-2x≤6 and 2x≥-6 is the inequalities represented by the number line
The visual representation of the real numbers on a straight lineis known as number line
On a number line each point of is assumed to correspond to a real number, and every real number to a point.
As we observe the graph the red line is directed towards left side which means the values are decreasing and line has solid point at 6 so it is included
Hence, the number line shows that -2x≤6 and 2x≥-6
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Where will X be after a rotation 90° clockwise about (-5,-1)?
Click on the grid to place the point.
The image point of the coordinate X after the rotation is (-1, 5).
Calculating the image point of the coordinate XWhen a point is rotated 90° clockwise around the origin, the new point will be formed by switching the x and y-coordinates and then negating the new x-coordinate.
So for point X (-5, -1), the new x-coordinate will be -1, and the new y-coordinate will be -(-5) = 5, giving the new point (-1, 5).
Therefore, after a rotation of 90° clockwise, point X (-5, -1) will be at the new location (-1, 5).
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Answer the questions below. I need answer for letter (c)
Answer:
C is the answer, please choose the letter C that's the answer
Please help me with my trig hw
Which function has the graph shown?
OAY COS
B. y -cos.x
● C. yin x
D. y sin (x)
f
The trigonometric function on the graph is:
f(x)= -cos(x)
So the correct option is B.
Which function is the graphed one?Here we can see the graph of a trigonometric function. We can see that the x-intercept is -1.
Notice that:
sin(0)= 0
cos(0) = 1
So the function can be an inversion over the x-axis of the cosine function, we coulod write this as:
f(x) = -cos(x)
That is the graphed function.
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The phrase absolute magnitude refers to the
A)
perceived color of a star.
3
)
exact distance from Earth.
C)
amount of light given off by a star.
D
amount of light received on Earth from any stan
ding
In which polygon is the sum of the number of sides and the number of diagonals equal to 105?
Answer:
Decagon
Step-by-step explanation:
Answer: 15-agon
Step-by-step explanation:
Sum of number of sides , n
formula for number of diagonals =
\(\frac{n(n-3)}{2}\)
If you added the 2 and made = 105
n + \(\frac{n(n-3)}{2}\) = 105
multiply everything by 2 to get rid of fraction
2n + n(n-3) =210
2n + n² - 3n = 210
n²-n -210 =0 factor
(n-15)(n+14)=0 set each =0 and solve can't get - so -14 is invalid
n=15
the rate of electricity charge of 20 units is RS 3 per units and rs 6.50 per units from 21 to 30 unit. find the charge of consumption of 28 units with rs 50 service charge
electricity consumed:28 units
charge upto 20 units : 20 * Rs 3 : Rs 60
charge from (21 to 28) : 8 * Rs 6.50 : 52
total charge including service charge : Rs 60 + Rs 52 + Rs 50 : Rs 162
A neighborhood is trying to set up school carpools, but they need to determine the number of students who need to travel to the elementary school (ages 5-10), the middle school (ages 11-13), and the high school (ages 14-18). A histogram summarizes their findings:
Histogram titled Carpool, with Number of Children on the y axis and Age Groups on the x axis. Bar 1 is 5 to 10 years old and has a value of 3. Bar 2 is 11 to 13 years old and has a value of 7. Bar 3 is 14 to 18 years old and has a value of 4.
Which of the following data sets is represented in the histogram?
{3, 3, 3, 7, 7, 7, 7, 7, 7, 7, 4, 4, 4, 4}
{5, 10, 4, 11, 12, 13, 12, 13, 12, 11, 14, 14, 19, 18}
{5, 6, 5, 11, 12, 13, 12, 13, 14, 15, 11, 18, 17, 13}
{3, 5, 10, 11, 13, 7, 18, 14, 4}
The correct answer is that the data set {3, 7, 4} is represented in the given histogram.(option-a)
The given histogram represents the number of children in each age group who need to travel to school. Since the histogram has only three bars, we can conclude that there are only three age groups.
