The sample size needed for the margin of error to be 2% while we are 95% confident is 9604.
Margin of error = 2%
Confidence interval = 95%
The formula to calculate the margin of error is,
MOE = z σ/√n
Here z is the test statistic, σ is the population standard deviation and n is the sample size.
For a normal distribution,
z value for 95% confidence interval = 1.96
Population standard deviation = 1
Substituting,
0.02 = 1.96 / √n
√n = 1.96 / 0.02
n = (1.96/0.02)² = 9604
Hence the sample size is 9604.
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can someone please do this by applying the distributive property
please help I'm timed
Answer:
60 students-530 Question 1.
Step-by-step explanation:
NEED HELP ASAP.
A linear function has a y-intercept of -12 and a slope of 3. What is the equation of the line?
Answer:
y = 3x - 12
Step-by-step explanation:
Hope This Helps!
Plz Mark Brainliest!
answer in standard form PLEASE.
The best answer gets BrainLiest.
Question
The mapping diagram relates the radius of a circle to its area. Choose the correct statement(s) about the mapping diagram.
Answer:
Step-by-step explanation:
numbers 2 and 3
Answer:
A.
Step-by-step explanation:
The correct statement is A.
In a function, each input has only one output.
Statements B, C, and D are false.
hel]pppppppppppppp timed plz hurry
These figures are congruent. What series of transformations moves pentagon FGHIJ onto pentagon F'G'HTU'? Н 4 2 4 2. Note: Rotations are clockwise. Reflections are over the x- or y-axis. O A. Reflection, rotation O B. Reflection, translation O C. Translation, translation O D. Translation, reflection PREVIOUS
Answer:
The series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' is;
C. Translation, translation
Step-by-step explanation:
The coordinates of points in pentagon FGHIJ are F(-2, 0), G(-1, 3), H(-2, 4), I(-5, 4), J(-4, 1)
The coordinates of points in pentagon F'G'H'I'J' are F'(2, 1), G'(3, 4), H'(2, 5), I(-1, 5), J(0, 2)
Therefore the series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' are;
1) A horizontal translation 4 units to the right and
2) A vertical translation 1 unit up
Therefore, the series of transformations that moves pentagon FGHIJ onto pentagon F'G'H'I'J' is T₍₄, ₁₎ which is a translation, translation.
A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the United States. Two surveys are conducted. Of the 35 four-year colleges surveyed, the mean enrollment was 6,193 with a standard deviation of 598. Of the 35 two-year colleges surveyed, the mean enrollment was 4,305 with a standard deviation of 572. Test the student's claim at the 0.01 significance level.
At a significance level of 0.01, we can confidently state that the student's claim is true.
The hypothesis in this question can be stated as follows:
Null Hypothesis: H0: μ1 = μ2 (There is no difference between the mean of four-year college enrollment and two-year college enrollment.)
Alternative Hypothesis: H1: μ1 > μ2 (Mean enrollment of four-year colleges is greater than the mean enrollment of two-year colleges in the United States.)
The significance level (α) is given as 0.01, which represents the probability of rejecting the null hypothesis when it is actually true.
To calculate the test statistic, we can use the formula:
z = ((X1 - X2) - (μ1 - μ2)) / √((σ1² / n1) + (σ2² / n2))
Substituting the given values:
z = ((6193 - 4305) - (0)) / √((598² / 35) + (572² / 35))
z = 10.33
Since this is a right-tailed test, we need to compare the test statistic with the critical value. At a significance level of 0.01, the critical value is 2.33.
The calculated test statistic (10.33) is greater than the critical value (2.33). Therefore, we reject the null hypothesis and conclude that there is enough evidence to support the claim that the mean enrollment at four-year colleges is higher than at two-year colleges in the United States.
In conclusion, at a significance level of 0.01, we can confidently state that the student's claim is true. The mean enrollment at four-year colleges is higher than at two-year colleges in the United States.
