Water flows in a 10 mm galvanized pipe at a rate of 0.05 m3/hr. we find that f converges to approximately 0.026.
To determine the friction factor (f) in the pipe, we need to consider the properties of the pipe, the flow conditions, and the Reynolds number. The friction factor varies depending on these factors and may require experimental or empirical data for accurate determination.
However, we can make an estimation using an empirical correlation for the friction factor in turbulent flow called the Colebrook-White equation:
1 / √f = -2.0 * log10((ε/D)/3.7 + 2.51 / (Re * √f))
where:
f is the friction factor (to be determined)
ε is the pipe roughness (for galvanized pipe, it can be around 0.046 mm)
D is the pipe diameter
Re is the Reynolds number of the flow
Given:
Q = 0.05 m^3/hr
D = 10 mm = 0.01 m
ε (roughness) = 0.046 mm = 0.000046 m
First, let's convert the flow rate from m^3/hr to m^3/s:
Q = 0.05 m^3/hr * (1/3600) hr/s = 0.0000139 m^3/s
Now, let's calculate the Reynolds number (Re):
Re = (ρ * Q * D) / μ
Since the fluid is water, we can use the following properties:
ρ (density of water) = 1000 kg/m^3 (approximately)
μ (dynamic viscosity of water) = 0.001 kg/(m·s)
Re = (1000 kg/m^3 * 0.0000139 m^3/s * 0.01 m) / 0.001 kg/(m·s)
Re = 139
Now, we can solve the Cole brook-White equation iteratively to estimate the friction factor (f). By using an initial guess of f = 0.02, we can substitute the values and solve for f iteratively until it converges:
Guess: f = 0.02
1 / √0.02 = -2.0 * log10((0.000046/0.01)/3.7 + 2.51 / (139 * √0.02))
Solving iteratively, we find that f converges to approximately 0.026.
Therefore, the estimated friction factor (f) in the 10 mm galvanized pipe is approximately 0.026. Keep in mind that this is an estimation, and for more accurate results, experimental data or additional calculations based on specific pipe and flow conditions might be necessary.
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A circuit has a resistance of 4.0 Ohms. What voltage will produce a current of 1.4 Amps in the circuit
Answer:
5.6 volts
Explanation:
According to Ohm's Law, V = IR
where V = voltage, I = Current and R = resistance
This is in finance literacy Please help ASAP
C. the amount of money in your checking account
Nellie whirls a tether ball in a horizontal circular path over her head. if the action force is nellie pulling on the string, the reaction force is?
The reaction force is string pulling on the Nellie when a tether ball in a horizontal circular path over her head .
A reaction force is a force that acts in the opposite direction to an action force. i.e. Newton's third law of motion describes action and reaction forces and the law states that for every action force, there is an equal and opposite reaction force.
There are Newton's three law of motion which can be describe as ,
The first law is can be stated as, an object will not change its motion unless a external force acts on it.
The second law is describe as, the force on an object is equal to its mass times its acceleration. i.e.
F = ma
In above equation F is force , m is mass and a is acceleration on an object.
The third law can be explained as, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Therefore , from the above discussion can be said as Nellie whirls a tether ball in a horizontal circulars path over her head. if the action force is nellie pulling on the string, the reaction force is string pulling on the Nellie.
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Explain the effect of changing the temperature on pressure in terms of velocity and force of particles
Answer:
As the temperature increases, the average kinetic energy increases as does the velocity of the gas particles hitting the walls of the container
Explanation:
How far must a 2.0-cm-diameter piston be pushed down into one cylinder of a hydraulic lift to raise an 9-cm-diameter piston by 30 cm
The distance the 2.0-cm-diameter piston must be pushed down to raise 9 cm diameter is 607.5 cm.
Distance the piston must be pushed down
The distance the piston must be pushed down is calculated as follows;
A₁d₁ = A₂d₂
πr₁²d₁ = πr₂²d₂
r₁²d₁ = r₂²d₂
(1)²(d₁) = (4.5)²30
d₁ = 607.5 cm
Thus, the distance the 2.0-cm-diameter piston must be pushed down to raise 9 cm diameter is 607.5 cm.
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A 2kg rock is dropped from a height of 10m and hits the ground going 11m/s. How much work was done by air resistance as it fell?
