ue or false: hypochlorites are probably the most extensively used of all chlorine compounds; however, chloramines are being employed more frequently as alternatives in treating water supplies due to concerns regarding the formation of cancer-causing substances.

Answer:

In first shell duplet rule is applied because first shell contains maximum 2 electrons

Explanation:

The binding energy of copper-63 is 9.213 × 10^9 kJ/mol nucleons.

The binding energy of a nucleus can be calculated using the Einstein's famous mass-energy equation:

E = Δm * c^2

where E is the binding energy, Δm is the mass defect of the nucleus, and c is the speed of light.

The mass defect (Δm) is the difference between the mass of the nucleus (in atomic mass units, amu) and the sum of the masses of its constituent protons and neutrons (also in amu). It arises due to the conversion of some mass into energy during the formation of the nucleus.

For copper-63, the number of protons is 29 and the number of neutrons is 34. The atomic mass of copper-63 is 62.92980 g/mol, which is equivalent to 62.92980/6.022 × 10^23 = 1.0441 × 10^-22 g per nucleus.

The mass of 29 protons is 29 × 1.00728 amu = 29.19712 amu.

The mass of 34 neutrons is 34 × 1.00867 amu = 34.30478 amu.

The total mass of protons and neutrons is 29.19712 + 34.30478 = 63.5019 amu.

The mass defect is therefore:

Δm = 63.5019 - 62.92980 = 0.5721 amu

The binding energy can now be calculated:

E = Δm * c^2 = 0.5721 amu * (1.66054 × 10^-27 kg/amu) * (2.99792 × 10^8 m/s)^2 * (6.022 × 10^23 nuclei/mol) / 1000 J/kJ

E = 9.213 × 10^12 J/mol nucleons

Converting this to kilojoules per mole of nucleons:

E = 9.213 × 10^12 J/mol nucleons / (1000 J/kJ) = 9.213 × 10^9 kJ/mol nucleons

Therefore, the binding energy of copper-63 is 9.213 × 10^9 kJ/mol nucleons.

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The salivary amylase did not perform well if the pH becomes lower because it needs neutral pH for performing its functions.

We can say that the salivary amylase did not perform their function very well within the stomach due to unfavourable environment such as lower pH. Due to lower pH, the enzyme structure is damaged so unable to perform its function so we can conclude that the salivary amylase did not perform well if the pH becomes lower.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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The extra step taken when cleaning up an acid or base spill is :

Acid and Base spills are treated with an extra caution during cleanup to prevent injury to skin and this is because strong acids are;

After neutralization, clean up the spill with a towel ( usually paper towel ) and avoid using a strong base to neutralize a strong acid as well.

Hence we can conclude that Neutralizing the Acid/base spill with with a weaker base such as sodium Bicarbonate or weak acid respectively  is the extra step.

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Answer:

A. Reduced precipitation is the cause of drought.

Explanation:

Reduced precipitation begins to insufficient water availability because water catch basins or tanks tend to dry out. When it drains out, people tend to start working and drying out the backup water sources and stored ones. Until such time, that the reservoirs of water will completely be dried out. And there will be no more water for them to use and there will be a drought.

hope this helps

Answer:

Option A

Explanation:

The statement indicating the need for further teaching would be, "I can stop taking my anticholinergic medication now that I'm on levodopa/carbidopa."

This statement indicates a misunderstanding by the patient about the purpose and usage of their medications. Levodopa/carbidopa is a combination medication used to treat the symptoms of Parkinson's disease, while anticholinergic medications are prescribed to manage certain symptoms associated with the disease.

It is important for the patient to understand that levodopa/carbidopa and anticholinergic medications have different mechanisms of action and serve distinct purposes in their treatment plan.

By stating that they can stop taking the anticholinergic medication now that they are on levodopa/carbidopa, the patient demonstrates a lack of comprehension about the role of each medication. Levodopa/carbidopa primarily helps increase dopamine levels in the brain to alleviate motor symptoms, while anticholinergics work by blocking the action of acetylcholine, another neurotransmitter involved in movement regulation.

The need for further teaching is essential to clarify the patient's understanding. It is crucial for them to grasp that discontinuing the anticholinergic medication without medical guidance can lead to a worsening of symptoms and potential complications.

The healthcare provider should emphasize the importance of following the prescribed regimen and consult with them to adjust the dosage or consider discontinuation of any medication.

