what does the spring scale read just before the mass touches the lower spring? express your answer to two significant figures and include the appropriate units.
Answers
The spring scale reads zero just before the mass touches the lower spring. The reading would be 0 N (newtons) to two significant figures.
A spring scale that is hanging from an item calculates the object's weight in newtons. The scale displays zero just before the mass contacts the lower spring because the object's weight has not yet had an impact on the spring. The only force operating on the spring at this time is that caused by gravity pulling on the spring.
The scale would therefore read 0 N (newtons) to two significant numbers. It is crucial to remember that accurate readings need correct calibration of the spring scale.
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The tension in the upper spring can be calculated using Hooke's law . the spring scale will read 0.16 N just before the mass touches the lower spring.
Explanation - Assuming that the spring scale is attached to the upper spring and the mass is hanging from it, the spring scale will read the weight of the mass. Just before the mass touches the lower spring, the weight of the mass will be equal to the tension in the upper spring.
Therefore, the spring scale will read the tension in the upper spring just before the mass touches the lower spring. The tension in the upper spring can be calculated using Hooke's law, which states that the force exerted by a spring is proportional to its extension or compression.
Therefore, the tension in the upper spring can be calculated as T = kx, where T is the tension, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
The displacement of the spring just before the mass touches the lower spring will be equal to the length of the upper spring minus the length of the lower spring. Assuming that the units of the spring constant are N/m and the displacement is in meters, the tension in the upper spring just before the mass touches the lower spring can be expressed as
T = k(x_upper - x_lower) = (k)(0.20 m - 0.02 m) = 0.16 N (to two significant figures). Therefore, the spring scale will read 0.16 N just before the mass touches the lower spring.
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Related Questions
a car travels at 17 m/s without skidding around a 35 m radius unbanked curve. what is the minimum value of the static friction coefficient between the tires and the road?
Answers
The minimum value of the static friction coefficient between the tires and the road is 0.61.
To find the minimum value of the static friction coefficient between the tires and the road, we need to use the centripetal force formula:
F = mv^2/r
Where F is the centripetal force required to keep the car moving in a circular path, m is the mass of the car, v is the speed of the car, and r is the radius of the curve.
Since the car is traveling at 17 m/s around a 35 m radius unbanked curve, we can plug in the values:
F = (m x 17^2) / 35
Now we need to find the maximum friction force that the road can provide, which is equal to the coefficient of static friction times the normal force:
f = μsN
Where f is the maximum friction force, μs is the coefficient of static friction, and N is the normal force.
To find the normal force, we need to use the weight formula:
W = mg
Where W is the weight of the car, m is the mass of the car, and g is the acceleration due to gravity (9.81 m/s^2).
So, N = mg = 1600 x 9.81 = 15,696 N
Now we can plug in the values for f and F:
f = μsN = μs x 15,696
F = (m x 17^2) / 35
Since the car is not skidding, the maximum friction force is equal to the centripetal force:
f = F
Therefore, we can set the two equations equal to each other:
μs x 15,696 = (m x 17^2) / 35
We know the mass of the car is 1600 kg, so we can substitute that in:
μs x 15,696 = (1600 x 17^2) / 35
Simplifying, we get:
μs = (1600 x 17^2) / (35 x 15,696) = 0.61
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If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is removed, what will happen in 2 s?
Answers
The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s
The free fall formula and the procedure we will use is:
fv = g* t
Where:
fv = final velocityg = acceleration due to gravityt = time takenh = height traveledInformation of the problem:
g = 9.8 m/s².t = 2 svf = ?Applying final velocity formula we get:
fv = g* t
fv = 9.8 m/s² * 2 s
fv = 19.6 m/s
What is free fall?It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.
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You need to pick up a book off the floor and place it on a tabletop. You expend 1.56J of energy to lift the book with a force of 300N. What is the distance?
Answers
Work done = Froce × distance
Now, keeping this formula in mimd, we can find the distance as follows;
= 1.56 = 300 × distance
= 1.56/300 = distance
= 156/30000 = distance
= 0.0052 m = distance
Lets convert it into cm so that you don't get troubled seeing it :)
= 1 m = 100cm
= 0.0052 × 100
= 0.52 cm
Which land feature is formed by two oceanic tectonic plates diverging? *
mid-ocean ridge
volcanic island arc
continental volcanoes
continental mountain range
Answers
Answer:
mid-ocean ridge
Explanation:
When two oceanic tectonic plates diverge, it means they pull away from each other. When this happens, new land is created where the two plates moved apart.
