What are the advantages of using resources such as geothermal energy, solar energy, and hydropower?

They produce large amounts of energy from burning fuels.

They can generate power by burning wastes.

They come from energy sources that never run out.

They increase the amount of greenhouse gasses.

Answer:

the metal gets cold and week

Explanation:

When osmotic pressure is kept constant, the relationship of molarity(m) and temperature(t) is inversely proportional.

This means that as the molarity of a solution increases, the temperature decreases, and vice versa. This relationship is described by the equation:

πV = nRT

where π is the osmotic pressure, V is the volume of the solution, n is the number of moles of solute, R is the gas constant, and T is the temperature. When π is kept constant, the equation can be rearranged to show the inverse relationship between molarity and temperature:

m = n/V = π/(RT)

As the molarity of the solution increases, the temperature must decrease in order to keep the osmotic pressure constant. Similarly, as the temperature of the solution increases, the molarity must decrease in order to keep the osmotic pressure constant.

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Answer:

decreases

Explanation:

Answer:

Decreases

Explanation:

There is less gas molecules and the air gets thinner the higher up you go

1.2mole•20.17g/1mole= 24.20g

CH4 has more ideal gas behavior than CCl4 due to its higher intermolecular interaction.

We must note that ideal gases have minimal interaction with each other. Hence, in deciding which gas has ideal gas behavior, we have to consider the gas that has the least degree of intermolecular interaction.

However, the both gases contain nonpolar molecules but CCl4 has a greater molecular mass and has more intermolecular interaction than CH4 hence CH4 has greater ideal gas behavior than CCl4.

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Answer:

ionic radii of elements increases down the group

Explanation:

Although at ionic state elements acquire noble gas configuration, there is an extra energy level down the group.

This leads to a decrease in attraction between electrons and the nucleus down the group.

For advanced level

Down the group an extra energy level creates screening of the penultimate shell decreasing the effective nuclear charge.

This leads to increase in the radius

To solve this problem, let's use the definition for molarity:

Replacing the values of the problem:

Now, to find the mass, we multiply by the molecular weight of NaCl. (Which is about 58.44g/mol)

The answer is approximately 22.2g of NaCl

To prepare a 459 M solution of NaOH dissolved in 975 mL of water, we would need 17.901 kg of NaOH.

Molarity is defined as the number of moles of solute per liter of solution. We are given the molarity of the solution as 459 M, which means that there are 459 moles of NaOH per liter of solution.

To find the number of moles of NaOH required to prepare 975 mL of the solution, we need to convert the volume to liters:

975 mL = 975/1000 L = 0.975 L

moles of NaOH = molarity x volume of solution in liters

moles of NaOH = 459 M x 0.975 L = 447.525 moles

mass of NaOH = moles of NaOH x molar mass of NaOH

The molar mass of NaOH is 40.00 g/mol. Therefore:

mass of NaOH = 447.525 moles x 40.00 g/mol = 17,901 g or 17.901 kg.

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Answer:

Between -195°C to -215°C

Explanation:

We begin from this data:

P under -220°C will be solid, because -220°C is the freezing point.

Above -220°C, P will be at liquid state.

Then -185°C is the boling point, so above that temperature we have P as a gas.

Between -175°C to -210°C

Above -185°C we said that P is gas, so at -175°C P is not liquid. This state is F.

Between – 190°C to -225°C

At -190°C, we can have P as liquid, but -225°C is under -220°C, where P changes from liquid to solid. Then, this state is also F.

Between -200°C to -160°C

Above -185°C we said that P is gas, so at -160°C P is not liquid. This state is also F. The same, as the first situation.

Between -195°C to -215°C

-195°C is a lower temperature than -185°C. P is still liquid, we did not get the boiling point yet. -215°C is higher than -220°C, P is also liquid. There are still 5°C until P completely freezes. This is the correct choice.

The spontaneous disintegration of a nucleus into a slightly lighter and more radioactive nucleus is accompanied by the emission of particles, electromagnetic radiation, or both.

Radioactivity is the phenomenon of the spontaneous disintegration of unstable atomic nuclei into atomic nuclei to shape greater energetically strong atomic nuclei.

