When the same force is applied to stretch two springs, their elongation or stretching distance will be dependent on their force constants option (a) is the correct answer.
The force constant is a measure of the stiffness of a spring, and it relates the force applied to the elongation of the spring. In this case, since the force constants of the two springs are different, they will respond differently to the same force applied.
Spring 2 has a higher force constant compared to spring 1, meaning that it is stiffer and requires more force to stretch it to a certain distance. Therefore, when the same force is applied to stretch both springs, spring 1 will be stretched farther than spring 2 since it is less stiff and requires less force to reach the same elongation distance. This means that option (a) is the correct answer.
It is important to note that the elongation of a spring is proportional to the force applied to it. Therefore, the force required to stretch spring 2 to the same distance as spring 1 will be greater than the force required to stretch spring 1. Hence, spring 2 will be stretched less than spring 1 when the same force is applied. Therefore, option (b) is not correct, and option (c) is also incorrect as both springs will not be stretched the same distance.
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What changes do you observe in the moon over the course of one
month?
iceland's position on the graph is due in part to its access to geothermal energy sources. describe how electricity is generated form geothermal source
Electricity is generated from geothermal sources in Iceland by utilizing geothermal power plants. These plants harness the natural heat from the Earth's core to produce electricity.
Geothermal power plants in Iceland tap into the country's abundant geothermal reservoirs by drilling deep into the ground to access hot water and steam. The high-pressure steam is directed towards a turbine, causing it to spin and activate a generator that produces electricity. The used steam is then condensed back into water and reinjected into the ground to maintain the geothermal reservoir's sustainability. Iceland's unique geological location and geothermal activity provide it with a reliable and sustainable source of electricity. The country's access to geothermal energy has played a significant role in positioning Iceland on the graph as a leader in renewable energy production. It has enabled Iceland to generate a substantial portion of its electricity from renewable sources, reducing reliance on fossil fuels and contributing to a cleaner and more sustainable energy sector.
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Calculate the period of oscillation of a pendulum with a small amplitude whose length is 2.5 meters
Answer:
T = 3.17 s
Explanation:
Given that,
The length of the pendulum, l = 2.5 m
We know that the period of oscillation of the pendulum is given by :
\(T=2\pi \sqrt{\dfrac{l}{g}}\)
Where
g is the acceleration due to gravity
\(T=2\pi \sqrt{\dfrac{2.5}{9.8}}\\\\T=3.17\ s\)
So, the period of oscillation is equal to 3.17 s.
Whispering Gallery: A hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the center, how high will the ceiling be at the center?
The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.
In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.
Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.
The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.
Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.
To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:
b = √(a² - c²)
where c represents the distance from the center to each focus. In this case, c = 25 feet.
Substituting the values into the formula:
b = √(50² - 25²)
b = √(2500 - 625)
b = √(1875)
b = 43.3 feet
Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.
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Question 18 of 25 What is the current model of the atom called? O A. Electron cloud model B. Plum pudding model OC. Planetary model O D. Nuclear model
The current model of the atom is called the electron cloud model or the quantum mechanical mode.
Current model of an atom explained.The current model of the atom is called the electron cloud model or the quantum mechanical model. This model describes electrons as existing in a three-dimensional region around the nucleus called the electron cloud, where the electrons are most likely to be found at any given time. This model incorporates principles of quantum mechanics, which recognizes the wave-particle duality of electrons and the probabilistic nature of their behavior, in contrast to the earlier classical models like the planetary model or the plum pudding model.
Therefore, the nuclear model, which describes the atom as consisting of a central nucleus surrounded by electrons, is a precursor to the modern quantum mechanical model.
