what is 97 reduced by n is 5 ? write the sentence as an equation

Answer:

A is 4

B is 8

C is 4

D is 2

Step-by-step explanation:

Can't explain

Answer:

A: (1,4) B: (5,8) C: (5,4) D: (4,2)

Step-by-step explanation:

I'm so sorry if I get this wrong, I worked on this 1 month ago in class but in pretty sure i'm right

Answer:

They won 35% of their games.

Step-by-step explanation:

I just searched it up and got this. Hope it helps.

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

The formula for slope according to first principle is :

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{f(x + h) - f(x)}{h} \]\)

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{ log(x + h) - log(x)}{h} \]\)

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{ log( \frac{x + h}{x} ) }{h} \]\)

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{ log( \frac{ h}{x} + 1 ) }{h} \]\)

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{ log( \frac{ h}{x} + 1 ) }{ \frac{h}{x} \times x} \]\)

\( \qquad \sf  \dashrightarrow \: \[ \displaystyle\lim_{x\to0} \: \: \sf \frac{1}{x} \bigg(\frac{ log_{e} ( \frac{ h}{x} + 1 ) }{ \frac{h}{x} \times log_{e}(10) } \] \bigg)\)

\( \qquad \sf  \dashrightarrow \: \[ \dfrac{1}{x \: log_{e}(10) } \displaystyle\lim_{x\to0} \: \: \sf \bigg(\frac{ log_{e} ( \frac{ h}{x} + 1 ) }{ \frac{h}{x} } \] \bigg)\)

\( \qquad \sf  \dashrightarrow \: \[ \dfrac{1}{x \: log_{e}(10) } \)

Now, the best estimate of slope is at x = 20 :

\( \qquad \sf  \dashrightarrow \: \[ \dfrac{1}{20\times 2.303} \)

\( \qquad \sf  \dashrightarrow \: \[ \dfrac{1}{46.06} \)

\( \qquad \sf  \dashrightarrow \: \approx0.0217\)

Answer:

tan∅ = -1517/817

Step-by-step explanation:

tan∅ = sin∅/cos∅

Answer:

Step-by-step explanation:

The total centimeters that the plants grew in all was 200 centimeters or 2.00 centimeters when written as a decimal.

Centimetres (cm) is a unit of length in the metric system, equal to one-hundredth of a metre. It is commonly used in everyday life, for example when measuring the height of a person or the size of a room. Centimetres are also used in scientific and engineering measurements, such as the size of an object or the distance between two points. Centimetres are divided into millimetres, which are one-thousandth of a metre.

This can be written as a decimal as 2.00 centimeters.

To determine the total centimeters, we simply add the individual centimeter measurements of the two plants.

Daysha's plant grew 100 centimeters and India's plant grew 100 centimeters.

Therefore, the total centimeters that the plants grew in all was 200 centimeters, or 2.00 centimeters when written as a decimal.

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Answer:

The anti-derivative of f(x) will be:

\(\int \:10x^4+12.5dx=2x^5+12.5x+C\)

Step-by-step explanation:

Given the function

\(\:f\left(x\right)=10x^4\:+\:12.5\)

Taking the anti-derivative of f(x)

\(\int \left(10x^4\:+\:12.5\right)\:dx\:\)

\(\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\)

\(\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx\)

Solving

\(\int 10x^4dx\)

\(\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\)

\(=10\cdot \int \:x^4dx\)

\(\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\)

\(=2x^5\)

similarly,

\(\int 12.5dx\)

\(\mathrm{Integral\:of\:a\:constant}:\quad \int adx=ax\)

\(=12.5x\)

so substituting these values

\(\int \left(10x^4\:+\:12.5\right)\:dx\:=\int \:10x^4dx+\int \:12.5dx\)

                                \(=2x^5+12.5x\)

                               \(=2x^5+12.5x+C\)   ∵ Add constant to the solution

Therefore, the anti-derivative of f(x) will be:

\(\int \:10x^4+12.5dx=2x^5+12.5x+C\)

Answer:  the correct answer is D

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

The expression (-9x)^4 can be represented as -6561x^3 without using exponents.

To express the expression (-9x)^4 without using exponents, we can expand it by multiplying the base (-9x) four times using the multiplication property.

(-9x)^4 = (-9x) * (-9x) * (-9x) * (-9x)

To simplify this expression, we can multiply the terms together, taking care to apply the rules of multiplication:

(-9x) * (-9x) = (-9 * -9) * (x * x) = 81 * x^2 = 81x^2

So, by substituting this result back into the original expression, we get:

(-9x)^4 = 81x^2 * (-9x) = -6561 x^3

Therefore, the expression (-9x)^4 can be represented as -6561x^3 without using exponents.

