Answer:
60 kmExplanation:
velocity = 30 km/hr.
time = 2 hr.
distance = velocity x time
= 30 km/hr. x 2 hr
= 60 km
The value of the surface area of the cylinder is equal to the value of the volume of the cylinder. Find the value of x.
The volume of a cylinder is given by the formula v=pi r^2h, where r is the radius of the cylinder and h is the height.
What Does a Cylinder's Surface Area Look Like?The overall area or region that the surface of a cylinder covers is referred to as its surface area. A cylinder's total surface area includes both the area of the curved surface and the area of the two flat surfaces because there are two flat surfaces and one curved surface. A cylinder's surface area is measured in square units like m2, in2, cm2, yd2, etc.
What is the cylinder's total surface area?The sum of the curved surface areas makes up the cylinder's overall surface area.
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All of the following elements are in the same group except...
nitrogen
selenium
sulfur
oxygen
Answer:
B
Explanation:
selenium is the right answer.
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What will happen if you heat a liquid to high temperatures?
It will become a solid.
It will become a plasma.
It will become a gas.
It will become a colloid.
Answer:
it becomes a gas
Explanation:
the matter expands, turning into steam, a gas.
A ball is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s. Calculate the vertical component of the velocity on getting to the ground
A ball when is projected horizontally from the top of a vertical cliff 40m high with a velocity of 20m/s, the vertical component of the velocity on getting to the ground is 28.3 m/s.
What is motion under gravitational field?When any object moves, it can be said to be in motion under gravity because gravity has an impact on the object’s vertical motion. Gravity is also called as the force that pulls things downward. In actuality, gravity pulls objects toward the Earth’s center.
What is the motion under gravity equation?The particle’s initial velocity is 0 during free fall. Consequently, this v=gt is the equation of motion.
An object launched into the air may also experience a shift in upward velocity due to gravity, which causes it to slow down and return to Earth’s surface. The Moon is kept in orbit by the force of Earth’s gravity, which also causes the Moon to rotate constantly.
Initial horizontal velocity = 20\(ms^{-1}\)
Initial vertical velocity = 0
Vy= Uy + gt
Vy= gt {Uy= 0}
Vy= 10 × 2.83= 28.3m/s
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a 3.0-pf capacitor is connected in series with a 4.0-f capacitor and a 48-v battery. what quantity of charge is supplied by the battery to charge the capacitors?
8.2 X \(10^{5}\)C quantity of charge is supplied by the battery to charge the capacitors.
\(C_{net } = \frac{C_{1} C_{2} }{C_{1} +C_{2} }\)
= \(\frac{3\times 4}{3+4}\)
= 12/17
= 1.714μ F
Q = CV
= 1.714x \(10^{6}\) F X 48V
= 82.27x \(10^{6}\)C
= 8.2 X \(10^{5}\)C
What is capacitor?A two-terminal electrical device known as a capacitor is capable of storing energy in the form of an electric charge. It is made up of two electrical wires that are spaced apart by a certain amount. Suction may be used to fill the space between the conductors, or a dielectric, an insulating substance, may be used instead. Capacitance is the term used to describe a capacitor's capacity to hold charges.
Pairs of opposing charges are held apart in capacitors to retain energy. A parallel plate capacitor has the most basic construction and is made up of two metal plates with a space in between them. However, many capacitor types are produced in a wide variety of shapes, sizes, lengths, girths, and materials.
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A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is moving at a velocity of –7 m/s. After colliding, the 35-gram ball moves at a velocity of –15 m/s. Assume there is no net force on the system.
What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth.
Explanation:
the answer is in the above image
Given:
mass of first ball, m1 = 35g
mass of second ball, m2 = 75g
velocity of first ball before collision, u1 = 9m/s
velocity of second ball before collision, u2 = -7m/s
velocity of first ball after collision, v1 = -15m/s
velocity of second ball after collision, v2 = ? (To Find)
Now it is given that there is no net force on the system of two balls
according to the Law of Conservation of Momentum so, here momentum is constant before and after collision:
P1 = P2
m1u1 + m2u2 = m1v1 + m2v2
35g*9m/s + 75g*(-7m/s) = 35g*(-15m/s) + 75g*v2
v2 = (35g*9m/s + 75g*(-7m/s) - 35g*(-15m/s))/75g
v2 = 4.2m/s
therefore, the velocity of second ball after collision is 4.2m/s
What is the formula of conservation of momentum?
