What are the steps for constructing an inscribed circle in using only a compass and a straightedge?

Answer: 1.367

Step-by-step explanation:

csc47° = 1.3673 ≈ 1.367

The value of cosec 47° is 1.367.

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

cosec 47°

The value of cosec 47°.

= 1.367334

Rounding to the nearest thousandth.

= 1.367

Thus,

The value of cosec 47° is 1.367.

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Answer:The solution to a system of linear equations is the point at which the lines representing the linear equations intersect. Two lines in the x y xy xy -plane can intersect once, never intersect, or completely overlap.

A system of linear equations is usually a set of two linear equations with two variables. x + y = 5 x+y=5 x+y=5x, plus, y, equals, 5 and 2 x − y = 1 2x-y=1 2x−y=12, x, minus, y, equals, 1 are both linear equations with two variables. When considered together, they form a system of linear equations.

a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

a constant term is a term in an algebraic expression that has a value that is constant or cannot change, because it does not contain any modifiable variables. For example, in the quadratic polynomial the 3 is a constant term.

Step-by-step explanation:

The correct value of 2f(a-1) is 2a^2 - 12a + 10.

To find the value of 2f(a-1), we need to substitute (a-1) into the function f(x) and then multiply the result by 2.

Given: f(x) = x^2 - 4x

Substituting (a-1) into the function:

f(a-1) = (a-1)^2 - 4(a-1)

Expanding and simplifying:

f(a-1) = (a^2 - 2a + 1) - (4a - 4)

f(a-1) = a^2 - 2a + 1 - 4a + 4

f(a-1) = a^2 - 6a + 5

Now, we multiply the result by 2:

2f(a-1) = 2(a^2 - 6a + 5)

Expanding:

2f(a-1) = 2a^2 - 12a + 10

Therefore, the value of 2f(a-1) is 2a^2 - 12a + 10.

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Answer:

\(x=4y+28\)

Step-by-step explanation:

\(\frac{x}{4} -7=y\)

\(\frac{x}{4} =y+7\)

\(x=4(y+7)\)

\(x=4y+28\)

Answer:

\(x = 4(y + 7)\\x=4y+28\)

Step-by-step explanation:

\( \frac{x}{4} - 7 = y \\ \frac{x}{4} = y + 7 \\ x = 4(y + 7)\\=4y+28\)

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Answer:

D

Step-by-step explanation:

Khan Academy

Answer:

hope it helps...............

The Hypotenuse-Leg congruence criteria is (D) two right angles, each of which has a 4-foot side opposite the right angle and a 3-foot leg

Two triangles are said to be congruent if they have the same size and shape. Hence, corresponding sides and angle are congruent to each other.

The Hypotenuse-Leg congruence theorem states that two right triangles are congruent if the hypotenuse and leg of one triangle is equal to the hypotenuse and leg of another triangle.

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Answer:

3.5 yd is your answer

Step-by-step explanation:

First, change in. to ft. Note that the measurement given to you is that 1 ft = 12 in.

Divide the amount of inches you have with 12.

126/12 = 10.5

Next, solve for yards. It is given to you that 1 yard = 3 feet.

Divide the amount of feet you have with 3.

10.5/3 = 3.5

3.5 yd is your answer

Answer:

x = - 20

Step-by-step explanation:

\(\frac{3}{4}\) x - 5 = x ( multiply through by 4 to clear the fraction )

3x - 20 = 4x ( subtract 3x from both sides )

- 20 = x

Answer:

  $3,951

Step-by-step explanation:

The growth factor for t years is given as 2^(t/6). Then in 13 years, the account will be multiplied by ...

  2^(13/6) ≈ 4.489848

Its value will be ...

  $880·4.489848 ≈ $3,951

The value of the given expression is - 9.

The square root of a number is a value that, when multiplied by itself, gives the original number.

For example, the square root of 25 is 5, because 5 x 5 = 25.

The symbol used to denote the square root of a number is √, and it is placed in front of the number.

For example, the square root of 25 can be written as √25.

