Use the value of the ratio to fill in the following two multiplicative comparison statements. a. The number of pancakes made is ________ times the amount of cups of flour needed. b. The amount of cups of flour needed is ________ of the number of pancakes made

To solve the given problem we will use the fact that the number of times the graph cuts the axis, that will be the degree of the function.

Given data:

We can see from the graph we can see that y- intercept is

and x- intercept are

Since the x - intercepts are

So, equation will have the form

But this equation does not satisfy the point

As on substituting x=0 in equation 1 we get

So, we should multiply the equatiojn (1) with some constant to satisfy the given condition.

So, the equation will be

So, the required equation is

Answer:

uoooooohuuuuuuuuuuuihouu

Anwser:

2  X=2

Step-by-step explanation:

Because I am right!

Answer:

(48, 3), (80, 5), (160, 10)

Answer: 1. Trapezoid. 2 scalene 3: 24  4: Q and R

Step-by-step explanation:

1 is trapzoid because there's only one parallel side. 2 is scalene since scalene triangles have no same sides. 3 is 24 because 4*2*3. 3 is Q and R because those sides are the same.

Answer: y = 4/3x+1

Step-by-step explanation:

Answer:

y=4/3 + 1

Step-by-step explanation:

There are different ways to do this for finding slope, you can use the formula or you can do rise over run. How to find rise over run you count how many places up so our current place is (-3,-3) and we are trying to find (3,5) so if you were to start with rise, you rise 8 places then run you go either left or right in our case right, you move 6 places.  So our fraction would be 8/6 or simplified 4/3. But using the formula to make sure we got the right answer, our formula is y2-y1/x2-x1 so that would look like 5- -3/3- -3. To solve on our top side two negatives give us a positive so the top is 8 and then bottom is 6 so we get 8/6 or 4/3. But our slope intercept would be y= 4/3x +1.

\(s = \frac{cardinality(s)}{cardinality( \omega)} = \frac{15}{100} = \frac{1.5}{100} \)

The shaded region represents 1.5 grids

\(1.5 = 1 \frac{0.5}{1} = 1 \frac{5}{10} = 1\frac{1}{2} \)

Answer:

D

Step-by-step explanation:

The answer and work is in the attached screenshot! :)

The graph of the translated function is g ( x ) = ( x + 5 )² + 2

Given data ,

Let the parent function be represented as f ( x )

Now , the value of f ( x ) is

f ( x ) = x²

On simplifying , we get

The function is translated 5 units to the horizontal left direction:

And , when the function is translated 2 units in the vertical upward direction:

So , the translated function is

g ( x ) = ( x + 5 )² + 2

Now , the vertex of the function g ( x ) = ( x + 5 )² + 2 is (-5, 2)

Hence , the graph of the function is plotted and g ( x ) = ( x + 5 )² + 2

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Answer:

0.03703703703

Step-by-step explanation:

Look it up

Answer:

Rotation

Step-by-step explanation:

Rotation around the origin I believe

The present age of the elder brother is in a ratio of 23 to the present age of the younger brother, which can be simplified to a ratio of 5 to 4.

Let's assume the present age of the elder brother is E years, and the present age of the younger brother is Y years. According to the given information, the difference in their ages is 5 years, which can be expressed as E - Y = 5.

Six years ago, the elder brother's age was E - 6, and the younger brother's age was Y - 6. According to the second given condition, the product of their ages at that time was 696, which can be expressed as (E - 6)(Y - 6) = 696.

To find the ratio of their present ages, we need to solve the two equations simultaneously. We can start by expanding the second equation:

(E - 6)(Y - 6) = 696

EY - 6E - 6Y + 36 = 696

EY - 6E - 6Y = 660

Now we can substitute the value of E - Y from the first equation into the second equation:

(E - Y) - 6E - 6Y = 660

5 - 6E - 6Y = 660

-6E - 6Y = 655

Simplifying the equation:

6E + 6Y = -655

Now we have a system of linear equations:

E - Y = 5

6E + 6Y = -655

Solving these equations, we find that the present age of the elder brother (E) is 23 years and the present age of the younger brother (Y) is 18 years.

Therefore, the ratio of the present age of the elder brother to the younger brother is 23:18, which can be simplified to 5:4.

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The function values;

Given,

The function; f(x) = 9 × 4ˣ

The value of the function is f(x). The slope of the line is m. b is either the function's value at x=0 or the position at which the line in the coordinate plane crosses the y-axis. x is the x-value. coordinate's

Four main categories can be used to classify different sorts of functions. One to one function, many to one function, onto function, one to one and into function—all based on the element.

We have to find the following function values;

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Answer:

we can compare 4 x 3 and 2 x 6, equal to 12. So, we can see that both products are similar and neither is greater.

Step-by-step explanation:

We can use the commutative property of multiplication to see that 3 x 4 is the same as 4 x 3 and 6 x 2 is the same as 2 x 6. When multiplying two numbers, the order of the numbers does not affect the product. Therefore, we can compare 4 x 3 and 2 x 6, equal to 12. So, we can see that both products are similar and neither is greater.