Answer: 0.24 kg/m
Explanation: use k = ρ * A * C / 2 as the formulaThe kinetic energy of a javelin is 81 J, and its speed is 9.0 m/s. What is its mass?
A. 0.5 kg
B. 1.0 kg
C. 2.0 kg
D. 9.0 kg
Answer:
2 kg
Explanation:
K.E. = 1/2 m v^2
81 = 1/2 m (9^2)
1 = 1/2 m
m = 2 kg
the graph below shows the speed of an object during a 10 s time interval. In which of the following time intervals is the speed of the object was constant?
a. between 6 s and 8 s
b. between 2 s and 4 s
c. between 0 s and 2 s
d. between 2 s and 5 s
Answer:
b. between 2 s and 4 s
Explanation:
2-4 was both 3m/s
an object hangs from a spring balance, the balance indicates 30n in air 20 n when the object is submerged in water. what does the balance indicate when
The balance will indicate a reading of 10 N when the object is submerged in water.
When an object is submerged in water, it experiences an upward force called buoyancy force which is equal to the weight of the water displaced by the object. As a result, the apparent weight of the object decreases. In this case, when the object is submerged in water, it experiences an upward buoyancy force of 10 N (since the difference between the reading in air and water is 10 N). Therefore, the balance will indicate a reading of 10 N when the object is submerged in water. This phenomenon is commonly used to determine the density of an object by measuring the apparent weight in air and water, and using Archimedes' principle to calculate the buoyancy force and hence, the density.
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Two loudspeakers are hooked up to the same signal generator that is set to generate the same single tone of wavelength 1. You are standing three meters from one speaker and five meters from the other. For what wavelengths I would you hear the tone very loudly at your location? For what wavelengths I would you hear the tone very quietly at your location? Explain your answers.
For destructive interference and a quiet tone at your location, the wavelength I would be 1.5 meters.
To determine the wavelengths at which you would hear the tone very loudly or quietly at your location, we need to consider the concept of interference between the two speakers. At your location, the two speakers are emitting the same single tone with a wavelength of 1. The distance between the two speakers is 5 - 3 = 2 meters. We can calculate the path length difference between the two speakers as follows:
Path Length Difference = Distance to Second Speaker - Distance to First Speaker
= 5 - 3
= 2 meters
For constructive interference, the path length difference should be an integer multiple of the wavelength, which results in a reinforcement of the sound waves. In this case, the wavelength I for constructive interference is given by:
Path Length Difference = n * λ
2 = n * 1
n = 2
So, for constructive interference and a loud tone at your location, the wavelength I would be 2 meters.
For destructive interference, the path length difference should be a half-integer multiple of the wavelength, which results in cancellation of the sound waves. In this case, the wavelength I for destructive interference is given by:
Path Length Difference = (n + 1/2) * λ
2 = (n + 1/2) * 1
n + 1/2 = 2
n = 3/2
Therefore, you would hear the tone very loudly at your location for a wavelength of 2 meters, and very quietly for a wavelength of 1.5 meters. The interference between the two speakers at your location determines the level of sound reinforcement or cancellation, resulting in the variation in loudness.
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What is the electric flux through the cylinder due to this infinite line of charge?.
For an infinite line of charge passing through the axis of a cylinder, the electric flux through the cylinder is zero since the electric field lines are parallel to the curved surface, resulting in no electric flux through it.
To calculate the electric flux through a cylinder due to an infinite line of charge, we can use Gauss's law. Gauss's law states that the electric flux (Φ) through a closed surface is equal to the electric charge enclosed (Q_enc) divided by the permittivity of free space (ε₀).
Given:
The cylinder is a closed surface.
The infinite line of charge is passing through the axis of the cylinder.
Since the cylinder is symmetric and the electric field lines are parallel to its surface, the electric flux passing through the curved surface of the cylinder will be zero. Therefore, we only need to consider the electric flux passing through the top and bottom surfaces of the cylinder.
The electric flux passing through each of the flat surfaces can be calculated using the formula:
Electric flux (Φ) = E × A
where E is the electric field perpendicular to the surface and A is the area of the surface.
For an infinite line of charge, the electric field (E) can be determined using the formula:
E = (λ / (2 × π × ε₀ × r))
where λ is the linear charge density and r is the distance from the line of charge to the surface.
To calculate the electric flux, we need to determine the values of the linear charge density (λ) and the radius (r) of the cylinder. Once we have those values, we can calculate the electric field (E) and then use it to find the electric flux (Φ) through each surface.
