what heat transfer mechanisms (conduction, convection, or radiation) are involved when heat flows through a glass windowpane? explain.

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Explanation:

Push and pull of an object is called force.

SI unit of force is Newton

Answer:

111.4 m

Explanation:

PE = m x g x h

349,300 = 320 x 9.8 x h

h = 349300 : 3136

h = 111,384 m

Answer:

0 degrees

Explanation:

this is because when the light ray hits a surface a medium at 90 degrees then the angle of incidence = 0 , thus light doesn't bend when it enters the medium, no bending means angle of refraction is 0 degrees

hope this helps ,please mark it

S' = 14.77 cm height of image = 0.577 mm is the computed response. It is inverted because magnification is negative.

Where radius (R) is positive because it is facing the same direction as the refracted light, and index of refraction (n1) = 1 for air and index of refraction for glass (n2) = 1.60, object distance from vertex to spherical surface (s) is 24 cm, or 0.24 meters, and image distance from vertex to spherical surface (s') is 4 cm, or 0.04 meters.

Height of object = y = 1.5 mm = 0.0015 m Height of image = y'

For a spherical reflecting surface, the object-image formula is:

According to the magnifying formula:

It is inverted because magnification is negative.

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Answer:

The untrue option is C: "More arrowheads on lines mean a brighter light"

Explanation:

Ray diagrams are used to show how the light behaves with things like mirrors or lenses. Where we only study how the direction of the light changes when it interacts with these objects.

The "light" is represented with arrows, where again, the only thing we care is the direction of the light, so the first statement is true, the arrowheads show the direction of the light, and only that.

The intensity of the light, in this context, has no effect on how light behaves, so there is not a necessity of representing the intensity of the light, thus, more arrowheads on lines do not mean a brighter light. It may only be used to represent changes in direction of the light.

Finally, we know that light travels in straight pats (the pats can be curved in some cases, like with large gravitational fields, but this is not the case of a ray diagram) so the lines that represent the light should always be straight, thus option B is also true.

The untrue option is C: "More arrowheads on lines mean a brighter light"

Answer:Whenever an object experiences uniform circular motion there will always be a net force acting on the object pointing towards the center of the circular path. This net force has the special form  , and because it points in to the center of the circle, at right angles to the velocity, the force will change the direction of the velocity but not the magnitude.

It's useful to look at some examples to see how we deal with situations involving uniform circular motion.

Example 1 - Twirling an object tied to a rope in a horizontal circle. (Note that the object travels in a horizontal circle, but the rope itself is not horizontal). If the tension in the rope is 100 N, the object's mass is 3.7 kg, and the rope is 1.4 m long, what is the angle of the rope with respect to the horizontal, and what is the speed of the object?

As always, the place to start is with a free-body diagram, which just has two forces, the tension and the weight. It's simplest to choose a coordinate system that is horizontal and vertical, because the centripetal acceleration will be horizontal, and there is no vertical acceleration.

The tension, T, gets split into horizontal and vertical components. We don't know the angle, but that's OK because we can solve for it. Adding forces in the y direction gives:

This can be solved to get the angle:

In the x direction there's just the one force, the horizontal component of the tension, which we'll set equal to the mass times the centripetal acceleration:

We know mass and tension and the angle, but we have to be careful with r, because it is not simply the length of the rope. It is the horizontal component of the 1.4 m (let's call this L, for length), so there's a factor of the cosine coming in to the r as well.

Rearranging this to solve for the speed gives:

which gives a speed of v = 5.73 m/s.

Example 2 - Identical objects on a turntable, different distances from the center. Let's not worry about doing a full analysis with numbers; instead, let's draw the free-body diagram, and then see if we can understand why the outer objects get thrown off the turntable at a lower rotational speed than objects closer to the center.

In this case, the free-body diagram has three forces, the force of gravity, the normal force, and a frictional force. The friction here is static friction, because even though the objects are moving, they are not moving relative to the turntable. If there is no relative motion, you have static friction. The frictional force also points towards the center; the frictional force acts to oppose any relative motion, and the object has a tendency to go in a straight line which, relative to the turntable, would carry it away from the center. So, a static frictional force points in towards the center.

