What are two things plants have which animal cells do not

Answer:

1 per 2 berarti a.2:3 berarti bagi bagi 1 22. 22 sama dengan 5

Explanation:

The lower jaw (mandible), which also shapes the lower face and chin, supports the bottom row of teeth. The bone that moves when the mouth opens and shuts is this one. The upper jaw's (maxilla) function is to support the nose, hold the upper teeth, and shape the middle of the face.

Answer:

\(m_{O_2}=120gO_2\)

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

\(2KClO_3\rightarrow 2KCl+3O_2\)

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

\(m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2\)

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a) The more basic solution is NaOH

b) The reason for this is that NaOH is a strong bas and dissociates completely in solution.

We know that the pH has to do with the degree of  acidity or alkalinity of the solution. The more the pH of the solution the more basic the solution is. The lesser the pH of the solution, the more acidic the solution is.

Drawing form the explanation above, the solution that is more basic is the sodium hydroxide solution. The sodium hydroxide solution is a strong base so it would ionize completely in solution.

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While having experienced polar explorers at the Catlin Arctic Survey would have been beneficial in many ways, it would also have been important for them to work collaboratively with the rest of the team.

Advantages:

Experienced polar explorers would have had a wealth of knowledge and skills, such as how to travel over the ice, how to set up camp, and how to handle emergencies.

Experienced polar explorers would have been able to make informed decisions about the best routes to take and the most efficient ways to travel. This could have helped to save time and energy.

Disadvantages:

Experienced polar explorers may have been set in their ways and resistant to new ideas. This could have hindered the team's ability to adapt to changing circumstances and make the most of new opportunities.

Experienced polar explorers may have been overconfident and taken risks that the rest of the team was not comfortable with. This could have put everyone's safety at risk.

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The theoretical yield of Acetylsalicylic acid is found out to be: 3.01 grams.

The limiting reagent is a substance that prevents a chemical reaction from occurring completely.

When a limiting reagent is used in a chemical reaction, the atoms, molecules, or ions of the other reactant that it (the limiting reagent) reacts with will either stay free or unreacted.

Popular compounds called acids and bases interact with one another to create salt and water. The Latin word "acere," which meaning "sour," is where the term "acid" originates.

According to the problem, we have 2.31 grams of salicylic acid. We need to determine the theoretical yield of acetylsalicylic acid.

The molar mass of salicylic acid is 138.12 g/mol. Therefore, the number of moles of salicylic acid we have is:

n = mass / molar mass

n = 2.31 g / 138.12 g/mol

n = 0.0167 mol

According to the balanced equation, 1 mole of salicylic acid reacts with 1 mole of acetic anhydride to produce 1 mole of acetylsalicylic acid. Therefore, the number of moles of acetylsalicylic acid produced is also 0.0167 mol.

The molar mass of acetylsalicylic acid is 180.16 g/mol. Therefore, the theoretical yield of acetylsalicylic acid is:

mass = n x molar mass

mass = 0.0167 mol x 180.16 g/mol

mass = 3.01 g

Therefore, the theoretical yield of acetylsalicylic acid is 3.01 grams.

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The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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Answer:

56.9kg

Explanation:

Given parameters:

∆Hfusion = 334J/g

Amount of energy  = 19kJ or 19 x 10³J

Initial temperature  = 0°C

Unknown:

Quantity of ice melted =  ?

Solution:

This process is a simple phase change from ice to water at the same temperature.

    H  = mL

   m is the mass of the ice

    L is the heat of fusion

   H is the amount of supplied heat

Insert the parameters and solve;

     19 x 10³ = m x 334

          m = \(\frac{19000}{334}\)   = 56.9kg

Answer:

flo-non metal

germ- metalloid

zinc - metal

phos- non metal

lithium- metal

The balanced equation  \(K_{2}Cr_{2}O_{7}\) oxidizes KI in the presence of \(H_{2}SO_{4}\)can be represented as

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

The balanced equation for the oxidation of KI (potassium iodide) by \(K_{2}Cr_{2}O_{7}\)(potassium dichromate) in the presence of \(H_{2}SO_{4}\)(sulfuric acid) can be represented as follows:

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

In this equation, \(K_{2}Cr_{2}O_{7}\) is the oxidizing agent, and KI is the substance being oxidized. The sulfuric acid (\(H_{2}SO_{4}\)) serves as a catalyst and provides the necessary acidic conditions for the reaction to occur.

