Answer:
a) the magnitude is 6.37 m/s
b) the direction relative to due west, as seen by Barbara is 46.37° north of west
Explanation:
Given the data in the question;
Barbara is skating due south at a speed of 4.6 m/s
Neil is skating due west at a speed of 4.4 m/s
so
\(u_{B}\)→ = 4.6 (-j^)
\(u_{N}\)→ = 4.4 (-i^)
\(u_{NB}\)→ = \(u_{N}\)→ - \(u_{B}\)→ = 4.4 (-i^) - 4.6 (-j^)
= -4.4i^ + 4.6j^
a) magnitude
magnitude |(\(u_{NB}\)→ )| = √( (-4.4)² + (4.6)²)
= √( 19.36 + 21.16)
= √40.52
= 6.37 m/s
Therefore, the magnitude is 6.37 m/s
b) direction relative to due west, as seen by Barbara.
using SOH CAH TOA
tan = opp / adj
so direction will be;
∅ = tan⁻¹( 4.6 / -4.4)
∅ = tan⁻¹( - 1.0454545 )
∅ = - 46.37°
Therefore, the direction relative to due west, as seen by Barbara is 46.37° north of west
A cart of mass 4 kg moves to the right with a speed 4 m/s. It strikes a 6 kg cart moving to the left with a speed of 6 m/s. If the carts couple together after the collision, what is their velocity? (Let the rightward direction be positive.)
Take into account that the momentum must conserve before and after the collision.
Before the collision the total momentum is:
\(\begin{gathered} p_o=p_1-p_2 \\ p_o=m_1v_1-m_2v_2 \\ p_o=(4kg)(4\frac{m}{s})-(6kg)(6\frac{m}{s}) \\ p_o=16\operatorname{kg}\frac{m}{s}-36\operatorname{kg}\frac{m}{s}=-20\operatorname{kg}\frac{m}{s} \end{gathered}\)p1 and p2 have opposite signd because the carts are moving in opposite directions. If motions to the right is considered as positive, then, the previous negative result means that total momentum beofre the collision is to the left.
Now, after the collision you obtain:
\(p=(m_1+m_2)v\)v is the speed of the cart together after the collision. Due to the momentum must conserve, po = p, then by solving for v and replacing, you have:
\(\begin{gathered} p=p_o=(m_1+m_2)v \\ v=\frac{p_o}{m_1+m_2} \\ v=\frac{-20\operatorname{kg}\frac{m}{s}}{4\operatorname{kg}+6\operatorname{kg}} \\ v=-2\frac{m}{s} \end{gathered}\)the speed of the carts togueter is 2m/s and the direction of motion is to the left.
Can someone tell me a very very simple physics experiment topic that links to biology?
Explanation:
One idea would be to investigate the correlation between your pulse pressure and your pulse rate. To do this, you'll need a blood pressure monitor.
First, measure your resting pressure and rate. Then exercise for 30 seconds. Measure your new blood pressure and pulse rate. Wait for your pressure and rate to return to normal, then repeat the trial for 1 minute, 1.5 minutes, 2 minutes, etc.
List the results in a table. This should include the amount of exercise time, your pulse rate, your systolic pressure (the high number, which is your blood pressure during contraction of your heart muscle), and your diastolic pressure (the low number, which is your blood pressure between heartbeats). Calculate your pulse pressure (systolic minus diastolic) for each trial. Graph the pulse pressure on the x-axis, and your pulse rate (beats per minute) on the y-axis.
What do you hypothesize will be the shape of the graph? Consider Bernoulli's formula, which relates fluid pressure and flow. How close do the results match your hypothesis? What might explain any differences?
What is longitudinal wave ?
Explanation:
Longitudinal waves are waves in which the vibration of the medium is parallel ("along") to the direction the wave travels and displacement of the medium is in the same (or opposite) direction of the wave propagationWhen using the thin lens equation, what explains why the value for the focal length of a given lens doesn't change?
The object and image distance change inversely, but in the same ratio.
The specific material and shape of each lens determines how it refracts light rays.
The object and image distance always change in direct proportion.
The focal length is a universal constant.
Answer:
The specific material and shape of each lens determines how it refracts light rays.
Answer:
D) The specific material and shape of each lens determines how it refracts light rays.