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Answer:

Difficulties regarding the emotions of your body.

Step-by-step explanation:

Difficulties regarding the emotions of your body.

We can see that the line is horizontal so its slope is 0.

Answer:

1.961x^2 - 8.647.

Step-by-step explanation:

I'm assuming the area of the triangle is 4.05 unit^2.

RQ is perpendicular to the x-axis.

The length of RQ = 9 so the area of the triangle

= 1/2 *9 * PQ = 4.05

PQ = 4.05 / 4.5 = 0.9.

So the value of x1 = 3 - 0.9 = 2.2.

The vertex is on the y-axis so the equation will be of the form ax^2 + c = 0.

So, as P (2.1, 0) and  R(3, 9) are points on the parabola we have the system:

(2.1)^2a  + c = 0

(3)^2a + c = 9

4.41 a + c = 0

9a + c = 9     Subtract:

4.59a = 9

a = 1.961

and c = -4.41* 1.961 = - 8.647,

Answer:

x = 7

y = 5

Step-by-step explanation:

We can do this algebraically using substation or elimination or we could do this graphically.

Answer:

x=7

y=5

Step-by-step explanation:

Answer:

x = 145

Step-by-step explanation:

x and 35° lie on a straight line and are supplementary angles , sum to 180°

x + 35 = 180 ( subtract 35 from both sides )

x = 145

$3,244.21 can be withdrawn each month for 25 years, assuming an interest rate of 7% and a starting principal of $500,000.

PV = PMT × [1 - (1 + r)⁻ⁿ] / r

where:

PV is the present value of the annuity

PMT is the payment amount per period

r is the interest rate per period

n is the total number of periods

In this case, we want to withdraw a fixed amount each month for 25 years, which represents 12 ×25 = 300 periods.

The interest rate per period is 7% / 12 = 0.5833%.

Let's assume that you want to withdraw a fixed amount each month, and you want the withdrawals to last for 25 years. To calculate the amount you can withdraw each month,

PV = PMT × [1 - (1 + r)⁻ⁿ] / r

500,000 = PMT × [1 - (1 + 0.005833)⁻³⁰⁰] / 0.005833

Solving for PMT, we get:

PMT = PV × r / [1 - (1 + r)⁻ⁿ]

PMT = 500,000 × 0.005833 / [1 - (1 + 0.005833)⁻³⁰⁰]

PMT = $3,244.21

Therefore, you can withdraw $3,244.21 each month for 25 years, assuming an interest rate of 7% and a starting principal of $500,000.

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Answer:

Thanks

Step-by-step explanation:

Thanks

Answer:

9:12

Step-by-step explanation:

Answer:

the answer is Less than "<"

Step-by-step explanation:

when you reduce both ratios you get 6:9=2:3 and 9:12=3:4

2:3<3:4

Answer:

B

Step-by-step explanation:

a prime polynomial is one which does not factor into 2 binomials.

its only factors are 1 and itself

attempt to factorise the given polynomials

3x³ + 3x² - 2x - 2 ( factor the first/second and third/fourth terms )

= 3x²(x + 1) - 2(x + 1) ← factor out common factor (x + 1) from each term

= (x + 1)(3x² - 2) ← in factored form

--------------------------------------------------

3x³ - 2x² + 3x - 4 ( factor the first/second terms

= x²(3x - 2) + 3x - 4 ← 3x - 4 cannot be factored

thus this polynomial is prime

----------------------------------------------------

4x³ + 2x² + 6x + 3 ( factor first/second and third/fourth terms )

= 2x²(2x + 1) + 3(2x + 1) ← factor out common factor (2x + 1) from each term

= (2x + 1)(2x² + 3) ← in factored form

-------------------------------------------------

4x³ + 4x² - 3x - 3 ( factor first/second and third/fourth terms )

= 4x²(x + 1) - 3(x + 1) ← factor out common factor (x + 1) from each term

= (x + 1)(4x² - 3) ← in factored form

--------------------------------------------------

the only polynomial which does not factorise is

3x³ - 2x² + 3x - 4

The incorrect statement is:

B. The three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x < 6.

In the given statement, there is an error in the inequality. The correct statement should be:

The three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x and 5 - x < 6.