As a result, the equation of the law of conservation of momentum is as follows: m1 u1 + m2 u2 represents the total momentum of particles A and B before the collision, and m1 v1 + m2 v2 represents the total momentum of particles A and B after the collision.
What is momentum unit?Momentum. If the mass of an object is m and it has a velocity v, then the momentum of the object is defined to be its mass multiplied by its velocity. momentum = mv. Momentum has both magnitude and direction and thus is a vector quantity. The units of momentum are kg m s−1 or newton seconds, N s.
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Decide which physical states are indicated in the following statement. Choose all that apply. Particles are in motion. a) solid. b) liquid. c) gas. d) none of these.
The given statement “Particles are in motion” is indicating that particles have kinetic energy and are moving. Hence, this statement is not indicating a specific state of matter. Hence, None of these. is the right option.
However, based on the states of matter, we can say that the motion of the particles depends on the physical state of matter. The three states of matter are:
Solid: In this state of matter, the particles have the least amount of kinetic energy and are held tightly in their positions by intermolecular forces. As a result, they are only capable of vibrating around their mean positions. The vibrations increase with an increase in temperature.
Liquid: In this state of matter, the particles have more kinetic energy than solids and are held together by relatively weaker intermolecular forces. The particles in the liquid are constantly in motion, which allows them to slide past one another and take the shape of the container that they are in. As temperature rises, the kinetic energy also increases.
Gas: In this state of matter, the particles have the highest amount of kinetic energy and are held together by the weakest intermolecular forces. The particles are in constant, random motion and are free to move in any direction. This gives them the ability to take up all the available space in a container.
The question should be:
Decide which physical states are indicated in the following statement. "Particles are in motion" Choose all that apply. Particles are in motion. a) solid. b) liquid. c) gas. d) none of these.
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a 78.0 kg ice hockey goalie, originally at rest, catches a 0.150 kg hockey puck slapped at him at a velocity of 34.0 m/s. suppose the goalie and the ice puck have an elastic collision and the puck is reflected back in the direction from which it came. what would their final velocities (in m/s) be in this case? (assume the original direction of the ice puck toward the goalie is in the positive direction. indicate the direction with the sign of your answer.)
In an elastic collision between a hockey goalie and a hockey puck, the final velocities of both objects can be calculated. The goalie, initially at rest, catches the 0.150 kg hockey puck slapped at him at a velocity of 34.0 m/s. After the collision, the puck is reflected back in the opposite direction.
In an elastic collision, both momentum and kinetic energy are conserved. We can use the principles of conservation of momentum and kinetic energy to solve for the final velocities. Since the goalie is initially at rest, their final velocity will depend on the mass and velocity of the puck. By setting up momentum and kinetic energy equations and solving them simultaneously, we can calculate the final velocities. The goalie's final velocity will be in the opposite direction of the initial puck velocity, indicated by the negative sign.
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Suppose that the tires are capable of exerting a maximum net friction force of 626 lb. If the car is traveling at 52. 5 ft/s , what is the minimum curvature of the road that will allow the car to accelerate at 3. 65 ft/s2 without sliding? The weight of the car is 3250 lbs
The minimum curvature of the road that will allow the car to accelerate at 3.65 ft/s² without sliding is approximately 0.1287 ft⁻¹.
To determine the minimum curvature, we need to consider the centripetal force required to keep the car on the road without sliding. This force is provided by the friction force between the tires and the road.
The centripetal force (Fc) can be calculated using the following formula:
Fc = m * a
where m is the mass of the car and a is the centripetal acceleration.
