What is it called when a skydiver is no longer accelerating downward?

Answer:

Elastic potential energy

Answer:

Elastic potential energy:  increases when you compress a spring.

Explanation:

The height of the given object is 35 feet tall.

From the given parameters:

The two legs of the right triangle = x and (x - 85)

The hypotenuse side, = 125

The length of the shadow is calculated by applying Pythagoras theorem as follows;

\(x ^2 + (x - 85)^2 = 125^2\\\\x^2 + x^2 -170x + 7225= 15625\\\\2x^2 - 170x -8,400 = 0\\\\2(x^2 -85x - 4,200) = 0\\\\x^2 -85x - 4,200 = 0\\\\\)

Factorize the equation as follows;

\(x^2 + (35x - 120x) - 4200= 0\\\\x^2 + 35x \ - 120 x - 4200 = 0\\\\x(x + 35) - 120(x + 35) = 0\\\\(x + 35) (x -120) = 0\\\\x = - 35 \ \ or \ 120\\\\\)

The length is always positive, thus, x = 120 ft

The height of the object is calculated as follows;

h = x - 85

h = 120 - 85

h = 35 ft

Thus, the height of the given object is 35 feet tall.

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Answer:

brain

Explanation:

Answer:

C. That the small portion of the space we can see is truly representative of all the rest of the universe that we cannot see.

Explanation:

The Cosmological Principle assumes that the small portion of the universe that we can see is representative of the entire universe, even though we can only directly observe a tiny fraction of it. It's an assumption used by Cosmologists to simplify their models of the universe.

Answer:

Maybe???

Explanation:

but how big is the paper?

but I think even the paper is super big, the ending result will still be too small to observe …

Complete Question:

an object on a number line moved from x = 12 m to x = 124 m and moved back to x = 98 m. the time interval for all the motion was 10 s. what was the average velocity of the object?

Answer:

v = 8.6 m/s

Explanation:

       \(v_{avg} =\frac{x_{f} -x_{o}}{t_{f} - t_{o} } (1)\)

       \(v_{avg} =\frac{x_{f} -x_{o}}{t_{f} - t_{o} } =\frac{98 m -12 m}{10.0 s - 0 s } = \frac{86m}{10.0s} = 8.6 m/s (2)\)

Answer:

The student knows that a chemical reaction has occurred because Liquids 3 and 4 have different properties than Liquids 1 and 2.

Explanation:

Answer:

any engli shʕಠ_ಠʔʕಠ_ಠʔʕಠ_ಠʔʕಠ_ಠʔʕಠ_ಠʔಠ﹏ಠ

Assuming no air resistance, the skydiver's velocity after 2.9 seconds would be 28.42 m/s.

Velocity is calculated using the equation:

where

v is the final velocity

u is the initial velocity (which we'll assume is 0 m/s for a skydiver jumping out of an airplane)

a is the acceleration due to gravity (which is approximately 9.8 m/s^2 near the Earth's surface), and

t is the time elapsed.

Using this equation, we can calculate the velocity of the skydiver after 2.9 seconds as follows:

v = 0 + (9.8 m/s^2)(2.9 s)

v = 28.42 m/s

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The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

If an object is lifted, work is done against gravitational force. The object gains energy.

Given are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.

The range of the projectile is given by R =  v²sin2θ / g

g = gravitational acceleration of Earth

If g = g(p) for planet , range  R =  v²sin2θ / g(p)..................(1)

The gravitational force of attraction = weight force

Gm² /d² = m g(p)

g(p) = Gm/d².........................(2)

For R = d/3, from equation (1), we have

d/3 =  v²sin2θ / g(p)

Plug the expression for g(p) , we get

v = √ [Gm/3dsin2θ ]

For velocity to be minimum, sin2θ =1

So, the minimum velocity will be

v = √ [Gm/3d]

Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

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Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.

A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.

The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.

As electron releases here, it is a Beta (β) decay.