Explanation:
The specific material and shape of each lens determines how it refracts light rays. Since the index of refraction for the material and its specific shape determine how it bends light, the focal length for a given lens doesn't change. If you change the position of the object, the distance of the image will change inversely, but not in given ratio.
hope it helps:)
The total clockwise moment about a pivot is 5 Nm and the total anti-clockwise moment is 10 Nm. Will the object turn?
Yes or no?
Answer:
Yes, the object will turn.
Explanation:
The object will turn because there is an net clockwise moment of 5 Nm and an anti-clockwise moment of 10 Nm, resulting in a net clockwise moment of 5 Nm. According to the laws of physics, an object will rotate in the direction of the net torque acting upon it. In this case, the net torque is acting in a clockwise direction, causing the object to rotate in that direction.
What do they mean when they say electricity is being wasted or used ? What is actually happening
Explanation:
Electricity is a form of energy (electrical energy).
When the electricity is used or wasted, it changes into another form of energy.
HELP ASAP ANSWER ALL OF THIS FOR 55 POINTS+BRAINLIST
1. Heat is transferred directly from one particle of matter to another by the process of
2. A circular flow of warmer fluid and cooler fluid is called a(n)
3. Heat is always transferred from to
4. is the transfer of energy by electromagnetic waves.
5. Heat that is transferred by the movement of currents within a fluid is called
6. The only form of heat transfer that does not require matter is
7. Water bubbles up through a hot spring at Yellowstone National Park. What method of heat transfer is this?
A conduction B convection
C radiation
D specific heat
In each of the following examples, identify whether heat is being transferred through conduction, convection or radiation. Some may have two possible answers. Choose the answer that best fits the situation.
Answer:
1. conduction
2. a convection current
3. Heat is always transferred from the object at the higher temperature to the object with the lower temperature
4. noooooo!Heat is always transferred from the object at the higher temperature to the object with the lower temperature
5.convection
6. Thermal radiation
7. convection again!
A. Conduction is the transfer of thermal energy through direct contact. Convection is the transfer of thermal energy through the movement of a liquid or gas.
B. Radiation is the transfer of thermal energy through thermal emission.
C. the heat required to raise the temperature of the unit mass of a given substance by a given amount
1. conduction, 2. convection current, 3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.
What are the modes of heat transfer?There are three main modes of heat transfer:
Conduction: This is the transfer of heat through a material by direct contact between molecules. In this mode, heat flows from hotter to colder regions within the material until the temperature is equalized.
Convection: This is the transfer of heat through a fluid (liquid or gas) by the movement of the fluid itself. This mode of heat transfer can occur by natural convection (due to density differences in the fluid) or forced convection (due to an external source such as a fan).
Radiation: This is the transfer of heat through electromagnetic waves, without the need for a medium to transfer the heat. All objects emit and absorb radiation, and the amount of radiation emitted depends on the temperature of the object. This mode of heat transfer is important for heating and cooling applications, such as radiators or refrigerators.
Here in the question,
1. Heat is transferred directly from one particle of matter to another by the process of conduction.
2. A circular flow of warmer fluid and cooler fluid is called a convection current.
3. Heat is always transferred from hotter objects to cooler objects.
4. Radiation is the transfer of energy by electromagnetic waves.
5. Heat that is transferred by the movement of currents within a fluid is called convection.
6. The only form of heat transfer that does not require matter is radiation.
7. Water bubbling up through a hot spring at Yellowstone National Park is an example of convection.
Therefore, The Answers to those questions are 1. conduction, 2. convection current,3. hotter objects to cooler objects. 4. Radiation, 5. convection, 6. radiation, 7. convection.
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A lump of clay with a mass of .50.0 g is moving south at a speed of 20.0 cm/s. It collides head on with a second lump of clay with a mass of 70.0 g that is moving north at a speed of 40.0 cm/s. The two lumps stick together, and no external horizontal forces act on the system. What is the velocity of the combined lump after the collision?
The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.
The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:
Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s
= -10.0 g·cm/s + 2800.0 g·cm/s
= 2790.0 g·cm/s
Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:
Total momentum after collision = (0.50 g + 70.0 g) × v
= 70.50 g × v
According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":
Total momentum before collision = Total momentum after collision
2790.0 g·cm/s = 70.50 g × v
v = 2790.0 g·cm/s ÷ 70.50 g
v = 39.5 cm/s
This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.