Answer:
Mid-Ocean Ridge
Explanation:
Just trust me
A net force of 120 newtons is applied to a 22 kg cart that is already moving at 3 meters per second.
How long was the force applied?
Answers
Answer:
1. F= 66 N
2. M= 40 kg
3. A= 5.45454545 repeating
Explanation:
A plane progressive wave is represented by the equation y=0. 5 sin (1000 πt -1000πx÷17) where y is in millimeters, t is in seconds, and x is in meters. Calculate the frequency and wavelength of the wave
Answers
The frequency of the wave is 500 Hz, and the wavelength of the wave is 0.034 meters.
In the given equation, y = 0.5 sin (1000 πt - 1000πx/17), the general form of a plane progressive wave is y = A sin (2πft - 2πx/λ), where A is the amplitude, f is the frequency, and λ is the wavelength.
Comparing the given equation to the general form, we can identify the values as follows:
Amplitude (A) = 0.5
Angular frequency (2πf) = 1000 π
Angular wave number (2π/λ) = 1000 π/17
From the angular frequency (2πf), we can determine the frequency (f) by dividing by 2π:
f = (1000 π) / (2π) = 500 Hz
From the angular wave number (2π/λ), we can determine the wavelength (λ) by taking its reciprocal:
λ = (2π) / (1000 π/17) = 34 / 1000 = 0.034 m
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Help PLZ ;)
If the distance between two objects increases, what happens to the force of gravity between them?
(A) Increases
(B) Decreases
(C) Stays the same
Answers
Answer:
B) Decreases
Explanation:
Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.
Hope this helps!
Answer:
The answer would be B
Explanation:
5). A body of mass 75kg lying on a surface of
μ = 0.4 move in the direction of a horizontal force
of 300N applied to it.
a). Calculate the
i). friction force
ii). acceleration of the body
b). Explain the result in aii).
Answers
Explanation:
a) i) Calculation of the friction force:
The friction force can be determined using the equation:
friction force = coefficient of friction * normal force
The normal force is equal to the weight of the object, which can be calculated as:
normal force = mass * gravitational acceleration
where the gravitational acceleration is approximately 9.8 m/s².
normal force = 75 kg * 9.8 m/s² = 735 N
friction force = 0.4 * 735 N = 294 N
ii) Calculation of the acceleration of the body:
Now, we can calculate the acceleration using Newton's second law:
net force = mass * acceleration
Since the applied force and the friction force act in opposite directions, the net force can be calculated as:
net force = applied force - friction force
net force = 300 N - 294 N = 6 N
mass = 75 kg
6 N = 75 kg * acceleration
acceleration = 6 N / 75 kg = 0.08 m/s²
b) Explanation:
In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.
The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.
The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.
Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.
Using the work-energy theorem, when driving 90 km/hr, how much more distance do you need to stop compared with driving 30 km/hr
Answers
When driving at 90 km/hr, you need approximately 4.5 times more distance to stop compared to driving at 30 km/hr.
The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. In the context of stopping a moving vehicle, this theorem can be applied to determine the additional distance required to stop when the initial velocity is increased.
1. The kinetic energy (KE) of an object is given by the formula: KE = ½ mv², where m is the mass of the object and v is its velocity.
2. Let's assume the mass of the vehicle remains constant. Therefore, the ratio of the kinetic energies at different velocities is equal to the ratio of the squares of the velocities: KE₁/KE₂ = (v₁/v₂)².
3. To compare the distances required to stop, we can equate the initial kinetic energy to the work done to stop the vehicle. Let's assume the work done is equal to the change in kinetic energy.
4. When driving at 30 km/hr, the initial velocity (v₂) is 30 km/hr and the initial kinetic energy (KE₂) is (½)mv₂².
5. When driving at 90 km/hr, the initial velocity (v₁) is 90 km/hr and the initial kinetic energy (KE₁) is (½)mv₁².
6. Using the ratio from step 2, we have KE₁/KE₂ = (v₁/v₂)² = (90/30)² = 9² = 81.
7. Therefore, the initial kinetic energy when driving at 90 km/hr is 81 times greater than when driving at 30 km/hr.
8. Since the work done to stop the vehicle is equal to the initial kinetic energy, the distance required to stop when driving at 90 km/hr is approximately 81 times greater than when driving at 30 km/hr.
