Answer:
The 5R's are Reuse, Reduce, Recycle, Repair and Recover.
How do you know if a compound is covalent
Answer:
Compounds containing two elements (binary compounds) can either have ionic or covalent bonding. If a compound is made from a metal and a non-metal, its bonding will be ionic. If a compound is made from two non-metals, its bonding will be covalent.
This sea grass has had the sun shining on it for most of the day. What can the sea grass do because it is in sunlight? What does this mean for the number of energy storage molecules in the sea grass?
The sea grass can
Answer:
I don't really get your question but I think my answer relates to your question :)
Explanation:
Due to the high availability of sunlight, sea grass can get the sufficient light energy to carry photosynthesis and storage of energy.
What is photosynthesis ?Photosynthesis is a biochemical process by which green plants synthesis energy and in the leaves by the aid of light energy. Here, the light energy is converted to chemical energy.
Plants need sunlight for the light reaction of photosynthesis. In the absence of sunlight, they cant synthesis energy and the chlorophyll does not get active. They will grow towards sunlight.
The sea grass are getting sufficient light energy for the synthesis of energy. The energy storage molecules ie. ATP in sea grass will be synthesized in higher rate with the presence of sun shining.
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What is limiting reagent?
:~}
In a chemical reaction, reactant which is present in the lesser amount gets consumed after sometime and after that no further reaction takes place whatever be the amount of the other reactant present.
Explanation:
~A limiting reagent is the reactant that gets consumed early in a chemical reaction
What is a Limiting reagent ?During a chemical reaction the reactant that gets consumed early in the reaction limits the quantity of product which will be produced in the chemical reaction. therefore the reactant that gets consumed early in a chemical reaction is a limiting reagent.
Hence we can conlcude that A limiting reagent is the reactan that gets consumed early in a chemical reaction.
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suppose you have two samples that are equal in weight, 22.3 g zn and 22.3 g cr2o3 . calculate the number of moles of each substance.
The Number of Moles of Zn is 0.34108 and the number of moles of Cr2O3 is 0.14671.
What is Number of Moles?
The ratio of a substance's given mass in a chemical reaction to the mass of one mole of that material is what determines how many moles there are of that substance. A mole of any substance is equal to 6.0231023, or Avogadro's number. The ratio of a substance's given mass in any kind of chemical reaction to the mass of one mole of that material is the number of moles of that substance.
Moles of Zn can be calculated by using the formula
22.3 g of Zn x 1 mole Zn/65.4 g = 0.341 moles of Zn.
Moles of Cr2O3 can be calculated by using the formula
22.3 g of Cr2O3 x 1 mole Cr2O3/151.99 = 0.146 moles of Cr2O3.
Hence, 0.34108 and 0.14671 will be the number of moles for Zn adn Cr2O3 respectively.
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Zn has a mole count of 0.34108, while Cr2O3 has a mole count of 0.14671.
What is Number of Moles?
The number of moles of a substance is determined by the ratio of its given mass in a chemical reaction towards the mass of one mole of that substance. A mole, or 6.0231023, is equal to one mole of any substance. The number of moles of a substance is defined as the mass of one mole divided by the given mass of the substance in any type of chemical reaction.
The formula can be used to determine moles of zinc.
22.3 g of Zn x 1 mole Zn/65.4 g = 0.341 moles of Zn.
The formula can be used to determine moles of Cr2O3.
22.3 g of Cr2O3 x 1 mole Cr2O3/151.99 = 0.146 moles of Cr2O3.
Therefore, the moles of Zn and Cr2O3 will be 0.34108 and 0.14671, respectively.
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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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6. What is NOT an example of a solution?
a. Acetic acid and water
b, soil and water
b. Sugar and water
c. iron and carbon
If we triple the temperature and double the volume, what would the new pressure of the system be?Group of answer choicesa. 20 atmb. 15 atmc. 7.5 atmd. 10 atm
If we triple the temperature and double the volume, The new pressure of the system be 10atm.
The equation of state for a fictitious ideal gas is known as the ideal gas law. Although it has several drawbacks, it is a decent approximation of the behaviour of numerous gases under various circumstances. The formula for the ideal gas equation is
To find pressure we us ideal gas equation:
PV = nRT
Therefore, if we multiply Volume by 2 and Temperature by 3, we get.
hence, by adding.
Given that nR are constant throughout, P (2V)=nR(3T).
then would only consider variables
P = 3T/2V
So p = 1.5 T/V
It can alternatively be expressed as P/1.5=T/V.
Pressure would therefore drop by a factor of 1.5 division.
The new pressure of the system is 10atm.