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The researcher should select arsenic because it belongs in the same group as phosphorus but has a higher atomic mass.

The correct option is C.

Phosphorus is in Group 15 (also known as Group V) of the periodic table. Elements in this group have 5 valence electrons, which means they tend to form compounds with a -3 oxidation state.

Other elements in Group 15 are:

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For the pH after the addition of each volume of acid, we need to consider the reaction between methylamine (CH₃NH₂) and HNO₃. Methylamine is a weak base, and HNO3 is a strong acid. The reaction can be written as:

CH₃NH₂ + HNO₃ -> CH₃NH₃+ + NO₃-

First, let's calculate the initial moles of methylamine in the 100.0 ml sample:

moles CH₃NH₂ = volume (L) * concentration (mol/L)

moles CH₃NH₂ = 0.100 L * 0.100 mol/L

moles CH₃NH₂ = 0.010 mol

Since CH₃NH₂ is a weak base, it will react with HNO₃ in a 1:1 ratio. Therefore, the number of moles of CH₃NH₂ reacting will be equal to the number of moles of HNO₃ added.

Now let's calculate the moles of HNO₃ added for each case:

a) 0.0 ml (no HNO₃ added): 0.010 mol

b) 20.0 ml: moles HNO₃ = 0.020 L * 0.250 mol/L = 0.005 mol

c) 40.0 ml: moles HNO₃ = 0.040 L * 0.250 mol/L = 0.010 mol

d) 60.0 ml: moles HNO₃ = 0.060 L * 0.250 mol/L = 0.015 mol

Now we need to calculate the moles of CH₃NH₂ and CH₃NH₃+ remaining after the reaction.

For case a) 0.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.000 mol = 0.010 mol

moles CH₃NH₃+ formed = 0.000 mol

For case b) 20.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.005 mol = 0.005 mol

moles CH₃NH₃+ formed = 0.005 mol

For case c) 40.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.010 mol = 0.000 mol

moles CH₃NH₃+ formed = 0.010 mol

For case d) 60.0 ml:

moles CH₃NH₂ remaining = 0.010 mol - 0.015 mol = -0.005 mol (Excess acid)

moles CH₃NH₃₊ formed = 0.015 mol

Since methylamine is a weak base, we need to consider the Kb value to calculate the concentration of hydroxide ions (OH-) and then convert it to pH.

The Kb expression for methylamine is:

Kb = [CH₃NH₃+][OH-] / [CH₃NH₂]

We can assume that [OH-] ≈ [CH₃NH₃+], so the equation becomes:

Kb = [OH-]^2 / [CH₃NH₂]

Rearranging the equation:

[OH-] = sqrt(Kb * [CH₃NH₂])

Now, let's calculate the OH- concentration and convert it to pH for each case:

a) 0.0 ml:

[OH-] = sqrt(3.7x10^-4 * 0.010 mol) ≈ 0.00608 M

pOH = -log10(0.00608) ≈ 2.22

pH = 14

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It would require approximately 6 half-lives for the amount of a radioactive isotope to decrease to 3.13% of its original value.

To determine the number of half-lives required for a radioactive isotope to decrease to 3.13% of its original value, we can use the equation:

Final amount = Initial amount * (1/2\()^(number of half-lives)\)

We want the final amount to be 3.13% of the initial amount, which can be expressed as 0.0313 times the initial amount.

0.0313 = 1 * (1/2\()^(number of half-lives)\)

To solve for the number of half-lives, we can take the logarithm (base 1/2) of both sides:

log(0.0313) = log((1/2\()^(number of half-lives)\))

Using logarithmic properties, we can rewrite the equation as:

log(0.0313) = (number of half-lives) * log(1/2)

We can now solve for the number of half-lives:

number of half-lives = log(0.0313) / log(1/2)

Calculating this expression, we find:

number of half-lives ≈ 5.141

Since the number of half-lives must be a whole number, we round up to the nearest whole number.

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Answer:

all of the above

Explanation:

Answer:

An organism that eats another organism is called a consumer

Answer:

Explanation:

A physical change can't reverse a chemical change. This is because a chemical change results in a new substance being formed. Chemical bonds are broken and and new bonds are formed between different atoms. Another chemical change would be needed to break the new bonds and reform the original bonds.

