Use the given endpoint R and midpoint of M of line RS to find the coordinates of the other endpoint S. R (4,-6), M (-7,8)

The graph of f(x)=√x+3+2 is shifted 3 units up and 2 units to the right from the parent graph of f(x)=√x.

We have,

Graph is a type of data structure that consists of a set of nodes (also called vertices) and edges. Each node is connected to other nodes by edges. Graphs are used to represent networks of communication, data organization, computational devices, the flow of computation, etc. They are also very useful for visualizing relationships between data points in a variety of fields.

The translation of the parent graph of f(x)=√x+3+2 is a vertical shift upward 3 units, followed by a horizontal shift to the right 2 units. This is represented by the bold line in the graph. In terms of the equation, the translation is represented by the addition of the 3 and the 2 to the function. The 3 causes the graph to shift vertically upward and the 2 causes the graph to shift horizontally to the right. As a result, the graph of f(x)=√x+3+2 is shifted 3 units up and 2 units to the right from the parent graph of f(x)=√x.

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complete question:

Below, the graph of f(x) = √x +3 + 2 is sketched in bold. Its parent function f(x)=√x is represented

by the thin curve.

1) Describe the

translation of the parent

graph.

2) How does the translation relate to the equation?

Answer:

see explanation

Step-by-step explanation:

Under a rotation ( clockwise or anticlockwise ) about the origin of 180°

a point (x, y ) → (- y, - x ), thus

A(5, 3 ) → A'(- 3, - 5 )

B(8, 10 ) → B'(- 10, - 8 )

C(11, 3 ) → C'(- 3, - 11 )

Answer:

146

Step-by-step explanation:

180=4+30+x

180=34+x

180-34=x

146=x

The expression is equivalent to \(\rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\\).

Expression; \(\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\)

Which expressions are equivalent to the given expression.

Expression; \(\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\)

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

\(\rm a(b+c) = ab+ac\)

Then,

The equivalent expression is,

\(\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\ \\ \rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\ \\ 2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\\)

Hence, the expression is equivalent to \(\rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\\).

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B:C:E are the answers;]

Answer:

Solution given:

x²+x-20=0

x²+5x-4x-20=0

x(x+5)-4(x+5)=0

(x+5)(x-4)=0

either.

x=-5

or

x=4

Step-by-step explanation:

x² + x -20 =0

or, x²+(5-4)x -20

or,x ²+5x -4x -20=0

or,x(x +5)-4(x+5)=0

or,(x+5)(x-4)=o

either,

x+5=0. x-4=0

or,x=0-5. or,x= 0+4

or,x=-5. or, x=4

hope it is helpful to you ☺️

To solve the problem, we can use the equations for the axial deformation of a bar under axial load:

ε = δ/L

σ = Eε

where ε is the strain, δ is the displacement, L is the length of the bar, σ is the stress, and E is the modulus of elasticity.

(a) To find the displacements at points B and C, we can use the equation:

δ = PL/AE

where P is the axial load, L is the length of the bar, A is the cross-sectional area, and E is the modulus of elasticity.

For point B, the axial load is 5000 lb and the cross-sectional area is 1 sq in. The length of the bar is 10 in (15 in - 5 in). The modulus of elasticity is 30x10^6 psi. Therefore, the displacement at point B is:

δB = (5000 lb x 10 in) / (1 sq in x 30x10^6 psi) = 0.0167 in

For point C, the axial load is 2000 lb and the cross-sectional area is 0.25 sq in. The length of the bar is 12 in (15 in - 3 in). The modulus of elasticity is 30x10^6 psi. Therefore, the displacement at point C is:

δC = (2000 lb x 12 in) / (0.25 sq in x 30x10^6 psi) = 0.008 in

(b) To find the axial load in each shaft, we can use the equation:

P = σA

where P is the axial load, σ is the stress, and A is the cross-sectional area.

For shaft AB, the stress is:

σAB = δB/LAB x E = 0.0167 in / 10 in x 30x10^6 psi = 50 psi

The cross-sectional area is 1 sq in. Therefore, the axial load in shaft AB is:

PAB = σAB x AAB = 50 psi x 1 sq in = 50 lb

For shaft BC, the stress is:

σBC = (δC - δB)/LBC x E = (0.008 in - 0.0167 in) / 3 in x 30x10^6 psi = -25 psi

The cross-sectional area is 0.196 sq in (π(0.375 in)^2 / 4). Therefore, the axial load in shaft BC is:

PBC = σBC x ABC = -25 psi x 0.196 sq in = -4.9 lb

The negative sign indicates that the load is compressive.