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Practice It!
Which of the following is a type of cell division that is necessary to prepare the chromosomes for sexual reproduction?
Meiosis
Mitosis
Translation
Transcription
25 points each, brainlets for best anser, SOoooo please help me -n-
Answer:
Wowowoowoww
St0p tHe sPamM MaAn
Okay little brain
Is there a difference between normal, dry, and oil shampoo?
Please put the URL (the info you got from)
The main difference between normal, dry, and oil shampoo is that normal shampoo has half amount of oil, dry shampoo has no oil content and oil shampoo has a large amount of oil.
Is dry shampoo better than regular shampoo?Experts say dry shampoo is great once but it shouldn't be a full-time replacement for washing your hair with water. Dry shampoo can be considered to be a hair freshener as compared to a hair cleaner. It does nothing to clean your scalp, which collects dirt.
Dry shampoo is not shampoo at all. The spray absorbs the oil content in your hair, making it less distinguishable. It doesn't remove oil and dirt the same way which is removed by shampoo and water.
So we can conclude that normal, dry, and oil shampoo has a different amount of oil content.
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c) Can two electrons have same set of all four quantum numbers? Justify.
It is not possible for two electrons to have the same set of all four quantum numbers in an atom, as it would violate the Pauli exclusion principle.
According to the Pauli exclusion principle, no two electrons in an atom can have the same set of all four quantum numbers. The four quantum numbers used to describe an electron's state are the principal quantum number (n), the azimuthal quantum number (l), the magnetic quantum number (m), and the spin quantum number (s).
The principal quantum number (n) determines the energy level of an electron and can have integer values starting from 1. The azimuthal quantum number (l) determines the shape of the electron's orbital and can have values from 0 to (n-1). The magnetic quantum number (m) determines the orientation of the orbital and can range from -l to +l. The spin quantum number (s) describes the spin of the electron and can have two possible values, +1/2 or -1/2.
Since each electron in an atom must occupy a unique set of quantum numbers, they must differ in at least one of the four quantum numbers. This ensures that no two electrons have the exact same quantum state.
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Science/chemistry question
The researcher should select arsenic because it belongs in the same group as phosphorus but has a higher atomic mass.
The correct option is C.
What are the elements in the same group as phosphorus in the periodic table?Phosphorus is in Group 15 (also known as Group V) of the periodic table. Elements in this group have 5 valence electrons, which means they tend to form compounds with a -3 oxidation state.
Other elements in Group 15 are:
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2... The table below shows the results of tests carried out on a salt D. Copy and complete the table. Test (a) (i) D + 10 cm³ of distilled water (ii) Solution D tested with litmus paper (b) (i) D (aq) + NaOH(aq) in drops, then in excess (ii) D (aq) + dil. NH3 solution in drops, then in excess (c) D (aq) + dil. HNO3 + AgNO3(aq) + NH3(aq) (d) Write the formula of the salt. Observation D dissolved to give a colourless solution White gelatinous precipitate Precipitate dissolved No visible reaction.. White precipitate Precipitate dissolved Inference Solution is acidic Zn²+ present
The question deals with the process of qualitative analysis and the salt we are to identify is D which is ZnCl2.
What is qualitative analysis of metal ions in chemistry?Qualitative analysis of metal ions in chemistry is the process of identifying the presence or absence of various metal ions in a given sample through the use of chemical tests. Qualitative analysis is important because it helps to identify the chemical composition of a substance.
We can see that the time that the NaOH(aq) in drops, then in excess was added, there was the appearance of a ppt which is Zn(OH)2. This is going to dissolve in excess.
Addition of dil. HNO3 + AgNO3(aq) + NH3(aq) would confirm the presence of the chloride anion.
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The temperature of a 95.4 g piece of copper decreases from 48°C to 25°C when the copper releases - 849 J of heat. What is the specific heat of copper?
a typical lead-acid storage battery contains sulfuric acid, h2so4, which breaks down into 2h so4 and each molecule delivers two electrons to the external circuit. if the battery delivers a total charge of 2.0 x 105 c, how many grams of sulfuric acid are used up?
\(61.25 \times 10^{24}\) grams of sulfuric acid is required if the battery delivers a total charge of 2.0 × 10⁵ C.
Each molecule of H₂SO₄ breaks into 2H and SO₄ and two electrons.
These two electrons are responsible for the charge delivered to the battery.
If total charge delivered to the battery is 2.0 × 10⁵ C.
The charge on each electron is \(1.6 \times 10^{-19}\) C.
