What is a hypothesis? O a part of the scientific method that is not necessary a specific and testable question O the variables I observe during the experiment HELP HELP PLS PLS PLS HELP NoW NowWWwWw I'll mark u BRAINLIEST!!!!!!!!​

The ozone molecule is composed of three atoms of the oxygen.

The ozone molecule (O3) is a triatomic molecule, meaning that it consists of three atoms. It is composed of three oxygen atoms, which are held together by covalent bonds.

The structure of the ozone molecule can be described as a bent or V-shaped molecule, with the three oxygen atoms arranged in a triangular fashion. The central oxygen atom is bonded to two other oxygen atoms, which are located above and below it, with bond angles of approximately 117 degrees.

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Answer:

O=C=O.

Four nonbonding electron pairs.

Explanation:

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In this case, as you can see on the attached picture, there are two double bonds between the central carbon atom and those two oxygen atoms because each oxygen shares two electrons to the central carbon for them to attain the octet. Moreover, the enclosed dots represent the nonbonding electron pairs, which are four in total. It is importante to notice that carbon dioxide (O=C=O) has a complete octet whereas carbon monoxide (C=O) does has an incomplete octet for C.

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The compound that is formed by the combination of the boron and oxygen is boron oxide.

The term periodic table has to do with the arrangement of the elements in such a way that they can be easily studied. We know that the compound boron oxide.

The boron atom is a member of group three while oxygen is a member of group six. We know that the compound is ionic thus the boron ion would combine with the oxygen ion in order to form the boron oxide. the boron is positive and oxygen is negative.

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Answer:

• SCl6 [ Sulphur hexachloride ]

• Na2O [ Sodium oxide ]

Or:

• Na2O2 [ Sodium peroxide ]

Explanation:

→ Ionic bonding or electrovalent bonding is the type of bonding between a metal and a non metal, where a metal loses its Outermost electrons to the non metal in order to gain stability.

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The maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).

Maximum distance between the balls:

The maximum distance between the two white balls will be achieved when they are placed at opposite ends of a diameter of the circular region.

In this case, the distance between them will be equal to the diameter of the circle, which is 2R.

Maximum angle between the balls:

To find the maximum angle between the two balls, imagine the center of the circle as the vertex of the angle, and the positions of the two balls as the endpoints of the angle's two sides.

Since the balls are located at opposite ends of a diameter, the angle formed will be a straight angle, which is 180 degrees (or π radians).

So, the maximum distance between the two white balls is 2R, and the maximum angle between them is 180 degrees (or π radians).

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Two white balls, A and B, are placed on a flat surface inside a circular region of radius R. What is the maximum distance and maximum angle between the balls that can be achieved

Answer:

c.CH4 < NH3 because the NH bond is more polar than the CH bond.

Explanation:

Answer:

B

Explanation:

3.2 × 10⁴

= 3.2 × 10000

= 32000 m

Phosphatidylserine is a type of phospholipid that is mainly found in cell membranes. Its structure is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule.

The fatty acid chains are hydrophobic, meaning they repel water, while the phosphate group and serine molecule are hydrophilic, meaning they attract water.

The glycerol molecule acts as a bridge that connects the two fatty acid chains to the phosphate group and serine molecule.
The structure of phosphatidylserine is important for its function in the cell membrane.

Because of the hydrophobic and hydrophilic components of its structure, phosphatidylserine is able to form a lipid bilayer, which is a barrier that separates the inside of the cell from the outside environment.

The hydrophilic heads of the phosphatidylserine molecules face outward and interact with water, while the hydrophobic tails face inward and repel water.
Phosphatidylserine also plays a role in cell signaling and apoptosis, which is programmed cell death.

It acts as a signaling molecule by binding to proteins that are involved in cellular pathways.