Here we have  

\(\frac{ \sqrt{36} - \sqrt[3]{8} - \sqrt{144} }{\sqrt[3]{-64} \sqrt[3]{125}} - 1\)  

As w know,

36 = 6 × 6 = 6²

8 = 2 × 2 × 2 = 2³

144 = 12 × 12 = 12²  

-64 = - 4 × -4 × -4 = (-4)³

125 = 5 × 5 × 5 = 5³  

Hence, the above expression can rewrite as follows

\(\frac{ \sqrt{36} - \sqrt[3]{8} - \sqrt{144} }{\sqrt[3]{-64}+ \sqrt[3]{125}} - 1 = \frac{ \sqrt{ 6^{2} } - \sqrt[3]{ 2^{3} } - \sqrt{12^{2} } }{\sqrt[3]{ (-4)^{2} }+ \sqrt[3]{5^{3} }} - 1\)

=  \(\frac{ 6 - 2 - 12 }{ -4 + 5} - 1\)

=  \(\frac{ -8 }{ 1} - 1\)

= -9

Therefore,

The value of the given expression is - 9.

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The slope of the function is m = -3.5, which indicates that the temperature decreases by 3.5 degrees for each 1000 feet increase in elevation.

The temperature at Sea level is 87 °F

The slope of a straight line function is the ratio of the rise to the run of the function.

Parts of the question that appear missing includes; The slope and the temperature at Sea level is required.

A point on the table of the graph is that at 4 feet, the temperature is 73 °F

The rate at which the the temperature changes = -3.5 °F  per 1,000 feet

The slope of the equation is therefore;

y - 73 = -3.5·(x - 4)

y = -3.5·x + 14 + 73 = -3.5·x + 87

y = -3.5·x + 87

The equation of the the line of the temperature above Sea level is an equation of a straight line, which is of the form; y = m·x + c

Where;

m = The slope of the function

By comparison, the slope of the equation of the line the function is; m = -3.5

The temperature at Sea level, which is the y-intercept is found at the point where x = 0, which gives;

y = -3.5 × 0 + 87 = 87

The temperature at Sea level is 87 °F

The slope of line of the graph of the function, m = -3.5

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Answer:

In AFGH, the measure of ZH=90°, the measure of ZF=44°, and GH = 14 feet. Find the length of HF to the nearest tenth of a foot.​ - 22536102.

Step-by-step explanation:

Answer:

The probability that a particular firm selected has $1 million or more in income after taxes is 49%.

Step-by-step explanation:

We are given a study of 200 computer service firms revealed these incomes after taxes below;

         Income After Taxes                  Number of Firms

           Under $1 million                              102

      $1 million up to $20 million                    61

           $20 million or more                          37      

                 Total                                           200    

Now, the probability that a particular firm selected has $1 million or more in income after taxes is given by;

Total number of firms = 102 + 61 + 37 = 200

Number of firms having $1 million or more in income after taxes = 61 + 37 = 98  {here under $1 million data is not include}

So, the required probability =  \(\frac{\text{Firms with \$1 million or more in income after taxes}}{\text{Total number of firms}}\)

                                           =  \(\frac{98}{200}\)

                                           =  0.49 or 49%

The probability that a particular firm selected has $1 million or more in income after taxes is 0.49 or 49%.

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

A study of 200 computer service firms revealed these incomes after taxes:

Income After Taxes Number of Firms Under

$1 million 102

$1 million up to $20 million 61

$20 million or more 37.

Then the total event will be

Total event = 102 + 37 +61 = 200

The probability that a particular firm selected has $1 million or more in income after taxes will be

Favorable event = 37 + 61 = 98

Then the probability will be

\(\rm P = \dfrac{98}{200} \\\\P = 0.49 \ or \ 49 \%\)

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There are no solutions to the system of inequalities Option (d)

Inequalities are a fundamental concept in mathematics and are commonly used in solving problems that involve ranges of values.