NEED MORE EXPLANATION?

The commutative property of multiplication states that when multiplying two numbers, the order of the numbers does not affect the product. This means that 3 x 4 is the same as 4 x 3, and 6 x 2 is the same as 2 x 6. We can use this property to compare 4 x 3 and 2 x 6, equal to 12. Therefore, we can see that both products are identical and neither is greater.

The interest rate required for Alejandro to end up with $11,000 is approximately 5.48%

From the question, we are to determine what interest rate would be required in order for Alejandro to end up with $11,000

Since the interest was compounded continuously, we will use the formula

A = Pe^(rt)

Where A is the amount

P is the principal

r is the interest rate

and t is the time.

From the given information,

P = $4,100

r = ?

t = 18

Putting the parameters into the formula

A = Pe^(rt)

11000 = 4100 × e^(r × 18)

11000 = 4100 × e^(18r)

11000 / 4100 = e^(18r)

2.682927 = e^(18r)

Take the natural log of both sides

ln(2.682927) = ln e^(18r)

0.986908 = 18r

r = 0.986908 / 18

r = 0.054828

r = 5.4828%

r ≈ 5.48%

Hence, the rate is 5.48%

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The domain of the function f(x) = 1/5x + 4 is  R - {- 4/5}.

An algebraic expression is a combination of terms both constants and variables. For example -

2x + 3y + z

3x + y

Given is the function as -

f(x) = 1/5x + 4

The given function is -

f(x) = 1/5x + 4

Domain is the set of {x} - values for which the function is defined.

Put -

5x + 4 = 0

x = -4/5

So, we can write the domain as -

domain → R - {-4/5}

Therefore, the domain of the function f(x) = 1/5x + 4 is  R - {- 4/5}.

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The line x=1 is a vertical asymptote of the function\(f(x)=x2−1x2−7x+6\), but the line x=-1 is not, and the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function.

a. The line x=1 is a vertical asymptote of the function  because when x tends to 1, the denominator tends to 0, resulting in an undefined value for the function.

b. The line x=-1 is not a vertical asymptote of the function \(f(x)=x2−1x2−7x+6\) because when x tends to -1, the denominator does not tend to 0, resulting in a finite value for the function.

c. If g has a vertical asymptote at x=1 and\(x→1 +limg(x)=[infinity]\), then \(x→1 −limg(x)=[infinity]\) is not necessarily true. This is because the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function as it approaches the asymptote. For example, if g(x) = 1/x, then\(x→1 +limg(x)=[infinity]\) The line x=1 is a vertical asymptote of the function \(f(x)=x2−1x2−7x+6\), but the line x=-1 is not, and the limit of a function approaching a vertical asymptote can be either positive infinity or negative infinity depending on the value of the function.

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Answer:

add a gallon

Step-by-step explanation:

Perpendicular lines always come together at a 90-degree angle.

What is perpendicular?

A perpendicular is a straight line in mathematics that forms a right angle (90 degrees) with another line. In other words, two lines are perpendicular to one another if they connect at a right angle.

A perfect 90° (degrees) angle, or a quarter turn, is referred to as a right angle in geometry and trigonometry. The angles next to each other are said to be at right angles if a ray is positioned so that its terminus is on a line and they are also equal. The word is a calque of the Latin angelus rectus, where rectus means "upright" and refers to a vertical basis line that is perpendicular to a horizontal baseline.

As the definition suggests the perpendicular lines will intersect with each other at a right angle.

Perpendicular lines are defined as two lines that meet or intersect each other at right angles (90°).

Hence, Perpendicular lines always come together at a 90-degree angle.

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The correct answer is 3/2. In this case, x = 3/2, and its square, (3/2)^2 = 9/4, is rational. x satisfies the given condition.option (c)

To explain further, we need to understand the properties of rational and irrational numbers.

A rational number can be expressed as a fraction of two integers, while an irrational number cannot be expressed as a fraction and has non-repeating, non-terminating decimal representations.

In the given options, (a) √5102.0 (£) and (b) √2 are both irrational numbers.

Their squares, (√5102.0)^2 and (√2)^2, would also be irrational, violating the given condition. On the other hand, (d) 4/5 is rational, and its square, (4/5)^2 = 16/25, is also rational.

Option (c) 3/2 is rational since it can be expressed as a fraction. Its square, (3/2)^2 = 9/4, is rational as well.

Therefore, (c) 3/2 is the only option where x is rational, but its square is irrational, satisfying the condition mentioned in the question.

In summary, the number x that satisfies the given condition, where x^2 is irrational but x is rational, is (c) 3/2.option (c)

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The interest is 16% compounded semi-annually, is Rs. 121,179.10.

To determine how much money needs to be deposited now to provide a payment of Rs. 15,000 at the end of each half year for 10 years, we will use the formula for the present value of an annuity.

