uppose is the portion of the parabolic sheet y = x² bounded by -2 5x53 and 0 Szs 5 with orientation in the negative y direction. If F (x, y, z) = xî + xyſ + yzł describes the flow of a fluid, find the rate of flow of 7 through I in the direction of orientation. Assign the result to q7.
Answers
The rate of flow of 7 through I in the direction of orientation is -587/3. This was obtained by parameterizing I, computing its tangent vector, and plugging them into the line integral formula for F.
To calculate the rate of flow of 7 through I, we need to find the line integral of F along the curve I. First, we need to parameterize I. Since I is the portion of the parabolic sheet y = x² bounded by -2 ≤ x ≤ 5 and 0 ≤ z ≤ 5, we can use x as the parameter and write I as the curve (x, x², 0) for -2 ≤ x ≤ 5. Then, we can compute the tangent vector of I as T(x) = (1, 2x, 0).
Next, we need to plug in the parameterization and the tangent vector into the line integral formula, which is ∫ F(T(x)) · T(x) dx, where the dot represents the dot product. After simplifying and integrating, we get q7 = -587/3.
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Related Questions
1. It's very kind _______ you to help us. Thanks a lot. A. for B. to C. with D. of
Answers
Hope this helps☺️
The extraction of oil from groundnut paste with hexane is shown as a single stage operation as follows:
Suppose that the feed composition is 36% oil and 64% inert solids and that pure hexane is to be used in the extraction. In one trial, 3 kg of hexane was used per kg of feed. The composition of the extract was 32% oil and no inert solid. It is also known that each kg of inert solids retains 1.8 kg of solution. Represent the following compositions on a right-angled diagram:
(a) The feed
(b) The extract
(c) Underflow (raffinate)
(d) The initial mixture of feed and the solvent
Answers
The diagram for the extraction to represent the information given is attached.
What is extraction?Extraction refers to the process of obtaining or removing something from a particular source or location. It can refer to various fields such as chemistry, physics, medicine, and data analysis.
In chemistry, extraction is the process of separating a particular component or substance from a mixture using various methods such as solvent extraction, distillation, or chromatography. In physics, extraction can refer to the removal of energy or particles from a system. In medicine, extraction refers to the removal of a tooth or a foreign object from the body. In data analysis, extraction refers to the process of retrieving specific data or information from a large set of data.
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What is land administration and cadastral survey
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Cadastral surveying is the sub-field of cadastre and surveying that specialises in the establishment and re-establishment of real property boundaries. ... A cadastral surveyor must apply both the spatial-measurement principles of general surveying and legal principles such as respect of neighboring titles.
When a tensile specimen is stretched in the plastic region to an engineering strain of 0.2, calculate the amount of cold work percent.
Answers
Answer:
0.2 x 100
Explanation:
Engineering strain is the original crossection/original crossection
cold work percentage is
original crossection/original crossection x 100
describe a process that would satisfy the conservation of energy principle but does not actually occur in nature
Answers
The only process I can think of that would satisfy the conservation of energy principle but does not occur in nature is a perpetual motion machine.
Working principle of perpetual motion machinePerpetual Motion Machine would produce work indefinitely without any external input of energy, thus violating the first law of thermodynamics which states that energy cannot be created or destroyed, only converted from one form to another.
While it is theoretically possible to design a machine that appears to produce more energy than it consumes, such a machine cannot exist in reality due to the various energy losses that occur in any real-world system.
These losses can occur due to factors such as friction, heat transfer, and resistance in electrical circuits, among others.
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Electronic dimmers of the type sold for residential use _______ intended for speed control of small motors.
Answers
Depending how old this question is, a plain
rheostat was used to create a voltage divider, reducing voltage to a universal motor.
Maybe they are just looking for solid state switch ??
A light dimmer is usually not interchangeable for motor control.
A Contractor Has A Job Which Should Be Completed In 100 Days. At Present, He Has 80 Men On The Job And It Is Estimated That They Will Finish The Work In 130 Days. Of The 80 Men, 50 Are Each Paid ₱120.00 A Day, 25 At ₱180.00 A Day, And 5 At ₱250.00 A Day. For Each Day Beyond The Original 100 Days, A Contractor Has To Pay ₱500.00 Liquidated Damages.A) How Many
A contractor has a job which should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00 liquidated damages.
a) How many more men should the contactor add so that he would complete the work on time?
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine?
