Two different atoms have six protons each and the same mass. however, one has a negative charge while the other has a positive charge.
describe what each atomic structure could be listing the possible number and location of all subatomic particles

Answer:

Organisms with a recessive trait can have a dominant allele for the trait.

Explanation:

hope this helps

Answer

D

Organisms can be bred for specific traits based on a pattern of inheritance.

positive, negative, positive are the entropy changes of the sugar plus water, the surroundings and the universe respectively

∆s of system is positive because it is becoming more disordered as it becomes a mixture as sugar dissolves.

∆s of surroundings is negative because it is giving heat to system (losing heat) so it is becoming more ordered.

∆s of the universe is positive because the reaction is spontaneous-- second law of thermo.

In spontaneous changes, the universe tends toward a state of greater disorder

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The process involves selectively precipitating and separating two metal ions from an ore sample using H₂S as a precipitating agent. The calculations required include determining the pH at which maximum separation of the metal ions occurs and calculating the percentage mass impurity of the metal obtained from the last precipitate.

The paragraph describes a process of selectively precipitating and separating two metal ions, Ni²+ and Co²+, from an ore sample using H₂S as a precipitating agent.

The solution is initially saturated with H₂S, and the pH is adjusted to selectively precipitate the first metal ion. The precipitate is filtered, dried, and reduced to obtain the pure metal.

The remaining solution is then adjusted in pH to co-precipitate the second metal ion with a trace concentration of the first metal ion. The co-precipitate is filtered, dried, and reduced to obtain the second metal.

The pH at which maximum separation occurs is determined, and the percentage mass impurity of the metal obtained from the last precipitate is calculated.

Further information and data are needed to provide a complete analysis and answer the specific questions regarding pH and impurity percentage.

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The mass percentage of sugar in the sweet tea is 10%

From the question,

We are to determine the mass percentage of sugar in the sweet tea

\(Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{Mass\ of\ sugar\ in\ the\ solution}{Mass\ of\ the\ solution} \times 100\%\)

Mass of sugar in the solution = 20 g

Mass of the solution = 20g + 180g = 200g

\(Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{200} \times 100\%\)

\(Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{2} \%\)

∴ Mass percentage of sugar in the sweet tea = 10%

Hence, the mass percentage of sugar in the sweet tea is 10%

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Habitat degradation: 25%, Exploitation: 50%, Invasive species and disease: 25%, Pollution: 25%, Climate change: 50%, Birds: 25%, Reptiles and amphibians: 25%, Mammals: 25% and Fish: 25%

Biodiversity is being threatened by many impacts from human activities. These include climate change, habitat destruction, over-exploitation of resources, pollution, and introduction of invasive species.

Climate change affects biodiversity by changing the physical and chemical environment, altering weather patterns, and increasing the frequency and intensity of extreme weather events. This can lead to a decrease in species diversity, as some species may not be able to survive in the new environment. Habitat destruction is another major factor in biodiversity loss, as it removes habitats that are necessary for species to survive and reproduce.

Over-exploitation of resources can lead to over-harvesting of animals and plants, removing an important source of food or shelter. Pollution can be toxic to species and can also disrupt the food chain. Finally, the introduction of invasive species can out-compete native species, leading to their decline.

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Answer:

Very important

Explanation:

To address the crevice corrosion issue in the high-pressure connectors and piping of the SWRO plant, several remedies can be considered, A SWRO (Sea Water Reverse Osmosis) plant is a water desalination facility that uses reverse osmosis technology to treat seawater or brackish water and produce freshwater

Material Selection: Evaluate the material compatibility with the operating conditions, especially the chloride ion concentration and temperature. Consider using corrosion-resistant alloys such as duplex stainless steel (e.g., 2205) or super duplex stainless steel (e.g., 2507) that have better resistance to chloride-induced corrosion compared to 316L or 317L stainless steel.