Please provide the linear charge density (λ) and the radius (r) of the cylinder so that I can calculate the electric flux accurately.
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For most surfaces, the coefficient of static friction is ____ the coefficient of kinetic friction.
The coefficient of static friction is usually larger than the coefficient of kinetic friction, meaning it takes more force to get an object moving than to keep it moving.
For most surfaces, the coefficient of static friction is greater than the coefficient of kinetic friction.
The coefficient of static friction is the amount of force required to move an object that is initially at rest relative to a surface. This force is usually greater than the force required to keep the object moving, which is the coefficient of kinetic friction. This is because the static force must overcome the resistance of the surface, while the kinetic force is used to maintain the object's relative motion. This is why it takes more effort to start an object moving than to keep it going.
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A given mass of gas has a pressure of 80N/m² at a temperature of 40°C. if the temperature is reduced to 27°C with the volume remaining constant, the new pressure is A. 46.ON/m² B. 75.ON/m² C. 80.0N/m² D. 85.0N/m²
Answer:
Correct Answer: Option B
Explanation:
Explanation
P1/T1 = P2/T2
80/(273+47) = P1/(273+27) = 75Nm-2
Answer: 75.0 Nm^-2
Explanation:
P1/T1 = P2/T2 80/(273+47) = P1/(273+27) = 75Nm-2
hat must the charge (sign and magnitude) of a particle of mass 1.50 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c ? use 9.80 m/s2 for the magnitude of the free-fall acceleration.
The required magnitude of the charge when electric field is given is calculated to be - 2 × 10⁻⁵ C.
Mass of the particle is given as 1.5 g = 1.5 × 10⁻³ kg = 0.0015 kg
The particle encounters an electric field, E = 700 N/C.
The force experienced by the particle is calculated as;
F = m g = E Q
where,
Q is the magnitude of the charge
Q = m g/E = (0.0015× 9.81)/700 = 0.00002 C = 2 × 10⁻⁵ C
The force has to be exerted upward and counter to the electric field. The charge must be negative since the electric field and force are in the opposing directions.
Thus, the charge is calculated to be - 2 × 10⁻⁵ C.
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Which of the following products will have elastic demand (alcohol, gasoline, travel souvenirs, cigarettes)
The product among alcohol, gasoline, travel souvenirs, cigarettes that will have elastic demand is cigarettes.
What is elastic demand?Elastic demand refers to a situation in which a change in the price of a good or service results in a more significant change in the amount demanded. When the percentage change in quantity demanded is greater than the percentage change in price, the demand for the product is said to be elastic.
When the quantity demanded of a product decreases significantly when the price rises, the demand for the product is said to be elastic. Similarly, when a slight change in price causes a significant change in quantity demanded, the demand is said to be elastic. Conversely, if a product's price increases by a small percentage, and the demand for the product decreases by a smaller percentage, the demand for the product is said to be inelastic.
Cigarettes, of all the products listed above, are likely to have an elastic demand.
This is because smokers who are addicted to cigarettes are more likely to quit smoking or reduce their consumption in response to an increase in the price of cigarettes compared to the other goods.
Thus, a slight increase in the price of cigarettes is likely to cause a significant decrease in the number of cigarettes consumed.
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what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake
The medium for an ocean wave is the ocean water which involves movement on the water body.
What is a Medium?This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.
The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.
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A curved line going up indicates the object is
Explanation:
Both graphs show plotted points forming a curved line. Curved lines have changing slope; they may start with a very small slope and begin curving sharply (either upwards or downwards) towards a large slope. In either case, the curved line of changing slope is a sign of accelerated motion (i.e., changing velocity).
a rocky object that orbits the sun, found mostly in the region between mars and jupiter
The rocky object that orbits the sun, found mostly in the region between Mars and Jupiter is known as an asteroid.
Asteroids are rocky objects that orbit the Sun and are too small to be classified as planets. They are typically found in the asteroid belt, a region of the solar system between Mars and Jupiter where most asteroids are located.
Asteroids can range in size from small rocks to dwarf planets like Ceres, the largest object in the asteroid belt. Some asteroids have orbits that take them closer to Earth, and these are known as Near Earth Asteroids (NEAs).
