The units of Planck's constant are Joule seconds (J*s).
Planck's constant is a fundamental physical constant that plays a crucial role in quantum mechanics. It relates the energy of a photon to its frequency through the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The unit of energy is Joules (J), and the unit of frequency is Hertz (Hz), so the unit of Planck's constant is J*s.
The significance of Planck's constant lies in its ability to bridge the gap between classical physics and quantum mechanics. It helps explain phenomena such as wave-particle duality, where particles can behave as waves and vice versa. Additionally, it is used in calculations related to atomic and subatomic particles, including the energy levels of electrons in atoms and the behavior of photons in lasers.
Overall, the units of Planck's constant demonstrate its importance as a fundamental constant in the field of quantum mechanics and its role in bridging the gap between classical physics and the mysterious realm of the subatomic world.
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The diagram shows a screwdriver being used as a lever to open a tin
Answer:
(a) Most reactive \({}\) Metal B
\({}\) Metal D
\({}\) Metal A
Least reactive \({}\) Metal C
(b) (i) Bubbles should form very slowly
(ii) No reaction takes place
Explanation:
(a) The given metals arranged in their order of reactivity are;
Most reactive \({}\) Metal B
\({}\) Metal D
\({}\) Metal A
Least reactive \({}\) Metal C
The other of reactivity is based on the nature of their reactivity of the metals in air
(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly
(ii) Similarly, given that metal C is unreactive, we have that when small pieces of metal C are added to dilute hydrochloric acid, no reaction takes place.
an athlete runs with velocity 11 km/h for 4 minutes, 14 km/h for the next 2 minutes, and 17 km/h for other 5 minutes. compute the total distance traveled.(use decimal notation. give your answer to two decimal places.)
The total distance traveled by an athlete that runs with velocity 11 km/h for 4 minutes, 14 km/h for the next 2 minutes, and 17 km/h for other 5 minutes is 223 m
v = d / t
v = Velocity
d = Distance
t = Time
1 km / h = 1 / 60 km / min
d = v / t
For first 4 minutes,
v = 11 km / h
v = 11 / 60 km / min
v = 0.183 km / min
d = 0.183 / 4
d = 0.046 km
For the next 2 minutes,
v = 14 km / h
v = 14 / 60 km / min
v = 0.23 km / min
d = 0.23 / 2
d = 0.12 km
For the next 5 minutes,
v = 17 km / h
v = 17 / 60 km / min
v = 0.283 km / min
d = 0.283 / 5
d = 0.057 km
Total distance = 0.046 + 0.12 + 0.057
Total distance = 0.223 km
Total distance = 223 m
Therefore, the total distance traveled is 223 m
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a potter carries 30 bricks to a distance of 50 m in 25 seconds. If the weight of 1 brick is 12N. Calculate work down and power
Answer:
(I)W=18×10³ J
(ii) P=720W
Explanation:
30 Bricks = 1brick weight× 30 Bricks
30 Bricks= 12×30
=360N
Distance=50m
Time= 25s
1. Work done= Force× Distance
=360×50
= 18×10³ J
2. Power= Work done/ Time
18×10³/25
Power= 720W.
Question #7: If the skater were to continue to roll on the ramp, the skater would get lower and lower each time and eventually stop. Which of the following explains this phenomenon? Energy escapes the system in the form of heat. O Energy is destroyed by the action of the wheels rolling on the ramp. O Potential energy is equal to zero when the skater reaches the bottom of the ramp. O Kinetic energy uses up energy until there is no more.
The Potential energy is equal to zero when the skater reaches the bottom of the ramp.
What is the kinetic energy of an object?The kinetic energy of an object is the energy possessed by the object due to its motion.
Mathematically, the formula for kinetic energy is given as;
K.E = ¹/₂mv²
where;
m is the mass of the objectv is the velocity of the objectBased on the law of conservation of energy, the potential energy of the skier is maximum at the maximum height and this potential energy is converted into kinetic energy and eventually becomes zero at the bottom of the ramp.
Thus, the correct explanation is Potential energy is equal to zero when the skater reaches the bottom of the ramp.
