Use Newton's method with initial approximation
x1 = −2
to find x2, the second approximation to the root of the equation
x3 + x + 6 = 0.
Use Newton's method with initial approximation
x1 = −2
to find x2, the second approximation to the root of the equation
x3 + x + 6 = 0.

For conducting experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.

As given in the question,

To conduct a experiment based on the effect of net force applied to an object the dependable quantities are as follow:

Force = mass × acceleration

As object remain same ⇒ mass is constant as object remain same.

And there is change in the acceleration.

Acceleration depends change in velocity over total time taken.

Acceleration depends on velocity and time.

Net force also depends on velocity and time.

Two measurements need to know  while conducting trail experiments are velocity and time.

Therefore, to conduct experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.

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Answer:

This would equal 13.

2x2=4, 6/2=3, 3x3=9, 9+4=13

Answer: 21

Step-by-step explanation:

y=x2

-14x+43

y= -x+7

21

Answer:

constant term= 8

exponent of the third term= 1

Step-by-step explanation:

the constant is the term that does not have a variable/letter attached to it...that would be positive 8

the third term is 3y, but there is an "understood" exponent of 1 there...it's just useless to say \(3y^{1}\)

Step-by-step explanation:

please find the answer attached

Answer:The mimimun is -86 at 3,7

Step-by-step explanation:

Answer:

384 in^2

Step-by-step explanation:

Surface Area (or SA for short) formula:

SA=2lw+2lh+2hw

(l=length, w= width, h= height)

9*12=108*2=216

9*4=36*2=72

12*4=48*2=96

216+72+96=384

Answer:384 in^2

Hope this helps!

True. Since the square matrix that represents the DCT coefficient is an orthogonal matrix, its inverse and transpose are the same. This property is a fundamental characteristic of orthogonal matrices and holds true for all orthogonal matrices.

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False While it is true that the square matrix that represents the DCT coefficient is orthogonal, it does not mean that its inverse and transpose are the same.

the inverse of an orthogonal matrix is its transpose. However, the transpose of the matrix does not necessarily mean that it is the same as the inverse of the matrix. In the statement is false because the inverse and transpose of an orthogonal matrix are not always the same.


The Discrete Cosine Transform (DCT) coefficient matrix is an orthogonal matrix. In the case of orthogonal matrices, the inverse matrix is indeed equal to the transpose of the original matrix. This is because the product of an orthogonal matrix and its transpose results in the identity matrix.

Since the square matrix representing the DCT coefficient is an orthogonal matrix, its inverse and transpose are the same.

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Fred owes $14,250 in credit card debt.

We must total up all of Fred's assets and liabilities, then subtract them to arrive at the amount he owes on his credit cards.

Let's figure it out:

Total Assets:

House (current value) = $105,900

Checking Account = $375

Vehicle (current value) = $13,500

Savings Account Value = $1,275

Total Liabilities:

Credit Card Debt = ?

Student Loans = $32,000

Personal Loans = $800

Total Assets - Total Liabilities = Net Worth

105,900 + 375 + 13,500 + 1,275 - (Credit Card Debt + 32,000 + 800) = 74,000

Solving for Credit card debt =

Credit Card Debt = 74,000 - 88,250

Credit Card Debt = -14,250 [The negative sign identifies it as a liability, as you can see.]

Therefore, Fred owes $14,250 in credit card debt.

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Answer

3x^2-2x+6=0\quad :\quad x=\frac{1}{3}+i\frac{\sqrt{17}}{3},\:x=\frac{1}{3}-i\frac{\sqrt{17}}{3}

Step-by-step explanation:

Answer:

Each student club must contribute $ 33.33 in order to meet the fundraising goal.

Step-by-step explanation:

Given that a school fundraiser has a minimum target of $ 500. Faculty have donated $ 100 and there are 12 student clubs that are participating with different activities, to determine how much money should each club raise to meet the fundraising goal, the following calculation must be performed:

(500 - 100) / 12 = X

400/12 = X

33,333 = X

Thus, each student club must contribute $ 33.33 in order to meet the fundraising goal.

The y-intercept of the equation of line  y = (7/9)x + 2/3 is 2/3.

The slope-intercept form is expressed as;

y = mx + b

Where m is slope and b is y-intercept.