In addition, phosphatidylserine is translocated to the outer leaflet of the cell membrane during apoptosis, which signals to immune cells that the cell is ready to be removed.
In conclusion, the structure of phosphatidylserine is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule. Its hydrophobic and hydrophilic components allow it to form a lipid bilayer in cell membranes, and it also plays a role in cell signaling and apoptosis.

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Answer:

56.96 grams

Explanation:

To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.

The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.

The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:

Molar mass of O2 = 2 x atomic mass of O

= 2 x 16.00 g/mol

= 32.00 g/mol

Therefore, the mass of 1.78 moles of O2 is:

Mass = number of moles × molar mass

= 1.78 mol × 32.00 g/mol

= 56.96 g

So the mass of 1.78 moles of O2 is 56.96 grams.

Answer:

SiO2

Explanation:

Si + O2 → SiO2

The expected lattice energies, in increasing order, are MgO> MgBr2> KBr.  

The ranking is related that the lattice energy being directly proportional to the strength of the ionic bond. If the bond is strong, the lattice energy would be high.

If the intermolecular force is strong, then the energy requires to break the bond would be greater. Thus, the lattice energy would be high.

MgO has the lowest lattice energy because it is the smallest and has the weakest attractive force between the ions. MgBr2 has a slightly higher lattice energy because the bromine ions are larger and have a stronger attractive force than the oxygen ions. KBr has the highest lattice energy because the potassium ions are larger than the bromine ions and have a stronger attractive force.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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The equilibrium expression can be written as follows:

K = [CaCO₃] × [H₂]⁴

------------------

[CaO] × [CH₄] × [H₂O]²

In this equilibrium expression, the square brackets represent the concentrations of the species involved in the reaction, and the coefficients of the balanced equation indicate the stoichiometric coefficients of the corresponding species.

The concentration of a pure solid (CaCO₃ in this case) is not included in the equilibrium expression, as it remains constant throughout the reaction.

The equilibrium constant (K) represents the ratio of the product concentrations to the reactant concentrations at equilibrium, each raised to the power of their respective stoichiometric coefficients. The specific values of these concentrations depend on the initial conditions, and K remains constant as long as the temperature is unchanged.

It is important to note that the equilibrium constant expression is written based on the balanced chemical equation. The stoichiometric coefficients determine the relationship between the concentrations of reactants and products, allowing us to express the equilibrium state quantitatively using the equilibrium expression.

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Answer: 2.34

Explanation:

pH= -log (H+)

H+ is the acid's M

pH= -log (0.0046) =2.34

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The stage that this most accurately describes while using the PCR is the initiation of DNA synthesis, also known as the denaturation stage.

In the denaturation stage of Polymerase Chain Reaction (PCR), the double-stranded DNA template is heated to a high temperature to separate the two complementary strands and create single-stranded DNA. The denaturation stage is the first step in the PCR cycle.

In this stage, the heat-stable DNA polymerase denatures the DNA and the primers anneal to the complementary single-stranded template. This marks the beginning of the extension stage, where the DNA polymerase synthesizes new complementary strands along the template DNA.

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The rate law show how concentration changes affect the rate of reaction. Correct answer is B.

The concentration of our reactants can affect how quickly a reaction proceeds. The rate law of a chemical reaction is an equation that outlines the connection between the concentrations of the reactants and the reaction rate.

The reaction rate is constant and independent of the N 2 O concentration, according to the rate law. In other words, the reaction is both zeroth order overall and zeroth order in N 2 O. C Doubling the concentration of N 2 O will have no impact on the reaction rate since the reaction rate is independent of the concentration.

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Answer:

Mitochondria is the powerhouse of the cell, but don't let this distract you from the fact that Mr. Krabs sold SpongeBob's soul for 62 cents

Answer:

mitochondria

Explanation:

False. J J. Thompson was not the one who experimented with alpha particles striking thin metal foils which led to postulate the nuclear atom.