In summary, when driving at 90 km/hr, you need approximately 4.5 times more distance to stop compared to driving at 30 km/hr (since 81 is approximately 4.5 times larger than 1).
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If Tango measures the speed of sound at its landing site as 240 m/s, while Foxtrot measures speed of sound as 258 m/s at it's landing site, where has each rover landed?
Answers
Tango landed in a site of lower temperature while Foxtrot landed in a site of higher temperature.
Effect of temperature on speed of soundSpeed of sound increases with increase in temperature because air molecules acquires more kinetic energy which increases their rate of vibration.
From the information, the speed of sound picked by Foxtrot (258 m/s) is greater than the speed of sound picked by Tango (240 m/s).
We can conclude that, Tango landed in a site of lower temperature while Foxtrot landed in a site of higher temperature.
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What would be the diameter of the earth if it had the density of a neutron star
Answers
Answer:
At neutron star density, the Earth's whole mass would fit inside a 305-meter-diameter sphere.
Explanation:
what is the force created by a hanging mass of 220 grams? (give answer in newtons to 2 places of decimal)
Answers
The force created by the hanging mass is: 2.16 N
What is force?It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.
To solve this exercise, the formula and procedure to be applied is:
F = m * g
Where:
m = massF = Forceg = gravityInformation about the problem:
F= ?1 N = kg * m/s²m = 220 gg= 9.8 m/s²By converting the mass form (g) to (kg) we have:
m = 220 g* 1 kg/1000 g
m= 0.220 kg
Applying the force formula, we get:
F = 0.22 kg * 9.8 m/s²
F= 2.16 N
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A baseball is hit so that it travels straight upward after being struck by the bat. A fan observes that it takes 3.00 s for the ball to reach its maximum height. Find (a) the ball’s initial velocity and (b) the maximum height it reaches.
Answers
Answer:
initial velocity is0m/s and final velocity is29.4m/s
if we compare light photons and energetic electrons which have constant velocity independent of energy
Answers
Light photons always travel at a constant speed (the speed of light) regardless of their energy, while the velocity of electrons is not constant and can vary with their energy.
Light photons and energetic electrons do not have constant velocities independent of energy. Light photons, which are particles of electromagnetic radiation, travel at a constant speed in a vacuum, which is approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum, denoted as the speed of light (c). This speed is a fundamental constant of nature and remains constant regardless of the energy of the photons. In other words, all photons, regardless of their energy, travel at the same speed in a vacuum.
On the other hand, energetic electrons do not have a constant velocity independent of their energy. According to classical physics, the velocity of an electron can vary depending on its energy. In classical mechanics, the kinetic energy of an object is related to its velocity. However, in the microscopic world of quantum mechanics, the behavior of particles such as electrons is described differently.
In quantum mechanics, the concept of particle velocity becomes less straightforward. Instead of velocity, quantum particles are described by wavefunctions, which represent the probability distribution of finding the particle at a certain location. The wavefunction of an electron evolves over time according to the Schrödinger equation, and it does not directly correspond to a well-defined classical velocity.
However, in certain situations, such as in electron beams or particle accelerators, electrons can be accelerated to high energies. In these cases, the energy of the electrons is related to their speed, but it is not a constant relationship. As the energy of the electrons increases, their speed can also increase, but it is not independent of their energy.
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a graph for horizontal position vs gravitational potential energy represents which of the following
(a) represent the slope of a track
(b) represent opposite of slope of track
(c) a linear relationship
Answers
Answer:
this may not be what you're looking for but here you go
Explanation:
A horizontal line means the object is not changing its position - it is not moving, it is at rest. A downward sloping line means the object is returning to the start. Speed-Time graphs are also called Velocity Time graphs. Speed-Time graphs look much like Distance-Time graphs.
The tendency to find a romantic partner that is similar in major social characteristics like ethnicity, social class, education level, geographic nativity, religion, etc. is known as what
Answers
The tendency to find a romantic partner who is similar in major social characteristics like ethnicity, social class, education level, geographic nativity, religion, etc. is known as assortative mating.
Assortative mating refers to the process of individuals selecting partners who share similar social traits or characteristics. It is also known as homogamy.