Summing forces in the y-direction tells us that the normal force is equal in magnitude to the weight. In the x-direction, the only force there is is the frictional force.

The maximum possible value of the static force of friction is

As the velocity increases, the frictional force has to increase to provide the necessary force required to keep the object spinning in a circle. If we continue to increase the rotation rate of the turntable, thereby increasing the speed of an object sitting on it, at some point the frictional force won't be large enough to keep the object traveling in a circle, and the object will move towards the outside of the turntable and fall off.

Why does this happen to the outer objects first? Because the speed they're going is proportional to the radius (v = circumference / period), so the frictional force necessary to keep an object spinning on the turntable ends up also being proportional to the radius. More force is needed for the outer objects at a given rotation rate, and they'll reach the maximum frictional force limit before the inner objects will.

Explanation:

Answer:

Explanation:  HIII

Answer:

the intercepts of a graph are point at which the graph crosses the axes

The equations of the lines in fully simplified slope-intercept form are

The linear graph represents the given parameter

For the first graph, we have the points

(0, -2) and (1, 1)

A linear equation is represented as

y = mx + c

Where

c = y when x = 0

So, we have

y = mx - 2

Using the point (1, 1) on y = mx - 2, we have

m(1) - 2 = 1

m - 2 = 1

Evaluate

m = 3

So, we have

y = 3x - 2

Using the above as a guide, we have the following equations for the other graphs

Graph 2: y = -4x + 2

Graph 3: y = -x - 2

Graph 4: y = 3/2x + 1

Graph 5: y = -2x + 2

Graph 6: y = x

Hence, the equation of the first line in fully simplified slope-intercept form is y = 3x - 2

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Answer:

As = 7.33 [m/s]

Explanation:

To solve this problem we must use the definition of the average speed, which is equal to the relationship between the distance over time.

As = x/t

where:

As = average speed [m/s]

x = distance = 132 [m]

t = time = 18 [s]

As = 132/18

As = 7.33 [m/s]

Answer:student 3 is the answer

Explanation:

Answer:

Gravity as well as electrostatic and magnetic attraction and reputation provide real life of example of forces being exerted by one object no another without them being in contact each other.

When an object is released with an initial velocity upward, the direction of its acceleration is typically downward.

This is because the force of gravity, which acts on the object, pulls it in the opposite direction to its motion. According to Newton's second law of motion, the net force on an object is equal to its mass multiplied by its acceleration. In this case, the force of gravity acts as the net force, causing the object to accelerate downward.

The acceleration due to gravity is approximately 9.8 meters per second squared on Earth, and it acts downward towards the center of the planet. Therefore, when the object is released with an initial velocity upward, the gravitational force causes it to decelerate and eventually change direction, resulting in a downward acceleration. This downward acceleration opposes the initial upward velocity of the object until it eventually reaches its peak and starts to fall back down under the influence of gravity.

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Answer:

N = 19.6 N

Explanation:

Given that,

Mass of a block, m = 2000 g

1 kg = 1000 g

It means, 2000 g = 2kg

We need to find the value of normal force on the block on a table. Normal force is balanced by the weight of the block as follows :

N = mg, g is acceleration due to gravity

N = 2 kg × 9.8 m/s²

N = 19.6 N

So, the normal force acting on the block is 19.6 N.

The acceleration of the eraser is 169.19 m/s².

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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Answer:

21% i hope im right if not srry :( .

Explanation:

Answer:

Explanation:

\(E=\frac{q}{F}\) where q is the charge of the electron and F is the electrostatic force. Filling in:

\(E=\frac{-1.6*10^{-19}}{9.2*10^{-15}}\) which gives you an electric field magnitude of

E = -1.7 × \(10^{-5\) C/N

Answer:

c

Explanation:

because if a tennis ball hit a tennis racket still it would not go anywhere. with the tennis ball hitting the moving racket it will go further

One that is in motion because both the ball and the racquet will contribute momentum.

Thus, option (c) is correct.

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

When the tennis ball hits a tennis racquet in motion, both the ball and the racquet will exert forces on each other in opposite directions.