A system of two inequalities is a set of two inequalities that are considered together. In this case, the system of inequalities is

y > 3x + 1

y < 3x - 3

The inequality y > 3x + 1 represents a line on the coordinate plane with a slope of 3 and a y-intercept of 1. The inequality y < 3x - 3 represents another line on the coordinate plane with a slope of 3 and a y-intercept of -3. We can draw these lines on the coordinate plane and shade the regions that satisfy each inequality.

The first line has a positive slope and goes through (negative 2, negative 5) and (0, 1). Everything to the left of the line is shaded. The second line has a positive slope and goes through (0, negative 3) and (1, 0). Everything to the right of the line is shaded.

We can start by analyzing the inequality y > 3x + 1. This inequality represents the region above the line with a slope of 3 and a y-intercept of 1. Therefore, any point that is above this line satisfies this inequality.

Next, we analyze the inequality y < 3x - 3. This inequality represents the region below the line with a slope of 3 and a y-intercept of -3. Therefore, any point that is below this line satisfies this inequality.

To determine which values satisfy both inequalities, we need to find the region that satisfies both inequalities. This region is the intersection of the regions that satisfy each inequality.

When we analyze the regions that satisfy each inequality, we see that there is no region that satisfies both inequalities. Therefore, there are no values that satisfy the system of inequalities shown.

There are no solutions to the system of inequalities y > 3x + 1 and y < 3x - 3 by analyzing the regions that satisfy each inequality on a coordinate plane. The lack of a solution is determined by the fact that there is no region that satisfies both inequalities.

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Complete Question :

Which is true about the solution to the system of inequalities shown?

y > 3x + 1

y < 3x – 3

On a coordinate plane, 2 solid straight lines are shown. The first line has a positive slope and goes through (negative 2, negative 5) and (0, 1). Everything to the left of the line is shaded. The second line has a positive slope and goes through (0, negative 3) and (1, 0). Everything to the right of the line is shaded.

Options:

a)Only values that satisfy y > 3x + 1 are solutions.

b)Only values that satisfy y < 3x – 3 are solutions.

c)Values that satisfy either y > 3x + 1 or y < 3x – 3 are solutions.

d)There are no solutions.

Answer:

D

Step-by-step explanation:

The checkboxes are denoted by brackets ([]) for checked and 'x' for unchecked states, respectively.

The fertilizing techniques that would be most effective for each example are as follows:

1. Farm with numerous workers and sensitive crops:

a. UDP (Unchecked )

b. Precision management (Checked)

2. A gardener raising produce for a family:

a. UDP (Checked).

b. Precision management (Unchecked )

3. Company that delivers corn to 10 states:

a. UDP (Unchecked)

b. Precision management (Checked)

Please note that the checkboxes are denoted by brackets ([]) for checked and 'x' for unchecked states, respectively.

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The correct statement regarding the mean of the data-set when the score of 47 is removed is given as follows:

The mean increased by about 6.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations, which is also called the cardinality of the data-set.

The observations for this problem are given as follows:

100, 95, 47, 83, 87, 89, 89.

There are 7 observations, and their sum is given as follows:

100 + 95 + 47 + 83 + 87 + 89 + 89 = 590.

Hence the mean is of:

590/7 = 84.29.

Removing the observation of 47, there will be 6 observations, with a sum of 590 - 47 = 543, hence the mean is of:

543/6 = 90.5.

Meaning that the mean increases by about 6.

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The answers are given below:-

a) The exponential function is: \(y(t) = 500e^{-0.0117593}\)

b) The rule is: \(y(t) = y(0)(\dfrac{358}{500})^{\frac{t}{8}\)

c) The half-life of the element is of 16.599 days.

The mathematical expression  \(f(x) = e^x\) denotes the exponential function. The phrase typically refers to the positive-valued function of a real variable, unless otherwise specified.

Following t days, the substance's amount's exponential function is given by:

\(y(t) = y(0)e^{-kt}\)

For this problem, we have that:

y(0) = 500, y(8) = 358.