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A soapbox derby race car starts at rest at the top of a track that has a vertical drop of 15 m. The car is to be stopped at the end of the track by colliding with and compressing a spring. In order to avoid injury to the driver, the spring must be compressed to 3.0 m before the car stops. What should be the force constant of this spring
In order to avoid injury to driver, The force constant of this spring should be 73.82 N/m
Calculation of force constant to this spring:
Here
vertical drop is 15 m.
mass of the car, m= 113 kg
gravitational acceleration, g= -9.8 m/s^2
spring compression before car stops, x= 3.0 m
In order to avoid injury to the driver,
we need to use Hooke's law and Newton's second law:
F(net) = F(x)
m*a=-k*x
here a=g
k= -(m*g) / x
here k is force constant of this spring
substituting the values we get,
k = -(113* -9.8) / (15)
k = 73.8266 N/m
Hence, the force constant of this spring should be 73.82 N/m
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A 980-kg sports car collided into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.6 m before stopping. The police officer, estimating the coefficient of kinetic friction between tired and the road to be 0.80, calculates the speed of the sports car at impact. What was that speed?
The speed of the sports car at impact was 15 m/s.
To solve this problem, we can use the conservation of momentum and the work-energy principle. The momentum of the system of the two cars before the collision is zero since the SUV is at rest.
After the collision, the two cars move forward together as a single system and come to a stop, so the momentum of the system is also zero.
By conservation of momentum, the momentum of the sports car before the collision is equal in magnitude to the momentum of the two cars after the collision:
m_sports_car * v_sports_car = (m_sports_car + m_SUV) * 0
where m_sports_car and m_SUV are the masses of the sports car and SUV, respectively, and v_sports_car is the speed of the sports car before the collision.
Solving for v_sports_car, we get:
v_sports_car = 0 kg*m/s / 980 kg + 2300 kg = 0 m/s
This tells us that the two cars came to a complete stop after the collision. However, we also know that the cars skidded forward before stopping.
Using the work-energy principle, we can calculate the initial kinetic energy of the system and equate it to the work done by the frictional force in stopping the system:
1/2 * (m_sports_car + m_SUV) * v² = F_friction * d
where F_friction is the frictional force, d is the distance the cars skid, and v is the speed of the sports car before the collision.
Solving for v, we get:
v = sqrt(2 * F_friction * d / (m_sports_car + m_SUV))
We are given the coefficient of kinetic friction between the tires and the road, which allows us to calculate the frictional force:
F_friction = friction_coefficient * (m_sports_car + m_SUV) * g
where g is the acceleration due to gravity.
Plugging in the values and solving, we get:
v = sqrt(2 * 0.80 * (980 kg + 2300 kg) * 9.81 m/s² * 2.6 m / (980 kg + 2300 kg))
v ≈ 15 m/s
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Your car battery is a 12 V DC source. Typically you might find a fuse that can handle a 5 amp surge. What resistance is that fuse protecting?
Answer:
2.4 ohms
Explanation:
From the question,
Applying ohm's law,
V = IR.................... Equation 1
Where V = Voltage of the car battery, I = current, R = resistance
Make R the subject of the equation
R = V/I.................. Equation 2
Given: V = 12 V, I = 5 amp.
Substitute these values into equation 2
R = 12/5
R = 2.4 ohms
during any process, the net electric charge of an isolated system does not change.T/F
Yes ,the net electric charge of an isolated system does not change.
A quality of matter known as a charge causes it to produce and experience electrical and magnetic phenomena. The fundamental tenet of charge conservation is that the system's overall charge is conserved.
As we all know, a system is a collection of things, and the interactions between charges and energy and momentum are comparable. However, this conservation rule makes more sense because an object's net charge depends on the quantity of electrons and protons present. Protons and electrons cannot suddenly arrive or vanish, and the overall charge must remain constant. This explains why a body always contains the same number of protons and electrons.
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Describe two ways that forces and motion are at work as you make the trip from your house to school.
Explanation:
Motion is just movement needing a force to act upon it. Pushing and pulling are examples of forces that can sped things up or slow things down. All a force ever does is change the motion or speed of the object it is applied to.
Your movement from your house to home is caused by some Forces that is causing to move. As without force there is no motion. These forces can either of push type or pull type.
a steel piano wire, of length 1.250 m and mass 5.00 g is stretched under a tension of 650.0 n. what is the speed of transverse waves on the wire?
The speed of transverse waves on the steel piano wire is approximately 403.12 m/s.
