Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
А. The charge on B will decrease.
В. The charge on B will increase.
C. The electric force between A and B will decrease.
D. The electric force between A and B will increase.

The energy of an absorbed photon is \(2.998 * 10^8\) and  the resulting unit for energy is Joules (J).

To determine the energy of an absorbed photon in electronvolts (eV), we can use the equation E = hv, where E represents energy, h is Planck's constant, and v is the frequency of the photon. By substituting the values and units correctly, we can calculate the energy in electronvolts.

To determine the energy of an absorbed photon, one can use the following formula:

energy of absorbed photon = Planck's constant x frequency of radiation

Where Planck's constant is equal to \(6.626 * 10^{-34\) Joule seconds and frequency of radiation is measured in Hertz (Hz).

The energy of an absorbed photon can also be expressed using the wavelength of the radiation instead of its frequency.

The formula for this is:energy of absorbed photon = Planck's constant x speed of light / wavelength of radiation

Where the speed of light is equal to \(2.998 * 10^8\) m/s.In both cases,

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Answer:

5.08 metres

Explanation:

The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron

The two protons will exert a repulsive force of 0.5 N when they are at a distance of \(2.146625 \times10^{-14} \,m\) away from each other.

As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.

\(0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}\)

ie; \(r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m\)

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Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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Answer:

53 minutes

Explanation:

To solve this problem, we need to use common proportions to convert.

= 11.7km * 1mi/1.61km * 1hr/8.2mi * 60min/hr

≈ 53 minutes

Best of LUck!

Assuming premise y is directly related to x2, k must exist by which y = k * x2.

Also, we wish to use the proportional variable, k, in a solution to describe each of these relationships. So, in the first, y changes in direct proportion to the square of x. This may now be expressed as y is directly related to x squared. In the above equation, y is equal to a certain integer multiplied by x squared.

This implies that the proportion between both always maintains the same, meaning that if x improves, y rises, and as x drops, y decreases. The proportionality connection equation's graph is a line that passes directly through the origin.

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Answer:

option B is the correct answer

Explanation:

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a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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Answer:

a) W = -4N,   b)  F_net = 0

Explanation:

The suspended weight of the spring ladder is subjected to two forces: the elastic force of the spring directed downwards and the gravitational force directed downwards.

             \(F_{e}\) - W = 0

             F_{e} = W

             F_{e} = W = 4 N

a) the gravitational force is the weight of the body

             W = -4N

b) as the system is in equilibrium, the net force is zero

             F_net = 0

There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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Explanation:

perpendicular to the rope

Tcd×sin23 = Tbd×sin25

Tcd = 1.08160 Tbd

along the rope

Tcd×cos23 + Tbd×cos25 =F

1.08160×Tbd×cos23 + Tbd×cos25 = 3700 lb

Tbd (1.08160×cos23°+cos25°)=3700

Therefore, Tbd = 1945.3965 lb

Tcd = 1945.3965×1.0816 = 2104.14085 lb.

Everything but blue & orange would now be present in the spectrum of light observed.

Spectrum refers to a range of different wavelengths of electromagnetic radiation. Electromagnetic radiation is a form of energy that travels through space and includes different types such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different wavelength and frequency, and together they make up the electromagnetic spectrum.

The concept of spectrum is used in a variety of fields, including physics, astronomy, and telecommunications. The spectrum of electromagnetic radiation is essential for many technologies, such as radios and televisions, cell phones, and medical imaging devices, as they all rely on the transmission and reception of specific wavelengths of electromagnetic radiation.

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Complete Question: -

Imagine that the blue light and orange light from the source were blocked. What color(s) would now be present in the spectrum of light observed?

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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Answer:

\(power = \frac{work \: done}{time \: passed} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

power=2525J/19S

=132.8947368421JS^-1

=132.9W

The required escape velocity from the asteroid in km/s and mph is 2.0 km/s and 4478 mph, respectively.

According to analyses of orbital statistics, asteroids of 10 km in size can strike the planet every 100 My or so, which is consistent with the theory that we were struck by an object of this size 65 My ago.