For shaft CD, the stress is:

σCD = -δC/LCD x E = -0.008 in / 3 in x 30x10^6 psi = -80 psi

The cross-sectional area is 0.049 sq in (π(0.25 in)^2 / 4). Therefore, the axial load in shaft CD is:

PCD = σCD x ACD = -80 psi x 0.049 sq in = -3.92 lb

The negative sign indicates that the load is compressive.

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Answer: 12+20 = 12 + 20 = 4(3+5)

Step-by-step explanation:

The values of Prmin, Vprmin, L3/2/Dmax are 30.333 kW, 63.04 m/s, and 16.65 respectively.

Prmin (minimum power required) can be determined by the below formula:

Prmin = 1/2 × ρ × V^3 × S × (Cd/Cl)The given data are:

Weight (W) = 18,680

N = m × g

=> m = W/g

        = 18,680/9.81

        = 1904.44 kg

Wing area (S) = 14.4 m^2

Coefficients:

CD = 0.0358 + 0.0405 × CL^2

For minimum power required, CL/CD should be maximum.

So, CL/CD = L/D

=> L/D should be maximum for minimum power required.

We need to find Vprmin and L3/2/Dmax as well.

We know that: CD = CDmin + (CL/CDmin)^2πAR/ε,

where:

CDmin = 0.0358, AR = b^2/S (aspect ratio), ε = 0.8 (Oswald's efficiency factor)

So, CD = 0.0358 + (CL^2)/(π × 8 × 0.8)

=> CL^2 = (CD - 0.0358) × π × 8 × 0.8

=> CL^2 = 2.008 × CD - 0.05728

Now, substituting CL^2 in the formula of Prmin, we get:

Prmin = 1/2 × ρ × V^3 × S × (Cd/Cl)

Prmin = 1/2 × ρ × V^3 × S × (CD/CL)

Prmin = 1/2 × 1.225 × V^3 × 14.4 × ((2.008 × CD - 0.05728)/CD)V^2

         = (2W)/(ρSCL)

         = 2 × 18,680/(1.225 × 14.4 × 1.732 × √((2.008 × CD - 0.05728)/CD))V

prmin = √((2 × 18,680)/(1.225 × 14.4 × 1.732 × √((2.008 × CD - 0.05728)/CD)))

         = 63.04 m/s

L/D = CL/CD

=> L3/2/D = (CL^3)/(CDmin)^(1/2)πAR/εL3/2/Dmax

                = (CL^3)/(CDmin)^(1/2)πAR/ε

                = (CL^3)/(0.0358)^(1/2)π(8)(0.8)

Therefore, L3/2/Dmax = ((2.008 × CD - 0.05728)^(3/2))/(0.0358)^(1/2)π(8)(0.8)

                                     = 16.65

Now, we know the values of Vprmin and L3/2/Dmax.

We can calculate Prmin as:

Prmin = 1/2 × ρ × Vprmin^3 × S × (CD/CL)

Prmin = 1/2 × 1.225 × (63.04)^3 × 14.4 × ((2.008 × CD - 0.05728)/CD)

Prmin = 30333.43 W = 30.333 kW

Therefore, the values of Prmin, Vprmin, L3/2/Dmax are 30.333 kW, 63.04 m/s, and 16.65 respectively.

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The unit cost of pears is $1.50 per pound.

Ratio basically compares quantities, that means it show value of one quantity with respect to other quantity.

If a and b are two values, their ratio will be a:b,

Given that,

Cost for 1/3 lb of pears = $0.50

Since, 1 lb = 1 pound

Implies that,

Cost of 1/3 pounds of pears = $0.50

To find the cost of one pound of pears,

Use ratio property,

1/3 pound costs = 0.50

1 pound costs = 0.50 x 3 = $1.50

The cost of one pound of pear is $1,.50.

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An example of a trig function that includes multiple transformations and how it is different from the standard trig function is; As detailed below

An example of a trigonometric function that includes multiple transformations is; f(x) = 3tan(x - 4) + 3

This is different from the standard function, f(x) = tan x because it has a vertical stretch of 3 units and a horizontal translation to the right by 4 units, and a vertical translation upwards by 3.  

Another way to look at it is by;

Let us use the function f(x) = sin x.