Given the equation of line in the question;

y = 7/9 x + 2/3

Simplify the right hand side

y = (7/9)x + 2/3

Using the slope-intercept form, the y-intercept is 2/3.

Therefore, the y-intercept in point form is (0,2/3).

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Answer:

No

Step-by-step explanation:

No, because there is no mutiplication sign, and it suppose to be 6x times 5.

The reward-to-variability ratio of the best feasible is 0.4221 that is option a.

The proportion of stocks invested in the optimal risky portfolio can be calculated with the use of following formula:

Portfolio Invested in the Stock = [(Expected Return of the Stock - Risk Free Rate)*(Standard Deviation of Bond)^2 - (Expected Return of the Bond - Risk Free Rate)*Covariance between Bond and Stock]/[(Expected Return of the Stock - Risk Free Rate)*(Standard Deviation of Bond)^2 + (Expected Return of the Bond - Risk Free Rate)*(Standard Deviation of Stock)^2 - (Expected Return of Stock - Risk Free Rate + Expected Return of Bond - Risk Free Rate)]*Covariance between Bond and Stock

Portfolio Invested in Bond = 1 - Portfolio Invested in the Stock

Here, Risk Free Rate = 4 and Covariance = 32*24*.1250 = 96

Using these values and other information provided in the question, we get,

Portfolio Invested in the Stock = [(10 - 4)*(24)^2 - (7 - 4)*96]/(10 - 4)*(24)^2 + (7 - 4)*(32)^2 - [(10 - 4 + 7 - 4)]*96 = .5593

Portfolio Invested in Bond = 1-.5593 = .4407

Step 2: Calculate Expected Return and Standard Deviation of the Optimal Risky Portfolio

Expected Return = Portfolio Invested in Stock*Expected Return of Stock Portfolio Invested in Bond*Expected Return of Bond = .5593*10% + .4407*7% = 8.68%

Standard Deviation = [(Portfolio Invested in Stock)^2*(Standard Deviation of Stock)^2 + (Portfolio Invested in Bond)^2*(Standard Deviation of Bond)^2 + 2*(Portfolio Invested in Stock)*(Portfolio Invested in Bond)]^(1/2) = [(.5593)^2*(32)^2 + (.4407)^2*(24)^2 + 2*(.5593)*(.4407)*(96)]^(1/2) = 21.90%

Step 3: Calculate Reward-to-Volatility Ratio

The reward-to-volatility ratio can be calculated with the use of following formula:

Reward-to-Volatility Ratio = (Expected Return of the Portfolio - Risk Free Rate)/Standard Deviation of Portfolio = (8.68 - 4)/21.90 = .4221

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Answer:

2 hours and 2 minutes

Step-by-step explanation:

think about it this way 430 + 202 is 632 Wich is 4:30+ 2 hours and 2 minutes is 6:30

Answer: so but 10 calculators

Step-by-step explanation:

The sum in terms of p of four consecutive even integers with p been the smallest is 4(p + 3)

Even numbers are numbers that can be divided into two equal groups and they can be easily divisible by 2 without any remainder.

p is the smallest of the four consecutive even integers. This means p come first and it is the first term of the numbers.

Therefore, the 4 consecutive even integers is represented as follows;

p, p + 2, p + 4, p + 6

So the sum is equal to:

sum = p + p + 2 + p + 4 + p + 6

sum = 4p + 12

sum = 4(p + 3)

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When comparing a sample mean to a population mean with an unknown population standard deviation, the researcher should use a t-test.

The t-test is a statistical test used to determine if there is a significant difference between the means of two groups or to compare a sample mean to a known or hypothesized population mean. It is commonly used when the population standard deviation is unknown and the sample size is small.

In this scenario, since the population standard deviation is unknown, the researcher cannot use a z-test, which requires knowledge of the population standard deviation. Instead, the t-test is appropriate because it estimates the population standard deviation based on the sample data.

The t-test calculates a test statistic called t-value, which is based on the difference between the sample mean and the hypothesized population mean, taking into account the sample size and the sample standard deviation. The t-value is then compared to the critical values from the t-distribution to determine the statistical significance of the difference.

Therefore, to compare a sample mean to a population mean when the population standard deviation is unknown, the researcher should use a t-test.

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Answer:78,800

Step-by-step explanation:

Answer:

Overall, available research suggests jurors exposed to pretrial publicity are more likely to favor the prosecution.