This phenomenon can be influenced by various factors, including social norms, cultural preferences, shared values, and opportunities for interaction within specific social circles or communities.
Assortative mating can contribute to perpetuating and reinforcing social divisions and inequalities and the transmission of cultural, educational, and economic advantages or disadvantages across generations. It plays a significant role in shaping social and demographic dynamics and patterns within societies.
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Chemical reaction and nuclear reactions cause matter to change in different ways. Which two statement describe how matter changes only in a chemical reactions?
Answers
All of the following are basic components of a masonry woodburning fireplace except
A)
a throat.
B)
a heat circulator.
C)
a smoke shelf.
D)
a damper.
Answers
A masonry woodburning fireplace typically includes the following basic components:
A) a throat: The throat is the narrow opening above the firebox that connects it to the flue. It helps direct the flow of smoke and gases.
C) a smoke shelf: The smoke shelf is a horizontal ledge located at the back of the fireplace, just above the firebox. It helps collect and redirect falling debris and prevents downdrafts.
D) a damper: The damper is a movable metal plate located in the throat or flue. It can be opened or closed to control the airflow and regulate the intensity of the fire.
A heat circulator, on the other hand, is not typically a component of a masonry woodburning fireplace. It refers to a device or system used to circulate warm air throughout a room or building, but it is not directly related to the fireplace itself.
PLS HELP, 20 POINTS
Which statement accurately describes the motion of the object in the graph above?
A. It moved from 3 cm to 10 cm at a constant speed of 2 cm/s.
B. It moved from 0 cm to 6 cm at an average speed of 1 cm/s.
C. It moved from 0 cm to 10 cm at an average speed of 2 cm/s.
D. It moved from 3 cm to 6 cm at a constant speed of 3 cm/s.
Answers
Answer:
A. It moved from 3 cm to 10 cm at a constant speed of 2 cm/s.
Explanation:
Just took the quiz.
It moved from 3 cm to 6 cm at a constant speed of 3 cm/s. This statement accurately describes the motion of the object in the graph above
What is motion of object ?
An object is said to be in motion , if its position changes with respect to its surroundings and time.
A. Object's motion is from 3 cm to 10 cm at a constant speed of 2 cm/s
let us check
time = 7 sec
distance = 10 - 3 = 7 sec
speed = distance / time = 7/7 = 1 m/s
wrong option
B. Object's motion is from 0 cm to 6 cm at an average speed of 1 cm/s.
distance = 6 cm
time = 7.5 sec
speed = 6/7.5 = 0.8 m/s
wrong option
C. Object's motion is from 0 cm to 10 cm at an average speed of 2 cm/s.
distance = 10 cm
time = 9 sec
speed = 10 / 9 = 1.11 m/s
wrong option
D. Object's motion is from 3 cm to 6 cm at a constant speed of 3 cm/s.
distance = 6-3 = 3 cm
time = 7.5 - 6.5 = 1 sec
speed = 3 /1 = 3 m/s
correct option D. It moved from 3 cm to 6 cm at a constant speed of 3 cm/s.
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how can I make a square fit in a triangle hole
Answers
cut the square and make it a triangle
When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction pressure and superheat
Answers
Answer:
The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.
Explanation:
1. The five components of refrigeration are:
Fluid refrigerantCompressorCondenser coilEvaporator coilExpansion device.The compressor limits the vapor released by the refrigerant. This
causes a rise in pressure (in refrigerant), which then pushes the
vapor into the coils on the outside of the refrigerator.
2. Now when the cooler air meets the warm gas present in the coils, it
gets converted into liquid form.
3. Thus, when the liquid form is at high pressure, the refrigerant then
cools down as it flows through the coils placed in the fridge ( in both
freezing and normal sections).
4. The refrigerant also absorbs the warm air present in the fridge, which
causes it to evaporate and flow back through the compressor and the
cycle repeats in the same form.
Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.
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The populations P (in thousands) of a particular county from 1971 through 2014 can be modeled byP = 71.7e0.0345twhere t represents the year, with t = 1 corresponding to 1971.(a) Use the model to complete the table. (Round your answers to the nearest whole number.)YearPopulation1980101240 Correct: Your answer is correct.1990142949 Correct: Your answer is correct.2000201843 Correct: Your answer is correct.2010285000 Correct: Your answer is correct.(b) According to the model, when will the population of the county reach 350,000?2018 Incorrect: Your answer is incorrect.