Answers
A contractor has a job that should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00.
liquidated damages.(a) How many more men should the contractor add so that he would complete the work on time?In the first case, we see that the contractor already has 80 men and they are working for 130 days to complete the job. So, we can use the following formula to determine the additional number of workers required to finish the work in 100 days.
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine Let’s assume that the contractor adds 440 workers, of which 2 are paid ₱180.00 a day and the rest are paid ₱120.00 a day.
The total cost of the new workers is, therefore, ₱9600.00 + ₱4500.00 + ₱49800.00 = ₱63,900.00.The cost of liquidated damages would be calculated as follows: $$LD = (130-100) \cdot 500 = ₱15,000.00$$.
Therefore, the contractor would save money if he employs more men and not pays the fine. The contractor’s savings would be:$$Savings = LD - Additional cost$$$$= 15000.00 - 63900.00 $$$$= -48900.00$$
Thus, we can see that the contractor would save ₱48,900.00 by employing more men and not paying the fine.
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go lite, a maker of outdoor gear, integrates the________ into its mission, which is to offset 100% of its environmental footprint.
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Outdoor gear manufacturer Go Lite incorporates the natural Measurement into its objective to completely offset its environmental impact.
What are common measuring units?Seven measures are known as basic units: metre, kg, minute, ampere, kelvin, mole, as well as corona. The first and most prevalent of them are meters, seconds, and kilograms.
How many different kinds of measures exist?The remaining units, including the area, mass, force, acceleration, and others we just examined, are derived from some of these fundamental seven units of measurement. Please kindly find the seven separate quantities as well as their respective results are tabulated listed below.
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in a regular pyramid, the slant height is always longer than a lateral edge of the pyramid. true or false
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The statement "In a regular pyramid, the slant height is always longer than a lateral edge of the pyramid" is false.
In a regular pyramid, the slant height refers to the distance from the apex (top) of the pyramid to any point on the lateral face, measured along the slanted surface. A lateral edge, on the other hand, refers to the length of an edge that connects the apex to a vertex of the base.
In a regular pyramid, the slant height and the lateral edge are typically not equal to each other. The slant height is generally longer than a lateral edge. This can be understood by considering the shape of a regular pyramid, where the slant height forms a diagonal along the lateral face, while the lateral edge is a straight line connecting the apex and a vertex of the base.
However, it is important to note that the specific lengths of the slant height and lateral edge depend on the dimensions of the pyramid, such as the base size and the height. The relationship between the slant height and lateral edge can vary depending on the specific measurements of the regular pyramid.
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As discussed in the text, one possible performance enhancement is to do a shift and add instead of an actual multiplication. Since 9 x 6, for example, can be written (2 x 2 x 2 + 1) x 6, we can calculate 9 x 6 by shift ing 6 to the left 3 times and then adding 6 to that result. Show the best way to calculate 0 x33 x 0 x 55 using shift s and adds/subtracts. Assume both inputs are 8-bit unsigned integers.
Answers
Answer:
The best way to calculate 0 x33 x 0 x 55 using shift s and adds/subtracts and assuming both inputs are 8-bit unsigned integers is attached below
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
What can be used as a tracing powder when checking for small oil leaks
Answers
Answer:
Talcum powder!
Explanation:
How to find the source of an oil leak:
This method simply involves using Talcum Powder as a visual aid to help pinpoint the location of an oil leak,
so you use Talcum powder for small oil leak :]
Have a wonderful day!
A parallel helical gearset consists of a 19-tooth pinion driving a 57-tooth gear. The pinion has a left-hand helix angle of 30°, a normal pressure angle of 20°, and a normal module of 2.5 mm.
Find:_______.
(a) The normal, transverse, and axial circular pitches
(b) The transverse diametral pitch and the transverse pressure angle
(c) The addendum, dedendum, and pitch diameter of each gear
Answers
Answer:
a)
normal circular pitch = 7.8539 mm
transverse circular pitch = 9.0689 mm
axial circular pitches = 15.7077
b)
transverse diametral pitch is 0.3464 teeth/mm
transverse pressure angle is 22.8°
c)
Addendum = 2.5 mm
dedendum = 3.125 mm
pinion diameter = 54.8482 mm and Gear diameter = 164.5448 mm
Explanation:
Given that;
module m = 2.5 mm
Number of teeth on Gear nG = 57 TEETH
Number of teeth on Pinion nP = 19 TEETH
Helix angle W = 30°
Normal Pressure angle β = 20°
finding the circular pitch
Pc = πm
we substitute
Pc = π * 2.5 mm = 7.8539 mm
now the diametral pitch p = π / Pc
= π / 7.8539
= 0.4 teeth/mm
a)
So the normal circular pitch
Pn = π / P
Pn = π / 0.4
Pn = 7.8539 mm
the transverse circular pitch
Pt = Pn / cosW
Pt = 7.8539 / cos30°
Pt = 9.0689 mm
for axial circular pitches
Px = Pt / tanW
Px = 9.0689 / tan30°
Px = 15.7077
b)
The transverse diametral pitch and the transverse pressure angle.