This interaction will result in a transfer of momentum from the racquet to the ball and vice versa, potentially giving the ball a greater momentum and therefore potentially causing it to go farther.

Thus, option (c) is correct.

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The magnitude of the linear acceleration a of the sphere is 5/7gsinθ whose mass is M and radius is R.

Given the radius of sphere = R

The mass of sphere = M

The angle of inclination = θ

Let the linear acceleration = a

The horizontal force component = F x = Mgcosθ

The vertical force component = Fy = Mgsinθ

The magnitude of linear acceleration of the sphere can be determined using the equation of motion for a body rolling without slipping.

The friction will be acting opposite to the force such that:

Mgsinθ = Ma + Ff

Mgsinθ = Ma + Iα/R

The moment of inertia of solid sphere I = 2/5MR^2

gsinθ = a + 2/5a

gsinθ = a( 1 + 2/5)

a = 5/7gsinθ

Therefore, the magnitude of the linear acceleration of the sphere is equal to 5/7gsinθ.

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Answer:

\(\sf Proof \ below\)

Explanation:

We know that acceleration is change in velocity over time.

\(\sf a=\frac{\triangle v}{t}\)

\(\sf a=\frac{v-u}{t}\)

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

\(\sf at=v-u\)

Add u to both sides.

\(\sf at + u=v\)

Answer:

Acceleration = v-u/t  when we flip -u and t to right hand side

then -u changes to plus and denominator t changes to numerator

then then  this equations becomes  v=u+at

Explanation:

Important support for general relativity came from studies of the precession of the orbit of Mercury

A route that an object in space follows around another is known as an orbit. A satellite is a thing that orbits the earth. An Earth- or moon-like natural satellite is one possibility. Moons are satellites that orbit many planets. A man-made satellite is also possible, such as the International Space Station.

Albert Einstein created the gravitational theory known as general relativity between 1907 and 1915. According to general relativity theory, the apparent gravitational pull between masses is caused by the bending of spacetime caused by those masses.

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Answer:

(I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

Explanation:

Given that,

Mass of black hole \(m= 1\times10^{8} M_{sun}\)

(I). We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Where, G = gravitational constant

M = mass

c = speed of light

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times1\times10^{8}\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=2.94\times10^{8}\ km\)

(II). Mass of block hole \(m= 6 M_{sun}\)

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times6\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=17.7\ km\)

(III). Mass of block hole m= mass of moon

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times7.35\times10^{22}}{(3\times10^{8})^2}\)

\(R_{g}=1.1\times10^{-7}\ km\)

(IV). Mass = 50 kg

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times50}{(3\times10^{8})^2}\)

\(R_{g}=7.4\times10^{-29}\ km\)

Hence, (I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

The energy conservation allows to find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

The schwarschild radius is defined as the distance from a black hole center at radius  which the escape velocity is equal to the light speed, in some cases it is also called the event horizon.

Let's use Newton's second law where force is the universal law of attraction and acceleration is centripetal.

        F = ma

        F = \(G \frac{Mm}{r^2}\)        

Where F is the force, M the mass of the black hole, m the handle of the body, r the radius and v the speed of the body.

The energy of the gravitational field is

        F = \(- \frac{dU}{dr }\)  

         U = \(-G \frac{Mm}{r}\)  

Let's use conservation of energy

        Em₀ = K + U = ½ m v² -  \(G \frac{Mm}{r}\)  

In infinity the energy

        Em_f = 0

energy is conserved

       Em₀ = Em_f  

       ½ m v² - \(G \frac{Mm }{r}\)  = 0

       r = \(\frac{2GM}{v^2}\)

From the definition of the Schwarschild radius this speed is equal to the light speed

        v = c

        r = \(\frac{2GM}{c^2 }\)  

They ask to calculate the radius for several cases of different mass, claculate the constant value

      V = \(\frac{2 \ 6.67 \ 10^{-11} }{(3 \ 10^8) ^2 }\)  

      V =  1.482 10⁻²⁷

1) A black hole of mass M = 1 10⁸ \(M_{sum}\)