Hence we can solve for k as follows:

\(y(t) = y(0)e^{-kt}\)

\(358=500e^{-8k}\)

\(e^{-8k}=\dfrac{358}{500}\)

\(lne^-8k}=ln0.716\)

-8k = ln(0.716)

k = -ln(0.716)/8

k = 0.041759389.

Hence:

\(y(t) = 500e^{-0.0117593}\)

For item b, 358/500 of the material is what is left over after each 8-day period, therefore f(t) = t/8, and the rule is as follows:

\(y(t) = y(0)(\dfrac{358}{500})^{\frac{t}{8}\)

For item c, using the rule from item a, we have to find t for which y(t) = 0.5y(0), hence:

\(y(t) = y(0)e^{-0.0117593}\)

\(0.5y(0)=y(0)e^{-0.0117593\)

\(e^{-0.0117593}=0.5\)

\(lne^{-0.0117593}=ln0.5\)

-0.041759389t = ln(0.5)

t = -ln(0.5)/0.041759389

t = 16.599.

The half-life of the element is of 16.599 days.

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The basic ratio of minutes of painting to minutes of instruction is 7 : 6

From the question, we have the following parameters that can be used in our computation:

Painting = 63 minutes

Instruction = 54 minutes

The ratio can be represented as

Ratio = Painting : Instruction

When the given values are substituted in the above equation, we have the following equation

Painting : Instruction = 63 : 54

Simplify

Painting : Instruction = 21 : 18

Simplify

Painting : Instruction = 7 : 6

This  ratio cannot be simplified

Hence, the solution is 7 : 6

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Let x = 2y. Then we want to show

sin(6y) + sin(4y) - sin(2y) = 4 sin(2y) cos(y) cos(3y)

Recall the angle sum identities,

sin(x ± y) = sin(x) cos(y) ± cos(x) sin(y)

cos(x ± y) = cos(x) cos(y) ∓ sin(x) sin(y)

which lets us write

sin(6y) = sin(4y + 2y) = sin(4y) cos(2y) + cos(4y) sin(2y)

sin(4y) = sin(2y + 2y) = 2 sin(2y) cos(2y)

cos(4y) = cos(2y + 2y) = cos²(2y) - sin²(2y)

Ultimately, we use these identities to rewrite the left side as

sin(6y) + sin(4y) - sin(2y)

= 2 (sin(4y) cos(2y) + cos(4y) sin(2y)) + 2 sin(2y) cos(2y) - sin(2y)

= 2 sin(2y) cos²(2y) + (cos²(2y) - sin²(2y)) sin(2y) + 2 sin(2y) cos(2y) - sin(2y)

Notice the underlined common factor of sin(2y). If we remove this from both sides of the identity we want to prove, then it remains to show that

2 cos²(2y) + (cos²(2y) - sin²(2y)) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

or

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1 = 4 cos(y) cos(3y)

Recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

which lets us write

3 cos²(2y) - sin²(2y) + 2 cos(2y) - 1

= 3 cos²(2y) - (1 - cos²(2y)) + 2 cos(2y) - 1

= 4 cos²(2y) + 2 cos(2y) - 2

= 2 (2 cos²(2y) + cos(2y) - 1)

= 2 (2 cos(2y) - 1) (cos(2y) + 1)

Recall the half-angle identity for cosine,

cos²(x/2) = 1/2 (1 + cos(x))

which means

cos(2y) + 1 = 2 • 1/2 (1 + cos(2y)) = 2 cos²(y)

and so

2 (2 cos(2y) - 1) (cos(2y) + 1)

= 4 (2 cos(2y) - 1) cos²(y)

= 4 cos(y) (2 cos(2y) - 1) cos(y)

Now notice the underlined factor of 4 cos(y), which also appears in the right side of the identity we want to prove. Eliminate this term and all that's left is to show that

(2 cos(2y) - 1) cos(y) = cos(3y)

which follows from a combination of the identities I mentioned above:

(2 cos(2y) - 1) cos(y)

= 2 cos(2y) cos(y) - cos(y)

= 2 • 1/2 (cos(2y + y) + cos(2y - y)) - cos(y)

= (cos(3y) + cos(y)) - cos(y)

= cos(3y)

as required.