Part A: Escape velocity is the bare minimum speed at which an object can break out of an astronomical body's gravitational influence. The following provides the escape velocity formula:

v = √((2GM)/r)

Where, G = gravitational constant M = mass of the astronomical body r = radius of the astronomical body

Now, let's substitute the given values to find the escape velocity from the asteroid.

Given, Diameter of the asteroid, d = 10 km

So, radius of the asteroid, r = d/2 = 5 km = 5 × 10³ m

Density of the asteroid, ρ = 3000 kg/m³

Mass of the asteroid, M = ρ × volume of the asteroid= ρ × (4/3)πr³= 3000 × (4/3) × π × (5 × 10³)³= 6.54 × 10¹¹ kg

Gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/kg²

Putting all these values in the escape velocity formula, v = √((2GM)/r)= √((2 × 6.67 × 10⁻¹¹ × 6.54 × 10¹¹)/5 × 10³)= 2.0 km/s

Therefore, the escape velocity from the asteroid is 2.0 km/s.

Part B : Now, let's convert the escape velocity from km/s to mph.1 km = 0.621371192 milesSo, v in mph = 2.0 km/s × (0.621371192 miles/km) × (3600 s/hour)= 4478 mph

Therefore, the escape velocity from the asteroid is 4478 mph (rounded to three significant figures).

Hence, the required escape velocity from the asteroid in km/s and mph is 2.0 km/s and 4478 mph, respectively.

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Question:

You are standing on the surface of a spherical asteroid 10 km in diameter, of density 3000 kg/m3.

Part A

Calculate the escape velocity from the asteroid in km/s.

Express your answer in kilometers per second using two significant figures.

Calculate the escape velocity from the asteroid in mph.

Express your answer in miles per hour using three significant figures

For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.

Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.

Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.

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In the figure provided, a 25.5° ramp in an airport has luggage sliding down to the owner.  If the ramp is 3.28 m long and the suitcase starts from rest, the time it will take for suitcase A to reach its owner is 1.25 seconds

The diagrammatic representation of the information given in the question is attached in the image below.

From the information given:

We are to find the time required for suitcase A to reach its owner.

To do this, let's compute the free body equation from the diagram.

Thus, both blocks tend to move together since the kinetic friction in A is larger than that of B.

So, summing up both equations, we have:

\(\mathbf{m_1 g sin \theta-m_2 g sin \theta - \mu_k_1 - \mu_k_2= (m_1+m_2)a}\)

Making acceleration a the subject, we have:

\(\mathbf {a = \dfrac{m_1 g sin \theta-m_2 g sin \theta - \mu_k_1 - \mu_k_2}{(m_1 + m_2)}}\)

\(\mathbf {a = \dfrac{(3.70 \times 9.8 \times sin25.5) +(9.69 \times 9.8 \times sin 25.5 )- 0.260 - 0.110}{(m_1 + m_2)}}\)

\(\mathbf {a = \dfrac{(15.610) +(40.88)- 0.260 - 0.110}{(3.70+ 9.69)}}\)

\(\mathbf {a = \dfrac{56.12}{(13.39)}}\)

a = 4.19 m/s²

Using the second equation of motion.

\(\mathbf{S = ut + \dfrac{1}{2}at^2}\)

Recall that the suitcase starts from rest;

∴

\(\mathbf{S = 0(t) + \dfrac{1}{2}at^2}\)

\(\mathbf{S = \dfrac{1}{2}at^2}\)

where;

\(\mathbf{3.28 = \dfrac{1}{2}(4.19) (t)^2}\)

By cross multiply;

3.28 × 2 = 4.19 t²

\(\mathbf{t^2 = \dfrac{3.28 \times 2}{4.19}}\)

\(\mathbf{t =\mathbf{ \sqrt{\dfrac{3.28 \times 2}{4.19}}}}\)

\(\mathbf{t =\mathbf{ \sqrt{1.566}}}\)

t = 1.25 seconds.

Therefore, we can conclude that it took suitcase A 1.25 seconds to reach its owner.

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Answer:

the force created by the earths north and south magnetic poles

Answer:

it’s B: the movement of the liquid outer core moving in relation to the solid inner core

Explanation:

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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The angle I can rightly be called the angle of reflection.