Radioactive decay is a tremendously exoergic, statistically random, first-order system that occurs with a small amount of mass being converted to strength.

Spontaneous disintegration of a radionuclide with the emission of lively particles or radiation, consisting of alpha or beta debris or gamma rays.

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There are 1103.014 grams in 8.100 g-mol of calcium sulfate.

To calculate the grams in 8.100 g-mol of calcium sulfate, we need to determine the molar mass of calcium sulfate (CaSO₄) first. The molar mass is calculated by adding up the atomic masses of each element in the compound.

Calcium (Ca) has an atomic mass of 40.08 g/mol, sulfur (S) has an atomic mass of 32.07 g/mol, and oxygen (O) has an atomic mass of 16.00 g/mol.

The molar mass of calcium sulfate (CaSO₄) is therefore calculated as:
(1 * 40.08) + (1 * 32.07) + (4 * 16.00) = 136.14 g/mol.

Now we can calculate the grams in 8.100 g-mol of calcium sulfate using the following formula:
grams = molar mass * moles.

Plugging in the values:

grams = 136.14 g/mol * 8.100 g-mol = 1103.014 g.

Therefore, there are 1103.014 grams in 8.100 g-mol of calcium sulfate.

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Answer:

One

Explanation:

A unicellular organism consists of one cell.

hope this helps :)

I think it's A. air, because that's the one that will never have a confirmed shape because air can be trapped in jars, bags, closed spaces, and our body til we breathe it out.

Answer:

B

Explanation:

Answer:

velocity

Explanation:

Polysaccharide is a type of carbohydrate (such as glycogen, cellulose, or starch) whose molecules are made up of many sugar molecules bound together.

What purpose does the polysaccharide serve?

In general, polysaccharides serve one of two purposes: they either store energy or sustain structural integrity. Highly compact polymers like starch and glycogen are employed to store energy. In plants and animals, cellulose and chitin, two linear polymers, provide structural support.

What is plant polysaccharide?

More than half of the carbs we consume come from starch, which is the most significant source of carbohydrates in the human diet. Granules of it can be found in plants. Amylose and amylopectin, two polymers, are combined to form starch. 10%–30% amylose and 70%–90% amylopectin make up natural starches.

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yep, the cell is the smallest unit in a living organism that is capable of carrying out all of the activities of life.

The fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

Fugacity is a measure of the escaping tendency of a component in a mixture, which is defined as the pressure that the component would have if it obeyed ideal gas laws. It is used as a correction factor in the calculation of equilibrium constants and thermodynamic properties such as chemical potential. Here we need to determine the fugacity in atm for pure ethane at 310 K and 20.4 atm and the change in the chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm. So, using the formula of fugacity: f = P.exp(Δu/RT) Where P is the pressure of the system, R is the gas constant, T is the temperature of the system, Δu is the change in chemical potential of the system.  Δu = RT ln (f / P)The chemical potential at the initial state can be calculated using the ideal gas equation as: PV = nRT    

=>  P

= nRT/V

=> 20.4 atm

= nRT/V

=> n/V

= 20.4/RT The chemical potential of the system at the initial state is:

Δu1 = RT ln (f/P)

= RT ln (f/20.4) Also, we know that for a pure substance,

Δu = Δg. So,

Δg1 = Δu1 The change in pressure is 24 atm – 20.4 atm

= 3.6 atm At the second state, the pressure is 24 atm.

Using the ideal gas equation, n/V = 24/RT The chemical potential of the system at the second state is: Δu2 = RT ln (f/24) = RT ln (f/24) The change in chemical potential is Δu2 – Δu1 The change in chemical potential is

Δu2 – Δu1 = RT ln (f/24) – RT ln (f/20.4)

= RT ln [(f/24)/(f/20.4)]

= RT ln (20.4/24)

= - 0.0911 RT Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is:

f = P.exp(Δu/RT)

=> f

= 20.4 exp (-Δu1/RT)

=> f

= 20.4 exp (-Δg1/RT) And, the change in the chemical potential between this state and a second state of ethane where the temperature is constant but pressure is 24 atm is -0.0911RT. Therefore, the fugacity in atm for pure ethane at 310 K and 20.4 atm is given by the equation: f = 20.4 exp (-Δg1/RT). The change in chemical potential between this state and a second state of ethane where the temperature is constant but the pressure is 24 atm is -0.0911RT.

