Answer:
the image because the pre image would be before the image
I roll a fair die twice and obtain two numbers: X 1
= result of the first roll, X 2
= result of the second roll. a. Find the probability that X 2
=4. b. Find the probability that X 1
+X 2
=7. c. Find the probability that X 1
=2 and X 2
≥4. Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same chance of winning the tournament. Team C is twice as likely to win the tournament as team D. The probability that either team A or team C wins the tournament is 0.6. Find the probabilities of each team winning the tournament.
a) The probability that X2 equals 4 is 1/6, or approximately 0.1667.
b) The probability that X1 + X2 equals 7 is 1/6, or approximately 0.1667.
c) The probability that X1 is not equal to 2 and X2 is greater than or equal to 4 is 2/6, or approximately 0.3333.
For the tournament, the probabilities of teams A, B, C, and D winning are 0.3, 0.3, 0.4, and 0, respectively.
a) Since the die is fair, each roll has an equal probability of 1/6 of landing on the number 4. Therefore, the probability that X2 equals 4 is 1/6.
b) To calculate the probability that X1 + X2 equals 7, we need to determine the number of favorable outcomes. The pairs of rolls that sum to 7 are (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1). Since there are six favorable outcomes out of a total of 36 possible outcomes (6 choices for the first roll and 6 choices for the second roll), the probability is 6/36, which simplifies to 1/6.
c) The probability that X1 is not equal to 2 is 5/6, as there are five other outcomes out of six possibilities. The probability that X2 is greater than or equal to 4 is 3/6, as there are three favorable outcomes out of six possibilities. Multiplying these probabilities together gives (5/6) * (3/6) = 15/36, which simplifies to 5/12 or approximately 0.4167. However, the question asks for the probability that X1 is not equal to 2 and X2 is greater than or equal to 4, so we subtract this probability from 1 to get 1 - 5/12 = 7/12 or approximately 0.5833.
For the tournament, let's denote the probability of team A winning as PA, team B winning as PB, team C winning as PC, and team D winning as PD. We are given that PA = PB, PC = 2PD, and PA + PC = 0.6. From this information, we can deduce that PD = 0 (since the sum of all probabilities must equal 1) and PC = 0.4. Substituting this into PA + PC = 0.6, we find PA = 0.2. Since PA = PB, we have PB = 0.2. Thus, the probabilities of teams A, B, C, and D winning the tournament are 0.2, 0.2, 0.4, and 0, respectively.
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what are the greatest common divisors of the following pairs of integers? (a) and answer = (b) and answer = (c) and answer =
The greatest common divisor (GCD) of 24 and 16 is 8. (A)
The GCD of two integers is the largest positive integer that divides both numbers without leaving a remainder. One way to find the GCD of two numbers is to factor both numbers into their prime factors and then find the product of the common prime factors.
In this case, 24 can be factored as 2³ * 3 and 16 can be factored as 2⁴. The largest power of 2 that divides both 24 and 16 is 2³, so the GCD of 24 and 16 is 2³ = 8.
Another way to find the GCD is to use the Euclidean algorithm, which involves repeatedly dividing the larger number by the smaller number and taking the GCD of the smaller number and the remainder until the remainder is 0.
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Complete question:
what are the greatest common divisors of 24,16
A) 8
B) 4
C) 2
D) 1
question 3 please :) (exact values)
Answer:
(a) h = 160 - 5·x
(b) V = 4·x² × h = 4·x² × (160 - 5·x) = 640·x² - 20·x³ = 20·x²·(32 - x)
∴ V = 20·x²·(32 - x)
Step-by-step explanation:
(a) The given dimensions of the cuboid (rectangular prism) are;
'4·x' meters by 'x' meters by 'h' meters
Let the 4·x meters represent the length, 'l', of the cuboid, let the x meters represent the width, 'w', of the cuboid, and let the h meters represent the height 'h' of the cuboid
Therefore, we are given that the cuboid is a wire cage, with the total length of the sides (edges) of the cuboid equal to 640 meters
Therefore, the sum of the edges are;
Top(4·x + x + 4·x + x) + Side(h + h + h + h) + Bottom(4·x + x + 4·x + x) = 640
20·x + 4·h = 640
∴ h = (640 - 20·x)/4 = 160 - 5·x
h = 160 - 5·x
(b) The volume of a cuboid, V, is given as follows;
V = The area of the base of the cuboid × The height of the cuboid
The area of the base of the cuboid = l × w = 4·x × x = 4·x²
The height of the cuboid = h = 160 - 5·x
∴ V = 4·x² × (160 - 5·x) = 640·x² - 20·x³
V = 640·x² - 20·x³ = 20·x²·(32 - x)
∴ V = 20·x²·(32 - x) QED.