Answers
ANSWERS
(a) Year - Population
• 1980 - 101,240
,• 1990 - 142,949
,• 2000 - 201,843
,• 2010 - 285,000
(b) 2016
EXPLANATION
(a) The population (in thousands) each year is given by,
\(P=71.7\cdot e^{0.0345t}\)If t = 1 represents year 1971, then for each year we have to find the difference between the year and 1970.
For year 1980,
\(P=71.7\cdot e^{0.0345(1980-1970)}\approx101.240\)The population is 101,240.
For year 1990,
\(P=71.7\cdot e^{0.0345(1990-1970)}\approx142.949\)The population is 142,949.
For year 2000,
\(P=71.7\cdot e^{0.0345(2000-1970)}\approx201.843\)The population is 201,843.
For year 2010,
\(P=71.7\cdot e^{0.0345(2010-1970)}\approx285.000\)The population is 285,000.
(b) In this problem we're given the population 350,000 and we have to find in what year the county will reach that population. In other words, we have to find t and then add that to 1970 to find the year.
Let's solve for t,
\(P=71.7\cdot e^{0.0345t}\)Divide both sides by 71.7,
\(\begin{gathered} \frac{P}{71.7}=\frac{71.7}{71.7}\cdot e^{0.0345t} \\ \frac{P}{71.7}=e^{0.0345t} \end{gathered}\)Apply natural logarithm to both sides,
\(\begin{gathered} \ln \frac{P}{71.7}=\ln e^{0.0345t} \\ \ln \frac{P}{71.7}=0.0345t \end{gathered}\)Divide both sides by 0.0345,
\(\begin{gathered} \frac{\ln \frac{P}{71.7}}{0.0345}=\frac{0.0345t}{0.0345} \\ \frac{\ln\frac{P}{71.7}}{0.0345}=t \end{gathered}\)And finally replace P and solve. Remember that P is in thousands of years, so we have to replace it by 350,
\(t=\frac{\ln \frac{350}{71.7}}{0.0345}=45.955\approx46\)This is 46 years after 1970,
\(1970+46=2016\)Let's see what's the population in 2016 to check the answer,
\(P=71.7\cdot e^{0.0345(2016-1970)}\approx350.546\)It is a bit more than 350,000. But let's see what's the population in 2015,
\(P=71.7\cdot e^{0.0345(2015-1970)}\approx338.658\)In 2015 population of the county won't reach 350,000. Thus, the county will have a population of 350,000 in 2016
you are in a boat and concerned about shallow water in a meandering river. where should you aim your boat to find the deepest water?
Answers
You're concerned about the shallow water in the meandering river. The below tips help you navigate the river safely and find the deepest water possible.
Here are some tips to help you find the deepest water:
Look for areas with a sharp bend or a curve in the river. This can indicate a deeper channel where the water flows more swiftly and has a greater depth.
Look for areas with a gradual slope or a drop-off in the riverbed. This can indicate a deeper area where the water flows more slowly and has a greater depth.
Keep an eye out for submerged objects, such as rocks or trees, that may indicate deeper water nearby.
Avoid areas with sandbars, as these can indicate shallow water.
Use your navigation tools, such as a depth sounder or GPS, to help guide you to the deepest water in the river.
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Refraction results from differences in light's
A. Frequency
B. Incident angles
C. Speed
D. All of these
Answers
Answer: A. Frequency
Explanation: The frequency of light remains constant when the light ray is incident on the interface of two media. But light moves at different speeds in different media. As a result, the wavelength of light also changes at the interface. This, in turn, causes a change in direction, which is refraction.
Convert 4 µL to mL
Please help meeeee
Answers
Answer:
0.004
Explanation:
1 micrometer= .001 milimeter
so 4 Micrometers= .004 milimeters
a pilot performs an evasive maneuver by diving vertically at 330 m/s . if he can withstand an acceleration of 9.0 g 's without blacking out, at what altitude must he begin to pull out of the dive to avoid crashing into the sea?
Answers
12100 m is altitude must he begin to pull out of the dive to avoid crashing into the sea
Data given us that,
Velocity = 330 m/s
Acceleration = 9.0g s
centripetal acceleration
a=v^2/r
r=v^2/a
v = velocity
r = altitude
a = acceleration
Put the value
r=108900/9
r=12100 m
Gravity has an impact on how the missile moves vertically. As a result, the vertical component of the starting speed will be 0 at the highest altitude point. The projectile will slow down as it ascends to its highest point, come to a complete halt, and then begin its free fall plummet to the ground.