The first bar represents children aged 5-10, of which there are 3. The second bar represents children aged 11-13, of which there are 7. The third bar represents children aged 14-18, of which there are 4.
Therefore, the data set that is represented in the histogram is:
{3, 7, 4}
None of the other data sets given match the values in the histogram. The first data set has duplicate values and is not sorted by age group. The second data set includes ages that are not represented in the histogram. The third data set has values for ages 6, 11, 12, 13, 14, 15, 17, and 18, but the histogram does not have bars for all those ages. (option-a)
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If 2 cards are selected from a standard deck of 52 cards.The first card is placed back in the deck before the 2nd card is drawn.What is the probability that a heart and a club will be drawn ?
There are 13 cards of each suit.
Picking a heart would be 13/52 which reduces to 1/4
Then replacing the card and picking a club would be the same : 1/4
Picking a heart then a club would be 1/4 x 1/4 = 1/16
Answer: 1/16
Can someone please help me find the area
Answer:
115
Step-by-step explanation:
(46 + 94/ 2) 45 = 115
Where does the graph of f(x) = (x + 9)(x - 4) cross the x-axis?
hi
f(x) = (x+9) (x-4)
if it's cross the x axis it's means f(x) = 0
(x+9) (x-4) = 0 means x+9 = 0 so x = -9 and x-4 = 0 so x = 4
answers f(x) = 0 for x = -9 and x = 4
PLEASE ANSWER - PLEASE ANSWER
The diagram shows triangle ABC. ABC and BED are straight lines. AB = 12.2cm, CD = 5.8cm, BE:ED = 3:1, Angle ADB = 90°, Angle ABD = 38°.
Work out the size of angle DCE, correct to 1 decimal place. SHOW ALL WORKING IN TEXT FORM, NO IMAGES.
The measure of angle DCE in this problem is given as follows:
m < DCE = 22.5º.
How to obtain the measure of angle DCE?The triangles in this problem are right triangles, meaning that the trigonometric ratios are used to find the measures.
The three trigonometric ratios are given as follows:
Sine of angle = length of opposite side divided by the length of the hypotenuse.Cosine of angle = length of adjacent side divided by the length of the hypotenuse.Tangent of angle = length of opposite side divided by the length of the opposite side.The segment DB is adjacent to angle of 38º, while the hypotenuse is of 12.2 cm, hence the length of segment DB is calculated as follows:
cos(38º) = DB/12.2
DB = 12.2 x cosine of 38 degrees
DB = 9.6 cm.
BE:ED = 3:1, means that segment DE is one-fourth of segment DB, and thus it's length is given as follows:
DE = 1/4 x 9.6
DE = 2.4 cm.
Then for the angle DCE, we have that the opposite side is of 2.4 cm while the adjacent side is of 5.8 cm, hence the tangent is used to find it's measure, as follows:
tan(x) = 2.4/5.8
x = arctan(2.4/5.8)
x = 22.5º
m < DCE = 22.5º.
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Answer:
x = 22.5°
Step-by-step explanation:
BD = cos(38)*12.2 = 9.61DE = 9.61*¼ = 2.4∠DCE = tan(2.4/5.8) = 22.5°Choose the best graph that represents the linear equation:
-x = 2y + 1
The line slants downward from left to right, indicating that as x increases, y decreases.
The given linear equation is -x = 2y + 1. To represent this equation graphically, we need to rearrange it into the slope-intercept form, which is y = mx + b, where m represents the slope and b represents the y-intercept.Rearranging the given equation, we get:2y = -x - 1
Dividing both sides by 2:y = (-1/2)x - 1/2
The slope of the line is -1/2, which means that for every unit increase in x, y decreases by 1/2 unit. The y-intercept is -1/2, indicating that the line intersects the y-axis at (0, -1/2).
Based on this information, the best graph that represents the linear equation y = (-1/2)x - 1/2 is a straight line with a negative slope of -1/2, starting at the point (0, -1/2) and extending infinitely in both directions.
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The probability of choosing a red three-card from a standard deck of cards is approximately 3.8%. What is the probability of the complement of this event?
