Answer:
the activity or condition of striving to gain or win something by defeating or establishing superiority over others.
Metals like potassium and sodium are kept in paroffin oil. Why?
Answer:
because they are high reactive to the air thats why we keep them in paroffin oil
How much energy is needed to convert 15.0 g of ice at -5.0 oC into water at 50.0 oC?
Using thermodynamics
\(\\ \sf\longmapsto Q=mc∆T\)
\(\\ \sf\longmapsto Q=0.015(328)(4184)\)
\(\\ \sf\longmapsto Q=20585.28J\)
Heat is transferred only when___________________.
Answer: the direction of decreasing temperature
What is the mass of an object with a density of 5.7 g/cm^3 and a volume of 48
cm^3? *
Answer:
273.6 g
Explanation:
mass =(density)(volume)
mass=(5.7g/cm^3 )(48 cm^3)
cancel out your cm^3 and your are left with grams
multiply (5.7g)(48)=273.6 g
The mass of an object with a density of 5.7 g/cm³ and a volume of 48 cm³ is 273.6 grams.
What is density?Density is defined as the degree to which a material is packed together.
It is also defined as a mass per unit volume of the substance.
Its SI unit is kilogram per cubic meter or gram per meter.
Density can be expressed as
Density = mass / volume
Mass = density x volume
As given, Density = 5.7 g/cm³
Volume = 48 cm³
So, Mass = 5.7 g/cm³ x 48 cm³
= 273.6 grams
Thus, the mass of an object with a density of 5.7 g/cm³ and a volume of 48 cm³ is 273.6 grams.
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Given the standard enthalpy changes for the following two reactions
Given the standard enthalpy changes for the following two reactions:
(1) 2C(s) + 2H2(g)C2H4(g)...... ΔH° = 52.3 kJ
(2) 2C(s) + 3H2(g)C2H6(g)......ΔH° = -84.7 kJ
what is the standard enthalpy change for the reaction:
(3) C2H4(g) + H2(g)C2H6(g)......ΔH° = ?
The standard enthalpy change for reaction (3) is 117.1 kJ.
The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.
To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.
First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):
C2H4(g)C2H6(g) ΔH° = -52.3 kJ
Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ
Now, we add the two modified equations together:
C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ
When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):
C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ
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A student is dissolving sugar in water to make candy. She notices that sugar lumps are forming at the bottom of the pan. What could she do to help more of the sugar dissolve?
1. Heat the solution
2. Cool the solution
3. Add more sugar to the pan
4. Take some water out the pan
The solutes in a solvent can be make more soluble by heating. Thus upon heating the sugar lumps forming at the bottom of the water can be easily dissolved.
What is solubility?Solubility of substance is the fraction of its concentration which dissolves in a solvent. Solubility is affected by several factors such as temperature, pressure, molecular weight, bond type etc.
Water is known as universal solvent because, it can dissolve almost all the inorganic and organic compounds. The hydroxide ions in water forms hydrogen bonds with compounds and easily dissolve them.
By providing thermal energy the intermolecular attraction of the solute molecules can be weekend and they easily forms bonds with the solvent molecules results in dissolution. Thus option 1 is correct.
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Which is a type of lipid?
A. Disaccharide
B. Triglyceride
C. Nucleotide
D. Enzyme
SUBMI
Answer:
B. triglyceride
Explanation:
Answer:
triglyceride becauseit is a fatty acid
The three states of matter can be arranged in the increasing order of interparticle forces as 1) gas > liquid >solid 2) solid >liquid > gas 3) liquid > gas > solid pls answer fast
Answer:
OPTION 2 SOLID>LIQUID>GAS
Explanation:
because the inter molecular forces are the strongest in the solid than in liquid and than in gas
describe the type of bonding in sodium metal
Metallic bonding in sodium
When sodium atoms come together, the electron in the 3s atomic orbital of one sodium atom shares space with the corresponding electron on a neighboring atom to form a molecular orbital - in much the same sort of way that a covalent bond is formed.
which of these is used to determine the age of an object? question 8 options: palynology taphonomy radiocarbon paleontology
Radiocarbon dating is used to determine the age of an object.
