What factors should be considered in quadcopter motor selection?
A) Voltage that matches battery and motor amp-hours
B) Amperage and weight
C) Maximum revolutions per minute and torque rating
D) Power-to-weight ratio and pitch

Brake fluid serves as a lubricant for the parts of the hydraulic system and ensures smooth and even operation is true.

Hydraulic system is defined as a mechanical operation that relies on the pressure of liquid to perform. Hydraulic systems use a pressured fluid to operate and carry out duties.

The term "brake fluid" also refers to hydraulic brake fluid. It is in charge of shifting various brake system components of a vehicle. Without this fluid, a car or truck would not be able to stop even when the driver applied the brakes within the vehicle since it operates at extremely high temperatures and pressures.

Thus, brake fluid serves as a lubricant for the parts of the hydraulic system and ensures smooth and even operation is true.

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Answer:

Explanation:

i took the test and screenshot it

The estimated drag force on the prototype submarine is approximately 30 N.

To estimate the drag force on the prototype submarine, we can use the concept of dynamic similarity. Dynamic similarity states that two systems will experience similar forces when their Reynolds numbers are the same. The Reynolds number (Re) is a dimensionless parameter that describes the ratio of inertial forces to viscous forces in a fluid flow.

Since the model is one-fifth scale, the length of the model submarine would be 4.85 m / 5 = 0.97 m. The speed of the model submarine in the wind tunnel is not given, but we know the speed of the prototype submarine in water. To maintain dynamic similarity, we need to scale the speed as well. Therefore, the speed of the model submarine can be calculated as 0.440 m/s / 5 = 0.088 m/s.

The kinematic viscosity of air is given as u = 1.849 x 10^-5 kg/m-s, and the air density is p = 1.184 kg/m^3. Thus, the Reynolds number of the model submarine in the wind tunnel can be calculated as:

Re_model = (p_air * v_model * L_model) / u_air

        = (1.184 kg/m^3 * 0.088 m/s * 0.97 m) / (1.849 x 10^-5 kg/m-s)

        ≈ 58,518

The Reynolds number of the prototype submarine can be calculated using the same equation, but with the properties of water and the dimensions of the prototype submarine:

Re_prototype = (p_water * v_prototype * L_prototype) / u_water

            = (999.1 kg/m^3 * 0.440 m/s * 4.85 m) / (1.138 x 10^-3 kg/m-s)

            ≈ 1,634,635

Since the model submarine and the prototype submarine need to have the same Reynolds number for dynamic similarity, we can set the Reynolds numbers equal to each other and solve for the drag force on the prototype submarine:

Re_model = Re_prototype

58,518 = (D_model * v_model * L_model) / u_air

Solving for D_model, we get:

D_model = (58,518 * u_air * L_model) / v_model

Now, we can substitute the values and calculate the drag force on the prototype submarine:

D_prototype = (58,518 * u_air * L_prototype) / v_model

           = (58,518 * 1.849 x 10^-5 kg/m-s * 4.85 m) / 0.088 m/s

           ≈ 30 N

Therefore, the estimated drag force on the prototype submarine is approximately 30 N.

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The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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The minimum number of stages required for the absorption column to meet the given specifications is 10, and the operating line equation is y = 0.37x + 0.63.

To plot the operating line and determine the minimum number of stages for the given conditions, we can use the following steps:

Determine the basis
Given that we need to choose 100 moles of entering gas as a basis, we can assume that the flow rate of gas is 100 moles per hour.

Calculate the flow rate of entering air and entering oil
The entering gas contains 20 mole percent acetone, which means that it contains 20 moles of acetone and 80 moles of air.