Answer:
96.2 thats the answer I think
8. A fee-based loan is one type of loan that you may encounter. Many payday/title businesses and pawn shops charge you a set fee for borrowing money from them. This fee can make it difficult to know what interest rate you are really paying.
Lucille takes her car to a title loan business to borrow some money. She is given $1500. She must pay $300 in addition to the $1500 from the loan in 6 months. What simple interest rate is she being charged?
Lucille is being charged a simple interest rate of 0.4, or 40%.
To determine the simple interest rate Lucille is being charged, we can use the formula for simple interest:
Interest = Principal × Rate × Time
In this case, the principal (P) is $1500, the time (T) is 6 months (or 0.5 years), and the total amount to be paid back (A) is $1500 + $300 = $1800. We need to find the rate (R).
Interest = Principal × Rate × Time
$300 = $1500 × R × 0.5
Simplifying the equation:
$300 = $750R
To isolate R, we divide both sides of the equation by $750:
$300 / $750 = R
0.4 = R
Therefore, Lucille is being charged a simple interest rate of 0.4, or 40%.
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find the value of x
6x 3x+ 2
Answer:
I believe the answer is 9
Step-by-step explanation:
What is the missing value A=3 b=5 c=?
Answer:
4
Step-by-step explanation:
Not sure about this question
The absolute minimum of the function is f ( -10 ) = -1
Given data ,
Let the function be represented as f ( x )
Now , the function f ( x ) is plotted on the graph
where the minimum of a function is the smallest value that the function takes on over its entire domain.
It is the point on the graph of the function that is the lowest possible point
So , the function has the minimum value of - 1 at the point x = -10
Hence , the minimum of function is f ( -10 ) = -1
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Give me more questions
Answer:
At a recent baseball game of 5,000 in attendance, 150 people were asked what they prefer on a hot dog. The results are shown.
Ketchup Mustard Chili
63 27 60
Based on the data in this sample, how many of the people in attendance would prefer chili on a hot dog?
900
2,000
2,100
4,000
Step-by-step explanation:
solve the equation using complete square method x²-x-2=0
The values of x in x²-x-2=0 are x = 2 or -1
How to solve the equation?The equation is given as:
x²-x-2=0
Add 2 to both sides
x² - x = 2
Take the coefficient of x
k = -1
Divide by 2
k/2 = -1/2
Square both sides
(k/2)² = 1/4
Add 1/4 to both sides of x² - x = 2
x² - x + 1/4= 2 + 1/4
Evaluate
x² - x + 1/4= 9/4
Express as perfect square
(x - 1/2)² = 9/4
Take the square roots
x - 1/2 = ±3/2
This gives
x = 1/2 ±3/2
Evaluate
x = 2 or -1
Hence, the values of x in x²-x-2=0 are x = 2 or -1
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Resuelve las siguientes ecuaciones
a. 3x + 30 = 80 + 2x
Answer:
3x + 30 = 80 + 2x
3x – 2x = 80 –30
x= 50
I hope I helped you^_^
Answer:
x=50
Step-by-step explanation:
3x + 30 = 80 + 2x
subtract 2x from both sides
1x + 30 = 80
subtract 30 from both sides
x=50
Approximate the area of the circle segment bounded by DE and arc DE if r =20 and theta=47°. Photo Attached
Answer: 1256.63706
Step-by-step explanation: A=(π20)2
The approximate area of the circle segment bounded by arc DE and chord DE is approximately 17.72 square units.
To approximate the area of the circle segment bounded by arc DE and chord DE, you can use the following formula:
Area = (1/2) * r^2 * (θ - sinθ)
Where:
r is the radius of the circle (r = 20 in your case).
θ is the central angle in radians (47° converted to radians is approximately 0.8203 radians).