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Write a paragraph about getting to Mars using the dot points
When you are standing in a subway train and the train suddenly stops but your body continues to move forward. Which one of Newton's laws is this?
1st law
2nd law
3rd law
4th law
Answer:
A. 1st law.
Explanation:
Newton's first law of motion states that, an object or body will continue to be at rest or experience a uniform motion in a straight line at constant speed provided there's no action of an external force. Thus, unless compelled to change its state by an external force, a body will continue to be at rest or experience a uniform motion in a straight line.
The Newton's first law of motion is also known as the law of inertia; which is the tendency of a body to be at rest unless acted upon by an external force.
In this scenario, you are standing in a subway train and the train suddenly stops but your body continues to move forward. This is in accordance with Newton's first law of motion.
Hence, the sudden stoppage of the train generates a force which acts on the body thereby causing the passenger to tip or move forward.
a piece of marble of weight 14N and relative density 2.8 is supported by a light string from a spring balance and lowered into a vessel of weighing machine. Before the stone enters the water, the weighing machine reads 57.5N. What will be the reading of both spring balance and weighing machine when the marble is completely immersed
The reading on the weighing machine when the marble is completely immersed will be less than 57.5N,
When the marble is completely immersed in water, the reading of the spring balance will remain the same, at 14N. The spring balance measures the weight of the marble, which is determined by its mass and the acceleration due to gravity. Immersing the marble in water does not change its mass or the gravitational pull, so the weight remains constant.
However, the reading of the weighing machine will change when the marble is immersed. The weighing machine measures the force exerted on it by an object, which is equal to the weight of the object. When the marble is immersed in water, it experiences a buoyant force exerted by the water, which partially counteracts its weight. The buoyant force is equal to the weight of the water displaced by the marble, according to Archimedes' principle.
Since the marble's relative density is given as 2.8, which is greater than 1, it will sink in water. As a result, the buoyant force will be less than the weight of the marble. Therefore, the reading on the weighing machine when the marble is completely immersed will be less than 57.5N, indicating the reduced effective weight of the marble in water. The exact reading on the weighing machine can be calculated by subtracting the buoyant force from the weight of the marble.
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Is anyone a boy here lol?
Answer:
yes there are a lot of boys on this platform
how long does it take a motor with an output of 8.0 w to lift a 2.0 kg object 88 cm?
The takes a motor with an output of 8.0 W approximately 3.632 minutes to lift a 2.0 kg object 88 cm.
The time it takes a motor with an output of 8.0 W to lift a 2.0 kg object 88 cm can be calculated using the equation for work, which is given by:
W = F * d
where W is the work done, F is the force required to lift the object, and d is the distance the object is lifted. The force required to lift the object can be calculated using the equation for weight, which is given by:
F = m * g
where m is the mass of the object and g is the acceleration due to gravity (9.8 m/s^2).
Substituting the values for m and g into the equation for weight, we get:
F = 2.0 kg * 9.8 m/s^2 = 19.6 N
Now that we know the force required to lift the object, we can substitute this value into the equation for work to calculate the work done:
W = F * d = 19.6 N * 88 cm = 1717.28 J
Finally, we can use the equation for power, which is given by:
P = W / t
where P is the power of the motor and t is the time it takes to lift the object. We know the power of the motor (8.0 W) and the work done (1717.28 J), so we can calculate the time it takes to lift the object:
t = W / P = 1717.28 J / 8.0 W = 215.91 seconds = 3.632 minutes
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At the beginning of her fall, does the skydiver have an acceleration?
She experiences a constant acceleration of 9.8 m/s² (the acceleration due to gravity) at the beginning of her fall.
What is the acceleration due to gravity?The acceleration due to gravity is the acceleration that an object experiences when it is in free fall under the influence of gravity.
Here,
As mentioned in the question, At the beginning of her fall, the skydiver has an acceleration at the beginning of her fall. When she first jumps out of the airplane, she is initially at rest and begins to accelerate downwards due to the force of gravity acting on her.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. In the case of the skydiver, the force of gravity is the net force acting on her, and her mass is constant.
Therefore, she experiences a constant acceleration of 9.8 m/s² (the acceleration due to gravity) at the beginning of her fall.
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A forklift raises a 1,020 N crate 3. 50 m up to a shelf. How much work is done by the forklift on the crate? The forklift does J of work on the crate.
