Use the relationship between the angles in the figure to answer the question. Which equation can be used to find the value of x? O x = 52 x + 52 = 180 O x + 52 = 90 O 52 + 38 = x + 52⁰ хо 1 WHAT'S THE ANSWER ​

Answer:

its the first one I think

2/3 is not greater than 4/5. Rather 4/5 is greater than 2/3.

To find which fractional number is greater than other we need to compare them. To compare two fractional numbers we to make their denominators same. We can do that by taking LCM.

LCM stands for "least common multiple". It is a mathematical concept used to find the smallest positive number divisible by two or more given numbers.

LCM of 3 and 5 is 15

2/3 will change into 10/15, as we multiply 5 with both numerator and denominator.

4/5 will change into 12/15, as we multiply 3 with both  numerator and denominator.

In 10/15  and 12/15 we will compare numerator as denominator is same now.

by comparing, we get:

12/15 > 10/15

So, 4/5 > 2/5

Therefore , 2/3 is not greater than 4/5.

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The correct question is -

"2/3 is greater than 4/5, right or wrong?"

Answer:

-------------------------------------

Given:

Find  the total amount after 5 years:

Find the amount of interest:

Answer:

B. Subtracted x

Step-by-step explanation:

Answer:

b) She subtracted x from both sides

Step-by-step explanation:

Step 1: 3(x - 4) = x + 8

Step 2: 3x - 12 = x + 8

Step 3: 2x – 12 = 8

3(x - 4) = x + 8

3x - 12 = x + 8

- x        - x (here, she subtracted x from both sides)

2x - 12 = 8

Hope this helps!

Answer:

100.

Step-by-step explanation:

Let the number of robberies be x ( in 2013).

Then x - 0.10x = 90

0.90x = 90

x = 90 / 0.90

= 100.

Answer:

44.8

Step-by-step explanation:

Answer:

C≥12,E≥6,C+E≤26

Step-by-step explanation:

i just took the quiz and got it right

The system of inequalities will be C≥12, E≥6, and C+E≤26. Then the correct option is A.

Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

The Inequality to graduate you must take at least 12 core credits,

C≥12

The Inequality to graduate you must take at least 6 electives credits,

E≥6

No more than a total of 26 credits for both core and electives.

C+E≤26

Hence, the correct option is A.

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Answer:

3.33  

Step-by-step explanation:

3 1/3 is equal to ((3*3)+1)/3

= 10/3  

= 3.33   ---------> Final answer

Based on the  calculation done, one can't have a negative number, thus, the regular polygon does not exist.

For a regular polygon of N sides, the measure of each interior angle is:A = (N - 2)*180/N

Here we want to have an interior angle of 220°, then we need to solve the equation:220° =  (N - 2)*180/N

For N, so let's do that: N*220° = (N - 2)*180°We can see that this equation has no solution for N integer:

N*220° = N*180° - 360°N*220° - N*180° = -360°N*40° = -360°N = -360°/40° = -9

We can't have a negative number, thus, the regular polygon does not exist.

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Answer:  31°

Step-by-step explanation:

Supplementary angles add up to 180 degrees so add 149 degrees to a number of degrees to get 180 degrees.That can be represent by the equation,

149 + x = 180  where x is the supplement so solve for x

-149         -149

x = 31

Answer:

100 x 25 x 4 = 10000\(m^{3}\)

Step-by-step explanation:

To summarize, the dimensions of the courtyard that will maximize the area when enclosed with redwood fencing are a length and width of 1:1, or L = W.

The question asks us to find the dimensions of a courtyard that will maximize the area when enclosed with redwood fencing.

In order to solve this problem, we will use a few basic mathematical principles.

First, we need to recognize that the area of a rectangle is equal to the product of its length and width,

or A=L x W.

Therefore, we will be looking to maximize the area by determining the dimensions of the rectangle that will produce the largest area possible.

We can maximize the area by considering the ratio between the length and width of the rectangle.

In this case, a ratio of 1:1 (length:width) will maximize the area.

Therefore, the dimensions of the courtyard that will maximize the area when enclosed with redwood fencing are a length and width of 1:1, or L = W.

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Answer:

21% or C

Step-by-step explanation:

If 60 students either didn't pass, got Cs or Bs, then 16 out of the 76 got As which is 21 percent.

Area of the base 'B' of a given rectangular prism is equal to 12 ft².

As given in the question,

For the given rectangular prism ,

Shape of the base is rectangle,

Length of the base of a rectangular prism = 4 ft

Width of the base of a rectangular prism = 3ft

Area of the base of a rectangular prism is given by

= ( length of the base ) × ( Width of the base)

Substitute the value of length and width of the base of the rectangular prism we get,

= ( 4 × 3 ) ft²

= 12 ft²

Therefore, area of the base 'B' of given rectangular prism is equal to 12 ft².

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Answer:

Step-by-step explanation:

Answer:

\( {2}^{150} \)

Step-by-step explanation:

Expression is represented as:

\(( {2}^{5 \times 2} )^{15} \)

Solve what's inside the parentheses:

\((2^{10} )^{15} \)

Include exponent outside parentheses:

\(2^{150} \)

This exponent represents 2 to the power of 150.

Using the arithmetic operations, the total change in her monthly electric bill over 5 months is +$10.58

For the past 5 months,

The change in her July electric bill = +$18.02

The change in her August electric bill =  +$1.03

The change in her September electric bill = -$0.44

The change in her October electric bill = -$6.84

The change in her November electric bill = -$1.19

The total change in her monthly electric bill over 5 months = Sum of all changes in her electric bill over 5 months

= +18.02+1.03-0.44-6.84-1.19

= +$10.58

Hence, the total change in her monthly electric bill over 5 months is +$10.58

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Answer:

8/27

Step-by-step explanation:

The value of the improper integral \(\int\limits^{infinity}_0 {\frac{1}{x^2+9} } \, dx\) is π/6.

Given integral is,

\(\int\limits^{infinity}_0 {\frac{1}{x^2+9} } \, dx\)

We can calculate the improper integral as,

\(\int\limits^{infinity}_0 {\frac{1}{x^2+9} } \, dx\) = \(\lim_{b \to \infty}[ \int\limits^b_0 {\frac{1}{x^2+9} } \, dx ]\) [Equation 1]

We have,

∫1 / (1 + x²) = tan⁻¹ (x) + C

∫ 1 / (x² + 9) dx = ∫ (1/9) / (x²/9 + 1) dx

                  = 1/9 ∫ 1 / [(x/3)² + 1] dx

Let u = x/3

Then, du = dx/3 or dx = 3 du

Substituting,

∫ 1 / (x² + 9) dx = 1/9 ∫ 1 / (u² + 1) 3 du

                        = 3/9 ∫ 1 / (u² + 1) du

                        = 1/3 [tan⁻¹(u)] + C

                        = 1/3 [tan⁻¹(x/3)] + C

Substituting in Equation 1,

\(\int\limits^{infinity}_0 {\frac{1}{x^2+9} } \, dx\) = \(\lim_{b \to \infty}[ \int\limits^b_0 {\frac{1}{x^2+9} } \, dx ]\)

                        = \(\lim_{b \to \infty}\) [1/3 (tan⁻¹(x/3)]₀ᵇ

                        = 1/3 × \(\lim_{b \to \infty}\) [ tan⁻¹ (b) - tan⁻¹(0)]

                        = 1/3 × \(\lim_{b \to \infty}\) [ tan⁻¹ (b) - 0]

                        = 1/3 × tan⁻¹(∞)

                        = 1/3 × π/2

                        = π/6

Hence the value of the integral is π/6.

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The jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d

From the question, we are to determine the jar that weighs more

From the given information

His jar of pennies weighs 84.96 ounces

and his jar of nickels weighs 3.11 kilograms

First, we will 84.96 ounces to kilogram

From the given conversion,

There are 0.0283495 kilograms per ounce

That is, 0.0283495 kg = 1 ounce

If 1 ounce = 0.0283495 kg

Then,

84.96 ounces = 84.96 × 0.0283495 kg

∴ 84.96 ounces = 2.4086 kg

His jar of pennies weighs 2.4086 kg

Since the John's jar of nickels weighs 3.11 kg, his jar of nickels weigh more.

3.11 kg - 2.4086 kg = 0.7014 kg

Convert 0.7014 kg to pounds

1kg =  2.20462 pounds

∴ 0.7014 kg = 0.7014 × 2.20462 pounds

0.7014kg ≅ 1.55 pounds

Hence, the jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d.

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No, molar mass is a constant and does not depend on pressure or temperature.

Molar mass is a physical property of a substance and is the mass of one mole of a given substance. It is a constant value that represents the amount of grams of a substance that contains 022 x 1023 atoms or molecules. Since molar mass is a constant, it does not depend on pressure or temperature. Pressure and temperature can affect the physical and chemical properties of a substance, but they do not have an effect on the molar mass. The molar mass of a substance can be useful in determining molecular and empirical formulas, as well as calculating densities and molar concentrations.

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To prove this identity, we start with Fermat's Little Theorem, which states that if p is a prime number and a is any integer coprime to p, then a^(p-1) ≡ 1 (mod p).

Using this theorem, we can rewrite the given identity as a^(p-1) * a(p-2) ≡ 1 (mod p^2).

Next, we can multiply both sides by a to get a^(p-1) * a(p-1) ≡ a (mod p^2).

Since a and p are coprime, we can use Euler's Totient Theorem, which states that a^φ(p) ≡ 1 (mod p) where φ(p) is the Euler totient function. Since p is prime, φ(p) = p-1, so a^(p-1) ≡ 1 (mod p).

Using this result, we can rewrite our identity as a^(p-1) * a(p-1) * a^-1 ≡ a^(p-1) ≡ 1 (mod p), which implies that a^(p-1) ≡ 1 (mod p^2).

Therefore, we have proven the identity a p(p−1) ≡ 1 (mod p 2 ), where a is coprime to p, and p is prime.

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Answer:

-10/f-6f

Step-by-step explanation:

simplify it the equation

The signof function is defined as follows:

def signof(num):
   if num > 0:
       return 1
   elif num == 0:
       return 0
   else:
       return -1

In the above code snippet, we have defined a function named signof which receives an integer argument named num. The if condition checks if the num is greater than 0, if yes, the function will return 1 as it is positive. Else if the num is equal to 0, then it will return 0, as per the requirement. Otherwise, it will return -1 as the number is negative. This code snippet will give the required output as per the requirement of the problem statement.

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A. For z = 0.50 = 66; B. For z = -0.25 = 57 and the probability of randomly selecting a score less than z = -0.25, you can use a standard normal (z-score) table or calculator. For z = -0.25, the probability is approximately 0.4013, meaning there's a 40.13% chance of randomly selecting a score less than z = -0.25.

To find the X value for each z-score, we use the formula:

X = u + (z * a)

where u is the mean, a is the standard deviation, and z is the z-score.

A. For z = 0.50:

X = 60 + (0.50 * 12)
X = 66

Therefore, the X value for z = 0.50 is 66.

B. For z = -0.25:

X = 60 + (-0.25 * 12)
X = 57

Therefore, the X value for z = -0.25 is 57.

To find the probability of randomly selecting a score that is less than z = -0.25, we use a z-table or a calculator that can calculate normal distribution probabilities. The probability of a score being less than z = -0.25 is the same as the area under the curve to the left of z = -0.25.

Using a z-table, we find that the probability of a score being less than z = -0.25 is 0.4013.

Therefore, the probability of randomly selecting a score that is less than z = -0.25 is 0.4013 or approximately 40.13%.

A. For z = 0.50:
To find the X value, use the formula X = μ + (z * σ), where μ is the mean and σ is the standard deviation.
X = 60 + (0.50 * 12) = 60 + 6 = 66

B. For z = -0.25:
X = 60 + (-0.25 * 12) = 60 - 3 = 57

To find the probability of randomly selecting a score less than z = -0.25, you can use a standard normal (z-score) table or calculator. For z = -0.25, the probability is approximately 0.4013, meaning there's a 40.13% chance of randomly selecting a score less than z = -0.25.

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Answer:

C. \(4\sqrt{7} -4x\sqrt{7}\) is correct

Steps:

\(4\sqrt{7} -3\sqrt{7}x-x\sqrt{7} \\\\4\sqrt{7} -3\sqrt{7} x-\sqrt{7} x\\\\4\sqrt{7} +(-3\sqrt{7} x-\sqrt{7} x)\\\\4\sqrt{7} -4\sqrt{7} x\)

Answer:

C. 4√7 - 4x√7

Step-by-step explanation:

4√7 - 3x√7 - x√7

combine like terms

4√7 - 4x√7

There are 9 possible schedules to play basketball such that dave can play on monday or wednesday or both which is union of two set .

so this question seems like we have to take union of ways of palying on monday or wednesday

let n(m) be number of ways of playing on monday

n(w) be number of ways of playing on wednesday

we have to find n(m∪w)

n(mUw) = n(m) +n (w) - n(m∩ w)

so n(m) = \(4_C__2\) as one day is now fixed which is monday so we have 4 available days and 2 days to play.

n(m) = \(4_C__2\)  = 6

similary n(m) = n(w) = 6

now  n(m∩w) = \(3_C__1\) as now we have  2 fixed day and we have 3 day remaining and only one day to play.

n(m∩w) = \(3_C__1\) =3

now n(mUw) = n(m) +n (w) - n(m∩ w)

=> 6 + 6 -3

=> 12 - 3

so n(mUw) = 9

so we have 9 schedules to paly keeping condition given in the question.

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No, multiplying by 10x10x10 is not the same as multiplying by 10 factors of 3.

Multiplying by 10x10x10 is not equivalent to multiplying by 10 factors of 3. When you multiply a number by 10, you're essentially adding a zero to the end of it, shifting all the digits one place to the left. So, multiplying by 10 three times (10x10x10) adds three zeros to the original number. However, when you multiply by 10 factors of 3, you are essentially multiplying the number by 3 ten times consecutively. This results in a different outcome.

For instance, if you start with the number 5 and multiply by 10x10x10, you would get 5,000. On the other hand, multiplying by 10 factors of 3 would yield a much larger number, 59,049, because each multiplication by 3 amplifies the result. Therefore, the two operations are not equivalent.

Therefore, multiplying by 10x10x10 and multiplying by 10 factors of 3 yield different outcomes. The former adds three zeros to the original number, while the latter multiplies the number by 3 repeatedly, resulting in a much larger value. It's crucial to understand the distinction between these operations to avoid confusion and accurately calculate mathematical expressions.

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a) To construct the table showing the values of the joint probability distribution of X and Y, we need to consider all possible combinations of X and Y based on the given information. Let's denote "S" for statistics, "M" for mathematics, and "P" for physics. The possible combinations are as follows:

X = 0, Y = 0: No statistics texts and no mathematics texts

X = 0, Y = 1: No statistics texts and one mathematics text

X = 0, Y = 2: No statistics texts and two mathematics texts

X = 1, Y = 0: One statistics text and no mathematics texts

X = 1, Y = 1: One statistics text and one mathematics text

X = 1, Y = 2: One statistics text and two mathematics texts

X = 2, Y = 0: Two statistics texts and no mathematics texts

X = 2, Y = 1: Two statistics texts and one mathematics text

X = 2, Y = 2: Two statistics texts and two mathematics texts

Now, let's calculate the probabilities for each combination:

P(X = 0, Y = 0) = (3/8) * (2/7) = 6/56

P(X = 0, Y = 1) = (3/8) * (2/7) = 6/56

P(X = 0, Y = 2) = (3/8) * (5/7) = 15/56

P(X = 1, Y = 0) = (3/8) * (3/7) = 9/56

P(X = 1, Y = 1) = (3/8) * (2/7) = 6/56

P(X = 1, Y = 2) = (3/8) * (5/7) = 15/56

P(X = 2, Y = 0) = (5/8) * (3/7) = 15/56

P(X = 2, Y = 1) = (5/8) * (2/7) = 10/56

P(X = 2, Y = 2) = (5/8) * (5/7) = 25/56

The table for the joint probability distribution of X and Y is as follows:

X = 0 6/56 6/56 15/56

X = 1 9/56 6/56 15/56

X = 2 15/56 10/56 25/56

b) To find the marginal distributions of X and Y, we sum the probabilities across the rows and columns, respectively.

The marginal distribution of X:

P(X = 0) = (6/56) + (6/56) + (15/56) = 27/56

P(X = 1) = (9/56) + (6/56) + (15/56) = 30/56

P(X = 2) = (15/56) + (10/56) + (25/56) = 50/56

The marginal distribution of Y:

P(Y = 0) = (6/56) + (9/56) + (15/56) = 30/56

P(Y = 1) = (6/56) + (6/56) + (10/56) = 22/56

P(Y = 2) = (15/56) + (15/56) + (25/56) = 55/56

The marginal distribution of X is (27/56, 30/56, 50/56), and the marginal distribution of Y is (30/56, 22/56, 55/56).

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Answer:

n = 108

Step-by-step explanation:

The three medians of a triangle intersect at the same point inside the triangle.

The segment from a vertex to the point in the center is 2 times as long as the

other part of the median line.  So OC is 2 times KC.

KC =108    

OC = 2(108)

2n + 10 = 216

2n = 206

n = 108

In ΔABC , Value of \(n= 31\) as per given condition of median of a triangle .

" Median of a triangle is defined as the line segment passing the vertex of a triangle and intersect at mid point of its opposite side.Intersecting point of three medians is known as Centroid."

Property used

Centroid divides the median in the ratio of \(2:1\) from vertex side.

According to the question,

Given,

In ΔABC,

BL, AM, CK are the medians of a triangle ABC.

'O' represents the Centroid

\(KC = 108\\\\OC = 2n +10\)

Ratio of \(KC : OC = 3: 2\)

Substitute the value of KC and OC we get,

\(108 : (2n + 10) = 3:2\\\\\implies 3 (2n+ 10) = 2(108)\\\\\implies 6n + 30 = 216\\\\\implies 6n = 186\\\\\implies n = 31\)

Hence, in ΔABC , Value of \(n= 31\) as per given condition of median of a triangle .

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