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Magnetism Assessment
Magnet A is a very weak magnet and Magnet B is a very strong magnet. They attract each other. The relative attractive force is
greater from magnet A
greater from magnet B
the same for both magnets
unable to be determined
1
2
3
4
5
6
7
8
9
Answer:
greater from magnet B to A
The relative attractive force is greater for magnet B and the magnetic force is also greater for magnet B
What is magnetic force?Magnetic force is the term used to describe the force that pulls items like iron. Magnetic force is the attraction or repellence that exists between two magnetic materials. Ferromagnetic materials include iron.
The magnetic force is strongest at the poles of the magnet and weak at the center of the magnet. The magnetic force can be either attractive or repulsive and like poles repel each other whereas unlike poles attracts.
Given data ,
Let the first magnet be = A
Let the second magnet be = B
Now , the Magnet A is a very weak magnet and Magnet B is a strong magnet
And , the magnets A and B attract each other so they are unlike magnets
Since , the magnet B is a strong magnet it will gave a relatively larger attractive force when compared to the weak magnet A
Hence , the magnet B will have greater magnetic force
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Which letter does not show one wavelength?
A
C
B
Answer:
B
Explanation:
the answer is letter B
Answer:B
Explanation:
It doesn't show one wavelength
Which phase of matter does line segment CD represent?
A. plasma
B. liquid
C. gas
D. solid
Answer:
C. Gas
Explanation:
Segment CD represents gaseous phase of matter as segment CD shows highest energy which is in case of gas.
What is matter?
Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.
Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.
The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.The intermolecular forces of attraction are different in different states of matter.Particles of matter have different sizes.
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Which description tells two processes scientists think move Earth's lithospheric plates?
Responses
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and friction between the plate and the asthenosphere
gravity acting on the edges of plates and friction between the plate and the asthenosphere
convection in the mantle and pressure of magma on the edge of the plate
The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.
What is the Earth's lithosphere?The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.
The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.
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Answer: convection in the mantle and pressure of magma on the edge of the plate
Explanation: I took the unit test
The frequency of the middle B note on a piano is 493.88 Hz. What is the wavelength of this note in centimeters? The speed of sound in air is 343.06 m/s. quizle
Explanation:
using
v = f × lambda
lambda = v/f
v = 343.06m/s to cm/s
343.06 × 100
34306.00cm/s
f = 493.88 Hz
lambda = (34306/493.88) cm/s÷Hz
lambda = 69.46cm
Here we know a frequency, and from this we want to find the wavelength of a soundwave with that frequency.
We will see that the solution is: Wavelength = 69.46cm
The equation we need to use is:
v = λ*fWhere:v = velocityλ = wavelengthf = frequency.In this particular case we know that the frequency is:
f = 493.88 Hz
And the velocity of the wave is:
v = 343.06 m/s
We can replace these in the general equation:
343.06 m/s = λ*(493.88 Hz)
(343.06 m/s)/(493.88 Hz) = λ
0.6946 m = λ
And we want to write this in centimeters, remember that:
1m = 100cm
Then:
λ = 0.6946 m = 0.6946*(100cm) = 69.46cm
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URGENT HELP:
Two sine waves of equal frequency are to be compounded, (1) a1= 3.0 × 10–6 m and ϕ0 = 60° and (2) a2= 4.0 × 10–6 m and ϕ0 = 150°. (a) Calculate their resultant amplitude, (b) What is the resultant’s initial phase angle. (c) Draw a circle of reference and a time graph for the sine waves.
Answer:
Explanation:
To solve this problem, we can use the following equations for the addition of two sinusoidal waves:
y1 = A1 sin(ωt + φ1)
y2 = A2 sin(ωt + φ2)
where A1 and A2 are the amplitudes of the waves, ω is the angular frequency, t is time, and φ1 and φ2 are the initial phase angles.
(a) To find the resultant amplitude of the two waves, we can use the following equation:
Ar = √(A1^2 + A2^2 + 2A1A2cos(φ2 - φ1))
where Ar is the resultant amplitude.