Surface Treatment: Apply appropriate surface treatments to enhance corrosion resistance. Passivation or pickling can remove surface contaminants and create a protective oxide layer on the metal surface, reducing the susceptibility to corrosion.

Design Modifications: Evaluate the design of the connectors and piping to minimize crevices and stagnant areas where corrosion can occur. Smooth transitions, avoiding sharp angles or crevices, can help promote better fluid flow and prevent the accumulation of corrosive substances.

Cathodic Protection: Implement cathodic protection methods, such as impressed current or sacrificial anodes, to protect the connectors and piping from corrosion. This technique involves introducing a more easily corroded metal (anode) to the system, which sacrifices itself to protect the connected metal (cathode) from corrosion.

Monitoring and Maintenance: Regularly monitor the corrosion levels and condition of the connectors and piping. Implement a maintenance program that includes periodic inspections, cleaning, and repairs, if necessary, to prevent corrosion from progressing.

It is important to consult with corrosion experts and engineers who specialize in SWRO plant operations to assess the specific conditions, perform material testing, and provide tailored solutions to mitigate the crevice corrosion problem effectively.

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Answer:

A. Molecules have finite volume.

Explanation:

Gases deviate from the ideal gas law at high pressures because its molecules have a finite volume.

Real gases have a finite volume which enables more interaction between the molecules while ideal gases are assumed not to have a finite volume or occupy space which is why it lacks any form of interaction between its molecules.

This difference is the deviation between the real and ideal gases.

Answer:

there wouldnt be funtion to most things

Explanation:

for ex the force of gravity if there was no equal force there would be a technical gravity

The mass of iron formed when 591 kJ of heat are released in the given reaction is 78 g.

To calculate the mass of iron formed, we can use the stoichiometry of the reaction and the given ΔH value. The reaction shows that 2 moles of aluminum react with 1 mole of iron(III) oxide to produce 2 moles of iron and 1 mole of aluminum oxide. The enthalpy change (ΔH) for this reaction is -850 kJ, which means that 850 kJ of heat is released when the reaction goes to completion.

First, we need to determine the ratio of heat released for the given amount of heat (591 kJ) to the heat released per mole of reaction (850 kJ). This ratio is 591 kJ / 850 kJ = 0.695.

Next, we know that 2 moles of aluminum produce 2 moles of iron, so the ratio of moles of iron produced to moles of aluminum reacted is 1:1. Thus, 0.695 moles of iron are produced when 591 kJ of heat are released.

Finally, we need to convert moles of iron to grams. The molar mass of iron (Fe) is 55.85 g/mol. Multiply the moles of iron by its molar mass to find the mass of iron formed:

0.695 moles * 55.85 g/mol ≈ 38.8 g

Rounded to the nearest whole number, the mass of iron formed is 78 g.

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Answer:

SULFUR: S²-

ALUMINIUM: Al³†

NITROGEN: N³-

CALCIUM: Ca²†

Answer:

.45g

Explanation:

Do not forget to add the unit at the end, grams(g).

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

The classification of the given compounds is as follows:

(a) lactose (C₁₂​H₂₂​O₁₁​) - non-electrolytes

(b) lactic acid (HC₃​H₅​O₃​) - weak electrolytes

(c) dimethylamine [(CH₃​)₂​NH] - weak electrolyte

(d) barium hydroxide Ba(OH)₂ - strong electrolytes

Electrolytes are substances that when in the molten or solution state conduct electricity and are decomposed by the direct current passing through them.

Electrolytes dissociate into the component ions when they are dissolved in water or in molten form. Some examples of electrolytes are acids and bases.

Strong electrolytes dissociate completely into one while weak electrolytes dissociate partially.

Non-electrolytes do not dissociate into ions in solution but remain as molecules. Some example of non-electrolytes is organic solvents.

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Answer:

37.1

Explanation:

mass of reactant side must be equal to mass of product side

Answer:

24.2 mL.

Explanation:

Assuming constant temperature, we can solve this problem using Boyle's law, which states:

Where:

We input the data:

And solve for V₂:

The closest option is the second one: 24.2 mL.