When solving the three-part inequality - 5x < 15x^2 < 3, we need to split it into two separate inequalities. The correct splitting should be:

- 5x < 15x^2 and 15x^2 < 3

Simplifying the first inequality:

- 5x < 15x^2

Dividing by x (assuming x ≠ 0), we need to reverse the inequality sign:

- 5 < 15x

Simplifying the second inequality:

15x^2 < 3

Dividing by 15, we get:

x^2 < 1/5

Taking the square root (assuming x ≥ 0), we have two cases:

x < 1/√5 and -x < 1/√5

Combining these inequalities, we get:

- 5 < 15x and x < 1/√5 and -x < 1/√5

Therefore, the correct statement is that the three-part inequality - 5x < 15x^2 < 3 is equivalent to - 6 ≤ 5 - x and 5 - x < 6, not - 6 ≤ 5 - x < 6 as stated in option B.

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Answer:

Your answer......4.66m

AC=√AB^2- BC^2

=√(5)^2-(1.8)^2

=4.66

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Answer:

Step-by-step explanation:

length = 5 m

height = 1.8 m

The triangle that it formed is given in the figure,

Now first we have to find angle A,

sin(A) =perp/hyp = 1.3/5 = 0.26

now we get ,

Angle A = 15 degree

now using ,

tan(15) = perp/base = 1.3/distance

distance = 1.3/tan(15)

distance =1.3/0.27

distance = 4.8 m

The expected number of coupons that will be redeemed is 0.96.

Given data:

To find the expected number of coupons that will be redeemed, multiply the probability of redemption for a single coupon by the number of coupons distributed.

Given that 16% of $10-off coupons delivered by mail are redeemed, the probability of redemption for a single coupon is 0.16.

Since six customers are randomly selected and mailed coupons, the number of coupons distributed is 6.

Therefore, the expected number of coupons that will be redeemed is:

Expected number of redeemed coupons = Probability of redemption * Number of coupons distributed

= 0.16 * 6

= 0.96

Hence, the expected number of coupons is 0.96.

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Answer:

5h...................

174 number of students must be in the 8th grade class.

A relationship between two expressions or values that are not equal to each other is called 'inequality.

Given that The eight grade class is planning a trip to Washington, D.C. this spring.

They need a minimum of 75 people to attend in order to reserve busses.

1/3 of the 8th grade class plus 17 parent chaperones have signed up and this is enough to satisfy the requirement,

We need to find the number of students must be in the 8th grade class

1/3x+17≤75

Subtract 17 on both sides

1/3x≤58

x≤174

Hence, 174 number of students must be in the 8th grade class.

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The area of the shaded region of the rectangle is approximately 573.92 square feet.

The figure in the image is that of a rectangle with a semi-circle inscribed in it.

The area of rectangle is expressed as:

Area = Length × Width

The area of semi-circle is expressed as:

Area = 1/2 × πr²

To determine the area of the shaded region, we simply subtract the area of the semi-circle from the area of the rectangle.

Area of shaded region = area of rectangle - area of semi-circle

Area of shaded region = ( Length × Width ) - ( 1/2 × πr² )

From the image:

Length = 40 ft

Width = 20 ft

Radius r = 12 ft

Plug the values into the above formula:

Area of shaded region = ( Length × Width ) - ( 1/2 × πr² )

Area of shaded region = ( 40 × 20 ) - ( 1/2 × 3.14 × 12² )

Area of shaded region = ( 800 ) - ( 226.08 )

Area of shaded region = 573.92 ft²

Therefore, the area is approximately 573.92 square feet.

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The value of m<RQS as required to be determined in the task content is; 70°.

It follows from the task content that the measure of angle RQS is to be determined as required.

Recall, the measure of the central angle subtended by an arc is twice that which it subtends at any point on the circumference.

Therefore, m<RPS = 2 • m<RQS.

m<RQS = 140°/2

m<RQS = 70°.

Ultimately, the measure of angle RQS are; 70°.

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The function that grows at the fastest rate for increasing values of x is f(x) = 4×2ˣ.

We can see this by comparing the growth rates of the three functions for larger and larger values of x.

As x gets larger, the exponential function f(x) grows much faster than the other two functions, which are both polynomial functions.

if we plug in x = 10, we get:

f(10) = 4×2¹⁰ = 4×1024 = 4096

h(10) = 9×10² + 25 = 925

g(10) = 15×10 + 6 = 156

As we can see, f(10) is much larger than h(10) and g(10), indicating that f(x) grows at a much faster rate than the other two functions.

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