Radiocarbon dating is a method used to estimate the age of organic materials based on the decay of radioactive carbon-14 isotopes. This technique is widely employed in archaeology, geology, and other scientific fields. When living organisms, such as plants or animals, are alive, they maintain a ratio of carbon-14 to stable carbon-12 isotopes.
However, once they die, the carbon-14 begins to decay at a known rate. By measuring the remaining carbon-14 and comparing it to the initial ratio, scientists can calculate the time that has passed since the organism's death. This method is particularly useful for dating objects that are up to around 50,000 years old. Palynology is the study of pollen grains, taphonomy focuses on the process of decay and fossilization, and paleontology deals with the study of fossils but not specifically dating methods.
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If you forgot to add the primers to your pcr reaction, what would happen and why?.
Your experiment would not work because Taq polymerase needs a tiny bit of DNA to add bases to. Due to the lack of an enzyme that could add new nucleotide bases, your process would not succeed.
What would happen if the primers for your PCR reaction were left out?The primers are absolutely necessary for a PCR reaction to work. The RNA primers must anneal before the heat-resistant DNA polymerases may start replicating DNA. The DNA polymerase cannot work without the primers, and as a result, no product will be produced.
DNA polymerase requires a primer on which it may add the first nucleotide since it can only add a nucleotide onto an already-existing 3'-OH group. This prerequisite allows the researcher to identify a particular area of the template sequence that they want to amplify.
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(e)
Indigestion tablets can be made from magnesium oxide. The magnesium oxide
neutralises some of the hydrochloric acid in the stomach.
Complete the word equation for the reaction between magnesium oxide and
hydrochloric acid.
+
water.
hydrochloric acid
+
magnesium oxide
All the oxides and hydroxides of metals are basic in nature.
Magnesium oxide is also basic in nature and is a water insoluble base.
When a dilute acid reacts with a base it forms salt and water because the acidity and basicity of the acid and base respectively neutralise each other.This process is known as neutralisation reaction.
When MgO reacts with HCl it forms MgCl2 and water.
In equation form
MgO + 2HCl — MgCl² + H2O
What kind of reaction is this?
AB + CD -> AC + BD
Calculate ΔH for the reaction CO(g) + H2(g) + O2(g) → CO2(g) + H2O(g)
Given:
2 C(s) + O2(g) → 2 CO(g)... ∆H = -222 kJ
C(s) + O2(g) → CO2(g)... ∆H = -394 kJ
2 H2(g) + O2(g) → 2H2O(g)... ∆H = -484 kJ
The value of ΔH for the reaction CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g) is -1272 kJ.
To calculate the enthalpy change (ΔH) for the given reaction, we can use Hess's law, which states that the overall enthalpy change of a reaction is equal to the sum of the enthalpy changes of the individual reactions involved.
Given the enthalpy changes:
1. 2 C(s) + O₂(g) → 2 CO(g)... ∆H = -222 kJ
2. C(s) + O₂(g) → CO₂(g)... ∆H = -394 kJ
3. 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ
We need to manipulate these reactions to obtain the desired reaction:
1. Reverse reaction 2: CO₂(g) → C(s) + O₂(g)... ∆H = +394 kJ
2. Multiply reaction 2 by 2 to balance carbon atoms: 2 CO₂(g) → 2 C(s) + 2 O₂(g)... ∆H = -788 kJ
3. Leave reaction 3 unchanged: 2 H₂(g) + O₂(g) → 2 H₂O(g)... ∆H = -484 kJ
By adding reactions 2 and 3, we obtain the desired reaction:
CO(g) + H₂(g) + O₂(g) → CO₂(g) + H₂O(g)... ∆H = -788 kJ + (-484 kJ) = -1272 kJ
Therefore, the value of ΔH for the given reaction is -1272 kJ.
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what is atomic structure and atomic configuration?
meaningful answer
will be marked as brainliest!
In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below
Explanation:
hope it help u
a hydrogen flowmeter reads 8.7 nlpm. calculate the molar flow rate.
The molar flow rate of hydrogen is approximately 0.0003884 mol/s.
