two strings both vibrate at exactly 819 hz. the tension in one of them is then increased slightly. as a result, six beats per second are heard when both strings vibrate. what is the new frequency of the string that was tightened? a) 825 hz b) 816 hz c) 813 hz d) 822 hz studydoc

The Doppler shift approaches 0 as the listener's speed approaches the speed of sound.

In part f of the question, when the source is stationary and the listener is moving towards the source at the speed of sound, the formula for the Doppler shift becomes:

\(fl = fsv + vlv + vs\)

Since the source is stationary (vs = 0) and the listener's speed (vl) approaches the speed of sound (v), the term vlv approaches v². Therefore, the Doppler shift frequency (fl) approaches 0 as the listener's speed approaches the speed of sound.

Hence, the answer to part f is a) 0.

In part g, when the listener is stationary and the source is moving towards the listener at the speed of sound, the formula for the Doppler shift remains the same:

\(fl = fsv + vlv + vs\)

In this case, since the listener is stationary (vl = 0) and the source is moving towards the listener at the speed of sound (vs = v), the term vsv becomes v². Therefore, the Doppler shift frequency (fl) will be twice the emitted frequency (2fs) when the sound waves reach the listener.

Hence, the answer to part g is c) 2fs.

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Answer: Fn = 450 N

Explanation:

Part of the tension acts in the upward y-direction, reducing the normal force.

ΣFy = Fn + Ftsin(30)-Fg

0 = Fn + (300 N)sin(30) - (60 kg)(10 m/s^2)

0 = Fn + 150 N - 600 N

0 = Fn - 450 N

Fn = 450 N

The logic gate in figure 5.88a is NAND gate. When two inputs are joined together it will act as a NOT gate. This is shown  in figure 5.88b.

A truth table is a table that shows the output of a logic gate for all possible combinations of its input values.

a. Truth table of NAND gate is:

A B Output

0 0 1

0 1 1

1 0 1

1 1 0

b. When one input each is given to two different NOT gates and these two gates are connected to an AND gate, a NOT gate is formed.

This is the truth table for these gates:

A B ~A ~B ~A AND ~B

0 0  1   1       1

0 1  1   0       0

1 0  0   1       0

1 1  0   0       0

As you can see from the truth table, the output of the AND gate is 1 (logic high) only when both inputs to the NOT gates are 0 (logic low). In all other cases, the output of the AND gate is 0 (logic low). Therefore, the output of the entire circuit is the negation of the input A. This is the behavior of a NOT gate.

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The image of the question is attached.

Explanation:

For 787 dreamliner airplane,

Mass, \(m_1=2450\ kg\)

Height, \(h_1=11500\ m\)

Potential energy of 787 dreamliner airplane is given by :

\(E_1=m_1gh_1\\\\E_1=2450\times 9.8\times 11500\\\\E_1=2.76\times 10^8\ J\)

For a boeing 747,

Mass, \(m_2=3150\ kg\)

Height, \(h_2=9000 \ m\)

:

Potential energy of a boeing 747 airplane is given by

\(E_2=m_2gh_2\\\\E_2=3150\times 9.8\times 9000\\\\E_2=2.77\times 10^8\ J\)

So, the potential energy of a boeing 747 airplane is more than the 787 dreamliner airplane.

Answer:

Water droplets could obtain charges thru contact with other drops.

Then if two similar drops (both positively charged) came in contact

charge could be transferred because one side of the drop would be positive and one side of the other would be negative by induction.

Several Physics Labs have built experiments called "Kelvins Thunderstorm"

where objects found in the home could be used to build a charge generator that can generate several thousand volts from falling water droplets.

Lightning usually occurs because of the very large potential that can build

because of charge differences between overhead clouds and the induced charge that will then follow in the ground. Mountain climbers know that it's time to look for safer ground when sparks start to jump from the ropes.

The height of the image will be 0.32 cm and 0.3328 cm, respectively, and the image will be inverted in both cases.