To find the speed of transverse waves on the steel piano wire, we can use the equation v = √(T/μ), where v is the speed of the wave, T is the tension, and μ is the linear mass density.
The linear mass density (μ) can be calculated by dividing the mass of the wire (5.00 g) by its length (1.250 m).
μ = mass/length = 5.00 g / 1.250 m = 4.00 g/m = 0.00400 kg/m.
Now, we can substitute the values into the equation v = √(T/μ):
v = √(650.0 N / 0.00400 kg/m) = √(162500 N/kg) = 403.12 m/s.
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the temperature of a heat engine is 500 k. some of the heat generated by the engine flows to the surroundings, which are at a temperature of 125 k.
Answer:
75%
Explanation:
if light with a 180 nm n m wavelength is absorbed by the surface, what is the velocity of the emitted electrons?
When light with a 180 nm wavelength is absorbed by the surface, the velocity of the emitted electrons is determined by the kinetic energy and momentum of the emitted electrons.
The photoelectric effect refers to the phenomenon in which the emission of electrons occurs from a metal surface when it is exposed to light. The electrons that are released in this process are referred to as photoelectrons.
According to the photoelectric effect equation, the kinetic energy of the photoelectrons (KE) is determined by the following equation:
KE = hf - Φ where h is Planck's constant, f is the frequency of the incident light, and Φ is the work function of the metal surface.
According to the photoelectric effect, the kinetic energy of the emitted electrons (KE) is given by the following equation:
KE = 1/2mv² where m is the mass of the electron and v is its velocity.
. The momentum of the emitted electrons is given by the following equation: p = mv where p is the momentum of the emitted electrons. Therefore, the velocity of the emitted electrons is given by the following equation: v = p/m. Thus, the velocity of the emitted electrons is determined by the kinetic energy and momentum of the emitted electrons.
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The complete question is :
The work function of palladium is 5.22 eV
a) What is the minimum frequency of light required to observe the photoelectric effect on Pd? ν = 1.26×\(10^{15} s^{-1}\)
b) If light with a 180 nm wavelength is absorbed by the surface, what is the velocity of the emitted electrons? Express your answer with the appropriate units
How many Watts of power does a model rocket engine have if it does 66 J of work on a model rocket in 0.9 seconds?
Power developed by a model rocket engine will be 73.3 watts. Power is the ratio of the work done or the enrgy to the time period.
What is the power output?The rate of the work done is called the power output. It is denoted by P.Its unit of a watt.
The given data in the problem is;
E is the energy = 66 J
P is the power output =?
t is the time period = 0.9 sec
The power output is given as;
\(\rm P = \frac{E}{t} \\\\ \rm P = \frac{66}{0.9} \\\\ \rm P = 73.3 \ watt\)
Hence power developed by a model rocket engine will be 73.3 watts.
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Alkaline earth metals have a low density
true
false
true
Explanation:
this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons
Help please!!! In what two ways does deforestation contribute to air pollution?
Answer: Deforestation fires, Lowers the amount of oxygen in the atmosphere.
Explanation:
In a lot of places they will cut down trees with heavy machinery which produce a lot of gases such as Carbon Monoxide, now in little scale thats okay. However many places do it to such a scale that there is almost 200 forest fires a day. Each fire lowers the amount of trees but increases air pollution.
While traveling along a highway a driver slows from 48 m/s to 30 m/s in 12 seconds. What is the automobile’s acceleration?
Answer:
-1.5 m/s^2
Explanation:
Acceleration is Final velocity - Initial Velocity/Time (seconds)
30-48= -18
-18/12 = -1.5
-1.5 m/s^2
PLEASE HELP!!!!! 30 POINTS!!!!! I HAVE NO IDEA HOW TO DO THIS!!
Match these items and the phrases with which they are associated.
1. upward force of a liquid on an object
2. H 2 O
3. basic unit of matter
4. amount of matter in an object
5. n = 1
6. l × w × h
7. drew first picture of atom
8. mass/volume
mass,
atom,
water,
buoyancy,
inner shell,
volume,
density,
Neils Bohr,
concrete
how is an unmagnetized piece of iron different from the same piece of iron when it is magnetized?