Therefore, the flow rate of entering air is 80 moles per hour.
Since the entering oil is acetone-free, the flow rate of entering oil is 0 moles per hour.
Calculate the flow rate of exiting air and exiting oil
Let's assume that the exiting air contains x moles of acetone per hour, and the exiting oil contains y moles of acetone per hour.
According to the given conditions, 98.5% of the acetone in the air is to be absorbed, which means that the exiting air contains 0.15 x moles of acetone per hour.
The concentration of the liquor at the bottom of the tower is to contain 8 mole percent acetone, which means that the exiting oil contains 0.08 y moles of acetone per hour.
Therefore, the flow rate of exiting air is (80 - 0.15 x) moles per hour, and the flow rate of exiting oil is y moles per hour.
Calculate the equilibrium values of y and x
The equilibrium relationship is ye = 1.85xe.

We can use this equation to calculate the equilibrium values of y and x for each stage.
For the first stage, we can assume that x1 = 20 and y1 = 0 (since the entering oil is acetone-free).
Using the equilibrium relationship, we can calculate y1e = 1.85 x1 = 37 and x1e = y1e / 1.85 = 20.
For the second stage, we can assume that x2 = (80 - 0.15 x1e) and y2 = y1e.
Using the equilibrium relationship, we can calculate y2e = 1.85 x2 = 135 and x2e = y2e / 1.85 = 73.0.
Similarly, we can continue this process for each stage until we reach the bottom of the tower, where the concentration of the liquor is to contain 8 mole percent acetone.
Plot the operating line
The operating line represents the relationship between the concentrations of acetone in the entering and exiting gas streams for each stage.

It can be calculated using the equation (y - ye) / (x - xe) = (L / V),

where L is the flow rate of entering oil and V is the flow rate of entering gas.
We can plot the operating line by connecting the equilibrium values of y and x for each stage.
Determine the minimum number of stages
The minimum number of stages can be determined by using the McCabe-Thiele method.

This method involves drawing a line parallel to the operating line that intersects the y-axis at the point where the concentration of acetone in the exiting oil is equal to the desired concentration of acetone in the liquor at the bottom of the tower (in this case, 8 mole percent).

The point where this line intersects the operating line represents the equilibrium value of y for the last stage.
We can count the number of stages required to reach this point and subtract one to obtain the minimum number of stages required.
In this case, the minimum number of stages required is 11.

Therefore, by means of a plate column, 11 stages are required to absorb 98.5% of the acetone from its mixture with air in a non-volatile absorption oil, and the concentration of the liquor at the bottom of the tower is to contain 8 mole percent acetone.

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Answer:

HVACR Industry Trade Groups

Explanation:

For Part A, the velocity of peg A when x = 1.2 m can be calculated using the equation v = s/t, where s is the distance traveled and t is the time taken. Since the link is moving at a constant speed of 10 m/s, the time taken to travel 1.2 m is 1.2/10 = 0.12 s.

Therefore, the velocity of peg A when x = 1.2 m is v = 10/0.12 = 83.33 m/s.

For Part B, the acceleration of peg A when x = 1.2 m can be calculated using the equation a = (v2 - v1)/t, where v2 and v1 are the velocities of the peg at the two different points and t is the time taken to travel between them. Since the link is moving at a constant speed of 10 m/s, the time taken to travel 1.2 m is 0.12 s.

Therefore, the acceleration of peg A when x = 1.2 m is a = (83.332 - 102)/0.12 = -833.33 m/s2.

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The MATLAB desktop interface allows users to navigate, view, and manage directories using GUI buttons, providing a user-friendly alternative to command-based operations.

The paragraph describes the functionality of MATLAB's desktop interface for working with directories. It explains that the current directory's name and path are displayed in the command window toolbar and in a separate subwindow to the left.

The subwindow allows users to view the contents of the current directory, navigate to parent directories using the "One Level Up" button or the "Directory Browser" button, create new directories using the "New Directory" button, and perform file operations such as moving or copying files between directories.

The paragraph emphasizes that these directory-related tasks, which were previously done using commands, can now be performed using the GUI buttons in MATLAB's desktop interface. This provides a user-friendly way to navigate and manage directories through mouse clicks.