Answer:

elements

Explanation:

compounds and molecules contain more than one elements.

The following actions describe deposition as flowing soil or mud due to gravity. Option D.

Sedimentation is the accumulation of sediments carried by the wind running water sea or ice. Sediments are carried as pebbles sand mud, or dissolved salts in water. A deposition is the direct transition of a substance from the gaseous state to the solid state on cooling without going through the liquid state.

Sedimentation is the geological process in which sediments soils and rocks are added to form landforms or land masses. Wind ice water and gravity cause previously weathered surface material to deposit and lose sufficient kinetic energy within the fluid to form a layer of sediment. Several factors influence how sediment settles. Sediment is removed from new surface locations. Precipitation is the change of state of a gaseous substance into a solid.

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The coefficients of Fe^3+ and Fe in the balanced equation are 2 and 2, respectively.

The balanced chemical equation for the given reaction is:

3 Mg + 2 Fe^3+ ---> 3 Mg^2+ + 2 Fe

This means that for every 3 moles of magnesium (Mg) that react, 2 moles of iron(III) ions (Fe^3+) are required. In the balanced equation, two Fe^3+ ions react with three Mg atoms to produce two Fe atoms and three Mg^2+ ions.

Therefore, the coefficients of Fe^3+ and Fe in the balanced equation are determined by the requirement to maintain the conservation of mass and charge on both sides of the equation.

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Answer:

La masa molar de la sustancia disuelta es de aproximadamente 138,473 g/mol

Explanation:

Los parámetros dados son;

La masa de benceno en el recipiente = 100 gramos

La masa de benceno que se evapora del benceno puro = 1.273 gramos

La masa del soluto no volátil disuelto en 100 gramos de benceno = 10 gramos

La masa de benceno que se evapora de la mezcla = 1.205 gramos

Según la ley de Raoult, tenemos;

\(P_ {solucion} = P_ {solvente} \times X _ {solvente}\)

Dónde;

\(P_ {solucion}\) = La presión de vapor de la solución.

\(P_ {solvente}\) = La presión de vapor del solvente

\(X_ {solvente}\) = La fracción molar del solvente

Por lo tanto;

\(X_ {solvente} = \dfrac {P_ {solucion}} {P_ {solvente}}\)

Según la ley de los gases ideales, tenemos;

\(P \times V = n \times R \times T = \dfrac{m}{M} \times R \times T\)

Dónde;

P = La presión del gas

V = El volumen ocupado por el gas

m = La masa del gas

M = La masa molar del gas

R = La constante universal de los gases

T = La temperatura del gas

n = El número de moles del gas

Por lo tanto;

\(P = \dfrac{m \times R \times T}{M \times V}\)

Donde R, T, M y V son constantes, tenemos P ∝ m

\(\therefore X_ {solvente} = \dfrac {P_ {solucion}} {P_ {solvente}} = \dfrac {Masa \ evaporada \ de \ solucion} {Masa \ evaporada \ de \ solvente} = \dfrac {1.205 \ g} {1.273 \ g} \approx 0.9466\)

\(X_ {solvente}\) ≈ 0.9466

\(X_ {solvente} = \dfrac {El \ numero \ de \ moles \ del \ solvente} {El \ total \ numero \ de \ moles \ de \ la \ solucion}\)

El número de moles del solvente, C₆H₆ = (Masa de C₆H₆) / (La masa molar de C₆H₆) = 100 g / (78.11 g.mol) ≈ 1.28025 moles

El número de moles del solvente, C₆H₆ ≈ 1.28025 moles

El número total de moles = El número de moles del solvente, C₆H₆ + El número de moles del soluto no volátil, \(n_ {soluto}\)

\(\therefore X_ {solvente} = 0.9466 = \dfrac {1.28025 \ moles} {1.28025 \ moles + n_ {soluto}}\)