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which of the following best describes dew point
a- the temperature at which water evaporates
b-the temperature at which condensation occurs
c-the temperature at which clouds evaporate
d-the temperature at which water freezes
A car travels 52 mph for 6 minutes, 46 mph for 3 minutes, 40 mph for the remaining time during a 30 minute journey. find the total distance travelled
Answer:
21.5 miles
Explanation:
Distance = Speed * time
Distance traveled in first 6 minutes = 52 * \(\frac{6}{60}\) = 5.2 miles
Distance traveled in next 3 minutes = 46 *\(\frac{3}{60}\) = 2.3 miles
Remaining minutes = 30 - 6 -3 = 21 minutes
Distance traveled in 21 minutes = 40 * \(\frac{21}{60}\) = 14 miles
Total distance traveled = 5.2 + 2.3 + 14 = 21.5 miles
In a hurry, you ask your friend to throw your laptop to you from 8 m away. Your friend throws you the laptop and you catch it at the same height from which it was thrown a mere 0.4 seconds later.
(a) At what angle did the laptop leave your friend’s hand?
(b) With what speed did the laptop leave your friend’s hand?
(c) What is the highest (above the starting point) that the laptop gets?
(a) The laptop left your friend's hand at an angle of approximately 45 degrees.
(b) The laptop left your friend's hand with a speed of approximately 7.85 m/s.
(c) The highest point reached by the laptop is approximately 1.23 meters above the starting point.
To determine the answers, we can use the principles of projectile motion. The key variables we need are the initial velocity (speed) and launch angle. The time of flight can also be calculated, which helps us find the highest point reached by the laptop.
(a) To find the angle, we can use the fact that the horizontal distance and time of flight are related. The horizontal distance traveled by the laptop is 8 meters, and the time of flight is 0.4 seconds. The equation for horizontal distance is given by:
Horizontal distance = Initial velocity * cos(angle) * time
Substituting the known values, we have:
8 = Initial velocity * cos(angle) * 0.4
Solving for the angle, we get:
cos(angle) = 8 / (Initial velocity * 0.4)
Taking the inverse cosine (arccos) of both sides, we find:
angle = arccos(8 / (Initial velocity * 0.4))
Substituting the known values, we can calculate the angle to be approximately 45 degrees.
(b) To find the initial velocity, we can use the vertical distance traveled by the laptop. Since the laptop was thrown and caught at the same height, the vertical displacement is zero. The equation for vertical displacement is given by:
Vertical displacement = (Initial velocity * sin(angle) * time) - (0.5 * g * time^2)
Since the vertical displacement is zero, we can set the equation equal to zero:
0 = (Initial velocity * sin(angle) * 0.4) - (0.5 * 9.8 * 0.4^2)
Simplifying and solving for the initial velocity, we find:
Initial velocity = (0.5 * 9.8 * 0.4^2) / (0.4 * sin(angle))
Substituting the known values and the angle calculated in part (a), we can determine the initial velocity to be approximately 7.85 m/s.
(c) To find the highest point reached by the laptop, we need to calculate the vertical displacement at the midpoint of the trajectory. Since the total time of flight is 0.4 seconds, the midpoint will be at t = 0.2 seconds. The equation for vertical displacement at a given time is:
Vertical displacement = (Initial velocity * sin(angle) * time) - (0.5 * g * time^2)
Substituting the known values and t = 0.2 seconds, we can find the vertical displacement:
Vertical displacement = (7.85 * sin(45) * 0.2) - (0.5 * 9.8 * 0.2^2)
Simplifying, we find the vertical displacement to be approximately 1.23 meters above the starting point.
The laptop left your friend's hand at an angle of approximately 45 degrees and with a speed of approximately 7.85 m/s. It reached a maximum height of approximately 1.23 meters above the starting point. These calculations were based on the principles of projectile motion and the given information of the distance, time of flight, and height.
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Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.
Which part of the statement is not true?
Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.
Primary clarifiers removing biological nutrients is not true. Primary clarifiers
involves the use of processes such as sedimentation in order to remove
particles floating or other inorganic solids from the waste water.
Biological nutrients such as nitrogen and phosphorus are found in waste
water and removal of these important nutrients for other uses is a part of
waste water management.
The secondary clarifiers are the ones responsible for the removal of
biological nutrients in the waste water through biofiltration etc.
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Convert 6.6 meters to centimeters
Answer:
6.6 Meters = 660 Meters
Explanation:
1 Meter = 100 Centimeters
please fast
The system shown in the figure below uses three chain comveyors. Each chain has a hydraulic motor: The torque that drives the motors is T: =1500 N.m
1 T2 =700 Nm and, T3 = 300Nm. The displactment volume of the motors is V01 =1000 cm3/rev V02 =1000 cm3/rev and, V09 =500 cm3 /rex. The motss have a volumetric efficiency of 0.9 and an overall efficiency of 0.85. The leakage of the bydraulic motors 1 and 3 is internal completely and the leakage of the hydraulic motor 2 is external completely. The pump produces a constant volumetric flow rate of 6.3U/min.