To answer this question, we need to use the thin lens equation, which relates the distance of an object from a lens to the distance of its image from the lens and the focal length of the lens. The equation is:

1/f = 1/d_o + 1/d_i

where f is the focal length, d_o is the distance of the object from the lens, and d_i is the distance of the image from the lens.

First, let's find the size of the image of the candle flame on the wall without the lens. We can use similar triangles to find that the height of the image is:

h_i = h_o * (d_i / d_o)

where h_o is the height of the object (the candle flame), which is 2.0 cm, and d_i is the distance of the image from the wall, which is 2.0 m. The distance of the object from the wall is the same as the distance of the image from the wall, so d_o = 2.0 m. Plugging in these values, we get:

h_i = 2.0 cm * (2.0 m / 2.0 m) = 2.0 cm

So the image of the candle flame on the wall without the lens is also 2.0 cm tall.

Now, let's consider the lens. We want to find the places where we can put the lens to form a well-focused image of the candle flame on the wall. A well-focused image is one where the image is sharp and clear, and the height and orientation of the image are similar to the object.

To find the places where we can put the lens to form a well-focused image, we need to solve the thin lens equation for d_i for various values of d_o, which will give us the distances of the image from the lens for different positions of the lens. We can then use the equation for the height of the image to find the height and orientation of the image for each position of the lens.

Let's start by solving the thin lens equation for d_i when d_o = infinity. This corresponds to the case where the lens is very far away from the candle flame, so we can treat the light rays from the candle flame as parallel. The thin lens equation becomes:

1/f = 1/d_i

Solving for d_i, we get:

d_i = f

Plugging in f = 32 cm, we get:

d_i = 32 cm

This means that if we place the lens 32 cm away from the candle flame, we will get a well-focused image of the candle flame on the wall. The distance of the image from the lens will be the same as the focal length of the lens, which is 32 cm. The height of the image will be:

h_i = h_o * (d_i / d_o) = 2.0 cm * (32 cm / 200 cm) = 0.32 cm

So the image will be much smaller than the object, and it will be inverted (upside down) because the object is closer to the lens than the focal point.

Now, let's solve the thin lens equation for d_i when d_o = 2.0 m. This corresponds to the case where the lens is right next to the candle flame, so the light rays from the candle flame are converging toward the lens. The thin lens equation becomes:

1/f = 1/d_o + 1/d_i

Plugging in f = 32 cm, d_o = 2.0 m, and solving for d_i, we get:

d_i = 33.28 cm

This means that if we place the lens 33.28 cm away from the candle flame, we will get a well-focused image of the candle flame on the wall. The height of the image will be:

h_i = h_o * (d_i / d_o) = 2.0 cm * (33.28 cm / 200 cm) = 0.3328 cm

So the image will be slightly smaller than the object, and it will be inverted (upside down) because the object is closer to the lens than the focal point.

We can put the lens in two places to form a well-focused image of the candle flame on the wall: 32 cm away from the candle flame, and 33.28 cm away from the candle flame. The height of the image will be 0.32 cm and 0.3328 cm, respectively, and the image will be inverted in both cases.

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The index of refraction of air, which is approximately 1.000: n_(2) = (1.000 × sin(45.0°)) / sin(17.0°). This expression will give us the index of refraction of the diamond.

To calculate the index of refraction of the diamond, we can use Snell's law, which relates the angles of incidence and refraction to the indices of refraction of the two media involved. Snell's law can be expressed as follows:

n1 × sin(θ_(1)) = n2 × sin(θ_(2))

where:

n_(1) is the index of refraction of the initial medium (in this case, air),

θ_(1) is the angle of incidence,

n_(2) is the index of refraction of the second medium (in this case, diamond),

θ_(2) is the angle of refraction.

We can rearrange the equation to solve for the index of refraction of the diamond, n_(2):

n_(2) = (n_(1) × sin(θ_(1))) / sin(θ_(2))

Given that the angle of incidence θ_(1) is 45.0° and the angle of refraction θ_(2) is 17.0°, we can substitute these values into the equation along with the index of refraction of air, which is approximately 1.000:

n_(2) = (1.000 × sin(45.0°)) / sin(17.0°)

This expression will give us the index of refraction of the diamond.