The incident ray, the reflected ray, and the normal all reside on the same plane, according to the angles of reflection. This suggests that reflection may occur when two angles are in the same plane as the normal.

The angle I and depicted can appropriately be referred to as the angle of reflection in light of the aforementioned information.

Lastly, it is obvious from the image that angle I is the angle of reflection.

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The mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.

The consequences of errors or mistakes in the experiments may be determined by the fact that errors are differences between observed values and what is true in nature.

The error causes results that are inaccurate or misleading and can misrepresent nature. Scientifically accepted values are scientists' current best approximations, or descriptions, of nature.

Experimental error is the difference between a measured value and its true value. In other words, it is the inaccuracy or inaccuracies that stop us from seeing an absolutely correct measurement. Experimental error is very common and is to some degree inherent in every measurement.

Therefore, the mistake that Farah made in this experiment is that she hung up the pieces of cotton before putting the fan on, also the water evaporating can take longer or shorter even if they are all the same.

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Answer:

Take slow, deep breaths. Or try other breathing exercises for relaxation. ...

Soak in a warm bath.

Listen to soothing music.

Practice mindful meditation. The goal of mindful meditation is to focus your attention on things that are happening right now in the present moment. ...

Write. ...

Use guided imagery.

Answer:

i think C is the answer

Explanation:

The gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.

The given problem is based on the concept of gravitational force. The force of attraction between the two massive bodies in a space is known as the gravitational force. Let us consider the mass of Earth and moon as M and m such that the gravitational force between each is,

\(F = \dfrac{G \times M \times m}{R^{2}}\)

Here,

G is the universal gravitational constant.

R is the distance between the Earth and Moon.

Clearly, the forces between the Earth and Moon varies directly with the masses of Earth and Moon and inversely with the distance between the Earth and Moon. Since, masses are the constant parameters, hence reducing the distance will increase the gravitational force.

Thus, we can conclude that the gravitational force between the Earth and Moon will increase by cutting the distance between the Earth and Moon in half. Hence, option (C) is correct.

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The mass of the picture is approximately 5.19 kilograms.

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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Answer:

Gravitional pull or gravity

Explanation:

Its that simple

Answer:

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work = (fd) = (5.2 x 13.5) = 70.2 Joules.

Rounded to 1 decimal place throughout.

Explanation:

The total work done on the vacuum is 70.2 J.

What is work done?

Work done is equal to product of force applied and distance moved.

Work = Force x Distance

Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.

Horizontal component of pull = (cos 55 x 33.9) = 19.4N.

Net horizontal force = (19.4 - 14.2) = 5.2N.

Work done by vacuum will be

Work =5.2 x 13.5

Work =70.2 J

Thus, the total work done on the vacuum is 70.2 J.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

F = 2250 [N]

Explanation:

In order to solve this problem, we must first use the following equation of kinematics.

\(v_{f}^{2} =v_{o}^{2}-2*a*x\)

where:

Vf = final velocity = 0 (come to rest)

Vo =  initial velocity = 30 [m/s]

a = acceleration or desaceleration [m/s²]

x = distance = 100 [m]

\((0)=30^{2} -2*a*100\\900 = 200*a\\a = 4.5 [m/s^{2}]\)

Now we must use the following equation of kinetics, which is based on Newton's second law that explains that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force [N]

m = mass = 500 [kg]

a = acceleration = 4.5 [m/s²]

\(F = 500*4.5\\F = 2250 [N]\)

Answer:

Do not see a picture or graph but suspect it would show the golf ball falling faster and striking the ground slightly before the soccer ball.

Probably D:  Soccer ball was affected by air resistance more than the golf ball.

Explanation:

Even though heavier, friction loss of the greater surface area soccer ball will counter pull of gravity more than the compact golf ball.

In a vacuum, (no friction) both objects fall at the same rate regardless of mass.

Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

U is the speed = 300m/s

H is the maximum height = 78.4m

g is the acceleration due to gravity = 9.8m/s²

Substitute into the fromula;

R = 300√2(78.4)/9.8

R = 300 √(16)

R = 300*4

R = 1200m

Hence the projectile travelled 1200m before hitting the ground