Let's calculate it:
θ = 47° * (π / 180) ≈ 0.8203 radians
Now, plug these values into the formula:
Area = (1/2) * (20^2) * (0.8203 - sin(0.8203))
Area ≈ (1/2) * 400 * (0.8203 - 0.7317)
Area ≈ (1/2) * 400 * 0.0886
Area ≈ 17.72 square units
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Perform the indicated operation:
(4 + 2i) (1 + 5i)
-6 +22i
6-221
-14 + 18i
6+22i
Answer:
-235+84i
Step-by-step explanation:
I hope this is what you were looking for.
jackson is conducting an experiment for his physics class. he attaches a weight to the bottom of a metal spring. he then pulls the weight down so that it is a distance of six inches from its equilibrium position. jackson then releases the weight and finds that it takes four seconds for the spring to complete one oscillation. Which function best models the position of the weight?a. s(t) = 6cos(2πt)b. s(t) = 6sin(π/2 t)c. s(t) = 6sin(2πt)d. s(t) = 6cos (π/2 t)
6 cos(π/2 t) is the best model for the position of the weight.
The motion of the weight on the spring can be modeled by a sine or cosine function because it oscillates back and forth around its equilibrium position.
We know that, the weight is initially pulled down 6 inches from its equilibrium position, so the function should have an amplitude of 6.
The time it takes for the spring to complete one oscillation is 4 seconds, so the period of the function is 4 seconds.
The general form of a sine or cosine function with amplitude A and period T is:
f(t) = A sin(2πt/T) or f(t)
= A cos(2πt/T)
Substituting the given values,
we get:
f(t) = 6 sin(2πt/4) or f(t)
= 6 cos(2πt/4)
Simplifying, we get:
f(t) = 6 sin(π/2 t) or f(t)
= 6 cos(π/2 t)
Therefore,
the function that best models the position of the weight is
s(t) = 6 cos(π/2 t).
So, the answer is option (D).
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9/12 = 3/D O D = 6 O D = 4 O D = 5 O D - 10
Answer:
The answer would be D = 4 or option 2.
Step-by-step explanation:
9/12 = 3/?
First, you want to simplify 9/12
9/12 = 3/4
This shows you that D = 4
please help me solve
Answer:
130 degrees
Step-by-step explanation:
DE+DA=130
The executive summary component of a business plan is to describe
a where the funds to start and operate your business will come from, when you expect to see
profit, and how much profit you expect to see
b. the size of the market, how your business will fit into the market, and how your business will
stand out from other businesses in the market
c. the 'big picture behind your business, what your business has to offer the consumer, and why
your business will be successful
d. how your business will be organized and what type of management or department structure
your business will have
Please select the best answer from the choices provided
ΟΑ
О В
ОС
Answer:
Executive summary describes the 'big picture behind your business, what your business has to offer the consumer, and why
Step-by-step explanation:
B is right
Solve for s.
3 = s - 2
s=
Answer:
3 = s - 2
s = 3 - 2
s = 1
what was hard lol
The atmospheric pressure at sea level is about 101 kilopascals. For every 1000-m increase in altitude, the pressure decreases about 11.5%. What is the pressure at an altitude of 5000 m?
The pressure at an altitude of 5000 m if The atmospheric pressure at sea level is about 101 kilopascals. For every 1000-m increase in altitude, the pressure decreases by about 11.5% is 58.08 kPa.
What is percentage?A percentage, often known as percent, is a division by 100. Percentage, which means "per 100," designates a portion of a total sum. 45 out of 100 is represented by 45%, for instance. Finding the percentage of a whole in terms of 100 is what percentage calculation is. Both manual calculation and the use of internet calculators are options.
Given:
The atmospheric pressure, P = 101 kPa,
For every 1000 meters, the pressure decreases by 11.5%,
So at the height of 5000 meter, the % decrease will be 5 × 11.5 = 57.5%,
Now let the 57.5% of 101 kPa be x then,
x = 57.5/100 × 101 kPa,
x = 58.08 kPa,
Therefore, the pressure at an altitude of 5000 m if The atmospheric pressure at sea level is about 101 kilopascals. For every 1000-m increase in altitude, the pressure decreases by about 11.5% is 58.08 kPa.
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