Trigonometric identities involve equations that use the trigonometric functions that are true for all variables in the equation

The identity is given as:

\(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\)

Let x = 2y.

So, we have:

\(\sin(6y) + \sin(4y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(\sin(4y + 2y) + \sin(2y + 2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand the identities using the angle sum identities,

\(\sin(4y)\cos(2y) + \cos(4y)\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand cos(4y) and sin(4y)

\(2\sin(2y)\cos^2(2y) + [\cos^2(2y) - \sin^2(2y)]\sin(2y) + 2\sin(2y)\cos(2y) - \sin(2y) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out sin(2y)

\(\sin(2y)[2\cos^2(2y) + \cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[3\cos^2(2y) - \sin^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Substitute

\(\sin^2(2y) = 1 - \cos^2(2y)\)

\(\sin(2y)[3\cos^2(2y) - 1 + \cos^2(2y) + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Evaluate the like terms

\(\sin(2y)[4\cos^2(2y) - 1 + 2\cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

\(\sin(2y)[4\cos^2(2y) + 2\cos(2y) - 2] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out 2

\(2\sin(2y)[2\cos^2(2y) + \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(2\sin(2y)[2\cos^2(2y) +2\cos(2y) - \cos(2y) - 1] = 4\sin(2y)\cos(y)\cos(3y)\)

Factorize

\(2\sin(2y)[2\cos(2y)( \cos(2y) + 1) -1( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(2y) + 1

\(2\sin(2y)[( 2\cos(2y) - 1)( \cos(2y) + 1)] = 4\sin(2y)\cos(y)\cos(3y)\)

By half identity, we have:

\(\cos\²(\frac x2) = \frac 12 (1 + \cos(x))\)

Multiply both sides by 2

\(2\cos\²(\frac x2) = (1 + \cos(x))\)

Replace x with 2y

\(2\cos\²(y) = 1 + \cos(2y)\)

So, we have:

\(2\sin(2y)[( 2\cos(2y) - 1)( 2\cos^2(y))] = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(2 \cos(2y) - 1)(\cos^2(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Factor out cos(y)

\(4\sin(2y)(\cos(y)(2 \cos(2y) - 1)(\cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Expand

\(4\sin(2y)(\cos(y)(2 \cos(2y)\cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

Using the half identity, we have:

\(4\sin(2y)(\cos(y)(2 * \frac 12 *\cos(2y + y) + \cos(2y - y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)(\cos(y)(\cos(3y) + \cos(y) - \cos(y)) = 4\sin(2y)\cos(y)\cos(3y)\)

\(4\sin(2y)\cos(y)\cos(3y) = 4\sin(2y)\cos(y)\cos(3y)\)

Recall that:

x = 2y

So, we have:

\(4\sin(x)\cos(\frac x2)\cos(\frac {3x}2) = 4\sin(x)\cos(\frac x2)\cos(\frac {3x}2)\)

Both sides of the equations are the same.

Hence, the identity \(\sin(3x) + \sin(2x) - \sin(x) = 4\sin(x)\cos(\frac x2)\cos(\frac{3x}{2})\) has been proved

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Answer:

a.{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b.{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.{d d, dg, g d, g g}

d.{dg, g d, gg}

Step-by-step explanation:

We have to find the sample space

a. We are given items

{a, b, c, d}

Therefore, the sample space

{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b. Items

Therefore, the sample space

{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.

Defective items (d)=4

Good items(g)=20

Therefore, the sample space

{d d, dg, g d, g g}

d.

Defective items (d)=1

Good items(g)=20

Therefore, the sample space

{d g, g d, g g}

The general solution of the first-order linear differential equation y' - (ln x)y = \(3 x^x\) is \(y=3x^{x} + cx^{x} e^{-x}\)

As per the give,n data the given differential equation is:

y' - (ln x) y = 3 \(x^x\)

Here have to determine the general solution of the first-order linear differential equation.

The differential equation is linear if the dependent variable y and its derivative only occur in the first degree.