To calculate the molar flow rate, we need to convert the volume flow rate from nanoliters per minute (nlpm) to moles per second (mol/s). Here's how you can do it:
Given:
Volume flow rate = 8.7 nlpm
Step 1: Convert volume flow rate to liters per second:
Volume flow rate (L/s) = Volume flow rate (nlpm) / 1000
Volume flow rate (L/s) = 8.7 nlpm / 1000 = 0.0087 L/s
Step 2: Convert volume flow rate to moles per second using the ideal gas law:
Molar flow rate (mol/s) = Volume flow rate (L/s) / molar volume (L/mol)
The molar volume depends on the conditions of temperature and pressure. Let's assume standard temperature and pressure (STP) conditions:
Standard temperature (T) = 273.15 K
Standard pressure (P) = 1 atm
At STP, the molar volume of an ideal gas is approximately 22.4 L/mol.
Molar flow rate (mol/s) = 0.0087 L/s / 22.4 L/mol
Molar flow rate (mol/s) ≈ 0.0003884 mol/s
Therefore, the molar flow rate of hydrogen is approximately 0.0003884 mol/s.
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I have to figure out the molar enthalpy kj/mol of the combustion of methanol from the data
• given that volume = 230ml ,therefore mass of water = 230g
,• ∆T = Tfinal-Tinitial =30.5-22.9 = 7.6°C
,• Specific heat capacity of water , C= 4.184J/°C*g
• Therefore , q = mass* C * ∆T
= 230 * 4.184 * 7.6
=7313.6 J /1000
q= 7.314KJ
2. Calculate Molar enthalpy using ∆H = q/n• given : mass of methanol burned = Mass F-Mass initial
=(2.51-1.65) = 0.86 g
• So ,moles of methanol , n = mass methanol/Mol. mass methanol
= 0.86g/32.04g/mol
=0.027 moles
• Finally , ∆H = q/n
= 7.314KJ / 0.027mol
=270.85KJ/mol
• However, this is an exorthemic reaction, heat is lost through combustion, our molar enthalpy should be negative.
This means that ∆H= -270.85KJ/molIs it alr to have a rebound??
Answer:
Next time you're just recently out of a serious relationship, and you're craving some sort of intimacy and comfort, feel confident that a rebound might actually be a good thing as long as it's an upgrade, either physically, emotionally, a fun date, or even just finding a way to shift your mentality toward viewing. so what im saying is if your happy in that relationship stay in it and if he or she becomes a meany leave it its not goo for your health
Which lists the substances from least to most acidic?
a. ammonia, blood, milk, orange juice
b. orange juice, milk, blood, ammonia
c. ammonia, milk, blood, orange juice
d. orange juice, blood, milk, ammonia
.The cell membrane acts like a filter allowing necessary materials in and waste out, while keeping the organelles and cytoplasm in. This means that a cell membrane is selectively
Answer: Permeable
Explanation:
The cell membrane is the outermost covering around the animal cells but it is also surrounded by the cell wall in the case of the plant cells. The cell membrane plays an important role in the cell that is it allows the entry of only certain substances like ions, molecules, atoms within the cell and only allows the exist of certain substances out of the cell. This is the selective permeability of the membrane. This process occurs through osmosis in which the desired molecules move from higher to lower concentration. Also it helps in maintaining the balance of nutrients and water within the cell. This helps in getting rid of the waste outside the cell. It provides the protection to the organelles and cytoplasm in the cell against the external injury caused by the external stressor outside the cell like water, pressure, pathogen, and others.
Draw Lewis structure(s) showing all possible equivalent resonance forms for the nitryl chloride molecule (NO2Cl Draw one structure per sketcher box, and separate any added sketcher boxes with the symbol. Do NOT show any n charges in your drawings. Do not draw double bonds to oxygen unless they are needed for the central atom to obey the octet rule.
The nitryl chloride molecule (NO₂Cl) consists of a central nitrogen atom bonded to two oxygen atoms and a chlorine atom, with the double bond delocalized between one oxygen and the nitrogen atom in resonance. The Lewis structure is given below.