Thus, the new function would be written as;

g(x) = sin (x - π/2), and this gives us;

g(x) = sin x cos π/2 - (cos x sin π/2)  = -cos x

This will make a graph by shifting the graph of sin x π/2 units to the right side.

Now, shifting the graph of sin xπ/2 units to the left gives;

h(x) = sin (x + π/2/2)

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Answer:

is 45

Step-by-step explanation:

the equation must be changed or else the number will be changed the 32

Answer:

a)x²

5²=25

b] (x+3)²

(5+3)²

(8)²=64

This refers to the ratio between the scale of a given original object and a new object. It is its representation but of a different size (bigger or smaller). For example, if we have a rectangle of sides 2 cm and 4 cm, we can enlarge it by multiplying each side by a number, say 2.

Solving for the area and scale factor we have:

L= 5 units

W = 2 units

A = (5 x 2)

A = 10 square units.

A= (Scale factor of  L * W)*  L * W

= (2 x 2 x 5 x 2)

A = 40 square units.

A= (Scale factor of  L * W)*  L * W

= (3 x 3 x 5 x 2)

A= 90 square units

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Answer:

-1 1/5

Step-by-step explanation:

-9+7 4/5

A. To save for her payout annuity with an ordinary annuity set up thirty years before her retirement, Holly Krech must make a monthly payment of $175.97.

B. If she sets up the ordinary annuity twenty years before her retirement, Holly Krech must make a monthly payment of $432.00.

To calculate the monthly payment for an ordinary annuity set up thirty years before retirement, we can use the formula for the present value of an ordinary annuity. Given the deposit amount of $218,437.048 and the total amount received from the annuity of $432,000, and solving for the monthly payment, we find that Holly must make a monthly payment of $175.97.

For an ordinary annuity set up twenty years before retirement, we use the same formula for present value. With the deposit amount and total amount received unchanged, we solve for the monthly payment, which comes out to be $432.00.

It's important to note that the monthly payment increases when the annuity is set up closer to the retirement date. This is due to the shorter time period available for saving, resulting in a higher required contribution to reach the desired payout amount.

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The number of ways to study for 3 hours for 3 nights is 7.

i.e

(0, 1, 2), (0, 2, 1), (1, 0, 2), (1, 2, 0), (1, 1, 1), (2, 0, 1), (2, 1, 0)

It is an arrangement of a set of numbers from a total set where the order of the set is not relevant.

We have,

Number of study hours = 3

Number of days = 3

Types of hours.

= 0, 1, and 2

The number of ways to study for 3 hours for 3 nights.

= (0, 1, 2), (0, 2, 1), (1, 0, 2), (1, 2, 0), (1, 1, 1), (2, 0, 1), (2, 1, 0)

Thus,

The number of ways to study for 3 hours for 3 nights is 7.

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Answer:

47 ÷ 3681 is approximately 0.0128

Answer:

The nswer is 0.0127682694919858

Also if I'm right can you let me know, please?

Also Also if I am right can I please have Brainliest??

You don't need to, I'm just glad I could help. ^^

You're a beautiful person, and worth so much, no matter your race or gender.

You deserve the world and more, and if I could give it to you, I would!

So please don't let anyone say otherwise, there are so many people in this world who love you, including me.

And if someone can't see your beauty then they're rather blind or you're just too bright for them!

Your amazing and I'm so proud of you for making it this far, so keep on with life, stay strong, and live long because I love you!

(Not in a weird way lol I love and care for everyone genuinely)

Answer:

22 blueberry pies and 19 apple pies.

Step-by-step explanation:

This can be solved using a system of equations. Your equation for amount of pies sold is x + y = 41, with x representing apple pies and y representing blueberry pies, and 41 being the total amount of pies sold. The other equation is for the amount of dollars earned from selling the pies, which is:

12x + 14y = 536     $12 per apple pie, $14 per blueberry pie, and a total of $536.

Let's first solve for x. The new equation would be x = 41 - y. Now, we plug this equation into the second equation.

12(41 - y) + 14y = 536    Here we substituted x for the equation we made.

429 - 12y +14y = 536

-12y +14y = 44   Here we moved the 429 to the other side by subtracting it from the left and right.

2y = 44

y = 22. Now we know that there was a total of 22 blueberry pies sold. Now we plug 22 pies back into the very first equation to find x, the amount of apple pies.

x + 22 = 41

x = 19. Now we know there was a total of 19 apple pies sold.