A covalent bond is the exact number of bonded pairs of electrons in a compound

One electron is added by each atom to a pair of shared electrons in a single bond. While double bonds share only one pair of electrons, triple bonds share three pairs. Bonds with multiple covalent bonds exchange several electron pairs

Covalent bonding happens when atoms share electron pairs. Atoms join together through covalent bonds to form a full electron shell, which boosts stability. By sharing their outermost (valence) electrons, atoms can fill out their outer electron shell and become stable. Nonmetals will swiftly create covalent bonds with other nonmetals in order to achieve stability.

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The noble gas with an atomic mass less than gold, but more than silver, is platinum. Noble gases are found in small amount in earth atmosphere.

The noble gases are a group of chemical elements that share several characteristics. They are all monatomic, odorless, and colorless gases with relatively little chemical reactivity under normal conditions. Helium, neon, argon, krypton, xenon, and radioactive radon are the six types of noble gases that are found in nature.

These gases don't receive, lose, or share electrons, making them inert or unreactive. They are also referred to as noble gases due to their rarity in the atmosphere of the earth.

Thus, The noble gas with an atomic mass less than gold, but more than silver, is platinum.

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chemical that appears as a colorless liquid, is used in a wide range of cleaning and personal care products, including hair dyes and bleaches, toothpaste and mouthwashes, bathroom cleaners and laundry stain removers. Hydrogen peroxide can also be found in over-the-counter first aid antiseptics, and it is used as a bleaching agent in some food products. It has other consumer and industrial uses as well, including water treatment.

Share:

Answer:

c

Explanation:

A hydrocarbon consists of only carbon and hydrogen atoms. Combustion occurs when a hydrocarbon reacts with oxygen to form carbon dioxide and water molecules.

Answer:

The answer is A

Explanation:

If kingsley adds 46.14 ml of NaOH to 250.00 ml of the HCOOH solution. the neutralization reaction resulted in 0.083 moles of HCOOH and 0.037 moles of\(HCOO^-\) left in solution The pH of the resulting solution is 2.21.

The balanced chemical equation for the neutralization reaction between HCOOH (formic acid) and NaOH (sodium hydroxide) is:

HCOOH + NaOH → NaCOOH + \(H_2O\)

From the balanced equation, we can see that 1 mole of HCOOH reacts with 1 mole of NaOH to produce 1 mole of NaCOOH and 1 mole of water.

First, we need to calculate the amount of HCOOH that reacted with NaOH:

0.083 moles HCOOH - 0.037 moles \(HCOO^-\) = 0.046 moles HCOOH

This is the amount of HCOOH that reacted with the 46.14 ml of NaOH added. We need to convert the volume of NaOH to moles using its molarity:

Molarity of NaOH = moles of NaOH / volume of NaOH (in liters)

Assuming the molarity of NaOH is 1.00 M (which is a common concentration for laboratory use), we have:

1.00 M = moles of NaOH / 0.04614 L

moles of NaOH = 0.04614 L × 1.00 M = 0.04614 moles

Since the reaction between HCOOH and NaOH is a 1:1 reaction, the number of moles of HCOOH left in solution is:

0.083 - 0.04614 = 0.03686 moles

To calculate the concentration of HCOOH, we divide the number of moles by the total volume of the solution:

0.03686 moles / 0.25000 L = 0.14744 M

Next, we need to calculate the concentration of HCOO-:

0.037 moles / 0.25000 L = 0.148 M

Since HCOOH is a weak acid, it partially dissociates in water to form \(H^+\) and \(HCOO^-\) ions. The equilibrium constant for this reaction is:

\(Ka = [H^+][HCOO^-] / [HCOOH]\)

We can assume that the concentration of \(H^+\) ions is equal to the concentration of \(HCOO^-\) ions, since HCOOH is a weak acid and does not dissociate much. We can also assume that the concentration of \(HCOO^-\) is equal to the amount of \(HCOO^-\) left in solution (0.037 moles / 0.25000 L = 0.148 M).