0.9466 × (1.28025 moles + \(n_ {soluto}\)) = 1.28025 moles

1.21189 moles + 0.9466 × \(n_ {soluto}\) = 1.28025 moles

\(n_ {soluto}\) = (1.28025 - 1.21189)/0.9466 moles ≈ 0.07221635 moles

\(\therefore \dfrac {Masa \ de \ soluto} {Molar \ masa \ de \ soluto} = \dfrac {10 \ g} {Molar \ masa \ de \ soluto} \approx 0.07221635 \ moles\)

\(\ Masa \ molar \ de \ soluto = \dfrac {10 \ g} {0.07221635 \ moles} \approx 138.473 \ g / moles\)

La masa molar de la sustancia disuelta (el soluto) ≈ 138,473 g/mol

Neutral atoms are atoms of an element that have the same number of protons and electrons, resulting in an atom with a total charge of 0.

Each element has a distinct atomic number, which is equal to the number of protons in an atom of that element. The mass number of an element is equal to the number of protons and neutrons in the atom. The number of electrons in a neutral atom is equal to the number of protons.

For example, sodium has an atomic number of 11, meaning it has 11 protons. The mass number of sodium is 23, meaning it has 11 protons and 12 neutrons. Since sodium is a neutral atom, it also has 11 electrons. Similarly, argon has an atomic number of 18, meaning it has 18 protons.

Its mass number is 40, meaning it has 18 protons and 22 neutrons. Since argon is a neutral atom, it also has 18 electrons. Copper has an atomic number of 29, meaning it has 29 protons. Its mass number is 63, meaning it has 29 protons and 34 neutrons. Since copper is a neutral atom, it also has 29 electrons.

Lastly, chromium has an atomic number of 24, meaning it has 24 protons. Its mass number is 52, meaning it has 24 protons and 28 neutrons. Since chromium is a neutral atom, it also has 24 electrons.

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When considering the electrophilic addition of Br2 to isoprene (2-methyl-1,3-butadiene), the product mixture predominantly contains 3,4-dibromo-3-methyl-1-butene (21%) over 3,4-dibromo-2-methyl-1-butene (3%) due to the following reasons:

1. Regioselectivity: During the electrophilic addition reaction, the initial attack of the electrophile (Br+) to isoprene's double bond leads to the formation of two possible carbocation intermediates.
2. Carbocation stability: The intermediate carbocation that leads to the formation of 3,4-dibromo-3-methyl-1-butene is a tertiary carbocation (3°), which is more stable than the secondary carbocation (2°) leading to 3,4-dibromo-2-methyl-1-butene.
3. Hyperconjugation: The greater of the tertiary carbocation is due to hyperconjugation, which is the interaction between the adjacent C-H σ-bonds stability with the empty p-orbital of the carbocation. The tertiary carbocation has more of these stabilizing interactions than the secondary carbocation.

In conclusion, the predominance of 3,4-dibromo-3-methyl-1-butene (21%) over 3,4-dibromo-2-methyl-1-butene (3%) in the product mixture results from the greater stability of the tertiary carbocation intermediate formed during the electrophilic addition reaction of Br2 to isoprene (2-methyl-1,3-butadiene).

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Answer:

1,760

Explanation:

There are 880 fathoms in a mile. To convert miles to fathoms, multiply the mile value by 880.

So, 2.00 × 880 = 1,760

Answer:

Tin and Copper

Explanation:

The two atoms that could potentially form alloys are the tin and copper atoms.

Alloys are mixtures formed between two or more metals.

The goal of forming alloys is to take properties of one metal and add to that of another metal so as to enhance both materials.

Alloys are only formed between metals.

The only metal pair given from the choices is that of tin and copper.

Therefore, the two atoms that could potentially form alloys is tin and copper.

Answer:

A, Heat is released as the reaction happens.