Substituting the given values, we get:
Ar = √((3.0 × 10^(-6))^2 + (4.0 × 10^(-6))^2 + 2(3.0 × 10^(-6))(4.0 × 10^(-6))cos(150° - 60°))
Ar ≈ 5.03 × 10^(-6) m
Therefore, the resultant amplitude is approximately 5.03 × 10^(-6) m.
(b) To find the resultant's initial phase angle, we can use the following equation:
tan(φr) = (A1sin(φ1) + A2sin(φ2))/(A1cos(φ1) + A2cos(φ2))
where φr is the initial phase angle of the resultant wave.
Substituting the given values, we get:
tan(φr) = (3.0 × 10^(-6)sin(60°) + 4.0 × 10^(-6)sin(150°))/(3.0 × 10^(-6)cos(60°) + 4.0 × 10^(-6)cos(150°))
φr ≈ 142.85°
Therefore, the resultant's initial phase angle is approximately 142.85°.
(c) The circle of reference and the time graph for the sine waves can be drawn as follows:
Sine Waves
The blue and red arrows represent the maximum displacement of the waves. The black arrow represents the displacement of the resultant wave. The time graph shows the displacement of each wave and the resultant wave over time.
The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?
Answer:
(1.8 × 10^9) meters in one minute
Explanation:
To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.
The speed of light is 3 × 10^8 meters per second.
There are 60 seconds in a minute.
Therefore, the distance light can travel in one minute is:
Distance = Speed × Time
Distance = (3 × 10^8 meters per second) × (60 seconds)
Calculating this, we get:
Distance = 3 × 10^8 meters/second × 60 seconds
Distance = 18 × 10^8 meters
Distance = 1.8 × 10^9 meters
So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.
During take-off a 8kg model rocket is burning fuel causing its speed to increase
at a rate of 4m/s2 despite experiencing a 90N drag.
What’s is the strength of the thrust?
(Answer unit is in N)( and the answer isn’t 212)
The strength of the thrust is 122 newtons.
The motion of the rocket is described by the second Newton's law, whose model is shown below:
\(\Sigma F = F - D = m\cdot a\) (1)
Where:
\(F\) - Thrust, in newtons\(D\) - Drag, in newtons\(m\) - Mass of the rocket, in kilograms\(a\) - Net acceleration of the rocket, in meters per square secondIf we know that \(D = 90\,N\), \(m = 8\,kg\) and \(a = 4\,\frac{m}{s^{2}}\), then the strength of the thrust is:
\(F = D + m\cdot a\)
\(F = 90\,N + (8\,kg)\cdot \left(4\,\frac{m}{s^{2}} \right)\)
\(F = 122\,N\)
The strength of the thrust is 122 newtons.
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How can I solve the following?
In (Figure 1), let V = 15.0 V and C1=C2=C3= 24.2 μF.
Part A: How much energy is stored in the capacitor network as shown in (Figure 1)?
Part B: How much energy would be stored in the capacitor network if the capacitors were all in series?
Part C: How much energy would be stored in the capacitor network if the capacitors were all in parallel?
Answer:
Part A - 4.084 mJ
Part B - 0.908 mJ
Part C - 8.168 mJ
Explanation:
Part A: How much energy is stored in the capacitor network as shown in (Figure 1)?
Since capacitors C₂ and C₃ are in series, their equivalent capacitance is C',
1/C' = 1/C₂ + 1/C₃ (Since C₁ = C₂ = C₃ = C)
1/C' = 1/C + 1/C
1/C' = 2/C
C' = C/2
Since C' is in parallel with C₁, the equivalent capacitance for the circuit is C" = C₁ + C' = C + C/2 = 3C/2
C" = 3C/2
The energy stored in the circuit, W = 1/2C"V² where C" = equivalent capacitance = 3C/2 and V = voltage = 15.0 V
W = 1/2C"V²
W = 1/2(3C/2)V²
W = 3CV²/4
since C = 24.2 μF = 24.2 × 10⁻⁶ F
W = 3CV²/4
W = 3 × 24.2 × 10⁻⁶ F (15.0 V)²/4
W = 3 × 24.2 × 10⁻⁶ F × 225 V²/4
W = 16335/4 × 10⁻⁶ FV²
W = 4083.75 × 10⁻⁶ J
W = 4.08375 × 10⁻³ J
W = 4.08375 mJ
W ≅ 4.084 mJ
Part B: How much energy would be stored in the capacitor network if the capacitors were all in series?