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Answer:

6.15m for 12.3 seconds

Explanation:

The magnitude of the gravitational force on mass m  at distance x along the axis of a very thin ring when it is at position x>0  is 4GMm/4x^2-L^2.

Every body in the universe attracts every other body with a gravitational force that decreases with distance as 1/r2.  if two bodies of different masses have the same acceleration they must be feeling forces in the same ratio as their masses (so a body twice as massive feels twice the gravitational force), that is, the gravitational force of attraction a body feels must be proportional to its mass.

The gravitational field at any point P in space is defined as the gravitational force felt by a tiny unit mass placed at P.

This relation can be find out by using the formula of gravitational potential = GMm/r and further integrating on small dx length at x from the origin of the rod, we get,

U = GMm/L㏑2x-2/2x+2.

now differentiating with respect to dx, we get

F =  4GMm/4x^2-L^2.

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Answer:

The point of contraflexure (PoC) occurs where bending is zero and at the point of change between positive and negative (or between compression and tension). In a beam that is flexing (or bending), the point where there is zero bending moment is called the point of contraflexure.

Answer:

a) 1.19 x 10^7 N/C

b) 2 x 10^-12 N

Explanation:

field due to Cl on (9.0xE¡)(1.6x10-19 C) (1.5Å—10-9m) -6.4x10 N/C field due to Ca+3 ion, 2(90x10 (1.6x10-19c) ((4.5-1.5)Å—10-9 m)' magnitude of net field at given point without dielectric E E+E 6.4x108 +3.2x108-9.6x10 N/C magnitude of net field at given point with di electric K 80.4 the force on sodium ion at this point, F-Edq= (1.19å—107 N/C)(1.6å—10-19C)= 2.0Å—10-12 N

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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9.14 s long it will take a cyclist to bring a bicycle with an initial speed of 12.8 m/s to a complete stop.

Depending on whether an object is moving much faster, slower, or in a different direction, its speed may change. Examples of acceleration include a falling apple, the moon orbiting the earth and a car which has stopped at a stop sign.

Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

a = -1.4 m/s²

v\(_i\) = 12.8 m/s²

v\(_f\) = 0

Δt = ?

We use formula

a = v\(_f\) - v\(_i\)/t

-1.4 = 0 - 12.8/t

t = 9.14 s

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Answer:

The magnitude of the acceleration is \(a_r = 1.50 \ m/s^2\)

The direction is  \(\theta = 32.5 6^o\) north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  \(F_{sail} = (330 ) \ N \ north\)

   The force exerted by water is  \(F_{keel} = (210 ) \ N \ east\)

      The mass of the boat(+ crew) is  \(m_b = 260 \ kg\)

Now Force is mathematically represented as

      \(F = ma\)

Now the acceleration towards the north is mathematically represented as

      \(a_n = \frac{F_{sail}}{m_b}\)

substituting values

       \(a_n = \frac{330 }{260}\)

      \(a_n = 1.269 \ m/s^2\)

Now the acceleration towards the east is mathematically represented as

       \(a_e = \frac{F_{keel}}{m_b }\)

substituting values

      \(a_e = \frac{210}{260}\)

      \(a_e =0.808 \ m/s^2\)

The resultant acceleration is  

      \(a_r = \sqrt{a_e^2 + a_n^2}\)

substituting values

     \(a_r = \sqrt{(0.808)^2 + (1.269)^2}\)

      \(a_r = 1.50 \ m/s^2\)

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        \(tan \theta = \frac{a_e}{a_n}\)

       \(\theta = tan ^{-1} [\frac{a_e}{a_n } ]\)

substituting values

     \(\theta = tan ^{-1} [\frac{0.808}{1.269 } ]\)

    \(\theta = tan ^{-1} [0.636 ]\)

   \(\theta = 32.5 6^o\)

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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So the entire heating process from start to all the water boiled away can be broken down into two steps.

Step 1: heating the water from 30C to 100C.

Let's use this formula

Q1 = (mcΔT)w + (mcΔT)Al

Since ΔT is the same for aluminum and water in this step (they're both increasing from 30 to 100), we can factor ΔT out.