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Answer:

the answer would be B motor

The agile software development methodology is characterized by several key principles and practices that differentiate it from traditional software development approaches. Here are the characteristics commonly associated with agile methodology:

Iterative and Incremental Development: Agile emphasizes the iterative and incremental delivery of software, with frequent feedback and adaptation throughout the development process.Collaboration and Customer Involvement: Agile promotes close collaboration between developers and stakeholders, including customers or end-users, to ensure that the software meets their needs.

Flexibility and Adaptability: Agile embraces change and encourages teams to be flexible and adaptable in responding to evolving requirements and priorities.Self-Organizing Teams: Agile teams are self-organizing and empowered to make decisions, fostering collaboration, accountability, and ownership.

Continuous Delivery and Continuous Improvement: Agile teams strive for continuous delivery of working software and continuous improvement through regular reflection and adaptation.Based on these characteristics, there is no specific characteristic of agile methodology that can be excluded. Therefore, the statement "The agile software development methodology is categorized by all of the following, except" does not have an accurate answer.

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Answer:

STICK SKILL DRILL...

Explanation:

The skill drill uses a Whip and Pause technique.The reason for whip and pause is that 6010 electrodes are fast freezing electrodes and the momentary whips allow the puddle to solidify a bit ..Length of Art..Too long an arc causes problems so try to keep the arc equal to or shorter than diameter of electrode.

Answer: a thicker line

Explanation:

Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.

Given the following data:

To find the magnetic flux per pole:

Mathematically, the emf generated by a DC generator is given by the formula;

\(E = \frac{\theta ZN}{60}\) × \(\frac{P}{A}\)

Where:

First of all, we would determine the total number of armature conductors:

\(Z = 144\) × \(2\) × \(3\)

Z = 864

Substituting the given parameters into the formula, we have;

\(520 = \frac{\theta (864)(660)}{60}\) × \(\frac{4}{2}\)

\(520 = \theta (864)(11)\) × \(2\)

\(520 = 19008 \theta \\\\\Theta = \frac{520}{19008}\)

Magnetic flux = 0.0274 Weber.

Therefore, the magnetic flux per pole is 0.0274 Weber.

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The seepage rate (Qseepage) from the river to the channel can be calculated using Darcy's law as follows:Qseepage=K×A×(h1−h2)Where, K is the hydraulic conductivity of the aquifer, A is the cross-sectional area of the flow, h1 is the height of the water table in the river, and h2 is the height of the water table in the channel.

The height difference (h1-h2) drives the flow of water through the aquifer.

To determine the cross-sectional area of flow, we first need to calculate the width of the aquifer. The distance between the river and the channel is 1000 m, and the length of the river section is 750 m. Therefore, the width of the aquifer is 1000 - 750 = 250 m. The cross-sectional area of flow is equal to the width of the aquifer multiplied by its average thickness. Thus, A = 250 × 10 = 2500 m².

Substituting the given values into the equation, we have:

Qseepage = 7.0 × 2500 × (5.0)

Qseepage = 87,500 m³/day

Therefore, the estimated seepage rate from the river to the channel is 87,500 m³/day.

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The three main principles in engineering design are: strategic balance, top management approach and team work.

The principles are fundamental concepts that engineers use to develop effective solutions to complex problems. These principles are based on scientific and mathematical principles as well as practical considerations related to the materials, technologies and resources available to the engineer.

The engineering design process involves several stages, including problem identification, research, concept development, prototyping and testing. Throughout each stage, engineers apply various principles to ensure that their designs meet the needs and requirements of the intended users.

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Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

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Answer:

4c4u4civ4j4

Explanation:

x24uu37z3x3uzu2

How fast is the fastest wind tunnel?

The JF-22 wind tunnel, which would be the fastest in the world, would be situated in the Huairou District of northern Beijing and be capable of simulating flights at speeds of up to 10 km/s, or 30 times the speed of sound.

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The suction line is sloped downwards unto the compressor for the prevention of accumulation of moisture on the downside of the walls.

To be able to maintain a dry surface without the accumulation of moisture on the lower walls, a downward slope is to be created between the evaporator and the compressor of such line of suction.

Hence, the way to prevent the accumulation of moisture has been aforementioned.

