samuel is calculated as;

\(v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)\)

(c) The final velocity when he enters the water;

The height traveled before he hits the water, h = 0.55 m

\(v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s\)

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In the figure, a 32 cm length of conducting
wire that is free to move is held in place
between two thin conducting wires. All of the
wires are in a magnetic field. When a 6.0 A
current is in the wire, as shown in the figure,
the wire segment moves upward at a constant
velocity.
The acceleration of gravity is 9.81 m/s?.
a) Assuming the wire slides without friction
on the two vertical conductors and has a mass
of 0.13 kg, find the magnitude of the minimum
magnetic field that is required to move the
wire.
Answer in units of T. b) What is the direction?

In the figure, a 32 cm length of conductingwire that is free to move is held in placebetween two thin

Answers

Answer:

.66354 T

Explanation:

Use F=ILB

B =  \(\frac{F}{IL}\)

B = Magnetic field

F= force due to magnetic

I= current

L= length in meters

F = mg

Final formula:

B=\(\frac{mg}{IL}\)

B=\(\frac{(.13)(9.8)}{(6)(.32)}\)

B= .66354

ayo btw ion know how to find direction, my b G

The minimum magnetic field required to move the wire is 66354 T.

The direction of magnetic field is normal to the page outwards.

What is magnetic field?

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

Given parameter:

Current passing through the wire, I = 6.0 A.

Length of the wire ,L = 32 cm = 0.32 m.

Mass of the wire, m = 0.13 Kg.

Acceleration due to the gravity, g = 9.8 m/s².

We know that, force acting on a current caring wire due to magnetic field is,  F=ILB

Where,

B = Required magnetic field.

To find the minimum magnetic field that is required to move the

wire, force acting on a current caring wire due to magnetic field is equal to weight the wire, that is, mg.

Hence, we can write,

mg = ILB

⇒ B = mg/IL

= (0.13 * 9.8)/(6.0 * 0.32)

=0.66354 Tesla

Hence, the minimum magnetic field is 0.66354 Tesla.

b) By using Maxwell's right hand thumb Rule along current flow, the direction of magnetic field is  determined as normal to the page pointing outwards.

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If the gravitational force disappeared , Earth would break away from its orbit and continue travelling in a ..............line into space.

If the gravitational force disappeared , Earth would break away from its orbit and continue travelling

Answers

A straight line into space.

Without the sun’s gravitational force, earth would not continue its elliptical orbit around the sun. All of the planets would travel in a straight line away from the sun if not for its strong gravitational pull.

Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.

Answers

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

How do i determine the quantity of heat energy?

First, we shall list out the given parameters from the question. This is shown below:

Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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A car weighs 15,000 n and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road

Answers

From pressure definition,  the area of the car tires that are in contact with the road is 0.079 m

What is Pressure ?

Pressure can be defined as the ratio of force to area. It is measured in Pascal.

Given that a car weighs 15,000 N and its tires are I flared to a pressure of 190 kPa. How large is the area of the cars tires that are in contact with the road ?

From the definition of Pressure, P = F/A

Where

P = 190 KPaF = 15,000 NA = ?

190000 = 15000/A

A = 15000/190000

A = 0.079 m

A car will have 4 tires. The area of one in contact with the road will be

A = 0.079/4

A = 0.02 m

Therefore, the area of the car tire that is in contact with the road is 0.02 m

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94. The cart shown below moves across the table top as the block falls. What is the acceleration of the cart? Neglect friction and assume the following data: m1=2.0kg,m2=4.0kg,I=0.4kg-m2,r=20cm

94. The cart shown below moves across the table top as the block falls. What is the acceleration of the

Answers

Since the rope is parallel to the table, the tension in the rope is also equal to the force acting on the cart.  The acceleration of the cart will be obtained as 1.32 m/s².

What is the acceleration of the cart?

Since the rope is parallel to the table, the forces acting on the system are the tension in the rope (T) and the weight of the hanging block (m1g). Since the rope is parallel to the table, the tension in the rope is also equal to the force acting on the cart.

The acceleration of the system can be found using Newton's second law:

ΣF = ma

where ΣF is the net force on the system, m is the total mass of the system, and a is the acceleration of the system.

The net force on the system is given by:

ΣF = T - m₁g

Substituting the given values, we get:

ΣF = T - m₁g = ma

To solve for the acceleration, we need to find the tension in the rope (T). We can do this by considering the torque on the pulley. The torque on the pulley is equal to the product of the force and the radius of the pulley (τ = Fr). The torque due to the weight of the hanging block is equal to m1g * r, and the torque due to the tension in the rope is equal to T * r. Since the pulley is not accelerating, the net torque on the pulley must be zero:

Στ = m₁g * r - T * r = I * α

where I is the moment of inertia of the pulley and α is the angular acceleration of the pulley. Since the pulley is not slipping, the linear acceleration of the cart is equal to the angular acceleration of the pulley divided by the radius of the pulley (a = α * r).