Un barco navega 300 km al oeste, después 100 km al sur, al final de su viaje, que tan lejos está de su posición inicial? Elabora en tu libreta el dibujo y resuelve.
Answer: 400 KL you have to add 300 KL + 100 KL = 400 KL
3- Find all values of Z such that e² = 2+i√3
The values of Z such that e² = 2 + i√3 are Z = ln(2 + i√3) + 2πik, where k is an integer.
To find the values of Z, we can start by expressing 2 + i√3 in polar form. Let's denote it as re^(iθ), where r is the modulus and θ is the argument.
Given: 2 + i√3
To find r, we can use the modulus formula:
r = sqrt(a^2 + b^2)
= sqrt(2^2 + (√3)^2)
= sqrt(4 + 3)
= sqrt(7)
To find θ, we can use the argument formula:
θ = arctan(b/a)
= arctan(√3/2)
= π/3
So, we can express 2 + i√3 as sqrt(7)e^(iπ/3).
Now, we can find the values of Z by taking the natural logarithm (ln) of sqrt(7)e^(iπ/3) and adding 2πik, where k is an integer. This is due to the periodicity of the logarithmic function.
ln(sqrt(7)e^(iπ/3)) = ln(sqrt(7)) + i(π/3) + 2πik
Therefore, the values of Z are:
Z = ln(2 + i√3) + 2πik, where k is an integer.
The values of Z such that e² = 2 + i√3 are Z = ln(2 + i√3) + 2πik, where k is an integer.
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Question 13IT, pre calc, I am at work so please answer so I can review it later tonight, thanks
EXPLANATION
Dividing the numerator and denominator by the highest denominator power (x^2):
\(=\lim _{x\to\: -\infty\: }\mleft(\frac{\frac{1}{x}+\frac{1}{x^2}}{1-\frac{2}{x}}\mright)\)Applying the following property:
\(\lim _{x\to a}\mleft[\frac{f\left(x\right)}{g\left(x\right)}\mright]=\frac{\lim_{x\to a}f\left(x\right)}{\lim_{x\to a}g\left(x\right)},\: \quad \lim _{x\to a}g\mleft(x\mright)\ne0\)\(With\: the\: exception\: of\: indeterminate\: form\)\(=\frac{\lim_{x\to\:-\infty\:}\left(\frac{1}{x}+\frac{1}{x^2}\right)}{\lim_{x\to\:-\infty\:}\left(1-\frac{2}{x}\right)}\)\(=\frac{\lim_{x\to\: -\infty\: }(\frac{1}{x}+\frac{1}{x^2})}{\lim_{x\to\: -\infty\: }(1-\frac{2}{x})}=\frac{0}{1}=0\)Now, we need to apply the same steps to x-> ∞
\(\mathrm{Apply\: the\: following\: algebraic\: property}\colon\quad a+b=a\mleft(1+\frac{b}{a}\mright)\)\(\frac{x+1}{x^2-2x}=\frac{x\left(1+\frac{1}{x}\right)}{x^2\left(1-\frac{2}{x}\right)}\)\(=\lim _{x\to\infty\: }\mleft(\frac{x\left(1+\frac{1}{x}\right)}{x^2\left(1-\frac{2}{x}\right)}\mright)\)Simplifying:
\(=\lim _{x\to\infty\: }\mleft(\frac{1+\frac{1}{x}}{-2+x}\mright)\)\(\lim _{x\to a}\mleft[\frac{f\left(x\right)}{g\left(x\right)}\mright]=\frac{\lim_{x\to a}f\left(x\right)}{\lim_{x\to a}g\left(x\right)},\: \quad \lim _{x\to a}g\mleft(x\mright)\ne0\)\(\mathrm{With\: the\: exception\: of\: indeterminate\: form}\)\(=\frac{\lim_{x\to\infty\:}\left(1+\frac{1}{x}\right)}{\lim_{x\to\infty\:}\left(-2+x\right)}\)\(=\frac{1}{\infty\:}\)\(\mathrm{Apply\: Infinity\: Property\colon}\: \frac{c}{\infty}=0\)\(=0\)In conclusion, the appropiate end behavior is as follows:
\(\lim _{x\to-\infty}f(x)=0;\text{ }lim_{x\to\infty}f(x)=0\)Which relation is also a function?