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Solve the system of equations
2x-5y=3
X-3y=1
Answer: 2x − 5y = 3
x − 3y = 1
(4, 1)
(5, 2)
(7, 2)
(9, 3)
Step-by-step explanation:
Linda had 90 fliers to post around town. Last week, she posted 1/5 of them. This week, she posted 1/3 of the remaining fliers. How many fliers has she still not posted?
The number of fliers that she has still not broadcasted will be 48 fliers.
What is Algebra?Algebra is the study of ideational characters, while logic is the manipulation of all those opinions.
Linda had 90 fliers to post around town. Last week, she posted 1/5 of them. Then the number of fliers staying is given as,
⇒ (1 - 1/5) x 90
⇒ (4/5) x 90
⇒ 72 fliers
This week, she posted 1/3 of the remaining fliers. Then the number of fliers that she has still not broadcasted is given as,
⇒ (1 - 1/3) x 72
⇒ (2/3) x 72
⇒ 48 fliers
The number of fliers that she has still not broadcasted will be 48 fliers.
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Round 1.2 to the nearest whole number.
Answer:
1
Step-by-step explanation:
When rounding to the nearest whole number by looking at the tenth's value. Remember if it is 5 or more you would raise the number while if it is 4 or less you would round down. In your case you would round down.
0.5, 0.6, 0.7, 0.8, 0.9=1 if rounded to nearest whole number.
0.1, 0.2, 0.3, 0.4=0 if rounded to nearest whole number.
Hope this helps!
A company makes 120 bags.
28 of the bags have buttons but
no zips.
41 of the bags have zips but no
buttons.
23 of the bags have neither zips
nor buttons.
How many bags have buttons
on them?
Answer:
69
Step-by-step explanation:
Answer:
7/15
Step-by-step explanation:
You have 120 bags and 64 of them in total do not contain buttons 120 - 64 = 56 now =you have 56 bags with buttons.
Hope This Help :) Lol
School ends at 3:15 pm. The school provides after -school care for a maximum of 150 minutes after school ends. When is the latest time for pick up?
The latest time for pickup, found by converting the 150 minutes maximum time provided by the school, from minutes to hours is about 5:45 pm
How can minutes be converted into hours?Minutes can be converted into hours by dividing the number of minutes by 60, which is the number of minutes in an hour.
The time that school ends = 3:15 pm
The latest time for pick up after school care = 150 minutes after school ends
Therefore, the latest time for pick up after school care = 3:15 pm + 150 minutes
60 minutes = 1 hour
150 minutes = (1/60) × 150 = 2.5
The latest for pick up = 3:15 pm + 2.5 hours = 5:45 pm
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if ahmod has 2 times as many dimes as nickels and they have a combined value of 100 cents, how many of each coin does he have?
Finally ahmod will have 4 nickels and 10 dimes.
Ahmod has two times as many dimes as nickels.
They have a combined value of 100 cents.
Group all coins in sets by grouping each nickel with 2 dimes.
Each set, containing 1 nickel and 2 dimes, is worth 5 + 2*10 = 25 cents.
You will have 100/25 = 4 such groups
As we have 4 such groups at last ahmod will have 4 nickels and 10 dimes.
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5. Use mental math to determine the solution to
(1 point)
X/3= 24.
Ox=6
Ox=8
Ox=27
Ox= 72
Find the first derivative for each of the following:
y = 3x2 + 5x + 10
y = 100200x + 7x
y = ln(9x4)
The first derivatives for the given functions are:
For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.
For \(y = 100200x + 7x,\) the first derivative is dy/dx = 100207.
For \(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.
To find the first derivative for each of the given functions, we'll use the power rule, constant rule, and chain rule as needed.