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The price of mercury used to make one manometer is $2.600X, and the price of mercury used to make 15 manometers is $39.00X, where X represents the cost of mercury per cubic inch.

To find the price of the mercury used to make one manometer, we need to know the cost of mercury per cubic inch. Once we have that information, we can calculate the cost for one manometer by multiplying the volume of mercury used (2.600 in^3) by the cost per cubic inch.

Let's assume the cost of mercury is $X per cubic inch.

Price of mercury used to make one manometer = Volume of mercury used * Cost per cubic inch

= 2.600 in^3 * $X/in^3

= $2.600X

Now, to find the price of mercury used to make 15 manometers, we can multiply the cost of one manometer by the number of manometers.

Price of mercury used to make 15 manometers = Price of one manometer * Number of manometers

= $2.600X * 15

= $39.00X

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J.J. Thomson observed cathode rays with every element he tested because cathode rays are a fundamental property of electrical discharge in a vacuum.

Cathode rays are streams of electrons emitted from the negatively charged electrode, known as the cathode, in a vacuum tube.

Thomson conducted his experiments using cathode ray tubes, which consist of a sealed glass tube with a cathode and an anode, connected to a high-voltage power supply. When the high voltage is applied, a current flows from the cathode to the anode, resulting in the emission of cathode rays.

Cathode rays were observed to have certain consistent characteristics, regardless of the material of the cathode or the gas present in the tube. These characteristics include;

Straight-line motion: Cathode rays travel in straight lines from the cathode to the anode. They can be deflected by electric and magnetic fields, indicating that they have a negative charge.

Independent of the cathode material: Thomson found that cathode rays were produced regardless of the material used as the cathode. Whether the cathode was made of metals, such as copper or aluminum, or non-metals, cathode rays were still emitted.

Independent of the gas present: Thomson also observed cathode rays in tubes containing different gases, such as hydrogen, nitrogen, or argon. The presence of cathode rays was not dependent on the gas used.

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Thomson saw cathode rays with every element tested, which led to the discovery of the electron as a fundamental particle.

Thomson's observation of cathode rays with every element tested was a significant discovery in the field of physics. During his experiments with cathode rays, Thomson observed that regardless of the material used for the cathode, cathode rays were always produced. This observation challenged the prevailing belief that cathode rays were a property of specific elements or compounds.

Thomson's experiments led him to propose the existence of a fundamental particle, which he called the electron. He hypothesized that cathode rays were composed of these negatively charged particles. This groundbreaking discovery revolutionized the understanding of atomic structure and laid the foundation for the development of the atomic model.

Thomson's observation of cathode rays with every element tested provided evidence for the existence of electrons as fundamental particles that are present in all matter. It demonstrated that electrons are not specific to certain elements but are a fundamental component of atoms.

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the molarity of the H₂SO₄ solution if it takes 40.0 ml of H₂SO₄ to neutralize 0.364 g of Na₂C0₃ is 0.0858

Calculation of the molarity of  H₂SO₄:

As per equation: H₂SO₄  + Na₂C0₃  ------> Na₂C0₄  +  H₂O  + CO₂

   1 mole of  H₂SO₄ reacts with  1 mole of Na₂C0₃

   1000   ml  1M   H₂SO₄        =    106 g. of Na₂C0₃  

     40  ml  1M  H₂SO₄       =    364 g. of Na₂C0₃

     1000   ml  1M   H₂SO₄   =     9.1 g.of Na₂C0₃

    __________________________________________

  1000 x 0.364

  ----------------------    =  9.1 g. of Na₂C0₃

        40

   Now  106 g. of Na₂C0₃   =    1 mole of  H₂SO₄

  Hence , 9.1 g. of Na₂C0₃  =0.0858 moles of H₂SO₄

  --------------------------------------------------------------------

          9.1 x1

        -------------                = 0.0858 moles of H₂SO₄

            106

0.0858 moles of H₂SO₄

The amount of moles of a solute in a liter of solution is known as its molarity. A capital M is used to represent molarity.