Answer:
D because if you graphed the others they wouldn't pass the vertical line test
What is the value of x in the equation 3x-4y=65, when y=4?
x=134
O x=21 / 3
O x=23
X=27
Answer:
\( \boxed{ \bold{ \huge{ \boxed { \sf{x = 27}}}}}\)
Step-by-step explanation:
Given, value of y = 4
To find : Value of x
\( \sf{3x - 4y = 65}\)
plug the value of y
\( \dashrightarrow{ \sf{3x - 4 \times 4 = 65}}\)
Multiply the numbers : 4 and 4
\( \dashrightarrow{ \sf{3x - 16 = 65}}\)
Move 16 to right hand side and change it's sign
\( \dashrightarrow{ \sf{3x = 65 + 16}}\)
Add the numbers : 65 and 16
\( \dashrightarrow{ \sf{3x = 81}}\)
Divide both sides by 3
\( \dashrightarrow{ \sf{ \frac{3x}{3} = \frac{81}{3} }}\)
Calculate
\( \dashrightarrow{ \sf{ x = 27}}\)
Hope I helped!
Best regards! :D
Answer:
Step-by-step explanation:
-4 x 4=-16 so you add the 16 to the 65 and get 81 so then you divide the 3 from the x so it would be 81/3=27
Use the function boxplot to draw a box plot of the rear width (the variable RW) by species (the variable sp). Attach your R code.
In the box plot you made above, on the x-axis you should see two tick labels B and 0 . Which of the following argument can be used to adjust the size of them? (These arguments all accept numerical values.)
(A) 1ty (B) Iwd (C) cex. 1ab (D) cex.axis
The argument can be used to adjust the size of the two tick labels B and 0 on the x-axis is cex.axis of the boxplot. Option D is the correct choice.
To create a boxplot of rear width (RW) by species (sp) using the boxplot function in R, you can use the following R code:
```R
boxplot(RW ~ sp, data = your_data)
```
In this code, replace 'your_data' with the name of your data frame containing the variables RW and sp.
Regarding the options for adjusting the size of the tick labels (B and 0) on the x-axis, the correct argument is (D) cex.axis. You can use this argument to set the size of the tick labels as follows:
```R
boxplot(RW ~ sp, data = your_data, cex.axis = desired_size)
```
Replace 'desired_size' with a numerical value to set the size of the tick labels.
The answer is: (D) cex.axis
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Given the parent function f(x) = 2x, which graph shows f(x) − 1? Group of answer choices exponential function going through point 0, 2 and ending up on the right exponential function going through point 0, 0 and ending down on the right exponential function going through point 0, 0 and ending up on the right exponential function going through point 0, 1.5 and ending up on the right
Answer:exponential function going through point 0, 0 and ending up on the right
explain what the error is? and explain how we can fix the error. b. what would be the output after removing the error? cone vol
The output of the code after removing the error is the volume of the cone which is a number. The formula for calculating the volume of a cone is:
Volume of a cone = 1/3 x π x r2 x h
Where r is the radius of the base of the cone and h is the height of the cone.
The formula is implemented in the code to calculate the volume of the cone. The variables radius and height are given values of 5 and 10 respectively. The formula is then used to calculate the volume of the cone and stored in the variable volume. The volume is then displayed on the webpage using the document.write function. The result will be displayed as "The volume of the cone is X" where X is the calculated volume of the cone in units cubed.
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It costs $0.50 to buy 1/3 lb of pears. What is the unit rate for the cost per pound.
The unit cost of pears is $1.50 per pound.
What is ratio?Ratio basically compares quantities, that means it show value of one quantity with respect to other quantity.
If a and b are two values, their ratio will be a:b,
Given that,
Cost for 1/3 lb of pears = $0.50
Since, 1 lb = 1 pound
Implies that,
Cost of 1/3 pounds of pears = $0.50
To find the cost of one pound of pears,
Use ratio property,
1/3 pound costs = 0.50
1 pound costs = 0.50 x 3 = $1.50
The cost of one pound of pear is $1,.50.
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Your bank account pays daily interest with an APR of 4.5%. what
is the EAR?
The effective annual rate (EAR) of a bank account that pays daily interest with an APR of 4.5% is 4.67%.