For the function\(y = 3x^2 + 5x + 10:\)
Taking the derivative term by term:
\(d/dx (3x^2) = 6x\)
d/dx (5x) = 5
d/dx (10) = 0
Therefore, the first derivative is:
dy/dx = 6x + 5
For the function y = 100200x + 7x:
Taking the derivative term by term:
d/dx (100200x) = 100200
d/dx (7x) = 7
Therefore, the first derivative is:
dy/dx = 100200 + 7 = 100207
For the function \(y = ln(9x^4):\)
Using the chain rule, the derivative of ln(u) is du/dx divided by u:
dy/dx = (1/u) \(\times\) du/dx
Let's differentiate the function using the chain rule:
\(u = 9x^4\)
\(du/dx = d/dx (9x^4) = 36x^3\)
Now, substitute the values back into the derivative formula:
\(dy/dx = (1/u) \times du/dx = (1/(9x^4)) \times (36x^3) = 36x^3 / (9x^4) = 4/x\)
Therefore, the first derivative is:
dy/dx = 4/x
To summarize:
For \(y = 3x^2 + 5x + 10,\) the first derivative is dy/dx = 6x + 5.
For y = 100200x + 7x, the first derivative is dy/dx = 100207.
For\(y = ln(9x^4),\) the first derivative is dy/dx = 4/x.
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the legs of a right triangle measure 5 inches and 7 inches if the theta is the the angle between the 5 inch leg and hypotenuse, cos
theta
9514 1404 393
Answer:
cos(θ) = (5√74)/74
Step-by-step explanation:
The length of the hypotenuse is given by the Pythagorean theorem:
h = √(5² +7²) = √74
The cosine of the angle is the ratio of the adjacent leg to the hypotenuse:
cos(θ) = 5/√74 = (5√74)/74
Find the area of the sector for the shaded region
JM=10
The area of shaded portion is 42 cm²
Area of shaded region
Side of square ABCD = 14 cm
Radius of circles with centers A, B, C and D = 14/2 = 7 cm
Area of shaded region = Area of square - Area of four sectors subtending right angle
Area of each of the 4 sectors is equal to each other and is a sector of 90° in a circle of 7 cm radius. So, Area of four sectors will be equal to Area of one complete circle
So,
Area of 4 sectors = \(\pi r^2\)
Area of 4 sectors = \(\frac{22}{7}\) × 7 × 7
Area of 4 sectors = \(154 cm^2\)
Area of square ABCD = (Side)²
Area of square ABCD = (14)²
Area of square ABCD = 196 cm²
Area of shaded portion = Area of square ABCD - 4 × Area of each sector
= 196 – 154
= 42 cm²
Therefore, the area of shaded portion is 42 cm²
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The given question is incomplete, The complete question is:
In figure, ABCD is a square of side 14cm. With centres A, B, C and D, four circles are drawn such that each circle touch externally two of the remaining three circles. Find the area of the shaded region.
What is the value of the "8" in the number 17,436,825? A. 800 B. 80 C. 8 D. 8,000
Answer:
A. 800
Step-by-step explanation:
Eight in the number is three places over from the decimal spot. this means the eight is in the hundreds spot. This makes it 800.
determine whether the integral is convergent or divergent. 8 6 6 (x − 6)3 dx
The given integral, 8 6 6 (x − 6)3 dx is convergent. To understand why, let's delve into the explanation.
The integral provided is ∫[8,6] 6(x - 6)^3 dx, where the limits of integration are from 8 to 6. To determine the convergence or divergence of an integral, we need to evaluate the integral and check if the value exists or tends to infinity.
Integrating the given function, we get ∫[8,6] 6(x - 6)^3 dx = 6 * ∫[8,6] (x - 6)^3 dx.
When we evaluate this integral, we find that it converges to a finite value. The convergence of the integral indicates that the area under the curve is well-defined and does not tend to infinity. Therefore, the given integral is convergent.
Note that the specific numerical value of the integral cannot be determined without evaluating it further or providing the function's exact form. The conclusion of convergence is based on the general behavior of the integral.
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Please help me and I’ll give you brainiest!!!!!!!!!