Hope this helps!

Answer:

1 group of 7

Step-by-step explanation:

Answer:

D. 3/20 or 15%

Step-by-step explanation:

You put the preferred events over the total events.

Total events=80

Desired events=12    (yellow)

12/80=0.15

multiply by 100 makes it a percent

15%

Get 12/80 and simplify it

12/80=6/40=3/20

3/20 Chance the Ricky would pull out a yellow Jelly bean

hope this helps!!

If you have more questions just ask me.

The option (B) (2, 5), (3, 6), (6, 9) is a function.

Function, is an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

"f(x) = ... " is the classic way of writing a function.

For the given situation,

The list of ordered pairs are given in option.

A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate.

According to the definition, the ordered pair should not have same x value.

Thus in option B (2, 5), (3, 6), (6, 9), each input is related to exactly one output.

Hence we can conclude that the list of ordered pairs of option (B) (2, 5), (3, 6), (6, 9) is a function.

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Answer:

its $375.70

Step-by-step explanation:

i guessed and got it right. good luck guys. love u. remeber to eat n drink water and try to spend some time outside if you can! i know its hard rn but we can do it! im proud of u all

The value of Erica's approximate monthly payment is $375.70. The correct option is C .

Rate of Interest is the rate at which a loan is borrowed or the rate at which an investment gives return .

It is given that

Student Loan Total =  $29,158

Rate of Interest = 9.4 %

Time Period = 10 years

The monthly payment is given by

\(\rm \dfrac{F p(i) }{ ( 1 - ( 1 + i )^{-n})}\)

Substituting the values in the equation

\(\rm = \dfrac{29158* (0.094/12) }{ ( 1 - ( 1 + (0.094/12) )^{-12*10})}\)

= $ 375.70

Therefore,The value of Erica's approximate monthly payment is $375.70. The correct option is C.

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Answer:

just move the decimal a 107 times and add 0's

Step-by-step explanation:

Answer:

No, I don't think so.

Step-by-step explanation:

If his suitcase weighs 23 kg and 10 kg is 22 pounds. You could seperate it. 10, 10, and 3 meaning 22+22= 44. This would mean that 1 kg would equal about 2.2 a pound. So 44 + ( 2.2 x 3 ) = 50.6 kg.

It would be 0.6 k.g over. I think this is right unless I calculated this wrong.

Andrew can not check his suitcase and it needs to remove some items or repack it in order to reduce the weight.

To measure and compare various things we use one term which is known as a unit.

For example, for  length measurement we use units like:- metre, centimetre, inch, miles.

To determine if Andre can check his suitcase, we need to convert the weight of his suitcase from kilograms to pounds since the weight limit for checked luggage is given in pounds.

Given that 10 kilograms ≈ 22 pounds, we can convert Andre's suitcase weight of 23 kilograms to pounds by multiplying it by the conversion factor:

23 kilograms x 22 pounds/kilogram ≈ 506 pounds

Therefore, Andre's suitcase weighs approximately 50.6 pounds, which exceeds the weight limit of 50 pounds.

Therefore, Andre cannot check his suitcase and needs to remove some items or repack it to reduce the weight below the weight limit.

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Answer:

7 1/2 divided by 3/4 is 10

Step-by-step explanation:

10

Brainiest please and thank you

Answer:

Step-by-step explanation:

Acceleration is defined as the rate of change of velocity.

Velocity is a vector, which means it contains a magnitude (a numerical value) and a direction.

So the velocity can be changed either by changing the speed or by changing the direction of motion (or both).

Answer:

velocity

Step-by-step explanation:

The definition of acceleration is: Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.

Answer:

26.55

Step-by-step explanation:

17.55 + 26.1 + 12 = 55.65

11.7 + 17.4= 29.1

55.65 - 29.1 = 26.55

Answer:

Step-by-step explanation:

Corresponding angles are equal.

∠J = ∠N

∠J = 23°

In similar triangles, corresponding parts are same ratio.

\(\dfrac{PM}{KL}=\dfrac{PN}{KJ}\\\\\\\dfrac{x}{12}=\dfrac{11.7}{17.55}\\\\\\x=\dfrac{11.7}{17.55}*12\)

x = 8 m

Answer: B : Mean Does Not change

Step-by-step explanation:

Answer: The answer is C

Step-by-step explanation:

I took the quiz and put B and got it wrong so don't trust his answer