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Answer:

The greater the density of a medium, the slower the speed of sound. This observation is analogous to the fact that the frequency of a simple harmonic motion is inversely proportional to m, the mass of the oscillating object.

Air molecules have more energy at higher temperatures, which means they vibrate faster. This allows the sound waves to also travel faster because they are propelled by collisions between the molecules

Answer:

Total time of moving at constant velocity = 50 seconds ( at C, E and G)

Answer: First, work out the difference (decrease) between the two numbers you are comparing. Next, divide the decrease by the original number and multiply the answer by 100. If the answer is a negative number, this is a percentage increase.

this is filled just send it to your teacher but change name and date

True. Certain types of pollution in the atmosphere, such as aerosols and particulate matter, can reflect and scatter incoming solar radiation, leading to a cooling effect on the Earth's surface.

This phenomenon is known as global dimming. However, it is important to note that while these pollutants may have a short-term cooling effect, they also have detrimental long-term effects on human health and the environment.

Additionally, the cooling effect of pollution does not offset the overall warming caused by greenhouse gas emissions.

Therefore, it is essential to address both pollution and greenhouse gas emissions in order to mitigate the impacts of climate change.

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The beat frequency they produce is 7 Hz.

When two waves of slightly different frequencies are sounded together, beats are produced at the difference of their frequencies. This difference in frequency is called the beat frequency. It is denoted by Δf. A car has two horns, one emitting a frequency of 198 Hz and the other emitting a frequency of 205 Hz.

The beat frequency is calculated by subtracting the lower frequency from the higher frequency. Here, the lower frequency is 198 Hz and the higher frequency is 205 Hz.

Thus, the beat frequency produced by the car's two horns is:205 Hz - 198 Hz = 7 Hz.

Therefore, the beat frequency is 7 Hz.

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Answer:

All forms of energy are either kinetic or potential. The energy associated with motion is called kinetic energy . The energy associated with position is called potential energy . Potential energy is not "stored energy".

Explanation:

The estimated age of the solar system is 4558 million years,

with N = 4.558.

The exponent n is a number that represents the power to which the base number is raised.

The exponential function is represented as xn, where x is the base and n is the exponent.

The question seeks to determine the value of n given N and the estimated age of the solar system.

The formula for calculating the value of n is:

N = 10n
Taking the logarithm of both sides, we get:
log(N) = log(10n)
Using the rule of logarithm, log(a^b) = b log(a), we can rewrite the equation as:
log(N) = n log(10)

Since log(10) = 1, we have:
n = log(N)

Substituting N with the estimated age of the solar system, we get:
n = log(4.558)

Using a calculator, we find that log(4.558) is approximately 0.6609.

the value of the exponent, n, is approximately 0.6609.

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The SI base units are the standard units of measurement defined by the International System held in France is called Si unit.

The particular solution to the given differential equation is y(x) = -3x^2 + 17x - 15.

We are given the differential equation 6y′′ + 9y′ = 17 - 32x. We need to find a particular solution to this equation.

First, we find the homogeneous solution to the differential equation by solving the characteristic equation:

6r^2 + 9r = 0

r(2r + 3) = 0

r = 0, -3/2

So, the homogeneous solution is yh(x) = c1 + c2e^(-3/2x), where c1 and c2 are arbitrary constants.

Next, we need to find a particular solution to the nonhomogeneous equation. We guess a solution of the form yp(x) = Ax + B. Substituting this into the differential equation, we get:

-9A + 6 = 17 - 32x

Solving for A and B, we get A = -3 and B = -15.

Therefore, the particular solution is yp(x) = -3x - 15.

The general solution is y(x) = yh(x) + yp(x) = c1 + c2e^(-3/2x) - 3x - 15.

Applying initial conditions can help us find the values of the constants c1 and c2, if given.

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The type of energy transfer that occurs in the atmosphere due to moving air molecules (wind) bumping into objects and moving vertically in the atmosphere is kinetic energy transfer. Kinetic energy is the energy of motion and is transferred from one object to another when they collide.

