Use the following scenario to answer the question. T'Keyah puts salt in ice water and then in boiling water to see which will dissolve faster. Which dissolving rate factor is she testing in these tests? (1 point) O solubility O agitation O particle size o tellmperature​

Answer:

Explanation:

a

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The graph of the velocity and the time  can be shown by option D.

We know that the movement of an object as it is falling under gravity would have a constant acceleration. The constant acceleration means that the velocity of the object is also held a constant.

We now have to look at the graphs as we have them here. The graph as it has been shown has the the velocity on the vertical axis and it has the time on the horizontal axis. The gradient of the slope is what we would refers to as the acceleration of the body.

We also need to recall that the acceleration has to be a constant since tje tow object would have to reach the ground at the same time if they are released from the same height at the same time.

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To determine the volume of a material of mass, m, you need its density.

The formula for density is \(p=mv\), rearranged to solve for volume, you get \(v=p/m\). As you have only provided the mass, you cannot determine the material's volume.

Answer:

both

the cleen soap is falling on a nasty floof cleans the floor and gets dirty

Explanation:

Answer:

UH UH

Explanation:

Answer: what ( younger brothers of hers )

Explanation:

K bye

Answer:

c

Explanation:

wavelength = speed of light/ frequency

= (3x 10^8 m/s)/(5.0 x 10^14 Hz)

= 6.0 x 10^-7 m

Answer:

Physics is applied every where? For example if you talking with you friends, that mean the sound that you produce oscillate through your friends' ear so he/ she can respond to you.

Explanation:

Physics is the fundamental unit about understanding the world around us.

There are several phenomena in our day-to-day life from the formation of the rainbow to the free falling of objects under the influence of gravity physics is applied almost everywhere.

Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.

Physics is a useful tool for seeing the real world, which is far larger than we can imagine. In every conceivable way, it describes the environment we live in. Almost all human activities, including walking, eating, and listening to music, require physics. Everywhere we look, there is physics.

In daily life, we encounter a number of events, such as the rainbow's emergence and items falling freely as a result of gravity. Nearly everywhere uses physics.

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a) Yes, the force of thrust of the engine does work as it is causing the plane to accelerate and lift off the ground.

b) Yes, the kinetic energy of the plane increases as it takes off and gains speed.

c) Yes, the gravitational potential energy of the plane increases as it gains height.

d) Yes, the force of thrust of the engine changes the mechanical energy of the plane.

The kinetic energy of an object is the form of energy that it possesses due to its motion which is also defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

The work done by the engine's thrust increases the plane's kinetic energy and gravitational potential energy, thereby changing its mechanical energy.

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Answer:

C

Explanation:

Usually when you are at the bottom you are at peak speed. It also shows that Kinetic Energy is the green bar and in picture C the green bar is highest.

The arrows are drawn in the figure which shows gravitational forces on each person on earth.

Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,

F∝ m₁.m₂

F ∝ 1/r²

F = G m₁,m₂÷r²

where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².

Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].

This is analogous with coulomb's law which gives force between two charges.

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Answer:

B.

Divide the height of the valley walls by the rate of erosion.

Explanation:

There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.

The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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Answer:

B ( magnetic field ) , I ( current ) and Length  are dependent variables in the design

Explanation:

To design the required experiment

Given that our aim is to determine the relationship between the force on conductor and length of the conductor

First step : place a current carry conductor in an external magnetic field where the length of the conductor will be denoted as L

The magnitude of Force on the conductor will be :

F = B*I*XL = B*I*Lsin∅

lets assume ∅ = 90°   then   F ∝ L  ( Force is directly proportional to the length of the conductor )

hence : Dependent variables here are : B ( magnetic field ) , I ( current ) and Length

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

The average number of hurricanes per globally stands at 15 hurricanes per year due to excess heat built up in Earth’s atmosphere.

Hurricanes are huge storms produced in the tropics due to large amounts of water vapor present in the atmosphere from the ocean coupled with strong winds with devastating effects on land.

The activities of man such as burning of fossil fuels have resulted in increased build of heat in the atmosphere and warming of the oceans. This is known as global warming.

Due to global warming, on average, the number of hurricanes per globally stands at 15 hurricanes per year.

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Answer:

The time period of the empty car will be "1.00 s".

Explanation:

The given values in the question will be:

Mass,

m = 250 kg

Loaded car's time period will be:

T = 1.08 s

Shock absorbers compression,

x = 4 cm

or,

  = 0.04 m

Now,

Weight of passengers will be:

⇒  \(F=mg\)

         \(=250\times 9.8\)

         \(=2450 \ N\)

The spring constant of shock absorbers will be:

⇒  \(k=\frac{F}{x}\)

        \(=\frac{2450}{0.04}\)

        \(=61.250 \ N/m\)

As we know,

Time period, \(T = 2 \pi\sqrt{\frac{M}{k} }\)

On substituting the values, we get

                   \(1.08=2\pi \sqrt{\frac{M}{61250} }\)

                  \(\frac{M}{61250}=0.02955\)

                      \(M=0.02955\times 61250\)

                           \(=1809.6 \ kg\) (Total mass of car as well as its passengers)

Now,

The mass of the empty car will be:

⇒  \(m'=M-m\)

          \(=1809.6-250\)

          \(=1559.6 \ kg\)

hence,

The time period of empty car will be:

⇒  \(T'=2\pi\sqrt{\frac{m'}{k} }\)

         \(=2\pi\sqrt{\frac{1559.6}{61250} }\)

         \(=2\pi \sqrt{0.0254}\)

         \(=1.003 \ s\)

or,

         \(=1.00 \ s\)

A 20.0 N block slides over a horizontal table. If it takes 5.0 N to move the block at a constant velocity, the coefficient of friction is D. 0.25.