Given:
Mass of the car (m) = 3250 lbs
Centripetal acceleration (a) = 3.65 ft/s²
To convert the mass from pounds to slugs (the unit used for the English system in calculations involving force), we divide by the acceleration due to gravity (32.2 ft/s²):
m = 3250 lbs / 32.2 ft/s²
m ≈ 100.9322 slugs
The centripetal force is equal to the net friction force (F) exerted by the tires on the road:
F = 626 lbs
The centripetal force can also be expressed as:
F = m * a
Solving for the radius of curvature (R):
R = v² / (g * tan(θ))
where v is the velocity of the car, g is the acceleration due to gravity, and θ is the angle of banking or curvature.
Given:
Velocity (v) = 52.5 ft/s
Acceleration due to gravity (g) = 32.2 ft/s²
Plugging in the values and rearranging the equation, we can solve for the minimum curvature (θ):
θ = atan(v² / (g * R))
θ ≈ atan((52.5 ft/s)² / (32.2 ft/s² * R))
Substituting the values and solving for θ:
θ ≈ atan(2756.25 / (32.2 * R))
To find the minimum curvature, we need to find the value of R that satisfies the equation above when θ = 0. This means the car is not banking and the entire centripetal force is provided by friction.
After performing the calculations, the minimum curvature of the road that will allow the car to accelerate at 3.65 ft/s² without sliding is approximately 0.1287 ft⁻¹.
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the power absorbed by a resistor is 1 w. if the current through the resistor is doubled, what will be the power absorbed by the resistor?
When the current through a resistor is doubled, the power absorbed by the resistor will increase by a factor of four. So, if the power absorbed by the resistor is initially 1 W, it will become 4 W when the current is doubled.
Current is the pace of stream of positive charge. The movement of electrons, ions, or other charged particles can result in current. Since electrons have a negative charge, they move in the opposite direction of current.
Current is typically signified by the image I. Ohm's regulation relates the ongoing coursing through a guide to the voltage V and obstruction R; thus, V equals IR. An elective assertion of Ohm's regulation is I = V/R.
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how do you think the angle of the plate will affect how much sunlight hits the plate?
The angle of the plate will affect how much sunlight hits the plate. The amount of sunlight that hits a surface depends on the angle of incidence, which is the angle at which the sunlight hits the surface. When the angle of incidence is perpendicular to the surface (i.e., the sun is directly overhead), the maximum amount of sunlight is received by the surface.
However, as the angle of incidence increases, the amount of sunlight that hits the surface decreases because the same amount of sunlight is spread over a larger area. Therefore, if the plate is not angled properly to face the sun, it will receive less sunlight, which will affect its efficiency in converting sunlight into electricity.
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A student applies a force of 50N to compress the spring in a marble launcher. The spring has a spring constant of 500N/m. The launcher is used to launch a 0. 005kg marble horizontally. The marble is launched from a height of 1. 25m. A. How far does the student compress the spring? (0. 1m) b. What is the velocity of the marble when it is launched? (31. 6m/s, yes this is unrealistically fast) c. How far away from the base of the launcher does the marble land? (15. 96m)
a. The student compresses the spring by approximately 0.1 meters. b. The velocity of the marble when it is launched is approximately 31.6 m/s. c. The marble lands approximately 15.96 meters away from the base of the launcher.
a. To determine the distance the student compresses the spring, we can use Hooke's Law, which states that the force required to compress or extend a spring is proportional to the displacement. The formula is:
\(F = k * x\)
Where F is the force applied, k is the spring constant, and x is the displacement.
Rearranging the formula to solve for x, we have:
x = F / k
Plugging in the given values, we get:
x = 50 N / 500 N/m = 0.1 m
Therefore, the student compresses the spring by approximately 0.1 meters.
b. To calculate the velocity of the marble when it is launched, we can use the principle of conservation of energy. The potential energy stored in the compressed spring is converted into kinetic energy of the marble. The formula for kinetic energy is:
\(KE = (1/2) * m * v^2\)
Where KE is the kinetic energy, m is the mass of the marble, and v is the velocity.
Setting the initial potential energy of the spring equal to the final kinetic energy of the marble, we have:
Simplifying the equation and solving for v, we get:
\(v = \sqrt{((k * x^2) / m)}\)
Plugging in the given values, we get:
v = √((500 N/m * (0.1 m)²) / 0.005 kg) ≈ 31.6 m/s
Therefore, the velocity of the marble when it is launched is approximately 31.6 m/s.
c. To determine the distance the marble lands from the base of the launcher, we can use the equations of motion. Since the marble is launched horizontally, the only force acting on it is the force of gravity in the vertical direction. The equation for the horizontal distance traveled is:
\(d = v * t\)
Where d is the distance, v is the horizontal velocity, and t is the time of flight.