Mean is used to measure the center of a set of values. It is good for summarizing values which are generally pretty similar to each other.

Mean is more usually referred to as the average. It is calculated by adding up all of the values and dividing by the total number of values. It is a good way for summarizing the center of values which are commonly very similar to each other.

The mean is the most often used measure of central tendency since it uses all values in the data set to give us an average. For data from skewed distributions, the median is better than the mean because it is not influenced by large values.

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Although part of your question is missing, you might be referring to this full question: _________ is used to measure the center of a set of values. It is good for summarizing values that are generally pretty similar to each other.

Answer:

y=3x-7

Step-by-step explanation:

To find the equation of a perpendicular line, you first need to find the negative reciprocal of the slope given. The slope is -1/3, so the slope of the perpendicular line will be 3

Now we just need to find the y intercept using the point (3, 2) and you can plug the coordinates in and then solve for b. Let's see what that looks like.

y=3x+b

2=3*(3)+b

2=9+b

-7=b So now we know the y-intercept and slope. We just put them together now

y=3x-7

Hope this helps!

The given triangles are obtuse = 36 m, right angled = 225 m and right angled = 2500 m.

Triangle can be defined in which it consists of three sides, three angles and sum of three angles is always 180 degrees.

7.) This triangle is obtuse.

To see this, we can use the Pythagorean theorem:

4*4 + 5*5 = 16 + 25 = 41

6*6 = 36 m

Since 41 > 36, we know that the triangle is obtuse.

8.) This triangle is right.

To see this, we can again use the Pythagorean theorem:

11*11 + 12*12 = 121 + 144 = 265

15*15 = 225 m

Since 265 = 225 + 40, we know that the triangle is right.

9.) This triangle is also right.

We can use the same method as before:

30*30 + 40*40 = 900 + 1600 = 2500

50*50 = 2500 m

Since 2500 = 2500, we know that the triangle is right.

Therefore, The given triangles are obtuse , right angled and right angled.

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The number of the students should be sampled to be within 0.25  alcoholic drinks of population mean with 95% probability is 62.

α is the result of subtracting one from confidence interval as well as dividing by two.

α =  (1 - 0.95) ÷ 2 = 0.25

Find z in the Z-table because z does have a p-value of 1 - α.

As a result, the p-value of z is  (1 - 0.025) = 0.975.

Thus, z  = 1.96

Now find M as;

M = z × (σ ÷ √n)

In which,

When M = 1,

The standard deviation, in accordance with the question, is approximately 1.

σ = 1

M = z × (σ ÷ √n)

0. 25 = 1.96 × (1 ÷ √n)

√n = 1.96 × (1 ÷ √n)

Squaring both sides,

(√n)² = ((1.96 × 1) ÷ 0.25)²

n = (7.84)²

n = 61.4656

n ≈ 62

Thus, the number of the students should be sampled to be within 0. 25 alcoholic drink of population mean with 95% probability is 62.

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Answer:

i think it is 3 sorry if i am wrong

a) The vector field F(x, y) = <3x³y², 2x³y - 4> is not conservative because its components do not satisfy the condition of having continuous partial derivatives.

For a vector field to be conservative, its components must have continuous partial derivatives and satisfy the property of the mixed partial derivatives being equal. In this case, the partial derivatives of F with respect to x and y are 9x²y² and 6x³y, respectively. The mixed partial derivatives ∂F₁/∂y and ∂F₂/∂x are 6x²y and 18x²y, respectively. As these mixed partial derivatives are not equal, the vector field F is not conservative.

b) To show path independence, we need to evaluate the line integral F.dr over two different paths and demonstrate that the results are equal. Evaluating F.dr over any curve from (1, 2) to (-1, 1) gives a result of -45.

Let's consider two different paths: Path 1 consists of a straight line from (1, 2) to (-1, 2), followed by another straight line from (-1, 2) to (-1, 1). Path 2 is a direct straight line from (1, 2) to (-1, 1). Evaluating the line integral F.dr along these paths, we find that the result is -45 for both paths. Since the line integral yields the same result regardless of the path, we conclude that the line integral F.dr is path independent.

Therefore, the line integral of F.dr over any curve from (1, 2) to (-1, 1) is -45.

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