Substituting for α and a, we get:

m₁g * r - T * r = I * a / r

Solving for T, we get:

T = (m₁g + I * a / r)

Substituting this expression for T into the equation ΣF = T - m₁g, we get:

ma = (m₁g + I * a / r) - m₁g

Simplifying, we get:

a = g * m₁ / (m₂ + I / r²)

Substituting the given values, we get:

a = (9.81 m/s²) * 2.0 kg / (4.0 kg + 0.4 kg-m² / (0.2 m)²) = 1.32 m/s²

Therefore, the acceleration of the cart is 1.32 m/s².

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A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole in the table as shown in the figure. Start by showing the free-body diagrams and force equations for each mass, and then derive an equation for the tangential speed of the puck. This will be an algebraic expression that includes the variables mentioned above.

Answers

The dangling mass will not move and the puck will keep rotating in its orbit, Therefore, V = √(mgR/M)  will be an algebraic expression that includes the variables mentioned above.

What  is centripetal force?

A centripetal force that causes a body to travel along a curved path. The centripetal force always acts orthogonally to the motion of the body and towards the fixed point of the path's instantaneous centre of curvature. Isaac Newton described it as "a force by which bodies are drawn or impelled, or in any way tend, towards a point as to a centre". Gravity is the centripetal force that causes astronomical orbits, according to Newtonian mechanics theory.

A common example of centripetal force is when a body moves at a constant speed along a circular path. The centripetal force is directed at right angles to the motion as well as along the radius of the circular path towards the centre.

Fc = mg

Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or

Fc = Mac

centripetal acceleration is related to the tangential velocity of the puck as

ac = V²/R

where R is the radius of the orbit. Then we have

Fc = M ac =M ω² R = M V² / R

and, thus

M V² / R = mg

and, solving for V, we get

V = √(mgR/M)

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A phase change is when a substance changes from one state of mind to nother because of the adding or removal of thermal energy

True

False

Answers

Answer:

true it all changes

Explanation:

________________________

match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only once. a blankpredicts that the strong, weak, and electromagnetic forces should become indistinguishable at high temperatures
1. A grand unified theory predicts that the strong, weak, and electromagnetic forces should become indistinguishable at high temperatures
2. The electroweak force is a single force that unifies the electromagnetic and weak forces.
3. Inflation was a dramatic expansion of the universe thought to have occurred when the universe was only a tiny fraction of a second old.
4. Olbers' paradox forces us to think about why the sky is dark at night.
5. Observations of the cosmic microwave background provide a way to test our theory of the Big Bang.
6. When a particle of ordinary matter meets its precise opposite particle of antimatter, the result is annihilation with complete conversion of mass into energy.

Answers

The correct matches for the given words are:

1. grand unified theory - predicts the strong, weak, and electromagnetic forces

2.electroweak force

3. Inflation

4. Olbers' paradox

5. cosmic microwave background

6. annihilation

What is electromagnetic force ?

Physical interactions between electrically charged particles are known as the electromagnetic force. It is the result of the interaction of all magnetic and electrical forces and operates between charged particles.

Both visible light and radiation in other wavebands that the human eye cannot see are produced by the electromagnetic field.

A faint glow of light known as the Cosmic Microwave Background radiation, or CMB for short, permeates the entire cosmos and falls on Earth with a remarkably consistent intensity from all directions.

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Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Which statement describes the way in which energy moves between a
system of reacting substances and the surroundings?
OA. The potential energy of the system and its surroundings
increases.
B. The thermal energy of the system and its surroundings increases.
C. Molecular collisions create energy that is then released into the
surroundings.
D. Molecular collisions transfer thermal energy between the system
and its surroundings.

Answers

The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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NO LINKS PLEASE

At what speed do a bicycle and its rider, with a combined mass of 90 kg
k
g
, have the same momentum as a 1500 kg
k
g
car traveling at 4.0 m/s
m
/
s
?

Answers

Answer:

2

Explanation:

In hiking, what fitness component is required of you

Answers

It’s strength, endurance and flexibility. Hope this helps

Does anybody know how to solve this? Thanks!!
The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0 , where v0=2.5m/s and x0=−5.0m . The polynomial relationship between position and time for the bowling ball is _______________.

exponential
inverse
linear
cubic
quadratic

Answers

The polynomial relationship between position and time for the bowling ball is linear.

What is a linear relationship between two variables?

A linear relationship between two variables is a term used to describe a straight-line relationship between the two variables.

Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

From the equation of linear relationship between two variable, the highest power of x is one.

The given equation for position and time;

x(t) = vot + xo

From this given equation, the highest power of t is one, hence it is called linear relationship.

Thus, the polynomial relationship between position and time for the bowling ball is linear.

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