The products of the reaction are potassium sulfate (\(K_{2}SO_{4}\)), chromium(III) sulfate (\(Cr_{2}(SO_{4})_{3}\)), iodine (), and water (\(H_{2}O\)).

Note that this equation represents a stoichiometrically balanced equation, ensuring that the number of atoms of each element is the same on both sides of the equation.

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The molar mass of the gas is obtained as 32.1 g/mol.

The molar mass has to do with the mass one mole of a substance. We know that according to the question, we can be able to obtain the number of moles of the compound from the ideal gas equation.

This is how we are able to get the number of moles of the gas as 0.14 moles. Now we need to use the information that we have to get the molar mass of the gass.

Number of moles = mass/ molar mass

Molar mass = mass/Number of moles

Molar mass =  4.5g/0.14  moles

= 32.1 g/mol

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There are 3.44 x 10^{22} particles in 0.057 moles of lithium bromide.

The lithium bromide formula also known as the lithium monobromide formula or Bromo lithium formula is explored. It is a counterion bromide-based salt of lithium.

we have to use Avogadro's constant,

Avogadro's constant, is approximately equal to 6.022 x 10^{22} particles per mole.

we can use the following formula:

number of particles = moles x Avogadro's constant

Substitute the values,

number of particles = 0.057 moles x 6.022 x 10^{23} particles/mol

Simplifying the equation

number of particles = 3.44 x 10^{22} particles

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The Safety Data Sheet (SDS) for regular bleach can be obtained from the manufacturer or supplier of the specific brand or product. It contains important information regarding the hazardous properties, handling, storage, and emergency procedures related to the bleach.

An SDS typically includes details such as the product's chemical composition, physical and chemical properties, potential hazards to health and the environment, precautionary measures for safe handling and storage, first-aid procedures, and information about proper disposal. It also provides guidance on personal protective equipment (PPE) to be used when handling the product and steps to take in case of accidental release or exposure.

The SDS serves as a crucial resource for understanding the potential risks associated with the use of regular bleach and helps ensure that appropriate safety measures are implemented. It is important to review and follow the information provided in the SDS to minimize the risk of accidents, injuries, or adverse health effects associated with the use of the product.

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Explanation:

Electron affinity is defined as the energy released by the addition of an electron to any gaseous atom. Electron affinity of an atom depends on the electronic configuration.

a).The carbon has vacant p-orbital and nitrogen has half-filled configuration which is more stable. Therefore, one electron can be easily added to carbon whereas nitrogen having more stable configuration releases more amount of energy on adding one electron. Therefore, nitrogen has more electron affinity than carbon.

The bromine has vacant p-orbital whereas argon has filled orbital which is most stable. Therefore, one electron can be easily added to bromine whereas argon having  more stable configuration releases more amount of energy on adding one electron.Therefore, argon has more electron affinity than bromine.

Answer:

1. a. C; b. N; c. C; 2. a. Br; b. Ar; c. Br

Explanation:

Use your Periodic Table and follow the trends in atomic properties (Fig. 1).

Electron affinity increases from left to right and from bottom to top.

The elements with the most exothermic EA are at the upper right corner

Exceptions are the noble gases (group 18) and the pnictogens (group 18).

The elements of Group 18 have a complete octet and have no tendency to accept electrons.  

The elements of Group 15 have half-filled p subshells. They are more stable than the elements immediately preceding them, so they are less exothermic when adding an electron.  

Ionization energy increases from left to right and from bottom to top.  

The atoms with the highest IE are at the upper right corner.

Atomic size increases from right to left and from bottom to top.  

The largest atoms are on the lower-left corner.

1. C vs N

(a)   EA: C. N is a Group 15 element

(b)    IE: N. N is further to the right.

(c) Size: C. C is further to the left.