Explanation:

Exothermic reactions release heat and/or light and is a reaction in which the overall enthalpy is negative. The one your mouse is hovering over explains Nuclear Fission. The third one explains an endothermic reaction, as heat is absorbed in the reaction. The product being cold is actually one of the key characteristics of an endothermic reaction. Two liquids being mixed that forms a solid is called a precipitate.

The balanced equation for neutralization reaction of H2SO4 and KOH is:H2SO4 + 2KOH → K2SO4 + 2H2OWe can use the stoichiometry of the reaction to calculate the number of moles of H2SO4 and KOH.

We have: Volume of H2SO4 solution = 28.37 mL = 0.02837 L Volume of KOH solution = 43.15 mL = 0.04315 L Concentration of H2SO4 solution = 0.142 M Concentration of KOH solution = 0.334 M Number of moles of H2SO4 = Concentration × Volume = 0.142 × 0.02837 = 0.00402854 mol Number of moles of KOH = Concentration × Volume = 0.334 × 0.04315 = 0.0144201 mol From the balanced equation, 2 moles of KOH reacts with 1 mole of H2SO4. Therefore, the number of moles of KOH that reacted is:2 × 0.00402854 = 0.00805708 mol

The remaining number of moles of KOH is the total number of moles of KOH minus the number of moles of KOH that reacted:0.0144201 - 0.00805708 = 0.00636302 mol The volume of the solution is the sum of the volumes of H2SO4 and KOH solutions:0.02837 + 0.04315 = 0.07152 L Therefore, the concentration of OH- that is unreacted is:0.00636302 / 0.07152 = 0.0889 M

Answer: 0.0889 M

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Answer:

C D E

Explanation:

i took the test

Volatility is a measure of how easily a liquid evaporates and it decreases with increase in intermolecular forces.Volatile liquids have large number of molecules in the gas phase above liquid phase. Hence, options A, C, F are correct.

Intermolecular force is the force which binds the molecules or atoms in compound together. Three are various kinds of intermolecular forces such as ionic bond, covalent , H-bonding, dipole forces etc.

When liquids molecules have strong intermolecular interaction between them they will not be capable of escaping into the gaseous state. Hence volatility decreases with increase in intermolecular force.

For a volatile substance, the number of molecules which are escaped into gas phase above liquid phase  during evaporation will be higher. More volatile liquids will have lower boiling point . Hence, the correct statements regarding volatility are A, C and F.

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A student is measuring the volume of a 42 gram rock. he places it in graduated cylinder that has 28 mL of water in it after the rock is in the cylindyer and the water level becomes 38L then then the density is  1.10kg/m³

A rock is a solid collection of mineral grains that grow or become cemented together

Here given data is

Mass = 42 gram

Volume = 38L

We have to find density of the rick = ?

Formula for density is

Density = mass/volume

Density = 42 gram/38L

Density = 1.10kg/m³

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Answer:

When mensuration volume of air within the flask at the primary temperature, a volume of 250mil was recorded, referred to as V1. The temperature of the air within the flask in boiling water was recorded as 99ᵒC, referred to as T2. so as to seek out the right calculations, 99ᵒC must be born-again to Kelvin by adding 273.

the primary temperature in Kelvin is 372K. the worth of V1/T1, may be found by swing 250/372. This involves a complete of zero.67. the quantity of the air within the flask of the second temperature was 177 mil, referred to as V2.

The temperature of the air within the cooled flask is 7ᵒC, referred to as T2. 7ᵒC must be born-again to Kelvin by adding 273 that involves a final total of 280K. the worth of V2/T2, found by swing 177/280 involves a complete of zero.63.

The close to equality in numbers may be attributed to Charles Law. Charles Law states that “as the temperature will increase, thus will the quantity of a gas sample once the pressure is command constant”.

The results of V1/T1 and V2/T2 were terribly on the brink of one another. this can be because of the very fact that this experiment was worn out as a closed system. In Charles Law, if there's a closed system the 2 ratios ought to have equal numbers. {this is|this is often|this may be} why it can be expected for the magnitude relation numbers to be terribly equal.