The transverse diametral pitch Pt = PcosW
= 0.4 * cos30°
= 0.3464 teeth/mm
transverse diametral pitch is 0.3464 teeth/mm
transverse pressure angle β1 = tan^-1 ( tan βn / cos W)
= tan^-1 ( tan20° / cos 30°)
= tan^-1 ( 0.42027 )
β1 = 22.8°
transverse pressure angle is 22.8°
c)
The addendum, dedendum, and pitch diameter of each gear
Now from table standard Tooth proportions for Helical Gears;
Addendum a = 1/p
= 1 / 0.4
= 2.5 mm
dedendum b = 1.25 / p
= 1.25 / 0.4
= 3.125 mm
now pinion diameter dP = Np / PcosW
= 19 / 0.4 (cos30°)
= 54.8482 mm
Gear diameter dG = nG / pcosW
= 57 / 0.4 (cos30°)
= 164.5448 mm
Select the correct answer.
Which chemical can you use to assist with your motor fuel needs?
O A.
ethylene glycol
OB.
ethanol
O c.
butanol
OD.
pentanol
O E.
propranolol
Reset
Next
Answers
Answer: Ethanol
Explanation:
What time ----–- the train arrve?
Answers
A six-lane divided multilane highway (three lanes in each direction) has a measured free-flow speed of 50 mi/h. It is on mountainous terrain with a traffic stream consisting of 7% large trucks and buses and 3% recreational vehicles. The driver population adjustment in 0.92. One direction of the highway currently operates at maximum LOS C conditions and it is known that the highway has PHF=0.90.
How many vehicles can be added to this highway before capacity is reached, assuming the proportion of vehicle types remain the same but the peak-hour factor increases to 0.95?
Process: (1) determine passenger car equivalent for trucks and buses; (2) determine passenger car equivalent for recreational vehicles; (3) calculate heavy vehicle factor; (4) determine 15-min passenger equivalent flow rate for current conditions; (5) determine 15-min passenger equivalent flow rate at full capacity; (6) calculate the volume for current and capacity conditions; (7) take the difference of the two volumes to determine how many vehicles were added
Answers
Answer:
The number of vehicles added to this highway before the capacity is reached is 1,511 vehicles.
Explanation:
see attached image
You are a successful engineer and you purchase a home with a pool. You install a solar
water heater to heat the water in your pool. This system works by continuously pumping
water from the pool up to the roof, where it runs through tubes, absorbing heat from the
sun, and then the heated water is then returned to the pool. You can model the rooftop
system as a heat exchanger. The pumping rate of the water is 4 gallons per minute and
the pool water enters and leaves the heater at 18 °C and 27°C, respectively
(p, = 4.18
−°K). Electricity in your area costs 34.5 cents per kWh. If you run the
heater for 12 hours (assume the temperature entering and leaving the heater is constant
during this time), calculate how much you save over 12 hours by using solar heat instead
of electricity for heating the water. Assume the heat exchanger is 100% efficient and
ignore pumping energy costs. Note that one gallon of water weighs 3.785 kg and one kWh
is equal to 3,600 kJ.Rev
Answers
Pumping rate = 4 gallons per minuteSpecific heat capacity of water = 4.18 J/gKCost of electricity = 34.5 cents per kWhHeat exchanger efficiency = 100%Pumping energy costs = ignoredDensity of water = 3.785 kg/gallonTime for which solar water heater runs = 12 hoursLet's first calculate the mass of water pumped in 12 hours by the solar water heater.1 gallon of water weighs 3.785 kg.