2. Ar vs Br

(a)   EA: Br. Ar is a noble gas.

(b)    IE: Ar. Ar is further to the right.

(c) Size: Br. Br is nearer to the bottom.

Answer:

The valence electrons in a solid metal sample are delocalized or evenly distributed throughout the metal structure.

Explanation:

The atoms of a metal in a metal sample are held together in crystal lattice structures by means of metallic bonds. The valence electrons of each atom in a metal are not held to that atom alone but are contributed to an electron cloud surrounding the atoms. Each atom becomes positively charged and are located at the center of crystal lattice while the electrons surround the positively charged nucleus of the atoms. Thus, the atomic nucleus of each are held together by the moving electron cloud and overlapping residual electron orbits.

This model of metallic crystal structure is known as the electron-sea model of bonding in metals. This model of metallic structure accounts for some properties of metals such as high electrical and thermal conductivity as well as ease with which metals are deformed. Since the electrons are not tightly-bound to any single atom but are free to move about, hence, metals are very good conductors of electricity. Similarly, collisions between metal ions transfer energy to neighboring ions and are responsible for their high thermal conductivity. Also, metals are easily deformed because the metal ions can easily change position without having to break any specific bonds.

Answer:

Valence electrons are shared among many metal ions.

Explanation:

Answer:

Explanation:

The density of a substance can be found by using the formula

\(Density = \frac{mass}{volume} \)

Making volume the subject we have

From the question

Density = 728 g/mL

mass of nickel = 5.040 g

Substitute the values into the above formula and solve for the volume

That's

\(volume = \frac{5.040}{728} \\ = 0.692307\)

We have the final answer as

Hope this helps you

Answer:

The answer would be 0.6923 mL :)

Answer:

Follows are the solution to the given question:

Explanation:

Dry Soil weight = solid soil weight = \(284 \ grams\)

solid soil volume =\(205 \ cc\)

saturated mass soil = \(361 \ g\)

The weight of the soil after drainage is =\(295 \ g\)

Water weight for soil saturation = \((361-284) = 77 \ g\)

Water volume required for soil saturation =\(\frac{77}{1} = 77 \ cc\)

Sample volume of water: \(= \frac{\text{water density}}{\text{water density input}}\)

\(= 361- 295 \\\\ = 66 \ cc\)

Soil water retained volume = (draining field weight - dry soil weight)

                                             \(= 295 - 284 \\\\ = 11 \ cc.\)

\(\text{POROSITY}= \frac{\text{Vehicle volume}}{\text{total volume Soil}}\)

                    \(= \frac{77}{(205 + 77)} \\\\= \frac{77}{(282)} \\\\ = 27.30 \%\)

(Its saturated water volume is equal to the volume of voids)

\(\text{YIELD SPECIFIC} = \frac{\text{Soil water volume}}{\text{Soil volume total}}\)

                              \(= \frac{66}{(205+77)}\\\\= \frac{66}{(282)}\\\\=0.2340\\\\ = 0.23\)

\(\text{Specific Retention}= \frac{\text{Volume of soil water}}{\text{Total soil volume}}\)

                            \(= \frac{11}{282} \\\\= 0.0390 \\\\ = 0.04\)

Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

Answer:

hen ,b=4-a. From. Equation (2). Then b= 3. Now,,(a)square+(b)square=1square+3square. =1+9. =10. therefore the value of a square plus bsquare is 10

Explanation:

Answer:

50Pa

Explanation:

pressure= force/area

= 500N/10m2

= 50Pa

"Spherical: Bacteria shaped like a ball are called cocci, and a single bacterium is a coccus. Examples include the streptococcus group, responsible for “strep throat.”

Rod-shaped: These are known as bacilli (singular bacillus). ...

Spiral: These are known as spirilla (singular spirillus). " - Medical News Today

Answer:

Did this for an assignment, reword and shorten it yourself, also give brainliest

Explanation:

The idea of Olive Oil coffee from a chemistry perspective brings several factors into consideration, such as polarity, solubility, density, melting points, boiling points, and types of mixtures.