Present value of an annuity = (Payment amount x (1 - (1 + r)^-n))/rWhere:r = interest rate per compounding periodn = number of compounding periodsPayment amount = Rs. 15,000n = 10 x 2 = 20 (since there are 2 half years in a year and the payments are made for 10 years)

So, we have:r = 16%/2 = 8% (since the interest is compounded semi-annually)Payment amount = Rs. 15,000Using the above formula, we can calculate the present value of the annuity as follows:

Present value of annuity = (15000 x (1 - (1 + 0.08)^-20))/0.08 = Rs. 121,179.10Therefore, the amount that needs to be deposited now to provide payment of Rs. 15,000 at the end of each half year for 10 years, if the interest is 16% compounded semi-annually, is Rs. 121,179.10.

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Answer:

Hewo can anyone help

Step-by-step explanation:

I would go with the last option,it looks like it makes sense.

Hope that helped,I have snap if you need anything else :)

Answer:

The last one

Step-by-step explanation:

To find:

The number of times graph intersect or touch the x-axis.

Solution:

It is known that the graph touches or intersect x-axis where y = 0. So, the graph touches or intersects when -3x²+x+4 = 0.

The above equation is a quadratic equation. The quadratic equation has two distinct real solutions.

Thus, the graph intersects or touches the x-axis at exactly two points.

So, the third option is correct.

\( \alpha + \beta = 90\)

\( \beta + 4 \alpha = 180\)

\( - \alpha - \beta = - 90\)

\( \beta + 4 \alpha = 180\)

\(3 \alpha = 90\)

\( \alpha = 30\)

\( \beta = 90 - \alpha = 90 - 30 = 60\)

\(( \alpha = 30) < = > ( \beta = 60)\)

Isolating the variable 'a' in the expression, we have:

So the correct option is B.

Answer:

Step-by-step explanation:

Answer:

4.2

Step-by-step explanation:

T = K/N

K= TN

= 3×7

K= 21

Therefore the time required for 5 employees can be calculated as follows

T= 21/5

= 4.2

Answer:

-11

Step-by-step explanation:

I hope this helps. Have a good day!

Answer:

-11

Step-by-step explanation:

21+(-11)=10

a. It represents the spread of the middle 50% of the data.

b. At least 50% of the students scored between 80 and 86.

c. Overall, we can say that the Math 6 class had a range of test scores, with some students performing very well and others performing less well.

How evenly distributed the middle 50% of the data is is determined by the interquartile range. In order to calculate it, the first quartile is subtracted from the third quartile.

A. The interquartile range (IQR) in a box-and-whisker plot is the distance between the first quartile (Q1) and the third quartile (Q3) of the data. It represents the spread of the middle 50% of the data.

B. To determine what percent of the students got 80% or higher, we need to find the upper fence, which is defined as 1.5 times the IQR above Q3. From the box-and-whisker plot, we can see that Q3 is approximately 86 and Q1 is approximately 71. Therefore, the IQR is 86 - 71 = 15. The upper fence is 1.5 * 15 + 86 = 108.5.

Looking at the plot, we can see that there are no data points above 100, so we can safely assume that no students scored above 100%. The highest score is 94, which is within the whiskers of the box-and-whisker plot. Therefore, we know that the percent of students who scored 80% or higher is between the percent of students who scored 80% or higher and the percent of students who scored 94% or higher.

From the plot, we can see that the median is approximately 80 and the third quartile (Q3) is approximately 86. This means that at least 50% of the students scored between 80 and 86. Additionally, we know that the maximum score is 94, so we can say that at least some students scored higher than 86. However, we don't know how many students scored between 86 and 94.

C. Based on the interquartile range, we can say that the middle 50% of the students scored between approximately 71 and 86. This suggests that there is a significant amount of variability in the test scores, as the range is quite wide. Additionally, we know that at least some students scored above 86, but we don't have enough information to determine how many or how high their scores were. Overall, we can say that the Math 6 class had a range of test scores, with some students performing very well and others performing less well.

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Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is the predicted number of years a 40 year old will wait before remarrying?

Given that the study found that the average 40 year old waits 4 years before remarrying, what is the value of the residual for a 40 year old?

Based on the printout and the residual plot, does it appear that time and age have a linear relationship? If so, how strong does the predictive relationship appear to be?

Answer:

 a

  The predicted number of years a 40 year old will wait before remarrying is     \(Time = 4.99\)

  b

  The value of the residual for a 40 year old  is  \(t = 0.99 \ years\)

c

   Based on the print out , we can say that the time and the age has a linear relationship

  And looking the R-sq we can say the 43.7% of time variation is due to age

Step-by-step explanation:

   From the regression equation

         \(Time = 0.03 + 0.124 Age\)

And from the question we are told that Age is  40 years so

      \(Time = 0.03 + 0.124 (40 )\)

      \(Time = 4.99\)

Therefore the predicted time 40 year old will wait for 4.99 years before remarrying

    From the question,the study found that the average 40 year old waits 4 years before remarrying,

     So the residual for a 40 year old is  mathematically evaluated as

              \(t = 4.99 - 4\)

             \(t = 0.99 \ years\)

Based on the print out , we can say that the time and the age has a linear relationship

  And looking the R-sq we can say the 43.7% of time variation is due to age