If the capacitors are connected in series, their equivalent resistance is C'
and 1/C' = 1/C₁ + 1/C₂ + 1/C₃
Since C₁ = C₂ = C₃ = C
1/C' = 1/C + 1/C + 1/C
1/C' = 3/C
C' = C/3
The energy stored in the circuit, W = 1/2C'V² where C' = equivalent capacitance = C/3 and V = voltage = 15.0 V
W = 1/2C'V²
W = 1/2(C/3)V²
W = CV²/6
since C = 24.2 μF = 24.2 × 10⁻⁶ F
W = CV²/6
W = 24.2 × 10⁻⁶ F (15.0 V)²/6
W = 24.2 × 10⁻⁶ F × 225 V²/6
W = 5445/6 × 10⁻⁶ FV²
W = 907.5 × 10⁻⁶ J
W = 0.9075 × 10⁻³ J
W = 0.9075 mJ
W ≅ 0.908 mJ
Part C: How much energy would be stored in the capacitor network if the capacitors were all in parallel?
If the capacitors are connected in parallel, their equivalent resistance is C'
and C' = C₁ + C₂ + C₃
Since C₁ = C₂ = C₃ = C
C' = C + C + C
C' = 3C
The energy stored in the capacitor network, W = 1/2C'V² where C' = equivalent capacitance = 3C and V = voltage = 15.0 V
W = 1/2C'V²
W = 1/2(3C)V²
W = 3CV²/2
since C = 24.2 μF = 24.2 × 10⁻⁶ F
W = 3CV²/2
W = 3 × 24.2 × 10⁻⁶ F (15.0 V)²/2
W = 3 × 24.2 × 10⁻⁶ F × 225 V²/2
W = 16335/2 × 10⁻⁶ FV²
W = 8167.5 × 10⁻⁶ J
W = 8.1675 × 10⁻³ J
W = 8.1675 mJ
W ≅ 8.168 mJ
The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?
allung d Uall, Wily
In which condition is mirage seen ? Why is light dispersed ?
Answer:
Mirage is a phenomenon which can be seen when the surface air gets heated up and it becomes lighter. Lighter air moves up in the atmoshphere.
Explanation:
When the lighter air from cooler areas to warmer areas are refracted and they bent upwards.and it dispers
,
Tarzan wants to swing on a vine across a river. He is standing on a ledge above the water's edge, and the river is 5.00 m wide. The vine is attached to a tree branch that is 8.00 m directly above the opposite edge of the river. Initially the vine makes a
60.0∘
angle with the vertical as he is holding it. He swings across starting from rest, but unfortunately the vine breaks when the vine is
20.0∘
from the vertical.
(a) Assuming Tarzan weighs 900.0 N, what was the tension in the vine just before it broke?
(b) Does be land safely on the other side of the river?
Answer:
E D G E N U I T Y
Explanation:
lol
a) The tension in the vine just before it broke was 845.72 N.
b) Tarzan doesn't land safely on the other side of the river.
What is weight?Weight gauges how much gravity is pulling on a body. The weight formula is provided by: w = mg. Weight being a force The SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change, the acceleration caused by gravity does.
Given parameters:
Wide of the river: d = 5.00 m.
Length of the tree branch: l = 8.00 m.
Initial angle of the tree branch = 60°.
Angle of tree branch when it breaks = 20.0°.
a) Weighs of Tarzan: W = 900.0 N.
The tension in the vine just before it broke = W cos20°
= 900.0 × cos20° N.
= 845.72 N.
b) Distance traveled by Tarzan using this branch = lsin60° - lsin20°
= 8.0( sin60° - sin20°) m = 4.19 m.
Hence, he doesn't land safely on the other side of the river.
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a uniform metre rule is pivoted at its centre and weights of 5 N and 12 N are hung at the 3 cm and 5 cm marks respectively. how far from the pivot must a 25 N weight be hung to balance the metre rule horizontally?
In order to balance the stick on the pivot, the total "moments" must be equal on both sides. A "moment" is (a weight) x (its distance from the center).
for the 5N weight: Moment = (5N) x (3 cm) = 15 N-cm
for the 12N weight: Moment = (12N) x (5 cm) = 60 N-cm
Sum of the moments trying to pull the stick down on that side = 75 N-cm
Whatever we hang on the other side has to provide a moment of 75 N-cm in the other direction. We have a 25N weight. Where should we hang it ?