To calculate the time of flight, we can use the equation:
t = √((2 * h) / g)
Where h is the initial height and g is the acceleration due to gravity.
Plugging in the given values, we get:
t = √((2 * 1.25 m) / 9.8 m/s²) ≈ 0.504 s
Finally, we can calculate the horizontal distance:
\(d = v * t\)= 31.6 m/s * 0.504 s ≈ 15.96 m
Therefore, the marble lands approximately 15.96 meters away from the base of the launcher.
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A 70 kg astronaut floating in an orbiting space station throws a 1.0 kg water bottle across the room at the speed of 8 m/s. How much force did it take to move the bottle?
Answer:
Explanation:
According to Newton's third law of motion, every action has an equal and opposite reaction. When the astronaut throws the water bottle, the bottle exerts a force on the astronaut in the opposite direction. Therefore, we can consider the force exerted on the water bottle to be equal in magnitude to the force exerted on the astronaut in the opposite direction.
To calculate the force exerted on the water bottle, we can use the formula:
Force = mass x acceleration
The mass of the water bottle is 1.0 kg, and its initial speed is 8 m/s. We can assume that the space station is in a state of free-fall, which means that the acceleration due to gravity is negligible.
Therefore, the force required to move the water bottle is:
Force = mass x acceleration
= 1.0 kg x 8 m/s
= 8 N
Therefore, it took a force of 8 Newtons to move the water bottle.
Convertir 1200 ms a cs
Convertir 0,3 mm a cm.
Answer:
You can do the reverse unit conversion from cm/s to m/s, or enter any two units below: Metre per second (U.S. spelling: meter per second) is an SI derived unit of both speed (scalar) and velocity (vector quantity which specifies both magnitude and a specific direction), defined by distance in metres divided by time in seconds.
Explanation:
--Calculate the density rho1 of the aluminum block using equation (3) in the lab manual:
--Calculate the density rho2 of the aluminum block directly using rho = m/v, where m is the mass of the object and V is the volume of the displaced water:
--Compare the average of these two calculated values of aluminum density with the known one, rhoAl = 2.7 g/cm3:
Object
Weight on digital scale (N)
Weight T1 (air) (N)
Weight T2 (submerged) (N)
Displaced water weight (N)
Displaced water volume (cm3)
Cork
0.71
0.71
0
1.69
60 mL/cm3
Aluminum
3.70
3.70
2.35
2.35
140 mL/cm3
Cork + Al
4.41
4.41
0.1
5.29
440 mL/cm3
Cork + ???
3.86
3.86
0
4.86
398 mL/cm3
****The middle column states the weight of submerged item. The item is fully submerged in this case.****
The density ρ1 of aluminium block = 1.35 g/cm³
The density ρ2 of aluminium block = 0.96 g/cm³
Weight on digital scale (N) = 3.70 N
Weight T1 (air) (N) = 3.70 N
Weight T2 (submerged) (N) = 2.35 N
Displaced water weight (N) = 2.35 N
Displaced water volume (cm³) = 140 mL/cm³
Density of aluminum = ρAl = 2.7 g/cm³
Density (ρ) is defined as the mass per unit volume of a substance. It is usually expressed in grams per cubic centimeter or kilograms per cubic meter.
The equation (3) in the lab manual is expressed as;
ρ1 = ρwater(W1 - W2) / (W2 - W3) where,
ρwater = Density of water
W1 = Weight on digital scale (in air)
W2 = Weight on digital scale (in water)
W3 = Weight of the displaced water
ρ1 = ρAl is the density of the aluminum block
Substituting the given values,
ρ1 = 1 g/cm³ (3.70 N - 2.35 N) / (2.35 N - 0 N)
ρ1 = 1.35 g/cm³
Hence, the density of aluminum block using equation (3) in the lab manual is 1.35 g/cm³
ρ2 = m / V where,
m = Weight in air - Weight in water (displaced water weight)
V = Displaced water volume
Substituting the given values,
ρ2 = (3.70 N - 2.35 N) / (140 mL/cm³)
ρ2 = 0.96 g/cm³
Average Density of aluminum = (1.35 g/cm³ + 0.96 g/cm³) / 2 = 1.155 g/cm³
% Error = [(ρAl - ρavg) / ρAl] × 100%
Substituting the given values,
% Error = [(2.7 - 1.155) / 2.7] × 100% = 57.22 %
Hence, the % Error in the density of the aluminum block is 57.22%.
Therefore, the calculation of the density rho1 of the aluminum block using equation (3) in the lab manual, calculation of the density rho2 of the aluminum block directly using rho = m/v and comparing the average of these two calculated values of aluminum density with the known one, rhoAl = 2.7 g/cm3 has been done.
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Explain why gravitational force is an inverse square law force.
Answer:
The inverse square law proposed by Newton suggests that the force of gravity acting between any two objects is inversely proportional to the square of the separation distance between the object's centers. Altering the separation distance (d) results in an alteration in the force of gravity acting between the objects.
Explanation:
what kinds of forces are thought to hold microtubular structure together?
Microtubular structures are primarily held together by noncovalent forces, specifically electrostatic interactions and Van der Waals forces.
What is Microtubular structures?
Microtubular structures are cylindrical, hollow structures composed of protein subunits called tubulins. They are a component of the cytoskeleton, a network of filaments and fibers found in the cells of eukaryotic organisms. Microtubules have a range of important functions within cells and are involved in various cellular processes.
Microtubules are cylindrical structures composed of tubulin protein subunits. The stability and integrity of microtubules rely on the interaction forces between these subunits.
Electrostatic interactions play a significant role in holding microtubular structures together. The tubulin subunits contain charged amino acid residues that can attract or repel each other based on their electrostatic charges. These electrostatic forces contribute to the alignment and arrangement of tubulin subunits, promoting the formation and stability of microtubules.
Van der Waals forces also contribute to the cohesion of microtubular structures. Van der Waals forces are weak attractive forces between molecules or atoms resulting from temporary fluctuations in electron distribution. These forces help maintain the close packing and organization of tubulin subunits within the microtubule.
Together, these noncovalent forces, specifically electrostatic interactions and Van der Waals forces, play crucial roles in holding microtubular structures together and ensuring their stability and functionality.
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a computer monitor has a power rating of 0.240 kw?
Why is electrical energy considered as potential energy as its the energy of moving electrons?
Answer:
Explanation: When the electrons move in another direction, they convert this chemical potential energy to electricity in the circuit, thus discharging the battery. So, the battery is all potential energy.
Answer:
because when it is in the electrical state it isn't really doing much. like a battery. it isn't making light, heat, sound, our movement. thus it is potential energy. like a compressed spring its holding energy ready to be used but it is not using it. hope that helped you.
Define Impulse And Momentum
Plsss Answer Now I Need Now
Answer:
Impulse-The effect of force acting over time to change the momentum of an object.
momentum-The product of mass of a particle and its velocity.
True or false: " The rotation of the earth and revolution of the earth mean essentially the same thing."
Answer:
FALSE
Explanation:
Rotation is spinning on its axis
Revolution is spinning around the sun
What is the period of a satellite in a circular orbit just above the surface of the Moon? The Moon’s mass is 7.36 × 1022 kilograms and its radius is 1.738 × 106 meters.
Answer:
F / m = a = G M / R^2 formula for gravitational attraction
a = ω^2 R formula for centripetal force for an object with radius R
G M / R^2 = ω^2 R equating accelerations
ω = (G M / R^3)^1/2
ω = 2 pi f = 2 pi / P for circular motion
P = 2 pi (R^3 / (G M))^1/2
R^3 / (G M) = (1.738E6)^3 / (6.67E-11 * 7.36E22) = 1.07E6
P = 6.28 * 1034 sec = 6500 sec = 1.80 hrs
A group of friends push a van, using a total force of 220 N. The van moves a distance of 0.2 m. How much work have they done?