The EAR is calculated using the following formula:
\(\begin{equation}EAR = (1 + \frac{APR}{n})^n - 1\end{equation}\)
Where:
EAR is the effective annual rate
APR is the annual percentage rate
n is the number of compounding periods per year
In this case, the APR is 4.5% and the number of compounding periods per year is 365. Plugging these values into the formula, we get:
\(\begin{equation}EAR = (1 + \frac{0.045}{365})^{365} - 1\end{equation}\)
EAR = 4.67%
Therefore, the EAR is 4.67%. This means that if you deposit $100 in an account that pays daily interest with an APR of 4.5%, you will have $104.67 at the end of the year.
It is important to note that the EAR is always higher than the APR. This is because compounding allows you to earn interest on your interest. For example, if you deposit $100 at an APR of 4.5%, you will earn $4.50 in interest in one year.
However, if your account compounds daily, you will earn interest on the interest that you earn each day. This means that you will earn more than $4.50 in interest in one year.
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Find the indicated segment.
(3x + 4) (x + 12)
Answer:
Step-by-step explanation:
i'm kinda bad at math but i think it's 9=9 or x+26. i'm not sure.try x+26 you can see if i'm incorrect or correct. i only gave you the 2 answer's i'm sure of well god bless :DWhat is the value of x?
Enter your answer in the box.
x =
Answer:
x = 4
I hope this helps
Please help!
Four more than twice a number is –10.
(I have 15 mins!)
Answer: -7
Step-by-step explanation:
2X + 4= -10
2X= -10 -4
2X= -14
X= -7
evaluate the triple integral xzdv where e = (xyz) 0
The integral is equal to the volume of the region defined by the limits of integration. The integral can be written as xzdv where e=(xyz) 0. This means that the integral is the volume of the region in the xyz-space bounded by the surfaces x=0, y=0, and z=0.
Solve for the limits of integration in terms of x, y, and z.Substitute the limits of integration into the integral.Integrate with respect to x, then y, then z.Evaluate the integral.The triple integral xzdv where e=(xyz) 0 is an integration of a function with respect to three variables over a three-dimensional region. This type of integral is used to calculate the volume of the region defined by the limits of integration. To solve this integral, the limits of integration must first be determined. This is achieved by solving for the values of x, y, and z which limit the region. Once the limits of integration have been determined, they can be substituted into the integral. Then, the integral is integrated with respect to x, then y, then z. Finally, the integral is evaluated to determine the volume of the region. The triple integral is a useful tool in physics, engineering, and mathematics, and can be used to solve a variety of problems.
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The angle of the roof on a shed is 23 degrees. the shed is 8 metres wide and the walls are 3 metres high. Find the length, y, of one side of the roof
According to the question and after using the Pythagorean theorem the length of one side of the roof is 7.416 metres.
What is Pythagorean theorem?The Pythagorean Theorem is a mathematical formula used to determine the length of the sides of a right triangle. It is named after the Greek mathematician Pythagoras, who is credited with discovering the formula in the 6th century BC. The theorem states that the sum of the squares of the two shorter sides of the triangle is equal to the square of the hypotenuse (the longest side of the triangle). In equation form, it is expressed as a² + b² = c², where a and b are the lengths of the two shorter sides of the triangle and c is the length of the hypotenuse.
We know that the hypotenuse is 8 metres (the width of the shed) and the two shorter sides are 3 metres (the height of the walls) and y (the length of the side of the roof).
Therefore, using the Pythagorean theorem, we have:
3² + y² = 8²
9 + y² = 64
y² = 55
y = √55
y = 7.416 metres
Therefore, the length of one side of the roof is 7.416 metres.
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Need help on this asap!! Also Thank you in advance!!
Answer:
50/sin90=x/sin45
x=35.36cm
-16 times 10^6x =-80
The solution to the equation -16 * 10^6x = -80 is x = 0.000005.
To solve the equation -16 * 10^6x = -80, we can start by simplifying the equation and isolating the variable x.
First, let's simplify the equation:
-16 * 10^6x = -80
To simplify, we can divide both sides of the equation by -16:
(10^6x) = (-80) / (-16)
Dividing -80 by -16 gives us a positive value:
(10^6x) = 5
To solve for x, we need to get rid of the exponent 10^6. We can rewrite 10^6 as 1,000,000:
1,000,000x = 5
Now, divide both sides of the equation by 1,000,000 to isolate x:
x = 5 / 1,000,000
Simplifying the right side gives us:
x = 0.000005
In scientific notation, the solution can be expressed as x = 5 * 10^(-6), where the exponent -6 indicates the number of decimal places to move the decimal point to the left. So, x = 0.000005 and x = 5 * 10^(-6) represent the same value.