Q1 = ((mc)w + (mc)Al)*ΔT

Where,

Q1: heat required to heat the system from 30 to 100

(mc)w: mass (m), heat constant (c), and temperature change (ΔT) for water

(mc)Al: mass (m), heat constant (c), and temperature change (ΔT) for aluminum

ΔT: temperature change

For water:

m = 2.2 kg

c = 4186 J/kgC (this is a constant specific to water, you need to look this up in a reference table)

For aluminum:

m = 0.75 kg

c = 900 J/kgC (this is the heat constant for aluminum)

ΔT = 100-30 = 70 C

Now let's plug in the variables we know:

Q1 = (2.2*4186 + 0.75*900)*70 = 691894 J

Step 2: heating the boiling water enough to vaporize it all

Let's use this formula:

Q2 = (mVap)*(LVap)

Where,

Q2: heat required to boil all the water away

mVap: mass of the system after the water boils away, so just the mass of the empty pot

LVap: latent heat of vaporization of water (this is a constant for water that you need to look up)

mVap = 0.75 kg

LVap = 2256000 J/kg

Now let's plug in the variables we know:

Q2 = 0.75*2256000 = 1692000 J

So now that we have the heat required for both steps, we can simply add those to get the total heat required.

QTotal = Q1 + Q2 = 691894 + 1692000

QTotal = 2383894 J

^Answer for part A

Power is the rate at which heat is transferred. 550W = 550J/s.

At 550 J/s, we can find how long it takes for 2383894 J to transfer.

P = Q/t

Where,

P: power, Q: total heat, t: time required (in seconds)

550 = 2383894/t

t = 2383894/550

t = 4334.35 s = 72.24 min

^Answer for part B

The United States still makes use of the form of measure that includes the units: feet, miles, and gallons while others make use of yards, kilometers and liters

This refers to the classification that describes the nature of the information within the values assigned to variables.

Therefore, we can see that the United States still makes use of the form of measure that includes the units: feet, miles, and gallons while others make use of yards, kilometers and liters

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c. Sodium and potassium

Perspiration, water given off by the intact skin, either as vapor by simple evaporation from the epidermis or as sweat, a form of cooling in which liquid actively secreted from sweat glands evaporates from the body surface.

When our body is sweating sodium and potassium is lost from the body along with water.

In order to maintain the integrity of the cells in the body ,Sodium and potassium are very important.

Sweat is also known as perspiration.

So,

By maintaining  the proper cell functioning and cell vitality optimum level of sodium and potassium should be maintained in the body.

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Answer:

An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.

The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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Answer: \(1.64 m/s^{2}\) (3 sig figs)

              \(1.6 m/s^{2}\) (2 sig figs)

Explanation:

First we need to find the weight of the cat using F=ma (117.72 = 12 * 9.81)

Using 117.72 we can find the force of friction by doing F = μ * N (35.316 = 0.3 * 117.72)

After we find the friction force we simply subtract the friction force from the applied force (19.684 = 55 - 35.316)

Using 19.684 we can find the acceleration using F / m = a (19.684 / 12 = 1.64)

From there you reduce your answer to the number of sig figs, which I think is 2 unless otherwise specified.

Answer:

The frequency decreases

Explanation:

The frequency will decrease as the wavelength continues to increase.

Wavelength is the distance between successive crests or troughs on a wave motion.

Frequency is the number of waves that passes through a point per unit of time.

    it is expressed as;

                  f  = \(\frac{speed }{wavelength}\)

We can see that frequency is inversely proportional to wavelength.

As wavelength increases the frequency reduces.

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

316 Hz

Explanation:

As for Frequencies of Elements, Gold is said to have 316 Hz

Answer:

The frequency of gold is 316 Hz

Explanation:

Since ancient times, gold is high valued and in the middle ages gold was experienced from the masters of alchemy not only for becoming rich, but also for healing purposes, as from Paracelsus and others.