An unmagnetized piece of iron differs from a magnetized piece of iron primarily in their internal structure and magnetic properties. In an unmagnetized iron, the individual magnetic domains are randomly oriented, which means that their magnetic fields cancel each other out, resulting in no net magnetic field.
On the other hand, when the iron becomes magnetized, the magnetic domains align in the same direction, thereby creating a net magnetic field. This process is typically achieved through the application of an external magnetic field or by placing the iron piece in close proximity to a strong magnet. The alignment of the magnetic domains causes the magnetized iron to exhibit magnetic properties, such as attracting or repelling other magnetic materials and generating a magnetic field.
In terms of practical applications, magnetized iron can be used in a variety of devices, such as electromagnets, transformers, and magnetic storage media. Unmagnetized iron, while not possessing these magnetic properties, still retains its inherent characteristics, like strength and ductility, making it suitable for structural and engineering purposes.
In summary, the main difference between an unmagnetized and magnetized piece of iron lies in the orientation of their magnetic domains and the resulting presence or absence of a net magnetic field. This difference gives rise to distinct magnetic properties, which ultimately determine their specific applications in various industries.
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On a red pine lumber beam with span of 3.2 m, the standard value of the permanent uniform load (including self-weight) is 4.1 kN/m, and the standard value of the variable uniform load is 1.0 kN/m. The safety level is grade 2, and the design life is 50 years. Select the section size of the beam.
TC13B, f=13N/mm², f, = 1.4 N/mm², E = 9000 N/mm²
the appropriate section size for the red pine lumber beam with the safety level is grade 2, and the design life is 50 years is 150 mm × 5.44 mm.
Determine the characteristic load:The characteristic load is the permanent uniform load (including self-weight) plus the variable uniform load.
Given ,
the permanent uniform load is 4.1 kN/m
the variable uniform load is 1.0 kN/m
the characteristic load is (4.1 + 1.0) kN/m = 5.1 kN/m.
Calculate the design load:The design load is determined by multiplying the characteristic load by the partial safety factor for loads.
In this case,
the safety level is grade 2
the partial safety factor for loads (γ_f) is 1.4.
the design load is 5.1 kN/m × 1.4 = 7.14 kN/m.
Determine the maximum bending moment:The maximum bending moment occurs at the mid-span of the beam and is given by the equation:
M = (wL^2)/8, where ,
w is the design load
L is the span of the beam
M = (7.14 kN/m × (3.2 m)^2)/8 = 9.14 kNm.
Select an appropriate section size,use the formula: M = (bh^2)/6,
where,
b is the width of the section
h is the height of the section
(b × h^2) = (6 × 9.14 kNm)/(13 N/mm²) = 4.446 kNm/mm².
Since we have one unknown (either b or h), we need to make an assumption about one of them. Let's assume the width (b) is 150 mm.
h^2 = (4.446 kNm/mm²)/(b).
Substituting the assumed value of b = 150 mm,
h^2 = (4.446 kNm/mm²)/(150 mm) = 29.64 mm²/mm.
Taking the square root, we find: h ≈ 5.44 mm.
Therefore, the appropriate section size for the red pine lumber beam is 150 mm × 5.44 mm.
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1. A ball rolls off of a table with a speed of 3.2 m/s. The table is 1.6 m high.
a) When does the ball hit the ground? (time)
b) How far away from the base of the table does the ball travel?
c) With what vertical speed does the ball hit the floor?
Answer:
Explanation:
for vertical displacement h = 1.6 , let time taken be t , initial vertical velocity = 0
h = ut + 1/2 g t²
= 1/2 g t²
1.6 = .5 x 9.8 x t²
t² = .3265
t = .57 s
b )
velocity in horizontal direction = 3.2 m /s
horizontal displacement
= 3.2 x .57 = 1.82 m
c )
for vertical movement
v = u + gt
= 0 + 9.8 x .57
= 5.58 m /s
The earth has a mass of 5.98 × 10^24 kg and the moon has a mass of 7.35 × 10^22 kg. The distance from the centre of the moon to the centre of the earth is 3.84 × 10^8 m. A rocket with a total mass of 1200 kg is 3.0 × 10^8 m from the centre of the earth and directly in between the earth and the moon. Find the net gravitational force on the rocket from the earth and moon.