Firstly, olive oil is a nonpolar substance, while coffee is primarily composed of polar compounds, such as caffeine and various acids. Polarity refers to the distribution of charge within a molecule, and polar and nonpolar substances do not readily mix. This fundamental difference in polarity makes it challenging to create a stable and homogeneous mixture between olive oil and coffee.

Secondly, solubility plays a crucial role. Coffee is soluble in water due to its polar components, allowing the extraction of flavor compounds when brewed. However, olive oil is not soluble in water, so attempting to mix it with coffee would result in phase separation, with the oil floating on top or forming droplets dispersed throughout the coffee. This lack of solubility further contributes to an unstable and unappealing mixture.

Density is another relevant factor. Olive oil is less dense than water, which means it would naturally rise to the top when mixed with coffee. This separation of phases would lead to an unpleasant texture and appearance in the cup.

Additionally, the melting points and boiling points of olive oil and coffee differ significantly. Olive oil has a higher melting point and boiling point compared to the volatile compounds found in coffee. When attempting to mix hot coffee with olive oil, the heat could cause the oil to evaporate or decompose, altering its flavor and aroma.

Moreover, considering the types of mixtures, the combination of olive oil and coffee would likely result in an unstable heterogeneous mixture rather than a homogeneous one. Homogeneous mixtures are uniform throughout, while heterogeneous mixtures have distinct phases. The immiscibility of oil and water would make it challenging to achieve a stable and well-blended mixture.

To stabilize such a mixture, emulsifiers or surfactants could be employed to promote the dispersion of oil in water. However, finding an appropriate emulsifier that can effectively bind polar and nonpolar components in coffee without compromising its taste and texture would be a difficult task.

In conclusion, the idea of Olive Oil coffee from a chemistry standpoint faces challenges related to the differences in polarity, solubility, density, melting points, boiling points, and the types of mixtures involved. These factors make it highly unlikely to achieve a stable and appealing combination.

Two or more than two atoms with different physical or chemical properties can not combine together to form an element.  Energy is the only factor that  determines the color of light of fireworks.

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

Fireworks has many different types of element. When any element is given an energy. Then the process of excitation of electrons takes place from its outermost shells. Every element absorb characteristic wavelength of energy and releases light to the corresponding wavelength.

Therefore, energy is the only factor that  determines the color of light of fireworks.

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Answer:

Explanation:

Limiting is HCl and excess is Ca(OH)2

excess is 296 grams Ca(OH)2

2 moles H2O will be formed

Answer:

Explanation:

We shall apply Arrhenius equation which is given below .

\(ln\frac{k_2}{k_1} = \frac{E_a}{R} [\frac{1}{T_1} -\frac{1}{T_2} ]\)

K₂ and K₁ are rate constant at temperature T₂ and T₁ , Ea is activation energy .

Putting the given values

\(ln\frac{5.9}{1} = \frac{39500}{8.3} [\frac{1}{298} -\frac{1}{T_2} ]\)

\(.000373= [\frac{1}{298} -\frac{1}{T_2} ]\)

T₂ = 335.27 K

= 62.27 °C

The higher temperature is 62.27°C.

Given that the activation energy of the reaction is:

Eₐ =  39.5 kJ/mol

initial temperature T₁ = 25°C = 298K

Let the final temperature be T₂

The rate constant at temperature T₁ be K₁, and at a temperature T₂ be K₂.

According to the question: K₂/K₁ = 5.9

Now, applying the Arrhenius equation we get:

\(\ln\frac{K_2}{K1}=\frac{E_a}{R}[\frac{1}{T_1} -\frac{1}{T_2}]\\\\\ln(5.9)= \frac{39.5}{8.3}[\frac{1}{298} -\frac{1}{T_2}]\\\\0.000373=\frac{1}{298} -\frac{1}{T_2}\)

T₂ = 335.27K

T₂ =  335.27 -273

T₂ = 62.27°C

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Answer:

Olfactory indicators

Explanation:

The substance whose odour changes in an acidic of basic medium are called olfactory indicators. In an olfactory indicator , smell varies depending on whether it is mixed with an acidic or basic solution.

Answer:A

Explanation: because alkane are non polar