It's important to note that the solution provided assumes a standard interpretation of the equation and the order of operations. If there are any additional constraints or context not mentioned in the question, they should be considered in the solution process.
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help asap pls ----------------------------------- Also tell me the graph from the second/third photo not the equation
Answer:
graph "B"
at 0 graph = -1200 that is the production cost
Step-by-step explanation:
(a+b)^2
(a+b)^2
(a+b)^2
(a+b)^2
Answer:
a^2 + 2ab + b^2
Step-by-step explanation:
student x pushes a 10-n box with a force of 2 n. at the same time, student y pushes the same box with a force of 6 n, but in the opposite direction. which would most likely occur? (ignore friction.)
Find the height of the tree in feet
The height of the tree in feet is 62 .
What is the height of the tree?Two triangles are similar if their corresponding angles are congruent and corresponding sides are proportional.
From the diagram:
Leg 1 of the smaller triangle = 5ft 2in = ( 5×12 + 12 )in = 62 in
Leg 2 of the smaller triangle = 10ft ( 10 × 12 ) = 120in
Leg 1 of the larger triangle = x
Leg 2 of the larger triangle = 120 ft = ( 120 × 12 )in = 1440 in
Since the corresponding sides of similar triangles are proportional.
We take equate their ratios
62/120 = x/1440
Solve for x
120x = 62 × 1440
120x = 89280
x = 89280/120
x = 744in
Convert back to feet
x = ( 744 ÷ 12 ) ft
x = 62 ft
Therefore, the value of x is 62 feets.
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Use the quadratic equation x^2 - 22x = 75 to answer the following question.
suppose an equivalent quadratic equation is written: x^2 -22x + c = 75 + c. what value of "c" would make the equation a perfect square trinomial.
The value of c=121 would make the equation a perfect square trinomial.
A quadratic equation is a second-order polynomial equation in a single variable x ax2+bx+c=0. with a ≠ 0
Standard Form: y = ax²+bx+cy=ax²+bx+c y=ax²+bx+c.
We have the equation x²-22x=75
The quadratic equation is written: x² -22x + c = 75 + c.
We want to make this into a perfect square, and suppose we choose the value of k such that:
x²-22x+c=(x+k)²
x²-22x+c=x²+2k+k²
Comparing the coefficient of x we have:
2k=−22⇒k=−11
And comparing constant coefficients we have:
c=k²⇒c=121
Hence If we choose c=121then we can write
x²−22x+121=(x−11)²
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State the domain of the rational function f(x)= 13/2 - x
Answer:
este egal cu 10 cu placere
10 = g - 19. Please help!!!
Answer: g = 29
10 = g - 19
add 19 to both sides:
29 = g
flip if u want
g = 29
hope this helped :)
Please help me with this
Answer:
1 and 4
Step-by-step explanation:
(x²+1)(x²-4) = x^4 -3x²-4
The green blank is 1 and the blue/purple is 4.
Hope this helped and brainliest please
The football player had an 80 yard gain on the play. Answer with integer(s)
from a population with a variance of 484, a sample of 256 items is selected. at 95% confidence, the margin of error is group of answer choices 16. 1.375. 2.695. 22.
The margin of error is 2.695 for a sample size of 256 and a population variance of 484 at a 95% confidence level.
To find the margin of error, we need to use the formula:
Margin of error = z* (sigma / sqrt(n))
Where z* is the z-score corresponding to the desired confidence level, sigma is the population standard deviation, and n is the sample size.
In this case, we know that the population variance (sigma^2) is 484, which means the standard deviation (sigma) is sqrt(484) = 22.
The sample size (n) is 256.
The confidence level is 95%, which means the z-score is 1.96.
So, plugging these values into the formula, we get:
Margin of error = 1.96 * (22 / sqrt(256))
Simplifying, we get:
Margin of error = 1.96 * (22 / 16)
Margin of error = 2.695
Hence, we use the formula Margin of error = z* (sigma / sqrt(n)), where z* is the z-score corresponding to the desired confidence level, sigma is the population standard deviation, and n is the sample size. The margin of error is 2.695 for a sample size of 256 and a population variance of 484 at a 95% confidence level.
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