Answer:
F = 4.48N
Explanation:
In order to calculate the net gravitational force on the rocket, you take into account the formula for the gravitational force between two objects, which is given by:
\(F=G\frac{m_1m_2}{r^2}\) (1)
G: Cavendish's constant = 6.674*10^-11 m^3kg^-1s^-2
r: distance between the objects
You have a rocket at the middle of the distance between Earth and Moon, then, you have opposite forces on the rocket.
If you assume the origin of a system of coordinates at the rocket position, with the Moon to the left and the Earth to the right, you have:
\(F=G\frac{M_em}{r_1^2}-G\frac{M_mm}{r_2^2}\) (2)
Me: mass of the Earth = 5.98*10^24 kg
Mm: mass of the Moon = 7.35*10^22 kg
m: mass of the rocket = 1200kg
r1: distance from the rocket to the Earth = 3.0*10^8m
r: distance between rocket and Moon = 3.84*10^8m - 3.0*10^8m = 8.4*10^7m
You replace the values of the parameters in the equation (2):
\(F=Gm[\frac{M_e}{r_1^2}-\frac{M_m}{r_2^2}]\\\\F=(6.674*10^{-11}m^3kg^{-1}s^{-2})(1200kg)[\frac{5.98*10^{24}kg}{(3.0*10^8m)^2}-\frac{7.35*10^{22}kg}{(8.4*10^7m)^2}]\\\\F=4.48N\)
The net force exerted over the rocket is 4.48N
The net gravitational force on the rocket from the earth and moon is 4.48N.
The gravitational force between two objects is:
F = Gm₁m₂/r²
Where m₁, m₂, are masses, r is the distance between them and G is gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²
Let us assume that the rocket is at the origin with the Moon to the left and the Earth to the right. Hence:
\(F=G[\frac{m_em}{r_1^2} -\frac{m_mm}{r_2^2} ]\)
Where me is the mass of earth = 5.98 × 10^24 kg,
r₁ is the distance from earth to rocket = 3.0 × 10^8 m,
m is the mass of rocket = 1200 kg,
mm is the mass of moon = 7.35 × 10^22 kg,
r₂ is the distance from moon to rocket = 3.84 × 10^8 m - 3.0 × 10^8 m = 0.84 × 10^8 m
Hence:
\(F=6.67*10^{-11}[\frac{1200*5.98*10^{24}}{3*10^8}-\frac{1200*3*10^{22}}{0.84*10^8} ]\\\\F=4.48\ N\)
The net gravitational force on the rocket from the earth and moon is 4.48N.
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a small metal cube has a density of 581 g/cm3 and has a mass of 50.225 g. calculate the length of the sides of the cube. a. 48.1 mm b. 9.30 mm c. 0.953 mm d. 4.42 mm\
Answer: d. 4.42 mm (rounded to two decimal places).
The density of the metal cube is given as 581 g/cm^3, and its mass is 50.225 g. Let's use the formula for the density of an object to find its volume first:
\(Volume = Mass / Density\)
Substituting the given values, we get:
\(Volume = 50.225 g / 581 g/cm^3 ≈ 0.08648 cm^3\)
Since the cube has equal length on all sides;
Volume of cube = \(length^3\)
Substituting the value of the volume we just calculated, we get:
\(0.08648 cm^3 = length^3\)
Taking the cube root of both sides gives:
length ≈ 0.444 cm
Converting to millimeters, we get:
length ≈ 4.44 mm
Therefore, the length of the sides of the cube is approximately 4.44 mm.
which is nearest to the option d.