Answer:
44
Explanation:
Work = Force X Distance
what is the acceleration of a ball that has dropped from a six-story building
Answer:
Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.
That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.
Explanation:
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what is the gain in gpe when a brick of 2.00 kg is lifted up by 11.5 m
[ HELP NEEDED URGENTLY
Answer:
E = 225.4 J
Explanation:
Given that,
The mass of a brick, m = 2 kg
It is lifted up by 11.5 m
We need to find the gain in gravitational potential energy. The formula for gravitational potential energy is given by :
\(E=mgh\\\\E=2\times 9.8\times 11.5\\\\E=225.4\ J\)
So, the gain in gravitational potential energy is 225.4 J.
What is the velocity of a rocket traveling at as it goes to outer space; traveling a distance of 100 meters in 50 seconds
Based on the information that the speed
8 of 11 Newton's Law of Cooling states that the temperature T of an object at any time t, in minutes, can be described by the equation T = Ts + (To-Ts)e-kt, where Ts is the temperature of the surrounding environment, To is the initial temperature of the object, and k is the cooling rate. What is the cooling rate of an object if the initial temperature was 110° C, the surrounding environment temperature was 10° C, and it took 25 minutes to cool down to 35° C. Round your result to 3 decimal places. k = 0.054 k = 0.055 k = 0.057 k = 0.400
The cooling rate of the object is 0.054.
Let's find the cooling rate (k) of an object using the given information. Ts = 10 °CTo = 110 °CT1 = 35 °Ct2 = 25 minutes. Now, the given formula is T = Ts + (To - Ts) e ^ -kt. Here, we know that the temperature drops from 110°C to 35°C, which is 75°C in 25 minutes. Now, we will substitute the values in the formula as follows:35 = 10 + (110 - 10) e ^ (-k × 25) => (35 - 10) / 100 = e ^ (-k × 25) => 25 / 100 = k × 25 => k = 0.054. Therefore, the cooling rate of the object is 0.054. Hence, option A is correct.
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Explain and reason why the the moon rotates around the earth every lunar cycle
Pls explain ASAP
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when does the bird have the most potential energy when it dives into a oceran
The bird has the most potential energy when it is at the highest point of its dive into the ocean.
1. Potential energy is the energy possessed by an object due to its position or state.
2. In this case, we are considering the potential energy of a bird diving into the ocean.
3. The potential energy of an object depends on its height and mass.
4. When the bird is at the highest point of its dive, it has the maximum potential energy.
5. As the bird dives deeper into the ocean, its height decreases, resulting in a decrease in potential energy.
6. At the moment the bird reaches the surface of the water, its potential energy is at its minimum, as it is at its lowest height.
7. The potential energy is converted into kinetic energy as the bird accelerates towards the water.
8. Kinetic energy is the energy possessed by an object due to its motion.
9. When the bird enters the water, its potential energy is completely converted into kinetic energy.
10. The bird continues to possess kinetic energy as it moves through the water.
11. Once the bird comes to a stop in the water, its kinetic energy is reduced to zero.
12. At this point, the bird's potential energy is also zero, as it is at its lowest height and not in motion.
13. Therefore, the bird has the most potential energy when it is at the highest point of its dive into the ocean.
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a surface low pressure center is generally associated with ____ on an upper level isobaric chart.
A surface low pressure center is generally associated with a trough on an upper level isobaric chart.
An area of the Earth's surface with relatively lower air pressure than the nearby areas is referred to as a surface low pressure system in meteorology. These low-pressure systems influence weather patterns significantly and are frequently linked to a variety of weather events, such as storms, cyclones, and fronts.
A trough is frequently seen together with a centre of surface low pressure on an upper-level isobaric chart, which shows lines of constant pressure at higher altitudes in the atmosphere. An area of relatively lower pressure than the surrounding areas at the same altitude is known as a trough. It can be identified on a chart by an extended, curved shape that resembles a dip or a U-shape.
A trough above a system of low pressure on an upper-level isobaric chart indicates that the area of lower pressure has spread vertically through the atmosphere. Convergence at the surface, upward air velocity, and the potential for atmospheric instability and weather disturbances are all supported by this structure.
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