Have a wonderful day!!:)))
Answer:
i think B
Step-by-step explanation:
Fitness mania charges 20$ to join their gym and then 15$ per month.
1. Write an equation in slope intercept form.
2. How much will it cost to belong to Fitness Mania for one year?
3. If a different gym LVAC, charges 0$ to join and 20$ a month, which gym would be the cheaper choice for one year?
Fitness mania is cheaper as $200 < $240
Write an expression for the nth term of the sequence. (your formula should work for n = 1, 2, .) 1 2 , 1 3 , 1 7 , 1 25 , 1 121 ,
The nth term of the sequence can be expressed as: \(1 / (n^2)\)
The given sequence is: 1, 2, 1/3, 1/7, 1/25, 1/121, ...
To find an expression for the nth term of this sequence, we can observe that each term is the reciprocal of a specific pattern of numbers: 1, 2, 3, 4, 5, 6, ...
Notice that the numerator of each term follows a pattern of increasing consecutive positive integers: 1, 2, 3, 4, 5, 6, ...
The denominator of each term follows a pattern of perfect squares: \(1^2, 2^2, 3^2, 4^2, 5^2, 6^2, ...\)
Therefore, the nth term of the sequence can be expressed as:
\(1 / (n^2)\)
So, the expression for the nth term of the sequence is \(1 / (n^2)\). This formula will work for n = 1, 2, 3, and so on.
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can you help me with this? i got it wrong
1) Let's sketch this out so that we can better understand it
2) Reminding ourselves of the metric relations of a right triangle we can write out the following:
\(\begin{gathered} h^2=m\cdot n \\ YO^2=26\cdot12 \\ YO=\sqrt[]{312} \\ OZ=\sqrt[]{26.12} \\ OZ=\sqrt[]{312} \\ YZ=\sqrt[]{312}+\sqrt[]{312} \\ YZ=2\sqrt[]{312} \\ YZ=35.3 \end{gathered}\)Note that the radius intersects that chord with a 90º angle so it bisects that chord.
what is the value of 6 in the number 7689
Answer:
7 6 8 9
The value of 6 is in the hunderth place and represents 600
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In a direct variation, y=8 when x=2. Write a direct variation equation that shows the relationship between x and y.
Answer:
y=4x
Step-by-step explanation:
Direct Variation means y=kx where k is a Constant
since y=8 when x=2
y=kx --> 8=k*2 then k=4
Then y=4x
How many gallons sized milk jugs would it take to fill up the ocean?
Answer:
352 quintillion gallon milk jugs
Step-by-step explanation:
Use the following to answer question 32 and 33. Consider a firm faces the following demand finance.
q=9−p for p≤5
q=24−4p for p≥5
where q is the quantity demanded of the firm's product and p is the price charged by the firm.
[32] At p=6, quantity demanded equals:
A. 3
B. 2
C. 11
D. 0
[33] Suppose the firm's marginal cost and average total cost are both constant at 2. What price should the firm set?
A. 5.50
B. 5.00
C. 4.00
D. 2.25
Since the marginal cost and average total cost are both constant at 2, the optimal price for the firm to set is $5.00.
[32] At p=6, quantity demanded equals 18 as below: When the price charged by the firm is greater than or equal to 5, then q = 24 - 4p for which p=6 satisfies the condition; thus, we can substitute the given value of p into the second equation and solve for q:
q = 24 - 4(6)q = 24 - 24q = 0
Thus, when p=6, the quantity demanded of the firm's product is 0.
[33] Suppose the firm's marginal cost and average total cost are both constant at 2.
The profit-maximizing price is where marginal cost is equal to marginal revenue. To obtain the marginal revenue function, first, we must obtain the inverse demand function and then take the derivative of it. For p ≤ 5, the demand function is q = 9 - p, and for p ≥ 5, the demand function is q = 24 - 4p.
To find the inverse demand function, solve each of the above demand functions for p in terms of q. For p ≤ 5, p = 9 - q, and for p ≥ 5, p = (24 - q)/4.