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Answer:

Explanation:

A scenario is an actual sequence of interactions (i.e., an instance) describing one specific situation; a use case is a general sequence of interactions (i.e., a class) describing all possible scenarios associated with a situation. Scenarios are used as examples and for clarifying details with the client. Use cases are used as complete descriptions to specify a user task or a set of related system features.

Any Voltage used on board a ship if less than 1kV (1000 V) then it is called as LV (Low Voltage) system and any voltage above 1kV is termed as High Voltage. Typical Marine HV systems operate usually at 3.3kV or 6.6kV.

Explanation:

trust

Answer:

Explanation:

a) To calculate the capillary porosity and total porosity for a concrete made with a water-to-cement (w/c) ratio of 0.52 and a cement paste binder that is 70% hydrated:

Capillary porosity refers to the interconnected network of small capillary voids within the concrete, while total porosity includes both capillary porosity and other types of pores present.

Given that the cement paste binder is 70% hydrated, we can assume that the remaining 30% of the paste consists of pores.

1. Capillary Porosity:

Capillary porosity is typically estimated as a percentage of the total volume of the cement paste binder. Since the cement paste binder makes up the entire volume of the concrete, the capillary porosity in this case is also 70%.

2. Total Porosity:

Total porosity includes both capillary porosity and the remaining non-capillary pores. In this case, the non-capillary porosity is 30% since the cement paste binder is 70% hydrated. Therefore, the total porosity is 70% + 30% = 100%.

b) If the w/c ratio is reduced to 0.42, the amount of water available for hydration decreases, which can affect the porosity of the concrete.

1. Capillary Porosity:

The capillary porosity is still 70% because it depends on the degree of hydration of the cement paste binder and is not affected by the w/c ratio.

2. Total Porosity:

To determine the total porosity, we need to consider the capillary porosity and the non-capillary porosity resulting from the reduced water content. However, without specific information about the relationship between the w/c ratio and non-capillary porosity, we cannot calculate the exact total porosity. We can only say that the total porosity will likely decrease due to the reduced water content.

c) If the cement paste is cured for a longer time and is 85% hydrated:

1. Capillary Porosity:

The capillary porosity remains the same as the degree of hydration does not affect it. It will still be 70%.

2. Total Porosity:

To determine the total porosity, we need to consider both the capillary porosity and the non-capillary porosity resulting from the hydration process. With the cement being 85% hydrated, we can assume that the non-capillary porosity is 15%. Therefore, the total porosity will be 70% + 15% = 85%.

Please note that these calculations provide estimates based on general assumptions and simplifications. The specific properties and behavior of concrete can vary depending on various factors and mix proportions.

Answer:

My guess is toxicty from gas fumes. Hope this helps

Explanation:

One of the four characteristics of hazardous waste is Toxicity. That is option B.

A hazardous waste is any material or substance that is capable of harming living organisms and making the environment dangerous for to live in.

The characteristics of a hazardous waste include:

Therefore, one of the four characteristics of hazardous waste is Toxicity.

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Taking the natural logarithm (ln) on both sides of the equation:

ln(0.007)

The formula for the charging or discharging of a capacitor in an RC circuit:

V(t) = V0 * (1 - e^(-t/RC))

Where:

V(t) is the voltage across the capacitor at time t

V0 is the initial voltage across the capacitor

R is the resistance in the circuit

C is the capacitance in the circuit

e is the base of the natural logarithm (approximately 2.71828)

In this case, we want to find the time required for V(t) to reach 99.3% of its steady value. Let's assume the steady value is V0.

0.993 * V0 = V0 * (1 - e^(-t/RC))

Simplifying the equation, we get:

0.007 = e^(-t/RC)

Taking the natural logarithm (ln) on both sides of the equation:

ln(0.007)

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Using the knowledge in computational language in C++ it is possible to write a code that course size complete the course class by implementing the coursesize() member function, which returns the total number of students in the course.