It was actually Ernest Rutherford who conducted the famous gold foil experiment that led to the discovery of the nuclear atom. Rutherford and his colleagues bombarded a thin gold foil with alpha particles and observed that most of the particles passed straight through the foil, but a small number were deflected at large angles. This led Rutherford to conclude that the atom must have a small, dense, positively charged nucleus surrounded by mostly empty space.

J.J. Thomson, on the other hand, is credited with the discovery of the electron and the development of the "plum pudding" model of the atom, which was later replaced by Rutherford's nuclear model.

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The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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Answer:The majority of chemical processes are reactions that occur in solution. Important industrial processes often utilize solution chemistry. "Life" is the sum of a series of complex processes occurring in solution. Air, tap water, tincture of iodine, beverages, and household ammonia are common examples of solutions.

A solution is a homogenous mixture of substances with variable composition. The substance present in the major proportion is called the solvent, whereas the substance present in the minor proportion is called the solute. It is possible to have solutions composed of several solutes. The process of a solute dissolving in a solute is called dissolution.

Explanation:

The formula of the hydrate is NiCl2·4.27H2O. The name of the hydrate is nickel (II) chloride tetrahydrate.

To determine the formula and name of the hydrate, we need to first find the value of "x" in the formula NiCl2·xH2O using the given information.

Mass of water = Initial mass - Mass of anhydrous salt

Mass of water = 0.470 g - 0.256 g

Mass of water = 0.214 g

The molar mass of H2O is 18.015 g/mol, so the number of moles of water present in the hydrated salt can be calculated as:

Moles of water = Mass of water / Molar mass of water

Moles of water = 0.214 g / 18.015 g/mol

Moles of water = 0.0119 mol

The number of moles of anhydrous salt can be calculated by dividing its mass by its molar mass:

Moles of anhydrous salt = Mass of anhydrous salt / Molar mass of anhydrous salt

Moles of anhydrous salt = 0.256 g / (Ni: 58.69 g/mol + 2Cl: 2 x 35.45 g/mol)

Moles of anhydrous salt = 0.00279 mol

The ratio of moles of water to moles of anhydrous salt is equal to "x" in the formula NiCl2·xH2O:

Moles of water / Moles of anhydrous salt = x

0.0119 mol / 0.00279 mol = x

x ≈ 4.27

Therefore, the formula of the hydrate is NiCl2·4.27H2O. The name of the hydrate is nickel (II) chloride tetrahydrate.

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Answer:

The reaction CO₂ + H₂O → C₆H₁₂O₆ + O₂ is exothermic because it releases energy. The energy is released because the bonds in the products (C₆H₁₂O₆ and O₂) are stronger than the bonds in the reactants (CO₂ and H₂O). Specifically, the reaction releases energy because the bonds between carbon and oxygen in CO₂ and the bonds between hydrogen and oxygen in H₂O are weaker than the bonds between carbon, hydrogen, and oxygen in C₆H₁₂O₆ and the bonds between oxygen atoms in O₂

A solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

We must first convert the amount of nitrate(V) ions in drinking water to moles per litre since the threshold concentration over which "Blue-Baby" Syndrome might manifest is 0.05 mg/cm3.

It is necessary to know the molar mass of nitrate(V) ions in order to convert from mg/cm3 to moles per litre (NO3-).

The formula below can be used to determine NO3-'s molar mass:

N: 14.01 g/mol for the atomic mass

O: 16.00 g/mol is the atomic mass (3 oxygen atoms in NO3-)

NO3-'s total molar mass is equal to 14.01 + 16.00 x 3 = 62.01 g/mol.

Let's now translate the specified concentration from mg/cm3 to moles/liter (M).

As 1 g = 1000 mg, 1 mg/cm3 is 0.001 g/cm3.

1 cm3 = 0.001 g/mL multiplied by 0.001 g/cm3

1 L/1000 mL x 0.001 g/mL = 0.001 g/L

We must change the grams into moles using the molar mass in order to get the molarity:

1.61 × 10-5 mol/L = 0.001 g/L / 62.01 g/mol

As a result, a solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.

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