So, the mass of water pumped in 12 hours = Pumping rate x density x time in minutes= 4 x 3.785 x 60 x 12 kg= 10,907.2 kgNext, we can calculate the energy required to increase the temperature of this water from 18 °C to 27 °C using electricity.Q = mcΔTWhere, m = mass of waterc = specific heat capacity of waterΔT = change in temperature= (27 - 18) °C = 9 °C= 9 x 4.18 x 10,907.2 J= 404,734.464 J= 404.73 kJ
This amount of energy requires electrical energy consumption of 404.73/3.6 = 112.426 kWhAnd the cost of using electricity for this amount of energy = 112.426 x 34.5 = $3880.62Therefore, the main answer is $3880.62 saved over 12 hours by using solar heat instead of electricity for heating the water,
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why would you want to change the ospf default reference-bandwidth?
Answers
You may want to change the OSPF (Open Shortest Path First) default reference bandwidth in order to accurately reflect the capacity of the network links when calculating OSPF cost metrics.
The reference bandwidth is used in the formula to calculate the cost of a link, which determines the preferred path for OSPF routing.
By default, OSPF assumes a reference bandwidth of 100 Mbps for calculating link costs. However, modern networks often have higher bandwidth links, such as 1 Gbps or 10 Gbps. In such cases, leaving the default reference bandwidth unchanged can result in suboptimal routing decisions.
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Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Answers
Answer:
Enthalpy, hsteam = 2663.7 kJ/kg
Volume, Vsteam = 0.3598613 m^3 / kg
Density = 2.67 kg/ m^3
Explanation:
Mass of steam, m = 1 kg
Pressure of the steam, P = 0.5 MN/m^2
Dryness fraction, x = 0.96
At P = 0.5 MPa:
Tsat = 151.831°C
Vf = 0.00109255 m^3 / kg
Vg = 0.37481 m^3 / kg
hf = 640.09 kJ/kg
hg = 2748.1 kJ/kg
hfg = 2108 kJ/kg
The enthalpy can be given by the formula:
hsteam = hf + x * hfg
hsteam = 640.09 + ( 0.96 * 2108)
hsteam = 2663.7 kJ/kg
The volume of the steam can be given as:
Vsteam = Vf + x(Vg - Vf)
Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)
Vsteam = 0.3598613 m^3 / kg
From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3
have examined classical and more modern software development techniques. In your own words share what you believe are some key differences between classical methodologies and more modern, workflow-based approaches.
Answers
There are a few key differences between classical and modern software development techniques.
What is software development techniques?
Software development techniques outline precise tactics and procedures that programmers are expected to adhere to in order to collaborate effectively with other programmers. Each approach has its own unique set of guidelines. However, they typically include rules dictating when to release new application updates, how to plan a new set of feature updates, how and when code is built, and how individual developers' code is merged into a broader codebase. When writing code or designing features, the majority of methodologies also include conceptual principles that are intended to assist developers in determining what is crucial and what is not. The majority of the time, as opposed to inflexible rules, high-level recommendations are at the core of software development approach and management techniques.
Classical techniques tend to be more rigid and focused on a waterfall approach, while modern techniques are more flexible and allow for a more agile development process. Classical techniques also tend to emphasize documentation and formal procedures, while modern techniques place more emphasis on collaboration and communication.
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For an electrical system, short dashed lines indicate?
Answers
A solid line around a component indicates that the component is complete. A dashed line around the component indicates that the component is being shown is not complete.
Allen made a diagram to compare radiation and conduction. A Venn diagram shows 2 intersecting circles, with the left circle labeled radiation and the right circle labeled conduction. There is an Y in the overlapping section. Which label belongs in the area marked Y? Must involve temperature differences between substances or objects Occurs when molecules are in direct contact Involves the movement of fluids based on density differences Can occur where there is little or no matter.
Answers
Allen made a Venn diagram to compare radiation and conduction. The diagram shows two intersecting circles, with the left circle labeled radiation, the right circle labeled conduction.
The overlapping region between the two circles is labeled "Y."The label that belongs in the area marked Y is "Occurs when molecules are in direct contact."Conduction occurs when molecules are in direct contact with each other. When two objects or substances are in contact, energy flows from the hotter object to the cooler object until both objects are at the same temperature.Radiation, on the other hand, does not require matter to transfer energy.
It involves the transfer of energy in the form of waves or particles through a vacuum or a transparent medium. Radiation is the transfer of heat from one body to another in the form of waves or rays.Most of the time, radiation and conduction occur at the same time. A good example of this is the transfer of heat through a metal pot. In this case, the heat from the burner is transferred to the metal pot through conduction, and then it is transferred to the food inside the pot through radiation.