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Compute the speed of sound in steel rails of a railroad track. The 29.0 x 10 weight density of steel is 49019 fps, and the Young’s modulus of steel is inz. Note: 29.0x 10°in2 = 4176. - 4176.0x10°15/ 1.2 x10* ft's b. 1.4x10* F15 a. c. 1.6x10* ft O‘fs d. 1.8*10*ft
Answers
The speed of sound in steel rails of a railroad track is 1.6x10⁵ ft/s.
The speed of sound in steel rails of a railroad track can be computed using the weight density of steel and the Young's modulus of steel.
The weight density of steel is 49019 fps, which is equivalent to 4176.0x10¹⁵/1.2x10¹⁵ ft's b. The Young's modulus of steel is inz.
To calculate the speed of sound, we use the formula:
speed of sound = √(Young's modulus/weight density).
Plugging in the values, we get:
speed of sound = √(inz/49019) = 1.6x10^5 ft/s.
Therefore, the speed of sound in steel rails of a railroad track is 1.6x10⁵ ft/s.
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A reheat Rankine cycle operates with water as the working fluid. Steam enters the first turbine at 8 MPa and 450°C and exits at 0.8 MPa. It is then reheated to 400°C before entering the second turbine, where it exits at 10 kPa. If the amount of work into the pump is 8.04 kJ/kg and the net work per cycle produced is 1410.25 kJ/kg, determine the thermal efficiency of the cycle
Answers
Answer:
The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%
Explanation:
p₁ = 8 MPa = 80 Bars
T₁ = 450°C = 723.15 K
From steam tables, we have;
v₁ = 0.0381970 m³/kg
h₁ = 3273.23 kJ/kg
s₁ = 6.5577 kJ/(kg·K) = s₂
The p₂ = 0.8 MPa
T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K
h₂ = 2768.30 kJ/kg
\(T_{2'}\) = 400°C = 673.15 K
\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg
p₃ = 10 kPa = 0.1 Bar
T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K
h₃ = 2583.89 kJ/kg
h₄ = \(h_{3f}\) = 191.812 kJ/kg
The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;
\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)
Therefore, we have;
\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)
Which in percentage is 36.81%.
A DC voltage source is connected to a resistor of resistance R and an inductor with inductance L, forming the circuit shown in the figure. For a long time before t=0, the switch has been in the position shown, so that a current I0 has been built up in the circuit by the voltage source. At t=0 the switch is thrown to remove the voltage source from the circuit. This problem concerns the behavior of the current I(t) through the inductor and the voltage V(t) across the inductor at time t after t=0.
A) From t=0 onwards, what happens to the voltage V(t) across the inductor and the current I(t) through the inductor relative to their values prior to t=0?
B) What is the differential equation satisfied by the current I(t) after time t=0?
Express dI(t)dt
in terms of I(t), R, and L.
C) What is the expression for I(t) obtained by solving the differential equation that I(t) satisfies after t=0?
Express your answer in terms of the initial current I0, as well as L, R, and t.
D) What is the time constant τ of this circuit?
Express your answer in terms of L and R?
Answers
A. After t=0, the voltage across the inductor V(t) will increase in the opposite direction to its initial polarity, while the current through the inductor I(t) will decrease exponentially towards zero.
B. The differential equation satisfied by the current I(t) after time t=0 is given by dI(t)/dt = -R/L * I(t), where R is the resistance of the resistor and L is the inductance of the inductor. This equation is obtained from Kirchhoff's voltage law and Faraday's law.
C. The solution to the differential equation is given by I(t) = I0 * exp(-Rt/L), where I0 is the initial current in the circuit at t=0. This equation shows that the current exponentially decays towards zero as time goes on.
D. The time constant τ of the circuit is given by τ = L/R. This represents the time it takes for the current in the circuit to decay to approximately 37% of its initial value.
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For resonance to occur, the object must experience a frequency equal to its what?
period
wavelength
amplitude
natural frequency
Answers
Answer:
natural frequency
Explanation:
Answer: correct answer is {d}
Explanation: i got it right on my assesment