A solution in chemistry is a combination of two or more compounds in which neither ingredient undergoes a chemical transformation. For instance, salt water is a solution that contains both salt and water (the solvent) (the solute). The concentration of a material in a solution is its amount of dissolution. In other words, it refers to the number of ingredients that have been added to your drink. In molarity, concentration is often expressed.

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Answer:

2.38x10²³ atoms oxygen

Explanation:

To solve this question we need to convert the mass of sand to moles using its molar mass (Molar mass SiO₂ = 60.08g/mol). Twice these moles are the moles of Oxygen and using Avogadro's number we can find the amount of atoms of Oxygen in the mixture:

Moles SiO₂:

11.87g * (1mol / 60.08g) = 0.1976moles SiO₂

Moles Oxygen:

0.1976moles SiO₂* 2 = 0.3951moles oxygen

Atoms oxygen:

0.3951moles oxygen * (6.022x10²³atoms / 1mol O₂) =

Answer:

Synthetic clothes can easily build up static electricity. It also easily can catch up on fire and when it does, it melts and can fuse to your skin.

Explanation:

Answer:

Explanation:

Synthetic fibres like Polyester catches fire very easily and melts. After melting It sticks to the body of the person wearing it causing severe burns. Hence it is advised not wear synthetic clothes while working in the Kitchen. Its advised to wear Apron or cotton clothes while cooking in Kitchen.

The mass  (g) of a 257 ml sample with a specific gravity of 1.75 is 449.75

Calculation ,

The Formula of specific gravity ( when density of the water is 1g/ml ) is given as ,

specific gravity = density of an object

Density of an object can be computed using the formula :

Density = mass/ volume

Specific gravity = mass/volume

From there we can drive a formula for mass by transposing volume to the other side of the equation ,

volume × specific gravity = mass  

mass =  1.75 × 257 ml = 449.75 gram

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Answer:

D

Explanation:

Only when melted is correct

Only when crystal is wrong

Only when dissolved in water is correct

Only when melted or dissolved in water is wrong

I hope this helps you :)

Answer:

If the temperature of the system is increased, then the equilibrium position would shift to the right side. According to Le Chatelier's principle, when a stress is applied to a system in equilibrium, the system will adjust itself to counteract the stress. In this case, increasing the temperature would be an external stress on the system, and the reaction would shift to consume more of the reactants, namely CH4 and H2S, to create more of the products, CS2 and H2, thus shifting the equilibrium position towards the products.

Explanation:

Answer:

Oxygen gas relighting a glowing splint. The oxygen gas is produced by the decomposition of hydrogen peroxide, which is squirted into a test tube containing the decomposition catalyst manganese (IV) oxide. When the glowing splint is introduced to the test tube, it bursts back into flame when it contacts the oxygen.

Explanation:

hope its help

Oxygen relights a glowing splint due to its role as a strong oxidizer. When a glowing splint is inserted into an environment containing oxygen, it triggers a rapid combustion reaction.

Oxygen readily reacts with the fuel source on the splint (typically carbon compounds), providing the necessary oxygen molecules for the combustion process.

This exothermic reaction releases heat and light energy, causing the splint to re-ignite.

Oxygen's ability to support combustion is vital for many natural processes and industrial applications, as it enables the release of energy stored in various substances, highlighting its importance in sustaining life and various chemical reactions.

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The amount of CaCO₃ that are consumed at the reaction is 6.7 grams.

Ideal gas equation will be represented PV = nRT from which we can calculate the moles of carbon dioxide, where

On putting all these values, we get

n = (1)(1.5) / (0.082)(273) = 0.0669 moles = 0.067 mol

Given chemical equation is:

CaCO₃ + 2HCl → CO₂ + CaCl₂ + H₂O

From the stoichiometry of the reaction it is clear that,

1 moles of CO₂ = produced by 1 moles of CaCO₃

0.067 moles of CO₂ = produced by 0.067 moles of CaCO₃

Now mass of CaCO₃ will be calculated as:

n = W/M, where

W = (0.067)(100) = 6.7g

Hence required mass of CaCO₃ is 6.7g.

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