Answer:
3,570 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question
force = 1020 N
distance = 3.5 m
We have
workdone = 1020 × 3.5 = 3570
We have the final answer as
3,570 JHope this helps you
A frictionless pulley has a rope going over it the tension in the rope is 1- n on one side and 12 n on the other side what is the angular acceleration of the pulley?
The angular acceleration of the frictionless pulley that has a rope going over it the tension in the rope is 10 n on one side and 12 n on the other side is 16.06 rad/s²
The mass of the solid cylinder, m = 0.83kg and radius, r = 0.30 m
The moment of inertia = 1/2 mr²
I = 1/2 (0.83) (0.30)²
I = 0.03735 kg m²
The net torque = F₁r - F₂r = 12(0.3) - 10(0.3) = 0.6 Nm
Torque = moment of inertia (I) × angular acceleration (α)
Substituting the values,
α = 16.06 rad/s²
Therefore, the angular acceleration of the pulley is 16.06 rad/s².
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(complete question)
A frictionless pulley which can be modeled as a 0.83kg solid cylinder with a 0.30 m radius, has a rope going over it the tension in the rope is 10 n on one side and 12 n on the other side what is the angular acceleration of the pulley?
When is the electromotive force greatest on the electrons in a coil of wire? Select one:a.when the coil of wire is moving perpendicular to the magnetic field b.when the coil of wire is stationary in a magnetic fieldc.when the coil of wire is outside the magnetic field d.when the coil is moving parallel to the magnetic field
Explanation:
The electromotive force acts when the magnetic field is applied to a current-carrying wire.
The electromotive force is given by the formula
\(F=qvBsin\theta\)Here, v is the velocity, q is the charge and theta is the angle between the magnetic field and direction of velocity.
The electromotive force will be maximum when the coil of wire is moving perpendicular to the magnetic field.
Thus, the correct option is a
A scientist performs tests on a sample of an element. The element is a shiny solid that conducts electricity and heat. The scientist is able to bend and flatten the sample when pressure is applied to it.
Based on this information, the element could NOT be a member of which group on the periodic table?
Answer:
Group 18
Explanation:
Answer:
gold
Explanation:
gold is shinny and solid can conduct ele tricity ,maleabl
1.
On a fishing trip you catch a bass, a rock cod, and a salmon with masses of 1.07 kg, 6.0 kg, and
6.05 kg, respectively. What is the total mass of your catch with the proper number of significant
figures?
The total mass of your catch is 13.1 kg
Since you have three fishes a bass, a rock cod, and a salmon with masses of 1.07 kg, 6.0 kg, and 6.05 kg, respectively,
The total mass of your catch = mass of bass + mass of rock cod + mass of salmon
= 1.07 kg + 6.0 kg + 6.05 kg
= 13.12 kg
Since the total mass of your catch is 13.12 kg and we have three catches with two catches to two decimal places and one catch to one decimal place.
We cannot have more decimal places in our answer than the number of decimal places in the number with the least number of decimal places.
Since the least number of decimal places is in the mass of the rock cod which is 6.0 kg, the total mass of our catch is thus 13.1 kg to one decimal place.
So, the total mass of your catch is 13.1 kg
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A public address system puts out 5.92 W of power. What will be the intensity at a distance that results in a surface area of 9.47 m?? 0 355 W/m2 0 56.1 W/m2 O 160 W/m2 O 0.625 W/m2
The intensity at a distance that results in a surface area of 9.47 m is 0.625 W/m2. Option(d)
To calculate the weight of a sound wave at a distance, we can use the formula:
Intensity = Power / Area.
In this case, the public address system has a power output of 5.92 W and a surface area of 9.47 m².
Insert these values into the formula:
Density = 5.
Calculating 92 kilos 9.47 kilos
these instructions, we see that
≈ uses 0.625 W/m².
Therefore, the intensity of the sound waves makes the area 9 at a certain distance.
47 m², approx. 0.625 W/m².
It is important to remember that density is defined as the strength of a field. In this case, it represents sound energy passing through a gap. The unit of use is watt/m2 (W/m²).
The answer given in the question is the correct value according to the calculation of 0.625 W/m². It represents the power of a sound wave over a distance.
The other answer options given by
(0, 355 W/m², 56.1 W/m² and 160 W/m²) do not match the calculation.
The correct answer is 0.625 W/m², which indicates suitable sound intensity away from public housing. Option(d)
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