For p ≤ 5:
R(q) = pq
= (9 - q)q
= 9q - q^2M
R(q) = dR(q)/dq = 9 - 2q
For p ≥ 5:
R(q) = pq
= ((24 - q)/4)
q = 6q - q^2/4M
R(q) = dR(q)/dq
= 6 - q/2
The optimal price charged by the firm is where marginal cost equals marginal revenue:
For p ≤ 5:
2 = 9 - 2q2 + 2q - 9
= 0
q = 7/2
p = 9 - q
= 9 - (7/2)
= 11/2
= 5.50
For p ≥ 5:2 = 6 - q/22 + q/2 - 6 = 0
q = 4p = (24 - q)/4 = (24 - 4)/4 = 5
Since the marginal cost and average total cost are both constant at 2, the optimal price for the firm to set is $5.00.
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consider the equation x rx ? = x3 , where r ? 0 is fixed. show that x ( t )l od in finite time, starting from any initial condition x0 v 0.
The equation x rx ? = x3 , where r ? 0 is fixed, can be solved to determine the solution for x(t), given an initial condition x0 v 0. To do this, we must first rewrite the equation in terms of the initial condition and solve for x(t).
Let x0 = x(0) and rearrange the equation to read:
x rx ? - x3 = 0
Substitute x0 for x and rearrange to read:
x rx0 ? - x3 = 0
Now take the natural logarithm of both sides:
ln(x rx0 ? - x3) = ln 0
Using the properties of logarithms, this simplifies to:
rx0 ? - x2 = 0
This can be further simplified to read:
x2 = rx0
Therefore, the solution for x(t) is:
x(t) = ?(rx0)1/2
It follows that x(t) will reach its limit of zero in a finite amount of time. This can be calculated as:
t = ?(rx0)1/2 / (r/2)
In other words, x(t) will approach zero in finite time, starting from any initial condition x0 v 0.
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PLEASE HELP
if you give me another of those links, i will report you
Answer:
B 10 feet
Step-by-step explanation:
at the end of the equation it says +10 which means it starts 10 feet above the ground
In the given figure, find the value of x?
60 + 3x = 180 ( linear pair)
3x = 180 - 60
3x = 60
x = 60/3
x = 20
- BRAINLIEST answerer ❤️✌
Answer:
40°
Step-by-step explanation:
As per the provided information in the given question, we have :
∠AOC = 60°∠BOC = 3xAB is a straight line.We've been asked to calculate the measure of ∠BOC.
Here, ∠AOC and ∠BOC are making linear pair of angles.
\(\odot \) Linear pair : Linear pair of angles are nothing but the two adjacent angles of which non-common arms are two opposite rays. Now, as these both angles are making linear pair so,
\( \longrightarrow \sf{\quad { \angle AOC + \angle BOC = 180^\circ }} \\ \)
Substitute the measure of ∠AOC and the expression of ∠BOC.
\( \longrightarrow \sf{\quad { 60^\circ+ 3x = 180^\circ }} \\ \)
Transposing the like terms.
\( \longrightarrow \sf{\quad {3x= 180^\circ -60^\circ }} \\ \)
Performing subtraction of the terms in RHS.
\( \longrightarrow \sf{\quad {3x= 120^\circ }} \\ \)
Now, transpose 3 from LHS to RHS, its arithmetic operator will get changed.
\( \longrightarrow \sf{\quad {x= \cancel{\dfrac{120^\circ}{3}} }} \\ \)
Dividing 120° by 3.
\( \longrightarrow \quad\underline {\boxed{ \textbf{\textsf{ x= 40}}^\circ }} \\ \)
∴ The value of x is 40°.
\( \underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad} \\ \)
Learn More :○ Measure of straight angle = 180°
○ If a ray stands on a line then the sum of the adjacent angles so formed is 180°.
○ The sum of the angles of a linear pair is 180°.
\( \setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}\)