The nitryl chloride molecule (NO₂Cl) can exhibit resonance, resulting in multiple equivalent resonance structures. Here are the possible resonance forms for NO₂Cl:
Resonance Form 1:
Cl
|
O = N - O
Resonance Form 2:
Cl
|
O - N = O
These two resonance structures represent the different arrangements of the double bond between the nitrogen and oxygen atoms. The actual structure of nitryl chloride is a hybrid of these resonance forms, with the double bond delocalized or spread out over both nitrogen and oxygen atoms.
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in order for a titration to be effective, all of the following must be true of the reaction, except a. reaction must be stoichiometric b. reaction must produce a precipitate c. reaction must be quantitative d. reaction must be rapid
In order for a titration to be effective, the reaction must produce a precipitate. The correct answer is option B, "reaction must produce a precipitate."
For a titration to be effective, the reaction must be stoichiometric, quantitative, and rapid. A stoichiometric reaction is one in which the amount of reactants is proportional to the amount of products.
A quantitative reaction is one in which all the reactants are consumed, leaving no excess. A rapid reaction is one that occurs quickly and does not take a long time to complete.
However, a reaction producing a precipitate is not necessary for the titration to be effective. Hence option B is correct.
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What is variable????
Answer:
Basically, a variable is any factor that can be controlled, changed, or measured in an experiment. It's anything that can be changed in the experiment.
Explanation:
Scientific experiments have several types of variables. The independent and dependent variables are the ones usually plotted on a chart or graph, but there are other types of variables you may encounter. The presence/absence of the chemical is the independent variable. The health of the (ex:)rat (whether it lives and can reproduce) is the dependent variable.
Answer:
Variable are all the quantities that could change in an experiment.Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 63.8 g aluminum nitrite and 52.5 g ammonium chloride react completely?
Taking into account definition of reaction stoichiometry, after 63.8 g aluminum nitrite and 52.5 g ammonium chloride react completely, there are present a mass of 43.66 grams of AlCl₃, 27.50 grams of N₂, 35.36 grams of H₂O and 9.78 grams of Al(NO₂)₃.
Reaction stoichiometryIn first place, the balanced reaction is:
Al(NO₂)₃(aq) + 3 NH₄Cl(aq) → AlCl₃(aq) + 3 N₂(g) + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Al(NO₂)₃: 1 moleNH₄Cl: 3 molesAlCl₃: 1 molesN₂: 3 molesH₂O: 6 molesThe molar mass of the compounds is:
Al(NO₂)₃: 165 g/moleNH₄Cl: 53.45 g/moleAlCl₃: 133.35 g/moleN₂: 28 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Al(NO₂)₃: 1 mole ×165 g/mole= 165 gramsNH₄Cl: 3 moles ×53.45 g/mole= 160.35 gramsAlCl₃: 1 mole ×133.35 g/mole= 133.35 gramsN₂: 3 moles ×28 g/mole= 84 gramsH₂O: 6 moles ×18 g/mole= 108 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 165 grams of Al(NO₂)₃ reacts with 160.35 grams of NH₄Cl, 63.8 grams of Al(NO₂)₃ reacts with how much mass of NH₄Cl?
mass of NH₄Cl= (63.8 grams of Al(NO₂)₃× 160.35 grams of NH₄Cl)÷165 grams of Al(NO₂)₃
mass of NH₄Cl= 62.002 grams
But 62.002 grams of NH₄Cl are not available, 52.5 grams are available. Since you have less mass than you need to react with 63.8 grams of Al(NO₂)₃, NH₄Cl will be the limiting reagent.
Mass of each product formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 160.35 grams of NH₄Cl form 133.35 grams of AlCl₃, 52.5 grams of NH₄Cl form how much mass of AlCl₃?
mass of AlCl₃= (52.5 grams of NH₄Cl× 133.35 grams of AlCl₃)÷ 160.35 grams of NH₄Cl
mass of AlCl₃= 43.66 grams
The following rule of three can be applied: if by reaction stoichiometry 160.35 grams of NH₄Cl form 84 grams of N₂, 52.5 grams of NH₄Cl form how much mass of N₂?
mass of N₂= (52.5 grams of NH₄Cl× 84 grams of N₂)÷ 160.35 grams of NH₄Cl
mass of N₂= 27.50 grams
The following rule of three can be applied: if by reaction stoichiometry 160.35 grams of NH₄Cl form 108 grams of H₂O, 52.5 grams of NH₄Cl form how much mass of H₂O?
mass of H₂O= (52.5 grams of NH₄Cl× 108 grams of H₂O)÷ 160.35 grams of NH₄Cl
mass of H₂O= 35.36 grams
Mass of Al(NO₂)₃ in excessThe following rule of three can be applied: if by stoichiometry 160.35 grams of NH₄Cl reacts with 165 grams of Al(NO₂)₃, 52.5 grams of NH₄Cl reacts with how much mass of Al(NO₂)₃?
mass of Al(NO₂)₃= (52.5 grams of NH₄Cl× 165 grams of Al(NO₂)₃)÷160.35 grams of NH₄Cl
mass of Al(NO₂)₃= 54.02 grams
If 63.8 grams of the compound are present, then the excess mass can be calculated as:
excess mass= 63.8 grams -54.02 grams
excess mass= 9.78 grams
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Pls this is very important for me. Whoever answer this whole I'll mark them as brainliest..... The question is many cars have catalytic converters in their exhaust systems. In a catalytic converter most of the Co and No are formed in a car engine is changed into less harmful products. Identify these products and state the metal catalyst used.
The most commonly used metal catalyst in catalytic converters is platinum (Pt) among the other possible metals that could also be used in this regard.
What is a catalytic inverter?
Through a sequence of chemical reactions, carbon monoxide (CO) and nitrogen oxides (NOx) produced by an automobile engine are transformed into less hazardous compounds in a catalytic converter.
We know that the catalytic inverter can be able to convert carbon monoxide into carbon dioxide and can also be able to convert nitrogen monoxide to nitrogen dioxide.
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which statement is true regarding the conversion of arginine to ornithine in the urea cycle? a. the enzyme catalyzing this reaction is a hydrolase. b. this enzyme-catalyzed reaction occurs in the matrix. c. one of the products of this reaction is fumarate. d. the enzyme catalyzing this reaction is a ligase. e. the enzyme catalyzing this reaction is a hydrolase, and the reaction occurs in a matrix.
This reaction is catalyzed by an enzyme called a hydrolase, and it takes place in a matrix.
What enzyme does arginine's transformation into urea and ornithine?By converting l-arginine to l-ornithine and urea, the ureohydrolase arginase, an enzyme that contains manganese, catalyzes the last stage in the urea cycle to get rid of harmful ammonia.
Why is arginine necessary for the urea cycle?It is changed by the enzyme arginase into L-ornithine, a building block for polyamines and urea, both of which are necessary for the urea cycle. Arg is a precursor of creatine, which is responsible for Arg catabolism, the production of agmatine, and the synthesis of proteins. Creatine is crucial for the energy metabolism of muscle, neuron, and testicles.
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For the reaction
? P4+? S8 - ? P4S10
what is the maximum amount of P4S10 which
could be formed from 15.29 g of P4 and 17.66 g
of Sg?
Answer in units of g.
Please hurry it’s due today and include the steps if you can
Which of the following statements below is TRUE?
Question 18 options:
Never reach across an open flame.
Never heat closed or stoppered glassware.
Never put a glass thermometer in a flame.
All of the above.
Is spoiling milk chemical change?
No, spoiling milk is not a chemical change. Spoiling milk is a physical change, which is a change in the state or appearance of a substance without changing its chemical composition.
When milk spoils, it is still composed of the same molecules, but its physical properties (such as taste, smell, and texture) have changed. Spoiling milk is caused by the growth of microorganisms, such as bacteria, which break down milk proteins and fats, causing changes in the milk's appearance, taste, and smell. In the case of milk, spoiling is the result of the growth of bacteria, which is a physical change. A physical change is a change in the physical state or appearance of a substance without any change in the chemical composition or identity of the substance.
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what is responsible for changes in the state of matter?
and how are
the molecules of a liquid different from that of a solid? PKSS HELOOOÑLPPPP
Answer:
Temperature and pressure are the two factors which are responsible for change in state of matter.
Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.
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