In the case of wind, the air molecules have kinetic energy due to their motion. As they collide with objects such as trees, buildings, or mountains, some of this kinetic energy is transferred to the objects, causing them to move. When the air molecules move vertically in the atmosphere, they can transfer kinetic energy to the air molecules above or below them, causing them to move as well.

This transfer of kinetic energy from the air molecules to objects or other air molecules is the reason for the movement and turbulence observed in the atmosphere. It is also the basis for many atmospheric phenomena such as thunderstorms, hurricanes, and tornadoes, where the transfer of kinetic energy between the air molecules can lead to the formation of intense vortices and turbulent flows.

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It is true that the incident angle is the angle formed between the barrier and the direction of wave propagation.

Wave propagation refer to the processes and different ways waves travels from one medium to another and transferring energy.

Therefore, is true that the incident angle is the angle formed between the barrier and the direction of wave propagation.

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Answer:

13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

Given n₂ = 4/3:

1 = 4/3 sin θ

sin θ = 3/4

If x is the radius of the circle, then sin θ is:

sin θ = x / √(x² + 12²)

sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

9/16 x² + 81 = x²

81 = 7/16 x²

x ≈ 13.6

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

This is defined as  sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

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The comparison between the distance traveled by the bullet compared with the distance traveled by the rifle at the same time shows that the bullet travels faster than the rifle due to greater acceleration.

Newtown's third law of motion states that for every action there is a reaction having equal magnitude but opposite direction.

In the case of bullet and rifle, both experience the same amount of force that is equal in magnitude but opposite in direction.

In physics, mass and acceleration have an indirect relation with each other i.e a = F/m. More mass means less acceleration and vice versa.

A rifle has a smaller amount of acceleration than a bullet. It is because the mass of the rifle is greater than the bullet therefore it covers less distance a s compare to a bullet having less mass and greater acceleration and thus travels faster.

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Answer:

Explanation:required formula is

W 1=F*S

W1=work done by Sam =?

F=force applied by sam=150N

S=displacement =10m

again

W2=F*S

W2=work done by friction =?

S=displacement =10m

F=friction =25N

W=W1-W2=net work done

please feel free to ask if you have any questions

The mass of the rock is approximately 86.304 tons.

To convert the mass of the rock from grams to tons, we can use the conversion factor that 1 ton is equal to 907.2 kilograms.

Mass of the rock = 7.84 x 10^7 grams

To convert grams to kilograms, we divide by 1000:

Mass in kilograms = (7.84 x 10^7 grams) / 1000 = 7.84 x 10^4 kilograms

Now, to convert kilograms to tons, we divide by 907.2:

Mass in tons = (7.84 x 10^4 kilograms) / 907.2 = 86.304 tons

Therefore, the mass of the rock is approximately 86.304 tons.

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Answer:

10

Explanation:

Amu denotes for unified atomic mass.

it is mostly used to define the atom's mass and molecules.

we know that

One unit of amu is 1 ÷ 12 of the mass of a nuclide 12C

And 1 u = 1.660 538 921 × 10-27 kg

In the inside we can found that there is 10 nucleons so here the alss of the atoms would be 10 amu  

Answer:

guy above me is right

Explanation:

Answer:

s = 37.81 m

Explanation:

Given that,

Mass of an apple, m = 1.5 kg

The apple falls for 2.75s before striking the ground.

We need to find how far the apple dropped before hitting the ground. It means we need to find the distance covered. Using the second equation of motion to find it :

\(s=ut+\dfrac{1}{2}gt^2\)

u is initial velocity, u = 0 (at rest)

\(s=\dfrac{1}{2}gt^2\\\\s=\dfrac{1}{2}\times 10\times (2.75)^2\\\\=37.81\ m\)

So, Apple dropped 37.81 m before hitting the ground.

Answer:

The lightning struck 1,360 meters away

Explanation:

1. List knowns

Speed of sound = 340 m/s

Time = 4 s

2. Find formula that uses above knowns

Speed = Distance / Time

Distance = Time x Speed

3. Substitute

Distance = 4 s x 340 m/s

Distance = 1360 meters