#include <iostream>

#include <string>

#include "Course.h"

using namespace std;

##########################

int main() {

   Course course;

   int count;

   // Adding the given student course details

   course.AddStudent(Student("Henry", "Bendel", 3.6));  

   course.AddStudent(Student("Johnny", "Min", 2.9));

   // Getting total number of students in the course

   count = course.CourseSize();

############################

   cout << "Course size: " << count << endl;

   return 0;

}

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Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

The defining feature of the Metaverse is that it is Virtual. This is its a most distinctive feature. See further details below.

The Metaverse does not compete with the internet; rather, it expands upon it.

Users navigate a virtual environment that duplicates features of the actual world utilizing technologies such as virtual reality (VR), augmented reality, artificial intelligence (AI), social media, and digital money in the metaverse.

Metaverse features include digital avatars, remote working, developing decentralization, hardware, encryption, and many more.

Similarly, virtual places like Zoom only allow for a single conversation. Participants at physical events can transition seamlessly from one talk to the next. Some colleges are utilizing metaverse technology to bypass internet and video meeting tool constraints.

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The military action that involves the use of electromagnetic and directed energy is defined as Electronic Warfare (EW).

Electronic Warfare (EW) refers to military action that uses electromagnetic energy to determine, exploit, impede, or sabotage hostile use of the electromagnetic spectrum and direct energy to deny adversaries the ability to operate effectively.

It involves a wide range of military operations, including electronic intelligence collection, electronic jamming, radar jamming, infrared countermeasures, and high-powered microwave weapons. It may also include cyber warfare, which is the utilization of digital technology to conduct military operations or gain a tactical advantage.

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Answer:

1)   V_win = 7.05 10¹⁰ m³ ,  2)V_ lost = 1.8471 10¹⁰ m³, 3)  h = 633.4  mm

Explanation:

In this exercise we will start by reducing all units to the SI system

    h1 = 2.69 inch (2.54 10-2 m / 1 inch) = 6.8326 10⁻² m

    Ф1 = 356.747 ft3 / s (1 m3 / 35.3147 ft3) = 10.1019 m³ / s

    Ф2 = 717,258 ft3 / s = 20,310 m³ / s

    h2 = 18.7 mm (1 m / 1000 mm) = 18.7 10⁻³ m

    V_subterránea = - 783.33 10³ m,

Now let's answer the questions

1) they ask us the amount of water that reaches the lake in 2018

volume of rainwater is

      V₁ = A. h t

      V₁ = 82 100 106 * 6.8326 10-2 * 12

      V₁ = 6.7315 10 10 m3

stream water volume in a year

      V₂ = Ф₁ t

       t = 1 year (365 days / year) (24 h / 1 day) (3600 s / 1h) = 3.1536 10⁷ s

       V₂ = 10.1019 3.1536 10⁷

       v₂ = 31,857 10⁷ m³

The total water volume is

     V_win = V₁ + V₂

     V_win = 6.7315 10¹⁰ + 31.857 10⁷

     V_win = 7.05 10¹⁰ m³

2) let's find the amount of water lost from the lake

volume of water to surrounding bodies

         V₃ = Ф₂ t

         V₃ = 20.310 3.1536 10⁷

         V₃ = 6.40496 10 8 m3

Volume of evaporated water

         V₄ = A h₂ t

          V₄ = 82 100 10⁶ 18.1 10⁻³ 12

          V⁴ = 1,783 10¹⁰ m³

groundwater volume

         V⁵ = 7.83.33 10³ m³

The volume of water lost is

       V_lost = V₃ + V₄ + V₅

       V_ lost = 6.40496 10⁸ + 1.783 10¹⁰ + 783.33 10³

       V_ lost = 1.8471 10¹⁰ m³

3) the change in the height of the lake

the change in volume is

      ΔV = V_ won - V_ lost

      ΔV = 7.05 10¹⁰ - 1.8471 10¹⁰

      ΔV = 5.20 10¹⁰ m³

the volume is

        v = A h

        h = V / A

        h = 5.20 10¹⁰/82100 10⁶

        h = 6.334 10⁻¹ m

        h = 633.4  mm