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Refrigerant-22 absorbs heat from a cooled space at 50°F as it flows through an evaporator of a refrigeration system. R-22 enters the evaporator at 10°F at a rate of 0.08 lbm/s with a quality of 0.3 and leaves as a saturated vapor at the same pressure. Determine:
a. The rate of cooling provided, in Btu/h.
b. The rate of exergy destruction in the evaporator.
c. The second-law efficiency of the evaporator.
Take T0 = 77°F. The properties of R-22 at the inlet and exit of the evaporator are: h1 = 107.5 Btu/lbm, s1 = 0.2851 Btu/lbm·R, h2 = 172.1 Btu/ lbm, s^2 = 0.4225 Btu/lbm·R.
Answers
Answer:
a) the rate of cooling provided is 18604.8 Btu/h
b) the rate of exergy destruction in the evaporator is 0.46 Btu/Ibm
c) the second-law efficiency of the evaporator is 37.39%
Explanation:
Given that;
Temperature of sink TL = 50°F = 510 R
Temperature at evaporator inlet TI = 10°F = 470 R
mass flow rate m" = 0.08 lbm/s
quality of refrigerant at evaporator inlet x1 = 0.3
quality of refrigerant at evaporator exit x2 = 1.0
T₀ = 77°F = 537 R
h1 = 107.5 Btu/lbm
s1 = 0.2851 Btu/lbm·R,
h2 = 172.1 Btu/ lbm,
s2 = 0.4225 Btu/lbm·R.
a) rate of cooling provided, in Btu/h.
QL = m"( h2 - h1)
we substitute
QL = 0.08( 172.1 - 107.5
= 0.08 × 64.6
= 5.168 Btu/s
we convert to Btu/h
5.168 × 60 × 60
QL = 18604.8 Btu/h
Therefore the rate of cooling provided is 18604.8 Btu/h
b) The rate of exergy destruction in the evaporator
Entropy generation can be expressed as;
S_gen = m"(s2 - s1) - QL/TL
so we substitute
S_gen = 0.08( 0.4225 - 0.2851 ) - 5.168 / 510
= 0.010992 - 0.01013
S_gen = 0.00086 Btu/ibm.R
now the energy destroyed expressed as;
X_dest = T₀ × S_gen
so
X_dest = 537 × 0.00086
X_dest = 0.46 Btu/Ibm
Therefore the rate of exergy destruction in the evaporator is 0.46 Btu/Ibm
c) The second-law efficiency of the evaporator.
Energy expended is expressed as;
X_exp = m"(h1 - h2) - m"T₀(s1 - s2)
we substitute
= 0.08( 107.5 - 172.1 ) - [0.08 × 537 ( 0.2851 - 0.4225 )
= -5.168 - [ - 5.9027)
= -5.168 + 5.9027
= 0.7347 Btu/s
Now second law efficiency is expressed as;
nH = 1 - (X_dest / X_esp)
= 1 - ( 0.46 / 0.7347 )
= 1 - 0.6261
= 0.3739
nH = 37.39%
Therefore the second-law efficiency of the evaporator is 37.39%
The ventilating fan of the bathroom of a building has a volume flow rate of 32 l/s and runs continuously. if the density of air inside is 1.20 kg/m3, determine the mass of air vented out in one day. the mass of air is kg.
Answers
The mass of air vented out in one day from the bathroom with a volume flow rate of 32 l/s and air density of 1.20 kg/m3 is approximately 3,283.2 kg.
To calculate the mass of air vented out in one day, first, we need to find the volume of air vented out in one day, which is given by:
Volume flow rate x time = 32 l/s x 86,400 s/day = 2,764,800 l/day
Then, we can convert this volume to mass using the density of air:
Mass = Volume x Density = 2,764,800 l/day x 1.20 kg/m3 = 3,283.2 kg/day
Therefore, the mass of air vented out in one day from the bathroom is approximately 3,283.2 kg.
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A smooth ceramic sphere (SG 5 2.6) is immersed in a fl ow of water at 208C and 25 cm/s. What is the sphere diameter if it is encountering (a) creeping motion, Red 5 1 or (b) transition to turbulence, Red 5 250,000
Answers
Answer:
a. 4\(\mu m\)
b. 1 m
Explanation:
According to the question, the data is as follows
The Density of water at 20 degrees celcius is 1000 kg/m^3
Viscosity is 0.001kg/m/.s
Velocity V = 25 cm/s
V = 0.25 m/s
Now
a. The creeping motion is
As we know that
Reynold Number = (Density of water × V × d) ÷ (Viscosity)
1 = (1,000 × 0.25 × d) ÷ 0.0001
d = (1 × 0.001) ÷ (1,000 × 0.25)
= 4E - 06^m
= 4\(\mu m\)
b. Now the sphere diameter is
Reynold Number = (Density of water × V × d) ÷ (Viscosity)
250,000 = (1,000 × 0.25 × d) ÷ 0.0001
d = (250,000 × 0.001) ÷ (1,000 × 0.25)
= 1 m
Consider a layer of fluid contained between two horizontal parallel plates. The separation between the plates is 3mm. The bottom plate is fixed while the upper plate moves horizontally when a horizontal force of 0.6N is applied to it. The viscosity of the fluid is 0.02 Ns/mand the effective area of the upper plate in contact with the fluid is 0.2m? Determine the horizontal velocity of the plate. Fill in the blank only the letter corresponding to the value that best matches your solution a) 0.26 m/s b) 0.38 m/s c) 045 m/s d) 0.62 m/s e) 0.71 m/s f) 10.76 m/s g) None of the above list
Answers
The horizontal velocity of the upper plate is 0.45 m/s, and the best match from the given options is option (c).
To determine the horizontal velocity of the upper plate, we can use the formula for the shear stress in a fluid: τ = μ*(du/dy), where τ is the shear stress, μ is the fluid viscosity (0.02 Ns/m), du is the change in velocity, and dy is the distance between the plates (0.003 m).
The shear stress can also be calculated as τ = F/A, where F is the force applied (0.6 N) and A is the effective area of the upper plate (0.2 m²). Solving for τ, we get τ = 0.6 N / 0.2 m² = 3 N/m².
Now, we can equate the two expressions for shear stress: 3 N/m² = 0.02 Ns/m * (du/0.003 m). Solving for du, we find du = (3 N/m² * 0.003 m) / 0.02 Ns/m = 0.45 m/s.
Therefore, the horizontal velocity of the upper plate is 0.45 m/s, and the best match from the given options is (c) 0.45 m/s.
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2 A SQUARE GIVEN
LENGTH OF DIAGONAL = 70 mm
Answers
Answer:
Area of square = 2,450 mm²
Explanation:
Given:
Length of diagonal = 70 mm
Find:
Area of square
Computation:
Area of square = diagonal² / 2
Area of square = 70² / 2
Area of square = 4900 / 2
Area of square = 2,450 mm²
The collector current is 10 ma, and the base current is 0. 1 ma. What is the current gain?
Answers
In a bipolar junction transistor, the current gain can be defined as the ratio of the collector current to the base current. It is generally denoted by \(hFE\)or \(β\).
When collector current (IC) is 10 mA and base current (IB) is 0.1 mA, then the current gain is given by the ratio of collector current to base current.
Therefore, the current gain (\(β\)) is given as:
\(β = IC/IBβ = 10/0.1β = 100\)
Thus, the current gain of the transistor is 100. This indicates that for every 1 mA of base current, the collector current is 100 mA. It is important to note that the current gain is not constant and varies with temperature, current, and other factors.
The current gain is an important parameter in transistor amplifiers as it determines the amplification factor of the circuit. An increase in the current gain leads to higher amplification and vice versa.
It is essential to choose a transistor with the appropriate current gain for a given application to ensure optimal performance.
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. Describe the “seven deadly wastes”
Answers
Answer:
The original seven wastes, or muda, are transportation, inventory, motion, waiting, overproduction, overprocessing and defects. ... When manufacturers are able to identify the seven wastes, they can correct and prevent further loss of time, money and other resources.
Explanation:
Answer:
transportation, inventory,motion, waiting,overproduction,overprocessing,and defects
Explanation:
they are often referred to by the acronym TIMWOOD
Oxidation Inhibitors are antioxidant additives that slow the degradation
of the oil stock by oxidation?
Answers
Answer: True
Explanation:
Oil oxidation is a process that all oil goes through and involves a series of chemical reactions between compounds in the oil and oxygen that lead to the quality of the oxygen falling. In other words, oxidation degrades oil.
Even though this is a process that all oil goes through and one that cannot be stopped, it's pace can be reduced. One way of doing this is by adding oxidation inhibitors which are antioxidant additives that work to slow the degradation of the oil stock by oxidation.