Given,

Frictional force (F) is 5.0 N

Normal force (N) is 20.0 N

The coefficient of friction (µ), a numerical value, is obtained by dividing the resistive force of friction (F) by the normal or perpendicular force (N) pushing the objects together.

i.e., µ = F/N

Calculating the coefficient of friction :

The frictional force is equal to and opposing the applied force since the box is traveling at a constant speed.

µ = F / N

µ = 5.0 N / 20.0 N

µ = 1/4 N

µ = 0.25 N

Thus, the coefficient of friction is D. 0.25.

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Given

The range of frequencies audible to human is n=20 Hz to n'=20,000 Hz

Speed of sound is v=340 m/s.

To find

Sound with which of the following wavelengths would be audible by the average person?

Explanation

We know,

velocity is given by

Thus,

Again,

Thus the sound between wavelength 0.017 m to 17 m would be audible.

Conclusion

The sound audible to the human is 5 m

I feel like it is short term, also it isnt simple

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's law can be expressed as:

P1 * V1 = P2 * V2

Where:

P1 = Initial pressure (80.8 kPa)

V1 = Initial volume (817 cm³)

P2 = Final pressure (101.3 kPa)

V2 = Final volume (to be calculated)

Let's plug in the values into the equation and solve for V2:

80.8 kPa * 817 cm³ = 101.3 kPa * V2

V2 = (80.8 kPa * 817 cm³) / 101.3 kPa

V2 ≈ 651.25 cm³

Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

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Answer:

(a) \(A_1=0.283m^2\)

(b) \(Q=-105.5kW\): From the air to the surroundings.

Explanation:

Hello,

(a) In this case, we can compute the area at the entrance by firstly computing the inlet volumetric flow:

\(V_1=\frac{mRT_1}{P_1M}= \frac{2.3\frac{kg}{s} *8.314\frac{kPa*m^3}{kmol* K}*450K}{350kPa*28.97\frac{kg}{kmol} } =0.849\frac{m^3}{s}\)

Then, with the velocity, we compute the area:

\(A_1=\frac{V_1}{v_1}=\frac{0.849\frac{m^3}{s} }{3\frac{m}{s} } =0.283m^2\)

(b) In this case, via the following energy balance for the nozzle:

\(Q-W=H_2-H_1+\frac{1}{2} mV_2^2-\frac{1}{2} mV_1^2\)

We can easily compute the change in the enthalpy by using the given Cp and neglecting the work (no done work):

\(\Delta H=H_2-H_1=mCp\Delta T=2.3kg/s*1.011\frac{kJ}{kg*K}*(300K-450K)\\ \\\Delta H=-348.795kW\)

Finally, the heat turns out:

\(Q=-348.795kW+\frac{1}{2}*2.3\frac{kg}{s}*[(460\frac{m}{s})^2 -(3\frac{m}{s})^2 ]\\\\Q=-348.795kW+243329.65W*\frac{1kW}{1000W}\\ \\Q=-105.5kW\)

Such sign, means the heat is being transferred from the air to the surroundings.

Regards.

A pilot light is typically wired in series with a thermostat to indicate whether the fan is moving air

We know that the pilot is such a person that have been trained so as to be able to fly the air plane. This is the individual that can be able to control a plane and there are tools that the pilot would have to use to do his job.

Now we know that the pilot light is one of the tools that the pilot can use to be able to use in the discharge of his job when he is flying the air craft that is moving and it has to be in series with the thermostat.

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The magnitude of the net force causing the block’s acceleration is 8N.

We know that,

                         \(F_{x} = mg* cos\alpha\) (force along x - axis) and

                         \(F_{y} = mg* sin\alpha\) (force along y - axis)

The magnitude of net force is given by :

                         \(F_{net} = \sqrt{F_{x} ^{2} + F_{y} ^{2} }\)

                         \(F_{net} = \sqrt{(mg*cos\alpha )^{2} + (mg*sin\alpha )^{2} } \\F_{net} = \sqrt{(mg)^{2}[ (cos\alpha) ^{2}+(sin\alpha) ^{2} ] } \\F_{net} = mg\)

Given, weight = 8N and angle \(\alpha =\) 15°

We know that F (force) = ma = mg = weight

Putting these values in above equation we get ,

                          \(F_{net} = 8N\)

So the magnitude of the net force causing the block’s acceleration is 8N.  

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