Total number of electrons that can produce 2.0 × 10⁵ C is,
\(\dfrac{2.0 \times 10^{5} }{1.6 \times 10^{-19}}\)
= electrons.
98 grams of H₂SO₄ delivers 2e⁻ to the battery.
1e⁻ needs 49 grams of H₂SO₄.
\(1.25 \times 10^{24}\) electrons will require, \(61.25 \times 10^{24}\) grams of sulfuric acid.
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Students were asked to select methods to increase the rate of dissolving a solid. Which methods would increase the rate?
Increasing the surface area, stirring or agitating the mixture, raising the solvent's temperature, and employing a solvent with a stronger polarity or one that is more similar to the solid's chemical makeup are all ways to speed up the dissolving process.
The methods to increase the rate of dissolving a solid.There are several methods that can increase the rate of dissolving a solid, including:
Increasing the surface area of the solid by crushing, grinding or pulverizing it into smaller pieces.
- Stirring or agitating the mixture, which helps to distribute the solvent and increase contact between the solvent and the solid.
- Increasing the temperature of the solvent, which increases the kinetic energy of the solvent molecules, making them more likely to collide with and dissolve the solid.
- Using a solvent that has a higher polarity or is more similar in composition to the solid, which can increase the attraction between the solvent and the solid and promote faster dissolving.
Therefore, the methods that would increase the rate of dissolving a solid are increasing surface area, stirring or agitating the mixture, increasing the temperature of the solvent, and using a solvent that has a higher polarity or is more similar in composition to the solid.
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A 5.25 L container of ammonia gas exerts a pressure of 652 mm Hg at a temperature of 243 K. Calculate the pressure of this same amount of gas in a
3.50 L container at a temperature of 221 K.
Show your work
Answer:
889.46 mmHg (2 d.p.)
Explanation:
Since we are dealing with the same amount of gas, but at different temperatures and volumes, we can use the combined gas law.
Combined Gas Law\(\boxed{\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}}\)
where:
P₁ is the initial pressure.V₁ is the initial volume.T₁ is the initial temperature (in kelvin).P₂ is the final pressure.V₂ is the final volume.T₂ is the final temperature (in kelvin).As we want to find the final pressure, rearrange the formula to isolate P₂:
\(\sf P_2=\dfrac{P_1V_1T_2}{T_1V_2}\)
The given values are:
P₁ = 652 mmHgV₁ = 5.25 LT₁ = 243 KV₂ = 3.50 LT₂ = 221 KSubstitute the values into the formula and solve for P₂:
\(\implies \sf P_2=\dfrac{652 \cdot 5.25 \cdot 221}{243 \cdot 3.50}\)
\(\implies \sf P_2=\dfrac{756483}{850.5}\)
\(\implies \sf P_2=889.456790...\)
\(\implies \sf P_2=889.46\;mmHg\;(2\;d.p.)\)
Therefore, the final pressure of the same amount of ammonia gas in a 3.50 L container at a temperature of 221 K is 889.46 mmHg (2 d.p.).
A chemist weighed out 2.9 g of nickel. Calculate the number of moles of nickel she weighed out. Be sure your answer has the correct number of significant digits.
Answer:moles = 2.9 g Ni × 1 mol Ni 58.69 g Ni = 0.0663 mol Ni
A sample of iodine-131 has an activity of 200 mCi. If the half-life of iodine-131 is 8. 0 days, what activity is observed after 16 days?
0. 5 half lives
Step [1]: Determine the number of half lives.
x 128
5. 88 x10-37
mci
16 days
128 half lives
2 half lives
80 half lives
1 day
Step [2]: Find the final activity.
50. 0 mci
200. Mci
200. Mci
(initial activity)
Iodine-131 is a radioactive isotope of iodine that has a half-life of 8.0 days. This means that after 8.0 days, half of the original amount of iodine-131 will have decayed, and after another 8.0 days (a total of 16 days), half of the remaining iodine-131 will have decayed again.
The activity of a radioactive sample is a measure of the number of radioactive decays that occur in a given time period. It is measured in units of becquerels (Bq) or curies (Ci). One curie is equal to 3.7 x 10^10 becquerels.
In this case, we are given that the initial activity of the sample is 200 mCi (milliCuries). To find the activity after 16 days, we can use the following equation:
Activity = Initial activity x (1/2)^(t/half-life)
where t is the time elapsed and half-life is the half-life of the isotope.
Substituting the given values, we get:
Activity = 200 mCi x (1/2)^(16/8)
Activity = 200 mCi x (1/2)^2
Activity = 200 mCi x 0.25
Activity = 50 mCi
Therefore, the activity observed after 16 days is 50 mCi. This means that half of the original iodine-131 has decayed in that time period. It is important to note that the actual number of atoms remaining in the sample will also be halved after 16 days, but the activity will be reduced by a factor of four (since activity is proportional to the number of decays per unit time).
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I need help finding the answer to this question
Answer:
1.1 for 3d, 0.76 for 16d.
Explanation:
You divide the mass of one nail by the nail size.... I think
You check the air pressure in your car tires on Monday morning and the pressure
reads 765 mmHg. A cold front drops the temperature considerably overnight. You
check your tire pressure Tuesday morning and the pressure reads 740 mmHg.
Using what you've learned about the properties of gases, what causes this change
in pressure?
when sodium metal is cut its surface become dull even they are not heated
Explanation:
Sufficient heat is produced in the reaction to cause the Metal to heat and to ignite the hydrogen produced in the reaction. Freshly cut sodium metal has a bright, shine surface that quickly become dull as it reacts with oxygen in the air around it.the calibration curve shows a steeper slope for the theobromine samples than for the caffeine samples. does this mean the detector is more sensitive to theobromine? why or why not? (consider the previous question in your answer.) 9. based on the structures of the molecules, would you expect the uv light to interact with them differently? 10. how would the calibration curves based on peak areas be different from the ones shown? how would they be similar?
(A).The steeper slope in the calibration curve for theobromine samples compared to caffeine samples does not necessarily mean that the detector is more sensitive to theobromine. (B). The calibration curves based on peak areas would likely show similar trends as the ones based on peak height.
The slope of the calibration curve is affected by various factors, such as the concentration of the analyte and the detector response. Thus, the difference in slope could be due to differences in the chemical properties of the two compounds that affect their behavior in the analytical system. . The peak area-based calibration curve would likely be more precise, particularly at lower concentrations, where the peaks are typically narrower and less well-defined.
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--The complete Question is, The calibration curve shows a steeper slope for the theobromine samples than for the caffeine samples. does this mean the detector is more sensitive to theobromine? why or why not? (consider the previous question in your answer.)
A. based on the structures of the molecules, would you expect the UV light to interact with them differently?
B. how would the calibration curves based on peak areas be different from the ones shown? how would they be similar? --
. The four metals, Strontium(Sr), Francium (Fr), Yttrium (Y), and Europium (Eu), in separate experiments, are dipped in aqueous solutions of SrNO3, FrNO3, Y(NO3)3, and Eu(NO3)2. The following results are obtained: 1. Yttrium metal does not react with any of the solutions 2. Strontium metal reacts with all of the other metals solutions 3. Francium metal reacts in a solution of Eu(NO3)2 a) List the four oxidizing agents in order from strongest to weakest by creating a small reduction table. Explain your reasoning below b) List the four reducing agents in order from strongest to weakest
Answer:
a) Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺
b) Sr > Fr > Eu > Y
Explanation:
Y is the least reactive metal because it does not react with any of the other solutions.
Sr is the most reactive metal because it reacts with all of the other solutions.
Sr + 2Fr⁺ ⟶Sr²⁺ + 2Fr
3Sr + 2Y³⁺ ⟶ 2Sr²⁺ + 2Y
Sr + Eu²⁺ ⟶ Sr²⁺ + Eu
Fr is more reactive than Eu because it reacts with Eu(NO₃)₂.
2Fr + Eu²⁺ ⟶ 2Fr⁺ + Eu
The order of reactivity is
Sr > Fr > Eu > Y
b) Reducing agents
In each of the above reactions. the more reactive metal is acting as a reducing agent — it is donating electrons to the cation of the other metal.
Thus, the order of activity of reducing agents is
Sr > Fr > Eu > Y
a) Oxidizing agents
The metal cations are the oxidizing agents.
The order of reactivity of the oxidizing agents is the reverse order of the reducing agents
Y³⁺ > Eu²⁺ > Fr⁺ > Sr²⁺
c) Standard reduction potential table
See the image below.
Solve the questions shown
The number of electrons, protons, and neutrons in argon is 18, 18 , and 22 respectively, the number of electrons , protons and neutrons in sulphur-32 is 16, 16, 16 respectively. The number of protons, neutrons, and electrons are 6 , 8 and 6. And for uranium-238 , 92 protons , 92 electrons and 146 neutrons.
What is proton, neutron, and electron and argon, sulphur, and uranium consist how many electrons, neutrons and protons?Electrons are the one revolving around the nucleus in shells K,L,M and N which have attraction to the nucleus.For uranium which is a radioactive element have two isotopes namely uranium-238 and uranium-235.The number of electrons , protons and neutrons in argon which is a noble gas element have 18, 18 and 22 respectively.The number of electrons, protons and neutrons in sulphur are 16, 16 and 16 respectively.The number of electrons, protons and neutrons in argon is 18,18 and 18 .To know more about electrons visit:
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How many moles of solute are present in .75 l of a .89 m (molar) solution?
0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.
Define the molarity of a solution.Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.
Given data:
V= 0.75
M=0.89
Molality = \(\frac{Moles \;solute}{Volume of solution in litre}\)
0.89 M= \(\frac{Moles \;solute}{0.75 L}\)
Moles= 0.6675
Hence, 0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.
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Select the statement that correctly describes the connection between two nucleotides:
A phosphodiester bond would form between the phosphate groups of each of the nucleotides..
A phosphodiester bond would form between the base of one nucleotide and the phosphate of the second nucleotide.
A phosphodiester bond would form between the phosphate group of one nucleotide and a hydroxyl group of the second nucleotide.
A phosphodiester bond would form between a purine base of one nucleotide and a hydroxyl group of the second nucleotide.
Answer:
The band that looks like milk in the night sky isn't actually milk,
Explanation:
Which is a trait of a technical text?
What reactants form a combustion reaction?
Answer:
Hydrocarbon and oxygen
Explanation:
"a substance reacts with oxygen gas, it must involve O² as one of the reactants."
Using this, we can confirm Hydrocarbon and oxygen is a valid one.
Identify whether the following foods made with sugar are mixtures , solutions , or supersaturated a . Chocolate candy bar b . Fruit glaze c . Fruit roll up d . Jelly e . Lemonade f . Lollipop g. Soft drink h . Sweet roll i . Sweetened iced tea j . Taffy
The given sugar food substances can be classified as:
Mixtures: Chocolate candy bar; Fruit glaze; Fruit roll up; Jelly; Lemonade; Lollipop; Soft drink; Sweet roll; Sweetened iced tea; TaffySolutions: Sweetened iced tea; Soft drink; LemonadeSupersaturated solution: Lollipop; Fruit glaze; Fruit roll up; Chocolate candy bar; JellyWhat are mixtures?Mixtures contain two or more substances physically joined together.
Examples are brass and carbonated drinks
What are Solutions?Solutions contains solutes dissolved in solvents.
Examples are sugar and salt solution.
Supersaturated solutions contain more than enough solute in a solvent.
Examples are Jelly and Jam.
Based on the definitions, the given substances can be classified as:
Mixtures: Chocolate candy bar; Fruit glaze; Fruit roll up; Jelly; Lemonade; Lollipop; Soft drink; Sweet roll; Sweetened iced tea; TaffySolutions: Sweetened iced tea; Soft drink; LemonadeSupersaturated solution: Lollipop; Fruit glaze; Fruit roll up; Chocolate candy bar; JellyLearn more about mixtures and solutions at: https://brainly.com/question/767871
If you are given the amount of MOLES CONSUMED of a compound, and it asks you for the mass percent of said compound, how do you find the mass percent of said compound?
Answer:
When we talk about a compound's mass percent, we want to know how much of that chemical is in a combination or sample. To calculate the mass percent, we must first know how much of the compound we have and how much of everything else we have.
Assume we have a dish of fruits that weights 100 grammes. We'd want to know how much of the fruit is made up of kiwis. We count the kiwis and discover that there are twenty of them.
To calculate the mass % of kiwis, we must first determine how much they weigh in comparison to the rest of the fruits. Assume the kiwis weigh 40 grammes in total. We may use this data to compute the percentage of kiwis in the fruit:
Mass percent of kiwis = (mass of kiwis ÷ total mass of fruits) × 100%
Mass of kiwis = 40 grams
Total mass of fruits= 100 grams
Mass percent of kiwis= (40 grams ÷ 100 grams) × 100% = 40%
So we can say that the fruits is 40% kiwis.
Similarly, when we want to find the mass percent of a compound in a mixture or sample, we need to know how much of that compound we have and how much of everything else we have. We can use the formula I gave earlier to calculate the mass percent of the compound.
which is Mass percent = (mass of compound consumed ÷ total mass of sample) × 100%
Below here is the answer, but i suggest you should give it a try first :)
Molar mass of the compound = 20 grams/mole
Mass of the compound consumed = 2 moles × 20 grams/mole = 40 grams
Total mass of the sample or mixture = 50 grams
Mass percent of the compound = (40 grams ÷ 50 grams) × 100% = 80%
So the mass percent of the compound in the sample is 80%.