The orifice of the flow control valve has a 0.5 mm diameter. The pressure fosses through the pipes are neglected. The capacity coefficient of the needie valve is 07. The volumetric Alow rate through the needle valve is given by: Q=C×A2 ×ΔF/rho where C is the capacity coefficient, A is the area of the orifice, ΔP is the difference of pressure through the needle valve and, rho is the density of the fiuid.
The density of the oil used in the hydraulic system is 860 kg/m3 . Determine the rotational speed of the motor 3 in rpm. a. 8 b. 92 c. 67 d. 42 e. 34 E. 56
The rotational speed of the motor 3 in rpm. b. 92
The figure shows a hydraulic circuit that uses three chain conveyors. The torque that drives the motors is T: =1500 N.m. T2 =700 Nm and, T3 = 300Nm.The volumetric flow rate produced by the pump is 6.3 liters per minute. The displacement volume of the motors is V01 =1000 cm3/rev. V02 =1000 cm3/rev and, V09 =500 cm3/rex.
The motors have a volumetric efficiency of 0.9 and an overall efficiency of 0.85. The leakage of hydraulic motors 1 and 3 is internal completely, while the leakage of hydraulic motor 2 is external completely.The orifice of the flow control valve has a diameter of 0.5 mm. The capacity coefficient of the needle valve is 0.7.
The pressure losses through the pipes are ignored. The volumetric flow rate through the needle valve is Q = C × A2 × ΔP / ρ where C is the capacity coefficient, A is the area of the orifice, ΔP is the pressure difference through the needle valve, and ρ is the density of the fluid. The density of the oil used in the hydraulic system is 860 kg/m3. We need to determine the rotational speed of motor 3 in rpm.
So,Let’s first determine the volumetric flow rate required by hydraulic motor 3. Using the expression of volumetric flow rate through the needle valve, we have Q = C × A2 × ΔP / ρ… (i)We are given that the capacity coefficient of the needle valve is 0.7. Its orifice diameter is 0.5 mm.
Hence, the area of the orifice is given byA2 = π d2 / 4where d is the diameter of the orifice. So, A2 = π × (0.5 mm)2 / 4 = 0.196 mm2 = 1.96 × 10-7 m2Using equation (i), we haveQ = C × A2 × ΔP / ρNow, we will calculate ΔP. To do this, we need to determine the flow rates Q1, Q2, and Q3.Let Q’ be the total volumetric flow rate through the system.
Since the overall efficiency of the system is given as 0.85, we haveQ’ = 0.85 × 6.3 l/min = 5.355 l/min = 5.355 × 10-3 m3/minWe know that the volume of fluid passing through the hydraulic motors is equal to their displacement volume multiplied by the number of revolutions per unit time.So, we haveQ1 = V01 × n1 … (ii)Q2 = V02 × n2 … (iii)Q3 = V03 × n3 … (iv)where V01, V02, and V03 are the displacement volumes of hydraulic motors 1, 2, and 3, respectively.
We are given that V01 = V02 = 1000 cm3/rev and V03 = 500 cm3/rev, which gives V01 = V02 = 1 × 10-6 m3/rev and V03 = 0.5 × 10-6 m3/rev.Substituting equations (ii), (iii), and (iv) in equation (i), we haveQ = C × A2 × (Q1 + Q2 - Q3) / ρSolving for Q3, we getQ3 = (Q1 + Q2 - Q) / C × A2 × ρPutting the given values in the above expression, we haveQ1 = V01 × n1 = (1 × 10-6 m3/rev) × n1Q2 = V02 × n2 = (1 × 10-6 m3/rev) × n2Q3 = V03 × n3 = (0.5 × 10-6 m3/rev) × n3Q = 5.355 × 10-3 m3/min = 5.355 × 10-3 / 60 m3/s = 8.925 × 10-5 m3/sA2 = 1.96 × 10-7 m2C = 0.7ρ = 860 kg/m3
Substituting the above values, we get8.925 × 10-5 = (1 × 10-6 × n1 + 1 × 10-6 × n2 - 0.5 × 10-6 × n3) / (0.7 × 1.96 × 10-7 × 860)Solving for n3, we have n3 = 91.6 rpmSo, the correct option is b. 92.
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While observing the chromosphere and corona of the Sun, scientists often observe bands of plasma, called filaments. What can these filaments tell us about the possibility of a solar storm?
Because they last for a very long time, they become unstable and then either slip back into to the sun and erupt into space.
What are the names of the eruptions that take place on the Sun's surface?Solar flares are abrupt outbursts that are among the most violent phenomena to occur on the Sun's surface.Flares can unleash energies equal than millions of thermonuclear weapons and normally endure for a few minutes.
A coronal filament eruption is what?The moment the filament size starts to diminish as seen in H pictures is when we designate the filaments eruption start time.This study reports 33 eruptive filament episodes, of which 73% are connected with CMEs and 76% with solar flares.
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Sushant went on an educational trip to a village. There he found a potter making pots. He found that the soil used for making pots was different from normal soil. Name the soil and also tell its characteristics.
The soil used for making pots by potters is commonly known as "Potter's Clay" or "Potter's Soil."
Characteristics of Potter's Clay:
1. Plasticity: Potter's clay has high plasticity, which means it can be easily molded and shaped into different forms without cracking or breaking.
2. Cohesiveness: It exhibits good cohesion, allowing the clay particles to stick together when moistened, forming a workable material.
3. Fine Particle Size: Potter's clay consists of fine particles that contribute to its plasticity and workability.
4. High Water Retention: It has the ability to retain water, which helps maintain the moisture content necessary for the clay to be shaped and formed.
5. Low Shrinkage: Potter's clay exhibits low shrinkage when it dries or undergoes firing, ensuring minimal distortion or cracking during the drying and firing processes.
6. Good Bonding Properties: The clay particles have the ability to bond together, creating a strong and durable structure once fired.
7. Good Porosity: After firing, the clay retains some porosity, allowing the pot to breathe and allowing for the exchange of air and moisture.
To measure a population’s baseline genetic state, it must have _____________ to be in hardy-weinberg equilibrium
Answer:
b
Explanation:
b
6th grade science If you answer this your the brainiest
Answer:
8. sketches and models helped the astronauts in their training program as they prepare for their missions
9. before building the Mars lander , students need to sketch their design
The foot of a 60 kg sprinter is on the ground for 0.40 s while her body accelerates from rest to 2.0 m/s.
What is the magnitude of the friction force?
We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.
To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.
Mass of the sprinter,
m = 60 kgTime the sprinter's foot is on the ground,
t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,
v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:
v = final velocity of the sprinter, which is 2.0 m/s
u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s
Substituting these values, we get:2.0
= 0 + a(0.40)Simplifying, we get:
2.0 = 0.4a
Dividing both sides by 0.4, we get:
a = 5 m/s² Substituting the values, we get:
F = 60 × 5F = 300 N
Therefore, the magnitude of the friction force is 300 N.
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If Steve throws a football 40 m and it travels for 3 seconds, what was the balls velocity?
Answer:
13.4 m/s^2
Explanation:
40 divided by 3 equals 13.3 repeating.
Calculate the speed of light in a medium whose refractive index is 2.4
Answer:
Approximately \(1.3\times 10^{8}\; \rm m\cdot s^{-1}\).
Explanation:
Look up the speed of light in vacuum: \(c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}\). Denote the speed as \(c\).
If the speed of light in a medium is \(v\), the refractive index of that medium would be:
\(\displaystyle n = \frac{c}{v}\).
Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.
Rearrange this equation to find the speed of light \(v\) in this medium:
\(\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}\).
Which are ways in which heat energy leaves the surface of land masses? select the three correct answers.
It is accurate to say that infrared energy, conduction to air later rising in convection, and evaporation are the processes in which the heat energy so produced exits the surface of land masses.
Fluid or gas particles are frequently moved by convection currents. These are produced as a result of variations in a particular gas or fluid's density and temperature. One of the two ways to transmit heat is through convection; the other two are through radiation and conduction. Only fluids, such as liquids and gases, undergo the convection process. This occurs because molecules within liquids and gases are free to move.
The difference in temperature between the two portions of the fluid can cause the convection process, which transfers heat energy. This temperature differential causes hot fluids to have a tendency to ascend while cold fluids have a tendency to sink.
The correct question is:
Which are ways in which heat energy leaves the surface of land masses? Select the three correct answers.(2 points)
a).evaporation
b).glacial motion
c).animal activity
d).conduction to air, which then rises in convection
e).plant growth
f).radiation of infrared energy
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The si unit of mass is the Newton. True or false.
The specific tension of muscle is about 30 N/cm^2. The cross-sectional areas of the prime movers for elbow flexion and extension have been measured as follows:
Muscles Cross-sectional area
Biceps brachii 3.6 cm2
Brachialis 6.0 cm2
Brachioradialis 1.5 cm2
Triceps brachii 17.8 cm2
A. Determine the maximum force that the elbow flexors (as a group of muscles) can exert.
B. Consider the elbow flexors to act together with a moment arm of 4 cm, and the triceps with a moment arm of 2.5 cm. If all of these muscles were activated fully, would the elbow flex or extend?
A. We need to compute the entire cross-sectional area of the prime movers for elbow flexion and multiply it by the specific tension of muscle to get the maximum force that the elbow flexors can produce. The elbow flexors have a total cross-sectional area of 3.6 + 6.0 + 1.5 = 11.1 cm2. As a result, the elbow flexors may exert the following amount of force:
Cross-sectional area times a certain tension equals force.
Force = 333 N Force = 11.1 cm2 x 30 N/cm2
B. We must compare the torques generated by the triceps and the elbow flexors in order to determine whether the elbow will flex or extend. A muscle's torque is determined by multiplying the force it exerts by the moment arm. The moment arm is the angle at which the muscle's line of action is perpendicular to the axis of rotation.
The total torque for the elbow flexors is:
Torque equals force times moment arm
Torque equals 333 N/4 cm.
1332 N cm of torque
The total torque for the triceps is:
Torque equals force times moment arm
Torque is equal to 17.8 cm2 x 30 cm2 x 2.5 cm.
1335 N cm of torque
Since the triceps generate slightly more torque than the elbow flexors do, the elbow would extend if all of these muscles were fully engaged.
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A. To determine the maximum force that the elbow flexors can exert, we need to calculate the total cross-sectional area of the prime movers for elbow flexion, and then multiply it by the specific tension of the muscle:
The total cross-sectional area of elbow flexors = Biceps brachii + Brachialis + Brachioradialis
= 3.6 cm2 + 6.0 cm2 + 1.5 cm2
= 11.1 cm2
The maximum force that the elbow flexors can exert = Total cross-sectional area x Specific tension of muscle
= 11.1 cm2 x 30 N/cm2
= 333 N
Therefore, the maximum force that the elbow flexors can exert is 333 N.
B. To determine whether the elbow would flex or extend if all of these muscles were activated fully, we need to calculate the net torque generated by the muscles:
Net torque = (Force x Moment arm)flexors - (Force x Moment arm)triceps
Where force is the maximum force that the elbow flexors can exert (333 N), the moment arm of the elbow flexors is 4 cm, and the moment arm of the triceps is 2.5 cm.
Net torque = (333 N x 4 cm) - (333 N x 2.5 cm)
= 999 Ncm - 832.5 Ncm
= 166.5 Ncm
Since the net torque is positive (166.5 Ncm), the elbow would flex if all of these muscles were activated fully.
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6. A balloon gathers -0.973 μC of charge as the wind blows it directly East through
Earth's magnetic field (BE = 5.01 x 10-5 T). If the magnetic force on the balloon is
8.11 x 10-10 N West.
what is the
velocity of the balloon?
a.-16.6 m/s
c. 8.44 m/s
b. 3.95 x 10-20 m/s
d. 16.6 m/s
Answer:
Explanation:
To determine the velocity of the balloon, we can use the formula for the magnetic force on a charged particle moving in a magnetic field:
F = qvB
Where:
F is the magnetic force,
q is the charge,
v is the velocity of the balloon, and
B is the magnetic field strength.
Given:
F = -8.11 x 10^-10 N (West)
q = -0.973 μC = -0.973 x 10^-6 C (the negative sign indicates the charge is negative)
B = 5.01 x 10^-5 T
We can rearrange the formula to solve for v:
v = F / (qB)
Substituting the given values:
v = (-8.11 x 10^-10 N) / (-0.973 x 10^-6 C * 5.01 x 10^-5 T)
v ≈ 16.6 m/s
Therefore, the velocity of the balloon is approximately 16.6 m/s. Option (d) is the correct answer.
two small charged particles, 1 and 2, are separated by 0.1mm. if the charge is tripled on both particles, how does the force by particle 1 on particle 2 change?
Integral multiple copies of e are used to quantify charge in any common material. While electrons carry one unit of negatively charged, e, protons carry one unit of positively charged, +e.
It's sometimes referred to as an electron, right?
The word "electron" now refers to
Visit the following to learn more about electrons:
cathode ray particles with negative charges. The minuscule electrons are negatively charged particles with very little mass. The mass of an atom is made up of both protons and neutrons.
We can now use the ideal gas law to calculate each partial pressure:
PHe=nHeRTV=81.54mol×0.08206atm⋅Lmol⋅K×293.15K10.0L=196.2atm
PO2=nO2RTV=1.60mol×0.08206atm⋅Lmol⋅K×293.15K10.0L=3.85atm
The total pressure is formed by adding the two component pressures:
Ptot=PHe+PO2=(196.2+3.85)atm=200.1atm
Any common material's charge is quantified in scale item e. A proton has one positive charge, +e, wh
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the parts of the mixture are noticenbly different from one another
Answer:
heterogeneous mixture :)
Explanation:
homogenous means the same type is in it, heterogeneous means different parts.
The greenhouse effect is when the sun's heat is trapped in the atmosphere warming the earth. True or false
Answer:
True
Explanation:
I believe the answer is true.
PLEASE HELP! ASAP
In which reaction is there a transformation of mass into energy?
A. Uranium breaks apart into krypton, barium, and three neutrons.
B. Sodium combines with chlorine to form sodium chloride.
C. Hydrogen combines with oxygen to form water
D. Ammonium nitrate breaks down into dinitrogen monoxide and
water
Explanation:
Specifically, small amounts of mass are turned into energy from the breaking up (fission) or combination (fusion) of the nuclei of atoms. Even spontaneous radioactive decay converts a bit of mass into incredible amounts of energy.
Answer:
A. Uranium breaks apart into krypton, barium, and three neutrons.
Explanation:
did the test !!
A 74.0 kg person climbs stairs, gaining 2.10 meters in height. Find the work done (in J) to accomplish this task
The work done by the person to climb the stairs is approximately 1521.72 Joules.
To find the work done by a person while climbing stairs, we can use the equation:
Work = force * distance * cos(theta)
where force is the force applied by the person, distance is the vertical distance climbed, and theta is the angle between the force applied and the direction of motion.
In this case, the force applied by the person is equal to their weight, which can be calculated using the equation:
force = mass * acceleration due to gravity
\(force = 74.0 kg * 9.8 m/s^2\)
force = 725.2 N
The distance climbed is given as 2.10 meters.
The angle theta is 0 degrees since the force applied by the person is in the same direction as the motion.
Now we can calculate the work done:
Work = 725.2 N * 2.10 m * cos(0°)
Work = 725.2 N * 2.10 m * 1
Work = 1521.72 J
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The Weight of an object is more at pole and less at equator of the earth. Give reason
The Weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
10. A 25 kg apple cart is being pushed with an applied force of 115 N. The coefficient of friction between the ground and the cart is 0.35. What is the acceleration of the cart?
Answer:
1.1 m/s²
Explanation:
From the question,
F -mgμ = ma.................... Equation 1
Where F = applied force, m = mass of the apple cart, g = acceleration due to gravity, μ = coefficient of friction., a = acceleration of the apple cart.
Given: F = 115 N, m = 25 kg, μ = 0.35
Constant: g = 10 m/s²
Substitute these values into equation 2
115-(25×10×0.35) = 25×a
115-87.5 = 25a
25a = 27.5
a = 27.5/25
a = 1.1 m/s²
What is called gravitational potential energy?
Answer:
Potential gravitational energy is the energy that the body has due to the Earth's gravitational attraction. In this way, the potential gravitational energy depends on the position of the body in relation to a reference level.
Explanation:
Balloon a is ___ charged and balloon c is ___ charged. If balloon a approaches balloon c there will be a force of blank between them
Balloon A is positively charged, and balloon C is negatively charged. If balloon A approaches balloon C, there will be an electrostatic force of attraction between them.
When two objects carry opposite charges, they exert an attractive force on each other. This force is known as the electrostatic force and follows Coulomb's law. According to Coulomb's law, the magnitude of the electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this scenario, since balloon A is positively charged and balloon C is negatively charged, they have opposite charges. Therefore, the electrostatic force between them will be attractive. The magnitude of the force depends on the charges of the balloons and the distance between them. It is important to note that without specific information about the charges of the balloons and their distance, it is not possible to determine the exact magnitude of the force. To calculate the force, you would need the values of the charges and the distance between the balloons.
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