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A rubber band has an un-stretched length of 0. 10m. If someone picks up a paper clip that has a mass of 10g (0. 010kg) and pulls back on it with a rubber band to a distance of. 25 m. With what speed would the paper clip be launched horizontally? The spring constant of the rubber band is 15 N/m
The speed at which the paper clip be launched horizontally, given that the paper clip has a mass of 0.01 Kg is 5.81 m/s
How do I determine the speed?We'll begin by obtaining the energy stored in the stored in rubber. This is shown below:
Initial length = 0.10 mNew length = 0.25 mExtension (e) = 0.25 - 0.10 = 0.15 mSpring constant (K) = 15 N/mEnergy stored (E) =?E = ½Ke²
E = ½ × 15× 0.15²
E = 7.5 × 0.0225
E = 0.16875 J
Finally, we shall determine the speed. Details below:
Mass (m) = 0.01 KgEnergy (E) = 0.16875 JSpeed (v) = ?KE = ½mv²
0.16875 = ½ × 0.01 × v²
0.16875 = 0.005 × v²
Divide both side by 0.005
v² = 0.16875 / 0.005
Take the square root of both side
v = √(0.16875 / 0.005)
v = 5.81 m/s
Thus, the speed is 5.81 m/s
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If the acceleration of an object is zero, then that object cannot be moving.
a. True
b. False
Answer:
False
Explanation:
Because acceleration just means that the speeds getting faster he could already be going at a same rate of speed and it wouldn't be counted as acceleration because acceleration would be if he increased the speed
regarding the oscilloscope and based on the information provided in the laboratory manual. what axis measures the voltage strength, the x-axis or the y-axis?
pertaining to the oscilloscope and in accordance with the details in the laboratory manual. what axis quantifies the voltage intensity? Voltage (on the vertical axis) versus time is plotted on the oscilloscope's graph (on the horizontal axis).
What is meant by a Oscilloscope?An oscilloscope is a class of electronic test equipment that graphically shows changing electrical voltages as a two-dimensional plot of one or more signals as a function of time.
The major goals are to show on the screen waveforms that are repeating or singular and would otherwise occur too quickly for the human eye to see. The waveform that is being presented can then be examined for characteristics like amplitude, frequency, rising time, time interval, distortion, and others.
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Which of the following statements is true?
A spark causes combustion in a gasoline engine.
All oxidation reactions cause explosions.
Batteries were invented during the 20th century.
All oxidation reactions absorb heat.
the attractive forces that exist between gas particles cause the measured pressure of a gas to be lower than that predicted by the ideal gas law true or false
The attractive forces that exist between gas particles cause the measured pressure of a gas to be lower than that predicted by the ideal gas law. is True because gas particles are in constant motion.
The attractive forces between gas particles are responsible for the deviation of real gases from ideal behavior, causing the pressure to be lower than expected. This is because the ideal gas law assumes that the gas particles are in constant motion and have no intermolecular forces acting upon them.
However, in real gases, there are attractive forces that exist between gas particles, which causes the gas molecules to have less kinetic energy and thus move more slowly. This slower movement leads to a lower pressure than would be predicted by the ideal gas law.
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equipotential lines are to electric field lines. when a charge is moved on an equipotential line, .
Equipotential lines are perpendicular to electric field lines. When a charge is moved on an equipotential line, no work is done and the potential energy remains constant.
Equipotential lines and electric field lines are related to the concept of electric potential, which is the electric potential energy per unit charge at a point in space due to a source charge.
Electric potential is measured in volts (V) and is a scalar quantity, meaning it has only magnitude and no direction.
Equipotential lines are lines in space that connect points having the same electric potential. In other words, all points on an equipotential line have the same electric potential value.
Electric field lines, on the other hand, represent the direction and strength of the electric field at every point in space. They point in the direction of the force that would be exerted on a positive test charge placed at that point in the field.
The relationship between equipotential lines and electric field lines is that they are always perpendicular to each other. This means that at any point on an equipotential line, the electric field vector is perpendicular to the line.
This can be mathematically proven using the gradient operator, which relates the electric field to the electric potential.
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the unit of pressure is derived unit, why?
Answer:
I hope you understand it.
I had presented answer very clearly would you mark brainliest