Then, \($\frac{d y}{d x}-(\ln x) y=3 x^x$\)

This is of the form \($\frac{d y}{d x}\) + P(x)y = Q(x) which is the linear equation.

In order to solve this kind of differential equation, we have to multiply it by an integrating factor.

Here, P = - ln (x), Q(x) = 3 \(x^x\)

I F = \(e^{\int P d x}\)

I F = \(e^{-\int \ln (x)}\)

I F = \(e^{-(x \ln x-x)}\)

I F = \(e^{x-x \ln x}\)

I F = \(\frac{e^x}{e^{x \ln x}}\)

I F = \(\frac{e^x}{x^x}\)

Hence, the general solution is

\(& y(I F)=\int Q(x)(I F) d x+c \\\)

\(& \Rightarrow y\left(\frac{e^x}{x^x}\right)=\int 3 x^x\left(\frac{e^x}{x^x}\right) d x+c \\\)

\(& \Rightarrow y\left(\frac{e^x}{x^x}\right)=\int 3 e^x d x+c \\\)

\(& \Rightarrow y\left(\frac{e^x}{x^x}\right)=3 e^x+c \\\)

\(& \Rightarrow y=3 x^x+c x^x e^{-x}\)

Hence, the general solution is \(y=3x^{x} + cx^{x} e^{-x}\)

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Answer:

35 percent of 105 is 36.75 .

Answer:

The standard deviation of the number of females in the sample is 3.21.

Step-by-step explanation:

For each freshmen, there are only two possible outcomes. Either it is a female, or it is not. Sixty freshmen are randomly selected (without replacement). This means that the hypergeometric distribution is used to solve this question.

Standard deviation of the hypergeometric distribution:

We have that:

N is the population size.

n is the sample size.

s is the number of successes in the sample.

The standard deviation is given by:

\(\sigma = \sqrt{n(\frac{s}{N})(1 - \frac{s}{N})(\frac{N - n}{N-1})}\)

A small liberal arts college in the Northeast has 350freshmen.

This means that \(N = 350\)

One hundred five of the freshmen are female.

This means that \(s = 105\)

Suppose sixty freshmen are randomly selected

This means that \(n = 60\)

Find the standard deviation of the number of females in the sample.

\(\sigma = \sqrt{60(\frac{105}{350})(1 - \frac{105}{350})(\frac{350 - 60}{350 -1})} = 3.21\)

The standard deviation of the number of females in the sample is 3.21.

Answer:

it's b

Step-by-step explanation:

literally twelve minus m

Answer:

B

Step-by-step explanation:

12 minus m is, 12 - m

Answer:

12.

Step-by-step explanation:

if to re-write the given condition, then

\(\frac{3}{0.25} =\frac{18}{1.5} =\frac{30}{2.5} =\frac{36}{3} ;\)

it is clear, the required constant is 12 (12 per hour).

Answer:

-1

Step-by-step explanation:

1/3 - 2/5 = x/15

Make denominators equal.

5/15 - 6/15 = x/15

Cancel the denominators.

5 - 6 = x

-1 = x

Answer:

I think it is integers

Answer:

rational numbers

integers

real numbers

3 remainder of 7 i fink

Step-by-step explanation:

The height of the roof will be 10.75 units.

Given is to find the height of the roof.

The upward motion is modelled by the equation -

S = - t² + 3t + 4

The height of the roof is equal to maximum height attained. For the maximum height attained -

dS/dt = 0

d/dt (- t² + 3t + 4) = 0

- 2t + 3 = 0

2t = 3

t = 3/2                                                    .... Eq(1)

The  height of the roof will be -

S(max) = - t² + 3t + 4

S(3/2) = - (3/2)² +(3 x 3/2) + 4

S(3/2) = 9/4 + 9/2 + 4

S(3/2) = 2.25 + 4.5 + 4

S(3/2) = 10.75 units.

Therefore, the height of the roof will be 10.75 units.

To solve more questions on algebraic expressions, visit the link below -

brainly.com/question/1041084

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