(25N) x (distance from the pivot) = 75 N-cm
Distance from the pivot = (75 N-cm) / (25 N)
Distance from the pivot = 3 cm
Answer:
The distance do a 25N be hung from the pivot is 31.2cm
20 POINTS
In order to maximize the acceleration of an object, one should
maximize the mass
maximize the force
minimize the velocity
maximize the inertia
A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducing velocity, until a docking maneuver is completed and the vehicle is attached to the station. How does the total momentum of the docked vehicle and station compare to the momentum of each object before the docking maneuver? greater momentum same momentum less momentum
Answer:
c. same momentum
Explanation:
got it correct on edge2020
Answer:
Explanation:c. same momentum
Explanation:
got it correct on edge2020
Help answer this please
Answer:
1. Atomic number
2. element symbol
3. element name
4. atomic mass
5 and 6 are the same as the diagram above... just rewrite using data
Describe Fleming’s left hand rule with the aid of a drawing
The left hand rule or Fleming's rule is a law used in electromagnetism that determines the movement of a conductor that is immersed in a magnetic field or the direction in which the force is generated within it.
In a conductor that is inside a magnetic field perpendicular to it and through which a current is circulated, a force is created whose direction will depend on how both magnitudes interact. This force that appears as a result is called the Lorentz force. To obtain the direction of the force, take the index finger of the left hand pointing to the direction of the magnetic field that interacts with the conductor and point the middle finger in the direction of the current flowing through the conductor, forming an angle of 90 degrees. In this way, the thumb determines the direction of the force that driver will experience.
Conventions:
* The direction of the mechanical force points the same as the finger.
*The direction of the magnetic field is from north to south.
*The current flows in the conventional direction, that is, from positive to negative.
Emory pushes the box with 20 Newtons of force. If the box is 4kg, how fast will the box accelerate?
How do the frequencies and the speeds of yellow light and blue light compare?
Answer: The frequency of yellow light is greater that blue light
Explanation: Hope this helps :)
the moon has an orbital period of 63.3 days. Calculate the average distance from the earth
Answer:
2 pi R / T = speed of moon
m V^2 / R = G M m / R^2 centripetal force = gravitational force
V^2 / R = G M / R^2
4 pi^2 R^2 / (T^2 R) = G M / R^2 using first equation
R^3 = 1 / (4 pi^2) * G M T^2 we need to know G and M
R^3 = .0253 * 6.67E-11 * 5.98E24 T^2 = 1.01E13 * T^2
63.3 da = 5.47E6 sec
T^2 = 2.99E13 sec^2
R^3 = 1.01E13 * 2.99E13 = 3.02E26 = 302E24 m^3
R = 6.70E8 m from center of earth
Using 1609 m/mile
R = 416,000 miles
Note: our moon is about 239,00 miles away
So this distance is about 1.74 our earth-moon distance
If T^2 proportional R^3 (the moon period is 27.3 da)
63.3/27.3 = 2.32 2.32^2 = 5.38
416/239 = 1.74 1.74^3 = 5.27
Not exact but reasonably close
The following table contains financial information for Trumpter Inc. before closing entries:
Cash
Supplies
Prepaid Rent
Salaries Expense
Equipment
Service Revenue
Miscellaneous Expenses
Dividends
Accounts Payable
Common Stock
Retained Earnings
$13,100
6,000
3,800
5,000
65,900
28,000
20,100
4,000
3,100
66,100
20,700
What is the amount of Trumpter's total assets?
The Total assets based on the given table is $88,800.
What are assets?An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.
The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment
Total assets = 13,100 + 6,000 + 3,800 + 65,900
Total assets = $88,800
Learn more about assets at:
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If the diameter of a moose eye is 40 mm, what is the total refractive power of the anterior portion of the eye?
Answer:
-the ratio of the speed of light
in air to the speed of light in the substance.
-speed of light in air 300,000 km/sec, which decreases when it passes through a transparent substance.
-e.g.. speed of light in substance = 200,000 km/sec, R.I. = 300,000/200,000 = 1.5
Explanation: