What 2 factors affect the impulse on an object in a collision?

Answer:

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

Explanation:

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):

\(T=\frac{1}{f}\)

In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:

\(T=\frac{1}{5*10^{10} Hz }\)

Solving:

T= 2*10⁻¹¹ seconds

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

The fequency is defined as the number of cycles achieved by the any wave it is expressed in hertz.

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):

\(T=\dfrac{1}{f}\)

In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:

\(T=\dfrac{1}{5\times 10^{10}}=2\times 10^{-11}\ Sec\)

A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

Thus a microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.

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The gravitational force between two people with 59 kg masses standing 2 meters apart is approximately 4.61 x 10^-8 Newtons.

The gravitational force between two objects can be calculated using the equation F = (G * m1 * m2) / r^2, where F is the force, G is the gravitational constant (approximately 6.67430 x 10^-11 N(m/kg)^2), m1 and m2 are the masses of the two objects, and r is the distance between them. Plugging in the values, we get F = (6.67430 x 10^-11 N(m/kg)^2 * 59 kg * 59 kg) / (2 m)^2, which simplifies to F ≈ 4.61 x 10^-8 N.

When a satellite with mass M takes time T to orbit a planet, doubling the mass to 2M would not change the time for it to orbit the planet. The time for an object to complete one orbit around another object (assuming a circular orbit) only depends on the mass of the central object and the distance between them, not the mass of the orbiting object. Therefore, the time for the satellite to orbit the planet would remain the same.

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Answer: D

Explanation:

cause i got it right

Given that the focal length of the object is F = 2.5 cm.

We have to find the position of the object such that no image is formed.

For a convex lens, the image will not be formed if it is placed at the focus.

Thus, the object should be placed at 2.5 cm as it is the focal length.

Answer

Resistivity R = K * L / A    where resistivity is constant for material, L the length of the material and A the area of the material

K = R * A / L     where R is the resistance of the material

Answer:

33.3m

Explanation:

Recall that for a regular wave, the relationship between, wavelength, frequency  and velocity (speed) is given by :

v = fλ,

where:

v = velocity (speed) of the wave = 50m/s

f = frequency of the wave = 1.5 Hz

λ = wavelength (we are asked to find this)

simply substitute the given values into the equation:

v = fλ

50 = 1.5 λ,

λ = 50/1.5

λ = 33.3m

The percentage change in gravitational energy is ≈ 0.16%

The gravitational potential energy is greater at the airport than at the altitude of the plane because the height h is zero at the airport and positive at the altitude of the plane.

Assuming that the altitude of the plane is significantly smaller than the radius of the Earth, we can use the approximation that the gravitational potential energy U of an object of mass m at a height h above the Earth's surface is given by:

U = -GmM/R + GmM/(R+h)

where G is the gravitational constant, M is the mass of the Earth, R is the radius of the Earth, and h is the height above the Earth's surface.

The percentage change in gravitational energy Un of the system of you and the Earth compared to the gravitational energy U when you were at the airport waiting to board the plane is:

(Un - U)/U * 100%

We can simplify this expression using the above equation for U:

(Un - U)/U = [GmM/(R+h) - GmM/R]/[-GmM/R] = (h/R) / (1 + h/R)

We can use the hint to approximate (1 + h/R) as (1 + x) where x = h/R is small. Then we can use the power series expansion:

(1 + x)^n = 1 + nx + n(n-1)x^2/2! + n(n-1)(n-2)x^3/3! + ...

For small x, we can ignore terms with higher powers of x. So, we can approximate:

(1 + x) ≈ 1 + x

Using this approximation, we can simplify the expression for the percentage change in gravitational energy as:

(Un - U)/U ≈ h/R

So the percentage change in gravitational energy is approximately equal to the ratio of the height above the Earth's surface to the radius of the Earth. If the altitude of the plane is, for example, 10 km and the radius of the Earth is approximately 6371 km, then the percentage change in gravitational energy is:

(Un - U)/U ≈ (10/6371) * 100% ≈ 0.16%

This means that the gravitational potential energy of the system of you and the Earth has increased by about 0.16% when you are at an altitude of 10 km compared to when you were at the airport waiting to board the plane.

As for the second part of the question, the gravitational potential energy is greater at the airport than at the altitude of the plane because the height h is zero at the airport and positive at the altitude of the plane.

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The magnitude of the net force on particle Q₂ is  6.487 x 10⁶ N.

The net force on particle Q₂ is obtained by applying Coulomb's law of electrostatic force.

Force between Q₁ and Q₂;

F₁₂ = kq₁q₂/r²

where;

F₁₂ = (9 x 10⁹ x 20.5 x 10⁻³ x 9.3 x 10⁻³)/(0.98)²

F₁₂ = 1.787 x 10⁶ N

Force between Q₂ and Q₃;

F₂₃ = kq₂q₃/r²

F₂₃ = (9 x 10⁹ x 9.3 x 10⁻³ x 31.6 x 10⁻³)/(0.75)²

F₂₃ = 4.7 x 10⁶ N

The net force on particle Q₂;

F(net) = F₁₂ + F₂₃

F(net) = 1.787 x 10⁶ N +  4.7 x 10⁶ N

F(net) =  6.487 x 10⁶ N

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A decibel is a dimensionless unit to express physical intensity or sound pressure levels.

A decibel is a dimensionless unit to express physical intensity or sound pressure levels. The decibel, in turn, measures the power of the sound, its energy, and the stronger or weaker it is emitted. Measures the volume of the sound.  It is a logarithmic scale that quantifies the relative loudness or softness of a sound compared to a reference level. The decibel scale is based on powers of 10, where an increase of 10 dB represents a tenfold increase in sound intensity. The reference level for the decibel scale varies depending on the context. In the field of acoustics, the commonly used reference level is 0 dB, which corresponds to the threshold of human hearing. Positive decibel values indicate increasing sound levels, while negative values indicate decreasing sound levels or the absence of sound.

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The stroking method of magnetization is a technique used to magnetize ferromagnetic materials. It is based on the principles of domain theory, which helps us understand the behavior of magnetic materials at the atomic and microscopic level.

In domain theory, a ferromagnetic material is composed of many tiny regions called magnetic domains. Each domain consists of a large number of aligned atomic magnetic moments, creating a net magnetic field within the domain.
However, the magnetic moments in different domains can be randomly oriented, resulting in a lack of overall magnetization in the material.

The stroking method takes advantage of the fact that magnetic domains can be influenced and aligned by an external magnetic field. When a ferromagnetic material is subjected to an external magnetic field, the field causes the magnetic moments in the domains to align in the direction of the applied field. As a result, the domains merge and grow in size, leading to an overall magnetization of the material.

To apply the stroking method, a non-magnetized ferromagnetic material, such as a piece of iron, is taken and a strong permanent magnet is brought close to it.
The magnet is then repeatedly stroked along the length of the material in the same direction. The stroking motion ensures that the external magnetic field from the permanent magnet is consistently applied to the material.

As the magnet is stroked, the aligned magnetic domains within the material start to merge and grow. This process continues with each stroke, gradually increasing the overall magnetization of the material. Eventually, after several strokes, the material becomes fully magnetized, with the majority of the magnetic domains aligned in the direction of the stroking.

The stroking method is effective because the repeated application of the external magnetic field helps overcome the resistance of domain boundaries within the material.
These boundaries are regions where magnetic moments change orientation between adjacent domains, and they can hinder the alignment process.
By stroking the material, the external field continuously acts on the domains, encouraging them to overcome these barriers and align more uniformly.

It's important to note that the stroking method is a relatively simple and basic technique for magnetizing materials. In practical applications, more sophisticated methods, such as using electromagnets or specialized machinery, are often employed to achieve precise and controlled magnetization. However, the underlying principle of domain alignment remains a fundamental concept in magnetism.

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Answer:

Yes

Explanation:

You need data to be able to compare experiments and come up with predictions.

the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.

Faraday's Law states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux passing through it. As the current in the straight wire increases, the magnetic field around it strengthens, and the change in magnetic flux through the circular loop causes an induced current. The direction of this induced current is determined by Lenz's Law, which states that the induced current will flow in such a way as to oppose the change in magnetic flux causing it.

In this case, as the magnetic field due to the straight wire increases, the induced current in the circular loop will flow in a direction that generates a magnetic field opposing the increase in the straight wire's magnetic field. The magnitude of the induced current depends on the rate of change of the magnetic field, the loop's size, shape, and distance from the straight wire, as well as the resistance of the loop's material. If the current in a long straight wire is increasing, the current is induced in the circular loop will be generated in the nearby circular loop.

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Given:

Initial velocity = 11 m/s

Average acceleration = -1.81 m/s²

Let's determine how long it takes the horse to decrease its velocity to 6.5 m/s.

Apply the equation of motion:

Where:

v is the final velocity = 6.5 m/s

u is the initial velocity = 11 m/s

a is the acceleration = -1.81 m/s²

t is the time in seconds.

Thus, we have:

Let's solve for t.

Subtract 11 from both sides:

Therefore, it took the horse approximately 2.49 seconds to decrease its velocity to 6.5 m/s

ANSWER:

2.49 seconds.

An action which is an example of a force which operates at a distance is a pebble falling to the ground. Thus, the correct option is B.

A force is an influence which can be changed upon with the motion of an object. A force can cause an object with some amount of mass to change the velocity of the object, i.e., to accelerate the object. Force can also be described as a push or a pull of the object. A force is a vector quantity because it has both the magnitude and direction.

A pebble falling to the ground level is an example of the force which operates at a specific distance. A force applied on the pebble covers some distance.

Therefore, the correct option is B.

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A football player throws a football 30 meters in 2.5 seconds, divide 30 by 2.5 and get 12.

An object's speed, also known as "v," is the amount by which its position changes over time or by how much it changes per unit of time, making it a scalar number.  

The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance traveled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The parameters of speed are time divided by distance. The metre per second (m/s), the SI measure of speed, is the most widely used unit of speed in daily life.

Therefore, A football player throws a football 30 meters in 2.5 seconds, divide 30 by 2.5 and get 12.

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The PR interval is a measurement of the time it takes for electrical impulses to travel from the upper chambers of the heart, called the atria, to the lower chambers, called the ventricles. This interval is measured on an electrocardiogram (ECG or EKG) and is represented by the time between the onset of the P wave and the onset of the QRS complex.

The electrical impulse that initiates the contraction of the heart muscle starts in the sinoatrial (SA) node, located in the right atrium. The impulse then travels through the atria, causing them to contract and pump blood into the ventricles. The impulse then reaches the atrioventricular (AV) node, which is located in the interatrial septum near the tricuspid valve. The AV node acts as a "gatekeeper" for the electrical impulse, slowing it down slightly before it travels through the bundle of His and into the ventricular conduction system. This delay allows the ventricles to fill with blood before they contract.

The PR interval is the time it takes for the electrical impulse to travel from the SA node to the AV node and then through the bundle of His to the ventricular conduction system. A normal PR interval is between 120 and 200 milliseconds. A prolonged PR interval can be a sign of a problem with the AV node or the bundle of His and may lead to a diagnosis of first-degree heart block.

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Answer:

D. Increasing resistance and keeping current from A P E X :))

Explanation:

The decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.

Voltage is the force applied by the power source to charged electrons in a conducting loop, allowing them to perform tasks such as igniting light.

As we know according to the ohm's law:

V = IR

Where 'V' is the volatge,

'I' is the current.

'R' is the resistance.

If we assume 'I' is constant

Then V∝R

As the resistance increases the voltage increases and vice versa.

Thus, the decreasing resistance and keeping current constant leads decreasing in voltage option (C) is correct.

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Answer:

Explanation:

Formula

KE = 1/2 m v^3

Givens

m  = 54 kg

v = 30 m/s

Solution

KE = 1/2 54 * 30^2

KE = 1/2 54 * 900

KE = 27 * 900

KE = 24300 Joules

The magnitude of charge Q that will make the force on charge q zero is Q = 2qL/(√2k),

In summary, the magnitude of charge Q that will make the force on charge q zero is Q = 2qL/(√2k), and its sign is negative if 2q/√2k > q/L, and positive otherwise.

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The block m2 will accelerate up the hill and the magnitude of block's acceleration is \(-2.25m/s^2\) also the tension of the wire is 12.054 N.

Given,

m2 = 3kg

m1 = 1kg

\(\theta = 40 \textdegree\)

Here, the m2 will accelerate uphill.

The free body diagram for the given setup is shown in the figure

Force for the mass m1 can be determined by formula ,F=mg

here, g=-9.8 m/s^2

\(F_1=1*(9.8)=9.8N\)

As the m2 is inclined then the force for m2 can be determined by formula,Here, g is negative because moving against gravity

\(F_2=mgsin\theta=3*(-9.8)*sin40\textdegree=-18.816N\)

The acceleration of the system's blocks can be determined by formula,

\(a=\frac{F_1+F_2}{m_1+m_2}\\\\a=\frac{9.8-18.816}{1+3}\\\\a=\frac{-9.016}{4}=-2.25m/s^2\)

Tension can be calculated by formula,

\(T=m_1g-m_1a=9.8-(-2.254)=12.054 N\)

Thus, the tension of the wire is 12.054 N.

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5

if zero falls between two significant numbers it becomes significant.

Explanation:

san po ung pagpipilian ?

Answer:

Transverse, I took a quiz and got it right :)

Answer:

transverse

Explanation:

This question involves the concepts of centripetal force and angular velocity.

The angular velocity of the Ferris wheel is found to be "1.15 rad/s".

The centripetal force in terms of angular velocity is given by the following formula:

\(F=mr\omega^2\)

where,

F = centripetal force = 1500 N

m = mass of person = 75 kg

r = radius = 15 m

ω = angular velocity = ?

Therefore,

\(1500\ N=(75\ kg)(15\ m)\omega^2\\\\\omega=\sqrt{\frac{1500\ N}{(75\ kg)(15\ m)}}\)

ω = 1.15 rad/s

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The attached picture shows the centripetal force.

Answer:

exercise can lower levels

Answer:

Atomic number...

Explanation:

The number of protons is the same as the number of electrons. The Atomic mass is the number of both the neutrons and number of protons.

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