The tabulated mass of the sun is \(M_{sum}\) = 1.989 10³⁰ kg

Let's  substitute

        r =  1.482 10⁻²⁷   1 10⁸ 1.989 10³⁰

        r = 2.94 10⁸ km

With two significant figures

        r = 2.9 10⁸ km

2) A black hole of mass M = 6 \(M_{sum}\)

        r =  1.482 10⁻²⁷ 6 1.989 10-30

        r = 17.7 km

3) a mini black hole with the mass of the moon

    Tabulated mass of the moon M = 7.35 10²² kg

       r =  1.482 10⁻²⁷  7.35 10²²    

       r = 1.1 10⁻⁷ km

4) A person of M = 50 kg

    r =  1.482 10⁻²⁷ 50

    r=  7 10-29 km

In conclusion using the conservation of energy we can find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

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Answer:C

Explanation:

You should just have to do the math and will get you C

Answer:

we need it to work and without it we dont have strength to do anything

Answer:

energy is important to all living organisms. energy for producers comes from the sun, and energy for consumers comes from other living organisms. the abundance of energy available for organisms impacts the population.

The  charge passing through the circuit in one second is 8 C.

Charge is property of matter that causes experience of force when kept in electric or magnetic field.

Electric charge exists as the physical property of matter that causes charged matter to experience a force when positioned in an electromagnetic field. Electric charges can be positive or negative. Like charges repulse each other and unlike charges attract each other.

Charge, also understood as electric charge, electrical charge, or electrostatic charge and symbolized by q, exists as a characteristic of a unit of matter that represents the extent to which it has more or fewer electrons than protons.

As we know

I =Q/t

where I is current and Q is charge ,t is time

so put the value in formula

8 = Q/

Q  =  8 coulomb.

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Answer:

When you have two materials with the same index of refraction, it means that if they are touched by a ray of light it won't have a chance, and its form would prevail.

Explanation:

The reason behind this is that in the first place. When light passes through an object of certain refraction it is modified from its natural state, allowing it to change in color to the human eye or many other effects in other perceptive elements. However, when the same light passes through two objects with the same refraction due to their physical characteristics, it doesn't change because once it comes out of the first one it will suffer the same effect from the last one. For it to change the refraction would have to be higher or lower. Then it would be modified. The reason is because the dimensions are not modified. Because at some point the ray of light has to come out of the first one to enter the second one.

The piston the student is standing on has a 0.22-times larger diameter than the piston the elephant stands on.

Given parameters:

Mass of the student: m = 70 kg.

Mass of the elephant: M = 1200 kg.

Let the diameters of the piston the student is standing on and the piston the elephant is standing on are respectively d and D.

Using Pascal's law , we can write,

Force applied by the student's weight  ÷ area  of the piston the student is standing on = Force applied by the elephant's weight ÷ area  of the piston the elephant is standing on.

⇒ 70 kg × g / π d² = 1200 kg × g / π D²

⇒ 1400 d² = 70 D²

⇒ d= 0.22D.

Hence, The piston the student is standing on has a diameter that is 0.22 times larger than the piston the elephant is standing on.

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Martinez Company needs to sell 14,286 units of its product and generate $1,000,020 in sales revenue to earn a profit of $120,000.

The contribution margin ratio approach involves calculating the contribution margin per unit and then using it to determine the break-even point and desired profit.

To calculate the contribution margin per unit, we subtract the variable cost per unit ($42) from the sales price per unit ($70), which gives us a contribution margin per unit of $28.

Next, we can use this contribution margin per unit to determine the break-even point. To break even, the company needs to cover its fixed costs of $300,000 and earn a profit of $0. This means that the break-even point in units is:

Break-even point = Fixed costs / Contribution margin per unit
Break-even point = $300,000 / $28
Break-even point = 10,714 units

To earn the desired profit of $120,000, we need to add this amount to the fixed costs in our calculation:

Sales volume in units = (Fixed costs + Desired profit) / Contribution margin per unit
Sales volume in units = ($300,000 + $120,000) / $28
Sales volume in units = 14,286 units

Finally, we can calculate the sales volume in dollars by multiplying the sales volume in units by the sales price per unit:

Sales volume in dollars = Sales volume in units x Sales price per unit
Sales volume in dollars = 14,286 units x $70
Sales volume in dollars = $1,000,020

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