Therefore, we can simplify the expression for Ka to:

\(Ka = [HCOO^-]^2 / [HCOOH]\)

Solving for [H+]:

\([H^+] = \sqrt{(Ka * [HCOOH] / [HCOO^-])}\)

The Ka value for formic acid is \(1.8 * 10^{-4\). Substituting the values:

\([H^+] = \sqrt{(1.8 * 10^{-4} * 0.14744 M / 0.148 M)} = 0.00618 M\)

Taking the negative logarithm of [H+] gives us the pH of the solution:

\(pH = -log[H^+] = -log(0.00618) = 2.21\)

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The mass of oxygen gas produced, given that 15.8 g of potassium permanganate is heated until no more oxygen gas is given off is 1.6 g

From the question given, the following data were obtained:

The mass of oxygen gas produced from the reaction can be obtained as follow:

Mass of potassium permanganate = Mass of remaining substance + mass of oxygen

Inputting the given parameters, we have:

15.8 = 14.2 + mass of oxygen

Collect like terms,

Mass of oxygen = 15.8 - 14.2

= 1.6 g

Thus, we can conclude that the mass of oxygen gas produced from the reaction is 1.6 g

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The Roman numeral in the manganese (IV) sulfide indicates : the positive charge on the manganese ion. The correct option is B.

The Manganese (IV) sulfide, chemical formula = Mn₂S₄ In the compound Manganese (IV) sulfide, the manganese (IV) contains the positively charged cation and the sulfide contains the negatively charged anion. The name of the manganese (IV) sulfide is that each of the manganese atom has the charge of +4.

Manganese = Mn⁴⁺

Sulfide = S²⁻

The chemical formula for the Manganese (IV) sulfide = Mn₂S₄. The  Roman numeral in manganese (IV) sulfide shows the positive charge on the manganese ion.

Therefore, the correct option is B.

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Answer:

A simulation is an imitation. Simulations are helpful to scientists because they allow scientists to study occurrences more closely.

Explanation:

Explanation:

A simulation is a way of imitating a process or change in the real world to predict what will happen or explain what did happen and why, these days simulations are often run on computer,scientists use simulations to answer questions see how complex system works test ideas and make predictions, hope it helps^^

btw I'm no expert, I did research^^

Answer:

Alchohol, Disenfective wipes, Bleach, Soap,

Explanation:

Answer:

1375 J/kg.°C

Explanation:

From the question First question,

Q = cm(Δt)................... Equation 1

Where Q = Heat released, c = specific heat capacity of the unknown metal, m = mass of the unknown metal, Δt = Change in temperature.

make c the subject of the equation

c = Q/mΔt.................. Equation 2

Given: Q = -5500 J (Since heat is released, Q is negative), m = 200 g = 0.2 kg, Δt = 10-30 = -20°C

Substitite these values into equation 2

c = -5500/[0.2×(-20)]

c = -5500/-4

c = 1375 J/kg.°C

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The considerations that should be taken when the choosing solvents for the recrystallization is the desired compound should be the significantly more soluble in one solvent than the other.

The Recrystallization is the process to purify the chemicals in the chemistry. We will mix the compound with impurity then we will purify it again by the using recrystallization method. So. the normal procedure is that to dissolve the substance that is to be purified in the suitable solvent, at the very high temperature, to form the almost saturated solution.

In the recrystallization, the solution is created by the dissolving the solute in the solvent at or the near its boiling point.

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The nuclear product of radioactive decay is called the daughter nuclide.

True

Radioactivity is a phenomenon in which particles such as alpha, beta and gamma rays are emitted from unstable atomic nuclei. This is due to the fact that the nucleus is unstable and requires a rearrangement of its protons and neutrons. Radioactive isotopes can be found in nature, or they can be artificially created. Radioactivity has many useful applications, such as medical imaging, cancer treatments, smoke detectors, and nuclear energy. It also has some potential dangers, such as radiation exposure and the risk of nuclear disasters.

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Answer:

D

Explanation:

The difference between a reflected and diffracted sound wave is:

A. A reflected sound wave changes direction as it passes through an opening, whereas a diffracted sound wave bounces back to the place of origin.

Reflection occurs when a sound wave hits a surface and bounces back in the opposite direction. When a sound wave is reflected, it changes direction but does not necessarily change its wavelength or frequency. This is why we can hear echoes in a room with reflective surfaces.

Diffraction, on the other hand, occurs when a sound wave passes through an opening or around an obstacle and changes direction. When a sound wave is diffracted, it spreads out and changes its wavelength and frequency. This is why we can hear sound around corners or through a partially open door.

Therefore, option D is the correct answer: A reflected sound wave bounces back to the place of origin, a diffracted sound wave changes direction as it passes through an opening.